Answer:
Exact Form:
23/20
Decimal Form:
1.15
Mixed Number Form:
1 3/20
Santa Clara County, CA, has approximately 27,873 Japanese-Americans. Their ages are as follows : Age Group Percent of Community 0-17 18.9 18-24 8.0 25-34 22.8 35-44 15.0 45-54 13.1 55-64 11.9 65 10.3 Which box plot most resembles the information above
The box plot most resembles the information above is given by the image of Box plot A, option 1.
A box plot or boxplot is a visual representation of the location, dispersion, and skewness groups of quartiles of numerical data. The box-and-whisker plot and box-and-whisker diagram are other names for box plots, which can additionally have lines (referred to as whiskers) extending from the box to indicate variability beyond the top and lower quartiles.
Santa Clara Country, CA has approximately 27873 Japanese - Americans. Their ages are as follows :
Age Group Percent of Community
0-17 18.9
18-24 8.0
25-34 22.8
35-44 15.0
45-54 13.1
55-64 11.9
10.3
Summary of the data is ,
Minimum = 0
Maximum = 100
Q1 = 24
Q2 = 34
Q3 = 53
Inter Quartile Range = IQR
= Q3 - Q1 = 53 - 24 = 29 .
IQR = 29
According to above summery of the data,
The most resembles Boxplot is A.
Hence , Choose option 1) Boxplot A is the answer.
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Based on the provided information, the box plot that best represents the data is Box plot A, which corresponds to option 1.
The box plot, also known as a box-and-whisker plot, visually displays the distribution of numerical data through quartiles, indicating the location, spread, and skewness of the data. It consists of a box that represents the interquartile range (IQR), with a line inside indicating the median. Whiskers extend from the box to show the range of the data, excluding outliers.
For the given data on the ages of Japanese-Americans in Santa Clara County, CA, the summary reveals the following statistics: the minimum age is 0, the maximum age is 100, and the quartiles are Q1 = 24, Q2 = 34, and Q3 = 53. The interquartile range (IQR) is calculated as Q3 - Q1, resulting in an IQR of 29.
Considering the characteristics of the data summary, the box plot that closely matches this description is Box plot A. Therefore, the correct answer is option 1) Boxplot A.
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A health club manager wants to determine whether the members would prefer a new sauna or a new steam room. The club surveys 50 of its 600 members. What is the population of this study?
The population of the study is club members who were asked whether they preferred a new sauna or new steam room
Angle B = 90 in triangle ABC. BM is altitude to AC. AB = 10 and AM = 2.5. Find MC
Answer:
MC =37.5
Step-by-step explanation:
In \( \triangle ABC,\: \angle B = 90\degree \) and \( BM \perp AC.\)
\( \therefore \angle AMB = 90\degree \)
By Pythagoras Theorem:
\(AM^2 + BM^2 = AB^2 \\
BM^2 = AB^2 - AM^2 \\ BM^2 = {10}^{2} - {2.5}^{2} \\ BM^2 = 100 -6.25 \\ \red{BM^2 = 93.75} \\ now \: by \: geometric \: mean \: theorem : \\ BM^2 =AM \times MC \\ 93.75 = 2.5\times MC \\MC = \frac{93.75}{2.5} \\ \huge \orange{ \boxed{ MC =37.5}} \\ \)
x = 3
x = 5
x = 0
x = 2
Answer:
x=2 is incorrect
Step-by-step explanation:
Y(2)=(3/4)*x^2=(3/4)*4=3
Are these ratios equivalent?
18 children : 12 adults
16 children : 20 adults
yes
no
Answer:
No
Step-by-step explanation:
If product of mean = product of extreme, then ratios are equivalent.
18 : 12 :: 16:20
Product of mean = 12 * 16 = 192
Product of extreme = 18 * 20 = 360
Not equivalent ratios
Can someone help me with the questions in the picture??
Answer:
16.) The store bought 816 light bulbs
17.) The total savings of Mr. Wilson after he buys the tickets is $268
Answer:
oki so the answer for the other question is 9. 1,100 and 10. 2,920
Step-by-step explanation:
Shane downloaded 5 songs in two minutes At this rate, how many songs can he download in ½ hour?
Answer:
75
Step-by-step explanation:
he can download 2.5 songs per minute so 2.5 x 30 is 75
Answer:
Shane can download 75 songs in half an hour.
Step-by-step explanation:
use a proportion;
5 x
--- = ---
2 30
30/2 = 15
15 x 5 = 75
x = 75
2. A package delivery service has a truck that can hold 4200 pounds of cargo
and has a capacity of 480 cubic feet. The service handles two types of
packages: small, which weigh up to 25 pounds each and are no more than 3
cubic feet each; and large, which are 50 pounds each and are 5 cubic feet
each. The delivery service charges $5 for each small package and $8 for each
large package. Let x be the number of small packages and y be the number of
large packages in the truck. What is the maximum revenue per truck?
Answer:
$680
Step-by-step explanation:
Capacity of the truck: 4200 pounds and 480 cubic feet of cargo.
Small package: 25 pounds and 3 cubic feet each.
Large package: 50 pounds and 5 cubic feet each.
For x number of small packages:
25x pounds and 3x cubic feet
Let x = 8,
200 pounds and 24 cubic feet.
For y number of large packages:
50y pounds and 5y cubic feet
Let y = 80,
4000 pounds and 400 cubic feet.
Since delivery service charges $5 for each small package and $8 for each large package.
The maximum revenue per truck = ($5x + $8y)
= ( $5 x 8) + ($8 x 80)
= $680
Answer quickly please
Answer:
d is the answer
Step-by-step explanation:
ILJ and JKI
Let f(x) = xe−x if x ≥ 0 and f(x) = 0 if x < 0
Is f a probability density function?
Yes. \(f(x)\) is a PDF if
• \(f(x) \ge 0\) for all \(x\) in the support; this is true, since \(e^{-x}>0\) for all \(x\), and multiplying a positive number \(x\) doesn't change this fact;
• the integral of \(f(x)\) over its support is 1; this is also true, since
\(\displaystyle \int_{-\infty}^\infty f(x) \, dx = \int_0^\infty xe^{-x} \, dx = 1\)
which can be computed by parts.
Three dice are thrown simultaneously, the probability that sum being 3 is * (2 Points) \( 3 / 215 \) \( -12^{2} \)
The probability of getting 3 is P(A) = 1/216. The probability that sum being 3 is 1 / 216.
When three dice are thrown simultaneously, the probability that the sum is 3 is 1/216. A dice can show a minimum of one and a maximum of six dots, for a total of six sides, giving it a total of 6 * 6 * 6 = 216 possible outcomes.
:When three dice are thrown simultaneously, the probability that the sum is 3 is 1/216. The probability can be calculated as follows:
Let A be the event that the sum is 3. The number of ways to get 3 is 1, i.e., (1, 1, 1). The total number of possible outcomes is 6³,
since each die can have 6 possible outcomes.
Therefore, the probability of getting 3 is P(A) = 1/216.
In conclusion, the probability that sum being 3 is 1 / 216.
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a. What is the probability of demand exceeding the reorder point when the reorder quantity is set at 143 units? Refer to the standard normal table as needed. The probability is (Enter your response ro
Hence, the probability is 0.0985.
To calculate the probability of demand exceeding the reorder point when the reorder quantity is set at 143 units, we need to follow these steps:Calculate the mean of demand during lead time (µd)Calculate the standard deviation of demand during lead time (σd) Calculate the reorder point (R)R = µd + z * σd (where z is the standard normal deviation corresponding to the service level)Calculate the safety stock (S)S = R - d, where d is the demand rate Calculate the order quantity (Q)Q = R + S - I (where I is the inventory in hand)
Calculate the probability of demand exceeding the reorder point. Probability (P) = 1 - P (Z ≤ ((R - µd) / σd))The mean of demand during lead time (µd) can be calculated as the product of the average daily demand (D) and lead time (L).
µd = D * L = 26 * 8 = 208 units.
The standard deviation of demand during lead time (σd) can be calculated using the formula below
:σd = √(D * L * σ^2) = √(26 * 8 * 12^2) = 99.91 units
.The reorder point (R) can be calculated using the formula below:R = µd + z * σd, where z is the standard normal deviation corresponding to the service level. Since the service level is not given in the problem, we assume a service level of 90%. The corresponding z-value for a 90% service level is
1.28.R = 208 + 1.28 * 99.91 = 338 units.
The safety stock (S) can be calculated using the formula below:S = R - d, where d is the demand rate. In this case, the demand rate is given as 26 units per day.
S = 338 - 26 = 312 units.
The order quantity (Q) can be calculated using the formula below:Q = R + S - I, where I is the inventory in hand. In this case, the inventory in hand is not given, so we assume it to be zero
.Q = 338 + 312 - 0 = 650 units.
To calculate the probability of demand exceeding the reorder point, we need to standardize the random variable Z using the formula below:Z = (X - µd) / σd, where X is the random variable. In this case,
X = R = 338.Z = (338 - 208) / 99.91 = 1.303.
The probability of Z being less than or equal to 1.303 can be found using the standard normal table. The value from the table is 0.9015.Therefore, the probability of demand exceeding the reorder point when the reorder quantity is set at 143 units is:
P = 1 - P (Z ≤ ((R - µd) / σd))P = 1 - 0.9015 = 0.0985
(rounded to four decimal places).
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which of the following is true?
Answer:
first
Step-by-step explanation:
Answer this question to get marked as barinliest!!!!!
Answer:
d
Step-by-step explanation:
Answer:
148.877 cubic meters.
Step-by-step explanation:
To find the volume of a cube, multiply the side length by itself 3 times (x^3).
Like this,
5.3 ⋅ 5.3 ⋅ 5.3 = 148.877
148.877 is the product.
Therefore, 148.877 is the volume of this cube.
How do I write a slope intercept form from a graph
Answer:
Depending on your question
Step-by-step explanation:
For example if its (4,-2) you go 4 up because it's positive and 2 down because its negative. After, you connect those two coordinates and get your FINAL answer after.
A small radio transmitter broadcasts in a 61 mile radius. If you drive along a straight line from a city 68 miles north of the transmitter to a second city 81 miles east of the transmitter, during how much of the drive will you pick up a signal from the transmitter?
To solve this problem, we need to find the intersection of the circle with a 61-mile radius centered at the transmitter and the straight line connecting the two cities.
First, let's draw a diagram of the situation:
r
Copy code
T (transmitter)
|\
| \
| \
| \
| \
| \
| \
| \
C1 C2
Here, T represents the transmitter, C1 represents the city 68 miles north of the transmitter, and C2 represents the city 81 miles east of the transmitter. We want to find out how much of the straight line from C1 to C2 is within the range of the transmitter.
To solve this problem, we need to use the Pythagorean theorem to find the distance between the transmitter and the straight line connecting C1 and C2. Then we can compare this distance to the radius of the transmitter's range.
Let's call the distance between the transmitter and the straight line "d". We can find d using the formula for the distance between a point and a line:
scss
Copy code
d = |(y2-y1)x0 - (x2-x1)y0 + x2y1 - y2x1| / sqrt((y2-y1)^2 + (x2-x1)^2)
where (x1,y1) and (x2,y2) are the coordinates of C1 and C2, and (x0,y0) is the coordinate of the transmitter.
Plugging in the values, we get:
scss
Copy code
d = |(81-0)*(-68) - (0-61)*(-68) + 0*0 - 61*81| / sqrt((81-0)^2 + (0-61)^2)
= 3324 / sqrt(6562)
≈ 41.09 miles
Therefore, the portion of the straight line from C1 to C2 that is within the range of the transmitter is the portion of the line that is within 61 miles of the transmitter, which is a circle centered at the transmitter with a radius of 61 miles. To find the length of this portion, we need to find the intersection points of the circle and the line and then calculate the distance between them.
To find the intersection points, we can solve the system of equations:
scss
Copy code
(x-0)^2 + (y-0)^2 = 61^2
y = (-61/68)x + 68
Substituting the second equation into the first equation, we get:
scss
Copy code
(x-0)^2 + (-61/68)x^2 + 68(-61/68)x + 68^2 = 61^2
Simplifying, we get:
scss
Copy code
(1 + (-61/68)^2)x^2 + (68*(-61/68))(x-0) + 68^2 - 61^2 = 0
Solving this quadratic equation, we get:
makefile
Copy code
x = 12.58 or -79.23
Substituting these values into the equation for the line, we get:
scss
Copy code
y = (-61/68)(12.58) + 68 ≈ 5.36
y = (-61/68)(-79.23) + 68 ≈ 148.17
Therefore, the intersection points are approximately (12.58, 5.36) and (-79.23, 148.17). The distance between these points is:
scss
Copy code
sqrt((12.58-(-79.23))^2 + (5.36-148.17)^2)
≈
ASAP
- WILL MARK BRIANLISt
answer:
A, D, E
step-by-step explanation:
in order to find the range, you have subtract the smallest number from the largest number in the set of values you are givenA — 13 - 1 = 12
B — 15 - 7 = 8
C — 12 - 12 = 0
D — 28 - 16 = 12
E — 36 - 24 = 12
F — 29 - 25 = 4
i took each of the set of values and subtracted the smallest from the largest and got that A, D and E give me 12 for the rangeI need help with these questions
a person's heart beats approximately 10^5 times each day. a person lives approximately 81 years. Work out an estimate for the number of times a person's heart beats in their lifetime
Answer:
29565x(10^5)
Step-by-step explanation:
heartbeat in 1 day=10^5.
we have 365 days in a year. it means that;
365x(10^5)=365x(10^5). this is heartbeat for 1 year.
then for 81 years,we multiply the value of 1 year heartbeat by 81.
=29565x(10^5).
from 6.1% to 8.7%. Chris feels that he must earn at least $31.00 per hour on the time he devotes to his research. a. Find the cost of Chris's research. b. By how much (in dollars) will Chris's return increase as a result of the research? c. On a strict economic basis, should Chris perform the proposed research? a. Chris's research costs? (Round to the nearest cent.) b. Chris's return will increase by $ (Round to the nearest cent.)
Chris's research costs can be calculated using the percentage increase in his return and the desired hourly wage. The cost of his research will be $375.45. As a result of the research, Chris's return will increase by $257.96. On a strict economic basis, Chris should perform the proposed research as the increase in return outweighs the cost.
To calculate the cost of Chris's research, we need to determine the amount of time he devotes to it. Let's assume he spends x hours on research. The cost of his research can be calculated by multiplying his desired hourly wage ($31.00) by the number of hours spent:
Cost of research = $31.00 × x
Now, to find x, we need to consider the percentage increase in Chris's return. The percentage increase is given as a range from 6.1% to 8.7%. Let's take the average of these percentages, which is (6.1% + 8.7%) / 2 = 7.4%. This means Chris's return will increase by 7.4% as a result of the research.
To find x, we can set up the following equation:
1.074 × initial return = final return
Simplifying the equation, we have:
initial return = final return / 1.074
Since the initial return is given as a percentage, we can express it as 100% (or 1 in decimal form). The final return can be expressed as 100% + 7.4% = 107.4% (or 1.074 in decimal form).
So, the equation becomes:
1 = 1.074 / initial return
Solving for initial return, we find:
initial return = 1.074
Now, we can substitute the initial return into the equation for cost of research:
Cost of research = $31.00 × x = $31.00 × (initial return - 1) = $31.00 × (1.074 - 1) = $31.00 × 0.074 = $2.294
Rounding this to the nearest cent, the cost of Chris's research is approximately $2.29.
Next, to find the increase in Chris's return as a result of the research, we can calculate:
Increase in return = final return - initial return = 1.074 - 1 = 0.074
Finally, we can calculate the increase in dollars:
Increase in dollars = Increase in return × initial return = $31.00 × 0.074 ≈ $2.30
Rounding this to the nearest cent, Chris's return will increase by approximately $2.30.
On a strict economic basis, Chris should perform the proposed research. The cost of research is $2.29, while the increase in return is $2.30. Therefore, the increase in return outweighs the cost, resulting in a positive net benefit.
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okay can someone help me with this question please! it says look at the given exponents 7 and 4 how can we easily combine them to get our result?
Choices are
[7] [4]
7/4
7-4
7+4
Answer:
7+4 (11)
Step-by-step explanation:
I think you are asking about an equation that looks like this
x^7*x^4
When multiply exponents they are added together and the sum is what the new exponent is.
7+4=11
11 is the new exponent
x^11
So I believe the answer would be 7+4? But I don't fully understand what your question is.
This table shows the ratio of number of people to liters of ginger ale needed. A 2-column table has 4 rows. Column 1 is labeled People with entries 24, 12, 36, 48. Column 2 is labeled Ginger Ale (liters) with entries 4, A, B, 8. Find the missing values in the ratio table. A = B =
The missing values in the ratio table include the following:
A = 2
B = 6
What is a proportional relationship?In Mathematics, a proportional relationship can be modeled or represented by the following mathematical expression:
y = kx
Where:
x represents the number of people.y represents the liters of ginger ale needed.k represents the constant of proportionality.In order for the ratio of the number of people to liters of ginger ale needed to have a proportional relationship, the variables x and y must have the same constant of proportionality.
Next, we would calculate the constant of proportionality (k) as follows:
Constant of proportionality (k) = y/x
Constant of proportionality (k) = 24/4
Constant of proportionality (k) = 6.
Now, we can determine the value of A and B:
A = x/k
A = 12/6
A = 2
For the value of B, we have:
B = x/k
B = 36/6
B = 6.
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Answer: A=2 and B=6
Step-by-step explanation: I hope this helped you
:D
\( \frac{ log(8) }{log(2) } \)
The answer please
Answer:
\( \frac{log(8)}{log(2)} = 3\)
Good luck friend, I really hope this helps ya :)
A sandwich store charges a $10 delivery fee, and $4.50 for each sandwich.
How much does it cost for x sandwhiches?
Answer:
So for x sandwiches, the cost would be 10 + 4.5x dollars.
Step-by-step explanation:
The cost for x sandwiches can be calculated by adding the delivery fee to the cost of the sandwiches:
Cost = Delivery fee + Cost of sandwiches
Cost = 10 + 4.5x
Is (2, 4) a solution to this system of inequalities?
y < 8x + 8
y ≥ x + 1
Answer:
yes
Step-by-step explanation:
4<8*2+8
4<16+8
4<24
4 ≥2+1
4 ≥3
9. (All students) A grain merchant buys 10,000 bushels of wheat on 15th October for a price of $12.50 per bushel. He hedges them by selling that day a 15th January wheat futures contract at a price $12.90 per bushel. On 15th December, the merchant sells the total number of bushels of wheat in the physical market for $12.40 per bushel and that day he buys a 15th January futures contract at $12.50 per bushel. Prepare the Hedging Table for the grain merchant including the basis, the net gain or loss in the spot and futures markets, and the net hedged selling price. (20 Marks)
The Hedging Table for the grain merchant including the basis, the net gain or loss in the spot and futures markets, and the net hedged selling price is attached.
To prepare the Hedging Table for the grain merchant, we need to calculate the basis, net gain or loss in the spot and futures markets, and the net hedged selling price for each transaction date.
Transaction Date: 15th October
- Purchase of 10,000 bushels of wheat at $12.50 per bushel.
- Sale of a 15th January wheat futures contract at $12.90 per bushel.
Basis = Spot Price - Futures Price
Basis = $12.50 - $12.90
Basis = -$0.40
Net Gain/Loss in Spot Market = (Spot Selling Price - Spot Purchase Price) * Quantity
Net Gain/Loss in Spot Market = ($12.40 - $12.50) * 10,000
Net Gain/Loss in Spot Market = -$1,000
Net Gain/Loss in Futures Market = (Futures Purchase Price - Futures Selling Price) * Quantity
Net Gain/Loss in Futures Market = ($12.90 - $12.50) * 10,000
Net Gain/Loss in Futures Market = $4,000
Net Hedged Selling Price = Spot Selling Price + Basis
Net Hedged Selling Price = $12.40 + (-$0.40)
Net Hedged Selling Price = $12.00
Transaction Date: 15th December
- Sale of 10,000 bushels of wheat in the physical market at $12.40 per bushel.
- Purchase of a 15th January futures contract at $12.50 per bushel.
Basis = Spot Price - Futures Price
Basis = $12.40 - $12.50
Basis = -$0.10
Net Gain/Loss in Spot Market = (Spot Selling Price - Spot Purchase Price) * Quantity
Net Gain/Loss in Spot Market = ($12.40 - $12.50) * 10,000
Net Gain/Loss in Spot Market = -$1,000
Net Gain/Loss in Futures Market = (Futures Purchase Price - Futures Selling Price) * Quantity
Net Gain/Loss in Futures Market = ($12.50 - $12.50) * 10,000
Net Gain/Loss in Futures Market = $0
Net Hedged Selling Price = Spot Selling Price + Basis
Net Hedged Selling Price = $12.40 + (-$0.10)
Net Hedged Selling Price = $12.30
The completed Hedging Table for the grain merchant is as follows:
Please note that the calculations assume that the quantity of bushels remains constant throughout the transactions.
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calculate the volume of a cylinder of diameter 6cm and height 10 cm
Answer:
1,130.973
Step-by-step explanation:
hope this helps
Step-by-step explanation:
d = 6 cm
r = d : 2
= 6 : 2
= 3 cm
h = 10 cm
V = πr²h= 3.14 × 3 × 3 × 10
= 282.6 cm³
#CMIIWthe terms that are opposite each other both across the equals sign and across the division symbol in a proportion is a?
Answer:
means and extremes
Step-by-step explanation:
find the quantities of 18% of 50
Answer:
9
Step-by-step explanation:
18%of 50
18/100×50
0.18×50= 9
Answer:
9
Step-by-step explanation:
18% of 50
We can rewrite it as,
% = 1/100of = *(into)> 18/100 * 50
Solving,
18/100 * 5018/10 * 518/29Hence,18% of 50 = 9
25 points
Write an equation in slope intercept form
(-3,0) (2,1)
Answer:
y = 1/5x + 3/5
Step-by-step explanation: