pls help i have no clue what this is

Answer:20

Step-by-step explanation:this is wrong

Answer:

40

Step-by-step explanation:

subtract median of dogs and median of cats

Answer: 7 cm

Step-by-step explanation: 35 ÷ 5 = 7

Answer:

\(x=25\)

Step-by-step explanation:

\(\frac{7}{5}x=35\)

\(x=25\)

Answer:

4

Step-by-step explanation:

Im  smart and goatified

Answer:4x^2–3>0

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

I got you

Step-by-step explanation:

6.05-12.50=13.55

48 divided by 13.55=3.542

x=3.542

Answer:

X= 1

Step-by-step explanation:

6.05x-12.5=48 Add 12.5 to both side

         +12.5 +12.5

6.05x = 60.5 now divide both sides by 6.05

/ 6.05    /60.5

X     =  1

The results of operations between vectors are, respectively:

Case A: u + w = <- 3, - 1>

Case B: - 6 · v = <6, 6>

Case C: 3 · v - 6 · w = <- 21, - 15>

Case D: 4 · w + 3 · v - 5 · u = <39, 4>

Case E: |w - v| = √(4² + 3²) = 5

In this problem we must determine the operations between vectors, this can be done by following definitions:

Vector addition

v + u = (x, y) + (x', y') = (x + x', y + y')

Scalar multiplication

α · v = α · (x, y) = (α · x, α · y)

Norm of a vector

|u| = √(x² + y²)

Now we proceed to determine the result of each operation:

Case A:

u + w = <- 6, - 3> + <3, 2>

u + w = <- 3, - 1>

Case B:

- 6 · v = - 6 · <- 1, - 1>

- 6 · v = <6, 6>

Case C:

3 · v - 6 · w = 3 · <- 1, - 1> - 6 · <3, 2>

3 · v - 6 · w = <- 3, - 3> + <- 18, - 12>

3 · v - 6 · w = <- 21, - 15>

Case D:

4 · w + 3 · v - 5 · u = 4 · <3, - 2> + 3 · <- 1, - 1> - 5 · <- 6, - 3>

4 · w + 3 · v - 5 · u = <12, - 8> + <- 3, - 3> + <30, 15>

4 · w + 3 · v - 5 · u = <39, 4>

Case E:

|w - v| = |<3, 2> - <- 1, - 1>|

|w - v| = |<4, 3>|

|w - v| = √(4² + 3²) = 5

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The nth term of the sequence -3, 0, 5, 10, 25, 5, 47 can be represented by the piecewise function:

nth term =

-3 + (n - 1) * 5, if n mod 5 ≤ 5

5 + (n - 1) * 15, if n mod 5 > 5

To find the nth term of a sequence, we need to identify the pattern or rule that governs the sequence. Upon analyzing the given sequence -3, 0, 5, 10, 25, 5, 47, we can observe the following:

The sequence starts with -3 and increases by 5 each time, except for the 5th term, where it increases by 15 (from 10 to 25). After the 5th term, the sequence starts again with 5 and continues to increase by 15 each time.

Based on this pattern, we can divide the sequence into two parts:

Part 1: -3, 0, 5, 10, 25 (increasing by 5 each time)

Part 2: 5, 20, 35, 50, 65 (increasing by 15 each time)

Now, to determine the nth term, we can consider the formula for arithmetic sequences:

nth term = first term + (n - 1) * common difference

For Part 1, the first term is -3 and the common difference is 5. Thus, the nth term for Part 1 is given by:

nth term = -3 + (n - 1) * 5

For Part 2, the first term is 5 and the common difference is 15. Therefore, the nth term for Part 2 can be expressed as:

nth term = 5 + (n - 1) * 15

However, since the sequence alternates between Part 1 and Part 2, we need to determine which part the nth term falls into. For that, we can use modular arithmetic:

If n mod 5 is less than or equal to 5, then the nth term is from Part 1.

If n mod 5 is greater than 5, then the nth term is from Part 2.

Let's calculate a few terms to illustrate this:

For n = 1, the sequence starts with -3, so the 1st term is -3.

For n = 2, we are still in Part 1, so the 2nd term is 0.

For n = 3, Part 1 continues, so the 3rd term is 5.

For n = 4, we are still in Part 1, so the 4th term is 10.

For n = 5, Part 1 ends, and the 5th term is 25.

For n = 6, the sequence starts with 5 in Part 2, so the 6th term is 5.

For n = 7, Part 2 continues, so the 7th term is 20.

For n = 8, we are still in Part 2, so the 8th term is 35.

Based on this analysis, we can conclude that the nth term for the given sequence is:

If n mod 5 ≤ 5:

nth term = -3 + (n - 1) * 5

If n mod 5 > 5:

nth term = 5 + (n - 1) * 15

Therefore, depending on the value of n and the remainder when divided by 5, we can use the appropriate formula to calculate the nth term.

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Answer:

if you're finding x, x=3

Answer:

Option D) 5

Step-by-step explanation:

In the given graph of a parabola, and the equation in vertex form, y = (x - k )²: The variable k represents the x-coordinate of the vertex, and the point where the axis of symmetry lies on the graph.  In the given graph, the vertex is the minimum point, occurring at point (5, 0). The x-coordinate of the vertex is also the value of k = 5.

Therefore, the correct answer is Option D) k = 5.

The difference in overall loss or gain between sell at the current day's high price or low price is found tp be the difference in overall gain as $280.10

The third option is correct.

High price value: 115 shares * $105.19 per share = $12,084.85

Low price value: 115 shares * $103.25 per share = $11,858.75

High price value: 30 shares * $145.18 per share = $4,355.40

Low price value: 30 shares * $143.28 per share = $4,298.40

The overall value at high price:

$12,084.85 + $4,355.40

= $16,440.25

The overall value at low price:

$11,858.75 + $4,298.40

= $16,157.15

In conclusion, the difference in overall gain or loss:

$16,440.25 - $16,157.15 = $280.10

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The probability that the sum of the pips selected that is at least 11 would be = 1/12.

To determine the probability of the selected events, the formula for problem should be used which is given below;

Probability = possible outcome/sample space

Possible outcome = at least 11 = (5,6),(6,5),(6,6)

= 3

Sample space = 36

Probability = 3/36 = 1/12

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Step-by-step explanation:

heres the answer to your

Answer:

Step-by-step explanation: -3/2 divided by 9/6

= -3/2 multiply (to divide fractions we multiply by their recipical) 6/9
Then, simplify
= -3/3 = 1
Answer: -1

Hope this helps lol

The simplified result is -1. The correct option is b.

Given that:

Expression, -3/2 ÷ 9/6

To solve the given expression, follow as:

Rewrite the division as multiplication by the reciprocal of the second fraction.

-3/2 ÷ 9/6 = -3/2 × (6/9)

Now, simplify the fractions:

-3/2 × (6/9) = -3/2 × (2/3)

-3/2 × (6/9) = - (3 × 2)/(2 × 3)

-3/2 × (6/9) = -6/6

Finally, the simplified expression is -6/6. However, further simplify it by dividing the numerator and denominator by their greatest common divisor, which is 6:

-6/6 = -1

So, the simplified result is -1. The correct option is b.

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Complete question:

Simplify Negative 3 over 2 divided by 9 over 6.

a. −4

b. −1

c. 4

d. 1

Answer:

  (-20x -25)/(x^2-x-30)

Step-by-step explanation:

You want to simplify the rational expression (3x²)/(x²-x-30) -(3x+5)/(x-6).

Usually these problems are constructed so that the higher-degree polynomial denominator has the lower degree denominator as a factor. That is the case here.

  \(\dfrac{3x^2}{x^2-x-30}-\dfrac{3x+5}{x-6}=\dfrac{3x^2}{(x+5)(x-6)}-\dfrac{(x+5)(3x+5)}{(x+5)(x-6)}\\\\=\dfrac{3x^2-(3x^2+20x+25)}{x^2-x-30}\)

  \(=\boxed{\dfrac{-20x-25}{x^2-x-30}}\)

Answer:

To find the z-score, we use the formula:

z = (x - mu) / (sigma / sqrt(n))

where:

x = sample mean = $5100

mu = population mean = $5000

sigma = population standard deviation = $250

n = sample size = 64

Substituting the values, we get:

z = (5100 - 5000) / (250 / sqrt(64))

z = 2.56

Therefore, the z-score that corresponds to a sample average of $5100 is 2.56 (rounded to four decimals).

Step-by-step explanation:

I clicked on the black picture. thought is was the box to enter the answer.

The graph of f(x) is the second one, so the correct option is B.

Here we have f(x), a piecewise function, and we want to see which one of the four graphs is the correct one.

You can see that the first domain of the function is:

x ≤ -4

So we must have a closed circle at x = -4, when the parabola ends.

The second domain is:

-4 < x < 1

So x here is not equal to -4 nor 1, so this part starts and ends with open circles.

finally, the linear part starts with a closed circle.

Also, notice that the line has a negative slope, so it goes down, then we can discard the first option.

Then we can see that the correct option is the second graph.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  \(\mu = 0.5 \ in\)

Generally the Null hypothesis is  \(H_o : \mu = 0. 5 \ in\)

                The Alternative hypothesis is  \(H_a : \mu \ne 0.5 \ in\)

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance \(\alpha = 0.05\)

The degree of freedom is evaluated as

            \(df = n- 1\)

           \(df = 15- 1\)

           \(df = 14\)

Using the critical value calculator at (social science statistics web site )  

           \(t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145\)

We are making use of this  \(t_{\frac{\alpha }{2} }\) because it is a one-tail test

Looking at the value of  t and \(t_{\frac{\alpha }{2} }\) the we see that  \(t < t_{\frac{\alpha }{2} }\) so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance \(\alpha = 0.05\)

The degree of freedom is evaluated as

            \(df = n- 1\)

           \(df = 15- 1\)

           \(df = 14\)

Using the critical value calculator at (social science statistics web site )  

           \(t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145\)

Looking at the value of  t and \(t_{\frac{\alpha}{2} ,df }\) the we see that t does not lie in the area covered by  \(t_{\frac{\alpha}{2} , df }\) (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance \(\alpha = 0.01\)

The degree of freedom is evaluated as

            \(df = n- 1\)

           \(df = 26- 1\)

           \(df = 25\)

Using the critical value calculator at (social science statistics web site )  

           \(t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787\)

Looking at the value of  t and \(t_{\frac{\alpha }{2} }\) the we see that t does not lie in the area covered by  \(t_{\alpha , df }\) (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance \(\alpha = 0.01\)

The degree of freedom is evaluated as

            \(df = n- 1\)

           \(df = 26- 1\)

           \(df = 25\)

Using the critical value calculator at (social science statistics web site )  

           \(t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787\)

Looking at the value of  t and \(t_{\frac{\alpha}{2} }\) the we see that  t  lies in the area covered by  \(t_{\alpha , df }\) (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

For multiplication it is 7 x h which is equal to 7h

For addition it is h+h+h+h+h+h+h= 7h

Answer:

A

Step-by-step explanation:

Process of elimination.

It can't be B or D cause those say that the temp go down while in your graph it goes up, and C is saying that it rises and becomes constant while in your graph it's the other way around.

Answer:

A.

Step-by-step explanation:

I said so

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

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The y-coordinate of the point on the line when x = 8 is -1

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

The given parameters are

Slope, m = 1/2

Point, (x1, y1) = (2, -4)

The linear equation is calculated as

y = m(x - x1) + y1

So, we have

y = 1/2(x - 2) - 4

When x = 8, we have

y = 1/2(8 - 2) - 4

Evaluate

y = -1

Hence, the y-coordinate of the point on the line when x = 8 is -1

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Answer:

7 c 7 fl oz

Step-by-step explanation:

Answer:

you cant round that to 30

Step-by-step explanation

29.20

29.2 2 is less than 5

so you cant round you can only round if the .tens place is 5 or more