Answer:
A, B, C
Explanation:
If an electric motor uses 50 kJ of energy to do 46 kJ of work, how efficient is it?
Answer:
The efficiency of an electric motor can be calculated using the formula:
Efficiency = (Work output ÷ Energy input) x 100%
In this case, the motor uses 50 kJ of energy to do 46 kJ of work. Plugging in the values:
Efficiency = (46 kJ ÷ 50 kJ) x 100%
Efficiency = 0.92 x 100%
Efficiency = 92%
Therefore, the efficiency of the electric motor is 92%.
Explanation:
Answer: 92%
Explanation:
The efficiency of the electric motor is 92%. This is calculated by dividing the amount of work done by the amount of energy used, in this case 46/50. This gives 0.92, or 92%.
A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. Friction is not negligible.
A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. Weight (W), the normal force( N), and the tension force( T )in the string will all be forces operating on the box.
How does tension force work?The force transmitted through a rope, string, or wire while opposing forces pull it is referred to as the tension force.
Energy is drawn equally from both ends by the tension force, which is exerted along the entire length of the wire.
A box is being dragged across the floor at a constant speed by a horizontally pulling rope. Friction has a big impact.
As a result, the weight W, normal force N, and tension force T in the string will all be acting on the box.
Your question is incomplete but most probably your full question was
A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. identify all the forces acting on the box.
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If you place a paper clip very close to a magnet, the paper clip
A. is attracted to the magnet.
B. moves toward the magnet.
C. becomes a temporary magnet.
D. all of the above
what is the difference between copernicus and kepler description of planetary orbits?
Answer:
Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.
In which direction does the sun appear to move across the sky
Answer:east
Explanation:Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.
Answer:
it rises east and moves west through out the day and sets west
if the mass of an object doubles, the gravitational force between it and another object will double . if the distance between two objects doubles, the gravitational force between them will .
When the distance between two objects is doubled, the gravitational force between them is reduced by one-fourth.
Newton's law of gravitation states that an object attracts every other object in the universe with a force that is directly proportional to the product of their masses and inversely proportionate to their square distances from one other. This force may be thought of as gravitational attraction.
So, when we double the distance between the two objects then force will get reduced to one-fourth as according to newton's law of gravitation, force is inversely proportional to the square of the distance between them.
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A vector has a magnitude of 3.6 m and points in a direction that is 165 counterclockwise from the € axis_
A vector has both magnitude and direction. In the case of the given problem, the vector has a magnitude of 3.6 meters and points in a direction that is 165 degrees counterclockwise from the € axis.
Here, we need to calculate the x and y components of the vector. By definition of trigonometric functions, we know that the cosine of an angle is the ratio of the adjacent side and hypotenuse while the sine of an angle is the ratio of the opposite side and hypotenuse.
The vector points in a direction that is 165 degrees counterclockwise from the € axis. We know that the x-axis is the reference line for angles. Hence, we need to find the angle made by the vector with the x-axis. This angle will be 180° − 165° = 15°.Since the vector makes an angle of 15° with the x-axis.
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Modeling the motion of the fly on the web as a mass on a spring, at what frequency will the web vibrate when the fly hits it?
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An electron moves with a speed of 6.2×10 6m s −1 along the +x-axis. It enters a region where there is a magnetic field of 1.6 T, directed at an angle of 60∘to the +x-axis and lying in the xy-plane. (e=1.60×10 −19C,m e=9.11×10 −31 kg) Calculate the magnitude of the acceleration of the electron.
We get the value of acceleration a = (-1.60×10^-19 C)(6.2×10^6 m/s)(1.6 T)sin(60°) / (9.11×10^-31 kg)
To calculate the magnitude of the acceleration of the electron, we can use the equation:
F = qvBsinθ
Where:
F = magnetic force on the electron
q = charge of the electron = -1.60×10^-19 C (negative because the electron has a negative charge)
v = velocity of the electron = 6.2×10^6 m/s
B = magnetic field strength = 1.6 T
θ = angle between the velocity vector and the magnetic field vector = 60°
The magnitude of the acceleration can be obtained using Newton's second law:
F = ma
Since F = qvBsinθ, we can rewrite the equation as:
ma = qvBsinθ
Solving for acceleration (a):
a = (qvBsinθ) / m
Substituting the given values:
a = (-1.60×10^-19 C)(6.2×10^6 m/s)(1.6 T)sin(60°) / (9.11×10^-31 kg)
Calculating this expression will give you the magnitude of the acceleration of the electron.
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at what distance from a 2.45*10^-6 C charge will the electric field be 100 N/C?
Answer:14.8
Explanation:
Trust me
The distance will be = 14.85 m
What is electric field ?A region around a charged particle or object within which a force would be exerted on other charged particles or objects.
given :
Charge (q)= 2.45*\(10^{-6}\) C
Electric field (EF) = 100 N/C
to find = ? distance (r)
Electric field = 1/4π∈o * (q/\(r^{2}\))
100 = 9 * \(10^{9}\) * ( 2.45*\(10^{-6}\) / \(r^{2}\))
\(r^{2}\) = 220.5
r= \(\sqrt{220.5}\)
r = 14.85 m
The distance will be = 14.85 m
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diagram for terrestial weather
The correct answer of terrestial weather:
The solar insolation in the visible and infrared regions of the solar electromagnetic spectrum is much more than the energy that space weather occurrences release into the troposphere and stratosphere. Despite claims to the contrary, there may be some connection between the Earth's climate and the 11-year sunspot cycle. There is no proof of this. For instance, it has frequently been suggested that the Maunder minimum, a 70-year period almost devoid of sunspots, is correlated to a cooler climate, but these correlations have vanished after further research. Changes in cosmic ray flux are hypothesized to affect how much cloud formation occurs.
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which way would 2 negatively charged balloons naturally move? what would that do to the amount of potential energy stored in the field?
Answer:
gsg
Explanation:
The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.
What is force of repulsion?The basic principle of charges is that, two like charges repel and unlike charge attracts. That is: two negative charged bodies or two positively charged bodies will repel each other and one negative charged body attracts a positively charged body.
In both cases attraction or repulsion the charged particles exerts a force with each other called the electrostatic force. The electrostatic force between two charges is directly proportional to the magnitude of charges and inversely proportional to the distance between them.
The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.
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How does Newton's third law explain how a rocket is launched upward?
O A. As the fuel burns, the rocket's mass decreases, allowing it to fly
faster and faster.
O B. Gases from burning fuel are pushed out of the bottom of the
rocket, and these gases push back on the rocket with an equal
amount of force.
C. When the rocket's speed increases, the amount of force needed to
move it decreases.
D. As the rocket accelerates upward, the air resistance pushing
against the rocket decreases.
Answer: Hi guys! The answer is B.
Explanation:
Got it right on Apex! :)
Chicago, il is currently in the e climate zone.
a) true
b) false
Answer:
false
Explanation:
A concave mirror forms image of an object thrice in its size on a screen magnification of a mirror gives information about the size of the image relative to the object it is defined as the ratio of size of image to the size of object it is represented by m m size of object size of image =magnification by mirror gives the information about the nature of the image produced by it.
Describe the nature of image formed 2nd if the object X distance from the pole of mirror then find image distance from the pole 3rd if the radius of curvature of mirror is are then write the relation between object distance image distance and focal length of the mirror give one use of concave mirror
The description of the nature of image formed 2nd if the object X distance from the pole of mirror then find image distance from the pole 3rd if the radius of curvature of mirror is are then write the relation between object distance image distance and focal length of the mirror give one use of concave mirror is given below
What is the description of the nature of image formed?A concave mirror is a mirror with a curved, inwardly facing surface. When an object is placed in front of a concave mirror, the mirror will form an image of the object. The nature of the image formed depends on the position of the object relative to the mirror.
If the object is placed at a distance greater than the focal length of the mirror, the image formed will be smaller than the object and will be located behind the mirror. This type of image is known as a virtual image.If the object is placed at a distance less than the focal length of the mirror, the image formed will be larger than the object and will be located in front of the mirror. This type of image is known as a real image.To find the image distance from the pole of the mirror, you can use the mirror equation:
1/image distance + 1/object distance
= 1/focal length.
If the object is X distance from the pole of the mirror, you can substitute this value for the object distance in the mirror equation to find the image distance.
The relationship between the object distance, image distance, and focal length of a concave mirror can be expressed using the mirror equation:
1/image distance + 1/object distance
= 1/focal length.
This equation tells us that the sum of the reciprocals of the object distance and image distance is equal to the reciprocal of the focal length.
Therefore, One use of a concave mirror is as a reflector in a flashlight or car headlight. The concave mirror focuses the light to a point in front of the mirror, creating a bright beam of light that can be directed at a specific location.
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On your desk, repeat the hand twist for the low and high pressure system models. Note the vertical motions of the palm of your hand. For the Low, the palm of your hand _____ during the rotating motion.
On your desk, to repeat the hand twist for the low and high pressure system models, you need to rotate your hand in a circular motion. During this rotating motion, the palm of your hand moves downwards for the low-pressure system model.
To demonstrate the hand twist for low and high pressure system models on your desk, follow these steps:
1. Place your right hand flat on the desk with your palm facing down for the high pressure system model. This represents a high pressure system in the Northern Hemisphere, which has a clockwise rotating motion.
2. Slowly rotate your hand clockwise while keeping it flat on the desk. Note that the palm of your hand does not have any vertical motion during this process.
3. Now, place your left hand flat on the desk with your palm facing down for the low pressure system model. This represents a low pressure system in the Northern Hemisphere, which has a counterclockwise rotating motion.
4. Slowly rotate your left hand counterclockwise while keeping it flat on the desk. Observe the vertical motion of your palm during this process.
For the low pressure system model, the palm of your hand remains flat during the rotating motion. There is no significant vertical motion observed in this demonstration.
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An NFL wide receiver prospect runs 40 m in 4.5 seconds. What is the average speed of the wide receiver (m/s)?
Answer:
8.89 m/s
Explanation:
rate = distance/time
40m/4.5 sec = 8.8888889 m/s
billy bob joe's truck has a mass of 3,800 g and an acceleration of 4.5 m/s^2. what is the force of the truck? (you will have to convert your grams first)
Answer:
17.1 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
3800 g = 3.8 kg
We have
force = 3.8 × 4.5
We have the final answer as
17.1 NHope this helps you
The image of the "infinitely-far-away" sun produced by a converging lens appears
A) between the lens and the focal point.
B) at the focal point.
C) beyond the focal point.
The correct answer is beyond the focal point (Option C). When a converging lens is used to view the sun, the image of the sun that is produced appears beyond the focal point.
This is because the converging lens takes the parallel rays of light that are coming from the sun and causes them to converge at a single point, which is known as the focal point. However, if the object being viewed is located at a distance that is greater than the focal length of the lens, then the image that is produced will be magnified and inverted and will appear beyond the focal point.
In the case of the sun, it is located at an infinite distance from the lens, which means that the parallel rays of light that are coming from the sun will be focused by the lens at the focal point. However, since the sun is located at an infinite distance, the image that is produced will be magnified and inverted, and will appear beyond the focal point.
It is important to note that the position of the image will depend on the distance between the lens and the object being viewed. If the object is located between the lens and the focal point, then the image will appear to be larger and will be located on the same side of the lens as the object. If the object is located beyond the focal point, then the image will appear to be smaller and will be located on the opposite side of the lens from the object.
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A car is moving along a straight test track. The position (in feet) of the car, \( s(t) \), at various times \( t \) is measured, with the results shown to the right. Use the table to answer parts (a)"
The car is at rest at \( t = 0 \) seconds, and it reaches a position of 80 feet at \( t = 4 \) seconds.
According to the given table, the position of the car at various times is measured. At \( t = 0 \) seconds, the car is at rest, as indicated by the position of 0 feet. This means that the car has not started moving yet.
As time progresses, we observe that the position of the car increases. For example, at \( t = 2 \) seconds, the car has moved to a position of 40 feet. This indicates that the car is covering a certain distance during each time interval.
At \( t = 4 \) seconds, we see that the car reaches a position of 80 feet. This means that in the time span of 4 seconds, the car has covered a distance of 80 feet.
The given information allows us to understand the relationship between time and position of the car. By analyzing the changes in position over time, we can determine the speed or velocity of the car at different instances.
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If the air bags are not in proper operating condition, Select one: a. the vehicle will come to an immediate stop. b. the warning light will stay on. c. a bell will sound. d. push the Reset button to correct the problem.
If the air bags are not in proper operating condition, the warning light will stay on.
It is important to have the air bags checked and repaired by a qualified mechanic to ensure they are functioning properly in the event of an accident. Driving with malfunctioning air bags can be dangerous and increase the risk of injury in a collision.
Some of the common causes of the airbag warning light are:
Faulty sensors: The sensors are devices that monitor various parameters of your car and tell the computer when to inflate the airbags. If the sensors are damaged, malfunctioning, or tripped accidentally, they can trigger the warning light.
Wet airbag module: The airbag module is an electronic device that controls the airbag system. It is usually located under the seat or behind the dashboard. If the module gets wet due to flooding, spills, or moisture, it can cause corrosion or short circuits that can activate the warning light.
Worn out airbag clock springs: The airbag clock springs are spiral wires that connect the driver’s airbag on the steering wheel to the electrical system. They allow the steering wheel to rotate while maintaining contact with the airbag. Over time, these wires can wear out or break and cause a loss of communication between the airbag and the computer.
Deactivated airbag: The airbag can be deactivated due to a fault in the airbag itself or in any of its components, such as the inflator, wiring, or connector. This can happen due to age, wear and tear, impact, or tampering.
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The linear impulse delivered by the hit of a boxer is 236 N · s during the 0.128 s of contact. What is the magnitude of the average force exerted on the glove by the other boxer?
The magnitude of the average force exerted on the glove by the other boxer is approximately 1844 N .
When a boxer delivers a punch, it imparts a linear impulse to the target.
The magnitude of the impulse is equal to the change in momentum of the target.
The duration of contact between the boxer's fist and the target determines the average force exerted on the target.
In this problem, the linear impulse delivered by the hit of a boxer is 236 N·s, and the contact time is 0.128 s.
To find the average force exerted on the glove by the other boxer, we can use the definition of impulse:
Impulse = Force x Time
Rearranging this formula, we get:
Force = Impulse / Time
Substituting the given values, we have:
Force = 236 N·s / 0.128 s = 1843.75 N
Therefore, the magnitude of the average force exerted on the glove by the other boxer is approximately 1844 N.
It is important to note that this calculation assumes that the contact force is constant during the entire duration of contact, which may not be the case in reality.
In addition, the force experienced by the target may vary depending on the angle and location of the punch.
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An astronaut landed on the moon. He decided to test Newton's Laws of Motion by playing golf on the moon.
The golf ball was hit. The ball traveled much farther on the moon than a golf ball that is hit with the same force on the Earth. Which statement BEST explains this phenomenon?
Select TWO correct answers.
The unbalanced force of friction from Earth's atmosphere slows the ball down, causing the ball not to travel as far.
The moon's gravitational pull is greater than the pull of the Earth, causing the ball to travel farther.
The ball's inertia is greater on the moon because of the space, causing it to travel farther.
The mass of the ball is the same on the Earth and the moon, so the ball will travel farther on the moon.
The moon's gravitational pull is not as strong as the Earth's gravitation pull, causing the ball to travel a greater distance.
Here are the two claims: Because of the moon's weaker gravity, the ball has a higher inertia and moves farther. As the moon has no atmosphere, there is no air resistance to cause the ball to slow down.
What happens if a golf ball is struck on the moon?The ball would fly six times further and land about 2 km (or 1.25 miles) further on the moon, where the gravity acceleration is six times smaller. A professional golfer could hit a drive on the moon this far if they had the right equipment.
On the moon, did astronauts play golf?On the moon, Alan Shepard of Apollo 14 played golf. He held a contingency sample extension handle with a no. 6 iron head in his hand as his "club." For personal things, each astronaut was given a set amount of weight. Shepard took the club head and three golf balls with his.
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Two charged balloons, one black and one red, are separated by some distance r. The black balloon has 5 times the charge of the red balloon The black balloon exerts a force of F black-red on the red balloon, and the red balloon exerts a force of F red-black on the black balloon. How does the magnitude of F black-red compare to F red-black?
The magnitude of F black-red compared to F red-black 5 times greater.
Gravitational force problemThe force exerted between two charged objects is given by Coulomb's law:
F = k * (q1 * q2) / r^2
where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two objects, and r is the distance between them.Let's denote the charge on the red balloon as q_red and the charge on the black balloon as q_black. Since the black balloon has 5 times the charge of the red balloon, we can write:
q_black = 5 * q_red
Now let's consider the force exerted by the black balloon on the red balloon. According to Coulomb's law, this force is given by:
F_black-red = k * (q_black * q_red) / r^2
Substituting q_black = 5 * q_red, we get:
F_black-red = k * (5 * q_red * q_red) / r^2
Simplifying this expression, we get:
F_black-red = 5 * (k * q_red^2) / r^2
Similarly, the force exerted by the red balloon on the black balloon is given by:
F_red-black = k * (q_red * q_black) / r^2
Substituting q_black = 5 * q_red, we get:
F_red-black = k * (q_red * 5 * q_red) / r^2
Simplifying this expression, we get:
F_red-black = 5 * (k * q_red^2) / r^2
Comparing the two expressions, we can see that:
F_black-red = 5 * F_red-black
Therefore, the magnitude of the force exerted by the black balloon on the red balloon is 5 times greater than the magnitude of the force exerted by the red balloon on the black balloon.
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an object has the mass of 42g on earth, what is its mass on the moon
Answer: 42g
Mass will still stay the same because mass is a weight without pull of gravitational force. So whichever plant it is in, even in jupiter, the mass is going to be 42g.
at the instance a current of 0.25 a is flowing through a coil of wire, the energy stored in its magnetic field is 6 mj. what is the self-inductance of the coil? hint the self-inductance of the coil is mh.
The self inductance of the coil is 200 m H.
So given,
Current(I) = 0.25 A
energy stored (E) = 6mJ
E= 6×10^3 J
Self Inductance (L) = ?
We know that, E =1/2 L I^2
L= 2E/ I^2
= 2 (6×10^3)/ 0.25^2
=12× 10^3 / 0.06
= 200 ×10^3 H
= 200 m H .
Self-inductance is the property of the current-carrying coil that resists or opposes the exchange of current flowing through it. This happens in particular because of the self-induced emf produced in the coil itself. In easy terms, we can also say that self-inductance is a phenomenon in which there may be the induction of a voltage in a current-carrying wire.
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The self-inductance of the coil when a current of 0.25 a is flowing through a coil of wire is 96 mH
To find the self-inductance of the coil, you will need to use the equation for the energy stored in a magnetic field:
E = (1/2) * L * i^2
Where E is the energy stored in the magnetic field, L is the self-inductance of the coil, and i is the current flowing through the coil.
In this case, the energy stored in the magnetic field (E) is given as 6 mJ, and the current flowing through the coil (i) is given as 0.25 A. Solving for the self-inductance (L) of the coil:
L = 2 * E / i^2
L = 2 * 6 mJ / (0.25 A)^2
L = 96 mH
Therefore, the self-inductance of the coil is approximately 96 mH.
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Which statement best describes what happens during a solar eclipse?
A. The Sun casts a shadow directly on Earth and the Moon.
B. Earth passes directly between the Sun and the Moon.
C. The Moon passes directly between Earth and the Sun.
D. Earth casts a shadow directly on the Sun and the Moon.
Answer: A.
Explanation:
Solar eclipse happens when Sun casts a shadow directly on Earth and the Moon. Option A is correct.
What is solar eclipse?A solar eclipse occurs when the Sun throws a shadow directly on Earth and the Moon.
When the Sun throws a shadow directly on the Earth and the Moon, it is called a solar eclipse.
Hence,option A is correct.
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What accommodations can be made for people with impaired vision?
Plot vector R 50m at an angle of 28 degrees wrtto the positive x axis. Find the x and y components of the vector and write it in vector form. What kind of vector is R?
The x and y-components of the vector R is 44.15i + 23.47j.
The given parameters:
Magnitude of vector R = 50 mPosition of vector R = 28 degreesWhat is component vectors?This is the representation of vectors in x and y-coordinates.The x and y-components of the vector R is calculated as follows;
\(R_x = R \times cos(\theta)\\\\R_y = R \times sin(\theta)\\\\R_x = 50 \times cos(28) = 44.15 \ i\\\\R_y = 50 \times sin(28) = 23.47 \ j\)
R is a unit vector.
The plot of vector R is in the image uploaded.
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Colle's fracture occurs when the radial styloid process breaks as a skateboarder hits the concrete with outstretched arms to stop their fall. True False
Colle's fracture is an injury that occurs when a person falls and lands on an outstretched hand. The fracture affects the radius, one of the bones that makes up the forearm. The radial styloid process is the end of the radius bone closest to the thumb. It helps to keep the wrist stable when the hand moves.
This fracture is also known as a distal radius fracture or wrist fracture.A skateboarder, who hits the concrete with outstretched arms to stop their fall can break the radial styloid process resulting in Colle's fracture. Therefore, the given statement is true. Here is a detailed explanation for the same:Colles' fracture is a type of wrist fracture. It occurs when the bone that connects the wrist to the thumb (the radius) breaks and moves toward the back of the wrist. Colles' fracture usually occurs when a person falls and lands on an outstretched hand. It is also common in older adults with osteoporosis, a condition that weakens the bones. In the case of a skateboarder, who hits the concrete with outstretched arms to stop their fall can break the radial styloid process. This will result in a Colle's fracture. In addition, Colles' fracture may be classified as:Extra-articular, which means the fracture does not extend into the wrist joint. This type of fracture is more common.Intra-articular, which means the fracture extends into the wrist joint. This type of fracture is less common but is more severe.
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