PLEASE SOLVE FAST!!! If the average American watches hours of TV every day , how many minutes will be spent in front of the TV by a person's 65th birthday? Solve using Dimensional Analysis.

Answer:

5 m/s

Explanation:

We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time

So, mass flow rate = 9000 kg / 1 minute = 150 kg/s

We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity

So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)

Solving for v (velocity):

v = 150/(1000*0.3) = 5 m/s

Therefore, the speed of water in the pipe is 5 m/s.

Answer:

Speed. I am speed.

Explanation:

The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible.

The gravitational force that the earth exerts on you is 444.52 N

Your mass, m = 100 pounds

m = 100 x 0.453592

m = 45.3592 kg

The gravitational force that the earth exerts on you is your weight

The weight is calculated by the formula:

W = mg

where g = 9.8 m/s²

The weight is therefore:

W = 45.3592 x 9.8

W = 444.52 N

Since the weight is the same as the gravitational force that the earth exerts on you, the gravitational force that the earth exerts on you is 444.52 N

So the acceleration of the student-bicycle system is \(a=5m/s^{2}\).

The gravitational force that acts on the bicycle system is

\(F_{g}=500N\)

Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.

Therefore, we can write

\(F_{g}=mg\)

500  = m x 10    (since , g = 10 m/s-s)

∴ m = 50 kg

Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write

\(F_{f}=ma\)

\(a=\frac{F_{f}}{m}\)

\(=\frac{250}{50}\)

Therefore \(a=5m/s^{2}\)

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The complete question is

A student rides a bicycle in a circle at a constant speed and constant radius. A force diagram for the student-bicycle system is shown in the figure above. The value for each force is shown in the figure. What is the acceleration of the student-bicycle system?

Shantanu's average velocity is 5 km/hour (or 5 km/hr) and his velocity in meters per second is 1.39 m/s.

What is Velocity?

Velocity is a vector quantity that describes the rate at which an object changes its position in a specific direction. In other words, velocity is the rate of displacement of an object per unit of time in a specific direction. It is a measure of both the speed and direction of an object's motion.

Shantanu's average velocity can be calculated by dividing the distance traveled by the time taken:

Average velocity = distance/time = 5 km/1 hour = 5 km/hour (or 5 km/hr)

To convert Shantanu's velocity to meters per second, we need to convert kilometers per hour to meters per second by multiplying by 0.2778 (1 km/hr = 0.2778 m/s):

Average velocity = 5 km/hour x 0.2778 m/s/km = 1.39 m/s (rounded to two decimal places)

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Answer:

B. Subtract the new volume from the original volume

Explanation:

Answer:

Explanation:

5-) in the 1st system the right side is heavier, the system is moving in that way with a 9.8k m^2/s

in the 2nd system right side is heavier too, the system is moving in that way with a 9.8k m^2/s

in the 3rd system both sides got the same weight so the system isn't moving in anyway. 0 m^2/s

There are two girders and 5 beams Each beam spans between two girders. The tributary area of rim  joist is  864ft²

Length of the rim joist = Y ft = 36ft

Length of each bay out of 4 = X/4 = 96/4 = 24ft

Tributary width of rim joist is half on each bay to its side

Tw = 24/2 + 24/2 = 24

Tributary area Ta = tw × length

Ta = 24 × 36 = 864ft²

The floor or roof area (in plan) that results in loading on a certain structural element is known as the tributary area. In each direction, name the adjacent column.

the distance between the two, measured.

multiplying by two the distance

From here, create a perpendicular line.

Repeat until a bounding polygon appears for each gridline that is close by.

A beam's tributary area is equal to its length times the addition of half its space to each adjacent girder.

The square footage of the deck surface area supported by one post is known as the tributary area. Depending on how the deck is set up, this can differ for each post.

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Weight of a body is defined as the force with which it is attached to the earth.

mass is the total quantity of matter present.

the weight of something is given as mass * acceleration

weight of an object is directly proportional to the mass of the object.  so, if mass doubles, weight will also double.

hope this helps :)

- jeron

Answer:

Incomplete question but the closest ans is

A) The displacement is not zero

Explanation:

For work to be done, the direction of force has to be parallel to or in the same direction as the displacement, this can then be calculated by

\(W=Fs \ cos\)θ

Where θ is the angle between direction of force and direction of displacement

By this equation,

if Force is zero, W is zero

if displacement is zero, W is zero

if force and displacement are perpendicular θ=90, cosθ = 0

So A is the cloest choices

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Given,

The mass of the teacher, m=63.5 kg

The height from which the teacher falls, h=1.55 m

Work is the measure of the transfer of energy. The work done by gravity will be equal to the potential energy lost by the teacher while falling. As she falls to the ground, she loses all her potential energy.

Therefore the work done by the gravity is given by,

Where g is the acceleration due to gravity.

On substituting the known values,

Thus the work done by gravity is 964.57 J

Answer:

average velocity = \(\bf 900 \space\ km/h\)

Explanation:

We can find the average velocity using the following equation:

\(\boxed{average \space\ velocity = \frac{total \space\ distance \space\ travelled}{ \space\ time \space\ taken}}\) .

In this case:

• total distance travelled = 450 km

• time taken = 30 min = 0.5 h

Substituting these values into the equation:

\(average \space\ velocity = \frac{450 \space\ km }{ 0.5 \space\ h}\)

                          ⇒ \(\bf 900 \space\ km/h\)

Answer:

3A

Explanation:

Rtoal=R1+R2+R3=5+10+15=30

I=V/R 90/30

I=3

Answer:

40 m

Explanation:

4 m/s   * 10 s   = 40 m  

  ( see how the 's' cancels out and you're left with "m" as your answer?)

Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.

~~~Harsha~~~

One of the main uses of this device is to examine a beam of charged particles

The cathode ray tube is a device used to determine the charge flowing in a gas. When an electric field is set up with the help of metal electrodes, the cathode ray tends to bend towards the positive electrode.

Since the cathode ray bends towards the electrodes, it implies that it has a charge and the electrodes present help us determine the charge of the beam of charged particles and thus examine the beam of charged particles.

So, one of the main uses of this device is to examine a beam of charged particles.

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Answer:

B

Explanation:

5789.8 W  is the average power of the elevator motor during this period and 1.115 * 10⁴ W this power compare with the motor power when the elevator moves at its cruising speed.

The rate with which the speed and direction of a moving object vary over time. A point a object going straight ahead is pushed when it accelerates or decelerates.

Mass of elevator = 650 kg

Time = 4.50 sec

Speed of the elevator = 1.75 m/s

Calculating the elevator's acceleration is necessary.

Using the acceleration formula

a = vf - vi / t

a = 1.75 / 4.50

a = 0.38 m/s2

(a). We must determine the net force acting on the elevator.

Using the force formula

T = mg + ma

T = m (g +a)

T = 650 (9.8 + 0.38)

T = 6617 N

We must determine the average velocity.

Using the average velocity formula

v' = vf + vi / 2

v' = 1.75 / 2

v' = 0.875 m/s

We must determine the average power.

Using the power formula

P = T * v'

P = 6617 * 0.875

P = 5789.8 W

(b). We must determine the motor's power input.

Using the power formula

P = F * v

P = mg * v

P = 650 * 9.8 * 1.75

P = 1.115 * 10⁴ W.

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Answer: A. If the surface aquifer has a high water table

Explanation:

The water table refers to the water level underground. If it is high, it means that the water underground is close to the surface such that if a well was dug, it would not need to be dug too far for water to be seen.

When heavy rain falls, flooding is avoided if the water is either able to run off efficiently or if the ground is able to absorb the water. When the water table is high, it means that the ground will not be able to absorb much because the water is already close to the surface which means that should heavy rain fall, there will most likely be a flood.

Let H and D denote the height and diameter, respectively, of cylinder P, and h and d the height and diameter of cylinder Q.

Then the volumes of P and D, denoted V and v, respectively, are

V = π (D / 2)² H = π D ² H / 4

v = π (d / 2)² h = π d ² h / 4

The height of P is twice the height of Q, so H = 2h.

The diameter of P is half the diameter of Q, so D = d / 2.

Substitute these into equation for the volume of cylinder P:

V = π (d / 2)² (2h) / 4

V = π (d ² / 4) (2h) / 4

V = π d ² h / 8

V = 1/2 • π d ² h / 4

V = v / 2

That is, cylinder P has half the volume of cylinder Q.

Recall that density is equal to mass per unit of volume. So R and ρ, the respective densities of cylinders P and Q, are

R = m / V = m / (v / 2) = 2 m / v

ρ = m / v

which means cylinder P has twice the density of cylinder Q (assuming both cylinders have the same mass m).

Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )

Answer:

15

Explanation:

1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.

We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.

The heat lost by the metal is given by

Q1 = m1c1ΔT1

Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.

The heat gained by the ice is given by

Q2 = m2c2ΔT2

Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.

Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2

m1c1ΔT1 = m2c2ΔT2

Solving for c1, we get

c1 = m2c2ΔT2 / (m1ΔT1)

By putting these values we get

c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]

c1 = 0.902 kJ/kg·K

Hence, the specific heat of the metal is 0.902 kJ/kg·K.

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Answer:

To convert nanometers (nm) to picometers (pm), you need to multiply the value by 1,000. Therefore, to convert 12 nanometers to picometers, you would perform the following calculation:

12 nm * 1,000 pm/nm = 12,000 pm

So, 12 nanometers is equal to 12,000 picometers.

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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Answer:

my assuytyyhyyyyyy gftdrrdtiifyb tvhyvth rv b yy

The study of excitons and biexcitons in semiconductor quantum dots is a fascinating and rapidly evolving field in semiconductor physics. Excitons are bound states of an electron and a hole created by the absorption of a photon in a semiconductor material. These quasi-particles exhibit unique optical and electronic properties, making them important for various applications such as optoelectronic devices and quantum information processing.

1. Introduction:

  - Provide an overview of excitons and biexcitons in semiconductor quantum dots.

  - Mention their significance in semiconductor physics and applications.

2. Excitons:

  - Define excitons as bound electron-hole pairs.

  - Explain how they form through photon absorption.

  - Discuss their properties, such as energy levels, binding energies, and radiative lifetimes.

  - Describe their behavior under external electric and magnetic fields.

3. Semiconductor Quantum Dots:

  - Introduce semiconductor quantum dots as nanoscale structures with unique quantum confinement effects.

  - Explain the synthesis methods for quantum dots, such as colloidal synthesis or epitaxial growth.

  - Discuss their size-dependent electronic and optical properties.

4. Biexcitons:

  - Define biexcitons as two excitons bound together.

  - Explain the conditions for biexciton formation.

  - Discuss their properties, including binding energies, lifetimes, and interaction with external fields.

5. Experimental Techniques:

  - Describe the experimental methods used to study excitons and biexcitons in semiconductor quantum dots, such as photoluminescence spectroscopy or ultrafast spectroscopy.

  - Highlight the importance of time-resolved techniques for understanding exciton dynamics.

6. Applications:

  - Discuss the applications of excitons and biexcitons in semiconductor quantum dots, such as in optoelectronic devices (e.g., solar cells, light-emitting diodes) and quantum information processing (e.g., quantum dots as qubits).

7. Current Research and Future Directions:

  - Provide an overview of recent advancements in the field.

  - Mention ongoing research efforts and emerging areas of interest.

  - Discuss potential future directions and challenges in the study of excitons and biexcitons in semiconductor quantum dots.

8. Conclusion:

  - Summarize the key points discussed in the project.

  - Emphasize the significance of excitons and biexcitons in semiconductor quantum dots for fundamental research and technological applications.

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Answer:

1.3

Explanation:

it will taken to as in from of standard form

Answer:

1.3 * 10^-5

Explanation:

We are learning about scientific notation.

When a number becomes a decimal followed before with zeroes, we know that the value of that number is decreasing. So instead of usually doing a positive exponent, we will do a negative exponent indicating we are going back.

So let's not only count the amount of zeroes followed before 13, but the decimal.

0.000013

The original number "1.3" went back 5 spaces, therefore making our exponent 5.

1.3 * 10^-5

Answer:

its food this was easy

Answer: It takes 12 N of force to pull the wagon.

Explanation: