Please help need this asap
Gravity on the surface of the moon is only 1/6
as strong as gravity on the Earth.
A) What is the weight of a 35 kg object on the
Earth? The acceleration of gravity is 10 m/s^2
Answer in units of N.
B) What is the weight on the moon?
Answer in units of N.
C) What is the mass on the earth?
Answer in units of kg.
D) What is the mass on the moon?
Answer in units of kg.

Answer:

\((75.0 \times 30) + (60.0 \times 6.0) = (75.0 \times V) + (60.0 \times 0) \\ 2250 + 360 = 75V \\ 75V = 2610 \\ V = 34.8 \: m {s}^{ - 1} \)

Answer:-2.86*10⁻⁴

Explanation: Use the equation change in volume = (change in pressure * original volume) / Bulks Modulus. ΔV = (-Δp*V₀) / B

Plugging in your numbers, you should get ΔV = (-2.29*10⁷*1) / (8*10¹⁰) = -2.86*10⁻⁴

ΔP = P₂-P₁  ----> ΔP = 2.30*10⁷ - 1.00*10⁵ = 2.29*10⁷

Answer:

75kgms/2

Explanation:

weight=mass*g=7.5kg*10ms/1=75

Answer:

The answer should be 3-At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.

Answer:

3. At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.

Answer:

Explanation:

A CD has an OD of 120 mm and an ID of 15 mm and has a mass between 14 and 33 grams. Let's call it m

Lets call the outer and inner radii R and r respectively

Find the moment of inertia about a line perpendicular to the surface of the disc through its center. We can integrate or look up the result from standard tables

I = ½m(R² + r²)

then use the parallel axis theorem to shift the position of the axis

I = ½m(R² + r²) + md²

where d is the distance of the shift. In this case d = R

I = ½m(R² + r²) + mR²

I = m(1.5R² + 0.5r²)

If we select a mass of say 20 grams

I = 0.020(1.5(0.060²) + 0.5(0.0075²))

I = 0.0001085625 kg•m²

The potential energy stored in stretched spring is 1 Joule with the given data.

The force required to hold a spring in stretched spring is 10 N

As we are to calculate potential energy,

Force = \(k * x\)= 10 N

Displacement is x = 0.20 m

Potential Energy can be mathematically defined as:

Ep =\((F * x)/2\)

If we place values given in question in the above equation:

Ep =\((10*0*20)/2\)

Ep = 2/2

Ep = 1 Joule

Therefore, potential energy stored in stretched spring turns out to be 1 Joule based on the data that we have.

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Answer:

0.6

Explanation:

There are four forces on the box:

Weight force mg pulling down,

Normal force N pushing up,

Tension force T pulling 30° above the horizontal,

and friction force Nμ pushing to the left.

Sum of the forces in the y direction:

∑F = ma

N + T sin 30° − mg = 0

N = mg − T sin 30°

Sum of forces in the x direction:

∑F = ma

T cos 30° − Nμ = 0

Nμ = T cos 30°

μ = T cos 30° / N

μ = T cos 30° / (mg − T sin 30°)

Plug in values:

μ = (250 N) cos 30° / ((50 kg) (9.8 m/s²) − (250 N) sin 30°)

μ = 0.59

Rounded to one significant figure, the coefficient of friction is 0.6.

The coefficient of kinetic friction between the box and floor is :  0.6

Given data :

Mass of box = 50 kg

Angle = 30°

Force required on rope  ( T ) = 250 N

speed = 20 m/s

g = 9.81 m/s²

Calculate the value of the coefficient of kinetic friction

First step : determine sum of forces in the y-direction

∑ Fy = ma

N  +  T sin 30°  - mg = 0

∴ N = mg - Tsin 30° ----- ( 1 )

Next step : Determine the sum of forces in the x-direction

∑ Fx = ma

T cos 30° - Nμ = 0

∴ μ = T cos 30° / N  ----- ( 2 )

where ; N = mg - T sin 30°

Final step : Determine the coefficient of kinetic friction between the box and floor

Back to equation ( 2 )

μ = T cos 30° / ( mg - T sin 30° )

    = 250 cos 30° / ( ( 50 * 9.81 ) - 250 * sin 30° ))

    = 0.59 ≈ 0.6

Hence we can conclude that The coefficient of kinetic friction between the box and floor is :  0.6

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The given magnitude of the two charges are 6μc and they exert a force of 0.7N on each other. We need to find the distance of separation between the particles.

By Coloumb's Law :-

\(\sf\longrightarrow F =\dfrac{1}{4\pi\epsilon_0} \dfrac{q_1q_2}{r^2} \)

where

Substitute the respective values,

\(\sf\longrightarrow \) 0.7 = {(9*10⁹) (6*6) (10-⁶ *10-⁶) }/ r²

\(\sf\longrightarrow \) r² = (36*9 * 10-³)/0.7

\(\sf\longrightarrow \) r =√{ 36*9*10-³)/√7 m

\(\sf\longrightarrow \) r = 6* 3* 10-¹ /√70 m

\(\sf\longrightarrow \) r = 0.21 m

And we are done!

Answer:

V₁ = 48 m/s

Explanation:

Using the Conservative Law of Momentum:

∑Qₓ = 0

Q₁ + Q₂ = 0

Q₁ = Q₂  (In absolute values)

Where:

Q₁: right before the impact

Q₂: right after the impact

So:

Q₁ = Q₂

m₁*V₁ + m₂*V₂ = m₁*V + m₂*V  (Because both ball and man moves together)

5 * V₁ + 75 * 0 = (5 + 75)*3

5V₁ = 80 * 3

V₁ = 240/5

V₁ = 48 m/s

Answer:

Atoms in a solid are close and tightly packed.They vibrate about fixed positions .They are arranged in a regular LATTICE.They cannot be compressed nor can they change shape.They have strong forces of attraction between them so they cannot move in order to move they have to gain ENERGY. Whereas the atoms in a liquid are not that close compared to the ones in solid.They take the shape of the container but their volume remains fixed.They have weak forces of attraction between atoms and have more energy which enables them to move.

Explanation:

Answer: A and D

a. Many objects move in arcs of circles or complete circles at times, and polar coordinates allowthe motion of such objects to be comprehended more easily. Some of Newton's laws in certaincases, such as calculation ofg from first principles, are much easier to calculate using polar coordinates.

b. "These coordinates are just used to confuse students.

c. ""Physics teachers are helping math teachers by getting students to practice theirtrigonometry.

d. ""In some cases, such as addition of forces, where a force magnitude is specified, it is simpler todescribe the forces in polar coordinates and be able to convert to the xy representation.

Explanation:

(A). Any force possessing a fixed magnitude and direction, it's always important to describe the for exactly as it is and also be able to convert it from one coordinate representation to another.

(D). Anything which involves radial motion(this is a motion along a radius) or motion along an arc of a circle or ellipse, this kind of motion is best explained and easily understood when in polar coordinates.

This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

According to Newton's Law of Gravitation:

\(F=\frac{Gm_1m_2}{r^2}\)

where,

Therefore,

\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)

F = 1355.78 N = 1.356 KN

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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,

The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

\(\rm F= \frac{Gm_1m_2}{r^2}\)  , Where

\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)

Putting values in the above formula:

\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer:

no

Explanation:

most psychologists are skeptical of ESP and believe it's not real. There actually more skeptical of ESP than other scientists.

a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Answer:

The angular acceleration of CD player is \(13.93\ rad/s^2\).

Explanation:

Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.

It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :

\(a=\dfrac{\omega_f-\omega_i}{t}\\\\a=\dfrac{41.8-0}{3}\\\\a=13.94\ rad/s^2\)

So, the angular acceleration of CD player is \(13.93\ rad/s^2\).

Answer:

5 years old 7 months and 21 days

Explanation:

Answer:

lina marcela medina de jurado

Two identical metal spheres carry charges of + q and - 2q respectively.

It is given that initially sphere has different charges and momentarily brought in contact with each other.

When the spheres are touched then charge is equally redistributed among spheres such that now they possess the equal amount of charges.

When they are suspended from the thread their separation increases compared to previous situation because now the value of force increases because of the change in the product of charges.

For example, Suppose initially they possess 15 C and 17 C charge and after redistribution they both possess 16 C  of charge.

Product of charges=15*17=255

Final Product of charges=16*16=256

As force depends upon the Product of the charges so there will be more repulsive force.    

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(1) The speed of light through vacuum is 3 x 10⁸ m/s.

(2) The speed of light in air at 30⁰C is 350 m/s.

(3) The speed of light in air at 0⁰C is 330 m/s.

(4) The transparent substance is glass.

(5) The color of light observed is red.

(6) The energy of a photon of red light is 2.85 x 10⁻¹⁹ J.

The speed of light through vacuum is 3 x 10⁸ m/s.

The speed of light in air at 30⁰C is 350 m/s.

The speed of light in air at 0⁰C is 330 m/s

n = speed of light in vacuum/speed of light in the substance

n = ( 3 x 10⁸ m/s) / ( 2 x 10⁸ m/s)

n = 1.5

The refractive index of glass is 1.5, thus, the transparent substance is glass.

f = v/λ

f = (3 x 10⁸) / (6.8 x 10⁻⁷)

f = 4.41 x 10¹⁴ Hz

The color of light observed is red based on the frequency and wavelength.

E = hf

E = (6.626 x 10⁻³⁴)(4.3 x 10¹⁴)

E = 2.85 x 10⁻¹⁹ J

Thus, the speed of light through vacuum is 3 x 10⁸ m/s.

The speed of light in air at 30⁰C is 350 m/s.

The speed of light in air at 0⁰C is 330 m/s.

The transparent substance is glass.

The color of light observed is red.

The energy of a photon of red light is 2.85 x 10⁻¹⁹ J.

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Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

Answer:

the commutator

Explanation:

took the quiz!

The part of the motor that causes the consistent motion of the electromagnet in the same direction is the commutator. The correct answer is C. The commutator.

The commutator is a critical component in a motor that enables the conversion of electrical energy into mechanical energy. It consists of a set of copper segments connected to the rotating coil or armature of the motor. As the armature spins, the commutator ensures that the electrical current flowing through the coil changes direction at the right time.

This change in current direction creates a rotating magnetic field that interacts with the permanent magnets, resulting in a continuous rotational motion of the motor. In essence, the commutator acts as a switch, controlling the flow of current and ensuring the electromagnet rotates in a consistent direction.

Therefore, the part of the motor that causes this motion is C. The commutator.

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Answer:

420

Explanation:

Heat required(Q)= m*c*

So Q=21000J

Power=50Wt

time= Q/Power

time=21000/50 sec

time=420seconds

Answer:

C)focusing on one goal at a time

Explanation:

Self-modification programs could be regarded as a program that help individual in managing unwanted as well as dysfunctional behavioral responses whenever they are going through a problem and try to deal with it. For instance the dysfunctional behavioral response for someone with a panic attack is avoidance. Some of the the steps that are involved in in a self-modification program are;

✓ specifying target behavior ✓designing a program

✓ gathering data about target behavior

Answer:

c

Explanation:

on edge 2020

Answer:

\(\mu=0.185\)

Explanation:

From the question we are told that:

Mass \(m=17kg\)

Force \(F=33N\)

Velocity \(v=1.6m/s\)

Distance \(d= 9.8m\)

Generally the equation for Work done is mathematically given by

 \(W=\triangle K.E+\triangle P.E\)

Where

 \(\triangle K.E=(F-F_f)*2\)

 \(F_f=F+\frac{\triangle K.E}{d}\)

 \(F_f=33+\frac{0.5*17*1.6^2}{9.8}\)

 \(F_f=30.8N\)

Since

 \(f = \mu*m*g\)

 \(\mu= 30.8/(m*g)\)

 \(\mu= 30.8/(17*9.81)\)

 \(\mu=0.185\)

Answer:

The mass of the other ball is 397.775 kg.

Explanation:

Gravitation is the force of mutual attraction that bodies experience due to the fact that they have a certain mass.

The universal law of gravitation is a classical physical law that describes the gravitational interaction between different bodies with mass.

The law was formulated by Newton, who deduced that the force with which two bodies of different masses are attracted only depends on the value of their masses and the square of the distance that separates them.

In other words, the Law of Universal Gravitation predicts that the force exerted between two bodies of masses M1 and M2 separated by a distance "d" is proportional to the product of their masses and inversely proportional to the square of the distance, that is:

\(F=G\frac{M1*M2}{d^{2} }\)

where:

In this case:

Replacing:

\(1.65*10^{-7} N=6.67384*10^{-11} \frac{N*m^{2} }{kg^{2} }\frac{81 kg*M2}{(3.61 m)^{2} }\)

Solving for M2:

\(M2=\frac{1.65*10^{-7} N*(3.61 m)^{2}}{6.67384*10^{-11} \frac{N*m^{2} }{kg^{2} }*81 kg}\)

M2= 397.775 kg

The mass of the other ball is 397.775 kg.

Explanation:

I have only 4 of them ,hope they help

the characteristics of the graphs we can find that the correct answer is:

      B.  error bars

Graph is a method of grouping the experimental results in such a way that they can be easily analyzed, in the different types of graphs the experimental values ​​of the points are plotted and if the errors of the measurements at each point are known.

The errors of each point are plotted in the form of bars bounded both by excess and by default, above each plotted point.

Let's analyze the different claims;

A. false The y-axis labels written on this axis

B. True. These are the error bar at each experimental point

C. False. They are not adornments or distractions, they are an important part of the information on the chart.

D. False. The division marks are on the y-axis

In conclusion, using the characteristics of the graphs, we were able to find the correct answer is:

    B.  Error bars

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Answer:

Acceleration= 0.52 m/s²

The scale will read a weight of 463.5 N during the elevator's acceleration.

To calculate the weight that the scale reads during the elevator's acceleration, we need to consider the forces acting on the child.

Weight is a force caused by the gravitational pull of the Earth on an object. It is given by the formula:

Weight = mass × gravitational acceleration

The mass of the child is given as 45.0 kg. The gravitational acceleration is approximately 9.8 m/s² on the surface of the Earth.

However, during the elevator's acceleration, there will be an additional force acting on the child due to the acceleration. This force is given by Newton's second law:

Force = mass × acceleration

In this case, the acceleration is the difference in velocity divided by the time taken, which is (3.0 m/s - 1.0 m/s) / 4.00 s = 0.5 m/s².

So, the additional force acting on the child during the acceleration is:

Additional Force = mass × acceleration = 45.0 kg × 0.5 m/s² = 22.5 N

Now, we can calculate the total force acting on the child, which includes both the weight and the additional force:

Total Force = Weight + Additional Force

Since the weight is equal to mass × gravitational acceleration, we can rewrite the equation as:

Total Force = mass × gravitational acceleration + Additional Force

Total Force = (45.0 kg × 9.8 m/s²) + 22.5 N

Total Force = 441 N + 22.5 N

Total Force = 463.5 N

Therefore, the scale will read a weight of 463.5 N during the elevator's acceleration.

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