please help me there are more questions after this.

Please Help Me There Are More Questions After This.

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Answer 1
Well give me a list of questions and I will try to solve them for you.

Related Questions

what is energy????
bye have a great day ​

Answers

Answer:

the capacity of doing work is called energy

have a great day

Answer:

the capacity for doing work is called energy.

have a great day

stay happy and healthy

Please help please :( I will really appreciate it thank you

Please help please :( I will really appreciate it thank you

Answers

Answer:

an Altitude

Step-by-step explanation:

Its altitude indicated by point A to line BC

Answer:

Im pretty sure that would be an altitude

Step-by-step explanation:

a golfer claims that his average golf score at the course he plays regularly is less than 90. the correct hypothesis statement for this golfer to prove his claim would be

Answers

The correct hypothesis statement for this golfer to prove his claim would be:

\(H_{0} :u\geq 90\)

\(H_{1} :u < 90\)

The golfer claims that his average score is less than 90.

Therefore, the null hypothesis is the opposite of what he claims

Null hypothesis \(H_{0}\) is average score \(u\) is greater than or equal to 90:

\(u \geq 90\)

\(H_{0} :u\geq 90\)

Alternative hypothesis \(H_{1}\) is then the opposite of null hypothesis.

Hence alternate hypothesis \(H_{1}\) is u< 90

\(H_{1} :u < 90\)

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The sum of 3 times a number and 7 is equal to 5. (translate into an equation)

Answers

Answer:

let n be the number then the sum of this number and 7 is n +7 and 3 times this sum is 3(n +7) 5 times the number less thirteen is 5n − 13

Step-by-step explanation:

Group the all the worksheets in the workbook and fill the range a1:f1 from the insurance worksheet across all worksheets maintaining the formatting. Ungroup the worksheets after the fill is complete and ensure the insurance worksheet is active

Answers

Below given steps, you will be able to group the worksheets, fill the range A1:F1 from the insurance worksheet across all the worksheets, and then ungroup the worksheets while keeping the insurance worksheet active.

To group all the worksheets in the workbook, you can follow these steps:
1. Open the workbook that contains the worksheets you want to group.
2. Click on the first worksheet tab.
3. Hold the Shift key on your keyboard and click on the last worksheet tab. This will select all the worksheets between the first and last.
4. Right-click on any of the selected worksheet tabs and choose "Group Sheets" from the context menu. This will group all the selected worksheets together.

Now, to fill the range A1:F1 from the insurance worksheet across all the worksheets while maintaining the formatting, you can use the following method:

1. Make sure the insurance worksheet is active. You can click on its tab to activate it.
2. Select the range A1:F1 on the insurance worksheet.
3. Press Ctrl+C on your keyboard to copy the selected range.
4. Right-click on any of the worksheet tabs and choose "Select All Sheets" from the context menu. This will select all the worksheets in the workbook.
5. Right-click on any of the selected worksheet tabs and choose "Paste" or press Ctrl+V on your keyboard. This will paste the copied range into the same location on all the selected worksheets.

After you have filled the range across all the worksheets, you can ungroup the worksheets by following these steps:

1. Right-click on any of the worksheet tabs and choose "Ungroup Sheets" from the context menu. This will ungroup the worksheets.
2. Make sure the insurance worksheet is still active. You can click on its tab to activate it.

By following these steps, you will be able to group the worksheets, fill the range A1:F1 from the insurance worksheet across all the worksheets, and then ungroup the worksheets while keeping the insurance worksheet active.

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3. Consider the null hypothesis that the population mean, β ​
, of the radon in the New Brunswick house is equal to the EPA cutoff of 4 . (a) Write the null hypothesis as a mathematical statement about β ​
. (b) Write the alternative hypothesis as a mathematical statement about β ​
. (c) When testing this null hypothesis, are you doing a left-tail, right-tail or twotailed test? Why or why not? (d) What estimator of β ​
(not the number for the estimate itself) will you need to use to test the null hypothesis? What is the formula for the variance of this estimator? (Don't derive it, just write it down). Howcan you estimate this variance formula? How can you use the estimated variance to obtain a standard error for your estimator of β ​
? 4. Test the null hypothesis from Question 3 using a t-test. Assume you do not know the population distribution of radon. You will have to rely on the central limit theorem and approximate the null distribution of your t-statistic using the N(0,1) distribution. Carry out your test at the 5% significance level (α=0.05). Clearly explain how you compute the t-statistic. Clearly state the rejection rule you are using and how you obtained your critical value. What is the result of your test?

Answers

(a) The statement assumes that the population mean of radon in New Brunswick houses (β) is equal to the EPA cutoff of 4.

The null hypothesis can be written as:

H0: β = 4

(b) The alternative hypothesis can be written as:

Ha: β ≠ 4

This statement suggests that the population mean of radon in New Brunswick houses (β) is not equal to the EPA cutoff of 4.

(c) When testing this null hypothesis, a two-tailed test is used. This is because the alternative hypothesis does not specify a direction (greater than or less than), but instead allows for the possibility that the population mean can differ from the EPA cutoff in either direction.

(d) To test the null hypothesis, we need to use an estimator of β. In this case, the sample mean (x) will serve as the estimator of β. The formula for the variance of this estimator, assuming simple random sampling, is:

Var(x) = σ²/n

Here, σ represents the population standard deviation and n is the sample size. To estimate this variance formula, we need the sample standard deviation (s). The estimated variance formula becomes:

Var(x)≈ s²/n

To obtain a standard error for the estimator of β, we take the square root of the estimated variance:

SE(x) ≈ √(s²/n)

4. To test the null hypothesis using a t-test, we will compute the t-statistic using the formula:

t = (x-β) / (SE(x))

In this case, since β is known (4), the formula simplifies to:

t = (x- 4) / (SE(x))

To carry out the test at the 5% significance level (α = 0.05), we will compare the computed t-statistic to the critical value(s) from the t-distribution with appropriate degrees of freedom. The rejection rule is as follows: If the absolute value of the computed t-statistic is greater than the critical value(s), we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

The result of the test will indicate whether there is sufficient evidence to reject the null hypothesis or not.

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Assume that the length of Earth's equator is exactly 25,100 miles and that the Earth is a perfect sphere. The town of Lena, Wisconsin, is at $45^{\circ}$ North Latitude, exactly halfway between the equator and the North Pole. What is the number of miles in the circumference of the circle on Earth parallel to the equator and through Lena, Wisconsin

Answers

The number of miles in the circumference of the circle on Earth parallel to the equator and passing through Lena, Wisconsin, is approximately 17,747.07 miles.

To calculate the circumference of the circle on Earth parallel to the equator and passing through Lena, Wisconsin, we need to determine the length of the circle's circumference at the given latitude.

Given:

Length of the Earth's equator = 25,100 miles

Latitude of Lena, Wisconsin = 45 degrees north

The circumference of a circle at a given latitude on a perfect sphere can be calculated using the formula:

Circumference = (Cos(latitude) * Earth's equator circumference)

First, we need to convert the latitude from degrees to radians:

Latitude in radians = 45 degrees * (π / 180)

Latitude in radians = π/4

Next, we can substitute the latitude in radians into the formula to calculate the circumference:

Circumference = (Cos(π/4) * 25,100 miles)

Using the value of the cosine of π/4 (which is √2 / 2), we have:

Circumference = (√2 / 2) * 25,100 miles

Simplifying:

Circumference ≈ 0.707 * 25,100 miles

Circumference ≈ 17,747.07 miles

Therefore, the number of miles in the circumference of the circle on Earth parallel to the equator and passing through Lena, Wisconsin, is approximately 17,747.07 miles.

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below. a) Which of the boxes has the smaller range of masses? b) What is the value of this range? Give your answer in grams (g). Box A 97653 4 Box A Box B 15 1469 5 6 2 478 39 835 8762 7 Box B Key 35 represents a mass of 53 g 51 represents a mass of 51 g​

Answers

Box B has the smaller range of masses, with a range of 49 grams, compared to Box A's range of 97,649 grams.

The question asks which of the boxes has the smaller range of masses and what is the value of this range in grams (g).
To find the range, we need to subtract the smallest value from the largest value in each box.
In Box A, the smallest value is 4 and the largest value is 97653. So, the range in Box A is 97653 - 4 = 97649 g.
In Box B, the smallest value is 2 and the largest value is 8762. However, we are given that key 35 represents a mass of 53 g and key 51 represents a mass of 51 g. So, the actual largest value in Box B is 51. Therefore, the range in Box B is 51 - 2 = 49 g.
Comparing the ranges, we can see that the range in Box B (49 g) is smaller than the range in Box A (97649 g).

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A manager's salary of N600 is increased by 12%. What is his new salary?​

Answers

Answer:

672

Step-by-step explanation:First you need to change the percent into 12 over 100 times 600.then the result is 72.after that it says increased so you plus 600 plus 72 and that is the answer

what is the circumference

what is the circumference

Answers

Answer:  69.43 cm

Step-by-step explanation:

Given: Arc length (JK) = 40.5 cm

Central angle ∠ JLK = 210°

Arc length = \(\dfrac{x}{360}\times\text{Circumference}\)

\(\Rightarrow\ 40.5=\dfrac{210}{360}\times\text{Circumference}\\\\\Rightarrow \text{Circumference} =40.5\times\dfrac{360}{210}\\\\\approx69.43\ cm\)

Hence, Circumference = 69.43 cm

the number of assists per match for the setter on your school's volleyball team has a mean of 55 and a standard deviation of 8. how many standard deviations from the mean is an outing with 74 assists?

Answers

2.375 number of standard deviation from mean outing with 74 assists.

Data dispersion in regard to the mean is quantified by a standard deviation, or "σ"

By figuring out how far off from the mean each data point is, the standard deviation may be determined as the square root of variance.

The deviation within the data set is bigger when the data points are more away from the mean.

According to the question,

Mean of the number of assists per match is 55

Standard deviation of the same is 8

Let x be the number of standard deviation from mean outing with 74 assists

=> 55 + 8x = 74

Solving for x

=> 8x = 74 - 55

=> 8x = 19

=> x = 19 / 8

=> x = 2.375

Hence, 2.375 number of standard deviation from mean outing with 74 assists.

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ne friday night, there were 42 carry-out orders at ashoka curry express. 15.14 13.56 25.59 35.13 26.89 18.27 36.43 35.42 32.66 40.48 43.76 31.24 33.28 44.99 13.33 44.53 18.47 40.58 17.65 34.80 17.77 40.29 42.57 40.54 18.22 13.60 37.39 15.14 37.88 45.03 20.85 35.08 23.25 30.97 44.46 25.36 29.09 33.34 14.97 23.04 43.47 23.43

Answers

(a) The mean and standard deviation of the sample is 26.83 and 10.59 respectively.

(b-1) The chi-square value is 12.8325 and the p-value is 0.0339.

(b-2) No, we cannot reject the hypothesis that carry-out orders follow a normal population distribution.

(a) To estimate the mean and standard deviation from the sample, we can use the following formulas:

Mean = sum of all values / number of values
Standard Deviation = square root of [(sum of (each value - mean)^2) / (number of values - 1)]

Using these formulas, we can calculate the mean and standard deviation from the given sample.

Mean = (15.14 + 35.42 + 13.33 + 40.29 + 37.88 + 25.36 + 13.56 + 32.66 + 44.53 + 42.57 + 45.03 + 29.09 + 25.59 + 40.48 + 18.47 + 40.54 + 20.85 + 33.34 + 35.13 + 43.76 + 40.58 + 18.22 + 26.89 + 31.24 + 17.65 + 13.60 + 23.25 + 23.04 + 18.27 + 33.28 + 34.80 + 37.39 + 30.97 + 43.47 + 36.43 + 44.99 + 17.77 + 15.14 + 4.46 + 23.43) / 42 = 29.9510

Standard Deviation = square root of [( (15.14-29.9510)^2 + (35.42-29.9510)^2 + (13.33-29.9510)^2 + ... ) / (42-1)] = 10.5931
Therefore, the estimated mean is 29.9510 and the estimated standard deviation is 10.5931.

(b-1) To perform the chi-square test at d = 0.025 (using 8 bins), we need to calculate the chi-square value and the p-value.

Chi-square value = sum of [(observed frequency - expected frequency)^2 / expected frequency]
P-value = 1 - cumulative distribution function (CDF) of the chi-square distribution at the calculated chi-square value

Using the formula, we can calculate the chi-square value and the p-value.

Chi-square value = ( (observed frequency - expected frequency)^2 / expected frequency ) + ...
P-value = 1 - CDF of chi-square distribution at the calculated chi-square value
Round your answers to decimal places. Do not round your intermediate calculations.


The chi-square value is 12.8325 and the p-value is 0.0339.

(b-2) To determine whether we can reject the hypothesis that carry-out orders follow a normal population distribution, we compare the p-value to the significance level (d = 0.025 in this case).

Since the p-value (0.0339) is greater than the significance level (0.025), we fail to reject the null hypothesis. Therefore, we cannot reject the hypothesis that carry-out orders follow a normal population distribution.

No, we cannot reject the hypothesis that carry-out orders follow a normal population distribution.

Complete Question: One Friday night; there were 42 carry-out orders at Ashoka Curry Express_ 15.14 35.42 13.33 40.29 37 .88 25.36 13.56 32.66 44.53 42.57 45.03 29.09 25.59 40.48 18.47 40.54 20.85 33.34 35.13 43.76 40.58 18.22 26. 89 31.24 17.65 13.60 23.25 23.04 18.27 33 . 28 34.80 37.39 30.97 43.47 36.43 44.99 17.77 15.14 4.46 23.43 olnts 14.97 e30ok  (a) Estimate the mean and standard deviation from the sample. (Round your answers t0 decimal places ) Print sample cam Sample standard deviation 29.9510 10.5931 Renemence (b-1) Do the chi-square test at d =.025 (define bins by using method 3 equal expected frequencies) Use 8 bins): (Perform normal goodness-of-fit = test for & =.025_ Round your answers to decimal places Do not round your intermediate calculations ) Chi square 0.f - P-value 12.8325 0.0339 (b-2) Can You reject the hypothesis that carry-out orders follow normal population? Yes No

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Find the coordinates of P so that P partitions the segment AB in the ratio 5:1 given the points A(2, 4) and B(8, 10).

Answers

The coordinates of P are P(7, 9) such that P partitions the segment AB in the ratio 5:1.

To find the coordinates of point P that partitions segment AB in the ratio 5:1, we can use the concept of section formula. The section formula states that if we have two points A(x1, y1) and B(x2, y2) dividing the segment in the ratio m:n, then the coordinates of the point P(x, y) can be found using the following formulas:

x = (nx1 + mx2) / (m + n)

y = (ny1 + my2) / (m + n)

In this case, A has coordinates A(2, 4) and B has coordinates B(8, 10). We want to find the coordinates of P that divide the segment AB in the ratio 5:1.

Plugging in the values into the formulas, we have:

x = (12 + 58) / (5 + 1) = (2 + 40) / 6 = 42 / 6 = 7

y = (14 + 510) / (5 + 1) = (4 + 50) / 6 = 54 / 6 = 9

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one electrician charges a $50 service call fee plus $25 per hour for labor. Another electrician charges a $35 service call fee plus $27.50 per hour for labor. how long would a job take if the total cost for each electrician is the same?​

Answers

Answer:

The answer would be 6.

Step-by-step explanation:

First, we need to make equations for these electricians fee's.

Electrician one: Y=25x+50, 50 is the upfront cost and 25 is the cost per hour for work.

Electrician two: Y=27.50x+35, It is the same thing for these numbers.

Then you need to incert numbers into the X place. Y will be your answer.

Y=25(6)+50, Y=150+50, Y=200

Y=27.50(6)=35, Y=165+35, Y=200

The answer would be 6. If both the electricians worked for 6 hours each, their prices would be equal.

"Create your own real-world example of a relation that is a function.
Domain: The set of_____
Range: The set of_____"​

Answers

Answer:

see below

Step-by-step explanation:

My gas tank can hold 16 gallons.

I go to the station to fill it at 2 dollars a gallon.

The domain is how much gas I put in the car

The domain is the set of real number between 0 and 16 gallon

The range is the cost of my gas.  It is  the set of real numbers between 0 and 32 .00 dollars

Answer:

Create your own real-world example of a relation that is a function.

Domain: The set of: 0

Range: The set of: 16

Two buses are 515 miles apart. At 9:30 A.M. they start traveling toward each other at rates of 48 and 55 miles per hour. At what time will they pass each other

Answers

The two buses are initially 515 miles apart and are moving toward each other. They will pass each other around 2:30 P.M.

To solve this problem, we can use the concept of relative speed. The combined speed of the two buses is the sum of their individual speeds, which is 48 + 55 = 103 miles per hour.

We can calculate the time it takes for the buses to meet by dividing the initial distance between them (515 miles) by their combined speed (103 miles per hour):

Time = Distance / Speed

Time = 515 miles / 103 miles per hour

Time ≈ 5 hours

Therefore, the two buses will pass each other approximately 5 hours after they start traveling toward each other. To determine the exact time, we need to consider the starting time (9:30 A.M.) and add 5 hours to it. So, they will pass each other around 2:30 P.M.

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Prove algebraically that the recurring decimal 0.472 can be written as
17
36

Answers

Given:

The recurring decimal is \(0.47\overline{2}\).

To prove:

Algebraically that the recurring decimal \(0.47\overline{2}\) can be written as \(\dfrac{17}{36}\).

Proof:

Let,

\(x=0.47\overline{2}\)

\(x=0.472222...\)

Multiply both sides by 100.

\(100x=47.2222...\)     ...(i)

Multiply both sides by 10.

\(1000x=472.2222...\)        ...(ii)

Subtract (i) from (ii).

\(1000x-100x=472.2222...-47.2222...\)

\(900x=425\)

Divide both sides by 900.

\(x=\dfrac{425}{900}\)

\(x=\dfrac{17}{36}\)

So, \(0.47\overline{2}=\dfrac{17}{36}\).

Hence proved.

what is 1/3 divided by 1/18

Answers

Answer:

6

Step-by-step explanation:

1/3 ÷ 1/18

1/3 × 18/1       Keep Change Flip

18/3=6

Answer: 6

Step-by-step explanation:

Not sure how to explain this answer but I’m pretty sure it’s 6 so yeah...

Derivations (20 marks): For each of the questions in this section provide a derivation. Other methods will receive no credit i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)
ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks) iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)

Answers

¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)

Proof:

1. ∃x(Fx & Gx) [Premise]

2. Fx & Gx [∃-Elimination, 1]

3. ∃xFx [∃-Introduction, 2]

4. ∃xGx [∃-Introduction, 2]

5. ∃xFx & ∃xGx [Conjunction Introduction, 3 and 4]

6. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx [1-5, Modus Ponens]



ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks)

Proof:

1. ¬ 3x(Px v Qx) [Premise]

2. ¬ Px v ¬ Qx [DeMorgan’s Law, 1]

3. Vx ¬ Px [∀-Introduction, 2]

4. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px [1-3, Modus Ponens]



iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)

Proof:

1. ¬ Vx(Fx → Gx) v 3xFx [Premise]

2. (¬ Vx(Fx → Gx) v 3xFx) → (¬ Vx(Fx → Gx) v Fx) [Implication Introduction]

3. ¬ Vx(Fx → Gx) v Fx [Resolution, 1, 2]

4. (¬ Vx(Fx → Gx) v Fx) → (Fx → Gx) [Implication Introduction]

5. Fx → Gx [Resolution, 3, 4]

6. ¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

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The United Kingdom Forestry Commission reports that 43% hectares of woodland area in the United Kingdom had certification identifying them as "sustainably managed" in 2016. Suppose an employee took a simple random sample of 400 of the hectares and saw that the records showed that 47% of the sampled hectares had that certification in 2016. Identify your information:


N =

400


P =

0. 43


Check Conditions:


10% Condition:

We assume 400 hectares is less than 10% of all hectares


Large Counts Condition:

400(0. 43) and 400(1-0. 43) are both < 10


Is this approximately normal?

Yes, BECAUSE the 10% condition is met!


Find the Important Values:


Mean of p-hat:


Standard Deviation of p-hat:

0. 0248


Assuming that the Forestry Commission's report is accurate, what is the approximate probability that more than 47% of the sample would have had the certification in 2016?

Draw Conclusions:


Is there strong evidence against the claimed value of 43%?


Since our probability of

is

than 5%, there

strong evidence against the claimed

Answers

There is not strong evidence against the claimed value of 43%.

N = 400
P = 0.43

Check Conditions:
10% Condition: We assume 400 hectares is less than 10% of all hectares, so this condition is met.
Large Counts Condition: 400(0.43) = 172 and 400(1-0.43) = 228 are both greater than 10, so this condition is met.

Is this approximately normal? Yes, because both the 10% condition and the Large Counts condition are met.

Find the Important Values:
Mean of p-hat: 0.43
Standard Deviation of p-hat: sqrt((0.43)(1-0.43)/400) = 0.0248

Assuming that the Forestry Commission's report is accurate, what is the approximate probability that more than 47% of the sample would have had the certification in 2016?
We need to find the z-score for 0.47: z = (0.47-0.43)/0.0248 = 1.61
Using a z-table, we find that the probability of getting a z-score greater than 1.61 is 0.0537.

Since our probability of 0.0537 is greater than 5%, there is not strong evidence against the claimed value of 43%.

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how to construct a confidence interval of the population proportion given at the level of confidence

Answers

Answer:

Step-by-step explanation:

what i do not undersante

suppose you lift a laptop that weighs 4.1 pounds off the floor onto a shelf that is 2 feet high. how much work have you done?

Answers

The required work done in lifting the laptop to a height of 2 feet will be 263.79 foot-poundal.

Total weight of the laptop is 4.1 pounds

Acceleration due to gravity = 32.17 ft/\(s^{2}\)

Now the height to which the laptop has been lifted = 2 feet

Since, there is no mentioned velocity of the laptop, therefore the kinetic energy will be zero

Therefore, the total work in lifting the laptop will be equal to the change in potential energy.

Potential energy is the energy that comes by virtue of its position with reference to other

Therefore, potential energy = mgh

Where, m = mass of the laptop = 4.1 pounds

g = acceleration due to gravity = 32.17 ft/\(s^{2}\)

h = height to which the laptop is lifted =  2 feet

Therefore potential energy = (4.1)(32.17)(2) = 263.79 foot-poundal

263.79 foot-poundal is the required work done.

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COS Need help please

COS Need help please

Answers

Answer:

8/17

Step-by-step explanation:

SOH CAH TOA. Cos = Adjacent/Hypotenuse

PLEASE HELP WORTH 50 POINTS!

PLEASE HELP WORTH 50 POINTS!

Answers

Jessica’s mistake is that when isolating h from b, she multiplied b instead of dividing it on both sides. The new formula for h would be A/2b=h.
Now let’s solve. 23/2(6)=h
23/12
Approx. 1.91

Answer:

the question was not correctly solved

Step-by-step explanation:

A=½bh

23=½*b*h

²/1×23= bh

²/1×23=6h

46=6h

h=7.666666667 / h=23/3

I hope this is helpful

from a consumer’s utility function alone, which of the following may be determined?

Answers

When analyzing a consumer's utility function: preferences, marginal utility, optimal consumption, and substitution and income effects.

From a consumer's utility function alone, you may determine the following:

1. Preferences: A consumer's utility function represents their preferences for different goods and services. By analyzing the function, you can determine which items the consumer prefers and how much they value them.

2. Marginal utility: The marginal utility is the additional satisfaction a consumer receives from consuming one more unit of a good or service. It can be derived from the utility function by taking its first derivative with respect to the quantity of the good or service.

3. Optimal consumption: By analyzing a consumer's utility function and taking into account their budget constraint, you can determine the optimal consumption bundle that maximizes their utility.

4. Substitution and income effects: The utility function can also help you analyze how changes in prices or income will affect a consumer's consumption choices, through the substitution and income effects.

Remember to keep these terms in mind when analyzing a consumer's utility function: preferences, marginal utility, optimal consumption, and substitution and income effects.

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I’ll give brainley , pleaseee helppp

Ill give brainley , pleaseee helppp

Answers

Answer:

Vertical Stretch & horizontal translation

Step-by-step explanation:

the vertical stretch makes the line bigger

Horizontal translation will move the shape 2 left of the x axis

Answer:

Srry bro its way to blurry for me to read... Also dont show your password to randoms.

Step-by-step explanation:

Can someone help me on this?

Can someone help me on this?

Answers

Answer:

C

Step-by-step explanation:

divide 22.5 by 10

=2.5

so

f=2 1/2c

Given that f(x) =1/x^2=1 . Compute f'(3) Compute using the
definition of derivative.

Answers

f'(3) = -2/27. To compute the derivative of f(x) using the definition of derivative, we use the following formula:

f'(x) = lim(h->0) [(f(x+h) - f(x))/h]

Let's begin by plugging in the given function and x-value:

f(x) = 1/x^2

x = 3

Now, we need to plug these values into the definition of the derivative and simplify.

f'(3) = lim(h->0) [(f(3+h) - f(3))/h]

f(3+h) = 1/(3+h)^2, so

f'(3) = lim(h->0) [(1/(3+h)^2 - 1/3^2)/h]

= lim(h->0) [(1/(9+6h+h^2) - 1/9)/h]

Next, let's simplify this expression by finding a common denominator:

f'(3) = lim(h->0) [((9/9) - (9+6h+h^2)/(9(9+6h+h^2)))/h]

= lim(h->0) [(9 - (9+6h+h^2))/(9h(9+6h+h^2))]

Now, we can simplify further by combining like terms and factoring out an h:

f'(3) = lim(h->0) [(-6h - h^2)/(9h(9+6h+h^2))]

= lim(h->0) [-6/(9+6h+h^2)]

Finally, we can plug in h=0 to get our answer:

f'(3) = -6/9^2

= -2/27

Therefore, f'(3) = -2/27.

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The hourly wage of some automobile plant workers went from $ 7.40 to $ 14.56 in 10 years (annual raises). If their wages are growing exponentially what will be their hourly wage in 3 more years

Answers

Their hourly wage in 3 more years (after a total of 13 years) will be 17.43 per hour.

We can solve this problem using the formula for exponential growth, which is:

\(A = P(1 + r)^t\)

Where:

A = the amount after t years

P = the initial amount

r = the annual growth rate (expressed as a decimal)

t = the number of years

Let's use this formula to solve the problem:

Find the initial amount

The initial hourly wage is 7.40, so P = 7.40

Find the annual growth rate

The wages grew from 7.40 to 14.56 in 10 years, so we can use this information to find the annual growth rate:

\(14.56 = 7.40(1 + r)^{10}\\(1 + r)^{10} = 14.56/7.40\\(1 + r)^{10} = 1.97297\\1 + r = (1.97297)^{(1/10)\)

1 + r = 1.076

r = 0.076 or 7.6%

So the annual growth rate is 7.6% (expressed as a decimal).

Find the amount after 13 years

We want to find the hourly wage in 3 more years, which is a total of 13 years (10 years of past growth + 3 more years). So t = 13.

\(A = P(1 + r)^t\\A = 7.40(1 + 0.076)^{13}\\A = 7.40(1.076)^{13}\\A = 7.40(2.355)\)

A = 17.43 (rounded to two decimal places)

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In a shipment of 400 parts, 14 are found to be defective. How many parts out of 1000 would NOT be defective?

Can you please show a proportion I am confused.

Answers

Answer:

965 parts would not be defective.

Step-by-step explanation:

So for every 400 parts, 14 are defective. That means 386 are not defective. 1000 is 2.5 times as many as 400. So multiply 386 by 2.5 to get your answer.

386/1 * 5/2

193/1 * 5/1

965/1

That means for every 1000 parts, 965 would not be defective. The proportion(s) would be 386:400/965:1000 here.

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