Please help me this is worth allot

Answer:

0.0337 J or 33.7 mJ

Explanation:

PEspring = ½ kx = 0.5 A 55.0 N/m A (0.0350 m) = 0.0336875 J = 2 2

Answer:

The law of the conservation of mechanical energy states that the total mechanical energy of a closed system remains constant, unless there is work done by non-conservative forces or heat transfer to or from the system.

In other words, the law states that the sum of the kinetic energy (energy of motion) and potential energy (energy due to position) of a system remains constant as long as there are no non-conservative forces acting on the system. Non-conservative forces are forces that dissipate energy, such as friction and air resistance. If these forces are present, they will convert some of the mechanical energy of the system into other forms of energy, such as heat or sound.

For example, if you lift a book off the ground, you are doing work on the book, which increases its potential energy. At the same time, the kinetic energy of the book decreases, because it is not moving. If you then release the book, it will fall to the ground, converting its potential energy back into kinetic energy. If there are no non-conservative forces present, the sum of the kinetic energy and potential energy of the book will remain constant throughout this process. This is an example of the conservation of mechanical energy in action.

The law of the conservation of mechanical energy states that the total mechanical energy of an isolated system remains constant, unless external forces are present. This means that the sum of the kinetic energy and potential energy within the system will remain constant over time, unless the system is subjected to external forces such as friction or gravity. This law is based on the principle that energy cannot be created or destroyed, but rather it can only be transferred or transformed. Therefore, any changes in the mechanical energy of a system must be due to the transfer or transformation of energy from one form to another, rather than the creation or destruction of energy itself.

Answer:

2) the sounds pitch

The strength or level of sound pressure

please give brainliest

have a nice day!

Answer:

Decreasing the angle to 10

Explanation:

Edge 2020

Gaining speed and changing the direction of force

A third-class lever makes our work easier by both magnifying force and gaining speed.

Hence, the correct option is D.

In a third-class lever, the effort (force) is applied between the fulcrum and the load. The load is closer to the fulcrum than the effort. This mechanical arrangement allows the lever to amplify the force applied at the expense of the distance the effort has to travel.

By applying a smaller force over a greater distance, a third-class lever can magnify the force applied to the load. Additionally, the increased distance covered by the effort compared to the load's displacement results in a greater speed at the load's end. So, both force magnification and speed gain are advantages of a third-class lever, making our work easier.

Therefore, A third-class lever makes our work easier by both magnifying force and gaining speed.

Hence, the correct option is D.

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Answer:

b. d. f.

Explanation:

Got it right on Edge

Answer:

2. Gina gathers information about a court case.

4. Hana interviews and advises a person who has been accused of a crime.

6. Dewayne creates the paperwork for a business contract.

The equation for the position vector r(t) of the particle at time t is :r(t) = 3i + 8j + 8k + (7i + 0j + 0k)t + (5/2i + 1/2j - 2k)t²

Given,Initial velocity, v0= 7 m/s

Final velocity, v = ?

Acceleration, a= 5i + j - 4k

Time, t = ?

Distance between the points, d= √(8 - 3)² + (9 - 8)² + (4 - 8)²

                                                    = √25 + 1 + 16

                                                    = √42 m

We know that,v = v0 + at

On substituting the given values in the above equation, we get,

7 + a×t = v

⇒ v = 7 + (5i + j - 4k)×t

Now, the equation of motion can be given by the following equation,r(t) = r0 + v0t + 1/2at²

Here,r0 = (3i + 8j + 8k) is the initial position of the particle

On substituting the given values in the above equation, we get,

r(t) = 3i + 8j + 8k + (7i + 0j + 0k)t + (5/2i + 1/2j - 2k)t²

Hence, The particle's location vector at time t is represented by the equation:r(t) = 3i + 8j + 8k + (7i + 0j + 0k)t + (5/2i + 1/2j - 2k)t²

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Answer:

It is 10.75

Explanation:

A. Mean drying time = 4.82 minutes

B. Simulated drying times: 3, 3, 4, 3, 4, 6, 5, 7, 7, 5, 7, 5

C. Average drying time for the 12 simulated processes = 5.33 minutes

A. To get the mean drying time, multiply each drying time by its relative frequency and add the products.

Mean = (3 * 0.14) + (4 * 0.30) + (5 * 0.27) + (6 * 0.18) + (7 * 0.11)

Mean = 0.42 + 1.20 + 1.35 + 1.08 + 0.77

Mean = 4.82

B. We can match each random number with its drying time to replicate 12 operations. If the random number is less than 0.14, drying takes 3 minutes. Repetition for all 12 random numbers.

Simulation drying times: 3, 4, 3, 4, 6, 5, 7, 5, 7, 5

C. Add the drying times and divide by 12 to determine the average drying time for the 12 simulated operations.

Average: (3+3+4+3+4+6+5+7+7+5+7+5) / 12 = 64 Average = 5.33

The average drying time for the 12 simulated procedures is 5.33 minutes.

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The swimmer would take 258 seconds, or 4 minutes and 18 seconds, to cross the river.

To solve this problem, we can use vector addition to find the swimmer's resultant velocity.

(i) Along what direction must he strike?

Let's draw a diagram to represent the situation:

    A

   /|

  / |

 /  |

/   |

B----C

In this diagram, the river flows from point A to point B, and the swimmer wants to cross the river from point C to point B. Let's call the velocity of the river Vr = 5 km/h and the velocity of the swimmer Vs = 10 km/h. We want to find the direction the swimmer should strike to cross the river straight.

Since the swimmer wants to cross the river straight, he needs to swim in a direction perpendicular to the river's flow. This means that the angle between the swimmer's velocity and the river's velocity should be 90 degrees.

Using trigonometry, we can find that the angle between the swimmer's velocity and the direction perpendicular to the river's flow is:

theta = arctan(Vr / Vs)

= arctan(5 / 10)

= 26.57 degrees

Therefore, the swimmer should strike at an angle of 26.57 degrees to the direction perpendicular to the river's flow.

(ii) What should be his resultant velocity?

To find the swimmer's resultant velocity, we need to add his velocity to the velocity of the river. Since the swimmer is swimming at an angle of 26.57 degrees to the direction perpendicular to the river's flow, we need to use vector addition to find his resultant velocity:

     Vs

    /|

   / |

  /  |Vr

 /   |

B----C--->river flow

Using trigonometry, we can find that the magnitude of the swimmer's resultant velocity is:

V = sqrt(Vs^2 + Vr^2)

= sqrt(10^2 + 5^2)

= 11.18 km/h

To find the direction of the swimmer's resultant velocity, we can use the following formula:

theta = arctan(Vr / Vs)

= arctan(5 / 10)

= 26.57 degrees

Therefore, the swimmer's resultant velocity is 11.18 km/h at an angle of 26.57 degrees to the direction perpendicular to the river's flow.

(iii) How much time would he take?

To find the time the swimmer would take to cross the river, we can use the following formula:

time = distance / velocity

The distance the swimmer needs to cross the river is the width of the river, which is 800 m. The swimmer's velocity is 11.18 km/h, or 3.1 m/s.

time = 800 / 3.1

= 258 seconds

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Answer:

1) For the swung puck tied to the string that has a mass m₁ and having another mass m₂ attached to the string that passes through a hole in the table, such that m₂ > m₁

The swung puck rotating on the table is kept in the circular motion on the table by the centripetal force acting towards the center of its rotation along the string, which is given by the amount the weight of m₂ exceeds m₁, in the same way a planet moving around the Sun is kept in its orbit by the gravitational attraction between the planet and the Sun.

2) i) The forces acting on the puck are;

a) The centripetal force in the string, acting inward, towards the center of rotation provided by the weight of m₂

b) The centrifugal force of the puck, acting outward, tending to continue its motion in a straight line

ii) The forces acting on the planet are;

a) The force of gravitational attraction between the planet and the Sun, acting towards the Sun, such that, the planet revolves around the Sun

b) The centrifugal force of the planet, acting outward, tending to move in a linear or straight path

Explanation:

Forces on Puck  Swung

Centrifugal Force (Outwards from  puck swung  )

Tension( Towards the center)

Forces on the Planet

Centrifugal Force (Outwards from  Planets  )

Gravitational Force ( Inwards towards Sun )

Let us suppose that the

The  puck swung is connected with a center at a distance of radius  r

so it is revolving around the point  just like planets revolve around the Sun.

The Centrifugal  Force and Gravitational Force  causes the planetary motion around the sun.

The Centrifugal force is an outward force  and is observed  from the accelerated frame of reference , In our case Planet and  puck swung are    the accelerated frame of references.

The Gravitational Force between the Sun and the planets  (directed towards Sun) is balanced by Centrifugal Force.

Let us consider that the string of  puck swung has negligible mass

So the Tension which is directed towards the center will provide the  force to counterbalance the centrifugal  force acting on puck swung.

So Tension will act towards the center in case of puck swung and centrifugal force will act outwards.

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Formula for Gravitational Potential Energy:

\(GPE=mgh\)

Gravitational potential energy(measured in joules) = mass(measured in kg) * acceleration(measured in 9.8 m/s^2 due to gravity) * height(measured in meters)

__________________________________________________________

Given:

\(m=49.1kg\)

\(h=14.7m\)

\(g=9.8m/s^2\) (due to gravity)

\(GPE=?\)

__________________________________________________________

Finding Gravitational Potential Energy:

\(GPE=mgh\)

\(GPE=49.1\times9.8\times14.7\)

__________________________________________________________

Answer:

\(\fbox{7073.346 Joules}\)

The possible energy of the emitted photons of the hydrogen atom in first energy level is -3.41 eV.

Hydrogen atom will emit electrons of certain energy when the hydrogen atom is in excited state.

Let a dot represent first energy level, the possible energy of the emitted photons is calculated as follows;

\(E = \frac{R_h}{n^2} \\\\E = \frac{-2.18 \times 10^{-18}}{(2)^2} \\\\E = - 5.45 \times 10^{-19} \ J\)

\(E = \frac{-5.45 \times 10^{-19}}{1.6 \times 10^{-19}} \\\\E = -3.41 \ eV\)

Thus, the possible energy of the emitted photons of the hydrogen atom in first energy level is -3.41 eV.

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Answer:ME= 1\2mv^2 + mgh

Explanation: I hope this helped.

The correctly represents the gravitational potential energy of a system is = - ΣGM₁M₂/R. Negative sign appears as gravitational force is attractive force.

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.

If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.

Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.

Potential energy of a system of particles can be represented as summation of individual's  potential energy. Hence, the correctly represents the gravitational potential energy of a system is = - ΣGM₁M₂/R.

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Hello!

Topic: Dinamic

Value to calculate: Force

First, we have to calculate the aceleration, for that, lets aplicate the formula:

\(\boxed{a=\frac{V-Vi}{t} }\)

How the final velocity is in km/h, we have to convert it on m/s, so:

m/s = km/h / 3,6

m/s = 105 / 3,6

m/s = 29,16

Then, lets replace formula according problem information:

\(a = \dfrac{29,16m/s-0m/s}{0,934s}\)

\(a =31,22\ m/s^{2}\)

Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:

\(\boxed{F=ma}\)

Replace and resolve it:

F = 856 kg * 31,22 m/s^2

F = 26724,32 kg * m/s^2

Then the force is of 26724,32 kg * m/s^2

But how we know an 1 kg * m/s^2 = 1 N

Then the average of the force is of 26724,32 N  

(1) The change in momentum of race car is 89880 kg-km/h.

(2) The average force exerted on the car is of 96231.26 N.

Given data:

The mass of race car is, m = 856 kg.

The initial speed of car is, u = 0 km/h.

The final speed of car is, v = 105 km/h.

The time interval is, t = 0.934 s.

1)

The change in the impact due to average force is known as momentum change. The expression for the change in momentum is given as follows,

\(\Delta P = m(v-u)\)

Solving as,

\(\Delta P = 856 \times (105-0)\\\\\Delta P = 89880 \;\rm kg.km/h\)

Thus, we can conclude that the change in momentum of race car is 89880 kg-km/h.

2)

Now, use the concept of impulse-momentum which says that the impulse is equal to change in momentum. Which means,

\(I = \Delta P\)

And impulse is,

\(F \times t = \Delta P\\\\F = \dfrac{\Delta P}{t}\)

Solving as,

\(F = \dfrac{89880}{0.934}\\\\F = 96231.26 \;\rm N\)

Thus, we can conclude that the average force exerted on the car is of 96231.26 N.

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Answer:

The equation Pi = c/2r means that Pi (r) = c/2, so r = c / (2 Pi). The radius of a circle is therefore equal to c / (2 Pi), where c is the circumference of the circle.

Explanation:

Explanation:

Efficiency is a way of describing the amount of useful ​output​ a process or machine can generate as a percentage of the ​input​ required to make it go. In other words, it compares how much energy is used to do work versus how much is lost or wasted to the environment. The more efficient the machine, the less energy wasted.

For example, if a heat engine is able to turn 75 percent of the fuel it receives into motion, while 25 percent is lost as heat in the process, it would be 75 percent efficient. Out of the original 100 percent of the fuel, 75 percent was output as useful work.  

the equation:

energy efficiency =useful output energy/total input energy

Ann's speed with sandbags is 400 meters in 5 minutes, or an average of 80 meters per minute.

In everyday use and in kinematics, the speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.Speed is defined as. The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.There are four types of speed which are uniform speed, variable speed, average speed, and instantaneous speed.

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Answer:

also increase

Explanation:

If the mass increases so will the weight.

Answer:

I'm pretty sure the speed of light is a constant so I my hypothesis is that the light will be travelling at *c*

Explanation:

The resources that we value—time, money, labor, tools, land, and raw materials—exist in limited supply. There are simply never enough resources to meet all our needs and desires.

Explanation:

Time, money, labor, land , and raw materials

Answer:

Yes

Explanation:

Because putting them together would make a type of energy making the answer yes

Answer:

refraction

Explanation: