PLEASE HELP WILL GIVE BRAINLIEST
Suppose an object is not moving. Are the forces balanced or unbalanced? What are the two forces acting on the object?

Answer:

105 kg*m/s

Explanation:

p=mv

momentum=mass*velocity

momentum=15kg*7m/s

momentum=105kg*m/s

Hi there!

A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).

We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.

\(d_y = v_yt + \frac{1}{2}at^2\)

dy = vertical displacement (height of table, 0.85 m)

vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)

t = time (? sec)
Simplify and rearrange the variables for 't'.

\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)

Plug in the given values.

\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)

B)

Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)

dₓ= horizontal displacement (? m)

vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)

t = time (0.4165 s)

Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)

Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)

If a third resistor is added in SERIES, what changes happens to the....

When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.

The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.

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Answer:

BBbbb

Explanation:

B is the correct answer:))))

Answer: B

Explanation: I think its B or A but mostly B

Answer:

The enthalpy of a reaction does not depend on the reactant path taken

Explanation:

i just took the test on a pex :)

Explanation:

Given that,

Current, I = 0.015 A

Voltage, V = 240 volts

We need to find the resistance. Using Ohm's law we can find it as follows :

\(V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega\)

So, When a current of 0.015 A passes through human body at 240 volts p.d it  causes​  16000 ohms of resistance.

Answer:

Magnitude of Paula’s acceleration\($a=39 \cdot 8m/sec^{2}$.\)

Explanation:

• An object is said to be accelerated if there is a change in its velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction at that point.

• To find the magnitude of her acceleration, use the formula:                               \($${v^2} = {u^2} + 2as$$\)

Where, is final velocity, is initial velocity, is acceleration and is displacement.

• Placing the value of the given initial velocity, \($u=0m/s$\), displacement, \($s = 0 \cdot 201m$\) and the final velocity,\($v = 4m/s$\) in the above formula.

\(\[\begin{align}& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\end{align}\]\)

\(\[& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\]\)

• Hence, magnitude of her acceleration, \($a=39 \cdot 8m/sec^2$\)

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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/\(s^{2}\).

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e \(V^{2}\) = \(U^{2}\) ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

\(V^{2}\) = \(U^{2}\) - 2as

0 = \((4)^{2}\) - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \(\frac{16}{0.402}\)

  = 39.801

a = 39.80 m/\(s^{2}\)

Therefore Paola's acceleration is 39.80 m/\(s^{2}\).

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The particle's average speed after 10 seconds is 110 m/s, and its average velocity is zero.

When a particle is thrown upwards, its initial velocity is in the upward direction and its acceleration is in the downward direction due to gravity. The acceleration due to gravity is approximately 10 m/s² near the surface of the Earth. Therefore, the particle's velocity decreases at a rate of 10 m/s² until it reaches its highest point, where its velocity is zero. After that, the particle's velocity becomes negative and it starts to fall back to the ground.

To find the particle's average speed after 10 seconds, we need to calculate the total distance traveled by the particle in 10 seconds. The formula to calculate the distance traveled by a particle under constant acceleration is:

distance = initial velocity * time + (1/2) * acceleration * time²

Substituting the given values, we get:

distance = 60 m/s * 10 s + (1/2) * 10 m/s² * (10 s)²

distance = 600 m + 500 m

distance = 1100 m

Therefore, the average speed of the particle after 10 seconds is:

average speed = total distance / total time

average speed = 1100 m / 10 s

average speed = 110 m/s

To find the particle's average velocity after 10 seconds, we need to calculate the displacement of the particle in 10 seconds. Displacement is the change in position of the particle, which is equal to the difference between its final and initial positions. Since the particle is thrown upwards and then falls back to the ground, its displacement after 10 seconds is zero. Therefore, the average velocity of the particle after 10 seconds is also zero.

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The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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Yes ,In my  DC experiment, when the capacitor was just began to charge the current in the circuit was O maximum between maximum and minimum.

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The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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Answer:

Looks like a cosine function graph. The wave pattern is transversal waves . The faster the amplitude the higher the wave. The force of the drop hitting the water pushes the water down and out causing waves  If the water hits from a higher amplitude the waves raise bigger . When you increase the frequency of the water drops the waves move faster but no bigger.  When you increase the frequency of the water drops the wave ripples faster .

Explanation:

An answer to part of your question

A transverse wave is the kind of wave pattern I observe in the sink in the top view.

Transverse waves

A transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations

Answer:

14 atoms

Explanation:

Number of atoms in Fe₂(CO₃)₃

An atom is the smallest indivisible particle that takes part in a chemical reaction.

In Fe₂(CO₃)₃; we have:

   Elements       Number of atoms

          Fe                       2

          C                         3

          O                     3(3) = 9

Total number of atoms = 2 + 3 + 9  = 14 atoms

(a) The tension in the string is determined as 19.6 N.

(b) The acceleration of each object is 5.3 m/s².

(c) The distance each object will move in the first second if it started from rest is 2.65 m.

(a) The tension in the string is the resultant weight of the masses and magnitude is calculated as follows;

T = ( 5.7 kg - 3.7 kg ) x 9.8 m/s²

T = 19.6 N

(b) The acceleration of each object is calculated as follows;

a = T / m

where;

a = 19.6 N / 3.7 kg

a = 5.3 m/s²

(c) The distance each object will move in the first second if it started from rest is calculated as;

s = ut + ¹/₂at²

where;

s = 0 + ¹/₂(5.3)(1²)

s = 2.65 m

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For the system to be balanced, the torque generated on each side of the fulcrum must be the same.

On the other hand, the torque τ generated by a force F applied at a distance d from the fulcrum is given by the equation:

Let W be the weight of the rock. Since the torque generated by the crate must be the same as the torque generated by the rock, then:

Rewrite the distance of 730 cm in meters:

Solve for W to find the weight of the rock:

Therefore, the rock must be as large as for its weight to be equal to 592N.

Answer:

108 N

Explanation:

Divide the force by uk to get the normal force

(25.7)/(0.238) = 107.98 N = 108 N

Answer:

107

Explanation:

The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

To plot the velocity vs. time graph, we'll use the given data points:

Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0

Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0

Let's plot these points on a graph:

Time (s) [x-axis] | Velocity (m/s) [y-axis]

--------------------------------------------

2.0               | 6.0

4.0               | 7.0

6.0               | 8.0

8.0               | 9.0

10.0              | 10.0

12.0              | 11.0

After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.

Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.

Using the formula for calculating the slope of a line:

Slope (k) = (Change in velocity) / (Change in time)

For the first two points:

Change in velocity = 7.0 - 6.0 = 1.0 m/s

Change in time = 4.0 - 2.0 = 2.0 s

Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²

Therefore, the slope of the graph is 0.5 m/s².

Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².

Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).

To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:

d = 0.5 * 1.5 = 0.75 meters

Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

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The probable question may be:

An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.

Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.

Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0

A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will

B. What is the physical significance of the slope value computed in part A?

C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.

Answer:

0.159

Explanation:

the formula to find its is 1÷2*gt^2

Answer:

D

Explanation:

v= a t

 = 5.1 * .25 = 1.275 m/s

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Answer:

Explanation:

A turbine and generator produce the electricity

"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.

Answer:

31.84

Explanation:

To find the magnitude of the sum of the three vectors, first, we need to add the vectors component-wise. Then, we can find the magnitude of the resulting vector.

Add the vectors component-wise:

Vector A + Vector B + Vector C = [13+13+0, 8+0+1, 0+8+8] = [26, 9, 16]

Find the magnitude of the resulting vector:

The magnitude of a vector [x, y, z] is given by the formula:

magnitude = sqrt(x^2 + y^2 + z^2)

Plugging in the values from the resulting vector:

magnitude = sqrt(26^2 + 9^2 + 16^2)

magnitude = sqrt(676 + 81 + 256)

magnitude = sqrt(1013)

magnitude ≈ 31.84

The magnitude of the sum of the three vectors is approximately 31.84.

Hope this helps!

ANSWER:

255.06 joules

STEP-BY-STEP EXPLANATION:

We have that the potential energy is given as follows:

where m is the mass, g is the gravity and h is the height, we replace and we would have:

potential energy equals 255.06 joules

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Answer:10 m/s

Explanation:

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Velocity is vector quantity.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time. Here in the question velocity is changing by using work energy theorem we have,

work done = change in kinetic energy

5000 = (.5).m.v² , where v is velocity.

5000 = (.5).100.v²

v = 10 m/sec

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.

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(a) The position where particle Q and P meet is 68.75 m.

(b) The velocity with which particle Q is shot is 15 m/s.

The time elapsed before the two particles meet is calculated as follows;

Distance Q - Distance P = Distance between them

Trise = (V - V₀)/g

Trise = (0 - 40) / -10

Trise = 4.0 s

Hmax = V₀t + 0.5gt²

Hmax = 40 x 4 - (0.5)(10)4²

Hmax = 80 m.

h = Hmax - (V² - V₀²)/2g

h = 80 - ((15)²- 0) / 20

h = 68.75 m.

Thus, the position where particle Q and P meet is 68.75 m

Tfall = (V - V₀)/g = (15-0) / 10

Tfall = 1.5 s

Fall time. = Rise time  for Q.

h = V₀t + 0.5gt²

h = 80 - 68.75

h = 11.25

V₀ x 1.5 - 5(1.5)² = 11.25

V₀ x 1.5 - 11.25 = 11.25

V₀ x 1.5 = 22.5

V₀ = 22.5 / 1.5

V₀ = 15 m/s

Thus, the velocity with which particle Q is shot is 15 m/s.

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Answer:

Et = 30018 [W]

Explanation:

To solve this problem we must use the definition of potential energy, which is expressed by the following equation:

\(E_{p} =m*g*h\)

where:

Ep = potencial energy [W]

g = gravity acceleration [m/s^2]

h = elevation = 120 [m]

m = mass flow = [1800/min]

But in order to get watts into potential energy, we must convert the mass flow from kilograms per minute to kilograms per second.

\(1800[\frac{kg}{min} ]*\frac{1}{60}\frac{min}{s}=30[\frac{kg}{s} ]\)

Ep = 30*9.81*120

Ep = 35316 [W]

If we use  85% of the potential  energy will have:

Et = 35316*0.85

Et = 30018 [W]

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

0.033 seconds

Explanation:

Period = 1/30 = 0.033 seconds

Answer:

The answer is 0.03 s

Explanation:

A.P.E.X.

A 20.0 N force is exerted on the small piston of a hydraulic system. The cross-sectional area of the small piston is 0.0500 m2.

What is meant by Hydraulic ?

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