PLEASE HELP
Evaluate 6 + 10v – 8w when v=4 & w= -2

Let u = tan⁻¹x, then du/dx = 1/(1+x²).

Using the formula for the derivative of inverse tangent, we have:

tan(u) = x

sec²(u) du/dx = 1

du/dx = cos²(u)

Substituting into the original expression, we get:

∫(tan⁻¹x × e^tan⁻¹x)/(1+x²) dx = ∫(tan⁻¹x × e^u × cos²(u)) du

Using integration by parts with u = tan⁻¹x and dv = e^u × cos²(u) du, we get:

v = (1/2) e^u (sin(u) + u cos(u))

∫(tan⁻¹x × e^u × cos²(u)) du = (1/2) e^u (sin(u) + u cos(u)) tan⁻¹x - ∫[(sin(u) + u cos(u)) / (1+x²)] dx

Substituting back u = tan⁻¹x, we get:

∫(tan⁻¹x × e^tan⁻¹x × cos²(tan⁻¹x)) dx = (1/2) e^tan⁻¹x (x sin(tan⁻¹x) + cos(tan⁻¹x)) tan⁻¹x - ∫[(x cos(tan⁻¹x) + sin(tan⁻¹x)) / (1+x²)] dx

Using the identity sin(tan⁻¹x) = x / √(1+x²) and cos(tan⁻¹x) = 1 / √(1+x²), we simplify the expression to:

∫(tan⁻¹x × e^tan⁻¹x × cos²(tan⁻¹x)) dx = (1/2) x e^tan⁻¹x + (1/2) ∫[e^tan⁻¹x / (1+x²)] dx

The remaining integral can be solved using another substitution with v = tan⁻¹x, which results in:

∫(tan⁻¹x × e^tan⁻¹x × cos²(tan⁻¹x)) dx = (1/2) x e^tan⁻¹x + (1/2) ln(1+x²) + C, where C is the constant of integration

Answer:

\( \boxed{\bold{\boxed{ \sf{1 \: , \: 2 \: , \: 3\: ,4 \: , \: 5 \: , \: 6 \: , \: 8 \: , \: 10 \: }}}}\)

Option D is the correct option

Step-by-step explanation:

Let the sets be A and B.

A = { 1 , 2 , 3 , 4 , 5 }

B = { 2 , 4 , 6 , 8 , 10 }

Finding A union B ( A ∪ B )

The union of sets A and B is the set of all elements which belongs either A or B or both A and B

So, list them :

A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 8 , 10 }

Hope I helped!

Best regards! :D

Answer:

4 pages

Step-by-step explanation:

Because he wrote 20 pages per hour, you would have to divide 20 by the amout of hours he wrote, which is 5. 20 divided by 5 is 4, so he wrote 4 pages per hour. Need to double check? Multiply 4 by 5. That gives you 20 pages in 5 hours.              

Answer:

Yup P is the right one having 62.26%

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

We can set it up as

P = 33/53

Q = 20/48

R = 54/90

S = 44/83

This is because we are calculating the percent of yellow birds in the total amt. of birds in a specified park.

Now we calculate =>

P = 33/53 = around 0.62

Q = 20/48 = around 0.416

R = 54/90 = 0.6

S = 44/83 = around 0.53

We find that Park P has the greatest percentage and -->

Thus, Park P is our answer and yes, you are correct.

Answer:

4 1/2 x 1/2

9/2 x 1/2 = 9/4

9/4 = 2 1/4

Step-by-step explanation:

The probability that either event will occur is P ( C ) = 0.89

Given data ,

Let the probability that either event will occur  be P ( C )

P ( A ) = 20/36

P ( B ) = 12/36

where P ( A or B ) = P ( C )

P ( C ) = P ( A ) + P ( B )

P ( C ) = 32/36

P ( C ) = 0.88888

Hence , the probability is P ( C ) = 0.89

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After calculating we found that: a) 95% of widget weights lie between 42 and 54 ounces.b) 97.35% of widget weights lie between 39 and 54 ounces and c) 0.3% of widget weights lie above 45 ounces.

a) Since the distribution is bell-shaped and the mean is 48 ounces with a standard deviation of 3 ounces, we can use the 68-95-99.7 Rule to determine that 68% of the widget weights lie within one standard deviation of the mean, 95% lie within two standard deviations of the mean, and 99.7% lie within three standard deviations of the mean. Thus, we know that 95% of the widget weights lie between:

48 - 2(3) = 42 ounces and 48 + 2(3) = 54 ounces.

b) To find the percentage of widget weights that lie between 39 and 54 ounces, we need to determine how many standard deviations away from the mean these values are.

39 ounces is 9 ounces below the mean, so it is (9/3) = 3 standard deviations below the mean.

54 ounces is 6 ounces above the mean, so it is (6/3) = 2 standard deviations above the mean.

Using the 68-95-99.7 Rule, we know that 99.7% of the widget weights lie within three standard deviations of the mean. Since 39 ounces is three standard deviations below the mean, we can conclude that 0.15% (or 0.003 x 100) of the widget weights lie below 39 ounces.

Likewise, since 54 ounces is two standard deviations above the mean, we know that 2.5% of the widget weights lie above 54 ounces. Thus, the percentage of widget weights that lie between 39 and 54 ounces is:

100% - 0.15% - 2.5% = 97.35%

c) We need to find the percentage of widget weights that lie above 45 ounces. Since 45 ounces is three standard deviations below the mean, we know that 99.7% of the widget weights lie above 45 ounces. Therefore, the percentage of widget weights that lie above 45 ounces is:

100% - 99.7% = 0.3%.

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Answer:

B).

Step-by-step explanation:

Add 8 to half the difference of 6 and 2 then subtract 1.

Answer:

I apologize but I haven't worked for an answer. but my mind is, what is the point of this question? everyone is familiar with the "when am I ever going to use this in life and why do I need to learn this?" but this is a whole new level of w t f.

Answer:

-30

Step-by-step explanation:

focus on 5² · 2.

⇒ 5² = 5·5.

⇒ 5·5 = 25.

So, your answer is -30.

Check the picture below.

The rate at which the energy pass through an area of 1.0 m² at 2.0 km is equal to 1.97 × 10⁹ J/s.

At a constant power, the intensity of a wave is inversely proportional to the distance from the source. Mathematically, the intensity of a wave with respect to the distance from a source can be modeled (represented) by this mathematical expression;

I ∝ 1/r²

Where:

Next, we would re-write the mathematical expression and then determine the intensity of a wave from source as follows;

I₁/I₂ = r₂²/r₁²

I₁ = I₂(r₂²/r₁²)

Note: We know that its intensity when it passed a point from the source is 2.0 km.

Substituting the given parameters into the formula, we have;

I₁ = 2.8 × 10⁶ × (53²/2²)

I₁ = 1.97 × 10⁹ J/m²s.

Now, we can calculate the rate of the energy by using this formula;

Power = intensity × area

Power = 1.97 × 10⁹ × 1.0

Power = 1.97 × 10⁹ J/s.

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Answer: 7: 29 stickers for each friend

8: 412 seats in each section

Step-by-step explanation:

We will have to divide 145 (stickers) by 5 (friends) to get 29

We will have to divide 2472 by 6 to get 412

7.) 145 ÷ 5 = 29 → Each friend will get 29 stickers

8.) 2,472 ÷ 6 = 412 → There are 412 seats in each second.

I divided for both problems using the long division method and multiplied which is the inverse operation, to check my work.

Answer:

98

Step-by-step explanation:

x(o) + 1(o)  = 180(o)

∠2° = ∠x°

∠1° = ∠3°

Answer:

angle 2 is 82 also and angle 3 and 4 is 180 - 82 = 98

Answer:

7250%

Step-by-step explanation:

To express 72 1/2 as a percentage, you need to convert it to a decimal first and then multiply by 100.

72 1/2 is equivalent to 72.5 as a decimal.

To convert it to a percentage:

72.5 * 100 = 7250

Therefore, 72 1/2 is equal to 7250% when expressed as a percentage.

let me know it is helpful for you or not

The quotient of z₁ by z₂ in trigonometric form is:

7/21 * (cos(584°) + i sin(584°))

To find the quotient of z₁ by z₂ in trigonometric form, we'll express both complex numbers in trigonometric form and then divide them.

Let's represent z₁ in trigonometric form as z₁ = r₁(cosθ₁ + isinθ₁), where r₁ is the magnitude of z₁ and θ₁ is the argument of z₁.

We have:

z₁ = 7(cos(577°) + i sin(577°))

Now, let's represent z₂ in trigonometric form as z₂ = r₂(cosθ₂ + isinθ₂), where r₂ is the magnitude of z₂ and θ₂ is the argument of z₂.

From the given information, we have:

z₂ = 21(cos(-7°) + i sin(-77°))

To find the quotient, we divide z₁ by z₂:

z₁ / z₂ = (r₁/r₂) * [cos(θ₁ - θ₂) + i sin(θ₁ - θ₂)]

Substituting the given values, we have:

z₁ / z₂ = (7/21) * [cos(577° - (-7°)) + i sin(577° - (-7°))]

= (7/21) * [cos(584°) + i sin(584°)]

The quotient of z₁ by z₂ in trigonometric form is:

7/21 * (cos(584°) + i sin(584°))

Option C, 21(cos(-7°) + i sin(-77°)), is not the correct answer as it does not represent the quotient of z₁ by z₂.

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Answer:

100 seconds

Step-by-step explanation:

200/2 = 100s

Answer:D

Step-by-step explanation:

I got you!

Answer:

7,722

Step-by-step explanation:

You would need to multiply the 4 numbers above together to get the final number.  That is basically it.

I would recommend you to write on a paper for smaller numbers and writing each combination for the choices.

The amount of money in Marianna's annuity after 6 years will be approximately $300,516.

To calculate the amount of money in Marianna's annuity after 6 years, we can use the formula for compound interest on an annuity:

A = P * ((1 + r/n)^(n*t) - 1) / (r/n)

Where:

A = the final amount in the annuity

P = the regular contribution (each quarter) = $10,000

r = annual interest rate = 8% = 0.08

n = number of compounding periods per year = 4 (since it's compounded quarterly)

t = number of years = 6

Plugging in the values:

A = 10000 * ((1 + 0.08/4)^(4*6) - 1) / (0.08/4)

Calculating this expression:

A ≈ 10000 * ((1.02)^24 - 1) / 0.02

A ≈ 10000 * (1.601032449136241 - 1) / 0.02

A ≈ 10000 * 0.601032449136241 / 0.02

A ≈ 10000 * 30.05162245681205

A ≈ 300,516.22

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Answer:

304200

Step-by-step explanation:

To find the value of P6, use the savings annuity formula

PN=d((1+r/k)N k−1)r/k.

From the question, we know that r=0.08, d=$10,000, k=4 compounding periods per year, and N=6 years. Substitute these values into the formula gives

P6=$10,000 ((1+0.08/4)6⋅4−1)/(0.08/4).

Simplifying further gives P6=$10,000 ((1.02)24−1)/(0.02) and thus P6=$304,218.62.

Rounding as requested, our answer is 304200.

The distance between the points (-6, 4) and (5, 4) is 11 units.

To find the distance between two points in a Cartesian coordinate system, we can use the distance formula:

Distance = √[(x2 - x1)² + (y2 - y1)²]

Given the two points (-6, 4) and (5, 4), we can plug in the coordinates into the distance formula:

Distance = √[(5 - (-6))² + (4 - 4)²]

        = √[(5 + 6)² + 0²]

        = √[11² + 0]

        = √[121]

        = 11

Therefore, the distance between the points (-6, 4) and (5, 4) is 11 units.

In this case, since the y-coordinates of both points are the same (4), the distance between them only considers the difference in their x-coordinates. As the x-coordinate of the second point is 11 units greater than the x-coordinate of the first point, the distance between them is simply the absolute value of the difference, which is 11.

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The Values of y varies directly with x

So, y = m * x

where m is constant

when y = 30 , x = 5

so,

30 = m * 5

m = 30/5 = 6

so, y = 6x

when x = 7, then solve to find y

y = 6 * 7 = 42

The price of the wheelbarrow is $86, and Pedro will need to pay an additional 30% of the price for shipping and handling.

To calculate the shipping and handling cost, we can first find 30% of the price of the wheelbarrow:

30% of $86 = 0.3 x $86 = $25.80

Therefore, Pedro will need to pay $25.80 for shipping and handling.

Step-by-step explanation:

Given \(g'(x) = g^{-2}, x> 0\ g(1) = 0 \ and \ g(2) = 0\)

To get g(x), we will have to integrate g'(x)

\(g(x) = \int\limits {x^{-2}} \, dx\\ g(x) = \frac{x^{-2+1}}{-2+1} + C\\ g(x) = -x^{-1} + C\\g(x) = -x^{-1} + C\\\)

If g(1) = 0, this means at x = 1, g(x) = 0

0 = -1⁻¹ + C

C= 1

Substitute C = 1 into the function

g(x) = -x⁻¹ + 1

If g(2) = 0, this means at x = 2, g(x) = 0

0 = -2⁻¹ + C

C= 2⁻¹

C =  1/2

Substitute C = 2 into the function

g(x) = -x⁻¹ + 1/2

Answer:

8 x 8 =64 + 16 x 8 = 128 =$192

Step-by-step explanation:

the answer of this equation is -5

The amount that a student would pay in interest on a $1,500 loan for 2 years is $161.70

What is simple interest?

Under simple interest loan arrangement, the same amount of interest is paid every year for the entire duration of the loan as the interest is determined as the loan principal multiplied by interest rate as well as multiplied by the loan duration expressed in years as indicated below:

I=PRT

I=the interest on the Stafford loans in dollars=unknown

P=Stafford loans principal=$1500

R=annual rate of interest on the loan=5.39%

T=the loan period in years=2

I=$1500*5.39%*2

I=$161.70

Over the period of 2 years, the interest on the student's loan is $161.70

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Answer:

its 5.11 grms because of the phto sintises

Step-by-step explanation:

The value of x is 1.75 and y is 5. The solution is obtained using properties of congruent triangles.

What is a congruent triangle?

Two triangles that are congruent will have precisely the same three sides and three angles.

The dimensions of the triangles' sides and angles determine whether two or more triangles are congruent. A triangle's size is determined by its three sides, and its shape by its three angles. Pairs of corresponding sides and corresponding angles in two triangles are said to be equal if they are congruent. They share a similar size and shape. In triangles, there are numerous congruence conditions.

The triangles are congruent by SAS congruency because

AC = CD (Given)

∠ACB = ∠DCE ( Vertically opposite angles)

BC = CE  (Given)

Thus, Triangle ABC ≅ Triangle DEC

Since, the triangles are congruent, therefore

⇒AC = CD

⇒4y-6 = 2x+6   ...(1)

Also, BC = CE

⇒3y+1 = 4x

⇒(3y+1)/4 = x    ...(2)

Now, substituting the value of x in (1), we get,

⇒4y-6 = 2(3y+1)/4+(6)

⇒4y-6 = (6y+2 +24)/4

⇒16y-24 = 6y+2 +24

⇒10y = 50

⇒y = 5

Now putting the value of y in (2), we get

⇒(3(2)+1)/4 = x

⇒7/4 = x

⇒ x = 1.75

Hence, the value of x is 1.75 and y is 5.

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The maximum number of pieces of drywall that can be installed before running out of screws is 0.

To determine the number of pounds of drywall that can be installed before running out of screws, we need to consider the weight of both the drywall and the screws.

Given:

12 screws are required per piece of drywall.

Each piece of drywall weighs 30 lbs.

Each screw weighs 0.011 lbs.

The company received a bulk order of 100 lbs of screws.

Let's denote the number of pieces of drywall as "x".

The weight of the screws can be calculated as:

Weight of screws = Number of screws × Weight per screw

Weight of screws = 12 screws × 0.011 lbs/screw

Weight of screws = 0.132 lbs

Now, we can calculate the maximum number of pieces of drywall that can be installed based on the weight of the screws:

Maximum number of pieces of drywall = Weight of screws / Weight per drywall piece

Maximum number of pieces of drywall = 0.132 lbs / 30 lbs

Maximum number of pieces of drywall ≈ 0.0044 pieces

Since it doesn't make sense to have a fraction of a drywall piece, we can round down the result. Therefore, the maximum number of pieces of drywall that can be installed before running out of screws is 0.

In conclusion, with the given bulk order of 100 lbs of screws, the company cannot install any drywall before running out of screws.

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