Answers
Answer:
63.97 sheets of paper
Step-by-step explanation:
40-18.25 = 21.75
21.75 divided by 0.35 = 63.97
Related Questions
While doing research on a local river, a scientist put tags on 418 rainbow trout. Later, the scientist captured 251 rainbow trout, of which 15 had tags. To the nearest whole number, what is the best estimate for the rainbow trout population?
Answers
Answer:
about 6995
Step-by-step explanation:
The second catch indicates about 15/251 of the fish were tagged. Then the population can be estimated to be 251/15 times the number that were tagged:
(251/15)(418) ≈ 6995
The population can be estimated to be about 6995 trout.
A seamstress is covering a banner with fabric. she has a piece of fabric that is 2 yards long and 36 inches wide. what size banner can she cover with the fabric? multiply the length and width to find the answer.
Answers
The seamstress can cover a banner of **72 square inches** with the fabric.
The length of the fabric is 2 yards, which is equal to 72 inches. The width of the fabric is 36 inches. To find the size of the banner that the seamstress can cover with the fabric, we need to multiply the length and width.
```
72 inches * 36 inches = 2592 square inches
```
Therefore, the seamstress can cover a banner of 2592 square inches with the fabric.
Here is an explanation of the steps involved in finding the answer:
1. We convert the length of the fabric from yards to inches.
2. We multiply the length and width of the fabric.
3. We simplify the result to get the size of the banner in square inches.
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I need help doing a two column proof for this please
Answers
The congruent arcs arcAB and arcCD, indicates that the chords AB and CD are also congruent, which indicates that quadrilateral ABCD is an isosceles trapezium and ∠A = ∠C
What is an isosceles trapezoid?An isosceles trapezoid is a trapezoid that has congruent base angles and congruent non parallel sides.
The quadrilateral ABCD is a trapezoid, therefore;
BD is parallel to AC
The measure of the arcs AB and CD are the same;
arcAB = arcCD
The converse of the chord and intercepted arc theorem indicates that the lengths of the chords, AB and CD are the same, therefore;
The trapezoid ABCD is an isosceles trapezoid
Which indicates that the base angles ∠A and ∠C are congruent
∠A ≅ ∠C
Therefore; ∠A = ∠C
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Place the following steps in the correct order to find the test statistic and then evaluate a true sample test of meetings with population variances equal but I known.
Pull the sample variances.
Calculate the value of t.
Determine the P value
Calculate the sample standard deviation's.
Answers
The p-value is determined using the t-distribution with appropriate degrees of freedom. This allows us to assess the probability of observing a test statistic as extreme or more extreme than the calculated t-value.
The correct order of the steps to find the test statistic and evaluate a two-sample t-test with population variances equal but unknown is as follows:
Pull the sample variances.
Calculate the sample standard deviations.
Calculate the value of t.
Determine the p-value.
First, the sample variances are obtained by calculating the variance of each sample. This is done by finding the sum of squared differences between each observation and the sample mean, divided by the degrees of freedom.
Next, the sample standard deviations are calculated by taking the square root of the sample variances. This gives us a measure of the spread or variability within each sample.
The value of t is then computed using the formula: t = (mean1 - mean2) / (sqrt((s1^2 / n1) + (s2^2 / n2))), where mean1 and mean2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.
The p-value helps in making a decision about the null hypothesis, such as rejecting or failing to reject it based on a predetermined significance level.
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\(\frac{x^{2} -1}{16x} X \frac{4x^{2} }{5x + 5}\)
Answers
Answer:
x^2-x / 20
Step-by-step explanation:
\(\underline{\underline{\large\bf{Solution:-}}}\\\)
\(\begin{gathered}\\\implies\quad \sf \frac{x^{2} -1}{16x} \times \frac{4x^{2} }{5x + 5} \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf \frac{\cancel{(x+1)}(x-1)}{16x} \times \frac{4x^{2} }{5\cancel{(x + 1)}} \quad\quad(a^2-b^2 = (a+b)(a-b))\\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf \frac{x-1}{\cancel{16x}} \times \frac{\cancel4x^{\cancel2} }{5} \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf \frac{(x -1)(x)}{4\times 5} \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf \frac{x^2-x}{20} \\\end{gathered} \)
More Identities:-\(\begin{gathered}\boxed{\sf{ {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf{ {(a - b)}^{2} = {a}^{2} + {b}^{2} -2ab \: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf{ {x}^{2} - {y}^{2} = (x + y)(x - y) \: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf {(a + b)² = (a - b)² + 4ab\: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf {(a - b)² = (a + b)² - 4ab\: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf {(a + b)² + (a - b)² = 2(a² + b²)\: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf{ (a + b)³ = a³ + b³ + 3ab(a + b)\: }} \\ \end{gathered}\)
\(\begin{gathered}\boxed{\sf {(a - b)³ = a³ - b³ - 3ab(a - b)\: }} \\ \end{gathered}\)
Another identity problem...
Answers
Answer:
cot(x)=-sqrt(3)/3
Step-by-step explanation:
I'm going to use the Pythagorean Identity sin^2(x)+cos^2(x)=1 to find the sine value since cotangent value is the cosine value over sine value.
Plug in:
sin^2(x)+(-1/2)^2=1
Simplify:
sin^2(x)+1/4=1
Subtract 1/4 on both sidea:
sin^2(x)=3/4
Square root both sides:
sin(x)=sqrt(3)/2. [Sine is positive since x is in 2nd quadrant]
cot(x)=(-1/2)/(sqrt(3)/2))
cot(x)=-1/sqrt(3)
Rationalize denominator by multiplying by sqrt(3)/sqrt(3):
cot(x)=-sqrt(3)/3
cot(x)=
Differential Equations - Diff
. The general solution of the equation A. sin(x+y)+x² + 2y² = c D. sin(x+y)+2x+4y=c cos(x+y)+2x+(cos(x+y)+ B. cos(x + y) + x² = c E. None 4y)y' = 0 is C. sin(x+y)+ y² = c
Answers
The general solution of the given differential equation is C. sin(x+y)+ y² = c.
The given differential equation is in the form of a first-order homogeneous linear differential equation. To solve it, we can separate the variables and integrate.
First, we rewrite the equation in a more suitable form by rearranging the terms:
sin(x+y) + y² = c
Next, we can separate the variables by moving all the terms involving y to one side and the terms involving x to the other side:
sin(x+y) = c - y²
To solve for y, we can take the arcsine of both sides:
x+y = arcsin(c - y²)
Now, we can isolate y by subtracting x from both sides:
y = arcsin(c - y²) - x
This equation represents the general solution of the given differential equation. It shows that the value of y depends on the value of x and the constant c. The equation involves the inverse sine function, indicating that the solution may consist of multiple branches.
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Please tell me the answer
Answers
Answer: Its D
Step-by-step explanation:
negative is down and left positive is up and right
Consider the surface S given by the graph of z = x siny on the domain D {(x, y) 0 < x < 3,0 SY ST} . Suppose S has upward orientation. = Please do the following: . Parametrize this surface
Answers
The parametrization of the surface S is: r(x, y) = (x, y, x * sin(y)) for 0 < x < 3 and 0 < y < π.
To parametrize the surface S given by the graph of z = x * sin(y) on the domain D: 0 < x < 3, 0 < y < π, we can use the following parametrization:
r(x, y) = (x, y, x * sin(y))
Here, (x, y) represents the coordinates on the domain D, and r(x, y) represents the corresponding point on the surface S. The first component x represents the x-coordinate, the second component y represents the y-coordinate, and the third component x * sin(y) represents the z-coordinate.
Therefore, the parametrization of the surface S is:
r(x, y) = (x, y, x * sin(y)) for 0 < x < 3 and 0 < y < π.
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CC has the following beginning balances in its stockholders' equity accounts on January 1, 2012: Common Stock, $100,000; Additional Paid-in Capital, $4,100,000; and Retained Earnings, $3,000,000. Net income for the year ended December 31, 2012, is $800,000. Court Casuals has the following transactions affecting stockholders' equity in 2012:
May 18 Issues 25,000 additional shares of $1 par value common stock for $40 per share.
May 31 Repurchases 5,000 shares of treasury stock for $45 per share.
July 1 Declares a cash dividend of $1 per share to all stockholders of record on July 15. Hint: Dividends are not paid on treasury stock.
July 31 Pays the cash dividend declared on July 1.
August 10 Reissues 2,500 shares of treasury stock purchased on May 31 for $48 per share.
Taking into consideration all the entries described above, prepare the statement of stockholders' equity for the year ended December 31, 2012.
Answers
Total stockholders’ equity 7,800,000
Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000
Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000
Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000
Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000
To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.
The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.
Calculations:Opening balance of common stock = $100,000
Opening balance of additional paid-in capital = $4,100,000
Opening balance of retained earnings = $3,000,000
Net Income for the year ended December 31, 2012 = $800,000
Retained earnings (Opening Balance) = $3,000,000
Add: Net Income for the year ended December 31, 2012 = $800,000
Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000
Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000
Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000
Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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the measure of an angle is 166 degrees. what is the measure of of its supplementary angle?
Answers
Answer:
14°
Step-by-step explanation:
Supplementary angles add up to 180° so subtract 166 from 180.
10) In how many ways can you receive change for a qurter if at least one coin is a dime? You must show work
of how you came up with your answer.
Answers
Answer:
15
Step-by-step explanation:
How do you factor with a leading coefficient greater than 1?
Answers
Factoring polynomials with a leading coefficient greater than 1 is to use the factoring by grouping technique or quadratic formula.
Factoring a polynomial with a leading coefficient greater than 1 can be more challenging than factoring a polynomial with a leading coefficient of 1. However, there are several methods and techniques that can be used to factor such polynomials.
One common method for factoring polynomials with a leading coefficient greater than 1 is to use the factoring by grouping technique. This involves grouping the terms of the polynomial in pairs and factoring out the greatest common factor of each pair.
The resulting expressions can then be further factored or combined to obtain the final factorization of the polynomial.
Another method for factoring polynomials with a leading coefficient greater than 1 is to use the quadratic formula, which can be used to find the roots of a quadratic polynomial. Once the roots are found, the polynomial can be factored as a product of linear factors.
In some cases, it may also be helpful to use a combination of these techniques, along with other algebraic manipulations, such as completing the square or long division.
Overall, factoring a polynomial with a leading coefficient greater than 1 may require more patience and creativity than factoring a polynomial with a leading coefficient of 1, but with practice and persistence, it is possible to develop the skills and techniques needed to factor such polynomials efficiently and accurately.
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Find the area of the triangle whose side are 21 cm, 20 cm, 13 cm used heron's formula
Answers
Answer:
126cm².
Step-by-step explanation:
To use Heron's formula to find the area (A) of a triangle given the lengths of its sides, we need to first calculate the semiperimeter (s), which is half the perimeter of the triangle:
s = (21 + 20 + 13) / 2 = 27
Then, we can use the formula:
A = sqrt(s(s-a)(s-b)(s-c))
where a, b, and c are the lengths of the sides of the triangle. Substituting the values, we get:
A = sqrt(27(27-21)(27-20)(27-13))
A = sqrt(27 x 6 x 7 x 14)
A = sqrt(15876)guu
A=126 cm²
Therefore, the area of the triangle is approximately 126cm².
To find:-
The area of triangle .Answer:-
The given sides of triangle are 21cm , 20cm and 13cm . For a traingle of sides \( a \) , \( b \) and \( c \) , area of triangle by Heron's Formula is given by,
\(\implies A =\sqrt{ s(s-a)(s-b)(s-c)} \\\)
where,
s is semi perimeter.We can find semi perimeter as ,
\(\implies s =\dfrac{a+b+c}{2} \\\)
\(\implies s =\dfrac{21cm + 20cm + 13cm}{2} \\\)
\(\implies s =\dfrac{54}{2}=\boxed{27}\)
Now on substituting the respective values, we have;
\(\implies A =\sqrt{ 27 ( 27 - 21) (27-20)(27-13)}cm^2 \\\)
\(\implies A =\sqrt{ 27 \ . \ 6 \ . \ 7 \ . \ 14}cm^2\\\)
\(\implies A =\sqrt{ 3^3 \ . \ 3 \ . \ 2 \ . \ 7 \ . \ 7 \ . \ 2} cm^2\\\)
\(\implies A = 3^2 \ . \ 2 \ . \ 7 cm^2 \\\)
\(\implies Area = 126 cm^2 \\\)
Hence the area of the traingle is 126 cm² .
and we are done!
Write a system of inequalities to represent this
situation.
The Washington family is hosting a cookout. They
decide to serve chicken and pork. They determine
that they will need at most 20 pounds of meat, and
they want to have at least twice as much chicken as
pork.
Answers
Answer:
c + p <= 20
2c >= p
Step-by-step explanation:
We can declare our variables as:
c = pounds of chicken
p = pounds of pork
The total meat can be expressed as c + p, and at most signifies that the family needs 20 pounds or less. Putting this together, one equation becomes c + p <= 20.
The family additionally wants at least 2 * c as p, which means that 2*c is greater than or equal to p, or 2c >= p.
hope this helps :)
Anyone know how to do this?
Answers
Answer:The answer is 64 degrees
Step-by-step explanation:I looked it up and it gave me the answer of 64.
How many and what type of solutions does 5x2−2x+6 have?
1 rational solution
2 rational solutions
2 irrational solutions
2 nonreal solutions
Answers
Answer:
2 nonreal solutions
Step-by-step explanation:
given a quadratic equation in standard form
ax² + bx + c = 0 (a ≠ 0 )
then the nature of the roots are determined by the discriminant
b² - 4ac
• if b² - 4ac > 0 then 2 real and irrational solutions
• if b² - 4ac > 0 and a perfect square then 2 real and rational solutions
• if b² - 4ac = 0 then 2 real and equal solutions
• if b² - 4ac < 0 then no real solutions
5x² - 2x + 6 = 0 ← in standard form
with a = 5 , b = - 2 , c = 6
b² - 4ac
= (- 2)² - (4 × 5 × 6)
= 4 - 120
= - 116
since b² - 4ac < 0
then there are 2 nonreal solutions to the equation
Mr. Hudkins wants his 6th grade math class to memorize their multiplication facts. He decides to increase the number of facts they are expected to memorize each week and creates the following table.
Usingw = number of weeks and m = number of multiplication facts, which of the following equations is represented by the table Mr. Hudkins created?
A
m = 30 × 2w
B
m = 15 + w
C
w = 15m
D
m = 15w
Answers
Answer: m = 15w
Step-by-step explanation: The reason why the answer is m = 15w is because since he said "He decides to increase the number of facts they are expected to memorize each week." Which makes it so that only the multiplication fact increased to 15 since they wouldn't put it lower then that. And there is a 2nd reason why the multiplication fact is 15. the reason why is because theres only one answer with 30 and its completely wrong. So therefore,, The answer is Multiplication Fact = 15weeks.
Answer:
m = 15w
Step-by-step explanation:
i dont even know where to start
Answers
Answer:
51
Step-by-step explanation:
85/10=8.5, 8.5x6=51
Answer:
51 boys
Step-by-step explanation:
10 * x = 6 * 85
6 * 85 = 510
10x = 510
510 ÷ 10 = 51
x = 51 Boys
the regression sum of squares (ssr) can be greater than the total sum of squares (sst). group of answer choices true false
Answers
The given statement is False . That is regression sum of squares (ssr) can be greater than the total sum of squares (sst).
Regression sum of squares (ssr)
The sum of squares regression is the sum of the differences between the predicted value and the mean of the dependent variable.
SSR = ∑( yᵢ-cap - y-bar)² and i = 1 to N
Total Sum of Squares (SST) :
Total Sum of Squares is the deviation of the value of the dependent variable from the sample mean of the dependent variable. Essentially, the total sum of squares quantifies the total sample variation. It can be found using the formula:
SST = ∑(yᵢ - y-bar )²
The first is that the regression sum of squares cannot be computed as a total sum of squares. Let's find an explanation for this. We know that the sum of squares can be divided. There's the dualism of squares, some of the squares and regressions, sums of squares, dead food. A regression sum of squares is not formed, it is a total sum of squares. This means the statement is false. The next processing is the value, which is always positive, but we know that the value the confession of the adjustment, in the range -1 to 1.
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I need help please some one help
Answers
5(y -2)+3(4 -y)
Show and explain work
(Distributive property)
Answers
Answer:
Step-by-step explanation:
5 ( y - 2 ) + 3 ( 4 - y )
multiply 5 by both y and -2
5y - 10 + 3 ( 4 - y )
multiply 3 by by both 4 and -y
5y - 10 + 12 - y
hope this helps
Answer:
Step-by-step explanation:
You multiply 5×y and 5×-2 which is 5y-10 then multiply 3×4 and 3-y which gives you 12-3y.. 5y-10+12-3y. letters with letters (5y+-3) 2y -10 + 12 (2) I forgot the rest but I hope this helped with half of the work
Which expressions are equivalent to 4(4a + 5)?
Choose 3 answers:
16a + 5
16a + 20
12a + 20 + 4a
28a + 10)
16a +5 +4
Answers
Answer:
The Equivalent of 4 (4a+b) isStep-by-step explanation:
step 1.
4 (4a +b)
step 2. multiple the whole bracket by 4
(4× 4a + 4×5)
16a + 20
Unit 8 right triangles trigonometry
Answers
You need to use a trig function to solve for x. In relationship to the 70 degree angle, the 13 unit side is opposite to it. Side x is the hypotenuse. Because of this, you use the sine function. Sine of an angle = length of opposite side/length of hypotenuse (sin(x) = O/H). You already know two of these values, you just need to solve for the third.
Now, I plug 70 degrees in for c and 13 in for the length of the opposite side. I plug in x for length of hypotenuse.
sin(70) = 13/x
I need to isolate x on one side
x(sin(70))=13
x=sin(70)/13
x = 13.834
PLEASE HELP I REALLY NEED IT!!!! WORTH 100 POINTS
Given:
90 miles
75 min
27 songs on your iPod
Question: How many miles would you have to drive to hear 43 songs? Show how you solve the problem using units and conversion factors.
And for guaranteed brainliest if first is answered correctly and explained, how many minutes would this take (THIS QUESTION IS NOT REQUIRED BUT APPRECIATED
Answers
Answer:
Question 1 : The answer is 143.3 miles
Question 2 : The answer is 120 minutes
Step-by-step explanation:
1.Based on the give conditions:
\(43 \times 90 \div 27 \\ calculate \frac{43 \times 90}{27} = \frac{430}{3} \)\( = 143.3\)
2. 90 miles = 75min
143.3 ÷ 90 = 1.6
75 × 1.6 = 120
so the answer is 120 min
A helicopter descends until it reaches the ground. The equation y=-300x+1200 gives the height, y in feet, X minutes after the pilot begins the descent.
Answers
The x-intercept is (4, 0) and y-intercept is (0, 1200) for the equation y = -300x + 1200 and graph shown below.
Define a term Graph?The data are simply presented in a structured manner in the graph. It helps us understand the data better. The mathematical data accumulated through perception is alluded to as information.
The data or information is shown in a line graph by being connected to one another by a straight line, which is a series of markers or dots.
Given equation is: y = -300x + 1200
For y-intercept we have to put, x=0
⇒ y = 1200
For x-intercept put, y= 0
⇒ 0 = -300x +1200
⇒ x= 4
Hence, the y-intercept is ( 0, 1200 ) and the x-intercept is ( 4, 0 )
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each tile in the model represents 1/4. How many titles make a group of 3/4
Answers
Answer:
3 tiles
because 1/4+1/4+1/4=3/4
I hope this helps you!
What is 6/7 x 14 pls help me
Answers
Answer:
\( \sf \: \frac{6}{7} \times 14 = 12\)
Step-by-step explanation:
Given problem,
\( \sf \rightarrow \: \frac{6}{7} \times 14\)
Let's solve the problem,
\( \sf \rightarrow \: \frac{6}{7} \times 14\)
\( \sf \rightarrow \frac{6}{\cancel{ \: 7 }} \times \cancel{14}\)
\( \sf \rightarrow \: 6 \times 2\)
\( \sf \rightarrow \: 12\)
Hence, the answer is 12.
Which of these is always true?
Two lines that share common end point are always perpendicular.
Two lines that share common end point are always parallel.
Two lines that are the always same distance apart are perpendicular.
Two lines that are always the same distance apart are parallel.
Answers
The integer which lies between -1/4 and 3/2 are:
a)0 and 1 b)0 and -1 c)1 and -1 d)-1 and 2
Which option is right?
Answers
Answer:
The correct answer is a) 0 and 1.
Step-by-step explanation:
By converting the fractions into decimals, we can see that -1/4 is equivalent to -0.25 and 3/2 equals 1.5. Therefore, anything with a value outside of -0.25 < x < 1 should be marked out. So, anything containing anything less than -0.25 cannot be considered (i.e., -1) and anything above one cannot be considered (i.e., 2). Therefore, the only option left is a) 0 and 1.
Answer:
a) 0 and 1
Step-by-step explanation:
the easiest way to think about this problem is using a number line to picture where the numbers are. I cant really do that easily on here but i will try my best to explain it with words.
If you think about where the numbers are on a number line you should see that -1/4 is slightly less than zero, which would put it to the left of zero.
Likewise, if you think about 3/2, which is equal to \(1\frac{1}{2}\) it is slightly bigger than 1, which would put it to the right of 1 on a number line.
So if you think about the integers (which are numbers that can be positive or negative but do not involve decimals or fractions ex. -2, -1, 0, 1, 2 etc.) which are between those two numbers on the number line, the only integers are 0 and 1, which gives you your answer.