Please sketch the high-frequency small-signal equivalent circuit of a MOS
transistor. Assume that the body terminal is connected to the source. Identify (name) each parameter
of the equivalent circuit. Also, write an expression for the small-signal gain vds/vgs(s) in terms of the
small-signal parameters and the high-frequency cutoff frequency H. Clearly define H in terms of
the resistance and capacitance parameters.
Type or paste question here

Answer:

agriculture,defense,industry,science

Explanation:

Edg 2021

The vectors are magnitude of vector v is 5. The sum of vectors v1 and v2 is (+) = (2, 1, 8).  The difference between vectors v1 and v2 is (-) = (6, -1, -2). The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).

To find the magnitude (||) of a vector, we can use the formula:

||v|| = sqrt(v1^2 + v2^2 + v3^2)

Given vector v = (4, 0, 3), we can calculate its magnitude as follows:

||v|| = sqrt(4^2 + 0^2 + 3^2)

     = sqrt(16 + 0 + 9)

     = sqrt(25)

     = 5

Therefore, the magnitude of vector v is 5.

Now, let's find the sum (+) and difference (-) of the given vectors.

Given vectors v1 = (4, 0, 3) and v2 = (-2, 1, 5), the sum of these vectors is calculated by adding the corresponding components:

v1 + v2 = (4 + (-2), 0 + 1, 3 + 5)

       = (2, 1, 8)

The difference between the vectors is found by subtracting the corresponding components:

v1 - v2 = (4 - (-2), 0 - 1, 3 - 5)

       = (6, -1, -2)

Lastly, let's calculate the scalar multiple of vector v1:

3v1 = 3(4, 0, 3)

   = (12, 0, 9)

Therefore, the vectors are as follows:

- The magnitude of vector v is 5.

- The sum of vectors v1 and v2 is (+) = (2, 1, 8).

- The difference between vectors v1 and v2 is (-) = (6, -1, -2).

- The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).

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Answer:

Diameter of pipe is 0.535 ft

Explanation:

see attachment, its works out 1st half

The risk assessment plan is given below as follows:

Risk Assessment Plan:

Identify Hazards:

Examining the geography of the site, one will be able to trace any impending physical dangers (e.g. unstable ground, unhidden electrical wiring). Additionally, reviewing the trade-work carried out and its particular risks by those conducting it (e.g. lofty movements, handling of power machines) as well as potential personal hazards related to the plant itself (e.g. inflammable elements, likelihood of explosions) should take place.

Evaluate the Risks:

To deduce the outliers of each uncovered threat (e.g. minor scratching, death) is necessary in order to measure the potency of occurrence (e.g. consistent, irregular, infrequent) for better understanding of the impact it can possibly cause (e.g. money due, legal effects, credibility damage). After taking these into consideration, assign a risk level based on them.

Control and Mitigation Measures:

Designing an agenda that seeks to eradicate or debilitate the detected hazards via putting into action engineering controls (e.g. support rails, anchorage vestments) as well as administrative prerequisites (e.g training agendas, warning signs), not forgetting to grant security equipment (PPE) wherever needed.

Action Plan:

A structured report must be written to make official knowledge of the assessment and control operations gone through. Furthermore, this document must be updated when fresh perils are noticed or at regular times, making sure that all personnel and contractors participating have knowledge about said hazards and safety methods applied along with being tutored on the correct use of said mechanisms.

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Answer:

depend what cereal yeha

Explanation:

no explanation

Both are true. Tech A claims that a vacuum gauge can be used to locate tiny vacuum leaks. According to tech B, the catalytic converter is usually placed behind the muffler.

Tailpipe. The catalytic converter has cleaned up the exhaust gases, which are then sent out of the car and into the atmosphere via the tailpipe, the last link in the exhaust system.

Hazardous pollutants from engine exhaust are decreased by the catalytic converter. The converter, which is situated between the exhaust manifold and the muffler, works with heat and metals that serve as catalysts.

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Answer:

See Explanation

Explanation:

The question has missing details;however, I'm able to pick the following points from the question

Having said that, the question can be solved in two ways.

I'll answer this question using the first method and the solution is as follows (See Comments for line by line explanation):

#This line prompt user for number of countries

n = int(input("Number of countries: "))

#This initializes an empty list for loan amounts

loan_amounts = []

#This initializes an empty list for country

country = []

#The following iteration gets names of countries and their respective loan amounts

for i in range(0,n):

    country_name = input("Name of country: ")

    loan = int(input("Loan Amount: "))

    country.append(country_name)

    loan_amounts.append(loan)

#This gets the maximum loan

max_loan = max(loan_amounts)

#This gets the index of the maximum loan

iindex = loan_amounts.index(max_loan)

#This gets the country with the maximum loan

max_country = country[iindex]

#This gets the minimum loan

min_loan = min(loan_amounts)

#This gets the index of the minimum loan

iindex = loan_amounts.index(min_loan)

#This gets the country with the minimum loan

min_country = country[iindex]

#This prints the country with the maximum loan and the loan amount

print(str(max_country)+": "+str(max_loan))

#This prints the country with the minimum loan and the loan amount

print(str(min_country)+": "+str(min_loan))

Answer:

Gauge Pressure = 408.3 KPa

Explanation:

The pressure inside the pipe can be given in terms of the elevation, by the following formula:

P = ρgΔz

where,

P = Absolute Pressure = ?

ρ = Density of Water = 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

Δz = elevation = 52 m

Therefore,

P = (1000 kg/m³)(9.8 m/s²)(52 m)

P = 509.6 KPa

Now, for gauge pressure:

Gauge Pressure = P - Atmospheric Pressure

Gauge Pressure = 509.6 KPa - 101.3 KPa

Gauge Pressure = 408.3 KPa

In summary, the XYZ Company will require:

(a) 705 processing and assembly operations,

(b) 710 workers (direct labor only), and

(c) 25,738 m2 of total floor space for the new plant.

To calculate the required processing and assembly operations, workers, and total floor space for the new factory, we can break down the problem into smaller parts and analyze each element.

(a) Processing and assembly operations:

Number of components made in the factory: 250 components * 35% = 87.5 (round up to 88 components)

Processing operations for components: 88 components * 8 processing operations = 704 processing operations

Assembly operations for final product: 1 assembly operation (as each product is assembled in one workstation)

Total operations = 704 processing operations + 1 assembly operation = 705 operations

(b) Number of workers (direct labor only):

Processing workers: 704 processing operations / 1 (one worker per work cell) = 704 workers

Assembly workers: 13 models * 1000 units/model = 13,000 units/year

Assembly time per unit: 48 min/unit = 0.8 hr/unit

Assembly time for all products: 13,000 units * 0.8 hr/unit = 10,400 hr

Assembly workers required: 10,400 hr / 2,000 hr/shift = 5.2 (round up to 6 workers)

Total workers = 704 processing workers + 6 assembly workers = 710 workers

(c) Total floor space required:

Processing floor space: 704 work cells * 25 m2/cell = 17,600 m2

Assembly floor space: 6 workstations * 25 m2/station = 150 m2

Total production area: 17,600 m2 + 150 m2 = 17,750 m2

Additional allowance (45%): 17,750 m2 * 45% = 7,987.5 m2

Total floor space = 17,750 m2 + 7,987.5 m2 = 25,737.5 m2 (round to 25,738 m2)

In summary, the XYZ Company will require:

(a) 705 processing and assembly operations,

(b) 710 workers (direct labor only), and

(c) 25,738 m2 of total floor space for the new plant.

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Answer:

41.015

Explanation:

Solution

Given that:

Th first step to take is to find  the longitudinal stress in the cylinder

σl = PD/4t

P = the pressure

D = the diameter

t = the thickness

Thus,

σl = 1.25 * ^ 6 * 0.45 / 4 * 6 * 10 ^ ⁻3

=23.475Mpa

Now. we find the hoop stress in the cylinder∠

σh = PD/2t

σh = 1.25 * ^ 6 * 0.45/ 2 * 6 * 10 ^ ⁻3

σh  =46.875 Mpa

Then

we find the normal stress in the line of the 30° angle with the longitudinal axis stated below:

σab = σh + σl/2 + ( σh - σl/2) cos 2θ + t sin 2θ

So,

σab  =46.875 + 23.4375/2 + ( 46.875 - 23.4375/2) cos 2(30°) + 0

σab= 41.015

Therefore the normal stress to line A-B is 41.015

When the correct satellite position is not being sent, the error that is encountered is known as a positioning error. This type of error can occur in GPS (Global Positioning System) technology when the GPS receiver fails to receive accurate information from the satellites it is communicating with.

GPS technology relies on a network of satellites orbiting the earth that transmit signals to GPS receivers on the ground. These signals contain information about the satellite's position, time, and other data that is used to calculate the receiver's position on earth. However, if the GPS receiver is unable to receive accurate information from the satellites due to various factors such as signal blockage or interference, it may lead to a positioning error.

Inaccurate or outdated information about the satellite's position can also cause positioning errors. This can occur when the satellite's orbit changes or when the satellite is replaced by a newer one with different characteristics. In some cases, errors can also occur due to technical issues such as receiver malfunction or software glitches.

Overall, positioning errors can have a significant impact on the accuracy of GPS data and can cause issues in applications that rely on precise location information such as navigation, surveying, and mapping. To mitigate these errors, GPS technology continues to evolve and improve with advancements in satellite and receiver technology, as well as more advanced algorithms and software.

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Answer:

the correct answer is not in the options

the answer is supposed to be 10m/s² from the formula F=ma

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:people tend to do this when they are in a different environment they lose something or just have something going on in their life

Explanation:

The inner surface temperature of the window is equal to -5 + 0.5417/A.

Temperature is a measure of the average kinetic energy of all the atoms and molecules in a system. It is a physical property of matter that can be observed and measured. Temperature can be measured in various ways, from the feeling of hot or cold on the skin to more precise scientific instruments. Heat is a form of energy and temperature is a measure of this energy.

The inner surface temperature of the window can be calculated using the equation:

Q = kA(T1-T2)/L

Where Q is the heat flux, k is the thermal conductivity, A is the area of the window, T1 is the inner surface temperature, T2 is the outer surface temperature, and L is the thickness of the window.

Rearranging the equation gives us:

T1 = T2 + (QL)/(kA)

Substituting the given values, we get:

T1 = -5 + (1300*0.005)/(1.2*A)

T1 = -5 + 0.5417/A

Therefore, the inner surface temperature of the window is equal to -5 + 0.5417/A.

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The rate of power input for this refrigerator is 3.33 kW.

A refrigerator with a COP (Coefficient of Performance) of 3.0 is designed to remove heat from the refrigerated space efficiently. The COP is the ratio of the amount of heat removed from the refrigerated space to the work (power input) done by the refrigerator.

In this case, the heat removal rate is given as 10 kW. To determine the rate of power input, we can use the following formula:

COP = (Heat removal rate) / (Power input)

Rearranging the formula to solve for the power input:

Power input = (Heat removal rate) / COP

By substituting the given values:

Power input = (10 kW) / (3.0)

Power input = 3.33 kW (approx.)

So, the rate of power input for this refrigerator is approximately 3.33 kW. This means that for every 3.33 kW of electrical power supplied to the refrigerator, it is able to remove 10 kW of heat from the refrigerated space. A higher COP indicates a more energy-efficient refrigerator.

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Carbon monoxide and oxygen-Incomplete combustion occurs in a coal-fired unit's furnace when insufficient oxygen (O2) is available during fuel combustion.

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Two different kinds of losses can happen in a three-phase induction motor. These losses are variable losses that are constant or fixed losses. Fixed or Constant Losses Consta.

Stator losses, including as stator iron loss and stator copper loss, are financed in part by this power input. Rotor input is provided with the leftover power, or (input electrical power - stator losses). Thus, rotor input P2 equals Pin minus stator losses (stator copper loss and stator iron loss).

Fixed losses, Copper losses, and stray losses are a few types of losses that can occur in three-phase induction motors. Core losses, bearing friction losses, brush friction losses (in wound rotor motors), and windage losses make up the majority of these losses.

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Answer:

Engine oil level.

Brake fluid.

Power steering fluid.

A network bridge is used to segment network traffic for the purpose of reducing bottlenecks. This type of bridge is commonly used in local area networks (LANs) to connect two or more segments of the network together.

By dividing the network into smaller segments, network traffic is reduced and the overall network performance is improved. Network bridges operate at the data link layer of the OSI model and are responsible for forwarding data packets between different segments of the network. They also help to filter out unnecessary network traffic and prevent it from congesting the network. Additionally, network bridges can help to improve network security by separating different network segments and preventing unauthorized access to certain parts of the network. Overall, network bridges are an important tool for network administrators to improve network performance and efficiency, while also enhancing network security.

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Answer:

B) sending end voltage : Vs-l-l = 345.8 ∠ 26.14⁰ kv

    sending end current : Is = 1.241 ∠ 15.5⁰ KA

    real power = 730.5 Mw

C) percent voltage regulation = 8.7%

D) Transmission line efficiency  = 95.8%

Explanation:

attached is the detailed solution to the problem

Given data:

l = 200 km

z = 0.032 + j0.35 Ω/km

y = j4.2 * 10^-6 S/km

A) find the total series impedance and shunt  admittance

B) sending end voltage : Vs-l-l = 345.8 ∠ 26.14⁰ kv

    sending end current : Is = 1.241 ∠ 15.5⁰ KA

    real power = 730.5 Mw

C) percent voltage regulation = 8.7%

D) Transmission line efficiency  = 95.8%

Answer:

Answer to the following is as follows;

Explanation:

A request for proposal is a documentation that invites prospective contractors to submit business opportunities to an agency or corporation interested in procuring a commodities, product, or valuable resource through a bid procedure.

A request for proposal (RFP) is a commercial document that introduces a project, defines it, and invites eligible contractors to compete on its completion.

Answer:

Option 1

Explanation:

As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :

Answer:

The first option

Explanation:

Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.

Incomplete question. The options read;

A. Tech A

B. Tech B

C. Both A and B

D. Neither A nor B.

Answer:

C. Both A and B

Explanation:

Technician B is correct because the technician highlighted valid reasons why draining the compressed air systems is important.

For example, since this system helps to absorb moisture or oil from storage areas they thus need to be drained periodically in other to allow for more absorption space.

Also, the reasons mentioned by Technician A are of course correct because it is generally believed that the application of lubricants such as oil helps to reduce wear and tear.

a. To find out the fundamental frequency and fundamental period of x[n] with T = 2.5 T0, here’s what we do:Given that the fundamental period of x(t) is T0 = 2π/ω0and the sampling period T = 2.5T0; then the fundamental frequency of x[n] will be: ω0' = ω0/T0'ω0' = ω0/ (2.5T0)ω0' = (1/2.5) ω0ω0' = (2/5)ω0and, the fundamental period of x[n] will be: T0' = T/1T0' = (2.5T0)/1T0' = 2.5 T0.

b. To find out if x[n] is periodic when T = 2T0; we compare the sampling period T with the fundamental period of x(t) (i.e. T0). We have:T = 2T0Since the sampling period T is a multiple of the fundamental period T0, the samples are NOT affected by any aliasing and hence x[n] is periodic.

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Answer: A. High

Explanation:

In order to have an obstructed view from your seat, you should always adjust your seat as high as possible, while staying comfortable.

Answer:

A

Explanation:

I put high and got it right.

Answer:

4.75m^2

Explanation:

Given:-

- Temperature of hot fluid at inlet:  \(T_h_i = 300\) °C

- Temperature of cold fluid at outlet: \(T_c_o = 120\) °C

- Temperature of cold fluid at inlet: \(T_c_i = 35\) °C

- The overall heat transfer coefficient: U = 1500 W / m^2 K

- The flow rate of cold fluid: m_c = 10,00 kg/ h

- The flow rate of hot fluid: m_h = 5,000 kg/h

Solution:-

- We will evaluate water properties at median temperatures of each fluid using table A-4.

Cold fluid:   Tci = 35°C , Tco = 35°C

                            Tcm = 77.5 °C ≈ 350 K  --- > \(C_p_c = 4195 \frac{J}{kg.K}\)

 Hot fluid:     Thi = 300°C , Tho = 150°C ( assumed )

                             Thm = 225 °C ≈ 500 K --- > \(C_p_h = 4660 \frac{J}{kg.K}\)

- We will use logarithmic - mean temperature rate equation as follows:

                             \(A_s = \frac{q}{U*dT_l_m}\)

Where,

                 A_s : The surface area of heat exchange

                 ΔT_lm: the logarithmic differential mean temperature

                 q: The rate of heat transfer

- Apply the energy balance on cold fluid as follows:

                   \(q = m_c * C_p_c * ( T_c_o - T_c_i )\\\\q = \frac{10,000}{3600} * 4195 * ( 120 - 35 )\\\\q = 9.905*10^5 W\)

- Similarly, apply the heat balance on hot fluid and evaluate the outlet temperature ( Tho ) :

                   \(T_h_o = T_h_i - \frac{q}{m_h * C_p_h} \\\\T_h_o = 300 - \frac{9.905*10^5}{\frac{5000}{3600} * 4660} \\\\T_h_o = 147 C\)

- We will use the experimental results of counter flow ( unmixed - unmixed ) plotted as figure ( Fig . 11.11 ) of the " The fundamentals to heat transfer" and determine the value of ( P , R , F ).

- So the relations from the figure 11.11 are:

                  \(P = \frac{T_c_o - T_c_i}{T_h_i - T_c_i} \\\\P = \frac{120 - 35}{300 - 35} \\\\P = 0.32\)    

                 \(R = \frac{T_h_i - T_h_o}{T_c_o - T_c_i} \\\\R = \frac{300 - 147}{120 - 35} \\\\R = 1.8\)

Therefore,         P = 0.32 , R = 1.8 ---- > F ≈ 0.97

- The log-mean temperature ( ΔT_lm - cf ) for counter-flow heat exchange can be determined from the relation:

                        \(dT_l_m = \frac{( T_h_i - T_c_o ) - ( T_h_o - T_c_i ) }{Ln ( \frac{( T_h_i - T_c_o )}{( T_h_o - T_c_i )} ) } \\\\dT_l_m = \frac{( 300 - 120 ) - ( 147 - 35 ) }{Ln ( \frac{( 300-120 )}{( 147-35)} ) } \\\\dT_l_m = 143.3 K\)

- The log - mean differential temperature for counter flow is multiplied by the factor of ( F ) to get the standardized value of log - mean differential temperature:

                       \(dT_l = F*dT_l_m = 0.97*143.3 = 139 K\)

- The required heat exchange area ( A_s ) can now be calculated:

                     \(A_s = \frac{9.905*10^5 }{1500*139} \\\\A_s = 4.75 m^2\)