PLS HELP QUICK BRAINLIST

1 what is one specific question about space that could be best answered using robotic space exploration tools like Venera (rather than manned missions)? What is one specific question that could be better answered using manned space missions? In your answer, make sure to identify both a use and an advantage of robotic space missions.

Where's the following words?

Answer:

the answer is D.

Explanation: Mark me brainlest

First:

5 cm = 0,05 m

Now, the formula:

F = k * (qq') / r²

Replacing:

F = 9x10⁹ * (55x10⁸ * 1x10⁷) / 0,05²

F = 9x10⁹ * (5,5x10¹⁶ / 2,5x10⁻³)

F = 9x10⁹ * 2,2x10¹⁹

F = 1,98x10²⁹

The force between the charges is 1,98x10²⁹ Newtons.

As the temperature of the balloon is lowered, its volume will decrease as well.

The kinetic theory of matter  says that all matter consists of many, very small particles which are constantly moving or in a continual state of motion.

According to Charles law, the volume of a fixed mass of a gas is directly proportional to its absolute temperature.

Based on Charles law, as the temperature of the balloon is lowered, its volume will decrease as well because the average kinetic energy of the gas molecules has reduced, the rate of gas collision decreased, which will cause a drop in the volume of the balloon.

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Answer; 10.6 i think

Explanation:

(a) At the top of the hill, the coaster has total energy (potential and kinetic)

E = (1000 kg) g (10 m) + 1/2 (1000 kg) (6 m/s)² = 116,000 J

As it reaches its lowest position, its potential energy is converted to kinetic energy, and some is lost to friction, making its speed v such that

1/2 (1000 kg) v ² = 116,000 J - 1700 J = 114,300 J

===>   v ≈ 15.2 m/s

If no energy is lost to friction as the coaster makes its way up the second hill, all of its kinetic energy would be converted to potential energy at the maximum possible height H.

1/2 (1000 kg) (15.2 m/s)² = (1000 kg) g H

===>   H ≈ 11.7 m

(b) At the top of the second hill with minimum height h, and with maximum speed 4.6 m/s, the coaster has energy

E = P + K = (1000 kg) g h + 1/2 (1000 kg) (4.6 m/s)²

Assuming friction isn't a factor again, the energy here should match the energy at the lowest point in part (a), 114,300 J.

(1000 kg) g h + 1/2 (1000 kg) (4.6 m/s)² = 114,300 J

===>   h ≈ 10.6 m

A state of character arises from the repetition of similar activities

Aristotle was a renowned scientist and philosopher. He has made significant contributions to society. He is renowned for his quotable sayings as well. Because of the correlation between the states of character and the distinctions between them, the behaviors we display must be of a specific type. States of character: The traits that "allow us to stand well or poorly in relation to the passions." Because: We are not commended and criticized only for having the ability to feel pleasure, grief, etc., virtues are not capacities.

Here in this quote, similar behaviors give birth to similar states of character

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At this precise moment, the person's speed is decreasing.

The labor involved in moving two charges from a distance of 'd 1 '=10 cm to a closer distance of 'd 2 '=4 cm must be determined for two charges q 1 =12 C and q 2 =8 C.

Between capacitor plates, the field is constant, but the potential rises linearly. As long as the geometry of the capacitor doesn't change, the capacitance won't either. The potential difference will therefore rise in a straight line with the charge since C = Q/V.

To do this, we first determine the charge in the system's potential energy and then take the difference.

Now, d 1 =10cm=1010 2 =10 1 m, and d 2 =4cm=410 2 m.

Consequently, potential (V 1) equals 4 0 when q 1 and q 2 are separated by d 1.

Potential (V 2) equals 4 0 when q 1 and q 2 are separated by a distance of d 2.

Work completed =V 2 + V 1 = 0

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.

Explanation:

To solve the problem, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Let's first find the weight of the unknown material in air:

W_air = 300 N

Next, let's find the weight of the unknown material in alcohol:

W_alcohol = 200 N

We can find the buoyant force acting on the material by subtracting the weight in alcohol from the weight in air:

F_buoyant = W_air - W_alcohol = 300 N - 200 N = 100 N

According to Archimedes' principle, this buoyant force is equal to the weight of the alcohol displaced by the material:

F_buoyant = ρ_alcohol * V * g

where ρ_alcohol is the density of the alcohol, V is the volume of the material, and g is the acceleration due to gravity.

Substituting the values we know:

100 N = 700 kg/m^3 * V * 9.81 m/s^2

Solving for V:

V = 0.0145 m^3

Finally, we can find the density of the material by dividing its weight in air by its volume:

ρ_material = W_air / V = 300 N / 0.0145 m^3 = 20690.3 kg/m^3

Therefore, the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.

Given :

To Find :

The falling apple's kinetic energy, gravitational potential energy, and total mechanical energy.

Solution :

We can use the conservation of energy principle to find the apple's kinetic energy, gravitational potential energy, and total mechanical energy at the height of 3.0m above the ground.

First, we need to find the gravitational potential energy (GPE) of the apple when it is at the height of 4.0m above the ground:

GPE = mgh

where m is the mass of the apple, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground.

So, GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) = 8.2266 J

Next, we find the apple's kinetic energy (KE) just before it hits the ground. We can use the conservation of energy principle, "which states that a system's total mechanical energy is conserved (i.e., it remains constant) if no external forces are acting on it." In this case, gravity is the only force acting on the apple, an internal force within the system (i.e., the apple and the Earth).

So, at the height of 3.0m above the ground, the total mechanical energy (TME) of the system is:

TME = GPE + KE

Since the apple is falling freely, we can assume that all of its potential energy at the height of 4.0m has been converted into kinetic energy just before it hits the ground. Therefore, at the height of 3.0m above the ground, the GPE is:

GPE = (0.21 kg) x (9.81 m/s^2) x (3.0 m) = 6.1359 J

Using the conservation of energy principle, we can find the kinetic energy just before the apple hits the ground:

TME = GPE + KE

KE = TME - GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) - 6.1359 J = 2.0907 J

Therefore, the kinetic energy of the apple just before it hits the ground is 2.0907 J.

To summarize:

Gravitational potential energy (GPE) of the apple at a height of 4.0m above the ground: 8.2266 J

Gravitational potential energy (GPE) of the apple at a height of 3.0m above the ground: 6.1359 J

Kinetic energy (KE) of the apple just before it hits the ground: 2.0907 J

The system's total mechanical energy (TME) is conserved throughout the fall.

Answer:

a) 20.29N

b) 19.43N

c) 15N

Explanation:

To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.

In all these calculations you can asume that one of the vectors coincides with the x-axis.

a)

\(F_R=(9cos(30\°)+12)\hat{i}+(9sin(30\°))\hat{j}\\\\F_R=(19.79N)\hat{i}+(4.5N)\hat{j}\\\\|F_R|=\sqrt{(19.79N)^2+(4.5N)^2}=20.29N\)

b)

\(F_R=(9cos(45\°)+12)\hat{i}+(9sin(45\°))\hat{j}\\\\F_R=(18.36N)\hat{i}+(6.36N)\hat{j}\\\\|F_R|=\sqrt{(18.36N)^2+(6.36N)^2}=19.43N\)

c)

\(F_R=(9cos(90\°)+12)\hat{i}+(9sin(90\°))\hat{j}\\\\F_R=(12N)\hat{i}+(9N)\hat{j}\\\\|F_R|=\sqrt{(12N)^2+(9N)^2}=15N\)

A psychologist will need to have good linguistic intelligence in other to be successful.

This is referred to as a professional who specializes in the handling of mental health challenges in individuals.

It is best for such professional to have a good linguistic intelligence as the right words being said to the patient will solve the problem thereby bringing in more success.

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#A

Refer to attachment

#B

Mass=4.4kg

acceleration=-1.74m/s^2

Use newtons second law

\(\\ \rm\longmapsto Force=ma\)

\(\\ \rm\longmapsto Force=4.4(-1.74)\)

\(\\ \rm\longmapsto Force=-7.656N\)

#C

initial velocity=u

Final velocity=v=0

Acceleration=a=-1.74m/s^2

Time=t=1.27s

\(\\ \rm\longmapsto a=\dfrac{v-u}{t}\)

\(\\ \rm\longmapsto u=v-at\)

\(\\ \rm\longmapsto u=0-(-1.74)(1.27)\)

\(\\ \rm\longmapsto u=1.74(1.27)\)

\(\\ \rm\longmapsto u=2.2m/s\)

The reason why pushing the wall is not work is that the box is moving but the wall is not. option C

In physics, work is defined as the transfer of energy from one system to another as a result of a force acting over a distance. Work is a scalar quantity and is expressed in units of joules (J) or other units of energy.

In physics, work is considered to be positive when the force applied and the distance moved are in the same direction and negative when they are in opposite directions. Work is considered to be zero when the force applied is perpendicular to the direction of motion.

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Answer:

555

Explanation:

L = .5a(t2)

8 = .5a(42)

8 = .5a(16)

8 = 8a

1m/s = a

F l l = 49(sin(30))

F l l = 24.5N FNET = F p - F l  l - F f k And then newtons law: F p - F l l  - F f k = m(a) F p - 24.5 - 21.22 = 5(1) F p = 50.72N

At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

1/f1 = 1/v - 1/u1

1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)

1/f1 = 0 - 4

1/f1 = -4

f1 = -1/4

f1 = -0.25 meters

The initial lens power (P1) is the reciprocal of the focal length:

P1 = 1/f1

P1 = 1/-0.25

P1 = -4 diopters

Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:

1/f2 = 1/v2 - 1/u1

1/f2 = 1/0.40 - 1/0.25

1/f2 = 2.5 - 4

1/f2 = -1.5

f2 = -1/1.5

f2 = -0.67 meters

The final lens power (P2) is the reciprocal of the focal length:

P2 = 1/f2

P2 = 1/-0.67

P2 ≈ -1.49 diopters

Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

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We have that Gravity a force acting down ward against any object and frictional force is a force acting a against  movement, Hence

Generally, Gravity a force acting down ward against any object on earth at an acceleration of about  9.8m/s

and frictional force is a force acting a against the movement based on contact with another surface

Therefore

Gravity is a field force acting downward on the couch:

This is True

Friction from the carpeted floor is a contact force acting against your push.

This is True

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We can  be more intentional on viewing parenting roles differently in order to most benefit our children/students through-

1. Being relational

2. Being consistent

3. Being Instructive

What is intentional Parenting?

Having a strategy and setting priorities for your time and energy is all that constitutes intentional parenting. Our daily decisions and the commitments you make are then influenced by these priorities.Being an intentional parent entails understanding that the time we spend with our children is valuable and finite, and that the choices we make about how to spend that time will have an impact for a lifetime.

Thankfully, successful parenting doesn't demand perfection in these areas of instruction and punishment, but it does call for us to be thoughtful. Therefore, we must keep the following in mind to be intentional parents:

1. Parenting with intention involves relationships.

As children grow older and their lives full with milestones and events, life becomes increasingly busy. Throughout the hectic times of school and extracurricular activities, look for methods to interact frequently. Look for chances to spend time with each of your kids alone. Find moments throughout the day to have fun, play, and converse, even if it is only for a little while.

2. Consistent (even relentless) attention is a hallmark of intentional parenting.

It calls for us to be persistent in our efforts to connect with our children, refusing to give up on potential future connections just because the current one falls short of our expectations. Parenting is not a chore for parents who do it intentionally. Every chance they have to affect their children is seen by them as a wonderful gift.

3. Parenting with intention is instructive.

Kids that grow up in intentional, relational families are frequently eager and willing to learn. Every day, search for opportunities to reinforce prior teachings or find instructive situations. Next, schedule specific, devoted times to concentrate on some larger goals.

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Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

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The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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Explanation:

I have a lot to say it was very nice to meet my parents are u doing well I dont want too its been so much I love you so I was like u know I am not a man but you are the auditions I have been in a long long long life is a triangle and a chair for me and my parents think about the way I

The double-slit experiment, fringes are more widely spaced when illumination is with monochromatic is low frequency light

What is low frequency light?

Light waves have a frequency that is proportional to their energy: Low frequency light is less energetic than high frequency light. Gamma rays therefore have the highest energy, which contributes to their high hazard to humans, whereas radio waves have the lowest energy.

Since the letters in the word "VIBGYOR" are written in decreasing frequency sequence, we can see that Orange has the lowest frequency among the alternatives while Red generally has the lowest frequency.

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Answer:

hi

Explanation:

false because the light of some stars can be very bright, but it can also be very far from the earth.

have a nice day

Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Explanation:

c because there is element

Answer:

C. H2 and N2 would react to produce more NH3

Explanation:

A.P.E.X

Answer:

m=30kg

Explanation:

m=\(\frac{F}{a}\)        ............(1)

F=150N

a=?

a=\(\frac{vf-vi}{t}\)

a=\(\frac{30-10}{4}\)

a=\(\frac{20}{4}\)

a=5ms^-2

Putting the value of "F" and "a" in eq (1),

m=\(\frac{150}{5}\)

Answer: Horizontal force.

The ball did not drop straight down under the force of gravity because the man also acted on the ball with  a horizontal force. So option A is correct

The definition of force is the pushing or pulling of anything. Push and pull are the result of two things interacting with one another. Stretch and crush are two more phrases that can be used to describe force.

The ball did not drop straight down under the force of gravity because the man acted on the ball with a horizontal force.

As the man runs, he moves the ball in a horizontal direction, which causes it to deviate from its straight-down trajectory under gravity and miss the bull's-eye target.

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We are given the following information

Mass = m = 45.0 kg

Initial speed = vi = 40.0 m/s

Time = t = 0.500 s

We are asked to find the average force that the seat belt exerted on her.

Recall from Newton's second law of motion,

Where a is the acceleration of the car and is given by

Where vf is the final velocity of the car that must be 0 since the car was stopped.

The negative sign indicates deacceleration since the card was stopped.

So, the force is

Therefore, the seat belt exerted a force of 3600 N on her.