Please solve this questions. Just write True or False. I think its simple for you.

The value of x for the second triangle if it is the reduction of the first drawing is 6.3 feet.

Given two triangles.

Also given that, the scale drawings given are the reduction of the figure.

Most probably, the second triangle must be formed after a reduction with a scale factor of k.

Let k be the required scale factor.

The value of k can be found by taking the ratio of the corresponding sides.

k = 5.2 / 10.4

  = 0.5

So all the corresponding sides will be half of the first triangle.

x = 0.5 × 12.6

  = 6.3 feet

Hence the value of x is 6.3 feet.

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Answer:

y = x + 1

Step-by-step explanation:

Parallel lines have same slope.

y = x - 1

Compare with the equation of line in slope y-intercept form: y = mx +b

Here, m is the slope and b is the y-intercept.

m =1

Now, the equation is,

         y = x + b

The required line passes through (-3 ,-2). Substitute in the above equation and find y-intercept,

        -2 = -3 + b

  -2 + 3 = b

         \(\boxed{b= 1}\)

    Equation of line in slope-intercept form:

                  \(\boxed{\bf y = x + 1}\)      

The equation is :

Solution:

If two lines are parallel to each other, then their slopes are equal. The slope of y = x - 1 is 1. Hence, the slope of the line that is parallel to that line is 1.

We shouldn't forget about a point on the line : (-3, -2).

I plug that into a point-slope which is :

\(\sf{y-y_1=m(x-x_1)}\)

Slope is 1 so

\(\sf{y-y_1=1(x-x_1)}\)

Simplify

\(\sf{y-y_1=x-x_1}\)

Now I plug in the other numbers.

-3 and -2 are x and y, respectively.

\(\sf{y-(-2)=x-(-3)}\)

Simplify

\(\sf{y+2=x+3}\)

We're almost there, the objective is to have an equation in y = mx + b form.

So now I subtract 2 from each side

\(\sf{y=x+1}\)

Thanks for the update. "Irrotational" means curl = zero, so we compute the curl, set it equal to zero, and solve for the constants.

\(\vec f(x,y,z) = (axy+z^3) \, \vec\imath + (3x^2-z) \, \vec\jmath + (bz^2-y) \, \vec k\)

\(\nabla \times \vec f(x,y,z) = \left(\dfrac{\partial(bz^2-y)}{\partial y} - \dfrac{\partial(3x^2-z)}{\partial z}\right) \, \vec\imath - \left(\dfrac{\partial(bz^2-y)}{\partial x} - \dfrac{\partial(axy+z^3)}{\partial z}\right) \, \vec\jmath \\ ~~~~~~~~~~~~ + \left(\dfrac{\partial(3x^2-z)}{\partial x} - \dfrac{\partial(axy+z^3)}{\partial y}\right) \, \vec k\)

\(\nabla \times \vec f(x,y,z) = 3z^2 \, \vec\jmath + (6-a)x \, \vec k\)

At this point, all we can conclude is that a = 6 to make the k-component vanish. Unfortunately there's no zeroing out the j-component, so the field as given is *not* irrotational.

As I mentioned in comments, if the i-component had instead been \(axy+bz^3\), we would have ended up with

\(\nabla \times \vec f(x,y,z) = 3bz^2 \, \vec\jmath + (6-a)x \, \vec k\)

in which case we would have b = 0.

I'll continue working with this "fixed" field to find Φ, if only to give you an idea of how to proceed. We want a scalar function Φ(x, y, z) such that the given vector field is the gradient of f. This would entail solving the partial differential equations,

\(\dfrac{\partial\Phi}{\partial x} = axy+bz^3 = 6xy\)

\(\dfrac{\partial\Phi}{\partial y} = 3x^2 - z\)

\(\dfrac{\partial\Phi}{\partial z} = bz^2-y = -y\)

Let's start with the last equation. Integrating both sides with respect to z yields

\(\Phi(x,y,z) = \displaystyle \int (-y) \, dz = -yz + g(x,y)\)

Now differentiate both sides with respect to y :

\(\dfrac{\partial\Phi}{\partial y} = -z + \dfrac{\partial g}{\partial y} = 3x^2 - z \implies \dfrac{\partial g}{\partial y} = 3x^2\)

Integrate both sides of the latter PDE with respect to y to solve for g :

\(g(x,y) = \displaystyle \int 3x^2 \, dy = 3x^2y + h(x)\)

Now we differentiate Φ with respect to x :

\(\Phi(x,y,z) = -yz + 3x^2y + h(x) \\\\ \dfrac{\partial\Phi}{\partial x} = 6xy + \dfrac{dh}{dx} = 6xy \implies \dfrac{dh}{dx} = 0\)

Integrate to solve for h :

\(h(x) = \displaystyle \int 0 \, dx = C\)

where C is an arbitrary constant.

So the scalar function whose gradient is our "fixed" field f is

\(\Phi(x,y,z) = -yz + 3x^2y + C\)

Answer:

$7/lb

Step-by-step explanation:

$70 / 10 lb = $7/lb

Answer:

$7 per pound of letuce

Step-by-step explanation:

We know

10 pounds = $70

1 pounds = ?

We cross multiply and get:

$7 per pound of letuce

So, the answer is $7 per pound of letuce

Answer:

the two equivalent ratios of 4 : 5 are 8 : 10 and 12 : 15.

Step-by-step explanation:

the two equivalent ratios of 4 : 5 are 8 : 10 and 12 : 15.

Answer:

f(x) = x³ - 4x + 6

f'(x) = 3x² - 4

a) f'(2) = 3(2²) - 4 = 12 - 4 = 8

6 = 8(2) + b

6 = 16 + b

b = -10

y = 8x - 10

b) 3x² - 4 = 0

3x² = 4, so x = ±2/√3 = ±(2/3)√3

= ±1.1547

f(-(2/3)√3) = 9.0792

f((2/3)√3) = 2.9208

c) 3x² - 4 = 8

3x² = 12

x² = 4, so x = ±2

f(-2) = (-2)³ - 4(-2) + 6 = -8 + 8 + 6 = 6

6 = -2(8) + b

6 = -16 + b

b = 22

y = 8x + 22

f(2) = 6

y = 8x - 10

The equation perpendicular to the tangent is y = -1/8x + 25/4

-The smallest slope on the curve is 2.92

The curve has the smallest slope at the point (1.15, 2.92)

The equations at tangent points are y = 8x + 16 and  y = 8x - 16

From the question, we have the following parameters that can be used in our computation:

y = x³ - 4x + 6

Differentiate

So, we have

f'(x) = 3x² - 4

The point is (2, 6)

So, we have

f'(2) = 3(2)² - 4

f'(2) = 8

The slope of the perpendicular line is

Slope = -1/8

So, we have

y = -1/8(x - 2) + 6

y = -1/8x + 25/4

We have

f'(x) = 3x² - 4

Set to 0

3x² - 4 = 0

Solve for x

x = √[4/3]

x = 1.15

So, we have

Smallest slope = (√[4/3])³ - 4(√[4/3]) + 6

Smallest slope = 2.92

So, the smallest slope is 2.92 at (1.15, 2.92)

Here, we set f'(x) to 8

3x² - 4 = 8

Solve for x

x = ±2

Calculate y at x = ±2

y = (-2)³ - 4(-2) + 6 = 6: (-2, 0)

y = (2)³ - 4(2) + 6 = 6: (2, 0)

The equations at these points are

y = 8x + 16

y = 8x - 16

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By using the concept of dilation factor, length of BC obtained is 3 units

What is dilation factor?

Dilation is a transformation which changes the size of a figure by a certain factor.

That factor is called the scale factor

In the figure, A'B'C'D' is the image of ABCD under dilation with a scale factor of 3

A'B'C'D' is the dilated figure

Length of B'C' = 9 units

Length of BC = \(9 \div 3\) = 3 units

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Complete Question

The figure has been attached here

answer is 2 because if we expand the bracket we get 2x–8y+3y which is 2x–5y but if it was 2(x+4y) it would be equal to 2x+8y+3y therefore being 2x+11y

The quotient of z₁ by z₂ in trigonometric form is:

7/21 * (cos(584°) + i sin(584°))

To find the quotient of z₁ by z₂ in trigonometric form, we'll express both complex numbers in trigonometric form and then divide them.

Let's represent z₁ in trigonometric form as z₁ = r₁(cosθ₁ + isinθ₁), where r₁ is the magnitude of z₁ and θ₁ is the argument of z₁.

We have:

z₁ = 7(cos(577°) + i sin(577°))

Now, let's represent z₂ in trigonometric form as z₂ = r₂(cosθ₂ + isinθ₂), where r₂ is the magnitude of z₂ and θ₂ is the argument of z₂.

From the given information, we have:

z₂ = 21(cos(-7°) + i sin(-77°))

To find the quotient, we divide z₁ by z₂:

z₁ / z₂ = (r₁/r₂) * [cos(θ₁ - θ₂) + i sin(θ₁ - θ₂)]

Substituting the given values, we have:

z₁ / z₂ = (7/21) * [cos(577° - (-7°)) + i sin(577° - (-7°))]

= (7/21) * [cos(584°) + i sin(584°)]

The quotient of z₁ by z₂ in trigonometric form is:

7/21 * (cos(584°) + i sin(584°))

Option C, 21(cos(-7°) + i sin(-77°)), is not the correct answer as it does not represent the quotient of z₁ by z₂.

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Answer:

12000 rad/min

Step-by-step explanation:

One formula we can use here is that the linear speed is the same, and the linear speed is equal to the angular speed multiplied by the radius.

Therefore, 2400π rad/min* 35 cm = 7 cm* x, with x representing the angular speed of the smaller wheel in radians per minutes. Dividing both sides by 7 cm, we get

2400π rad/min * 35 cm / 7 cm = x

2400 π rad/min * 5 = 12000 rad/min = x as our answer

The domain of the graph of the exponential function is (d) all real numbers

From the question, we have the following parameters that can be used in our computation:

The graph of the exponential function

The rule of an exponential function is that

The domain is the set of all real numbers

This means that the input value can take all real values

However, the range is always greater than the constant term

From the graph, the constant term is 0

So, the range is y > 0

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Answer:

CAB is 37 degrees

Step-by-step explanation:

90 + 53 = 143

180 - 143 = 37

Answer:

amount of coloured fabric in mm = 48

amount of white fabric in mm = 12

ratio = white fabric : coloured fabric = 12 : 48 = 1:4

Answer:

The answer is D

Step-by-step explanation:

Answer:

Intersecting (fourth answer choice)

Step-by-step explanation:

First, let's convert both lines to slope-intercept form, whose general equation is y = mx + b, where

Converting y - 3x = 4x to slope-intercept form:

(y - 3x = 4x) + 3x

y = 7x

Thus, the slope of this line is 7 and the y-intercept is 0.

Converting 6 - 2y = 8x to slope-intercept form:

(6 - 2y = 8x) - 6

(-2y = 8x - 6) / -2

y = -4x + 3

Thus, the slope of this line is -4 and the y-intercept is 3.

Checking if y = 7x and y = -4x + 3 are perpendicular lines:

We can show this in the following formula:

m2 = -1 / m1, where

Thus, we only have to plug in one of the slopes for m1.  Let's do -4.  

m2 = -1 / -4

m2 = 1/4

Thus, the slopes 7 and -4 are not negative reciprocals of each other so the two lines are not perpendicular.

 Checking if y = 7x and y = -4x + 3 are parallel lines:

The slopes of parallel lines are equal to each other.

Because 7 and -4 are not equal, the two lines are not parallel.

Checking if the lines intersect:

Method to solve the system:  Elimination:

We can multiply the first equation by -1 and keep the second equation the same, which will allow us to:

-1 (y = 7x)

-y = -7x

----------------------------------------------------------------------------------------------------------

    -y = -7x

+

    y = -4x + 3

----------------------------------------------------------------------------------------------------------

(0 = -11x + 3) - 3

(-3 = -11x) / 11

3/11 = x

Now we can plug in 3/11 for x in y = 7x to find y:

y = 7(3/11)

y = 21/11

Thus, x = 3/11 and y = 21/11

We can check our answers by plugging in 3/11 for x 21/11 for y in both y = 7x and y = -4x + 3.  If we get the same answer on both sides of the equation for both equations, the lines intersect:

Checking solutions (x = 3/11 and y = 21/11) for y = 7x:

21/11 = 7(3/11)

21/11 = 21/11

Checking solutions (x = 3/11 and y = 21/11) for y = -4x + 3:

21/11 = -4(3/11) + 3

21/11 = -12/11 + (3 * 11/11)

21/11 = -12/11 + 33/11

21/11 = 21/11

Thus, the lines y = 3x = 4x and 6 - 2y = 8x are intersecting lines (the first answer choice).

This also means that lines are not skew since lines had to be neither perpendicular nor parallel nor intersecting to be skew.

Answer:

x = 0.39 or

x = -1.72

Step-by-step explanation:

The quadrateic formula is:

\(x = \frac{-b\pm\sqrt{b^2 - 4ac} }{2a}\)

eq: 3x² + 4x - 2

which is of the form ax² + bx + c = 0

where a = 3, b = 4 and c = -2

sub in quadratic formuls,

\(x = \frac{-4\pm\sqrt{4^2 - 4(3)(-2)} }{2(3)}\\\\=\frac{-4\pm\sqrt{16 + 24} }{6}\\\\=\frac{-4\pm\sqrt{40} }{6}\\\\=\frac{-4\pm2\sqrt{10} }{6}\\\\=\frac{-2\pm\sqrt{10} }{3}\\\\=\frac{-2+\sqrt{10} }{3} \;or\;=\frac{-2-\sqrt{10} }{3}\\\\=0.39 \;or\; -1.72\)

The relationship between the number of students that are good at a given subject is an illustration of sets.

We use the following representations:

\(M \to\) Mathematics

\(E \to\) English

\(P \to\) Psychology

From the question, we have the following parameters

\(M = 45\) -- Mathematics

\(M\ n\ E =15\) -- Mathematics and English

\(M\ n\ P =13\) -- Mathematics and Psychology

\(E\ n\ P =16\) -- English and Psychology

\(P=20\) -- Psychology

\(All = 9\) -- All 3 subjects

\(Total = 80\) -- All students

The number of students that are good at mathematics only is as follows:

First, we calculate those that are good at mathematics and English only

\((M\ n\ E)' = M\ n\ E - All\)

\((M\ n\ E)' = 15 - 9 = 6\)

Then those that are good at mathematics and psychology only

\((M\ n\ P)' = M\ n\ P - All\)

\((M\ n\ P)' = 13 - 9 = 4\)

So, the students that are good at mathematics only are:

\(M' = M - (M\ n\ E)' -(M\ n\ P)' - All\)

\(M' = 45 - 6 -4 -9\)

\(M' = 26\)

Hence, 26 students are good at Mathematics only.

To calculate the number of students that are not good in any of the subjects, we make use of the complement rule

\(A + A' = Total\)

Where:

\(A \to\) Students that are not good in any

\(A' \to\) Students that are good in at least one

So, we have:

\(A' =M' + (M\ n\ E)' + (M\ n\ P)' + (E\ n\ P)' + All\)

Where:

\((E\ n\ P) = (E\ n\ P)' - All\)

\((E\ n\ P) = 16-9 = 7\)

The equation becomes:

\(A' =26 + 6 + 4+7+9\)

\(A' =52\)

Recall that:

\(A + A' = Total\)

\(A = Total - A'\)

\(A = 80 - 52\)

\(A = 28\)

Hence, 28 students are not good at all.

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The equation of the perpendicular line passing through (0, -1) is y = -9x - 1.

To find the equation of a line that is perpendicular to the given line y = (1/9)x + 2 and passes through the point (0, -1), we can use the fact that perpendicular lines have slopes that are negative reciprocals of each other.

The given line has a slope of 1/9. To find the slope of the perpendicular line, we take the negative reciprocal of 1/9, which is -9.

Using the slope-intercept form of a linear equation, y = mx + b, where m represents the slope and b represents the y-intercept, we can substitute the slope and the coordinates of the given point (0, -1) into the equation.

y = -9x + b

Since the line passes through the point (0, -1), we can substitute the x-coordinate as 0 and the y-coordinate as -1 into the equation:

-1 = -9(0) + b

-1 = b

Therefore, the y-intercept (b) of the perpendicular line is -1.

Putting it all together, the equation of the line that passes through (0, -1) and is perpendicular to y = (1/9)x + 2 is:

y = -9x - 1

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Answer:

1, 4, 7

Step-by-step explanation:

This must be the answer to your problem

Answer:

Step-by-step explanation:

k(k+1)(k+2) - 3k(k+1)

k and (k+1) are common to both terms.

k(k+1)(k+2) - 3k(k+1) = k(k+1)[(k+2) - 3] = k(k+1)(k-1)

The Distance the handler will move from the starting point to the return point will be approximately 439.8204 feet.

The distance the handler will move from the starting point to the return point when creating an arc of a circle with a radius of 70 feet, we need to find the length of the arc.

The formula to calculate the length of an arc is given by:

Length of arc = (θ/360) * 2πr

Where:

θ is the central angle of the arc (in degrees)

r is the radius of the circle

In this case, since the handler is creating a full circle, the central angle is 360 degrees.

Length of arc = (360/360) * 2π * 70

Length of arc = (1) * 2π * 70

Length of arc = 2π * 70

Length of arc = 140π

To find the approximate value in feet, we can use the approximation π ≈ 3.14159.

Length of arc ≈ 140 * 3.14159

Length of arc ≈ 439.8204 feet

Therefore, based on the given theory and using a circle with a radius of 70 feet, the distance the handler will move from the starting point to the return point will be approximately 439.8204 feet.

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Answer:

1/2

Step-by-step explanation:

In a deck of cards, there are 13 hearts and 13 diamonds

13+13 = 26 hearts or diamonds

P( hearts or diamonds) = numbers of hearts or diamonds / total

                                       =26/52

                                       = 1/2

Answer:

2.3,2 4/5, 3.01, 3.017, 3.10, 4 1/8, 4.2

19

\( \mathtt \red{Hope \: it \: helps \: uhh..}\)

answer = 19 Haha.......

The answer is a. (4,0) and (0,-2)

Answer:

18

Step-by-step explanation:

Answer:

Step-by-step explanation:

3y – 6x = 3     -----------------------------------(I)

y = 2x + 1      ----------------------------------(II)

Substitute y = 2x + 1 in equation (I)

3*(2x+ 1) - 6x = 3

3*2x + 3*1 -6x = 3

  6x + 3 - 6x = 3              

               3 = 3

So, no solutions

Answer:

Use the substitution method to determine the solution type of the following system.

3y – 6x = 3

y = 2x + 1

Correct Answer

Infinitely many solutions

No solutions

(3, –1)

(2, 0)

Step-by-step explanation: