Please helppppp I need help​

Answer:

I could try to help but I can't see the stuff on the chart

The correct equation to find the number of tea bags Sarah has is D. t + 39 + 22 = 87. The total number of tea bags they have altogether (87).

In the equation D. t + 39 + 22 = 87, t represents the number of tea bags Sarah has. We add the quantities of tea bags her mom and sister have, which are 39 and 22, respectively. The sum of these three quantities should equal the total number of tea bags they have in total, which is given as 87.

To solve the equation, we can simplify it by adding 39 and 22: t + 61 = 87. Next, we can isolate t by subtracting 61 from both sides of the equation: t = 87 - 61. Simplifying further, we find that t = 26. Therefore, Sarah has 26 tea bags.

In conclusion, Sarah has 26 tea bags based on the given information and the equation t + 39 + 22 = 87.

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Answer:

Step-by-step explanation:

divide 1.5 by 4 to get 1/9 of the cost, and then multiply that by 9 to get the cost of one kilo.

or 3.375, round it for money purposes

$3.38

Answer:

Y = -2X + 7

Step-by-step explanation:

Y = a(x-h)^2 + k

From (h,k) h = 0 k = 7 x = 2 y = 3

3 = a(2-0) + 7

3 = 2a - 0 + 7

Collect like terms

2a = 3 - 7

2a = -4

Divide both sides by 2

2a/2 = -4/2

a = -2

y = a(x-h) + k

y = -2(x-0) + 7

y = -2x + 0 + 7

y = -2x + 7 or

y + 2x - 7 = 0

27.3

Step-by-step explanation:

Here, we can add the outside sides of the trapezoid, which are already given:

6 + 6 + 9 = 21

Then for the circle, we can find half of the circumference with πr. The diameter of the circle is 4 (given), so the radius (half the diameter) is 2.

Thus,

π(2) ≈ 6.28

By adding all of these parts, you get

21 + 6.28 = 27.28

Which, rounded to the tenths is 27.3

Answer:

52.4

Step-by-step explanation:

The perimeter of a Trapezoid:

P=a+b+c

6+15+8+8=37

The perimeter of a semicircle:

\(L=\pi r+d= 3\pi+6\\=15.4248 \\=15.4\)

Add both together:

37+15.7=52.4

Answer:

4.295cm

Step-by-step explanation:

Here,

Circumference = 27cm

We know,

C=2πr

or, 27 = 2×22×r

7

or, 44×r = 27

7

27

or, r = 44

7

or, r = 27×7

44

Therefore, r = 4.295cm

Answer:

seven times the difference of a number b, and two

Step-by-step explanation:

hope this helps

Answer:

4 times x + 15 = 6 times x -3

The data represents the linear equation.

Equations whose variables have a power of one are called linear equations. One example with one variable is where ax+b = 0, where a and b are real values and x is the variable.

We have the table:

x → y

-9 →  -71

-8 → -63

-7 → -55

-6 →  -47

-5 →  -39

To prove that the data represents in the tables are from the linear equation:

If a first difference of the table of values shows a constant rate of change,

then the function is a linear equation.

So,

y₂-y₁ = -63 + 71 = 8

y₃ - y₂ = -55 + 63 = 8

y₄ - y₃ = -47 + 55 = 8

y₅ - y₄ = -39 + 47 = 8

Here, 8 is the constant rate of change.

So, the data represents the linear equation.

Therefore, the data represents the linear equation.

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On the number line, 3 and 11 are the numbers that are a distance of 4 units from 7..

On there are two types of numbers one is a positive and the other is a negative number. These two are separated by the number zero which is known as the origin. Positive numbers are on the right side of the origin and negative numbers are on the left side of the origin on the number line.

We have been asked the numbers which are a distance of 4 units from 7 on the number line.

For that, we will first add 4 to the number 7, that is,

                            4 + 7 = 11

Thus, number 11 is a distance of 4 units from 7 on the number line if we move to the right side from 7.

Now we will subtract 4 from the 7 we will get,

                          7-4 = 3

Thus, Number 3 is a distance of 4 units from 7 on the number line if we move to the left side from 7.

Hence 3 and 11 are the numbers that are a distance of 4 units from 7 on the number line.

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multiply Start Fraction 5 Over 7 End Fraction by 3.

What do math fractions mean?

An element of a whole is a fraction. In mathematics, the number is represented as a quotient, where the numerator and denominator are divided. Both are integers in a simple fraction.

                                Whether it is in the numerator or denominator, a complex fraction contains a fraction.

                             The numerator and denominator of a correct fraction are opposite each other.

What is basic fraction theory?

Every fraction has two components: the numerator, which is the actual number of parts, and the denominator, which is the total number of parts.

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Answer:

c is the answer i took the test

Step-by-step explanation:

Answer:

Step-by-step explanation:

48

Answer:

51

Step-by-step explanation:

Pythagorean theorem

a^2+b^2=c^2

45^2+24^2

2025+576

2601=c^2

square root both sides

51=c

Hopes this helps please mark brainliest

An exponent is a number written above and to the right side of a value or number in math. The value or number is called the base, and the expression is read out as;

"Base raised to the power of exponent."

An example is given below;

In this example, 10 is the base and 3 is the EXPONENT.

The expression is now read out as,

"10 raised to the power of 3"

Note that even unknown values (such x as we commonly use in math) can also be an exponent or base. For example, we can have;

So basically, an exponent indicates the number of times a number is used to multiply itself.

The possible values are -

(a²,b²) = p

(a²,b) = p if p|-r and (a²,b) = p² if p|r

(a²,b³) = p² if p|-r and (a²,b³) = p³ if p|r

What is gcd?

The greatest common factor (GCF) that divides two or more numbers is known as the greatest common divisor (GCD). The highest common factor is another name for it (HCF).

Since (a, b) = p it can be written a = pr and b = ps where r and s are integers such that (r, s) = 1.

Then a² = p²r².

Then by Theorem 1.7, (a²,b) = (p²r²,ps) = p(pr²,s).

By Theorem 1.8, (r²,s) = 1 .

Thus, there are two cases to consider: if p|s then, (a²,b) = p², and if p|-s then (pr²,s) = 1 (Again by Theorem 1.8)  so that (a²,b) = p in that case.

Thus, there are two cases for (a²,b): namely p or p².

The same analysis shows that (a³,b) must be either p, p² or p³ depending on the power of p that divides b.

Analyze (a²,b³) as follows.

Using the notation already introduced, and

Theorem 1.7, it is obtained that (a²,b³) = (p²r²,p³s³) = p²(r²,ps³).

Since, (r, s) = 1, Theorem 1.8 shows that (r²,s³) = 1.

Therefore, there are two possibilities for (a²,b³) -

(a²,b³) = p² if p|-r and (a²,b³) = p³ if p|r.

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a. To write an equation representing this scenario, let's use x to represent the number of single kayaks rented and y to represent the number of two-person kayaks rented. The equation would be: 50x + 75y = 600. This equation represents the total amount of money earned by renting out x number of single kayaks and y number of two-person kayaks. The goal is to earn $600 per day.

b. To find the x-intercept, we need to set y equal to zero in the equation and solve for x:
50x + 75(0) = 600
50x = 600
x = 12
So the x-intercept is (12,0), which means that if the company rents out 12 single kayaks, they will earn $600 in revenue.
To find the y-intercept, we need to set x equal to zero in the equation and solve for y:
50(0) + 75y = 600
75y = 600
y = 8
So the y-intercept is (0,8), which means that if the company rents out 8 two-person kayaks, they will earn $600 in revenue.

c. The intercepts represent the points at which the company will earn $600 in revenue by renting out only single kayaks (x-intercept) or only two-person kayaks (y-intercept). These points can help the company determine the minimum number of kayaks they need to rent out to meet their revenue goal. For example, if they only have single kayaks available, they would need to rent out at least 12 kayaks to earn $600. If they only have two-person kayaks available, they would need to rent out at least 8 kayaks to earn $600.

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Henry could only see one line since both lines had the same slope, which means that the graphs of both equations will be identical and hence overlap.

Linear equations in a system 3x + 2y = 4, and 9x + 6y = 12

We must demonstrate why Henry could only make out one line when he plotted the equations 3x-2y=4 and 9x-6y=12 on a graph.

Take the provided linear equation system into consideration.

3x - 2y = 4 ................(1)

9x - 6y = 12 ..................(2)

Due to the fact that equation (2) is a multiple of equation (1), 3 (3x - 2y = 4) = 9x - 6y = 12

The slopes of the provided equations are also same.

Difference with regard to x for equation (1) yields,

additional to equation (2),

With regard to x, we can differentiate to get,

The graphs of both equations will overlap since both lines have the same slope and hence have the same appearance on the graph.

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Answer:

10.6

Step-by-step explanation:

range is the difference between the lowest and the highest number

example: the lowest number wold be 1.1 and the highest is 11.7 you need to subtract them and then you have your answer!!!

The range of the given set of data is 10.8.

The given data is 2.3, 4.5, 6.7, 1.1, 11.6, 4.5, 11.7, 8.5, 3.2, 6.7, 7.9.

We need to find the range of the given data.

The range is the difference between the highest and lowest values within a set of numbers. To calculate the range, subtract the smallest number from the largest number in the set.

From the given set of data, we can see that the lowest observation is 1.1 and the highest observation is 11.7.

Now, range=11.7-1.1=10.8

Therefore, the range of the given set of data is 10.8.

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Answer:

37(t)-10

Step-by-step explanation:

Answer:

Deal A is best

Step-by-step explanation:

Given

Deal A:

3/4 lb for $2.50

Deal B:

2/10 lb for $5.25

Required

Which deal is the better

To do this, we simply calculate the lb/dollar ratio

i.e.

\(Ratio = \frac{Amount}{Size}\)

For Deal A:

\(Ratio = \$2.50/\frac{3}{4}lb\)

\(Ratio = \$2.50 * \frac{4}{3}lb\)

\(Ratio = \frac{\$10}{3}lb\)

\(Ratio = \$3.33/lb\)

For Deal B:

\(Ratio = \$5.25/\frac{2}{10}lb\)

\(Ratio = \$5.25 * \frac{10}{2}lb\)

\(Ratio = \frac{52.5}{2}lb\)

\(Ratio = \$26.25/lb\)

The better deal is the least expensive:

Hence: Deal A is better

Answer: $650 + $450 divide it and then subtract it then it should be the answer X

Step-by-step explanation: answer

The total number of boxes required to cover the kitchen floor is 14.

The dimensions of the kitchen floor are 14' × 24'

⇒Length of the kitchen floor = 14 feet

⇒Width of the kitchen floor= 24 feet

The area of the kitchen floor= Length × Width

⇒ Area = 14 × 24

⇒ Area = 336 sq. ft.

Since, 4 boxes of flooring cover 100 sq. ft.

∴1 box will cover = 100/4 sq. ft.

⇒25 sq. ft.

Now, Number of boxes required to cover the floor of the kitchen will be,

⇒ Area of the floor / Area covered by 1 box of flooring

⇒336/25

⇒ 13.44

∴ The total number of boxes required to cover the kitchen floor is 14 (rounded up from 13.44).

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Answer:

3 series I believe

Step-by-step explanation:

7-4=3 this is what I got I believe it's right

Answer:

Turn everything into fractions. You can also combine like terms.

Step-by-step explanation:

The function f is \(f(x)=4x^{2}+6\)

The f(x) can be calculated as follows:

First, find the inverse of g(x)

\(g(x)=2x+1\)

replace g(x)=y

\(y=2x+1\)

Swap x with y

\(x=2y+1\)

Subtract both sides by 1

x-1=2y

Divide both sides by 2

\(\frac{x-1}{2}=y\)

Swap sides

\(y=\frac{2x-1}{2}\)

Replace y with \(g^{-1}(x)\)

\(g^{-1}(x)=\frac{2x-1}{2}\)

Given that \(f=h\circ g^{-1}\)

It follows \(f=h(g^-1}(x))\)

Substitute  \(g^{-1}(x)=\frac{2x-1}{2}\)

\(f=h(\frac{2x-1}{2})\)

Remember \(h(x)=4x^{2}+4x+7\)

Then, it follows:

\(f=4(\frac{2x-1}{2})^{2}+4(\frac{2x-1}{2})+7\)

Expand and simplify

\(f=4(\frac{4x^{2}-4x+1}{4})+2(2x-1)+7\\f=4x^{2}-4x+1+4x-2+7\\f=4x^{2}+6\)

hence \(f(x)=4x^{2}+6\)

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p-value is less than 0.05, we reject null hypothesis and conclude that model is significant.

In order to solve this question we use R software.

R codes :

d=read.table('data.csv',header=T,sep=',')

head(d)

attach(d)

fit=lm(Heart.Rate~Age+Weight+Height)

summary(fit)

fit2=lm(Heart.Rate~Age+Weight)

summary(fit2)

R outputs:

> d=read.table('data.csv',header=T,sep=',')

> head(d)

 Heart. Rate Age Weight Height

1         85  60    201     67

2        102  48    263     59

3         67  58    167     69

4         58  58    109     60

5         75  40    135     62

6         70  27    144     64

> attach(d)

> fit=lm(Heart.Rate~Age+Weight+Height)

> summary(fit)

Call:

lm(formula = Heart.Rate ~ Age + Weight + Height)

Residuals:

    Min       1Q   Median       3Q      Max

-21.1662  -7.9919   0.3377  10.3521  25.4165

Coefficients:

           Estimate Std. Error t value Pr(>|t|)

(Intercept) -2.86211   36.23799  -0.079   0.9377

Age          0.45993    0.21595   2.130   0.0428 *

Weight       0.12192    0.04841   2.519   0.0183 *

Height       0.59428    0.50119   1.186   0.2464

---

Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 13.15 on 26 degrees of freedom

Multiple R-squared:  0.2841, Adjusted R-squared:  0.2015

F-statistic: 3.439 on 3 and 26 DF,  p-value: 0.03137

> fit2=lm(Heart.Rate~Age+Weight)

> summary(fit2)

Call:

lm(formula = Heart.Rate ~ Age + Weight)

Residuals:

   Min      1Q  Median      3Q     Max

-26.126  -9.851   1.049  10.328  22.284

Coefficients:

           Estimate Std. Error t value Pr(>|t|)

(Intercept) 36.63974   14.36802   2.550   0.0168 *

Age          0.45122    0.21744   2.075   0.0476 *

Weight       0.12065    0.04876   2.474   0.0199 *

---

Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 13.25 on 27 degrees of freedom

Multiple R-squared:  0.2454, Adjusted R-squared:  0.1895

F-statistic:  4.39 on 2 and 27 DF,  p-value: 0.02235

A.

Multiple linear regression equation :

y hat =  -2.862    +   0.460 X1  +    0.122 x2    +   0.594 x3

b.

F =   3.439 on 3 and 26 DF,

p-value: 0.03137

Since p-value is less than 0.05, we reject null hypothesis and conclude that model is significant.

c.

The variable whose p-value is less that variable is highly correlated with heart rate.

Here variable weight is highly correlated with heart rate.

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The shaded region is made up of the area of a rectangle minus the areas of the semicircles. The semicircles have a diameter of 2 inches, so the radius of each semicircle is 1 inch.

The area of each semicircle can be found using the formula pir^2, where r is the radius. So the area of each semicircle is pi1^2 = pi square inches.

The area of the rectangle is found by multiplying the length by the width: 1 foot * 12 inches/feet = 12 square inches.

The shaded region is the area of the rectangle minus the area of the semicircles. So the area of the shaded region is 12 square inches - 2* pi square inches = 12 - 2* pi square inches.

It's important to note that the length of the shaded region is given in feet (1-foot) but the area of the semicircles and the rectangle is given in square inches.

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Answer:

men=150

women=250

total=400

Step-by-step explanation:

a) fraction of men

men/total=150/400=15/40

men/total =3/8

b)let married be x

so unmarried wil be 250-x

married/unmarried=3/2

x / 250-x =3/2

x =3(250-x)/2

2x =750-3x

5x=750

x=750/5

x =150

married =150

unmarried=250-150=100

c)20% of men will be :20x150

100

: 30

no of men =150+20%

=150+30

=180

d)no. of women decreased=250-60

=190

percentage of women leaved=% x 250

100

190x100/250=%

76 =%

76% women leaved

It took too much time

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