Answer:
x= 2b-a
Step-by-step explanation:
Answer:
x=2b-a
Step-by-step explanation:
The first step is to subtract 2a from both sides to get the equation 2x=4b-2a
The next step is to divide by 2 so you can get x by itself which turns the equation to x=2b-a
The test statistic of z=2.75 is obtained when testing the claim that p
=0.877. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of α=0.05, should we reject H 0
or should we fail to reject H 0
? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a test. b. P-value = (Round to three decimal places as needed.) c. Choose the correct conclusion below. A. Reject H 0
. There is not sufficient evidence to support the claim that p
=0.877. B. Fail to reject H 0
. There is not sufficient evidence to support the claim that p
=0.877. C. Fail to reject H 0
. There is sufficient evidence to support the claim that p
=0.877. D. Reject H 0
. There is sufficient evidence to support the claim that p
=0.877.
D). Reject H0. is the correct option. The solution to this question is:Given that z = 2.75, H0: p = 0.877.
The hypothesis test is one-tailed because we are testing the value of the population proportion in one direction only, i.e. if it is less than 0.877 or greater than 0.877.
Thus, this is a right-tailed test. The p-value is found using a standard normal distribution table.
To use the table, we need to convert our z-value into an area under the curve.
To do this, we need to determine the area to the right of the z-value.
We can use the following formula to find the p-value:
P(Z > z) = P(Z > 2.75) = 0.0029 (using the standard normal distribution table)
Hence, P-value = 0.0029.Using a significance level of α = 0.05, we compare the p-value with α/2 = 0.025
since this is a right-tailed test. We reject H0 if the p-value is less than α/2, and we fail to reject H0 if the p-value is greater than or equal to α/2.
Here, P-value = 0.0029 < α/2 = 0.025.Hence, we reject H0.
There is sufficient evidence to support the claim that p ≠ 0.877.
Therefore, the correct answer is option D: Reject H0.
There is sufficient evidence to support the claim that p ≠ 0.877.
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if(x) = x4 - 6x2 +3 Find the intervals where f is concave up and where it is concave down. Locate all inflection points. (You may write on the next page if you need more space for this question.)
You have the following function:
\(f(x)=x^4-6x^2+3\)In order to determine the intervals, it is necessary to calculate the first derivative of the function, equal it to zero, and identify the zeros of the equation, just as follow:
\(\begin{gathered} f^{\prime}(x)=4x^3-12x=0 \\ 4x(x^2-3)=0 \end{gathered}\)the zeros of the previous equation are:
\(\begin{gathered} x_1=0 \\ x_2=\sqrt[]{3} \\ x_3=-\sqrt[]{3} \end{gathered}\)Next, it is necessry if the previous values are minima or maxima. Evaluate the second derivative for the previous values of x. If the result is greater than 0, then, it is a minimum. If the result is lower than zero, it is a maximum:
\(\begin{gathered} f^{\prime}^{\prime}(x)=12x^2-12 \\ f^{\prime}^{\prime}(0)=12(0)^2-12=-12<0 \\ f^{\prime}^{\prime}(\sqrt[]{3})=12(\sqrt[]{3})^2-12=24>0 \\ f^{\prime}^{\prime}(-\sqrt[]{3})=12(-\sqrt[]{3})^2-12=24>0 \end{gathered}\)Then, for x=0 there is a maximum, and for x=-√3 and x=√3 there is a minimum.
Hence, until x = -√3 the function decreases. In between x=-√3 and x=0 the function increases. In between x=0 and x=√3 the function decreases and from x=√3 the function increases.
Furthermore, it is necessary to find the inflection points. Equal the second derivative to zero and solve for x:
\(\begin{gathered} f^{\prime}^{\prime}(x)=12x^2-12=0 \\ x^2=1 \\ x=\pm1 \end{gathered}\)then for x=1 and x=-1 there are inflection points.
The interval where the function is concave up is:
(-∞ , -1) U (1, ∞)
The interval where the function is concave down is:
(-1,1)
please help me ♀️ im a tad bit slow-
9514 1404 393
Answer:
Michelle$5Step-by-step explanation:
The dollar value of the 20% coupon will increase if the discount is from a larger amount. Applying the $25 coupon first reduces the amount that the 20% applies to, so reduces the dollar value of the 20% coupon.
Michelle used the 20% coupon first, so its value was 20%($100) = $20.
Natasha used the $25 coupon first, so the value of the 20% coupon was ...
20%($100 -25) = 20%(%75) = $15.
Michelle paid $20 -15 = $5 less.
Help me please I am so sad
Answer:B 8;45
Step-by-step explanation:
Answer:
Dont be sad :) The answer is B but give brainliest to the other person ʕ •ᴥ•ʔ
Step-by-step explanation:
Out of 1,200 students that attend Norman Rockwell Middle School, how many would most likely sign up for after school tutoring, if 48 out of 80 students randomly surveyed said they would like to have extra help after school?
Answer:
720
Step-by-step explanation:
Out of 80 students the no. of students who sign up=48
So, out of 1200 students 48×1200÷80=720 students sign up.
chris has been given a list of bands and asked to place a vote. his vote must have the names of his favorite and second favorite bands from the list. how many different votes are possible?
There are nC2 different votes possible, where n is the number of bands on the list and nC2 represents the number of ways to choose 2 bands out of n.
To calculate nC2, we can use the formula for combinations, which is given by n! / (2! * (n-2)!), where ! represents factorial.
Let's say there are m bands on the list. The number of ways to choose 2 bands out of m can be calculated as m! / (2! * (m-2)!). Simplifying this expression further, we get m * (m-1) / 2.
Therefore, the number of different votes possible is m * (m-1) / 2.
In the given scenario, we don't have the specific number of bands on the list, so we cannot provide an exact number of different votes. However, you can calculate it by substituting the appropriate value of m into the formula m * (m-1) / 2.
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In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level.
When the lake warms up in the summer, the trout swim 20 feet deeper than that.
At what position relative to sea level do the trout swim in the summer?
Given :
In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level.
When the lake warms up in the summer, the trout swim 20 feet deeper than that , d = 20 feet .
To Find :
At what position relative to sea level do the trout swim in the summer.
Solution :
Depth in spring from surface , \(D_s=30\ feet\) .
Let , depth in summer is D .
Now , depth in summer relative to sea-level is :
\(D=D_s+d\\\\D=30+20\ feet\\\\D=50\ feet\)
Therefore , trout swim 50 feet deep below the sea level in the summer .
Hence , this is the required solution .
Answer:
-50
Step-by-step explanation:
bcuz it is
Graph the function in your notebook. Determine whether the function is linear or nonlinear.
Answer:
It is linear because if all x values are different, it makes it linear.
What is the area of this
Answer I will mark branliest
Answer:
D 50
Step-by-step explanation:
Answer:
55
Step-by-step explanation:
5y^2+4x
5(3)^2+4(2.5)
5(9)+4(2.5)
45+4(2.5)
45+10
=55
What is the percent of change from 10 to 8
Answer:
-20%
Step-by-step explanation:
8-10/10 x 100% = -20%
(How to do it)
first subtract your second number to your first (8-10) then divide by your first number (8-10/10) then multiply it by 100%.
Options for the first box: Time it takes Gilbert to travel 5 miles, increase in Gilberts average biking speed, distance Gilbert travels, biking speed for the second practice rideOptions for the second box: add, multiply, divide, subtract
We know that Gilbert's first practice ride covers 5 miles of the course, and his second practice ride covers 9 miles of the course.
And we also know that between these practice rides, he increase his average speed by 2 miles/hour.
We have the next two functions:
- First practice ride :
\(a(x)=\frac{5}{x}\)- Second practice ride :
\(b(x)=\frac{9}{x+2}\)Where, x represents his speed during the first practice ride
a) We know that
\(velocity=\frac{distance}{\text{time}}\)So, if the functions model the time
\(\text{time}=\frac{\text{distance}}{\text{velocity}}\)We can see that the denominator represents the velocity.
Finally, the denominator of the function that models practice ride 2 represent the biking speed for the second practice ride.
b) Knowing that a(x) and b(x) represent the time it took Gilbert to do each practice ride,
to find the a function that models the total amount of time Gilbert spent doing practice rides on the race course, add the functions.
I NEED AN ANSWER ASAP PLEASE
Step-by-step explanation:
the correct answer is option a 6a-7
The path of a cannon firing a cannonball can be modeled by the function h(x) = –x2 + 4x + 12, where x is time in seconds and h(x) is the height of the cannonball in feet. At what time does the cannonball reach its maximum height? seconds
Answer:
after 2 seconds
Step-by-step explanation:
Given
h(x) = - x² + 4x + 12
The ball will reach its maximum at the vertex of the parabola
Find the zeros by letting h(x) = 0, that is
- x² + 4x + 12 = 0 ← multiply through by - 1
x² - 4x - 12 = 0 ← in standard form
(x - 6)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 6 = 0 ⇒ x = 6
x + 2 = 0 ⇒ x = - 2
The x- coordinate of the vertex is at the midpoint of the zeros, thus
\(x_{vertex}\) = \(\frac{-2+6}{2}\) = \(\frac{4}{2}\) = 2
Substitute x = 2 into h(x)
h(2) = - 2² + 4(2) + 12 = - 4 + 8 + 12 = 16
The cannonball reaches its maximum height of 16 ft after 2 seconds
Answer:
2 seconds
Step-by-step explanation:
I just did it just trust me. This isn't reated to the answer but I had spagehtti for lunch
what is 40 percent of 85?
Answer:
Answer is 34.
Step-by-step explanation:
I hope it's helpful!
Answer:
34
Percentage Calculator: What is 40 percent of 85? = 34.
Question 7 > Consider the function f(t) = 10 sec² (t) - 7t². Let F(t) be the antiderivative of f(t) with F(0) F(t) = = 0. Then
The antiderivative F(t) of the function f(t) = 10sec²(t) - 7t² with F(0) = 0 is given by F(t) = 5tan(t) - (7/3)t³ + C, where C is the constant of integration.
To find the antiderivative F(t) of f(t), we need to integrate the function with respect to t. First, let's break down the function f(t) = 10sec²(t) - 7t². The term 10sec²(t) can be expressed as 10(1 + tan²(t)) since sec²(t) = 1 + tan²(t). Thus, f(t) becomes 10(1 + tan²(t)) - 7t².
Now, integrating each term separately, we get:
∫(10(1 + tan²(t)) - 7t²) dt = ∫(10 + 10tan²(t) - 7t²) dt
The integral of 10 with respect to t is 10t, and the integral of 10tan²(t) can be found using the trigonometric identity ∫tan²(t) dt = tan(t) - t. Finally, the integral of -7t² with respect to t is -(7/3)t³.
Combining these results, we have:
F(t) = 5tan(t) - (7/3)t³ + C
Since F(0) = 0, we can substitute t = 0 into the equation and solve for C:
0 = 5tan(0) - (7/3)(0)³ + C
0 = 0 + 0 + C
C = 0
Therefore, the antiderivative F(t) of f(t) with F(0) = 0 is given by F(t) = 5tan(t) - (7/3)t³.
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1. Determine (with a proof or counterexample) whether the arithmetic function f(n) = nn is multi- plicative, completely multiplicative, or neither.
The arithmetic function f(n) = nn is neither multiplicative nor completely multiplicative.
To determine whether an arithmetic function is multiplicative or completely multiplicative, we need to check its behavior under multiplication of two coprime numbers.
Let's consider two coprime numbers, a and b. Multiplicative functions satisfy the property f(ab) = f(a)f(b), while completely multiplicative functions satisfy the property f(ab) = f(a)f(b) for all positive integers a and b.
For the arithmetic function f(n) = nn, we have f(ab) = (ab)(ab) = aabbbb ≠ (aa)(bb) = f(a)f(b). Hence, f(n) = nn is not multiplicative.
To check if it is completely multiplicative, we need to show that f(ab) = (ab)(ab) = (aa)(bb) = f(a)f(b) for all positive integers a and b. However, this is not true in general. For example, let's consider a = 2 and b = 3. We have f(2 * 3) = f(6) = 36 ≠ (22)(33) = f(2)f(3). Therefore, f(n) = nn is not completely multiplicative either.
In conclusion, the arithmetic function f(n) = nn is neither multiplicative nor completely multiplicative.
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An upscale resort has built its circular swimming pool around a central area that contains a restaurant. The central area is a right triangle with legs of 60 feet, 120 feet, and approximately 103.92 feet. The vertices of the triangle are points on the circle. The hypotenuse of the triangle is the diameter of the circle. The center of the circle is a point on the hypotenuse (longest side) of the
The center of the circle, and consequently the central point of the resort's swimming pool, is located at the intersection of the two legs of the right triangle, approximately 60 feet from one vertex and 120 feet from the other.
The upscale resort has ingeniously designed its circular swimming pool to encompass a central area containing a restaurant. This central area takes the form of a right triangle with legs measuring 60 feet and 120 feet, while the hypotenuse, the longest side of the triangle, spans approximately 103.92 feet. The vertices of the triangle neatly coincide with points on the circumference of the circular pool.
Due to the properties of a right triangle, the hypotenuse is also the diameter of the circle. This means that the circular pool is precisely constructed around the right triangle, with its center located at the midpoint of the hypotenuse.
To determine the exact coordinates of the center of the circle, we can consider the properties of right triangles. Since the legs of the right triangle are perpendicular to each other, the midpoint of the hypotenuse coincides with the point where the two legs intersect.
In this case, the center of the circle is the point of intersection between the 60-foot leg and the 120-foot leg of the right triangle.
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Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of y plus StartFraction one-half EndFraction equals 3 left-parenthesis x minus 2 right-parenthesis.?
y + 2 =y plus 2 equals StartFraction one-third EndFraction left-parenthesis x plus 3 right-parenthesis.(x + 3)
y – 2 = y minus 2 equals StartFraction one-third EndFraction left-parenthesis x minus 3 right-parenthesis.(x – 3)
y + 3 = y plus 3 equals StartFraction one-third EndFraction left-parenthesis x plus 2 right-parenthesis.(x + 2)
y – 3 = y plus StartFraction one-half EndFraction equals 2 left-parenthesis x minus 3 right-parenthesis.(x – 2)
Answer:
B. y - 2 = 1/3(x - 3)
Answer:
B.
Explanation:
If you actually do the math you get B
If you wouldn't mind, please help.
Answer:
32
Step-by-step explanation:
Start with your expression
\(4b-y\)
We know b=7 and y=-4, plug these numbers into the expression.
\(4(7)-(-4)\)
\(32\)
Consider the linear equation.
32 4y = 18
Which two ordered pairs are on the graph of the linear equation?
Which real-world scenario can be described by the algebraic expression 4w? withdrawing w dollars from the bank and giving 4 dollars to a friend buying w items that cost $4 per item buying w items and dividing them among 4 friends buying w items and giving 4 of them to a friend
Answer:
The answer should be B
Buying w items that cost $4 per item
Step-by-step explanation:
i took the test on edg e 2020
help pleasejhdfjg THIS ASSIGNMENT IS LIKE 2 WEEKS OVERDUE
a) A 2*2 area model would not work to multiply (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) because this expression has 5 terms, and a 2*2 area model can only accommodate 4 smaller areas (b) The area model for (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) with the correct lengths and widths labeled has been attached below. (c) The final total area is 2x² - 10x - 15.
What is an area model?An area model is a way to visualize multiplication by breaking up the larger rectangle into smaller rectangles whose areas represent the products of the terms being multiplied. To determine the correct rows and columns for the area model, we count the number of terms in each factor and use that as a guide. For example, if one factor has 3 terms and the other has 4 terms, we would use a 3x⁴ area model, with 3 rows and 4 columns.
a) A 2*2 area model would not work to multiply (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) because this expression has 5 terms, and a 2*2 area model can only accommodate 4 smaller areas.
b) The area model for (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) with the correct lengths and widths labeled has been attached below.
2x⁴ − 3x³ − 2x² − 4x − 1
+---------------------------------------
x | 2x⁵ -3x⁴ -2x³ -4x² -x
|
3 | 6x⁴ -9x³ -6x² -12x -3
+---------------------------------------
c) To find the total area of a rectangle with length (x + 8) and width (x − 5), we can use an area model with 2 rows and 2 columns. The length (x + 8) corresponds to one dimension of the rectangle, while the width (x − 5) corresponds to the other dimension. The area of each smaller rectangle in the model represents the product of one term from each factor.
x + 8 x - 5
+--------------------
x | x² + 8x x² - 5x
|
-5 | -5x + -40 -5x + 25
+--------------------
The final total area can be found by adding up the areas of the smaller rectangles:
Total area = x² + 8x + x² - 5x - 5x - 40 + 25
= 2x² - 10x - 15
= 2x² - 10x - 15.
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PLSSS HELP ANSWER THESE QUESTIONS! WORTH 35 POINTS WILL GIVE BRIANLIEST IF ANWRS ARE CORRECT!
For which value of x do following expressions make sense?
THE FOLLOWING QUESTION HAVE TO BE ANWERED AS X IS LE THAN OR GREATER THAN WHATEVER THE ANWER IS
43a) √x+5 40a) ∛a 44b) √(-5x)^3 47e) √13-(13-2x)
THE NEXT COUPLE OF QUETION HAVE TO ANWERED AS X = WHATEVER THE ANSWER IS.
43b) √|x| + 1 44a) √(-2x)^2
45a) √x-5 = 3 The root is only over x-5
45b) √2x+4 = 2 the root is only over 2x+ 4
45c) √x(x+1) = 0 root is only over x(x+1)
45d) √x+5 = -1 the root is only over x+5
45e) √x + x^2 = 0 the root is only over x
42d) root 5 over x+3 = 17 1
9e) root 4 over x = 1 THE ANSWER IS NOT 1
19f) ∛x - 2 = 0 the root is only over x
THE FOLLOWING QUESTIONS HAVE NUMERICAL ANSWERS
9a) root 0.6 over 36 9h) root (4-10) over 0.01
The values of the variables and numbers in radical form are presented as follows;
43a) x > -5
40a) a > 0
44b) x < 0
47e) x > 0
43b) x = The set of all real numbers
44a) The set of all numbers
45 a) x = 14
45 b) x = 0
45 c) x = -1
45 d) x = -4
45 e) x = 1
42 d)x = 5/196
9 e) x = 4
9 f) x = 8
9 a) √(0.6/36) ≈ 0.13
9 h) √((4 - 10)/(0.01)) = i·10·√6
What is a radical expression in mathematics?A radical also known as a root is represented using the square root or nth root symbol and is the opposite of an exponent.
43 a) \(\sqrt{x + 5}\)
x + 5 > 0
Therefore, x > -5
40a) ∛a
a > 0
44b) √(-5·x)³
-5·x < 0
x < 0
47e) √(13 - (13 - 2·x))
(13 - (13 - 2·x)) > 0
13 > (13 - 2·x)
0 > -2·x
x > 0
43b) √|x| + 1
x = All real numbers
44 a) √(-2·x)²
√(-2·x)² = -2·x
x = Set of all numbers
45 a) √(x - 5) = 3
(x - 5) = 3² = 9
x = 9 + 5 = 14
45b) √(2·x + 4) = 2
2·x + 4 = 2²
2·x = 2² - 4 = 0
x = 0/2 = 0
45c) √(x·(x + 1)) = 0
(x·(x + 1)) = 0
(x + 1) = 0
x = -1
45 d) √(x + 5) = -1
(x + 5) = (-1)²
x + 5 = 1
x + 5 = 1
x = 1 - 5 = -4
x = -4
45e) √x + x² = 0
√x = -x²
(√x)² = (-x²)² = x⁴
x = x⁴
1 = x⁴ ÷ x = x³
x = ∛1 = 1
x = 1
42d) \(\sqrt{\dfrac{5}{x} } +3= 17\)
\(\sqrt{\dfrac{5}{x} }= 17-3 =14\)
\(\dfrac{5}{x} }=14^2=196\)
\(x = \dfrac{5}{196}\)
9e) \(\sqrt{\dfrac{4}{x} } = 1\)
\(\dfrac{4}{x} } = 1^2\)
x × 1² = 4
x = 4
19f) ∛x - 2 = 0
∛x = 2
x = 2³ = 8
9a) \(\sqrt{\dfrac{0.6}{36} }\)
\(\sqrt{\dfrac{0.6}{36} }\) = \(\sqrt{\dfrac{1}{60} }= \dfrac{\sqrt{15}}{30} \approx 0.13\)
9h) \(\sqrt{\dfrac{4-10}{0.01} }\)
\(\sqrt{\dfrac{4-10}{0.01} }\)= √(-600) = √(-1)·√(600) = i·10·√6
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A 3-foot vertical post casts a 24-in. shadow at the same time a pine tree casts a 30-foot shadow. How tall is the pine tree? What is the scale factor of the post to the tree? Can someone pls tell a step by step guide!!!
Answer:
30
Step-by-step explanation:
An account has $26,000 after 15 years. The account received 2.3 percent interest compounded continuously. How much was deposited initially. Show all work.
The intital amount deposited was $18485.82.
How to find the compound interest?If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:
\(a = p(1 + \dfrac{r}{n})^{nt}\)
An account has $26,000 after 15 years. The account received 2.3 percent interest compounded continuously.
A = 26000
R = 0.02.3
\(a = p(1 + \dfrac{r}{n})^{nt}\)
\(26000 = p(1 + \dfrac{2.3}{100})^{15}\\\\26000 = p \times 1.4064\\\\\P= 18485.82\)
Therefore, the intital amount deposited was $18485.82.
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This question is for ktishler1 what is 1+1?
Answer: 11
if u put 1 and 1 together
u get 11
Answer:
2
Step-by-step explanation:
1 +1=2
because 1 means you only have one thing then add one more thing that gives you two things
How many grains of sand are there in 6,300 kg of sand?
(only need an answer to the second part)
When one grain of sand weighs 7×10⁻⁵ g, then there are 9.0 × 10¹⁰ grains of sand in 6300 kg of sand.
Given, one grain of sand approximately weighs 7×10⁻⁵ g.
Then how many grains of sand are there in 6300 kg of sand = ?
we know that one grain of sand weighs = 7×10⁻⁵ g.
therefore, 6300 kg = 6300 × 10³ g sand contains
= 6300 × 10³/7×10⁻⁵
= 900×10³/10⁻⁵
= 900 × 10³ × 10⁵
= 9.00 × 10² × 10³ ×10⁵
= 9.0 × 10²⁺³⁺⁵
= 9.0 × 10¹⁰
Hence there are 9.0 × 10¹⁰ grains of sand in 6300 kg of sand.
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please help me please
Answer:
Surface area= 6(5·5)+6(3·3)-2(3·3)
Step-by-step explanation:
first figure out the surface area of both cubes
for the larger cube- 5 multiplied by 5 for the area of one side then multiplied by 6 for all faces
for the smaller cube- 3 multiplied by 3 for the area of one side then multiplied by 6 for all the faces.
the cubes are touching on one face, this is the whole area of one side of the 3 by 3 cube, meaning two of these faces must be subtracted to find the surface area of the whole shape
hope that helps
A car is traveling along a road that makes a 13° angle with the ground. Find the elevation of the car on a stretch of road that extends horizontally 125 meters. Round your answer to the nearest tenth.
Answer:
Therefore, the elevation of the car on the stretch of road, rounded to the nearest tenth, is approximately 29.7 meters.
Step-by-step explanation:
To find the elevation of the car on a stretch of road that extends horizontally 125 meters, we can use trigonometry.
Given:
Angle of the road = 13°
Horizontal distance = 125 meters
We can use the tangent function to calculate the elevation:
tan(angle) = opposite / adjacent
In this case, the opposite side represents the elevation, and the adjacent side represents the horizontal distance.
Let's denote the elevation as "e". The equation becomes:
tan(13°) = e / 125
To solve for "e", we can rearrange the equation:
e = 125 * tan(13°)
Using a calculator, we can evaluate this expression:
e ≈ 125 * tan(13°) ≈ 29.7