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Two objects that each have a mass of 10,000 kg are 5.5 m apart. What is the gravitational force between them? (Universal constant of gravitation: 6.67 x 10-11)

a. 2.20 x 10^-4 N
b. 1.51 x 10^-3 N
c. 2.59 x 10^-5 N
d. 1.99 x 10^-4 N

The student changed more than one independent variable.

A dependent variable is a variable that changes as a result of the manipulation of the independent variable. It's the result you want to measure and it depends on the independent variable. In statistics, the dependent variable is also called the response variable it responds to changes in another variable.

In other words, the two characteristics of the experimental design we've talked about so far are that the experiment must have at least two comparable conditions, and the researcher must match the participants to the conditions, not the participants themselves. That's it. The independent and dependent variables are those when you run the experiment. The independent variable is the one that changes and the dependent variable is the one that changes.

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Answer:

The object appears larger

Explanation:

B

A 1 kg item falls 2.50 m from the table's base.

a) By the conservation of momentum, we have:m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'where m₁ = 0.5 kg, m₂ = 1 kg, v₁ = √(2gh) = √(29.812.5) = 7.85 m/s (where h = 2.5 m is the height of the track), v₂ = 0, and v₁' and v₂' are the velocities of the 0.5 kg block and 1 kg object, respectively, after the collision.

Solving for v₁' and v₂', we get:v₁' = (m₁ - m₂)/(m₁ + m₂) * v₁ = -1.95 m/s v₂' = 2m₁/(m₁ + m₂) * v₁ = 3.90 m/s. So the 0.5 kg block moves backwards with a velocity of 1.95 m/s, and the 1 kg object moves forward with a velocity of 3.90 m/s.

b) The maximum height reached by the 0.5 kg block can be found using conservation of mechanical energy.

At the top of the track, the block has potential energy mgh, which is converted entirely into kinetic energy just before the collision. After the collision, the block travels up the track again until it comes to rest at some maximum height \(h_m_a_x\). At this point, it has kinetic energy of 1/2 m₁v₁'². Setting these equal, we get:mgh = 1/2 m₁v₁'² Solving for h, we get:

\(h_m_a_x\) = v₁'²/(2g) = (1.95 m/s)²/(2*9.81 m/s²) = 0.190 m.

So the 0.5 kg block travels back up the track to a height of 0.190 m after the collision.

c) To find the horizontal distance the 1 kg object travels before landing on the table, we can use the time it takes to fall from a height of 2 m. This can be found using the equation h = 1/2 gt², where h = 2 m and g = 9.81 m/s². Solving for t, we get :t = √(2h/g) = √(2*2/9.81) = 0.64 s During this time, the object travels a horizontal distance of d = vt , where v = v₂' = 3.90 m/s.

Therefore :d = vt = (3.90 m/s)(0.64 s) = 2.50 m. So the 1 kg object lands 2.50 m away from the bottom of the table.

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The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole

The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²

Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

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Answer:

Proxima Centauri was discovered in 1915.

Robert Innes used a blink comparator to examine a photographic plate showing an area of 60 square degrees around Alpha Centauri.

The sixty-four-meter radio telescope at Parkes Observatory in Australia.

they used the James Webb Space Telescope and The sixty-four-meter radio telescope.

no nothing as been to Proxima Centauri it would take about 54,400 years to get there.  

getting to Proxima Centauri, our solar system's nearest star, would take four years and three months. And that is travelling at light speed, a velocity well beyond our reach. The quickest we could currently get to Proxima Centauri, using our fastest rockets, is 80,000 years.

Explanation:

Explanation:

Mass=7 kg means that it weights 7 kg while measuring on beam balance .

Answer:

a) 0 metres

b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s

c) 20 m/s

Explanation:

a) Formula of displacement= velocity x time

time=40 s

velocity =0 m/s

∴ displacement= 0 x 40 = 0 m

Magnitude of displacement is 0 m

b) The increase in velocity shows that there has been acceleration.

c) The average velocity of the car is =\(\frac{0+40}{2\\}\)   {initial velocity + final velocity}

                                                            =\(\frac{40}{2}\)

                                                             =20

Therefore, the magnitude of the average velocity  of the car is 20 m/s

The true statement, given the data from the question is: Both blocks will float equally over water.

To know which statement is true, we shall obtain the density of each blocks. Details below

For block A:

Density = mass / volume

Density of block A = 10 / 25

Density of block A = 0.4 g/mL

For block B:

Density = mass / volume

Density of block B = 20 / 50

Density of block B = 0.4 g/mL

From the above calculation, we can see that the two blocks have the same density.

Thus, we can conclude that the true statement is both blocks will float equally over water.

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Answer:

1.5

Explanation:

Answer:

compound

Explanation:

a substance made from two or more different elements that have been chemically joined. Examples of compounds include water (H2O), which is made from the elements hydrogen and oxygen, and table salt (NaCl), which is made from the elements sodium and chloride.

Answer:

24 J

Explanation:

\(K = \frac{1}{2} mv^{2} = \frac{1}{2} (3kg)(4m/s)^{2} = 24 J\)

Answer:

\(M_2=0.79kg\)

Explanation:

From the question we are told that:

Period \(T=0.517s\)

Trial 1

Spring constant \(\mu=117N/m\)

Period \(T_1=0.37\)

Mass \(m=0.400kg\)

Trial 2

Period \(T_2=0.52\)

Generally the equation for Spring Constant  is mathematically given by

\mu=\frac{4 \pi^2 M}{T^2}

Since

\(\mu _1=\mu_2\)

Therefore

\(\frac{4 \pi^2 M_1}{T_1^2}=\frac{4 \pi^2 M_2}{T_2^2}\)

\(M_2=M_1*(\frac{T_2}{T_1})^2\)

\(M_2=0.400*(\frac{0.52}{0.37}})^2\)

\(M_2=0.79kg\)

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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The gravitational potential energy gained by the body of mass 52 kg when climbing a stairs is 1274 J.

Gravitational potential energy is the energy of a body due to its position in the gravitational field.

To calculate the gravitational potential energy, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the gravitational potential energy of the body is 1274 J.

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To solve the given problems, we'll use the principles of work-energy and conservation of energy. Let's address each question one by one:

(1) What is the work done by Chris on the box when the speed of the box reaches 2.1 m/s?

The work done by Chris on the box is equal to the change in the box's kinetic energy. Since the box starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the formula:

Kinetic energy = (1/2) * mass * velocity^2

Plugging in the values:

Mass of the box (m) = 53 kg

Final velocity (v) = 2.1 m/s

Kinetic energy = (1/2) * 53 kg * (2.1 m/s)^2

Calculate the value of the kinetic energy, which represents the work done by Chris on the box.

(2) What is the speed of the box when it reaches the bottom of the slope (Point B in the diagram)?

To determine the speed at the bottom of the slope, we'll use the principle of conservation of energy. The total mechanical energy of the box is conserved as it moves from the top to the bottom of the slope.

The initial potential energy at the top of the slope is converted into kinetic energy at the bottom of the slope, neglecting any energy losses due to friction.

Potential energy at the top = m * g * h1

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between floors (h1) = 3.2 m

Calculate the initial potential energy.

The final kinetic energy at the bottom is given by:

Kinetic energy at the bottom = (1/2) * m * v^2

Where:

Mass of the box (m) = 53 kg

Velocity at the bottom (v) = ?

Equating the initial potential energy to the final kinetic energy, solve for v to find the speed of the box at the bottom of the slope.

(3) To what speed does the box slow down when it reaches the bottom of the ramp to the pickup truck?

Since the ramp connecting the first floor to the bed of the pickup truck is frictionless, there is no external force doing work on the box. Thus, the mechanical energy of the box is conserved as it moves from the bottom of the slope to the bottom of the ramp.

Using the same principle of conservation of energy, equate the final kinetic energy at the bottom of the slope to the initial potential energy at the bottom of the ramp.

Potential energy at the bottom of the ramp = m * g * h2

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between the first floor and the truck bed (h2) = 0.90 m

Calculate the potential energy at the bottom of the ramp.

Equating the potential energy at the bottom of the ramp to the final kinetic energy, solve for the speed of the box at the bottom of the ramp.

(4) What is the speed of the box when it reaches the bed of the pickup truck?

Since the ramp connecting the first floor to the truck bed is frictionless, there is no external force doing work on the box. The mechanical energy of the box is conserved as it moves from the bottom of the ramp to the truck bed.

Using the same principle of conservation of energy, equate the final potential energy at the bottom of the ramp to the final kinetic energy at the truck bed.

Potential energy at the truck bed = m * g * h

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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The potential difference is related to the kinetic energy of the electron by the formula,

1/2mv^2 = eV

where

m is the mass of the electron

e is the charge of the electron

V is the potential dfference

From the information given,

V = 382.11 x 10^3

m = 9.1 x 10^-31

e = 1.6 x 10^- 19

Thus, we have

1/2 x 9.1 x 10^-31 x v^2 = 1.6 x 10^- 19 x 382.11 x 10^3

45.5 x 10^- 32v^2 = 611.376 x 10^- 16

v^2 = 611.376 x 10^- 16/45.5 x 10^- 32

Taking square root of both sides,

v = 3.67 x 10^8 m/s

The velocity is 3.67 x 10^8 m/s

Answer:

I think the  answer is frequency

Answer:

wAvE

Explanation:

i have my ways

Since the  refractive index of the core is higher than that of the cladding, light in the core striking the cladding boundary at an angle steeper than the critical angle is reflected back into the core by total internal reflection.

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Explanation:

Video games are developed around a structure that is unique from your usual media, where there is a sense purpose in mind when playing a game, as decided by the player, and it allows them to explore creative options in order to solve scenarios, depending on the genre. In the use of phones, internet, or computers, this structure is more rare and diverse from video games, which does not lean more toward a creative purpose to build from. That idea gives people the inspiration and discover skills they never knew they even had.

Answer:

8 divided by 12 is 1.6

Explanation:

. .......

Aproximately 1.09 m/s was the locust's first speed.

In engineering mechanics, vectors are used to express values with both a magnitude and a direction. For analysis, vector representations of a variety of engineering quantities—including forces, displacements, velocities, and accelerations—are required.

Δy = vsin(θ)t - 0.5gt²

0 = v*sin(55°)t - 0.5(-9.81 m/s²)*t²

t = 2vsin(55°)/g

Now, we can use the horizontal motion of the locust to find the initial velocity v. The horizontal distance traveled by the locust is given by:

Δx = v*cos(55°)*t

Substituting the expression for t that we just found:

0.750 m = vcos(55°)2vsin(55°)/g

Solving for v:

v = √(0.750 mg/(2sin(55°)*cos(55°)))

v ≈ 1.09 m/s

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Answer:

Explanation:

F = ma so filling in:

60.0 = 4.50a and

a = 13.3 m/s/s