Answer:
150
Step-by-step explanation:
the formula for this is 2a squared + 4 a h
when we plug everything in we end up getting 2*3 squared + 4*3*11
and when solved it gets toy 150
In a study of the gasoline mileage of model year 2017 automobiles, the mean miles per gallon was 27.5 and the median was 26.8. The smallest value in the study was 12.70 miles per gallon, and the largest was 50.20. The first and third quartiles were 17.95 and 35.45 miles per gallon, respectively. Determine the type of skewness.
Answer:
This is skewed torwards the right. Or in other words positively skewed distribution.
Step-by-step explanation:
All of the values are fairly close together torwards the lower range. While 50.20 is more of an outlier, so this graph would gradualy skew to the right.
Your taxable wages for Social Security purposes are $1100. How much is your Social Security tax if you have previous taxable wages of $102,000?
If you have previous taxable wages of $102,000 and your current taxable wages are $1,100, your Social Security tax would be $6,324 for the previous wages and $68.20 for the current wages.
To calculate the Social Security tax, we need to know the tax rate for Social Security and the taxable wages. Let's assume the Social Security tax rate is 6.2% for both the employee and the employer.
Given that your taxable wages for Social Security purposes are $1,100, and your previous taxable wages are $102,000, we can determine the Social Security tax amount.
First, we need to calculate the Social Security tax on the previous taxable wages of $102,000. Multiply $102,000 by 6.2% (0.062) to find the Social Security tax for that amount:
Social Security tax = $102,000 x 0.062 = $6,324
Next, we calculate the Social Security tax on the current taxable wages of $1,100. Multiply $1,100 by 6.2% to find the tax amount:
Social Security tax = $1,100 x 0.062 = $68.20
Therefore, if you have previous taxable wages of $102,000 and your current taxable wages are $1,100, your Social Security tax would be $6,324 for the previous wages and $68.20 for the current wages.
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Which applies the power of a product rule to simplify (58) 3?
(51) 3 - 51
(50) 3 = 3(51) = 151
(51) 3 - 5343 - 1256
(51) 9 = 53t = 1251
Answer:
Option (3)
Step-by-step explanation:
The given expression is (5t)³
By solving this expression by the product of powers of the exponents,
(5t)³ = (5)³(t)³ [Since (a.b)³ = (a)³.(b)³]
= 125t³
Therefore, Option (3) will be the answer.
the histogram below shows the height distribution for students in a high school math class
Answer:
1. 34 students.
2. 6 is the median height.
3. 10 have 171cm 4 have 190cm.
4. 2 students have no taller than 171cm.
Step-by-step explanation:
I really can't explain it because it hard to explain how i answered your question.
On a field trip, the ration of students who brought a water bottle to those who didn’t was 7 to 4. If 60 students did not bring water bottle, determine the total number of students on the field trip.
Answer:
165 students
Step-by-step explanation:
7/4 = x/60
(60*7)/4 = 105
105 + 60 = 165
8. Simplify (+2) × (+6) (-3)
Step-by-step explanation:
= ( +2 ) × ( + 6 ) ( -3 )
= + 12 (- 3 )
\( = - 36\)
hence - 36 is the answer...
Madison is in the business of manufacturing phones. She must pay a daily fixed cost of $400 to rent the building and equipment, and also pays a cost of $125 per phone produced for materials and labor. Make a table of values and then write an equation for C,C, in terms of p,p, representing total cost, in dollars, of producing pp phones in a given day.
The equation that represents the total cost is C = $400 + $125p .
What is the total cost?The equation that represents the total cost is a function of the fixed cost and the variable cost. The fixed cost remains constant regardless of the level of output. The variable cost changes with the level of output.
Total cost = fixed cost + total variable cost
Total cost = fixed cost + (variable cost x total output)
C = $400 + ($125 x p)
C = $400 + $125p
Total cost when 0 phones are made = $400 + $125(0) = $400
Total cost when 1 phone are made = $400 + $125(1) = $525
Total cost when 2 phones are made = $400 + $125(2) = $650
Total cost when 3 phones are made = $400 + $125(3) = $775
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A distribution with three or more peaks is said to be
When a distribution has three or more peaks then it is said to be a multimodal distribution .
What are the types of distributions ?In histograms, there are often three types of distributions which are classified according to the number of peaks that they have . A unimodal distribution would be a histogram that has a single peak in its distribution .
Then there are binomial distributions which boast of having two peaks , Then finally, there is the multimodal distribution which is for all distributions with either three peaks, or more than that .
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Find the mean, median, mode 1. 40, 38,29,34,37, 22, 15, 38 2. 26, 32, 12, 18, 11, 14, 21, 12,27 3. 3,3,4,7,5,7,6,7,8,8,8. 9,8, 10, 12, 9, 15, 15
NEED THE ANSWER ASAP
NONSENSE, REPORT
i will (brainliest) if it's correct!!!
Mean: 34.125, Median: 31.5, Mode: 38
Mean: 19.222, Median: 18, No mode
Mean: 8.611, Median: 8, Mode: 8
Let's find the mean, median, and mode for each set of numbers:
Set: 40, 38, 29, 34, 37, 22, 15, 38
Mean: To find the mean, we sum up all the numbers and divide by the total count:
Mean = (40 + 38 + 29 + 34 + 37 + 22 + 15 + 38) / 8 = 273 / 8 = 34.125
Median: To find the median, we arrange the numbers in ascending order and find the middle value:
Arranged set: 15, 22, 29, 34, 37, 38, 38, 40
Median = (29 + 34) / 2 = 63 / 2 = 31.5
Mode: The mode is the number(s) that appear(s) most frequently in the set:
Mode = 38 (appears twice)
Set: 26, 32, 12, 18, 11, 14, 21, 12, 27
Mean: Mean = (26 + 32 + 12 + 18 + 11 + 14 + 21 + 12 + 27) / 9 = 173 / 9 ≈ 19.222
Median: Arranged set: 11, 12, 12, 14, 18, 21, 26, 27, 32
Median = 18
Mode: No mode (all numbers appear only once)
Set: 3, 3, 4, 7, 5, 7, 6, 7, 8, 8, 8, 9, 8, 10, 12, 9, 15, 15
Mean: Mean = (3 + 3 + 4 + 7 + 5 + 7 + 6 + 7 + 8 + 8 + 8 + 9 + 8 + 10 + 12 + 9 + 15 + 15) / 18 ≈ 8.611
Median: Arranged set: 3, 3, 4, 5, 6, 7, 7, 7, 8, 8, 8, 8, 9, 9, 10, 12, 15, 15
Median = 8
Mode: Mode = 8 (appears 4 times)
Mean: 34.125, Median: 31.5, Mode: 38
Mean: 19.222, Median: 18, No mode
Mean: 8.611, Median: 8, Mode: 8
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Solve for x. I attached the question. Pls help me :(
Answer:
x = 16°
Step-by-step explanation:
What we know:
∠JML = 47°
∠JKL = (7x + 21)°
∠JML is an inscribed angle
∠JKL is an inscribed angle
Inscribed angles are half of the value of their intercepted arc
So if m∠JML = 47° then mArc JL is double that or 94°
And ∠JKL is intercepted by Arc JML which is the rest of the circle not intercepted by ∠JML so
mArc JL + Arc JML = 360°
94 + Arc JML = 360
Subtract 94 from both sides to isolate Arc JML
Arc JML = 266°
So if Arc JML = 266° then it's intercepted inscribed angle is half of that.
Arc JML ÷ 2 = ∠JKL
266 ÷ 2 = ∠JKL
133 °= ∠JKL
Now we can use this value and set it equal to the expression to find the value of x
(7x + 21) = 133
Subtract 21 from both sides to isolate the x
7x = 112
Divide both sides by 7
x = 16
What is a point-slope equation of the line with slope -12 that goes through the point (5, 3)?
A. y- 3 = -12(x - 5)
B. y + 3 = 12(x + 5)
C. y + 3 =-12(x + 5)
D.y-3 = 12(x - 5)
Answer:
A. y- 3 = -12(x - 5)
Step-by-step explanation:
The nth term of a sequence is 5n + 1.
Which of these statements is true?
None of the terms are multiples of 5.
All of the terms are multiples of 5.
Oo
Some of the terms are multiples of 5.
Answer:
2nd option
Step-by-step explanation:
note that
5n ← generates multiples of 5, that is
5 × 1 = 5
5 × 2 = 10
5 × 3 = 15
5 × 4 = 20 , etc
5, 10, 15, 20, ....... are multiples of 5
but 5n + 1 does not generate multiples of 5 as
5 + 1 = 6
10 + 1 = 11
15 + 1 = 16
20 + 1 = 21
6, 11, 16, 21 are not multiples of 5
what is the gradient?
Answer:
\( \frac{3}{2} \)Step-by-step explanation:
hi thereas we know gradient of Graf=\( \frac{∆y}{∆x} \)
\( \frac{3}{2} \)1 A. All master photographers are artists.
2. Ansel Adams is a master photographer.
Therefore, Ansel Adams is an artist.
B. 1. All master photographers are artists.
2. Ansel Adams is an artist.
Therefore, Ansel Adams is a master photographer.
Answer:
A is the appropriate option.
Step-by-step explanation:
The question given is a conditional statement.
With the condition that all master photographers are artist. This implies that any person who is a master photographer is automatically an artist.
A. Comparing the statement here, since Ansel Adam's is a master photographer, he is an artist.
B. Ansel Adams is an artist, but it is possible that not all artists are master photographer.
A is the correct option.
1. All master photographers are artists.
2. Ansel Adams is a master photographer.
Therefore, Ansel Adams is an artist.
Answer:
The correct answer is A.
Step-by-step explanation:
Please help me with this, I am not sure what to do.
Since \(x\) is approaching 1 from the left/below, we take the part of \(f(x)\) that is defined over \(x<1\), for which we have
\(f(x) = \dfrac{x-1}{\sqrt{x-1}}\)
Since \(x\neq1\), we can simplify this to
\(f(x) = \dfrac{x-1}{(x-1)^{1/2}} = (x-1)^{1/2} = \sqrt{x-1}\)
and this is continuous at \(x=1\), so we can evaluate the limit by directly substituting \(x\).
To summarize:
\(\displaystyle \lim_{x\to1^-} f(x) = \lim_{x\to1} \frac{x-1}{\sqrt{x-1}} = \lim_{x\to1} \sqrt{x-1} = \sqrt{1-1} = \boxed{0}\)
Find two square numbers that total 45
PLS HELP 50 POINTS!!
The line segment FG represent the volume of water decreases in Katherine's water bottle.
From the given graph, x-axis represents the distance from home (km) and the y-axis represents the volume (L).
The line segment FG represent the volume of water decreases in Katherine's water bottle, the line segment HI represent the volume of water increases in Katherine's water bottle and the line segment KL represents there is no change in water level.
Therefore, the line segment FG represent the volume of water decreases in Katherine's water bottle.
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TAKE MY POINTS pleaseeee
Answer:
156 M
Reasoning you add How far He has walked from his starting point
Step-by-step explanation:
Answer: 156 m here u go
Use the image to determine the direction and angle of rotation. Graph of triangle ABC in quadrant 1 with point A at 1 comma 3. A second polygon A prime B prime C prime in quadrant 4 with point A prime at 3 comma negative 1. 90° clockwise rotation 180° clockwise rotation 180° counterclockwise rotation 90° counterclockwise rotation
Shen bought a desk on sale for $218.40. This price was 72% less than the original price. What was the original price?
Answer:
780
Step-by-step explanation:
In this example we will call Original Price = y
72%=0.72
218.40=0.72*y
1-0.72=0.28
218.4÷0.28=780
Determine the unknown length. Round your answer to the nearest tenth, if necessary.
Answer:
16
Step-by-step explanation:
a^2+b^2=c^2
a^2+12^2=20^2
144+a^2=400
a^2=256
a=16
Simplify the following polynomial expression.
Answer:
D. 5x^4 -37x^3 -6x^2 +41x -6
Step-by-step explanation:
We really only need to look at the first and last terms to determine which answer choice to select.
The x^4 term in the sum will be ...
5x^4 -8x^4 -(-4x^3)(2x) = (5 -8 +8)x^4 = 5x^4
The constant term in the sum will be ...
(-1) +(2) -(-1)(-7) = -1 +2 -7 = -6
The only answer choice matching these first and last terms is Choice D.
_____
Additional comment
You can work out the other three terms as ...
-9x^3 -(-4x^3)(-7) = (-9 -28)x^3 = -37x^3
4x^2 -(5x)(2x) = (4 -10)x^2 = -6x^2
(7x) +(-3x) -(5x(-7) -1(2x)) = (7 -3 +35 +2)x = 41x
These all match choice D.
The tables of ordered pairs represent some points on the graphs of two lines. What is the solution to the system of equations represented by the two lines? There are no zeroes on the chart. What do I do
To find the solution to the system of equations represented by the two lines based on the given tables of ordered pairs, you can follow these steps:
Examine the tables and identify a pattern or relationship between the x-values and y-values for each line.Determine the slope (rate of change) of each line by calculating the difference in y-values divided by the difference in x-values for any two points on the line.Once you have the slopes, compare them to see if they are equal or different.If the slopes are different, the lines intersect at a single point, which represents the solution to the system of equations.If the slopes are equal, the lines are parallel, and there is no solution to the system of equations.If the slopes are different, you can find the intersection point by solving the system of equations using either substitution, elimination, or another suitable method.For such more question on equations
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Help pls!! Determine whether each value is greater for function Q, the same for both functions, or greater for function R
The following conclusion about both functions are:
The initial value for function R (3) is greater than that for function Q (-2).The rate of change for function Q (3) is greater than that for function R (1/3).What is a Linear Function?A linear function is modelled as, y = mx + b
b is initial valuem is the rate of change = change in y/change in x.Function Q:
y = 3x - 2
Initial value (b) = -2
Rate of change (m) = 3
Function R:
Initial value = 3
Rate of change = 1/3
Therefore, the following conclusion about both functions can be made:
The initial value for function R (3) is greater than that for function Q (-2).The rate of change for function Q (3) is greater than that for function R (1/3).Learn more about linear functions on:
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Which statement best describes a strategy for estimating the perimeter of the figure below if the grid squares have
side lengths 1 cm?
Add the lengths of the horizontal and vertical segments, and then subtract 5 because the diagonal side is 4 units
wide and 2 units tall.
O Add the lengths of the horizontal and vertical segments, and then subtract 3 because the diagonal side is 4 units
wide but only 2 units tall.
O Add the lengths of the horizontal and vertical segments, and then add 3 because the diagonal side is 4 units wide
but only 2 units tall.
O Add the lengths of the horizontal and vertical segments, and then add 5 because the diagonal side is 4 units wide
and 2 units tall.
The best statement that describes the strategy for estimating the perimeter of the figure (please see the attached diagram) is the option;
Ad the lengths of the horizontal and vertical segments, and then add 5 because the diagonal side is 4 units wide and 2 units tall
What is an estimate of an amount?An estimate is an approximation of a true value, which is a value that is close to the actual value of the measured quantity.
Please find attached a diagram of the possible figure created with MS Word
The length of the side of the sides of the possible figure in the figure, obtained from a similar question on the internet are;
Base length = 5 units
Height = 4 units
The figure has a diagonal side which is 4 units wide and 2 units tall.
The length of the slant side, found using Pythagorean theorem can be obtained as follows; Length = √(4² + 2²) = 2·√5 ≈ 5
The correct option is therefore to add the lengths of the horizontal and vertical segments, and then add 5 because the diagonal side is 4 units wide and 2 units tall
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Fill in the missing statements and reasons for the proof. Given ∠2 ≅ ∠3 proof ∠1 ≅ ∠4
The proof is given as follows:
∠1 ≅ ∠2 - Vertical Angles are ≅∠2 ≅ 3 - Given∠3 ≅4 - Vertical Angles are ≅Thus, ∠1 ≅ 4 Transitive properties.What are transitive properties?The transitive property argues that "if two quantities are equal to the third quantity, then we may claim that all the quantities are equal to one other".
The term transitive refers to a transfer. If there are three quantities a, b, and c, and if an is connected to b by some rule and b is related to c by the same method, then a and c are related to each other by the same rule; this property is known as the transitive property of equality.
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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A mayoral candidate in a large metropolitan area has hired you to take a poll to determine the proportion of registered voters who plan to vote for him. He would like you to report a 95% confidence interval with a margin of error no more than 0.04. Whiat is the smallest sample size that will produce an interval with these specifications?
Answer:
The smallest sample size that will produce an interval with these specifications is 601.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.
\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)
In which
z is the zscore that has a pvalue of \(1 - \frac{\alpha}{2}\).
The margin of error is:
\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)
95% confidence level
So \(\alpha = 0.05\), z is the value of Z that has a pvalue of \(1 - \frac{0.05}{2} = 0.975\), so \(Z = 1.96\).
He would like you to report a 95% confidence interval with a margin of error no more than 0.04. What is the smallest sample size that will produce an interval with these specifications?
We have to find n for which M = 0.04.
We dont know the true proportion, so we use \(\pi = 0.5\), which is when the smallest sample size needed will have it's largest value.
\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)
\(0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}\)
\(0.04\sqrt{n} = 1.96*0.5\)
\(\sqrt{n} = \frac{1.96*0.5}{0.04}\)
\((\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2\)
\(n = 600.25\)
Rounding up
The smallest sample size that will produce an interval with these specifications is 601.
which statement explains the relationship between corresponding terms in the table? no links please
Dawn spent $26.50, including sales tax, on 4 books and 3 folders. The books cost $5.33 each and the total sales tax was $1.73.
How much was each folder?
Explain your process and justify your reasoning.
Answer:
1.15
Step-by-step explanation:
26.50-1.73= 24.77
Each book was 5.33 and since there was 4 of them:
5.33 x 4 = 21.32
We subtract from the original answer
24.77- 21.32 = 3.45
3.45/3 = 1.15
Hope this makes sense