Please help :((((((((

350 N/m² is the pressure of a 210kg mass with a surface area of 6m2 on the surface it sets.

The pressure of a 210 kg mass with a surface area of 6 m² can be calculated by dividing the force exerted by the mass on the surface by the area.

Since pressure is defined as force per unit area, the formula to calculate pressure is:

Pressure = Force / Area

The force exerted by the mass can be calculated using the equation:

Force = mass * gravity

where gravity is the acceleration due to gravity (approximately 9.8 m/s²).

Substituting the given values, we have:

Force = 210 kg * 9.8 m/s²

Next, we can calculate the pressure:

Pressure = Force / Area = (210 kg * 9.8 m/s²) / 6 m²

Evaluating the expression, we find:

Pressure ≈ 343.33 N/m²

Rounding to two significant digits, the pressure is approximately 350 N/m².

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Answer:

so then the main bild and or project dont get ruined and to make sure everything will fit and work right

The velocity of the car before the brakes were pressed was approximately 17.995 m/s. This velocity is obtained by subtracting the product of the acceleration and time from the final velocity using the kinematic equation.

To determine the velocity of the car before the brakes were pressed, we can use the kinematic equation that relates initial velocity (Vi), final velocity (Vf), acceleration (a), and time (t):

Vf = Vi + at

In this case, the final velocity (Vf) is given as 3.5 m/s, the acceleration (a) is -6.5 m/s² (negative sign indicates deceleration), and the time (t) is 2.23 seconds. We need to find the initial velocity (Vi).

Rearranging the equation, we have:

Vi = Vf - at

Substituting the given values, we get:

Vi = 3.5 m/s - (-6.5 m/s² * 2.23 s)

  = 3.5 m/s + 14.495 m/s

  = 17.995 m/s

Therefore, the velocity of the car before the brakes were pressed was approximately 17.995 m/s.

It's important to note that the direction of the velocity would be west since the car was initially driving west along Steeles Avenue and experienced acceleration in the east direction. However, since the problem does not explicitly mention the direction, we focus on the magnitude of the velocity.

The negative sign of the acceleration indicates deceleration, and the direction of the velocity is west based on the initial direction of the car.

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We are asked to determine the distance between crest of a sound wave that has a frequency of 440 Hz. To do that we will determine the wavelength using the following formula:

Where:

The speed of sound at 20°C is equal to:

Now, we substitute the values:

Solving the operations:

Therefore, the distance from crest to crest is 0.78 meters.

Now, we are asked to determine the time it takes the string to go from the crest to the trough. To do that we will determine the period first using the following formula:

Now, we substitute the frequency:

Now, since the time it takes to go to crest to trough is half the time it takes the wave to go from crest to crest we divide the result by two:

Therefore, the time is 0.0012 seconds.

To determine the rate at which heat needs to be removed from the water in order to keep its temperature constant at 50°C, we can use the principles of heat transfer and energy conservation.

First, let's calculate the heat transferred from each ball during the quenching process. We can use the equation:

Q = mcΔT

Where Q is the heat transferred, m is the mass of the ball, c is the specific heat capacity of brass, and ΔT is the change in temperature.

Given that the diameter of the ball is 5 cm, the radius (r) is 2.5 cm or 0.025 m. The volume of the ball is:

V = (4/3)πr^3

The mass can be calculated using the density formula:

m = ρV

Where ρ is the density of brass.

Now, we can calculate the mass of each ball and the total heat transferred from all the balls in 2 minutes.

Let's assume there are 100 balls per minute, so in 2 minutes, we have 200 balls.

Using the given values:

Density of brass (ρ) = 8522 kg/m^3

Specific heat capacity of brass (c) = 0.385 kJ/kg • °C

Initial temperature of the balls (T1) = 120°C

Final temperature of the balls (T2) = 74°C

For each ball:

V = (4/3)π(0.025)^3

m = ρV

Q = mcΔT

Calculate the total heat transferred:

Total heat transferred = Q × Number of balls

Finally, to determine the rate at which heat needs to be removed from the water, we divide the total heat transferred by the duration of quenching (2 minutes).

Rate of heat removal = Total heat transferred / Quenching time

Please note that the specific heat capacity is given in kJ/kg • °C, so we need to convert the mass of the ball from kg to grams for consistent units. Performing these calculations will provide the rate at which heat needs to be removed from the water.

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The equivalent equation for V is V = m/d.

The density of a substance is the connection between the mass of the substance and what sort of space it takes up (quantity). The mass of atoms, their length, and how they may be organized decide the density of a substance.

Density is a vital concept because it lets us decide what materials will drift and what substances will sink whilst positioned in a liquid.

The density will increase as pressure increases. Altitude and climate structures can alternate the air's strain. As you move better, the air's strain decreases from around 1,000 millibars at sea level to 500 millibars at around 18,000 ft.

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The average power developed by the boy during the climb is approximately 29.4 W.

In physics, the amount of energy transferred or converted per unit time is called power.

total height = number of steps x height of each step

total height = 30 x 0.15 m = 4.5 m

Given, time = 60 s

As power = work done / time

work done = force x distance

force = mass x gravity

mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).

force = 40 kg x 9.81 m/s² = 392.4 N

The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m

work done = force x distance

work done = 392.4 N x 4.5 m = 1765.8 J

power = work done / time

power = 1765.8 J / 60 s

power ≈ 29.4 W

Therefore, the average power developed by the boy during the climb is approximately 29.4 W.

As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.

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A scientist studying the milky way galaxy notices a bright light in the sky, I and II provides information would she need to prove that the object is a comet and not a star.

Since we are viewing the galaxy edge on and from within, we perceive the galactic disk as a band that surrounds the entire sky. Depending on the time of year and where you are on Earth, you can see different portions of the disk, but you can always see some of it.

Ice, dust, and tiny rocks or particles are the main components of comets. They are included in the solar system because they orbit the sun.

They become heated by solar radiation as they approach the sun and begin to release gases that were initially condensed. The comet's tail glows brightly as a result of the gas release.

They produce a bright coma that can be several times the diameter of Earth when they have warmed up.

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Answer:

Explanation:

The question is incomplete as it does not have the options which are:

deciduous forest

taiga (boreal forest)

temperate rainforest

tropical rainforest

Answer:

Taiga (boreal forest)

Explanation:

A Biome refers to the habitat which is occupied by flora and fauna living in similar conditions.  These biomes are distinguished based on many features like precipitation, temperature and many other physical factors.

In the given question, the biome which receives an annual rainfall of 35 to 100 cm annually and is mostly covered by the coniferous trees is known as "Taiga biome" which is also known as Boreal forest.

The Taiga biome is one of the largest terrestrial biomes which is present in Eurasia and North America. The biome is characterised by the conifers trees and therefore is also known as the Coniferous trees.

Thus, Taiga (boreal forest) is the correct answer.

Answer: Taiga(boreal forest)

Explanation:

A rational function attains a horizontal asymptote when the degree of the numerator is less than or equal to the degree of the denominator.

Let's consider a rational function f(x) with numerator N(x) and denominator D(x). If the degree of N(x) is less than the degree of D(x), then the horizontal asymptote is y = 0. This is because as x approaches infinity or negative infinity, the higher degree terms in the denominator will dominate, causing the function to approach zero. If the degree of N(x) is equal to the degree of D(x), then the horizontal asymptote is determined by the ratio of the leading coefficients of the numerator and denominator. Let's say the leading coefficient of N(x) is a and the leading coefficient of D(x) is b. In this case, the horizontal asymptote is y = a/b. As x approaches infinity or negative infinity, the ratio of the leading coefficients determines the value that the function approaches. A rational function attains a vertical asymptote when the denominator becomes zero at certain values of x. To determine the vertical asymptote, we find the values of x that make the denominator zero and take the limit of the function as x approaches those values. If there is a factor (x - c) in the denominator, where c is a constant, then x = c is a vertical asymptote. As x approaches the value c, the function approaches positive or negative infinity, depending on the signs of the coefficients of the terms in the numerator.

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The question is incomplete as it does not have the options which are:

The waves have a trough.

Particles move only small distances.

particles travel the length of the wave, moving in an up-and-down motion.

The waves have a crest.

The energy is transferred perpendicular to the direction of the wave motion.

Answer:

Explanation:

Transverse waves are the waves which can be characterised easily by their oscillation in a perpendicular direction to the path of the wave propagation.

The particle follows the wave nature and moves only to a small distance like ripples in the water and these waves possess the trough, the lower part and the crest the upper part.

These waves can be observed in ripples of the water, in a string of the guitar while playing and the electromagnetic waves.

Thus, the selected options are correct.

The inductance (L) of a series RL circuit is 0.36 H, which represents the property of the circuit to oppose changes in current flow by storing energy in a magnetic field.

In a series RL circuit, the inductance (L) affects the rate at which the current changes when the circuit is connected to a voltage source. To find the inductance, we need to consider the time it takes for the current to reach one-third of its final value after connecting the circuit to a battery.

Given:

Resistance (R) = 1.0 kW (kilowatts) = 10³ Ω (ohms)

Time (t) = 30 µs (microseconds) = 30 × 10⁻⁶ s (seconds)

The time constant (τ) of an RL circuit is given by the formula:

τ = L/R

To find the inductance (L), we can rearrange the formula as:

L = τ × R

Since we are given the time (t) it takes for the current to increase to one-third of its final value, we can calculate the time constant (τ) using the formula:

τ = t / ln(3)

Substituting the values, we have:

τ = (30 × 10⁻⁶ s) / ln(3)

Now, we can calculate the inductance (L) by multiplying the time constant (τ) by the resistance (R):

L = τ × R = (30 × 10⁻⁶ s) / ln(3) × 10³ Ω = (30 × 10⁻³ Ω·s) / ln(3)

Evaluating this expression, we find that the inductance (L) of the series RL circuit is approximately 0.36 H (henries).

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The surface area of the right side of the box is 0.109376 m², The electric flux through the right side of the box is 146.9552 Nm²/C, The electric flux through the top side of the box is 311.298 Nm²/C, The electric flux through the bottom side of the box is 311.298 Nm²/C., The electric flux through the back side of the box is 2290.1376 Nm²/C and The total charge enclosed by the Gaussian box is 8023.472 nC

A Gaussian box is located in a region of space where there is a non-uniform electric electric field.

The box has a length of L=80.4 cm, a width of w=55.2 cm, and a height of h=19.8 cm.

The electric field has the following magnitudes at different locations in space:•

At the right side of the box, the field has a magnitude of E1 = 1345 N/C.• At the top, bottom, front, and back sides of the box, the field has a magnitude of E2 = 2847 N/C.• At the left side of the box, the field has a magnitude of E3 = 4249 N/C.

The surface area of the right side of the box = A = wh= 55.2 cm × 19.8 cm = 1093.76 cm² = 0.109376 m².

The electric flux through the right side of the box is Φ1 = E1 × AΦ1 = 1345 N/C × 0.109376 m² = 146.9552 Nm²/C

The electric flux through the top side of the box is Φ2 = E2 × AΦ2 = 2847 N/C × 0.109376 m² = 311.298 Nm²/C.

The electric flux through the bottom side of the box is Φ2 = E2 × AΦ2 = 2847 N/C × 0.109376 m² = 311.298 Nm²/C.

Φ2 = E2 × AΦ2 = 2847 N/C × 0.804 m² = 2290.1376 Nm²/C.

The electric flux through the back side of the box is Φ2 = E2 × AΦ2 = 2847 N/C × 0.804 m² = 2290.1376 Nm²/C.

The electric flux through the left side of the box is Φ3 = E3 × AΦ3 = 4249 N/C × 0.109376 m² = 465.31024 Nm²/C.

We can find the total charge enclosed by the Gaussian box using Gauss' law, which states that the total flux through the surface of a closed Gaussian surface is proportional to the charge enclosed by the surface.

q = ε0Φ

Where q is the charge enclosed by the Gaussian box, Φ is the total electric flux through the box, and ε0 is the electric constant.

Substituting the given values, we get

q = ε0Φq = (8.85 × 10⁻¹² C²/Nm²)(146.9552 Nm²/C + 2 × 311.298 Nm²/C + 2 × 2290.1376 Nm²/C + 465.31024 Nm²/C)q = 8.023472 × 10⁻⁹ C or 8023.472 nC

Therefore, the total charge enclosed by the Gaussian box is 8023.472 nC.

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The expression for induced current I(t) is given by I(t) = -0.03136 - 0.03136t and the value of I at t = 10s is -0.3456 A.

We know that induced emf is given as,e= -dΦ/dt

Where Φ is the magnetic flux.

The flux linkage of the coil is, Φ=NAB

where N is the number of turns, A is the area of the coil, and B is the magnetic field.

e= -N dΦ/dt

Now, the magnetic field is given as,B= 0.020t+ 0.010t²

The area of the coil is,A= πr²= π(2.5×10⁻²m)²= 1.96×10⁻³ m²

Now, the flux linkage is,Φ= NBA= (20)(1.96×10⁻³ m²)(0.020t+0.010t²)= 7.84×10⁻⁴t + 3.92×10⁻⁴t²

The induced emf is,e= -N dΦ/dt= -20 dΦ/dt= -20(7.84×10⁻⁴+ 7.84×10⁻⁴t)= -1.568×10⁻²- 1.568×10⁻²t

The current induced is given as,I= e/R= (-1.568×10⁻²- 1.568×10⁻²t)/0.50I(t)= -0.03136- 0.03136t

When t= 10s,I(t=10s)= -0.03136- 0.03136(10)= -0.3456 A

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Answer:

1/3

Explanation:

Velocity ratio = distance moved by effort / distance moved by load

A planes average speed between two cities is 610 km/hr. If the trip takes 2. 25 hrs, then the distance covered by a plane is  1372.5 kilometers.

To calculate the distance the plane flies, we can use the formula:

Distance = Speed × Time

Given that the average speed of the plane is 610 km/hr and the trip takes 2.25 hours, we can substitute these values into the formula to find the distance.

Distance = 610 km/hr × 2.25 hrs

To multiply these values, we need to align the units correctly. By canceling out "hrs" in the numerator and denominator, we get:

Distance = 610 km × 2.25

Multiplying 610 km by 2.25 gives us:

Distance = 1372.5 km

Therefore, the plane flies a distance of 1372.5 kilometers.

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Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane The plane flies 1372.5 km

Let's find the solution to this problem .The formula for distance, speed and time isd

= s * there,

d = distance covered by the planes

= speed t

= time taken

Substituting the given values, we have610 × 2.25 = 1372.5 km

Hence, the plane flies 1372.5 km.

Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane

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Albert Einstein's 1905 theory of special relativity is one of the most important papers ever published in the field of physics. Special relativity is an explanation of how speed affects mass, time and space.

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Answer:  its C- Albert Einstein

Explanation: the person above me is right and I also got it right on the test.

Using the concepts of motion, we got that  is the acceleration of gravity on planet x in which  a 5.0 * 10^1 kg barbell can be lifted by exerting a force of only 180N.Minimal force needed in earth is   N.

We know very well that rate of change of momentum in per unit time is equal to the Force according to newton second law.

It means

F=dp/dt or in other words,we know that this F=ma

where m is the mass of the body and a is the acceleration.

So, in planet X, we are given that applied force is 180N and mass of the object is 50 kg

So applying the formula

=>F=ma

=>180=50×a

=>a=50/180

=>a=0.277m/s²

Now, the minimum force needed to lift the same object in earth is given by the same formula

=>F=ma but here a is gravity whose value is equal to 9.8

=>F=50×9.8

=>F=490N

Hence, on planet x, a 5.0 * 10^1 kg barbell can be lifted by exerting a force of only 180 n, the acceleration of gravity on planet x is 0.277m/s² and if the same barbell is lifted on earth, minimal force is needed is 490N.

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Answer:

KE increases and PE decreases.

Explanation:

First, note that the formula for kinetic energy is KE = (1/2)mv^2 where m is the mass and v is the velocity and the formula for potential energy is PE = mgh where h is the height it is at. Since mass and the acceleration provided by gravity doesn’t change, we can disclude that our conclusion. We know that the height (h) and velocity (v) does change, so let’s look at that. As you continue down the slope, you accelerate due to gravity. Thus, velocity increases and KE increases. As you continue down the slope, you get closer to the ground, hence h decreases and PE decreases.

I hope this helped! :)

Answer:

About 59.83 kg

Explanation:

The formula for kinetic energy is \(KE = \frac{1}{2}mV^2\), where KE = Kinetic Energy in Joules (J), m = mass in kilograms (kg), and V = Velocity in meters per second (m/s).

In this problem, we are given the Kinetic Energy amount as 193 Joules and the Velocity as 2.54 m/s. Let's plug it into our equation

Now, let's solve this equation.

Step 1: Simplify both sides of the equation.

Step 2: Divide both sides by 3.2258.

We have that for the Question,it can be said that the field has a value of

From the question we are told

a small object with a charge of magnitude q creates an electric field. at a point 1.0 m to the north of the charge the field has a value of 2.0 n/c directed south. at a point 0.5 m to the west of the charge the field has a value of

Generally the equation for the electric field   is mathematically given as

\(E=\frac{q}{4\piE_0r^2}\)

Therefore

\(if E_A=3N/C\\\\E_B=\frac{3}{0.25}\\\\\frac{q}{4\piE_0}=3N/C\\\\\)

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Answer:

Explanation:

The displacement is a vector quantity, it tells how far away from a point a distance or a destination is

given that the distance covered are

50. km, 30. km, and 65 km

the displacement is expressed as

= 50+30+65

=145km

We actually performed straight addition because in all the movement the antarctic explorers did not record any deviation from the initial direction, hence they maintained a linear movement from the beginning to the end

Answer:

I'm fairly certain it's 1,800

Explanation:

The efficiency of the wedge with force F=900 N displaces the wedge 0.10 m is 55.55%  or 56%.

The efficiency of the machine equals the ratio of output energy and input energy. It is also defined as the ratio of work done on a load by the machine to the work done on the effort by the machine.

A load is defined as the weight lifted by the machine. The effort is defined as the force applied to bring the desired change in the load. Work done is defined as the product of force and displacement.

The efficiency, η = Output power / Input power, and the highest efficiency of the machine is equal to one. The efficiency of the machine has no unit. The efficiency η = (Actual work done / Ideal work done) × 100.

From the given,

Force = 900 N

Displacement = 0.1 m

Work done = F × s = 900×0.1 = 90 J

Actual work done = 50 J

Efficiency,η = (50/90) × 100

           η  = 55.55 %

Thus, the efficiency of the wedge is 55.56%.

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Answer:base

Explanation:apex

Answer:

1,211.1 kg.

Explanation:

the force of gravity is less on the moon than on earth, so if the man can lift 200kg on earth, he could lift a greater amount on the moon because there is less resistance from gravity.

To know the amount of mass he can lift on the moon, we first need to know the amount of weight that is equivalent to those 200kg here on earth. This because the weight of the object is equal to the force that must be applied to lift it, and that force is applied by the man and it will be the same here and on the moon.

We calculate weight using the formula:

\(w=mg\)

where \(w\) is the weight of the object (the force with which the earth attracts the object) \(m\) is the mass and g the acceleration of gravity.

so

\(w=200g\)

for earth the acceleration due to gravity is:  \(g=9.81m/s^2\)

thus:

\(w=(200kg)(9.81m/s^2)\\w=1962N\)

now we use this value to calculate the mass he can lift on the moon, since for the moon \(g=1.62m/s^2\).

we use the same equation, w =mg substituting w = 1962N and \(g=1.62m/s^2\):

\(w=mg\\\\1962N=m(1.62m/s^2)\\\\m=\frac{1962N}{1.62m/s^2}\\\\ m=1,211.1kg\)

he can lift 1,211.1 kg.

You can also find the result using the approximate value of the acceleration of gravity on the moon as g/6, where g is the acceleration on earth.