PLEASE HELP!
What metal can be shaped using just your hands

A.gold
B.aluminum
C.silver
D.platinum

Answer: Coefficient 0

subscript for V 2

subscript for O 5

Explanation: yes

There is no coefficient in V₂O₅ and the subscript of vanadium V is 2 and the subscript of oxygen is 5.

Vanadium pentoxide is an ionic compound formed by donating electrons from the vanadium metal to oxygen.  The chemical formula of vanadium pentoxide is V₂O₅.

The chemical formula of a compound is written in terms of the chemical symbol of each constituent elements and the number of their atoms. The number of atoms is written as subscript for the chemical symbols.

In V₂O₅, there are are 2 vanadium atoms and 5 oxygen atoms. Coefficients are numbers prior to the formula in reaction. Here there is no coefficient and the subscript for V is 2 and that of O is 5.

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Answer:

45 m/s north

Explanation:

Edge 2020

Answer: (B) 45 m/s north

Explanation: right on edge 2020 (so basically the same reason as person above)

Answer:

The molar mass of sulfuric acid (H2SO4) can be calculated by adding the atomic masses of its constituent atoms:

Molar mass of H2SO4 = 2(1.008 g/mol) + 1(32.06 g/mol) + 4(15.99 g/mol) = 98.08 g/mol

Therefore, the mass of 2.25 moles of H2SO4 is:

mass = number of moles x molar mass

mass = 2.25 moles x 98.08 g/mol = 220.68 g

So, the mass of 2.25 moles of sulfuric acid is 220.68 grams.

Answer:

Explanation:

Just saw your request regarding answering this so here it is:

All of them belong of Group 1 in periodic table and thus are highly reactive! Pattern of reactivity for Group 1 (Alkali metals) increases as you move down the group as their radius keeps increasing and thus electrons can be easily lost. Thus, to ID the lumps, Sheena should look at their reactivity and she should get the following trend:

Most reactive: Potassium (K)

Intermediate: Sodium (Na)

Least reactive: Lithium (Li)

Hope it helps!

a)CH3-CH2-CH2-CH=CH2

b)CH3-CH2-CH2-CH2-CH2-CH2-CH3

c)CH≡C-CH2-CH2-CH2-CH3

d)CH3-CH2-CH2-CH2-CH2-CH2-CH=CH2

e)CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2-CH3

give me brain list

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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Answer:

Explanation:

1. 546.0ml x \(\frac{L}{1000mL}\)= 0.5460L

2. 86.0kg x \(\frac{1000g}{1 kg}\)= 8.60x\(10^{4\) g

3. 2.56 pound x \(\frac{16 ounces}{1 pound}\)= 40.1 ounces

4. 75.3 pound x \(\frac{453.6 g}{1 pound}\) = 45200 g

5. 12.5 yard x \(\frac{91.44 cm}{1 yard}\) = 1140 cm

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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Answer:

The more you get closer to a substance in the periodic table things that are included into the substance start to get bigger

Explanation:

Answer: D) Eight

Just pretend this part doesn't exist nope nothing to see here the answer is correct on edge2020 I swear on my brainly points

Answer:

d

Explanation:

The half-life of a reaction is the time it takes for the concentration of a reactant to decrease to half its initial value. In a first-order reaction, the rate of the reaction is directly proportional to the concentration of the reactant. This means that the rate of the reaction depends on the concentration of compound A.

To calculate the half-life of compound A, you can use the equation:

half-life = (ln(2)) / k

where k is the rate constant for the reaction.

Plugging in the values given in the question, we get:

half-life = (ln(2)) / 0.45

This simplifies to:

half-life = 1.44 / 0.45

Which gives us a final result of:

half-life = 3.2 hours

So the half-life of compound A at 250°C is approximately 3.2 hours.

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Answer:

2.10 moles of O₂

Explanation:

2 H₂O₂ (l) → 2H₂O(l)  + O₂(g)

In this reaction we say, that 2 moles of hydrogen peroxide can decompose to 2 moles of water and 1 mol of oyxgen.

So ratio is 2:1, according to stoichiometry.

If we apply a rule of three;

2 moles of hydrogen peroxide can decompose to 1 mol of oxygen

Then 4.20 moles of hydrogen peroxide may produced (4.20 . 1)/2 =

2.10 moles of O₂

Answer:

The answer is B.

Explanation:

Answer:

\(k_1=0.107s^{-1} \\\\k_2=0.711M^{-1}s^{-1}\)

Explanation:

Hello there!

In this case, according to the given information and the attached picture in which we can see the units of the rate constant, it turns out possible for us to realize the two called rate laws are:

\(r=k[A]\\\\r=k[A]^2\)

The former is first-order and the latter second-order; in such a way, we solve for the rate constant in both cases to obtain the following:

\(k=\frac{r}{[A]}=\frac{1.6x10^{-2}M/s}{0.15M}=0.107s^{-1} \\\\k=\frac{r}{[A]^2}=\frac{1.6x10^{-2}M/s}{(0.15M)^2}=0.711M^{-1}s^{-1}\)

Regards!

Answer:

translational, rotational, and oscillatory.

Explanation:

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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This is due to the fact that a substance's chemical qualities, such as its molecular form, polarity, and functional groups, govern how it behaves and interacts with other substances.

By illustrating the spatial arrangement of atoms and chemical bonds within the molecule, chemical structure establishes the molecular geometry of a compound. In doing so, chemists are given a crucial visual depiction of a chemical formula.

In a chemical reaction, reactants come into contact with one another, atoms in the reactants break their connections with one another, and then the atoms reorganise and form new bonds to create the products.

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Answer:

0.2257kg

Explanation:

Using the formula density= mass/ volume

22.57g/cm³=mass/10cm³

mass = 22.57g/cm³*10cm

=225.7g

but in kg

= 0.2257kg

Answer:

1. Density can be used to identify a substance

2. Density can be used to ascertain whether a substance will float in water.

Explanation:

The calculation of the density of a substance can be used to identify the substance. If the density of a substance is calculated accurately, and compared with a table of standard densities, then we can identify that substance.

Also, density determines whether an object will float or sink in water. If an object is less dense than water then it will float in water. If it is denser than water, then it will sink in water.

Answer:

mass NH₃ produced = 72.9g (3 sig. figs.)

Explanation:

                 3H₂      +      N₂                =>       2NH₃

given      excess           60.1g                    (?)grams

moles =>                      (60.1g/28g/mol)

                                     = 2.15mole    =>     2(2.15mole)

                                                                     = 4.29mole NH₃

mass NH₃ = 4.29moles x 17 g/mole = 72.9grams NH₃

Always convert given data into moles, solve in terms of moles and convert to needed dimension from mole yields. :-)

Answer:

73.07 grams of ammonia is produced.

Explanation:

In order to find the grams of ammonia produced, we need to find the amount of the reactants so that we know how much product (ammonia) the reactants (Hydrogen and Nitrogen) can and will produce.

First, we need to use the balanced equation to find the amount of moles equivalent to the 60.1 grams of Nitrogen that reacts.

To convert from Grams to Moles, we will divide by the molar mass (amu)..

60.1 grams of N2 /  2(14.01) grams  N2 = 2.144896502 moles of N2.

So, we know that 60.1 grams of N2 equals 2.144896502 moles.

       Now, we will look at the balanced equation and convert from moles of N2 to moles of NH3 in order to later find the grams of NH3 (ammonia) produced..

2.144896502 moles N2 *  2 moles NH3/1 mol N2 = 4.289793004 moles NH3.

     Now that we know the amount of moles produced of ammonia, we will convert to grams. We can do this by multiplying by the molar mass of ammonia which is 17.034 (N = 14.01, H = 1.008, ---> 14.01 +3(1.008) = 17.034)

4.289793004 moles NH3 * 17.034/1 mol = 73.07233403 grams NH3

This can be estimated to 73.07 grams of NH3 (ammonia) produced.

If you are still confused on how to convert between moles and grams, please see the uploaded image.

Answer:

3) 310 g/mol

Explanation:

Hello,

In this case, for calcium carbonate, we are able to compute its gram-formula mass by considering the atomic mass of each element composing it and their subscripts as shown below:

\(M=3*m_{Ca}+2*m_P+4*2*m_O\\\)

Thus, we compute:

\(M=3*40g/mol+2*31g/mol+4*2*16g/mol\\\\M=310g/mol\)

Hence answer is 3) 310 g/mol . Remember this is also known as the molar mass of the mentioned compound.

Best regards.

There is a double bond between the carbon atoms and a lone pair on oxygen.

The term Lewis structure has to do with the structure that shows the arrangement of atoms in a compound. It is normal that the structure would be composed of the symbols of the elements and the bonds that they form as dots or sometimes as a single line to show shared electrons.

Now we can see that the compound C2H2O is a compound that contains a double bond between the carbon atoms. There is a lone pair of electron that resides on the oxygen atom. The structure of this compound is shown in the image attached.

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Answer:HNO3 + NaOH = NaNO3 + H2O is a neutralization reaction (also a double displacement reaction). The strong acid (HNO3) and strong base react to produce a salt (NaNO3) and water (H2O).Type of Chemical Reaction: For this reaction we have a neutralization reaction. Balancing Strategies: Here is a neutralization reaction. The HNO3 and NaOH combined and form a salt and water.

hope this helps have a nice night ❤️

Explanation:

You would use 300.0125 g of CaCl2 and 623.2875 g of water to create a 923.3 g solution that contains a 32.5% (m/m) concentration of CaCl2.

We must first determine the mass of the solute (CaCl2) and the mass of the solvent (water) in order to calculate the mass of CaCl2 required to create a solution with a particular percentage (m/m) concentration.

Given: The solution's total mass is 923.3 g, and CaCl2's percentage (m/m) is 32.5%

The mass of CaCl2 in the solution is first calculated as follows:

CaCl2 mass is (300.0125 g) = (32.5 / 100) x 923.3 g.

Next, we determine how much water there is in the solution:

Water mass is equal to the sum of the solution's mass and CaCl2 mass.

923.3 g - 300.0125 g = 623.2875 g is the mass of water.

Therefore, you would use 300.0125 g of CaCl2 and 623.2875 g of water to create a 923.3 g solution that contains a 32.5% (m/m) concentration of CaCl2.

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Answer:

1.44 g

Explanation:

1. get number of nitrogen atoms in 9.79 grams of nitrogen

1 mole of Nitrogen is 6.022 x 10^23 atoms N which is = 14.01g N

2.

if 6.022 x 10^23 atoms of Nitrogen is 14

then x atoms  of Nitrogen is 9.79

3.

6.022 x 10^23/ x = 14/9.79 ->

x = 8.431 x 10^24 / 9.79 =

8.61799714478 x 10^23

4.

8.61799714478 x 10^23 atoms of N

6.022 x 1023 atoms of H have a mass of 1.008g, so

8.61799714478 x 10^23 atoms of H have a mass of (1.008/6.022 x 1023) x 8.61799714478 x 10^23) = 1.44250051072175g

1.44 g

yeahchemistrycom

Answer:

0.00000000910938;

9.109380 * 10^-9

Explanation:

Given the question :

Given :

1.602176*10-¹⁹/ 1.758820*10¹¹

The numbers are expressed in the form:

A * 10^b ; Where;

A = Coefficient ; 10 = base ; b = exponent

The Coefficients can be divided directly as :

1.602176 / 1.758820 = 0.9109380

Using the division law of indices, the exponents acn be worked out as follows since they have the same base :

10^-19 / 10^-11 = 10^(-19 - (-11)) = 10^(-19+11) = 10^-8

Thus, we have ;

0.9109380 × 10^-8

In standard form:

9.109380 * 10^-9

In Expanded form:

10^-8 = 0.00000001

0.9109380 * 0.00000001 = 0.00000000910938

0.000000009 +

0.0000000001 +

0.00000000000 +

0.000000000009 +

0.0000000000003 +

0.00000000000008

__________________

0.00000000910938

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