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The function's domain and range as represented either by set of ordered pairs:

Domain = (-13 , -7 , 5 , 11)

Range = (9 , -5 , 14 , 11)

Range and domain The domain of something like a function is the set of values that can be plugged into it. This set contains the x values in a function like f. (x). A function's range is the collection of values  that the function can take. This is the set of values that the function returns after we enter an x value.

The set of ordered pairs = {(-13, 9), (-7,-5), (5, 14), (11,-10)}.

(x,y)

x=input

y=output

As a result, the domain consists only of the first numbers.

range refers to all of the second numbers.

x=domain

y=range

So,

Domain = (-13 , -7 , 5 , 11)

Range = (9 , -5 , 14 , 11)

The function's domain and range as represented either by set of ordered pairs:

Domain = (-13 , -7 , 5 , 11)

Range = (9 , -5 , 14 , 11)

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The choices :

Three

B , E , D

The value of x in the equation 2/3(x - 5) - 1/4(x - 2)= -3/2 is x = 16/5

The equation is given as

2/3(x - 5) - 1/4(x - 2)= -3/2

Multiply through the equation by 12

So, we have

12 * 2/3(x - 5) - 12 * 1/4(x - 2)= -3/2 * 12

Evaluate the products

So, we have

8(x - 5) - 3(x - 2)= -18

Open the brackets

So, we have

8x - 40 - 3x + 6= -18

Evaluate the like terms

So, we have

5x = 16

Divide both sides of the equation by 15

So, we have

x = 16/5

Hence, the value of x in the equation 2/3(x - 5) - 1/4(x - 2)= -3/2 is x = 16/5

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Answer:

I thank it is the 3 ed one

Step-by-step explanation:

sorry if im wong

Answer:
3(n+7) =
(3)(n) + (3)(7) =
3n + 21

Step-by-step explanation:

I hope this helps you :D

The relation r2 on {a, b, c, d} is r2 = {(a,c),(a,d),(b,a),(b,c),(b,d),(c,c),(d,a),(d,c)}.

To find r2, we need to compute the composition of r with itself.

r2 = r ∘ r

To do this, we need to take each element in r and find all possible pairs that can be formed by combining the first element of the pair with the second element of another pair. Then we need to remove any duplicates from the resulting set.

Starting with r = {(a,b),(a,d),(b,c),(c,c),(d,a)}, we can form the following pairs:

(a,b) ∘ (a,d) = (b,d)

(a,b) ∘ (b,c) = (a,c)

(a,b) ∘ (d,a) = (b,a)

(a,d) ∘ (b,c) = (a,c)

(a,d) ∘ (c,c) = (a,c)

(a,d) ∘ (d,a) = (b,a)

(b,c) ∘ (c,c) = (b,c)

(b,c) ∘ (d,a) = (b,a)

(c,c) ∘ (c,c) = (c,c)

(d,a) ∘ (c,c) = (d,c)

(d,a) ∘ (d,a) = (a,a)

Removing duplicates, we get:

r2 = {(a,c),(a,d),(b,a),(b,c),(b,d),(c,c),(d,a),(d,c)}

Therefore, the relation r2 on {a, b, c, d} is r2 = {(a,c),(a,d),(b,a),(b,c),(b,d),(c,c),(d,a),(d,c)}.

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The value of "m" represents the length of side G F in the kite F G H K. The value of "m" is 3.5. Given that sides G F and F K are congruent, we can conclude that their lengths are equal.

We are given that the length of side G H is 5 m 1 and the length of side H K is 3 m 7.

To find the value of "m," we need to find the length of side G F.

Since G F and F K are congruent, we can set up an equation:

5 m 1 = 3 m 7

To solve for "m," we need to subtract 3 m from both sides of the equation:

5 m - 3 m = 3 m - 3 m + 7

This simplifies to:

2 m = 7

Now, we can solve for "m" by dividing both sides of the equation by 2:

m = 7 ÷ 2

m = 3.5

Therefore, the value of "m" is 3.5.

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a) To derive the integrated rate law from the second order rate law, we start with the differential rate equation:

\[ \frac{d[A]}{dt} = -k[A]^2 \]

where \([A]\) represents the concentration of the reactant A and \(k\) is the rate constant.

To integrate this equation, we separate the variables and integrate both sides:

\[ \int \frac{d[A]}{[A]^2} = -\int k dt \]

This gives us:

\[ -\frac{1}{[A]} = -kt + C \]

where \(C\) is the integration constant. We can rearrange this equation to isolate \([A]\):

\[ [A] = \frac{1}{kt + C} \]

To determine the value of the integration constant \(C\), we use the initial condition \([A] = [A]_0\) at \(t = 0\). Substituting these values into the equation, we get:

\[ [A]_0 = \frac{1}{C} \]

Solving for \(C\), we find:

\[ C = \frac{1}{[A]_0} \]

Substituting this value back into the equation, we obtain the integrated rate law:

\[ [A] = \frac{1}{kt + \frac{1}{[A]_0}} \]

b) The integrated rate law describes the relationship between the concentration of a reactant and time in a chemical reaction. It provides a mathematical expression that allows us to determine the concentration of the reactant at any given time, given the initial concentration and rate constant.

In the derived integrated rate law, we observe that the concentration of the reactant \([A]\) decreases with time (\(t\)). As time progresses, the denominator \(kt + \frac{1}{[A]_0}\) increases, leading to a decrease in the concentration. This is consistent with the second order rate law, where the rate of the reaction is directly proportional to the square of the reactant concentration.

The integrated rate law also highlights the inverse relationship between the concentration of the reactant and time. As the denominator increases, the concentration decreases. This relationship is important in understanding the kinetics of a chemical reaction and can be used to determine reaction orders and rate constants through experimental data analysis.

By deriving the integrated rate law, we can gain insights into the behavior of chemical reactions and make predictions about the concentration of reactants at different time points. This information is valuable in various fields, including chemical engineering, pharmaceuticals, and environmental science, as it allows for the optimization and control of chemical processes.

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The value of the line integral is approximately 2446.94.

To evaluate the line integral:

∫c (x^2y^2) ds

where c is the top half of the circle with radius 5 centered at (0,0) and is traversed in the clockwise direction, we can use the parameterization:

x = 5 cos(t)

y = 5 sin(t)

where t goes from pi to 2pi. This parameterization traces out the top half of the circle in the clockwise direction.

We can then express ds in terms of dt:

ds = sqrt[(dx/dt)^2 + (dy/dt)^2] dt

= 5 dt

Substituting the parameterization and ds into the integral, we get:

∫c (x^2y^2) ds = ∫pi^2pi (25cos^2(t) * 25sin^2(t)) (5 dt)

Simplifying, we get:

∫c (x^2y^2) ds = 3125 ∫pi^2pi (cos^2(t)sin^2(t)) dt

Using the identity cos^2(t)sin^2(t) = (1/4)sin^2(2t), we can further simplify:

∫c (x^2y^2) ds = (3125/4) ∫pi^2pi (sin^2(2t)) dt

Using the formula ∫sin^2(u) du = u/2 - (1/4)sin(2u), we can evaluate the integral:

∫c (x^2y^2) ds = (3125/4) [(2t)/2 - (1/4)sin(4t)]_pi^2pi

= (3125/4) [2pi - pi/4 - (2pi - pi/4)]

= (3125/4) (pi/2)

= 2446.94 (rounded to two decimal places)

Therefore, the value of the line integral is approximately 2446.94.

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Hi!

Your answer to this question would be every option except for 0.

This is because the question is saying: x is less than or equal to negative 3.

Thus, you answer, all options except 0

Have a wonderful/night!

God bless!

Answer: it is the 4 one which is 3(5-n)=2n+16

Answer:

7+8=15 that's the total

7\15 or 8\15

Answer: that is it’s simplest form

Step-by-step explanation:

The limit exists and is equal to 9/2.

In this case, we want to evaluate the limit of (t³ - 64)/(t² - 16) as t approaches 4. We can't substitute t=4 directly into the function because it results in an undefined value in the denominator.

We notice that the denominator can be factored as (t+4)(t-4). So, we can simplify the function as:

(t³ - 64)/(t² - 16) = ((t-4)(t²+4t+16))/((t-4)(t+4))

Now, we can cancel out the factor (t-4) from both the numerator and denominator to get:

(t³ - 64)/(t² - 16) = (t²+4t+16)/(t+4)

Now, we can substitute t=4 into the simplified function, which gives us:

(4²+4(4)+16)/(4+4) = 36/8 = 9/2

Therefore, the limit of the function as t approaches 4 exists and is equal to 9/2. We can write this as:

lim t→4 (t³ - 64)/(t² - 16) = 9/2

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x+2x+x=d is solution set of a linear system whose augmented matrix.

What does matrix mean?

First statement

[ 1 2 3 | d][x]

[ 1 2 3]x=d

x+2x+3x=d

Second statement

Ax=d

Given that A = [ 1 2 3]

[ 1 2 3]x=d

x+2x+3x=d

x+2x+x=d

Then, they are going to have the same solution

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The percentage of Country A women weigh between 110 and 200 pounds is 80%.

The percentage is the value of one quantity compared to a larger quantity.

The percentage is the quotient multiplied by 100.

Five-number summary for the weights of women in Country A = 100, 110, 120, 160, 200

The class value of women who weigh between 110 and 200 pounds = 4

The class value of women who weight less than between 110 and 200 pounds = 1

The ratio of women who weight between between 110 and 200 pounds and those who weigh less is 4:1

The sum of ratios = 5 (4 + 1)

The percentage of women weighing between between 110 and 200 pounds = 80% (4/5 x 100).

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There will be 60 residuals for simple bivariate regression's  60 observations.

According to the statement

We have given that the there is 60 observations and we have to find the number of simple bivariate regression for these observations.

So, For the solution of this problem,

We know that the

A simple linear regression (also known as a bivariate regression) is a linear equation describing the relationship between an explanatory variable and an outcome variable, specifically with the assumption that the explanatory variable influences the outcome variable, and not vice-versa.

And we know that the it is always same for the number as the number of given observations.

That's why there is 60 residuals.

So, There will be 60 residuals for simple bivariate regression's  60 observations.

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The Probability that all four of the light bulbs work is 0.004 approx.

The probability that all four light bulbs work can be calculated by taking the product of the probability that each individual light bulb works. If each light bulb works independently of the other light bulbs, then the probability that all four light bulbs work is:

P(all 4 bulbs) = P(bulb 1) * P(bulb 2) * P(bulb 3) * P(bulb 4)

P(all 4 bulbs) = 0.25 * 0.25 * 0.25 * 0.25

P(all 4 bulbs) = 0.25^4

P(all 4 bulbs) = 0.00390625

So, the probability that all four light bulbs work is 0.00390625 or approximately 0.004.

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The difference quotient of \(f(x) = x^2 - 6x + 5\) is is 2x - 6 + h.

To find the difference quotient for the function \(f(x) = x^2 - 6x + 5\), we need to evaluate

(f(x + h) - f(x)) / h, where h is not equal to 0.

First, let's find f(x + h):

\(f(x + h) = (x + h)^2 - 6(x + h) + 5\)

\(= x^2 + 2hx + h^2 - 6x - 6h + 5\)

\(= x^2 - 6x + 5 + 2hx - 6h + h^2\)

Now, we can substitute the values of f(x + h) and f(x) into the difference quotient:

\((f(x + h) - f(x)) / h = ((x^2 - 6x + 5 + 2hx - 6h + h^2) - (x^2 - 6x + 5)) / h\)

= (2hx - 6h + h^2) / h

= 2x - 6 + h

Therefore, the difference quotient of \(f(x) = x^2 - 6x + 5\) is 2x - 6 + h.

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Answer:

\(a_n=(-2)^{n-1}\)

Step-by-step explanation:

So a geometric sequence can be explicitly defined as: \(a_n = a_1(r)^{n-1}\). IN this case we're given r, but we don't know what a_1 is. We can find this by lugging in 4 as n, and -8 as a_n, since they're given values

Plug known values in:

\(-8 = a_1(-2)^{4-1}\)

Subtract the values in the exponent

\(-8 = a_1(-2)^3\)

Simplify the exponent

\(-8 = a_1 (-8)\)

Divide both sides by -8

\(1=a_1\)

So the nth term can be defined as: \(a_n = 1(-2)^{n-1}\), and since the 1 is redundant, the equation can simply be defined as: \(a_n=(-2)^{n-1}\)

Answer:

1.363

Step-by-step explanation:

Area of the sector is x/360 * pi * r^2

A = 40/360 * pi * 7*7

= 1/9 * 22/7 * 49

= 1/9 * 22 * 7

= 17.111111

Area of the triangle OMN = 1/2 ab sin C

so here A = 1/2 * 7 * 7 * sin 40

= 49/2 * sin 40

= 15.748296437320213494904763542728

so, Area of shaded segment is

= Area of sector - area of triangle

= 17.1111111 - 15.748296437320213494904763542728

= 1.363

The total number of possibilities or independent variables in R4X4  is 1 + 1 + 1 + 1 = 4. Thus, the dimension of S is 4.
the total number of possibilities or independent variables in the subspace of R3×3 is 3 + 2 + 1 = 6. Hence, the dimension of S is 6.

The dimension of the subspace S of upper triangular matrices in R3x3 is 6.

To determine the dimension of the subspace S, we need to find the number of linearly independent vectors that span S.

In the case of upper triangular matrices in R3x3, we can observe that the entries below the main diagonal (including the diagonal) can be arbitrary values since they do not affect the upper triangular structure. Thus, we have:

The first row has 3 possibilities.

The second row has 2 possibilities (excluding the first entry).

The third row has 1 possibility (excluding the first and second entries).

Therefore, the total number of possibilities or independent variables is 3 + 2 + 1 = 6. Hence, the dimension of S is 6.

(b) The dimension of the subspace S of diagonal matrices in R4x4 is 4.

Explanation:

In the case of diagonal matrices in R4x4, all the entries outside the main diagonal are zero. Therefore, we have:

The first diagonal entry has 1 possibility.

The second diagonal entry has 1 possibility.

The third diagonal entry has 1 possibility.

The fourth diagonal entry has 1 possibility.

Hence, the total number of possibilities or independent variables is 1 + 1 + 1 + 1 = 4. Thus, the dimension of S is 4.

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Answer:

(A) 1

Step-by-step explanation:

We know that the formula is x = (m/m+n) (x2-x1) + x1.

But the trick to the question which is why everyone is getting it wrong is because it asks for F to D not D to F.

The reason everyone else was getting 4 was because they were using this.

They solved the equation x = (8/8+5) (9-[-4]) -4 where it was D to F. This equation does turn out to be 4 but it is incorrect.

However, the correct equation (because it is supposed to be F to D) is

x = (8/8+5) (-4 -9) +9 which is in fact equal to 1.

I also just took the quiz and got 100%.

PRESS THAT THANKS BUTTON!!!

Answer:

Step-by-step explanation:

You want an equation and its solution to help you find the number of miles Carter must ride his bicycle each day (m) to total 28.7 miles after 3 more days, given he has already ridden 17 miles this week.

The total number of miles for the week will be 28.7. That will consist of the sum of miles already ridden (17) and the number each day multiplied by the remaining number of days.

The miles ridden each day is defined in the problem statement as "m". The number of remaining days is 3, so the total number of miles ridden on those days will be 3m.

Carter wants the sum to be ...

  17 +3m = 28.7

This is the equation being asked for.

This 2-step equation is solved in the usual way:

  3m = 11.7 . . . . . . . . subtract 17 from both sides

  m = 3.9 . . . . . . . . . divide both sides by 3

Carter would have to ride an average of 3.9 miles each day to reach his goal.

__

Additional comment

Your life experience should tell you how things add up. A total is the sum of its parts. Total miles = (miles already done) + (miles to go), for example.

Multiple things that are the same value can be "added" using multiplication: m + m + m = 3m, for example.

Answer:

M=6/7 (M= six over seven)

Step-by-step explanation:

Answer:

\(\boxed{\sf{-3}}\)

Step-by-step explanation:

You can solve this problem by using the slope formula to find the slope of the line.

Slope formula:

\(\sf{\dfrac{Y_2-Y_1}{X_2-X_1}=\dfrac{RISE}{RUN}}\)

y2=(-2)

y1=10

x2=(-5)

x1=(-9)

Rewrite the problem down and then solve it.

\(\sf{\dfrac{(-2)-10}{(-5)-(-9)} }=\dfrac{-2-10}{-5+9}=\dfrac{-12}{4}\)

Divide by 4 as well.

\(\sf{\dfrac{-12\div4}{4\div4}=\dfrac{-3}{1}=\boxed{\sf{-3}}}\)

Therefore, the slope is -3.

I hope this helps! Let me know if my answer is wrong or not.

Answer : value of x and y in the matrix equation is:

x = -3

y = +4, -4

Step-by-step explanation :

The matrix expression is:

\(\left[\begin{array}{ccc}x+4\\y^2+1\end{array}\right]+\left[\begin{array}{ccc}-9x\\-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

First we have to add left hand side matrix.

\(\left[\begin{array}{ccc}(x+4)+(-9x)\\(y^2+1)+(-17)\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

Now we have to add left hand side terms.

\(\left[\begin{array}{ccc}x+4-9x\\y^2+1-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

\(\left[\begin{array}{ccc}4-8x\\y^2-16\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

Now we have to equating left hand side matrix to right hand matrix, we get:

\(\Rightarrow 4-8x=28\text{ and }y^2-16=0\\\\\Rightarrow 8x=4-28\text{ and }y^2=16\\\\\Rightarrow x=-3\text{ and }y=\pm 4\)

Therefore, the value of x and y in the matrix equation is -3 and +4, -4 respectively.

Answer:

D is wrong. The correct answer choice is C ( x=-3 and y= +4, -4)

Step-by-step explanation:

Math unit test review

Answer:

5

Step-by-step explanation:

12-7=5

Answer:

5

Step-by-step explanation:

We know that x is equal to 7. That means we can replace x with this value. This makes our new expression:

12 - 7

12-7 is equal to 5, so this expression will equal 5 when x = 7.

Answer:

blue

Step-by-step explanation:

you have to multiply the length x width so 18x8 to get the area for the rectangle which is 144 and then multiply the base and the height then multiply that by 0.5 to get the area for the triangle so it will be 8x6=48 48x0.5=24 then add the area of the triangle to the area of the rectangle so 24+144=168

Answer:

156.54 ft^2

Step-by-step explanation:

Area of rectangle

18.5 x 10 = 185

Area of quater of a circle

pi x 10^2 x 1/4 = 78.53981634...

Area of entire shape

185 + 78.53981634... = 156.53981634...

Answer:

2/8 po sana maka tulong po salamat

StartFraction 36 + 9 StartRoot 7 EndRoot + 4 StartRoot 2 EndRoot + StartRoot 14 EndRoot Over 9 EndFraction is the Square root.

What in mathematics is a square root?

It is possible to multiply an integer by its square root in order to obtain the original value.

                         Square root is represented by the symbol sqrt, which stands for square root of, end square root. The opposite of squaring an integer is finding its square root.

(9 + sqrt(2))/(4 - sqrt(7))

Multiply and divide by 4 + sqrt(7)

[(9 + sqrt(2))(4 + sqrt(7))]/(4² - 7)

[36 + 4sqrt(2) + 9sqrt(7) + sqrt(14)]/9

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