please please help me with this question, this is the third time i’ve asked this question and no one has answered :(

Mean: to find the mean you add all the data and then divide into the number of data.

number of data: 8

Median: to find the meadian order the data from least to greather and then select the middle data (as the total of data is 8 you select the two data in the middle and calculate the average)

Data ordered:

Middle data: 11 and 11:

Mode: To find the mode you look for the data that repeat the most.

Range: To find the range of a data set you substract from the greatest value the least value:

Greatest value: 17

Least value: 6

The quota sampling produces the same advantages for convenience sampling that stratified random sampling produces for probability sampling.

Sampling:

Sampling is defined as the process in statistical analysis where researchers take a predetermined number of observations from a larger population.

Given,

Here we need to find the type of sampling that produces the same advantages for convenience sampling quota sampling.

Before, move on to the result, first we have to know the details about quota sampling and the probability sampling.

Probability sampling defined as the selection of a sample from a determined number of population, when this selection is based on the principle of randomization, that is, random selection or chance.

In contrast to probability sampling, Quota sampling means a non-probability sampling method in which researchers create a sample involving individuals that represent a population.

Based on these definition we have identified that the method that is best suitable answer for this one is stratified random sampling.

Because the stratified random sampling means, is a probability sampling technique in which the total population is divided into homogenous groups to complete the sampling process.

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Explanation:

We start with one block at the very left side. This is algebraically written as \(a_1 = 1\). The small subscript '1' means we're dealing with the first term, and that is set equal to 1. In other words, the first term is 1.

The second term is three since we have three blocks as the next figure down the line. So \(a_2 = 3\). We can then see that \(a_3 = 6\) and \(a_4 = 10\)

The sequence of the first four terms are: 1, 3, 6, 10.

The notation \(a_n = a_{n-1} + n\) tells us "to get the nth term \(a_n\), we add the previous term (\(a_{n-1}\)) to the value of n".

For example, if we wanted the third term, we would add the second term a2 onto the value of n = 2. In order to know a2, we need the diagram or you would have to use the recursive formula to find it.

Furthermore, it means that to find the fifth term \(a_5\), we do the following

\(a_n = a_{n-1} + n\\\\a_5 = a_{5-1} + 5\\\\a_5 = a_{4} + 5\\\\a_5 = 10+5\\\\a_5 = 15\)

The fifth figure will have 15 small little blocks to it. You can draw this out by copying the fourth figure, and then adding 5 smaller blocks to the very bottom portion. The sixth figure is basically a copy of the fifth one, but we have six little blocks along the bottom. This is the "plus n" being applied in the recursive formula.

So the 6th figure will have 15+6 = 21 blocks in total while the 7th figure has 21+7 = 28 blocks. This points us to choice (3).

Side note: These are known as triangular numbers. Note how the gaps between consecutive values of 1,3,6,10,15,21,28 is +2,+3,+4,+5,+6,+7.

Answer:

Sam made a mistake. The answer should have been 30.

This is what Sam should have done:

2n^2 - 20

2n^2 - 20 = 2(5)^2 - 20

= 2(25) - 20

= 50 - 20

= 30

Sam multiplied 2 and 5 when he should have done the power first.

Answer:

d=24

Step-by-step explanation:

Answer:

answer below

Step-by-step explanation:

a) will be all of them

b)will be all of their unions, so the values they all have in common in this case 4, 6

c)will be the values in common with a and b and all of c,

d)will be all of the values of a and b and all of the values in common with c

sorry I csnnot give an actual answer at the moment, but i can explain what each question wants from you in literal word form.

The formula a(7) * 1.01 represents an exponential growth model, where a(7) is the area covered by mold at week 7, and 1.01 represents a growth rate of 1% per week.

The exponential growth model is represented by the formula a(7) * 1.01, where a(7) is the area covered by mould at week 7, and 1.01 indicates a weekly growth rate of 1%.

By multiplying the area at week 7 by 1.01, we can approximate the area covered by mold at week 8.

However, it's important to note that this model assumes that the growth rate remains constant and does not account for any limiting factors such as availability of food or changes in environmental conditions.

Additionally, this model may not accurately represent the actual growth of mold, as mold growth can be complex and affected by many variables.

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One fourth of the values are less than or equal to 4.2, and three fourths are above 4.2.

The second quartile of a dataset, also known as the median, is a measure of central tendency that divides the dataset into two equal halves. It is the value that separates the lower 50% of the data from the upper 50% of the data.

The correct answer is C. One fourth of the values are less than or equal to 4.2, and three fourths are above 4.2.

The second quartile, also known as the median, is the value that separates the lower 50% of the data from the upper 50% of the data. So, if the second quartile of a data set is 4.2, it means that 50% of the values in the data set are below 4.2, and 50% of the values are above 4.2.

Since the first quartile is the value that separates the lower 25% of the data from the upper 75% of the data, we know that one fourth of the values must be less than or equal to the second quartile (4.2). Similarly, since the third quartile is the value that separates the lower 75% of the data from the upper 25% of the data, we know that three fourths of the values must be above the second quartile (4.2).

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The second quartile of a data set is 4.2. Which statement about the data values is true?

A. The data value 2.5 will lie below the second quartile.

B. The data value 4.7 will lie below the second quartile.

C. One fourth of the values are less than or equal to 4.2, and three fourths are above 4.2.

D. One fourth of the values are less than or equal to 4.2, and half of the values are above 4.2.

E. One fourth of the values are above 4.2, and half of the values are less than or equal to 4.2.

Answer:

f=-27, hope this helped my love have a good rest of your day ^^

Step-by-step explanation:

subtract 24 from both sides

the you get f=-27

Three techniques for efficient multiplication and division at a low level include the Karatsuba algorithm, the Schönhage-Strassen algorithm, and the Toom-Cook algorithm.

The Karatsuba algorithm is a divide-and-conquer technique that reduces the number of multiplication operations required by recursively breaking down the operands into smaller parts. It has a time complexity of O(n^log2(3)), which is an improvement over the traditional O(n^2) complexity. However, it requires additional memory to store intermediate results.

The Schönhage-Strassen algorithm is based on the Fast Fourier Transform (FFT) and uses number theoretic techniques. It has a time complexity of O(n log n log log n) and is particularly efficient for large numbers. However, it requires complex arithmetic operations and is more suitable for specialized applications.

The Toom-Cook algorithm is an extension of the Karatsuba algorithm and allows for even larger operands. It breaks down the operands into multiple parts and performs intermediate computations using polynomial interpolation. It has a time complexity of O(n^log2(5)) and strikes a balance between the Karatsuba and Schönhage-Strassen algorithms.

In conclusion, these three techniques provide efficient alternatives to traditional multiplication and division methods. The Karatsuba algorithm is suitable for general-purpose applications, while the Schönhage-Strassen algorithm is more specialized for large numbers. The Toom-Cook algorithm offers a balance between efficiency and applicability to a wider range of operand sizes.

Understanding the advantages and disadvantages of each technique allows for selecting the most appropriate approach based on specific requirements and constraints. The article "Faster Integer Multiplication" by Furer provides further insights into a fast integer multiplication technique, likely discussing one or more of these algorithms in detail and presenting additional optimizations.

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Answer:

Step-by-step explanation:

\(8c-4-2c+5\\\\\mathrm{Group\:like\:terms}\\=8c-2c-4+5\\\\\mathrm{Add\:similar\:elements:}\:8c-2c=6c\\=6c-4+5\\\\\mathrm{Add/Subtract\:the\:numbers:}\:-4+5=1\\=6c+1\)

Answer:

4th is the answer

Step-by-step explanation:

Answer:

the measure of <ABD = 1/2 the measure of <ABC is the answer :)

Step-by-step explanation:

The probability that a randomly selected Christian living in the United States would identify as Catholic can be calculated by dividing the number of Catholics in the US by the total number of Christians in the US.

To do this calculation, we need to know the accurate data on the number of Catholics and the total number of Christians in the US. Let's assume that there are X Catholics and Y total Christians in the US.

The probability of a randomly selected Christian being Catholic would be:

P(Catholic) = X/Y

Without the accurate data on the number of Catholics and total Christians in the US, it is not possible to calculate the exact probability. However, if we assume that the data provided is accurate and stable, we can use the formula above to calculate the probability.

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Answer:

The largest interger that satisfies the equation is 3

Step-by-step explanation:

If we subtract 10 from each side, we get 7x<=21

Then, we divide 7 on each side to get x<=3.

So the largest interger to satisfy the equation is 3

(Btw, <= means less than or equal to)

Hope this helped you, and have a great day!

Answer:

x<=3

Step-by-step explanation:

minus 10 fom both sides

7x + 10-10<=31-10

restate as

7x<=21

divid both side by same factor

7x/7 and 21/7

restate as

x<=3

When arranging indistinguishable objects in such a way that no two objects are in the same row or column, the number of possible arrangements depends on the dimensions of the grid.

The number of ways to arrange indistinguishable objects without any repetitions in a grid, such that no two objects are in the same row or column, depends on the dimensions of the grid. Let's assume the grid has M rows and N columns. In this case, the number of possible arrangements can be determined using combinatorics.

To find the total number of arrangements, we start with the first column. There are M choices for the first object in this column. Moving to the second column, there are M-1 choices since we need to avoid repetition within the same row. Continuing this process, the number of choices decreases by 1 for each subsequent column.

Therefore, the total number of arrangements can be calculated as M x (M-1) x (M-2) x ... x (M-N+1), where N is the number of columns. This can be further simplified as M! / (M-N)!, where "!" represents the factorial operation.

In conclusion, when arranging indistinguishable objects in a grid such that no two objects are in the same row or column, the number of possible arrangements depends on the dimensions of the grid. By applying combinatorial principles, the total number of arrangements can be calculated using the formula M! / (M-N)!.

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Answer:

Both 16 and 1 are squares. This suggests using the formula for the difference of squares. Answer link.

Step-by-step explanation:

Every time you have a difference in the format of

A2−B2 you can factor as (A−B)(A+B).

Then you have to identify if your quantity is the difference of two squared quantities.

It is. In fact we can write it as:

16x2−1=(4x)2−12

Then we can apply our rule

\( {(4x)}^{2} - {1}^{2} = (4x - 1)(4x + 1)\)

Answer:

Step-by-step explanation:

the degree of 8^8t

16777216t : the degree of the mnonmial is 1, because the degree of the variable is 1

The total gross earnings are given as follows:

$360.

The total gross earnings are obtained applying the proportions in the context of this problem, first obtaining the total number of hours and then multiplying by the rate.

The hours are given as follows:

After November 14, the hours are given as follows:

Hence the total number of hours is obtained as follows:

3.5 + 2 + 3.5 + 4 + 5 + 5.5 + 4.5 + 4 = 32 hours.

The rate is of $11.25 per hour, hence the total earnings are given as follows:

11.25 x 32 = $360.

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The unit price per folder of 1 box at the regular price is $0.2996. The unit price on the special offer is $0.2397. The special offer is the better buy since it offers a lower unit price per folder.

To calculate the unit price per folder of 1 box at the regular price, we divide the regular price ($7.49) by the total number of folders in a box (25). The unit price per folder at the regular price is $0.2996.

For the special offer of buy one get one free, we consider that for every box purchased, an additional box is received for free. Therefore, the total cost is still $7.49, but the total number of folders is doubled to 50. Dividing the total cost by the total number of folders, we find that the unit price per folder on the special offer is $0.2397.

Comparing the two unit prices, we see that the unit price on the special offer is lower than the unit price at the regular price. Therefore, the special offer is the better buy since it provides a lower unit price per folder.


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The probability that the dog is still lost at the end of the second day is 0.41

To solve this problem, we can use Bayes' theorem, which allows us to update the probability of an event based on new information.

Let A be the event that the dog is in forest A, and B be the event that the dog is in forest B. Let F be the event that the dog is found within two days.

We want to calculate P(F'), the probability that the dog is still lost at the end of the second day. We can use the law of total probability to express this as

P(F') = P(F'|A) × P(A) + P(F'|B) × P(B)

where P(F'|A) is the probability of not finding the dog within two days given that the dog is in forest A, P(F'|B) is the probability of not finding the dog within two days given that the dog is in forest B, and P(A) and P(B) are the prior probabilities of the dog being in forest A and forest B, respectively.

Using the information given in the problem, we can calculate

P(F'|A) = 1 - 0.5 = 0.5 (the probability of not finding the dog in forest A within two days is 1 - 0.5 = 0.5)

P(F'|B) = 1 - 0.8 = 0.2 (the probability of not finding the dog in forest B within two days is 1 - 0.8 = 0.2)

P(A) = 0.7 (the prior probability of the dog being in forest A)

P(B) = 0.3 (the prior probability of the dog being in forest B)

Plugging these values into the formula above, we get

P(F') = 0.5 × 0.7 + 0.2 × 0.3 = 0.41

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The given question is incomplete, the complete question is:

Oscar has lost his dog; there is a 70% probability it is in forest A and a 30% chance it is forest B. If the dog is in forest A and Oscar looks there for a day, he has a 50% change of finding the dog. If the dog is in forest B and Oscar looks there for a day, he has an 80% chance of finding the dog. what is the probability that the dog is still lost at the end of the second day?

Answer:

Some states consider some income to be tax free. this statement is false

it would probably go with one of the first 2. they sound opposite of each other. probably go with the first 1?

sorry if I'm wrong

The mean of the number of drivers expected not to be wearing seatbelts is approximately 4.35, the variance is approximately 15.62, and the standard deviation is approximately 3.95 and they expect to stop approximately 4.35 cars before finding a driver whose seatbelt is not buckled.

a. To find the mean, variance, and standard deviation of the number of drivers expected not to be wearing seatbelts, we can model the situation using a geometric distribution.

Let's define a random variable X that represents the number of cars stopped until the first driver without a seatbelt is found. The probability of a driver not wearing a seatbelt is given as p = 0.23.

The mean (μ) of a geometric distribution is given by μ = 1/p.
μ = 1/0.23 ≈ 4.35

The variance (σ^2) of a geometric distribution is given by σ^2 = q/p^2, where q = 1 - p.
σ^2 = (0.77)/(0.23^2) ≈ 15.62

The standard deviation (σ) is the square root of the variance.
σ = √(15.62) ≈ 3.95


b. The expected number of cars they expect to stop before finding a driver whose seatbelt is not buckled is equal to the reciprocal of the probability of success (finding a driver without a seatbelt) in one trial. In this case, the probability of success is p = 0.23.

Expected number of cars = 1/p = 1/0.23 ≈ 4.35

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The correct answers are His sample was not drawn at random ,he ought to purchase more fat-free donuts, he may look at the data's histogram to see whether it is roughly typical.

Given that, Bjorn is attempting to calculate the difference between the average sugar level of two distinct kinds of donuts: a fat-free kind and a full-fat variety.

He gathers 60 donuts to test in order to do this: There are 22 fat-free donuts and 38 full-fat donuts. The correct answers are A, D and E He did not get a random sample He should get more fat free donuts He could check the histogram of the data to see if it's approximately normal

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\(D = \frac{1}{2} dk\)

\(k = \frac{2D}{d} \)

After drawing an arc across AB by placing the tip of the compass on point A, Joaquin's next step in constructing the perpendicular bisector of line AB is to repeat the same process by placing the tip of the compass on point B and drawing an arc.

The intersection point would be the midpoint of line AB.Then, he can draw a straight line from the midpoint and perpendicular to AB. This line will divide the line AB into two equal halves and hence Joaquin will have successfully constructed the perpendicular bisector of line AB.

The perpendicular bisector of a line AB is a line segment that is perpendicular to AB, divides it into two equal parts, and passes through its midpoint.

The following are the steps to construct the perpendicular bisector of line AB:

Step 1: Draw line AB.

Step 2: Place the tip of the compass on point A and draw an arc across AB.

Step 3: Place the tip of the compass on point B and draw another arc across AB.

Step 4: Locate the intersection point of the two arcs, which is the midpoint of AB.

Step 5: Draw a straight line from the midpoint of AB and perpendicular to AB. This line will divide AB into two equal parts and hence the perpendicular bisector of line AB has been constructed.

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To show that exp(sqrt((ln x)(ln ln x))) is sub exponential, we need to prove that it grows slower than any exponential function.

Let's start by defining what sub exponential means. A function f(x) is sub exponential if and only if lim x→∞ f(x)/exp(εx) = 0 for all ε > 0.
Now let's apply this definition to exp(sqrt((ln x)(ln ln x))).
f(x) = exp(sqrt((ln x)(ln ln x)))
g(x) = exp(εx)
We want to show that lim x→∞ f(x)/g(x) = 0 for all ε > 0.
f(x)/g(x) = exp(sqrt((ln x)(ln ln x))) / exp(εx)
= exp(sqrt((ln x)(ln ln x)) - εx)
To simplify this expression, we can take the logarithm of both sides:
ln(f(x)/g(x)) = sqrt((ln x)(ln ln x)) - εx
Now we can use L'Hopital's rule to evaluate the limit:
lim x→∞ ln(f(x)/g(x))
= lim x→∞ (d/dx)[sqrt((ln x)(ln ln x)) - εx] / (d/dx)[exp(εx)]
= lim x→∞ (sqrt(ln ln x) / 2sqrt(ln x)) - ε) exp(εx)
= -ε
Therefore, lim x→∞ f(x)/g(x) = exp(-ε) > 0 for all ε > 0.

Since f(x) grows slower than any exponential function, we can conclude that exp(sqrt((ln x)(ln ln x))) is subexponential.
To show that exp(sqrt((ln x)(ln ln x))) is subexponential, we'll analyze its growth rate compared to a standard exponential function.
Step 1: Define the given function and a standard exponential function.
- Given function: f(x) = exp(sqrt((ln x)(ln ln x)))
- Standard exponential function: g(x) = exp(x)
Step 2: Compare their growth rates.
A function is subexponential if it grows slower than an exponential function.
Step 3: Take the limit of their ratio as x approaches infinity.
We'll examine the limit of f(x)/g(x) as x approaches infinity. If the limit is 0, then f(x) is subexponential.
Limit as x approaches infinity of [f(x)/g(x)]:
= Limit as x approaches infinity of [exp(sqrt((ln x)(ln ln x))) / exp(x)]
Step 4: Simplify the limit expression.
Using the properties of exponentials, we can rewrite the limit as:
Limit as x approaches infinity of exp(sqrt((ln x)(ln ln x)) - x)
Step 5: Evaluate the limit.
As x approaches infinity, ln x and ln ln x both approach infinity, but their product approaches infinity slower than x itself. Therefore, the expression (sqrt((ln x)(ln ln x)) - x) approaches negative infinity, and the limit becomes:
exp(-∞) = 0
Since the limit is 0, we can conclude that exp(sqrt((ln x)(ln ln x))) is subexponential.

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Answer: cot B

Step-by-step explanation: if i am right mark me as brainliest

Answer: 10.6 tenths divided by .04 hundredths

Step-by-step explanation: i cant expain it srry

Answer:

265

Step-by-step explanation:

because you devide and i used a calculator but most people use paper 10.6÷0.04 equals 265

The sampling technique used in this scenario is Random sampling

The correct answer is an option (a)

We know that the random sampling is nothing but a method of choosing a sample of observations from a population to make assumptions about the population. It is also called as a porbability sampling.

It  allows for the randomization of sample selection.

There are four random sampling methods –

simple random sampling,

systematic sampling,

stratified sampling,

and cluster sampling.

In random sampling, the randomized selection of a small segment of individuals or members from a whole population.

Here, the soda bottle company  have equipment that can pull every tenth bottle from the assembly line without causing a backup on the line.

Therefore,  the sampling technique used: Random

The correct answer is an option (a)

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The complete question is:

Select the sampling technique used:

A soda bottling company needs to test the quality of the bottles they produce. They have equipment that can pull every tenth bottle from the assembly line without causing a backup on the line.

a) Random

b) Stratified

c) Cluster

d) Systematic

e) Convenience

Answer:

the Answer is B 107⁰ its 180⁰-73⁰