Please I need help with this asap!!! I will mark you as brainliest if right!!! Explain!!

Answer:

-10

Step-by-step explanation:

Note that the points plotted on the line is by 2 (essentially, each line signifies 2).

The blue point is on the 5th line from the 0. 5 x -2 = -10

-10 is your answer.

~

Answer:Thus, the measure of angle B in terms of angle A is B = 90° - A.

Step-by-step explanation:
If sin(A) = cos(B), then we can use the co-function identity to relate the two angles. The co-function identity states that sin(x) = cos(90° - x) for any angle x.

So, if sin(A) = cos(B), then we can say that B = 90° - A.

Thus, the measure of angle B in terms of angle A is B = 90° - A.

Answer:

The Answer is 47

Step-by-step explanation:

Because you do A squared plus B squared equals C squared and Squared is just multiplying both by two.

Answer:

x=8

Step-by-step explanation:

6²+x²=10²

36+x²=100

x²=100-36

x²=64

square root of 64 is 8

x=8

Ethan deposited amount $144,000 over 31 years and made a total of $565,165.25 in interest.

Ethan's total deposit amount to his IRA was $144,000 ($400 per month for 31 years). The total amount he had in his IRA upon retirement was $709,165.25. This means that he made a total of $565,165.25 ($709,165.25 - $144,000) in interest over the length of the investment. This amount was likely made up of a combination of capital gains, dividends, and other investment returns. It is important to note that the interest rate can vary depending on the type of investments chosen, so this amount may be higher or lower depending on the types of investments made.

1. Calculate the total number of months Ethan invested for: 31 years x 12 months = 372 months

2. Calculate the total amount deposited: $400 per month x 372 months = $148,800

3. Calculate the total amount upon retirement: $709,165.25

4. Calculate the total interest made: $709,165.25 - $148,800 = $565,165.25

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The requreid function has two intervals of decreasing values, one between -1 and 1, and the other between 3 and 5. Options C and E are correct.

The function is decreasing in the interval -1 < x < 1,
which means that as x increases from -1 to 1, the corresponding values of the function decrease.

Similarly, the function is decreasing in the interval 3 < x < 5, which means that as x increases from 3 to 5, the corresponding values of the function decrease.

Therefore, the function has two intervals of decreasing values, one between -1 and 1, and the other between 3 and 5.

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Therefore , the solution of the given problem of expressions comes out to be  y (or f(x)) is equal to zero at this location.

Instead of using random estimates, shifting numbers—which might factor be growing, decreasing, or blocking—should be used. They could only help one another by exchanging instruments information, or solutions to issues. The arguments, components, or quantitative comments for methods like greater disagreement, fabrication, and blending may be included in the statement of fact equation.

Here,

We must first fix y = 0 and then solve for x in order to determine the x-intercept of the equation 24x = 80.

Initially, the equation

=> 24x = 80

When we multiply both sides by 24, we get:

=> x = 80/24

When we simplify the fraction, we obtain:

=> x = 10/3

Therefore, (10/3, 0) is the x-intercept of the equation 24x = 80. The x-intercept, which denotes the location where the equation's graph intersects the x-axis,

indicates that y (or f(x)) is equal to zero at this location.

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Answer: We can use trigonometry to solve this problem.

First, let's draw a diagram to represent the situation:

           |

           |

           | 8 km

           |

           |

   --------X---------

           | 3 km

           |

           |

           |

           |

The starting point is at the X, and the destination is 8 km south and 3 km west of the starting point.

To find the distance and bearing of the destination from the starting point, we can use the Pythagorean theorem and trigonometric functions.

The distance between the starting point and destination is the hypotenuse of a right triangle with legs of length 8 km (south) and 3 km (west). So we can use the Pythagorean theorem:

distance = √(8² + 3²) ≈ 8.6 km

To find the bearing (direction) of the destination from the starting point, we can use trigonometry. The bearing is the angle between the line connecting the starting point and destination and the line pointing due north.

We can use the tangent function to find this angle:

tan(θ) = opposite/adjacent = 3/8

θ = tan⁻¹(3/8) ≈ 20.56°

So the bearing of the destination from the starting point is approximately 20.56° west of due south.

Therefore, the distance of the destination from the starting point is approximately 8.6 km and the bearing of the destination from the starting point is approximately 20.56° west of due south.

Step-by-step explanation:

Answer:  300 in3

Step-by-step explanation: To find the volume you multiply the base area by the height. 30 x 10 = 300. Did this for my exam and got the question correct.

The volume of the prototype is 300in^3.

Since The designer uses octagons with a base area of 30 in2 and rectangles with a length of 10 in to create a prototype for the new package.

So here the volume is

= 30(10)

= 300

Therefore, The volume of the prototype is 300in^3.

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The concept of consecutive integers is explained as follows:

Consecutive numbers, or consecutive integers, are integers that follow each other in order. The difference between any two consecutive numbers is always 1. For example, the consecutive numbers starting from 1 would be 1, 2, 3, 4, 5, and so on. Similarly, the consecutive numbers starting from -3 would be -3, -2, -1, 0, 1, 2, and so on.

It is important to note that if we have a consecutive sequence of integers, one number will be even, and the next number will be odd. This is because the parity (evenness or oddness) alternates as we move through consecutive integers.

Furthermore, the sum of two consecutive numbers (and, in fact, the sum of any number of consecutive numbers) is always an odd number. This is because when we add an even number to an odd number, the result is always an odd number.

To generate a sequence of consecutive integers, we can start with any integer n and then use n, n+1, n+2, and so on to obtain consecutive integers. For example, if n is an integer, then n, n+1, and n+2 will be consecutive integers.

Here are some examples of consecutive integers:

- Starting from 1: 1, 2, 3, 4, 5, ...

- Starting from -3: -3, -2, -1, 0, 1, 2, ...

- Starting from 1004: 1004, 1005, 1006, 1007, ...

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Answer:

  (a)  Inconsistent

Step-by-step explanation:

Two linear equations can be compared by putting both of them in standard form. Here, that means removing a common factor from the coefficients of the first equation.

  3x -6y = -12 . . . . given first equation

  x -2y = -4 . . . . . . divide by 3

Compare this to the second equation:

  x -2y = -8

The constants (-4, -8) are different, so there are no values of x and y that can satisfy both equations. The equations are described as inconsistent.

Answer:

Step-by-step explanation:

Equation 1

Equation 2

On comparison, it is seen that the slopes are same, but the y-intercepts are different.

This means this has no solution, or the graph is inconsistent.

Answer:

(a)  5/12

Step-by-step explanation:

to solve this problem you can make all fractions equivalent with 12 as the denominator

a) 5/12

b) 2/3 = 8/12      Multiply top and bottom by 4

c) 5/6 = 10/12     Multiply top and bottom by 2

d) 3/4 = 9/12       Multiply top and bottom by 3

if you compare numerators, the smallest one is the closest to zero, which would be (a) 5/12

Answer:

A 5/12

Step-by-step explanation:

first you need to round these all to /12 so a is 5/12

12/3 is 4 so multiply 4 by two which means b is 8/12

12/6 is 2 so multiply 5 by two which gives us c = 10/12

12/4 is 3 and multiply 3 x 3 which is 9 so d is 9/12

5 is the lowest decimal/fraction which makes it the closest to 0

Yes, the data give convincing evidence to support Phoebe's hunch. As the result of the test is a p-value that is 0.1 of less than 0.05.

The p-value is the probability of obtaining a result as extreme or more extreme given that the null hypothesis is true. The p-value is calculated by comparing the test statistic to the probability distribution under the null hypothesis.

The ratio of seniors bringing a bag lunch= 78/104 or 0.75,

while the ratio of sophomores bringing a bag lunch= 52/80 or 0.65.

This indicates that the proportion of seniors bringing a bag lunch is higher than the proportion of sophomores bringing a bag lunch.

Further, the difference between the proportions is

0.75-0.65 = 0.1,

which is a large enough difference to be considered significant.

The result of the test is a p-value of less than 0.05, which is statistically significant and indicates that the difference in the proportions is due to the different ages, and not due to chance.

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False. It is not optimal for Anil to give Bala one-third of the lottery money (£33.33). According to Anil's preferences, his utility function is given by u(A,B) = min{2A, B}.

This function implies that Anil values his own money (A) more than the money he gives to Bala (B). By giving Bala one-third of the money, Anil would keep only £66.67 for himself, which is less than what he could potentially keep if he gave Bala a smaller amount. To maximize his own utility, Anil should give Bala the minimum amount possible, which in this case would be zero.

Anil's utility function indicates that he values his own money (A) twice as much as the money he gives to Bala (B). By maximizing his utility, Anil would want to keep as much money for himself as possible, while still giving Bala some amount of money. In this case, Anil can keep £100 for himself, which is the maximum amount possible, while giving Bala £0.

This division of money maximizes Anil's utility according to his preferences. Therefore, it is not optimal for Anil to give Bala one-third of the lottery money; instead, he should give Bala the minimum amount of £0 to maximize his own utility.

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Answer:

Not sure if this is what you are looking for but. Both X and Y go up at the same time and the line is linear.

Step-by-step explanation:

does this answer your question?

For any lower bound L of A, we have −L ≤ N, which implies that −N is the greatest lower bound for A.

To prove that A has the greatest lower bound, we can follow the hints given:

Hint #1: Since A is bounded below, it has a lower bound M ∈ R. Now define a new set B:= {x ∈ R: x = −a for some a ∈ A}. Prove that −M is an upper bound for B as follows. Let x ∈ B be arbitrary. It follows that x = −a for some a ∈ A.

To prove that −M is an upper bound for B, we need to show that for any x ∈ B, x ≤ −M. Since x = −a for some a ∈ A, we have −a ∈ A. Since M is a lower bound for A, we have −a ≥ M. Therefore, x = −a ≤ −M, which implies that −M is an upper bound for B.

Hint #2: Use the result of Hint #1 to help explain that B has a least upper bound N ∈ R.

Since −M is an upper bound for B, B is bounded above. By the Completeness Axiom, B has a least upper bound, denoted as N.

Hint #3: Prove that −N is the greatest lower bound for A as follows. Let a ∈ A be arbitrary, and note that −a ∈ B. Continue this argument and establish that −N is a lower bound for A. To verify that −N is the greatest lower bound, let L ∈ R be an arbitrary lower bound for A. By an argument analogous to that suggested in Hint #1, −L is an upper bound for B.

Let's prove that −N is a lower bound for A. Since N is the least upper bound of B, we have x ≤ N for all x ∈ B. Since B = {x ∈ R: x = −a for some a ∈ A}, we have −a ∈ B for any a ∈ A.

Therefore, for any a ∈ A, we have −a ≤ N, which implies that −N is a lower bound for A.

To prove that −N is the greatest lower bound for A, let L ∈ R be an arbitrary lower bound for A. By the same reasoning as in Hint #1, we can show that −L is an upper bound for B.

Since N is the least upper bound of B, we have −L ≤ N. Therefore, for any lower bound L of A, we have −L ≤ N, which implies that −N is the greatest lower bound for A.

In conclusion, we have proven that A has the greatest lower bound, which is −N.

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Answer:

the value of x is 9, in this expression

Step-by-step explanation:

A type of quantitative analysis in which the amount of a species in a material is determined by converting the species to a product that can be isolated completely and weighed is "gravimetric analysis."

Gravimetric analysis is a quantitative chemical analysis method in which the contribution sought is transformed into a material (of different compositions) that can be separated and weighed from the sample.

Some key features regarding the gravimetric analysis are-

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The labor quantity variance of Clark Company is $1800 U (Unfavorable). Option b is correct.

Compare the actual labor hours used with the standard labor hours allowed and multiply the difference by the standard labor rate.

Standard labor hours allowed = Standard hours per unit × Number of units produced

Standard labor hours allowed = 2 hours × 1200 units = 2400 hours

Actual labor hours used = 2500 hours

Labor quantity variance = (Actual labor hours used - Standard labor hours allowed) * Standard labor rate

Labor quantity variance = (2500 hours - 2400 hours) × $18 per hour

Labor quantity variance = 100 hours × $18 per hour

Labor quantity variance = $1800

Since the actual labor hours used exceeded the standard labor hours allowed, the labor quantity variance is unfavorable. Therefore, the labor quantity variance is $1800 U (Unfavorable).

Option b is correct.

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The product of the zeros in the given polynomial is 5.

Given is a polynomial p(x) = (a+1)x² + (2a+3)x + (3a+4), the sum of zeros is -1,

We need to find the product of its zeros,

So,

We know that in the polynomial ax²+bx+c = 0,

the sum of the roots = -b/a

Product of the roots = c/a

Therefore,

Here a = a+1, b = 2a+3 and c = 3a+4

So,

-(2a+3)/a+1 = -1

-2a-3 = -a-1

-a = 2

a = 2

Put a = 2 in value of c,

c = 3(2)+4 = 10

So, the product of the zeros is = 10/2 = 5

Hence the product of the zeros in the given polynomial is 5.

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For the relationship, two variables are needed.

One of the variable is given as 'z'. Let the other one be 'x'.

Then you need to translate that 'x' is six more than four times a number 'z'.

This can be expressed as,

Thus, the right side of the expression represents the relationship "six more than four times a number z".

The missing sides of the special right triangles are listed below:

Case 1: y = √2 · 13, x = 13

Case 2: x = y = 15√2

Case 3: x = 6, y = 3√3

Case 4: x = 17√3, y = 17

Case 5: x = y = 10

Case 6: x = 50, y = 25

Case 7: x = y = 4√7

Case 8: x = 16√3, y = 8√3

Case 9: x = 11√3, y = 33

Case 10: x = 3√2, y = 2√6

Case 11: x = √10, y = 2√5

Case 12: x = 4√7, y = 8√21

Herein we find twelve cases of special right triangles whose missing sides must be determined by using the following rules:

45 - 90 - 45 Right triangle

r = √2 · x = √2 · y

30 - 60 - 90 Right triangle

x = (1 / 2) · r

y = (√3 / 2) · r = √3 · x

Where:

Case 1

y = √2 · 13

x = 13

Case 2

x = y = 15√2

Case 3

x = 3 / (1 / 2)

x = 6

y = 3√3

Case 4

x = 34 · (√3 / 2)

x = 17√3

y = 34 · (1 / 2)

y = 17

Case 5

x = y = 10

Case 6

x = 25√3 / (√3 / 2)

x = 50

y = 25√3 / √3

y = 25

Case 7

x = y = 2√14 · √2 = 2√28 = 4√7

Case 8

x = 24 / (√3 / 2)

x = 48 / √3

x = 16√3

y = 24 / √3

y = 8√3

Case 9

x = 22√3 · (1 / 2)

x = 11√3

y = 22√3 · (√3 / 2)

y = 33

Case 10

x = √18

x = 3√2

y = √6 / (1 / 2)

y = 2√6

Case 11

x = √10

y = √20

y = 2√5

Case 12

x = 4√21 / √3

x = 4√7

y = 4√21 / (1 / 2)

y = 8√21

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The area of the vertical cross section of the cylinder is approximately 71.68 square units.

The circumference of a cylinder can be calculated using the formula:

C = 2πr

Where C is the circumference and r is the radius of the cylinder.

In this case, we know that the circumference is 30, so we can set up the equation:

30 = 2 * 3.14 * r

Dividing both sides of the equation by 2 * 3.14, we get:

r = 30 / (2 * 3.14)

r ≈ 4.777

The area of the vertical cross section of a cylinder is given by the formula:

A = πr^2

Substituting the value of r we found:

A = 3.14 * (4.777)^2

A ≈ 71.68

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Answer: 72

Step-by-step explanation: 40% of 360 is 144 meaning he bought 216. 50% of 216 is 108, and 25% of 144 is 36. Meaning he donated 72 more bought models then made models.

the solutions for -2sinθ = 1.2 in the interval 2π ≤ θ ≤ 4π are approximately:

θ ≈ -0.6435 radians, 5.499 radians, 3.785 radians, and 9.927 radians.

To solve the equation -2sinθ = 1.2 in the interval 2π ≤ θ ≤ 4π, follow these steps:

Step 1: Rewrite the equation in terms of sinθ:

sinθ = -1.2 / 2

Step 2: Check if the right-hand side of the equation is within the range of the sine function, which is -1 to 1. If it is not, then there are no solutions in the given interval. In this case, -1.2/2 = -0.6, which is within the range of the sine function, so we can proceed.

Step 3: Use the inverse sine function (arcsin) to find the value of θ:

θ = arcsin(-0.6) + 2kπ or θ = π - arcsin(-0.6) + 2kπ

where k is an integer (k = 0, ±1, ±2, ...)

Step 4: Substitute the value of k to find all possible solutions within the interval 2π ≤ θ ≤ 4π:

1. For k = 0:

θ = arcsin(-0.6) = -0.6435 radians (approx)

2. For k = 1:

θ = arcsin(-0.6) + 2π ≈ 5.499 radians (approx)

3. For k = -1:

θ = π - arcsin(-0.6) ≈ 3.785 radians (approx)

4. For k = 2:

θ = π - arcsin(-0.6) + 2π ≈ 9.927 radians (approx)

So, the solutions for -2sinθ = 1.2 in the interval 2π ≤ θ ≤ 4π are approximately:

θ ≈ -0.6435 radians, 5.499 radians, 3.785 radians, and 9.927 radians.

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odds= probability/ (1-probability)

Answer:

2/4a-4

Step-by-step explanation:

dividing 2/4a-4 is =1/2a-4