pls help me !! i’ll give brainliest !!

Answer:

They buy at wholesale and sell at an 80% markup. The retail prices are;

0 - 20 pairs.

= 25 * 1.80

= $45.00

21 - 40 pairs

= 23 * 1.80

= $41.40

41 - 60 pairs

= 21 * 1.80

= $37.80

61 - 80 pairs

= 19 * 1.80

= $34.20

81 or more pairs

= 17 * 1.80

= $30.60

The volume of the cone is 1/3.

If a prism and a cone have the same base area and the same height, we can use the formula for the volume of each shape to find the volume of the cone.

The volume of a prism is given by V_prism = base area × height. Since the volume of the prism is given as 1, we can write:

1 = base area × height

The volume of a cone is given by V_cone = (1/3) × base area × height. Since the base area and the height are the same as the prism, we can substitute them into the formula:

V_cone = (1/3) × base area × height = (1/3) × 1 = 1/3

Therefore, the volume of the cone is 1/3.

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Answer:

Wheres the question I need it

Answer:

54 square miles

Step-by-step explanation:

The easiest thing to do is to separate the figure into one 5x9 rectangle and one 3x3 square. The rectangle area is 5x9=45 square miles and the square is 3x3=9 square miles. So total is 45+9=54 square miles.

Answer:

x-10

Step-by-step explanation:

Answer:

X - 10

Step-by-step explanation:

Just took the test on A P E X

Answer:

The sequence is arithmetic and the common difference is -6.

Answer:

the common difference is -6

because 87-6=81

81-6=75

like that

y = e^((1/2)(tan(x) + C)) is the solution to the given differential equation.

To solve the given differential equation (y^2 + 2) dx = y sec^2(x) dy, follow these steps:

Step 1: Rewrite the equation as a separable differential equation.
To do this, divide both sides by y(y^2 + 2) to isolate dx and dy:

(dy/y) = (sec^2(x) dx) / (y^2 + 2)

Step 2: Integrate both sides of the equation.
Integrate the left side with respect to y, and the right side with respect to x:

∫(1/y) dy = ∫(sec^2(x) / (y^2 + 2)) dx

Step 3: Evaluate the integrals.
For the left side, the integral of 1/y with respect to y is ln|y| + C₁ (where C₁ is a constant).
For the right side, let u = y^2 + 2, then du = 2y dy, so the integral becomes:

∫(sec^2(x) / u) (1/2) du = (1/2) ∫(sec^2(x) du)

Now, the integral of sec^2(x) with respect to u is tan(x) + C₂ (where C₂ is another constant).

Step 4: Combine the constants and express the solution.
The general solution is given by:

ln|y| = (1/2)(tan(x) + C), where C = 2(C₁ - C₂).

To express y in terms of x, take the exponential of both sides:

y = e^((1/2)(tan(x) + C))

This is the solution to the given differential equation.

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There are 2 rearrangements of abcd in which no two adjacent letters are also adjacent letters in the alphabet.

What is letter arrangements?

A sorting technique that allows the person to arrange alphabets as conditioned according to the question. Then total arrangements are calculated to know the result.

According to the given question:

Using XXXX as stencil for letters arrangement

We can't put B in either of the middle positions, as there would only be the far end at which to put both A and C and we can't put two things in one slot. That is, XBXX would require A and C to both be in the red X in order to avoid putting them next to B...can't do that, so B can't go in the middle.

Similarly, we can't put C in either of the middle positions, as there would only be the far end at which to put both B and D and we can't put two things in one slot.

So, B and C must go on the ends.

BXXC can only be filled in as BDAC.

CXXB can only be filled in as CADB.

Hence there are 2 such arrangements.

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Answer:

  θ = {π/6, 5π/6} +2kπ . . . . for any integer k

Step-by-step explanation:

Multiplying by the product of the denominators, we can simplify this to ...

  sin(θ)² +(1+cos(θ))² = 4sin(θ)(1+cos(θ))

  sin(θ)² +1 +2cos(θ) +cos(θ)² = 4sin(θ)+4sin(θ)cos(θ)

  2 +2cos(θ) = 2sin(θ)(2 +2cos(θ)) . . . . show similar factors

  2(2sin(θ) -1)(1 +cos(θ)) = 0 . . . . subtract left side, complete the factoring

These factors are zero when ...

  2sin(θ) -1 = 0   ⇒   sin(θ) = 1/2   ⇒   θ = π/6, 5π/6

  1 +cos(θ) = 0 . . . . . extraneous solution; makes equation undefined

__

Solutions are periodic with period 2π, so the complete solution set is ...

 θ = {π/6, 5π/6} +2kπ . . . . for any integer k

Answer:

222

Step-by-step explanation:

Find the average of the 2 numbers , that is

average = \(\frac{sum}{count}\) = \(\frac{123+321}{2}\) = \(\frac{444}{2}\) = 222

Organizational culture is defined as the common beliefs, values, attitudes, customs, behaviors, and traditions that characterize a specific organization and determine the manner in which it functions. Organizational culture is set by the manager.

In a corporate or business environment, organizational culture can influence the daily operations of employees. It is the responsibility of managers to create a positive culture that emphasizes teamwork, respect, integrity, and accountability. The manager is an essential individual responsible for establishing and maintaining the organization's culture, which will ultimately define the employee's attitudes, behaviors, and productivity levels. He or she sets the tone for the workplace by creating an environment that fosters collaboration, innovation, and success. Employees need to feel connected to their workplace and colleagues to be motivated to do their best work. If a manager promotes a culture of fear, competition, or dishonesty, employees may become unmotivated or unproductive. An effective manager understands the importance of creating a positive workplace culture and works hard to establish and maintain it. Managers can establish a positive culture by encouraging open communication, providing regular feedback and recognition, fostering a sense of teamwork, creating opportunities for professional development, and setting high standards for performance. Managers must lead by example and demonstrate the behaviors and attitudes that they expect from their employees. They must hold themselves and others accountable for their actions, communicate expectations clearly, and provide support when needed. A positive organizational culture will enable an organization to attract and retain top talent, increase employee engagement, and promote collaboration and innovation.

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The square root of √(14 - 8√3) simplifies to ±√(14 + 8√3).

To simplify the expression √(14 - 8√3), we can follow these steps:

Let's assume √(14 - 8√3) = x.

Square both sides of the equation to eliminate the square root:

(√(14 - 8√3))² = x²

14 - 8√3 = x²

Rearrange the equation to isolate the radical term:

8√3 = x² - 14

To simplify further, let's solve for x by isolating the radical term:

x² = 8√3 + 14

x² = 14 + 8√3

Now, we can solve for x by taking the square root of both sides:

x = ±√(14 + 8√3)

In order to simplify the phrase (14 - 8), we may do the following:

Assume that (14 - 83) equals x.

To get rid of the square root, square both sides of the equation:

(√(14 - 8√3))² = x²

14 - 8√3 = x²

To find the radical term, reorder the equation:

8√3 = x² - 14

Let's solve for x using the radical term alone to further simplify the problem:

x² = 8√3 + 14 x² = 14 + 8√3

By taking the square root of both sides, we can now find x:

x = ±√(14 + 8√3)

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(a) The real discrete Fourier transform (DFT) is calculated for the given data set to analyze the helicopter's acoustic signature.

(b) To obtain the ck values and illustrate the relative size of each term in the Fourier series, we calculate the magnitude of each coefficient and plot their amplitudes on a bar graph against the corresponding frequency component, k.

To analyze the helicopter's acoustic signature, the real DFT is computed for the provided data set. The DFT transforms the time-domain measurements of acoustic pressure into the frequency domain, revealing the different frequencies present and their corresponding amplitudes. This analysis helps in understanding the spectral characteristics of the helicopter's acoustic signature and identifying prominent frequency components.

Using the Fourier series representation, the amplitudes (ck's) of the different frequency components in the Fourier series are determined. These amplitudes represent the relative sizes of each term in the series, indicating the contribution of each frequency component to the overall acoustic signature. By plotting the amplitudes on a bar graph, the relative strengths of different frequency components become visually apparent, enabling a clear comparison of their importance in characterizing the helicopter's acoustic signature.

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Using a system of equations, there are 19 horses and 18 chickens in the field.

Let's solve this problem using a system of equations.

Let's assume:

x = number of horses

y = number of chickens

We can set up the following equations based on the given information:

Equation 1: The total number of heads: x + y = 37

Equation 2: The total number of feet: 4x + 2y = 112

We have two equations with two unknowns, so we can solve this system of equations.

From Equation 1, we can solve for x in terms of y:

x = 37 - y

Substituting this value of x into Equation 2, we get:

4(37 - y) + 2y = 112

148 - 4y + 2y = 112

-2y = 112 - 148

-2y = -36

y = -36 / -2

y = 18

Now that we have the value of y, we can substitute it back into Equation 1 to find x:

x + 18 = 37

x = 37 - 18

x = 19

The correct question is:

A farmer notes that in a field full of horses and chickens there are 37 heads and 112 feet. How many of each animal are there?

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The optimal solution for the given linear programming problem using the Big-M method is x₁ = 4, x₂ = 2, with a maximum value of Z = 22.

To solve the given linear programming problem using the Big-M method, we first convert it into standard form by introducing slack, surplus, and artificial variables.

The objective function is to maximize Z = 4x₁ + 3x₂. The constraints are 2x₁ + x₂ ≥ 10, -3x₁ + 2x₂ ≤ 6, x₁ + x₂ ≥ 6, and x₁, x₂ ≥ 0.

We introduce slack variables s₁, s₂, and s₃ to convert the inequalities into equalities. The initial Big-M tableau is set up with the coefficients and variables, and the artificial variables are introduced to handle the inequalities. We set a large positive value (M) for the artificial variables' coefficients.

In the first iteration, we choose the most negative coefficient in the Z-row, which is -4 corresponding to x₁. We select the s₂-row as the pivot row since it has the minimum ratio of the RHS value (6) to the coefficient in the pivot column (-3). We perform row operations to make the pivot element 1 and other elements in the pivot column 0.

After multiple iterations, we find that the optimal solution is x₁ = 4, x₂ = 2, with a maximum value of Z = 22. This means that to maximize the objective function, x₁ should be set to 4 and x₂ should be set to 2, resulting in a maximum value of Z as 22." short

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An equation of the plane through the point (-1, -5, 1) and perpendicular to the vector (5, 4, 2) can be -4x + 5y - 2z = 11.

First, the normal vector of the plane must be determined. The vector perpendicular to the given vector (5, 4, 2) is (-4, 5, -2).

Now, the equation of the plane can be determined using the given point and the normal vector. The standard form of the equation of a plane is Ax + By + Cz = D.

We can use the point (-1, -5, 1) and the normal vector (-4, 5, -2) to calculate the values of A, B, C, and D in the equation. To do this, we can use the point-normal form of the equation of a plane.

The point-normal form is (x - x1) × nx + (y - y1) × ny + (z - z1) × nz = 0. We can plug in the point and normal vector values into this equation to calculate A, B, C, and D.

Therefore, the equation of the plane is -4x + 5y - 2z = 11.

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Answer:

true

Step-by-step explanation:

Hope this helps. :)

We can write the value of 6 hundred thousandths by using multiplication and the required value is 6,00,000.

This problem can be done by using multiplication. Like 6 hundred can be multiplied with the thousand then the value gets. We can write the value of 6 hundred thousandths by using multiplication and the required value is 6lakhs.

In mathematics, the number has ones place, tens place and hundreds place, thousands place. So, by that we can conclude the required value.

The value can be get by multiplying the given terms

Given 600 and multiplied by thousandths

600 * 1000 = 6,00,000

So, the required value is 6 lakhs or 6,00,000.

Therefore, this problem can be done by using multiplication. Like 6 hundred can be multiplied with the thousand then the value gets. We can write the value of 6 hundred thousandths by using multiplication and the required value is 6lakhs.

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h(x) = -7/6x - 25/6.

Given h(-1)=-2 and h(-7)=-9

For linear function h(x), we can use slope-intercept form which is y = mx + b, where m is the slope and b is the y-intercept.

To find m, we can use the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line.

h(-1) = -2 is a point on the line, so we can write it as (-1, -2).

h(-7) = -9 is another point on the line, so we can write it as (-7, -9).

Now we can find m using these points: m = (-9 - (-2)) / (-7 - (-1)) = (-9 + 2) / (-7 + 1) = -7/6

Now we can find b using one of the points and m. Let's use (-1, -2):

y = mx + b-2 = (-7/6)(-1) + b-2 = 7/6 + b

b = -25/6

Therefore, the linear function h(x) is:h(x) = -7/6x - 25/6

We can check our answer by plugging in the two given points:

h(-1) = (-7/6)(-1) - 25/6 = -2h(-7) = (-7/6)(-7) - 25/6 = -9

The answer is h(x) = -7/6x - 25/6.

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The percentage of the automobiles have an average miles per gallon between 38.7 miles per gallon and 48.9 miles per gallon is, 68%

We have to give that,

The average miles per gallon of a particular automobile model are approximately normally distributed with a given mean = 43.8 miles per gallon and standard deviation = 5.1 miles per gallon.

The formula for the mean is,

z = (X - μ) / σ

Where, σ = standard deviation

μ = mean of the observation.

Here, x = 38.7 miles /gallon

z₁ = (38.7 - 43.8)/5.1

z₁ = 1

For x = 48.9 miles/gallon

z₂ = (48.9 - 43.8) / 5.1

z₂ = 1

Using standard Z-table: for z₁ and z₂,

For z₁ = -1 , the value from Z table = 0.1587

For z₂ = 1  , the value from Z table = 0.8413

Percentage of automobiles have an average miles per gallon between 38.7 miles per gallon and 48.9 miles per gallon:

=0.8413 - 0.1587

= 0.6826

= 68.26%

= 68%

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Complete question is,

The average miles per gallon of a particular automobile model are approximately normally distributed with a given mean = 43.8 miles per gallon and standard deviation = 5.1 miles per gallon. What percentage of the automobiles have an average miles per gallon between 38.7 miles per gallon and 48.9 miles per gallon?

a.68%

b.75%

c.95%

d.100%

Answer:

b=d

x=

bStep-by-step explanation:

The graph can be used to determine how many gallons of water will be left in the pool.  It can also be used to estimate the rate of decrease of water in the pool over time.

The given graph shows the relationship between the number of gallons of water remaining in the pool and the number of hours the pool has drained. As time passes, the number of gallons of water in the pool decreases.

The graph shows an exponential decay function, where the number of gallons of water remaining in the pool decreases rapidly at the beginning, then the rate of decrease slows down over time. This is because the amount of water draining from the pool depends on the amount of water remaining in the pool. As the amount of water decreases, there is less water to drain, and the rate of decrease slows down.

The graph can be used to determine how many gallons of water will be left in the pool after a certain amount of time, or how long it will take to drain the pool completely. It can also be used to estimate the rate of decrease of water in the pool over time.

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Answer:

Yes!

Step-by-step explanation:

28 - 4t = 3t

Isolate t:

28 = 7t

t = 28 / 7 = 4

Therefore, there are number of 120 ways to fill the three roles in the play from the ten students auditioning.

Given that,

Roll can be filled = 3

Here we use concept of combinations:

We know that,

Selections are another name for combinations.

Combinations are the choosing of items from a given collection of items. We do not want to arrange anything here.

We aim to choose them.

The number of distinct r-selections or combinations from a set of n items is denoted by \(^{n}C_{r}\).

The number of ways to choose a group of r items from a larger group of n items is given by the following formula:

\(^{n}C_{r}\) = n! / (r!  (n-r)!)

In this case, we have n = 10 (the number of students auditioning) and r = 3 (the number of roles to be filled).

So, the number of ways to choose 3 roles from 10 students is:

\(^{10}C_{3}\) = 10! / (3! * (10-3)!) = 120

Hence,

There are 120 wats of filling.

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Step-by-step explanation:

l=✓9²+4²

l=√81+16

l=✓97

f(x) = x is a simple linear function with a slope of 1, f(x) = 3 5 6 is a constant function, f(x) = 3-x is a linear function with a negative slope of -1,  f(x) = 1 is a constant function, f(x) = 2 is a constant function

A constant function is a mathematical function whose output value is the same for every input value

From the given parameters, f(x) = x is a simple linear function with a slope of 1, this implies  that for every unit increase in x, the value of y increases by 1.

Also,  f(x) = 3 5 6 is a constant function, where the value of y is always 3 5 6, regardless of the value of x.

In the same way,  f(x) = 3-x is a linear function with a negative slope of -1, which means that for every unit increase in x, the value of y decreases by 1. The fourth function f(x) = 1 is a constant function, where the value of y is always 1, regardless of the value of x.

The domain of the fifth function is 3 0, which means that x can take any value between 3 and 0.

The sixth function f(x) = 2 is a constant function, where the value of y is always 2, regardless of the value of x.

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Answer:

b i took the test

Step-by-step explanation:

The level of significance is type I error

The level of significance is the measurement of the statistical significance. It defines whether the null hypothesis is assumed to be accepted or rejected.

In statistical hypothesis testing, a type I error is the mistaken rejection of an actually true null hypothesis, while a type II error is the failure to reject a null hypothesis that is actually false.

Beta error is the statistical error (said to be 'of the second kind,' or type II) that is made in testing when it is concluded that something is negative when it really is positive.

Here, Level of significance is the type I error because a type I error is a kind of fault that occurs during the hypothesis testing process when a null hypothesis is rejected, even though it is accurate

Hence, the level of significance is type I error

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Answer:

3.287 Customers

Step-by-step explanation:

Interarrival time (a) = 60 seconds per minute / 190 customers per minute = 0.316 seconds.

Utilization = p / (a × m) = 2 / (0.316 × 8) = 0.792.

Number in queue = Tq / a = 1.038 / 0.316 = 3.287 customers.

The 95% confidence interval for the mean difference in price per gallon of diesel fuel and regular unleaded gasoline is approximately (-0.209, 0.369). The interval includes zero, indicating no convincing evidence of a significant difference between the two fuel types.

To construct a 95% confidence interval for the true mean difference in the price per gallon of diesel fuel and regular unleaded gasoline, we can use the provided data. The sample mean difference is calculated by taking the average of the observed differences, and the standard error of the mean difference is calculated using the formula mentioned earlier.

From the given data, the sample mean difference is 0.08 (calculated as the average of the observed differences), and the standard error of the mean difference is 0.135.

To calculate the confidence interval, we need the critical value corresponding to a 95% confidence level. Since the sample size is not provided, we'll assume a reasonably large sample size and use the critical value of 1.96 for a two-tailed 95% confidence interval.

Using the formula for the confidence interval

Confidence Interval = D ± (t * SE(D))

Confidence Interval = 0.08 ± (1.96 * 0.135)

Calculating the confidence interval

Lower bound = 0.08 - (1.96 * 0.135) ≈ -0.209

Upper bound = 0.08 + (1.96 * 0.135) ≈ 0.369

The 95% confidence interval for the true mean difference in the price per gallon of diesel fuel and regular unleaded gasoline is approximately (-0.209, 0.369).

Since the confidence interval contains both positive and negative values, including zero, we can conclude that there is not convincing evidence of a statistically significant difference in the mean price per gallon of diesel fuel and regular unleaded gasoline.

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--The given question is incomplete, the complete question is given below "  Construct and interpret a 95% confidence interval for the true mean difference. Does the interval provide convincing evidence of a difference in the mean price per gallon of diesel fuel and regular unleaded gasoline? OH OH OH OH OH OH OH IN 0 IN IN Regular Unleaded 2.27 2.25 2.25 2.25 2.25 2.29 2.07 2.15 2.14 2.07 2.07 2.14 2.29 2.25 2.29 2.25 2.25 2.19 Diesel 2.15 2.35 1.85 2.47 2.45 2.47 2.28 2.28 2.28 2.29 2.28 2.28 2.26 2.24 2.26 2.27 2.25 2.39 Difference -0.12 0.1 -0.4 0.22 0.2 0.18 0.21 0.13 0.14 0.22 0.21 0.14 -0.03 -0.01 -0.03 0.02 0 0.2 2 IN IN IN HE IN IN IN 3 IN IL IN IN IN 0.14 0.22 IN IN IN IN 0.21 0.14 -0.03 -0.01 -0.03 0.02 IN IN IL 2.14 2.07 2.07 2.14 2.29 2.25 2.29 2.25 2.25 2.19 2.29 2.29 1.99 1.99 1.99 1.99 1.99 1.99 2.28 2.29 2.28 2.28 2.26 2.24 2.26 2.27 2.25 2.39 2.35 2.35 2.41 2.45 2.38 2.47 2.39 2.47 0 0.2 IL IL IL 0.06 0.06 0.42 0.46 0.39 0.48 0.4 0.48 IL IL IL IL IL IL IL ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ ΜΟ 2.25 2.19 2.35 2.19 2.19 2.17 2.17 2.17 2.17 2.19 2.19 2.06 2.15 2.04 2.04 1.89 1.87 1.99 2.35 2.38 2.39 2.06 2.06 2.06 2.06 2.07 2.09 2.06 2.06 2.13 2.13 1.99 1.95 2.05 2.25 2.07 0.1 0.19 0.04 -0.13 -0.13 -0.11 -0.11 -0.1 -0.08 -0.13 -0.13 0.07 -0.02 -0.05 -0.09 0.16 0.38 0.08 MO MO MO MO MO MO MO KS KS KS KS 1.95 1.99 1.99 1.99 1.91 1.87 1.99 2.05 2.05 1.97 1.88 1.87 1.89 1.89 1.99 2.25 1.89 2.09 2.18 2.21 2.07 2.09 2.15 2.18 2.05 2.04 2.04 2.34 2.35 2.23 2.35 2.16 2.15 2.18 2.04 2.27 0.23 0.22 0.08 0.1 0.24 0.31 0.06 -0.01 -0.01 0.37 0.47 0.36 0.46 0.27 0.16 -0.07 0.15 0.18 KS KS KS KS KS KS KS KS KS KS KS KS KS KS KS KS CO CO СО CO CO CO CO СО Co 1.96 1.99 2.09 2.11 2.09 2.09 1.93 1.93 1.97 2.14 2.21 2.05 2.05 2.15 2.05 2.19 2.09 2.07 2.15 2.33 2.23 2.19 2.29 2.34 2.24 2.39 2.15 2.18 2.18 2.37 2.35 2.28 2.09 2.09 2.35 1.99 0.19 0.34 0.14 0.08 0.2. 0.25 0.31 0.46 0.18 0.04 -0.03 0.32 0.3 0.13 0.04 -0.1 0.26 0.08 "--