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Describe the life cycle of a star before it collapses into a black hole.
Describe the life cycle of a star before it becomes a black dwarf.
What is the likely outcome of our sun? *
The sun will supernova and become a black hole.
The sun will swell, encompassing the inner planets and collapses into a dwarf star.
The sun will become a pulsar.
How Do You Know?
P.S. the how do you know is only for the last question
Answers
1) describe the life cycle of a star before it collapses into a black hole.
1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.
2) describe the life cycle of a star before it becomes a dwarf.
ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.
3) what is the likely outcome of our sun?
ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.
Related Questions
explain why sound wave travel faster in liquid than gas
Answers
Answer:
Because gas contains free molecules but not liquid.
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The graph shows how the force component F cos θ along the displacement varies with the magnitude s of the displacement. Find the work done by the force. The graph plots F cosine of theta versus s. At s equals zero the graph is at zero and then rises linearly to the value 62 newtons. It then descends linearly to zero forming a shaded triangle of base 1.6 meters.
Answers
The work done by the force is 49.6 J.
The complete question is in the attachment. The formula to calculate work done
W = F × d × cos α
F = force (Newton) d = displacement (m) α = the angle between the force and the displacementWhen the condition
Forces that work in an object F = F cos θIt means the direction of the force is to the right along the x-axis.The displacement along the x-axis
The direction of the displacement is to the right along the x-axis. α = 0°cos α = cos 0° = 1W = F cos θ × d × cos α
W = F cos θ × d × 1
W = F cos θ × d
The area under the curve in the force against displacement graph shows the work done.
W = Area of triangle
W = (b × h) ÷ 2
W = (b × h) ÷ 2
W = (62.0 × 1.60) ÷ 2
W = 99.2 ÷ 2
W = 49.6 Joule
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A 3.0 x 10^3 kg truck travels through a curve with a radius of 150 m at 113 km/hr. If the curve is flat, what is the coefficient of friction required to keep the vehicle from skidding off the road? In a real-world situation, would the truck remain on the road?
Answers
Answer:
from what i could figure out. A 6600 pound truck traveling at 113 km/ hr will need to have 58.4070965 psi. on each wheel. if going going on a curve that have an incline of atleast 2.℅ , which is close to the average curvature of a road. But at that speed and flat angle of the road. and distance . Once the truck is in itsvturn the truck will loose 1/4 of the tires psi, adding the weight , ofvtge truck and the ineshia of the tryck as it leans to one side . The truck will not be able to with stand the force on its tires and slide to the side and roll the tryck as it slide off the road dropping atleast 1-2 inch drop off the pavement.
A force of 25 newtons moves a box a distance of 4 meters in 5 seconds. The work done on the box is_ No, and the power is_Nm/s
Answers
Explanation:
workdone = force x distance
workdone= 25 x 4
workdone = 100 joules ( the unit for workdone is joules or Nm )
POWER = workdone/ time
power = 100/5
power = 20 watts ( the unit for power is watts or Nm/s )
If you ride a bicycle 36 m in 12 seconds, what is your speed?
O A. 0.3 m/s
O B. 3 m/s s
O C. 0.09 m/s
/
D. 2 m/s
Answers
Answer:
3m/s
Explanation:
Speed is distance/time,
36m/12s = 3m/s
find the resultant of the two velocity vector and the angle that the resultant moves with the first vector
Answers
Answer:
Explanation:
To find the resultant of two velocity vectors, we can use vector addition. Given two velocity vectors v1 and v2, their resultant vector vR can be found by adding the two vectors:
vR = v1 + v2
The angle that the resultant moves with the first vector can be found using trigonometry. If we let theta be the angle between v1 and vR, then we can use the following formula:
tan(theta) = (vR_y / vR_x)
where vR_x is the x-component of the resultant vector and vR_y is the y-component of the resultant vector.
Alternatively, we can use the dot product to find the angle between the two vectors. The dot product of two vectors is defined as:
v1 . v2 = |v1| |v2| cos(theta)
where |v1| and |v2| are the magnitudes of the vectors and theta is the angle between them. Solving for theta, we get:
theta = acos((v1 . v2) / (|v1| |v2|))
where acos is the inverse cosine function.
To summarize:
Find the resultant vector vR by adding the two velocity vectors v1 and v2: vR = v1 + v2
Find the angle theta between v1 and vR using either the tangent formula or the dot product formula:
a. tan(theta) = (vR_y / vR_x)
b. theta = acos((v1 . v2) / (|v1| |v2|))
Answer the following. (a) What is the surface temperature of Betelgeuse, a red giant star in the constellation of Orion, which radiates with a peak wavelength of about 970 nm? K (b) Rigel, a bluish-white star in Orion, radiates with a peak wavelength of 145 nm. Find the temperature of Rigel's surface. K
Answers
Answer:
(a) T = 2987.6 k
(b) T = 19986.2 k
Explanation:
The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:
\(T = \frac{0.2898\ x\ 10^{-2}\ m.k}{\lambda_{max}}\)
where,
T = Radiated surface temperature
\(\lambda_{max}\) = peak wavelength
(a)
here,
\(\lambda_{max}\) = 970 nm = 9.7 x 10⁻⁷ m
Therefore,
\(T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}\)
T = 2987.6 k
(b)
here,
\(\lambda_{max}\) = 145 nm = 1.45 x 10⁻⁷ m
Therefore,
\(T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}\)
T = 19986.2 k
Newton’s universal law of gravity tells us that F = G(m1m2/d2). Newton’s second law tells us that a = Fnet/m.
(a) With a bit of algebraic reasoning show that your gravitational acceleration toward any planet of mass M a distance d from its center is a = GM/d2.
(b) How does this equation tell you whether or not your gravitational acceleration depends on your mass?
Answers
How much energy is needed to change the temperature of 50g of water 15°c
Answers
Explanation:
This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature
A rightward force of 4.0 N is exerted upon an object for a distance of 3.0 meters.
What is the work done on the object?
Answers
Answer:
W = 12 J
Explanation:
Given that,
Force, F = 4 N
The object moves in rightward direction for a distance of 3 m.
Work done on the object is given by :
\(W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J\)
So, the work done on the object is 12 J.
A 0.3 mm long invertebrate larva moves through 20oC water at 1.0 mm/s. You are creating an enlarged physical model of this larva so you can better study its flow pattern in the laboratory. Your model must be able to move at 50 cm/s and you will place the model in honey instead of water. Honey has a density of 1400 kg/m3 and a viscosity of 600 Pa-s.
Required:
How long should your model be?
Answers
Answer:
Explanation:
For the problem, we should have same reynolds number
ρvd/mu = constant
1000×1×10⁻³×0.3×10⁻³/1.002×10⁻³ = 1400×0.5×d/600
d = 25.66 cm
27. The number of coils of wire through which a bar magnet is moved is increased. The
amount the needle on the meter is deflected
A. increases
B. decreases
C. shows no change
D. does not move at all
Answers
The amount the needle on the meter is deflected A. increases
This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.
The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.
By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.
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Calculate the change in thermal energy of the water in a pond with a mass of 1,000 Kg and a specific heat of 4,184 J/kg °C if the water cools by 1°C
Answers
We will consider that specific heat of any material raises the temperature of 1 kg in 1°C.
Q= m ( Tf - Ti ) C,
where m is mass, Tf is final temperature, Ti is initial temperature and C is the specific heat of the substance.
So, by substituting values, the answer we get is 4184000 J
Hope it helps you...
Answered by Benjemin
The change in thermal energy of the water in a pond is 4,184 kj.
Given to us,
Mass of the water of the pond, m = 1,000 kgs.,
specific heat of the water, C = 4,184 J/kg °C,
change in temperature, ΔT = 1 °C,
As we know, change in heat is given by,
\(\bold{Q=m\times C\times \Delta T }\),
where,
m = mass,
C = specific heat,
ΔT = \(\bold{(T_f-T_i)}\) = change in temperature.
Substituting the value we get,
\(Q=m\times C\times \Delta T\\Q=1,000 \times 4,184\times 1\\Q = 4,184,000\ j\\Q = 4,184\ kj\)
Hence, the change in thermal energy of the water in a pond is 4,184 kj.
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A point charge q1 has a magnitude of 3.5x10-6 C. A second charge q2 has a magnitude of -1.8x10-6 C and is located 0.15 m from the first charge. Determine the electrostatic force exerts on each other.
Answers
The electrostatic force exerts on each other is 1.134 N
Electrostatic force calculation.
The electrostatic force between the two charges is given by Coulomb's Law:
F = k * |q1| * |q2| / r^2
where k is the Coulomb constant (9.0 x 10^9 N*m^2/C^2), |q1| and |q2| are the magnitudes of the two charges, and r is the distance between them.
Substituting the given values, we have:
F = (9.0 x 10^9 N*m^2/C^2) * (3.5 x 10^-6 C) * (1.8 x 10^-6 C) / (0.15 m)^2
F = 1.134 N
The electrostatic force exerted on each charge is equal in magnitude but opposite in direction, according to Newton's Third Law. Therefore, the magnitude of the force on each charge is 1.134 N, but they point in opposite directions. The force on q1 is attractive (toward q2), while the force on q2 is repulsive (away from q1).
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onsider laminar flow of a fluid through a square channel with smooth surfaces. now the average velocity of the fluid is doubled. determine the change in the head loss of the fluid. assume the flow regime remains unchanged
Answers
The head loss doubles when the average velocity is doubled.
The velocity formula: why?
The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).
How do velocity and speed differ?Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.
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When I mix 200g of water at 10°C with 300g of water at 55°C, what is the final temperature of the mixture?
Answers
Answer:
4th of August is the
Explanation:
5th and then I can help out by getting
While you push a box you begin to decrease the force you are exerting on the box. When will the box reach equilibrium?
A. When the force you are exerting on the box is equal to 0.
B. When Fyou on box = -Fbox on you.
C. When the force of the box becomes Fyou on box < Fbox on you
D. The box will never reach equilibrium.
Answers
The application of a force on the box overcomes the friction and causes the box to accelerate
While the force is decreasing, the box will stabilize;
B. When \(\underline{F_{you \, on \, box} = -F_{box \, on \, you}}\)Reason:
Newton's third Law of Motion states that action and reaction are equal in magnitude and opposite in direction
When the box is pushed with a force, \(F_{you \, on \, box}\), the reaction of the box of mass, m, is as follows;
\(F_{you \, on \, box}\) = \(F_{friction}\) + m × accelerationWhere;
\(F_{friction}\) = \(-F_{box}\) for example
The negative sign is due to the direction of the friction force, or \(F_{box}\) is opposite to the direction of the applied force
When the force is decreased to F₂ = \(F_{you \, on \, box}\), such that we have;
\(F_{you \, on \, box}\) = \(-F_{box \, on \, you}\) , which is the condition for equilibrium, and the net
force is zero and according to Newton's first law of motion, the box moves
at constant speed no acceleration
Therefore the box will reach equilibrium when;
\(\mathbf{\underline{F_{you \, on \, box} = -F_{box \, on \, you}}}\)Learn more about equilibrium here;
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Answer:
When the force you are exerting on the box is equal to 0
Explanation:
Once again expert verifiers are sabotaging people here is the actual answer.
A movie stunt double is supposed to run across the top of a train (in the opposite direction that the train is moving) and just barely jump off before reaching a tunnel, but after reaching the end of the train (starting from the front). If the train is moving at 150 km/hr, is 2 km long and the tunnel is 20 km away from the end (where the stunt double is going to jump from), how fast (in km/hr) will the stunt double need to run
Answers
Answer:
the required speed/velocity of the stunt double is 13.633 km/h
Explanation:
Given the data in the question;
velocity of train V = 150 km/h
distance = length of train + distance between the tunnel and the end
= 2 km + 20 km = 22 km
first we calculate time t taken by the train to reach the tunnel;
t = distance / velocity
we substitute
t = 22 km / 250 km/h
t = 0.1467 hr
so the velocity of the of the stunt double will be;
velocity = distance / time
we substitute
velocity = 2 km / 0.1467 hr
velocity = 13.633 km/h
Therefore, the required speed/velocity of the stunt double is 13.633 km/h
A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
Answers
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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) The graph in the figure shows the position of a particle as a function of time as it travels along the x-axis.
What is the average velocity of the particle between t = 2.0 s and t = 4.0 s?
Answers
The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
What is average velocity?Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.
The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
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Given: g=10 m/s^2
A car moves a distance of 80 m during
a time interval of 10 s. The average
speed v_avg of this car is:
2 m/s
6 m/s
O 10 m/s
O 8 m/s
O 4 m/s
Answers
During a 10-second period, a car travels 80 meters. This car typically travels at a speed of 8 m/s.
An illustration of average velocity.For instance, if it takes a person 40 minutes to travel 20 miles north, 20 miles south, and finally 20 miles in between, their average speed is 40 miles divided by 40 minutes, or 1 mile per minute. Instead of distance, average velocity takes into account total displacement.
How is average velocity calculated?The total displacement must be divided by the total time elapsed in order to determine the average velocity.
average velocity= total displacement/ total time
avg velocity=80/10=8m/s
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How does the orientation of the bar magnet affect the measured magnetic field strength?
Answers
When two magnets are close to each other, the magnets experience a repulsive or attractive force. The magnetic field strength is affected by the orientation of the magnet.
The direction in which the bar magnet obtains its maximum magnetic property is called the orientation of the magnet. The magnetic field strength depends on the orientation of the magnet.
The magnetic field lines emerge from the north pole and end in the south pole. When the two bar magnets of opposite poles face each other, an attractive force will be produced and magnetic field strength increases.
When the bar magnet of the same poles faces each other, repulsive force will produce and magnetic field strength decreases. Hence from the orientation of the bar magnet, the magnetic field strength gets affected.
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According to Newton's first law, an object at rest will _____.
never move
stay at rest forever
start moving
stay at rest unless moved by force
Answers
fill in the blank. a 10-kg rock and a 20-kg rock are thrown upward with the same initial speed v0 and experience no significant air resistance. the 20 kg rock will reach a height which is___the maximum height of the 10-kg rock.
Answers
The 20 kg rock will reach a height which is less than the maximum height of the 10-kg rock.
The 20-kg rock will reach a height which is less than the maximum height of the 10-kg rock.
The maximum height reached by an object is proportional to the square of its initial velocity. The force of gravity acting on an object is proportional to its mass. Hence, the acceleration due to gravity is equal to the force of gravity divided by the mass of the object. This means that a heavier object will have a smaller acceleration and will reach a lower maximum height compared to a lighter object, despite being thrown with the same initial velocity.
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A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:
Answers
Our muscles need more oxygen to make energy (in the form of ATP) while we workout.
When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.
Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.
The respiratory system is the organ system engaged in this process.
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# complete question:
A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:
Student 1: Wow! I am so hot and sweaty! I need some water to cool down.
Student 2: My cheeks are really red.
Student 3: I am breathing so hard, I can barely catch my breath!
Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.
A 42.2 kg sled is pulled forward with a 143 N force across ground with μk = 0.269. What is the net force on the sled?
Answers
The net force on the sled is 31.89 N. During sledding, the main forces are normal force and gravity.
What are the forces at work on a sledge?The weight of the sledge and its rider, the normal force, and the kinetic frictional force all act on the moving sledge.
What is the purpose of calculating net force?Net force is significant because it describes the motion of an object and can be used to calculate acceleration. Newton's first law of motion states that an object in motion will remain in motion, while an object at rest will remain at rest unless acted on by an unbalanced net force.
We can calculate by using the equation:
Net force = Force applied - Force of friction
where Force of friction = coefficient of kinetic friction (μk) * Normal force
we can use the equation:
Normal force = weight of sled
weight of sled = mass * gravitational acceleration
we know that gravitational acceleration (g) = 9.8 m/s^2
Therefore, the normal force = 42.2 kg * 9.8 m/s^2 = 413.56 N
The force of friction:
Force of friction = 0.269 * 413.56 N
= 111.11 N
We can calculate,
Net force = 143 N - 111.11 N = 31.89 N
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A. 65-year old emmetrope wearing +2.50D readers has a near point of accommodation of 25cm.what is his near point of accommodation without glasses? B. The patient above wishes to have glasses for reading material at 50cm. what should the appropriate power of the reading spectacles be?
Answers
If he does not use the lenses, his near point will be 66.7 cm. For him to read a material at 50 cm, he has to use a lens of 2.0D.
What is the near point?The near point is the nearest area which a person can see or have distinct vision. The focal length of the lens is f = 100/2.5 = 40cm
Then;
1/40 = -1/v + 1/25
1/v = 1/25 - 1/40
v = 66.7 cm
Also, for the purpose of reading at 50 cm
1/f = -1/50 + 1/25
1/f = 1/25 - 1/50
f = 50cm
The power of this lens is;
100/50 cm = 2 D
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When talking about the products of photosynthesis, why is it a HUGE issue when a vast amount of the rainforests is dying along with vast amounts of forests from fires/deforestation? Remember, we know that this hurts the ecosystems of animals living there, but what else does it effect?
Question 5 options:
the creation of too much smoke
the creation of carbon dioxide
the creation of carbon monoxide
the creation of oxygen
Answers
Answer:
the creation of oxygen
Explanation: i just took the k12 test :)
7. Imagine you could look at the flashlight from behind your object, looking
from the darkest and lightest parts of the object's shadow. How much of
the light source do you think you could see from each location?
Answers
From the darkest part of the object's shadow, you would be able to see a small amount of the light source. There would be a small amount of light that is visible, but it would be faint. On the other hand, from the lightest part of the shadow, you would be able to see much more of the light source. The light source would be far brighter and more visible, and you would be able to identify the source of the light.
Hope this helps! Have a nice day. :)Two blocks are connected by a massless rope over a massless, frictionless pulley, as shown in the figure. The mass of block 2 is 2=11.3 kg , and the coefficient of kinetic friction between block 2 and the incline is =0.200 . The angle of the incline is 31.5° . If block 2 is moving up the incline at constant speed, what is the mass 1 of block 1?
Answers
The mass of block 1 is 1.30176 kg.
What is tension in physics?A tension force in physics is a force developed in a rope, string, or cable when stretched under an applied force.
Tension is acted along the length of the rope/cable in a direction that is opposite to the force applied on it.
According to the question,
Mass of block 2= 11.3 kg
Kinetic friction μ=0.200
The component of the weight in the direction of the incline
W = m₂gsinθ
T = \(F_{f} - W\)........(1)
When the force of friction
\(F_{f}\) = μ\(_k\)N
\(F_{f}\) = μ\(_k\)(m₂gcosθ)
Here , Put the value in equation 1
T = m₂gcos 31.5° - μ\(_k\)m₂gcos 31.5°
We know that ,
T - m₁g = 0
T = m₁g
So,
m₁g = m₂g (Sin 31.5° - 0.200 x cos 31.5°)
m₁ = 11.3 x (0.0840 - 0.2 x 0.996)
m₁ = 11.3 x (0.1152)
m₁ = 1.30176 kg
Hence, the mass of block 1 is 1.30176 kg.
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