PLEASE HELP MEEEEEEE

The correct answer is (X) |A|x = 5t, y = 2 - 5t, z = t.

Parametric equations of the line, we need to find a direction vector for the line that is parallel to both planes. The direction vector can be found by taking the cross product of the normal vectors of the two planes.

The normal vectors of the given planes are n1 = (-1, 1, 3) and n2 = (-5, 3, 4).

Step 1: Take the cross product of the normal vectors: n = n1 x n2 = (1, -8, 8).

Step 2: The direction vector for the line is the normalized form of n, which is d = (1/3) * (1, -8, 8) = (1/3, -8/3, 8/3).

Step 3: Write the parametric equations of the line using the point (0, 2, 1) and the direction vector d:

x = 0 + 5t = 5t,

y = 2 + (-8/3)t = 2 - 5t,

z = 1 + (8/3)t = 1 + 8t/3.

Therefore, the correct answer is |A|x = 5t, y = 2 - 5t, z = t.

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The total amount that you need to pay for the lunch after the sales tax and the tip will be $ 42.85.

We are given that:

The cost of lunch = $ 32

Sales tax = $ 4.45

Tip = 20 %

So, the tip will be calculated by finding the percentage of cost that you are planning to pay has a tip.

Tip = 20 % of $ 32

Tip = 20 / 100 × $ 32

Tip = 0.2 × $ 32

Tip = $ 6.4

Total amount needed to be paid for the lunch = $ 32.00 + $ 4.45 + $ 6.40

Total amount = $ 42.85

Therefore, we get that, the total amount that you need to pay for the lunch after the sales tax and the tip will be $ 42.85.

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Expression of the rate per minute at which air freshener dispenses sprays is equal to fraction 4 over 30.

As given,

The graph represents

x-axis: Time in minutes

y-axis: Number of sprays

Ordered pairs ( 30,4) ,(60, 8) ,( 90,12), and ( 120, 16)

Consider any two points ( 90,12) ,(120 , 16)

Expression of the rate per minute=( y₂ -y₁)/(x₂ -x₁)

                                                     =( 16 - 12)/(120 -90)

                                                     = 4/30

Therefore, expression of the rate per minute at which air freshener dispenses sprays is equal to fraction 4 over 30.

The complete question is :

The graph shows the number of sprays an automatic air freshener dispenses, y, in x minutes: A graph is shown. On the x-axis, the values are from 0 till 150 in increments of 30 for each grid line, and on the y-axis, the values are from 0 to 20 in increments of 4 for each grid line. The title of the graph on the x-axis is Time in minutes, and the title on the y-axis is Number of Sprays. A line is shown connecting ordered pairs 30, 4 and 60, 8 and 90, 12 and 120,16. The title for the graph is Dispense Rate. Which expression can be used to calculate the rate per minute at which the air freshener dispenses sprays?

fraction 4 over 30

fraction 30 over 4

fraction 30 over 16

fraction 16 over 30

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An earthquake that is twice as powerful as a 6.1 magnitude earthquake would register 6.7 on the Richter scale.

The Richter scale measures the magnitude of an earthquake based on the logarithm of the amplitude of seismic waves. Each increase of one on the Richter scale represents a ten-fold increase in the amplitude of the seismic waves.

Therefore, an earthquake that is twice as powerful as a 6.1 magnitude earthquake would have seismic waves with amplitudes that are ten times greater, which would correspond to a 6.1 + 1 = 7.1 magnitude earthquake. However, the Richter scale is limited to 10 as its maximum value, so the earthquake cannot have a magnitude of 7.1.

Instead, we need to take into account that a magnitude 7.0 earthquake is ten times more powerful than a magnitude 6.0 earthquake. Therefore, an earthquake that is twice as powerful as a 6.1 magnitude earthquake would register 6.7 on the Richter scale, which is halfway between 6.0 and 7.0.

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The value of y₀ will the solution have a vertical asymptote at t = 7 and a t-interval of existence -infinity < t < 7 is y₀ = 1/14

We know that the solution of the initial value  problem y' = 2y2, y(0) = yo. is given by \($\frac{1}{y} = -2t + \frac{1}{y_0}$\), which simplifies to \(y = \frac{y_0}{1 - 2ty_0}$\)

For a vertical asymptote to occur at t = 7, the denominator of y must be zero at t = 7, which means 1 - 2ty₀ = 0 has to hold at t = 7. This gives us

y₀= 1/14.

To ensure that the solution exists for -∞<t<7, we need to make sure that the denominator 1 - 2ty₀ is never zero in that interval. Since y₀ > 0, we have

1 - 2ty₀ < 1, which means the denominator is always nonzero for any value of t in the interval -∞< t < 7.

Therefore, the only value of y₀ that satisfies both conditions is y₀ = 1/14

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Answer:

g=m/R-h²

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Answer:

g=m/R-h²

Step-by-step explanation:

Rg = m+h²g

Rg-h²g=m

by transposing h²g to the other side of the equation it has acquired a negative sign.

after this you factorise the left side.

g(R-h²)=m

now you divide both sides of the equation by R-h². The reason for doing so is because you're trying to single out g.

g=m/R-h²

a)  The Mean Value Theorem for Integrals is proved.

b)   The Mean Value Theorem for Integrals does not hold for this function on this interval because it is not continuous.

(a) The Mean Value Theorem for Integrals states that for a continuous function f(x) on the closed interval [a, b], there exists a value c in [a, b] such that:

∫(a to b) f(x) dx = f(c) * (b - a)

To prove this theorem, we will use the following steps:

Step 1: Consider the function F(x) = ∫(a to x) f(t) dt.

Step 2: By the Fundamental Theorem of Calculus, F'(x) = f(x) for all x in [a, b].

Step 3: Apply the Mean Value Theorem for Derivatives to the function F(x) on the interval [a, b]. This yields the existence of some c in [a, b] such that:

F(b) - F(a) = F'(c) * (b - a)

Step 4: Substituting F'(x) = f(x) and simplifying gives:

∫(a to b) f(x) dx = f(c) * (b - a)

Therefore, the Mean Value Theorem for Integrals is proved.

(b)

The continuity assumption in the Mean Value Theorem for Integrals is necessary for the theorem to hold.

For example, consider the function f(x) = |x| on the interval [-1, 1]. This function is not continuous at x = 0, as the left and right limits do not match.

However, when we calculate the integral using the formula from the Mean Value Theorem for Integrals, we get:

∫(-1 to 1) |x| dx = ∫(0 to 1) x dx + ∫(-1 to 0) -x dx

= (1/2)x^2 |0^1 + (-1/2)x^2 |-1^0

= 1/2 + 1/2

= 1

But there is no value c in [-1, 1] such that f(c) * (1 - (-1)) = 1. Therefore, the Mean Value Theorem for Integrals does not hold for this function on this interval because it is not continuous.

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Answer:

Below

Step-by-step explanation:

First let's determine the slope if thus function

Let m be the slope of this function

m = [0-(-4)]/ 2-0 = 4/2 =2

So our equation is:

y = 3x +b

b is the y-intercept wich is given by the image of 0

Here it's -4

So the equation is:

y = 2x-4 wich is also y = x-2 after simplifying

●●●●●●●●●●●●●●●●●●●●●●●●

A line that is parallel to this one will have the same slope.

Examples:

● y= 2x+3

● y = 2x-7

■■■■■■■■■■■■■■■■■■■■■■■■■■

A line that is perpendicular to this one and has a slope m' satisfy this condition:

m*m'= -1

m'= -1/m

m' = -1/2

So this line should have a slope that is equal to -1/2

Answers from the choices:

y = -1/2 x +1/2

y+1= -1/2 (x-3)

Use a second order difference scheme while adhering to the finite difference procedure we discussed in lecture, the rewritten initial value is cos(t)+C.

The k initial differences of a sequence or a function are involved in a difference equation of order k, just as the k first derivatives of a function are related in a differential equation of order k.

The two aforementioned relationships enable the transformation of a recurrence relation of order k into a difference equation of order k and, in the other direction, a difference equation of order k into a recurrence relation of order k. Every transformation is the inverse of every other transformation, and the sequences that satisfy the recurrence relation are the exact ones that provide the solution to the difference equation.

Calculations:

syms y(t) z(t)

eqns = [diff(y,t)==z, diff(z,t)==-y];

[ySol(t),zSol(t)] = dsolve(eqns)

ySol(t) = C

cos(t)+C

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Answer:

y=1/-2x+2.5

Step-by-step explanation:

Y=Mx+c

Mx(slope)=y2-y1/x2-x1= 6-2/-5-3 =4/-8= 1/-2

C(y-intercept)= replace one of of the points here to find C

2=1/-2(3)+c, c= 2.5

Final answer > y=1/-2x+2.5

The equation that correctly applies the distributive property of multiplication is C. ​(0.5⋅0.5)+(0.5⋅0.3)+(0.5⋅0.2)=0.5⋅(0.5+0.3+0.2)​.

The distributive property of multiplication indicates that a mathematical expression in the form of a(b + c) can also be expressed to be equal to ab + ac.

When doing multiplication operations involving addition or subtraction, the distributive property can be used because it yields the same solution.

(0.5⋅0.5)+(0.5⋅0.3)+(0.5⋅0.2) = 0.5⋅(0.5+0.3+0.2)​

= 0.5 x 0.5 + 0.5 x 0.3 + 0.5 x 0.2

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c. 89 rolls 5 extra dimes

40.2° is the best approximation for the measure of angle egf in triangle .

How do triangles work?

Angle EGF = x

Sin x = 12/18.6

Sinx ≈ 0.6452

x ≈ Sin⁻¹(0.6452).      Use a calculator.

x ≈ 40.18°

x ≈ 40.2°

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Brandon rode his bike 8.35 miles further than Randy.

To find out how much further Brandon rode his bike last month than Randy, you'll need to subtract Randy's miles from Brandon's miles using the given values.

Step 1: Identify the miles ridden by both Brandon and Randy.
- Brandon rode 56.28 miles.
- Randy rode 47.93 miles.

Step 2: Subtract Randy's miles from Brandon's miles.
- 56.28 miles (Brandon's miles) - 47.93 miles (Randy's miles) = 8.35 miles.

So, last month, Brandon rode his bike more than Randy.

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To answer your question, I would need more information about the terminal point and its relationship to the circle.

If you have a point on the circumference of a circle and you draw a line from the center of the circle to that point, the measure of the terminal point's vertical distance above the center of the circle in units of the radius of the circle can be found using trigonometry. Specifically, if the angle between the line and the horizontal axis is theta (in radians), then the vertical distance is given by:

vertical distance = sin(theta)

In this case, the vertical distance is measured in units of the radius of the circle.

The new velocity of the 4kg mass can be determined using the conservation of momentum equation, which states that momentum (m * v) is conserved before and after a collision.

The momentum of the 2 kg mass prior to the collision is (2 kg) * (5 m/s) = 10 kg m/s. Because the 2 kg mass reverses direction after the collision, its momentum is now -10 kg m/s. Thus, the sum of the two masses and velocities before and after the collision must be equal.

The total momentum before the collision is: 10 kg m/s + 0 kg m/s = 10 kg m/s. And the total momentum after the collision is: -10 kg m/s + (4 kg)Vf = (4 kg)Vf - 10 kg m/s where Vf is the velocity of the 4 kg mass after the collision

Therefore,  Vf = (10 kg m/s + 10 kg m/s) / 4 kg = 5 m/s, which means that v = 5 m/sec. Thus, the new velocity of the 4kg mass is 5 m/sec.

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Using Law of Cosines, the square root of a negative number is not a real number, there is no solution for x.

We can use the Law of Cosines to solve this problem. Let's label the distance between Samir and Ayisha as "x". Then, using the Law of Cosines, we have:

cos(18°) = (80² + x² - 82²) / (2 * 80 * x)

Simplifying this equation, we get:

cos(18°) = (x² - 2x + 3996) / (160x)

Multiplying both sides by 160x, we have:

160x * cos(18°) = x² - 2x + 3996

Simplifying, we get:

0 = x² - 2x + 3996 - 160x * cos(18°)

Now we can use the quadratic formula to solve for x:

\(x = [2 \pm \sqrt{(4 - 4(1)(3996 - 160cos(18^o))) ]} / 2\)

\(x = [1 \pm \sqrt{(1 - (3996 - 160cos(1^o°)))} ]\\x = [1 \pm \sqrt{(160cos(18^o) - 3995)]}\)

Plugging in the value of cos(18°) (which is approximately 0.951), we get:

\(x = [1 \pm \sqrt{(160(0.951) - 3995)}]x = [1 \pm \sqrt{(-2494.4)}]\)

Since the square root of a negative number is not a real number, there is no solution for x. Therefore, the problem may be incorrect or incomplete.

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Step-by-step explanation:

Since it is given that it costs $2.34 for every $1000 face value, and it was given that he wanted to buy a $75000 plan, multiplying $2.34 by 75 (75000 includes 75 $1000 face value), it should yield us the annual premium.  

2.34 * 75 = $175.50

We don't need to multiply it by 10 years as only the annual premium is being solved for.

Answer:

C $212.57

Step-by-step explanation:

I Just took the test on e2020

Mixture is kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container.

Sand and water are separated in this situation using filtering. The filter funnel, which is lined with filter paper, is filled with the sand and water mixture.

The paper allows the water to escape and accumulate in the beaker. Sand particles build up in the filter funnel because they can't pass through the filter paper. One of humankind's first methods of water treatment, distillation desalination is still a widely used treatment method today.

Many ancient civilizations employed this method to turn seawater into drinkable water aboard their ships. The differing densities of salt and sand are the basis for another physical separation technique. Sand has a density of 2.65 g/cm3, but salt has a density of 2.16 g/cm3. 

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Answer:

X=4,y=30

Step-by-step explanation:

given,

y=8x-2 ....(i)

3x+y=42...(ii)

now,

putting value of y in equation ii

we get,

3x+y=42

3x+(8x-2)=42

or,3x+8x=42+2

or,11x=44

or,X=4

again,

putting value of X in equation i

y=8x-2

=8×4-2

=30

The given problem is a 0-1 integer programming problem, which involves finding the maximum value of a linear objective function subject to a set of linear constraints, with the additional requirement that the decision variables must take binary values (0 or 1).

To solve this problem by implicit enumeration, we systematically evaluate all possible combinations of values for the decision variables and check if they satisfy the constraints. The objective function is then evaluated for each feasible solution, and the maximum value is determined.

In this case, there are three decision variables: x1, x2, and x3. Each variable can take a value of either 0 or 1. We need to evaluate the objective function 2x1 - x2 - x3 for each feasible solution that satisfies the given constraints.

By systematically evaluating all possible combinations, checking the feasibility of each solution, and calculating the objective function, we can determine the solution that maximizes the objective function value.

The explanation of the solution process, including the enumeration of feasible solutions and the calculation of the objective function, can be done using a table or a step-by-step analysis of each combination.

This process would involve substituting the values of the decision variables into the constraints and evaluating the objective function. The maximum value obtained from the feasible solutions will be the optimal solution to the problem.

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Answer:1

1. \(x = 30\)

2. ∠ABC = 120°, ∠BCD = 90°, ∠CDA = 60°, ∠DAB = 90°

Step-by-step explanation:

It's important to note here that the measure of all interior angles in a quadrilateral will add up to 360°

We know this using the formula\((n-2)\cdot 180\), a 4 sided figures angles will add up to

\((4-2)\cdot 180\\\\2\cdot 180\\\\360\)

This means that all of the angles (4x, 3x, 2x, 3x) will add up to 360.

\(4x + 3x + 2x + 3x = 360\)

Combine like terms:

\(12x = 360\)

Divide both sides by 12:

\(x = 30\)

We know now substitute x for 30 in for all of the side lengths.

∠ABC = 4x = \(4\cdot 30 = 120\)°

∠BCD = 3x = \(3\cdot 30 = 90\)°

∠CDA = 2x = \(2\cdot 30 = 60\)°

∠DAB = 3x = \(3\cdot 30 = 90\)°

Hope this helped!

Step-by-step explanation:

Now, all angles if summed up will equal 360°.

\(4x + 3x + 2x + 3x = {360}^ \circ\)

\( {12x}^{ \circ} = {360}^{ \circ} \)

\( \boxed{x = {30}^{ \circ} }\)

Now, we will find the Respective angles:-

ABC = 4x = 120°

BCD = 3x = 90°

CDA = 2x = 60°

DAB = 3x = 90°.

The equation that shows an example of the associative property of addition is:

\(\((-7+i)+7i = -7 + (i+7i)\)\)

According to the associative property of addition, the grouping of numbers being added does not affect the result. In this equation, we can see that both sides of the equation represent the addition of three terms:

\(\((-7+i)\), \(7i\),\)  and  \(\(i\).\)  The equation shows that we can group the terms in different ways without changing the sum.

The equation  \(\((-7+i)+7i = -7 + (i+7i)\)\)  demonstrates the associative property by grouping  \(\((-7+i)\)\) and  \(\(7i\)\)  together on the left side of the equation, and  \(\(-7\)\) and  \(\((i+7i)\)\)  together on the right side of the equation. Both sides yield the same result, emphasizing the associative nature of addition.

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The  inequality is Amount A= 15.5 x where x>6.

What is inequality?

An inequality compares two values ​​and indicates whether one is less than, greater than, or simply not equal to the other. In mathematics, the relationship between two expressions or values ​​that are not equal  is called an inequality.

Here ,Given , Cost of 1 gift basket = $15.50

Let the no. of gift basket be 'x'

=>  x > 6

Therefore, Amount of money She will spend

=> $15.50x where x > 6

=>A = 15.5x : x > 6

Therefore the inequality is Amount A= 15.5x where x>6.

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Answer:

i would recomend matway for these questions

it will tell you the answers

Given :

Michaela runs to the end of her street and back in 90 s.

Her brother, Jacob, walks to the end of the street and back in 3 min.

They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob.

To Find :

How many times did each person go to the end of the street and back.

Solution :

Let, they both walk for T seconds.

Number of rounds Michaela walk is, n₁ = T/90 .

Number of rounds Jacob walk is, n₂ =T/180 .

It is given that :

n₁ = n₂ + 5

T/90 + T/180 = 5

( T/90 + T/180 ) × 180 = 5×180

2T + T = 900

3T = 900

T = 300 s

So, n₁ = 300/90 = 3

n₂ = 1

Hence, this is the required solution.

Answer:

36 dollars

Step-by-step explanation:

We need to think backwards to solve this question.

(8 - 2) x 2 = 12

(12 - 2) x 2 = 20

(20 - 2) x 2 = 36

Answer:

n=2.56

Step-by-step explanation:

Statistically significant linear relationship between the independent variables (study hours and GPA) and the dependent variable (ACT score), and the multiple regression equation can be used to predict the ACT score based on the hours studied and the student's GPA.

In this scenario, the dependent variable is the ACT score, while the independent variables are the number of hours spent studying (x1) and the student's GPA (x2).

To find the p-value for the regression equation, we can use a statistical software or calculator to perform a multiple linear regression analysis. The p-value represents the probability that the observed relationship between the independent and dependent variables is due to chance.

Assuming that we have performed the analysis and obtained the results, we can say that the p-value is less than 0.01 (since the level of significance is set at 0.01). This suggests that there is a statistically significant linear relationship between the independent variables (study hours and GPA) and the dependent variable (ACT score).

To identify the multiple regression equation that best fits the data, we can look at the coefficients for each independent variable. These coefficients represent the change in the dependent variable (ACT score) for every one unit increase in the independent variable, holding all other variables constant.

Based on the given data, we can write the multiple regression equation as:

ACT score = b0 + b1(hours studied) + b2(GPA)

where b0 is the intercept, b1 is the coefficient for hours studied, and b2 is the coefficient for GPA.

Using the regression analysis results, we can plug in the values of the coefficients to obtain the specific equation that fits the data.

Overall, we can conclude that there is a statistically significant linear relationship between the independent variables (study hours and GPA) and the dependent variable (ACT score), and the multiple regression equation can be used to predict the ACT score based on the hours studied and the student's GPA.

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