Please help thank you !

Answer:

$1349

Step-by-step explanation:

Given data

Principal= $1000

Rate= 3%

Time= 10years

Applying the formula

A=Pe^rt

where e is the mathematical constant approximated as 2.7183

substitute

A=1000*2.7183^0.03*10

A=1000*2.7183^0.3

A=1000*1.349

A=1349

Hence the final amount after 10 years is

$1349

f(x) = x is a simple linear function with a slope of 1, f(x) = 3 5 6 is a constant function, f(x) = 3-x is a linear function with a negative slope of -1,  f(x) = 1 is a constant function, f(x) = 2 is a constant function

A constant function is a mathematical function whose output value is the same for every input value

From the given parameters, f(x) = x is a simple linear function with a slope of 1, this implies  that for every unit increase in x, the value of y increases by 1.

Also,  f(x) = 3 5 6 is a constant function, where the value of y is always 3 5 6, regardless of the value of x.

In the same way,  f(x) = 3-x is a linear function with a negative slope of -1, which means that for every unit increase in x, the value of y decreases by 1. The fourth function f(x) = 1 is a constant function, where the value of y is always 1, regardless of the value of x.

The domain of the fifth function is 3 0, which means that x can take any value between 3 and 0.

The sixth function f(x) = 2 is a constant function, where the value of y is always 2, regardless of the value of x.

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Answer:

if it is a square, then it is a quadrilateral

Step-by-step explanation:

For, f(x) = 3x2 – 11x + 8 / (x + 5)(x - 1). (1) x = 1 is a vertical asymptote to the graph off. (II) y = 3 is a horizontal asymptote to the graph off. The correct answer is (II) ONLY.
To determine vertical asymptotes, we look for values of x that make the denominator of the fraction equal to zero. In this case, the denominator is (x + 5)(x - 1), which is equal to zero when x = -5 and x = 1. Therefore, x = -5 and x = 1 are vertical asymptotes of the graph of f(x).
To determine horizontal asymptotes, we look at the end behavior of the function as x approaches positive or negative infinity. In this case, the degree of the numerator (2) is less than the degree of the denominator (2), so we know that there is a horizontal asymptote at y = 0. We can confirm this by dividing the numerator by the denominator using long division or synthetic division. The result is:
f(x) = 3 - 26/(x + 5) + 9/(x - 1)
As x approaches infinity or negative infinity, the fractions with x in the denominator approach zero, leaving only 3 as the limit of the function. Therefore, y = 3 is a horizontal asymptote of the graph of f(x).
So the correct answer is (II) ONLY.

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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It will take approximately 7.27 years for your mother's investment to become worth $1,000,000 when invested in a well-diversified, low-cost mutual fund returning 10% per year.

To determine the number of years it will take for your mother's investment to become worth $1,000,000, we can use the future value formula:

FV = PV * (1 + r)^n

Where:

FV = Future value ($1,000,000)

PV = Present value ($500,000)

r = Annual interest rate (10% or 0.10)

n = Number of years (unknown)

Substituting the given values into the formula:

$1,000,000 = $500,000 * (1 + 0.10)^n

Simplifying the equation:

2 = (1.10)^n

Taking the logarithm of both sides:

log(2) = log(1.10)^n

Using the logarithmic property:

log(2) = n * log(1.10)

Solving for n:

n = log(2) / log(1.10)

Using a calculator:

n ≈ 7.27

Therefore, it will take approximately 7.27 years for your mother's investment to become worth $1,000,000 when invested in a well-diversified, low-cost mutual fund returning 10% per year.

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In the Hotelling model with two ice-cream vendors on a linear beach divided into 100 segments, there are two Nash equilibria: the "Corner Equilibria." These equilibria occur when each vendor sets up their stand at one of the extreme ends of the beach. These equilibria are unique and cannot be surpassed by any other configuration.

In the Hotelling model, the vendors aim to maximize their profits by attracting customers. Since customers go to the closest stand, each vendor wants to position themselves in a way that minimizes the distance to potential customers.

If one vendor sets up their stand at one end of the beach, the other vendor will position themselves at the opposite end to evenly split the customers. This creates a stable equilibrium as neither vendor can gain by moving closer to the other.

Any deviation from the corner equilibria would result in a longer distance for customers, making the deviating vendor less attractive. Therefore, the corner equilibria are the only stable outcomes in this game. Other configurations would lead to a disadvantage for the vendors and thus would not be sustainable Nash equilibria.

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Use the CSS "background-image" property to configure a linear gradient.

The "background-image" property in CSS allows you to set an image or a gradient as the background of an element. When configuring a linear gradient, you can use the "linear-gradient()" function as the value for the "background-image" property. This function allows you to define the starting and ending points of the gradient, as well as the colors and stops along the gradient.

By specifying the desired colors, positions, and angles within the "linear-gradient()" function, you can create customized linear gradients to apply as backgrounds to elements on a web page, achieving visually appealing effects and smooth transitions.

Therefore, Use the CSS "background-image" property to configure a linear gradient.

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To configure a linear gradient in CSS, you can use the 'background-image' property with the 'linear-gradient()' function.

To configure a linear gradient in CSS, you can use the 'background-image' property along with the 'linear-gradient()' function. Here's an example:

In the above code, replace 'element' with the selector for the HTML element you want to apply the gradient to. 'direction' specifies the direction of the gradient, such as 'to right' or 'to bottom'. 'color1', 'color2', and so on represent the colors you want to use in the gradient. You can specify multiple colors to create a smooth transition between them.

For example, to create a horizontal gradient from red to blue, you can use the following code:

This will apply a linear gradient from red to blue horizontally on the selected element.

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Answer:

y = 105x

Step-by-step explanation:

He loses $105 per month

Answer:

horizontal line y = 3

Step-by-step explanation:

The slope of a line gives the measure of its rate of change.

The horizontal line with equation y = 3 is parallel to the x- axis and has a slope of zero.

Thus y = 3 has a rate of change of zero

Answer:

Horizontal line y = 3.

Step-by-step explanation:

Answer:

Surface area of the given prism = 63 square feet

Step-by-step explanation:

Surface area of the given triangular prism = Area of two triangular bases + Area of three vertical rectangles

Area of triangular bases = 2[\(\frac{1}{2}(\text{Base})(\text{Height})\)] (Since the bases of this prism are right triangles)

                                        = 3 × 3

                                        = 9 square ft

Area of one vertical rectangular face = (Length × Width)

                                                             = (3 × 6)

                                                             = 18 square feet

Area of all vertical sides = 3 × 18 = 54 square feet

Total surface area = 9 + 54 = 63 square feet

3x = 6y + 21

6y + 21 - 2y = 3

4y + 21 = 3

4y = -18

y = - 4.5

x = - 2

( -2, -4.5 )

please give brainliest

To send Kred to a Krew member, you can follow the steps provided by the Kred platform. These steps typically involve accessing your Kred account, selecting the desired recipient, specifying the amount of Kred to send, and confirming the transaction.

Sending Kred to a Krew member usually requires using the features and functionalities provided by the specific Kred platform or service. The process may vary depending on the platform, so it is recommended to refer to the official documentation or guidelines provided by the platform. Typically, you would need to log in to your Kred account, navigate to the appropriate section for sending Kred, select the intended recipient from the list of Krew members, enter the desired amount of Kred to send, review the transaction details, and confirm the transfer. The platform may also offer additional options or settings for customizing the transfer process.

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Answer:

The point (-2, 4) is not a solution of the linear equation, 5·y =  3·x + 18

Please find attached the required graph of the linear equation 5·y =  3·x + 18 written in the form y = 3/5·x + 18/5

Step-by-step explanation:

The given equation is 5·y = 3·x + 18, from which we have;

y = 3/5·x + 18/5

To draw the graph, we generate for vales of y corresponding to values of x as follows;

x,      y

-6,    0

-5,    0.6

-4,    1.2

-3,    1.8

-2,    2.4

-1,      3

0,      3.6

1,       4.2

2,      4.8

3,      5.4

4,       6

5,       6.6

6,       7.2

7,        7.8

8,        8.4

9,        9

10,      9.6

11,       10.2

12,      10.8

13,      11.4

14,       12

15,      12.6

16,      13.2

Therefore, when y = 0, x = -6, when x = 0, y = 3.6, when x = -2, y = 2.4, when y = 4, x = -2, x = 6

Therefore, the point (-2, 4) is not a solution of the linear equation, 5·y =  3·x + 18

Answer:

(x + 4)² - 4 = 0

Step-by-step explanation:

Given

x² + 8x + 12 = 0

To complete the square

add/ subtract ( half the coefficient of the x- term )² to x² + 8x

x² + 2(4)x + 16 - 16 + 12 = 0

(x + 4)² - 4 = 0

a) The integral converges to ∞.

b) 1) an = 1/(2n + 1) 2) an = \((-1)^{n+1}\) * \((3/2)^{n-1}\) 3) an = sin((n-1)π/2)

a) To find the value of B such that the integral of [(x/(\(x^{2}\) + 1)) - (B/(3x+1))] from 0 to infinity converges, we need to consider the behavior of the integrand as x approaches infinity.

As x approaches infinity, the term (x/(\(x^{2}\) + 1)) approaches 0 because the denominator grows faster than the numerator. Therefore, the behavior of the integrand is mainly determined by the term (B/(3x+1)).

For the integral to converge, the term (B/(3x+1)) must approach 0 as x approaches infinity. This happens when the value of B is 0.

So, B = 0.

Now, let's evaluate the integral using this B value:

∫[x/(\(x^{2}\) + 1)] - [0/(3x+1)] dx from 0 to infinity

∫[x/(\(x^{2}\) + 1)] dx from 0 to infinity

To evaluate this integral, we can use a substitution. Let u = \(x^{2}\) + 1, du = 2xdx.

The integral becomes:

(1/2) ∫(1/u) du from 1 to infinity

(1/2) [ln|u|] from 1 to infinity

(1/2) [ln|∞| - ln|1|]

(1/2) [∞ - 0]

The integral converges to ∞.

b) Let's find a reasonable formula for each of the given sequences:

1) {an} from n = 1 to infinity = {1/3, 1/5, 1/7, 1/9, .......}

The sequence represents the reciprocals of odd positive integers. A reasonable formula for this sequence is:

an = 1/(2n + 1)

2) {an} from n = 1 to infinity = {-3, 2, -4/3, 8/9, -16/27, ......}

The sequence alternates between a negative number and a positive number, with the absolute values following a geometric pattern. A reasonable formula for this sequence is:

an =  \((-1)^{n+1}\) * \((3/2)^{n-1}\)

3) {an} from n = 1 to infinity = {1, 0, -1, 0, 1, 0, -1, 0, .....}

The sequence repeats the pattern of 1, 0, -1, 0. A reasonable formula for this sequence is:

an = sin((n-1)π/2)

Using a trigonometric function, we can represent the repeating pattern of 1, 0, -1, 0.

Correct Question :

a) Find a number B such that the integral of [(x/x^2 + 1) - (B/3x+1)] from 0 to infinity converges. And then evaluate the integral using this B value.

b) For each of the following sequence, find a reasonable formula for an that matches. the given terms:

1 ) {an} from n = 1 to infinity = { 1/3, 1/5, 1/7, 1/9, .......}

2) {an} from n = 1 to infinity = {-3, 2, -4/3, 8/9, -16/27, ......}

3) {an} from n = 1 to infinity = {1, 0, -1, 0, 1, 0, -1, 0, .....}

(Hint: Think about a trigonometric function.)

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The gradient of the straight line 2y - 4 = 16x + 1 is 8.

What is equation of line?

The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term. It is an equation of degree one, with variables x and y.

To find the gradient of the straight line 2y - 4 = 16x + 1, we first need to rearrange the equation into the standard form of y = mx + c:

2y - 4 = 16x + 1

2y = 16x + 5

y = 8x + 5/2

Now we can see that the gradient of the line is 8, which is the coefficient of x in the equation y = 8x + 5/2. Therefore, the gradient of the straight line 2y - 4 = 16x + 1 is 8.

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Answer:

\(x=\pm2\)

Step-by-step explanation:

\(f(x)=4x^4-64\)

\(0=4x^4-64\)

\(0=x^4-16\)

\(16=x^4\)

\(\pm2=x\)

Answer: y - 2 = 2(x - -3)

The slope is 2 is you find the intercept.

Step-by-step explanation:

:)

(a) The expected frequency for each cell can be computed using the formula E_ij = (R_i * C_j) / n, where R_i is the sum of the i-th row, C_j is the sum of the j-th column, and n is the total sample size.

(b) The observed frequencies in the first row are lower than expected, while the observed frequencies in the second row are higher than expected.

(c) After Computing x²stat. Is it significant at a=0.05 is 16.25.

For (a) The expected frequency for each cell can be computed using the formula E_ij = (R_i * C_j) / n, where R_i is the sum of the i-th row, C_j is the sum of the j-th column, and n is the total sample size. Thus, we have:

For (b) To compare the observed and expected frequencies for each cell, we can compute the deviations and standardized residuals. The deviations are obtained by subtracting the expected frequency from the observed frequency in each cell, and the standardized residuals are obtained by dividing the deviations by the square root of the corresponding expected frequency. The results are shown in the table below:

         a               b

We can see that the observed frequencies in the first row are lower than expected, while the observed frequencies in the second row are higher than expected.

(c) The chi-squared statistic is computed using the formula

X² = Σ [(O_ij - E_ij)^2 / E_ij]

where the sum is taken over all cells. For this table, we have:

Since the computed X² value of 16.25 is larger than the critical value of 3.84, we reject the null hypothesis of independence and conclude that there is a significant association between the two variables.

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Answer:

53,412 and 66,894

Step-by-step explanation:

In this question we have to assume the things

Let us assume

Bill randall be X

So, the Corrine Brown is X + 13,482  as the corrine brown received 13,482 more votes than the Bill Randall

And, the total number of votes is 120,306

Now the equation is

X + X + 13,482 = 120,306

2X + 13,482 = 120,306

2X = 106824

X = 53,412 i.e Bill randall

And, the corrine brown is

= 13,482 + 53,412

= 66,894

The composition of a nontrivial rotation, denoted as Tp, with any vector v results in another rotation. The center of this rotation can be determined using the information provided.

Let's consider a nontrivial rotation p with center P and an arbitrary vector v. The composition of p with v can be expressed as Tp(v), which represents the action of applying p to v. Since p is a rotation, it preserves distances and angles. Therefore, the composition Tp(v) is also a rotation, as it maintains the same properties.

To determine the center of the rotation Tp, we need to find a fixed point of Tp. In other words, we are looking for a point Q such that Tp(Q) = Q. Let's assume that such a point exists and denote it as Q.

Now, consider the action of Tp on the vector PQ. Since Tp(Q) = Q, we have Tp(PQ) = PQ. This implies that Tp(P) + Tp(Q) = PQ.

Since Tp(P) is the image of P under the rotation Tp and PQ is fixed under Tp, it follows that Tp(P) + PQ = PQ. Simplifying this equation, we get Tp(P) = 0, which means the image of the center P under the rotation Tp is the zero vector.

Hence, the center of the rotation Tp is the origin (0,0) in the coordinate system.

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The square mil area for a 2 inch wide by 1/4 inch thick copper busbar is 500 square mils.

To find the square mil area for a 2 inch wide by 1/4 inch thick copper busbar, we need to multiply the width and thickness of the busbar in mils.

1 inch = 1000 mils

So, the width of the busbar in mils = 2 inches x 1000 mils/inch = 2000 mils

And, the thickness of the busbar in mils = 1/4 inch x 1000 mils/inch = 250 mils

Therefore, the square mil area of the copper busbar = width x thickness = 2000 mils x 250 mils = 500,000 square mils.

Hence, the square mil area for a 2 inch wide by 1/4 inch thick copper busbar is 500,000 square mils.

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Answer:

Answer

The answer is 130 because 130+70)180

12) There were about 557 principals in attendance. 13) Option A: The college will have about 480 students who prefer cookies. 14) Option C: bar graph, title favorite sport and the x axis labeled sport and the y axis.

The relationship between two quantities that are measured on the same scale and in the same units is known as a percentage. The relative size or magnitude of one thing in comparison to another is represented by proportions, which are frequently stated as ratios, fractions, or percentages. For instance, if there are 8 girls and 12 boys in a class, the girl-to-boy ratio is 8:12, or 2:3, which indicates that there are 3 guys for every 2 girls. Statistics, geometry, and physics are just a few of the mathematical and scientific disciplines that use proportions. Proportions are frequently used in statistics to describe the distribution of a population or a sample.

12) For the number of principals in conference we set up a proportionality with total people as follows:

We know that, 52 principals out of 70 people thus:

52/70 = x/750

Now,

x = (52/70) * 750

x = 557.14

Hence, we can predict that there were about 557 principals in attendance at the conference.

13) Given that, out of 225 students 27 prefer cookies thus,

27/225 = 0.12

That is 12% students like cookies.

Now, for the total number of students we have:

0.12 * 4000 = 480

Thus, option A: The college will have about 480 students who prefer cookies.

14) For the collected data the best representation is option C: bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44.

15) For the given description of the line plot the median is:

For Bus 47 = 16

For Bus 18 = 13

The faster bus is Bus 47, with a median of 16.

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Answer:

Step-by-step explanation:

If B is the midpoint of AC, where the coordinate of the midpoint B is (6, 4) and endpoint C is (9,2). To get the other coordinates A, we will use the midpoint formula;

B(X,Y) = (x₁+x₂/2, y₁+y₂/2)

From the formula;

X = x₁+x₂/2 and Y = y₁+y₂/2

From the coordinaes given X = 6, Y = 4, x₂ = 9 and y₂ = 2

To get x₁:

From X = x₁+x₂/2

6 = x₁+9/2

cross multiply

12 = x₁+9

x₁ = 12-9

x₁ = 3

Similarly for y₁;

Y = y₁+y₂/2

4 = y₁+2/2

cross multiply

8 = y₁+2

y₁ = 8-2

y₁ = 6

Hence the coordinates of the missing endpoint A(x₁,y₁) is (3, 6)

The runner with the second-lowest time is the second-place finisher in the race.

To find the second-place finisher, we can use the SMALL function. The SMALL function takes two arguments: an array of values and an integer which represents the nth smallest value to extract from the array. In this case, we will use the array of runner times and the integer 2.

The syntax for the SMALL function is as follows:

=SMALL(array,2)

For example, if the array of runner times is {32, 22, 56, 11 }, the calculation would look like:

=SMALL({32, 22, 56, 11}, 2).

The result of this calculation is 22, which is the second-lowest time in the array. Therefore, the runner with the second-lowest time is the second-place finisher in the race.

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Answer: The length of the side is 14 inches

Step-by-step explanation: Using the formula V=(b^2xh):3

Input the numbers we are given: 196=(b^2x3):3 now calculate 196=(14^2x3):3 side b=14 inches

Answer:

-28

Step-by-step explanation:

Answer:

the answer is h and L

Step-by-step explanation: