Please help me solve this​

Answer:

True I think.

Step-by-step explanation:

True, An expression to represent this is, 1.12S

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

To Calculate the percent of a number , divide the number by whole number and multiply by 100.

We have to given that;

In honors math increased by 12% in this year students.

Now, if S represents students.

Then, An expression to represent this situation is,

⇒ S + 12% of S

⇒ S + 0.12S

⇒ S (1 + 0.12)

⇒ 1.12S

Thus, The expression is true.

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Answer:

Step-by-step explanation:

The measure of the arc opposite to 189° is 136°.

Secant lines are lines that intersect a curve at two distinct points. They are used to approximate the slope of the curve by measuring the change in the y-coordinate of the two points divided by the change in the x-coordinate of the two points.

The measure of the angle opposite to 189° is x.

To solve for x, we can use the property of alternate interior angles.

The sides of the two secant lines that intersect outside the circle form alternate interior angles whose measures are equal.

Therefore, the two angles formed by the secant lines inside the circle must have the same measure.

Therefore, 53° + x° = 189°.

Subtracting 53° from both sides, we get x° = 136°.

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Answer:

x = 145

Step-by-step explanation:

x and 35° lie on a straight line and are supplementary angles , sum to 180°

x + 35 = 180 ( subtract 35 from both sides )

x = 145

By answering the presented question, we may conclude that Sales Rep: expression This entity maintains information about sales reps such as SalesRepID and SalesRepName.

An expression in mathematics is a collection of representations, numbers, and conglomerates that mimic a statistical correlation or regularity. A real number, a mutable, or a mix of the two can be used as an expression. Mathematical operators include addition, subtraction, fast spread, division, and exponentiation. Expressions are often used in arithmetic, mathematic, and form. They are used in the representation of mathematical formulas, the solution of equations, and the simplification of mathematical relationships.

The ER diagram above depicts the database entities and their connections. Here's a quick rundown of each entity and its characteristics:

Employee: This object contains information on employees such as EmployeeID, Name, DateOfBirth, and Dependents.

ProductID, ProductName, ManufacturingDate, ExpiryDate, and SupplierID are all stored in this object.

Supplier: This entity holds supplier-specific information such as SupplierID, SupplierName, ContactPerson, and ContactNumber.

CustomerID, CustomerName, ContactPerson, and ContactNumber are all stored in the Customer entity.

Sales Rep: This entity maintains information about sales reps such as SalesRepID and SalesRepName.

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Explanation:

First we solve for y.

x + 2y = -14

2y = -14 - x

2y = -x - 14

y = (-x - 14)/2

y = -x/2 - 14/2

y = (-1/2)x - 7

The equation is in slope intercept form y = mx+b

Parallel lines have equal slopes, but different y intercepts. This means the slope of any line parallel to this given one will have a slope of -1/2

For example, y = (-1/2)x + 10 is parallel to y = (-1/2)x - 7, since both have the same slope of -1/2 but different y intercepts.

Answer:

Step-by-step explanation:

y=kx²

y₁=k(1)²=k

y₃=k(3)²=9k

y₁-y₃=k-9k=32

-8k=32

k=-4

y=-4x²

y₋₂=-4(-2)²=-16

For the marching bands vary from 18 to 48 player, the numbers of players  arranged in the greatest number of rectangles is 48 players.

As given in the question,

Number of players in the given marching bands vary from 18 to 48 players

To form a rectangles in the marching bands minimum two rows are required.

Greatest length and width of the rectangles formed by 18 to 48 players

19,23,29,....,47 are prime numbers

18 = 2 ×9 , 3×6

20 = 2×10 ,4×5

21= 3×7

22 = 2× 11

24=2×12, 3×8, 4×6

and so on

48 = 2 ×24 , 3×16, 4×12, 6×8,

48 players represents greatest number of rectangles

Therefore, for the marching bands vary from 18 to 48 player, the numbers of players  arranged in the greatest number of rectangles is 48 players.

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Answer:

11,44,83

Step-by-step explanation:

4y+7y+6=116(exterior angle is equal to sum of two opposite interior angle in traingle)

11y=116-6

y=110÷11=11

4y=4×11=44

7y+6=7×11+6=83

Answer:

H0: μd=0 Ha: μd≠0

t= 0.07607

On the basis of this we conclude that the mean weight differs between the two balances.

Step-by-step explanation:

The null and alternative hypotheses as

H0: μd=0 Ha: μd≠0

Significance level is set at ∝= 0.05

The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571

The test statistic under H0 is

t = d/ sd/ √n

Which has t distribution with n-1 degrees of freedom

Specimen        A               B           d = a - b         d²

1                     13.76        13.74         0.02           0.004

2                    12.47        12.45          0.02         0.004

3                    10.09        10.08           0.01        0.001

4                       8.91       8.92          -0.01          0.001

5                     13.57      13.54           0.03        0.009

6                     12.74      12.75          -0.01        0.001

∑                                                      0.06         0.0173

d`= ∑d/n= 0.006/6= 0.001

sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882

sd= 0.05368

t= 0.001/ 0.05368/ √6

t= 0.18629/2.449

t= 0.07607

Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.

(f/g)(-5) is equal to 1/4, and the value -1 is not in the domain of f/g.

To find (f/g)(-5), we need to substitute -5 into the functions f(x) and g(x) and then divide f(-5) by g(-5).

Given:

f(x) = (4+x)(6+x)

g(x) = 1+x

Substituting -5 into the functions:

f(-5) = (4+(-5))(6+(-5)) = (-1)(1) = -1

g(-5) = 1+(-5) = -4

Now, we can calculate (f/g)(-5):

(f/g)(-5) = f(-5) / g(-5) = -1 / -4 = 1/4

Therefore, (f/g)(-5) equals 1/4.

Now let's determine the values that are not in the domain of f/g. The values that are not in the domain of f/g are the values that make the denominator g(x) equal to zero. In this case, the denominator is g(x) = 1+x.

To find the values that make the denominator zero, we solve the equation:

1 + x = 0

Subtracting 1 from both sides, we get:

x = -1

So, the value x = -1 is not in the domain of f/g because it would make the denominator equal to zero.

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Answer:

4.428 hours

Step-by-step explanation:

If the learning rate is 0.81, the slope of the learning curve is:

\(b=\frac{ln(0.81)}{ln(2)} \\b=-0.304\)

The time it takes to produce the n-th unit is:

\(T_n=T_1*n^b\)

If T1 = 8 hours, the time required to produce the seventh unit will be:

\(T_n=8*7^{-0.304}\\T_n=4.428\ hours\)

It will take roughly 4.428 hours.

The needed number of days at 10 degrees is given as follows:

11 days.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

In which:

For this problem, we have that when x decreases by 5, y increases by 2, hence the slope m is given as follows:

m = -2/5

m = -0.4.

Hence the time needed for a temperature of 10 degrees is given as follows:

9 + 2 = 11 days.

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Answer: 44 2/15

Step-by-step explanation:

Answer:

I will help you okay????

Answer:

Me I sent them to you already. emily

English is a West Germanic language first spoken in early medieval England which eventually became the leading language of international discourse in today's world.

The net loss from accepting the special order at a discount of 25% from the regular price, without the existence of excess capacity is $38,700.

Since Coronado Co. lacks the excess capacity for special orders, it implies that it will incur fixed costs per unit of the special order in addition to the variable costs.

Therefore, the company will incur a per unit cost of $40 ($16 + $12 + $9 + $3) while generating a revenue of $39 per unit.

This results in a loss of $1 per unit.

Selling price per unit = $52

Unit Costs:

Direct Materials = $16

Direct Labor = $12

Variable Overhead = $9 (75% of $12)

Total variable cost per unit = $37

Fixed Overhead = $3 (25% of $12)

Special order price per unit = $39 ($52 x 1 - 75%)

Contribution margin per unit = $2 ($39 - $37)

Total contribution margin = $77,400 ($2 x 38,700)

Fixed Overhead without excess capacity = $116,100 ($3 x 38,700)

Net loss = $38,700 ($77,400 - $116,100)

Thus, without excess capacity, it is inadvisable for Coronado to accept the special order at a total loss of $38,700.

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To find all points on the x-axis that are 16 units away from the point (5, -8), we can use the distance formula. The distance between two points (x₁, y₁) and (x₂, y₂) is given by the formula:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

In this case, the y-coordinate of the point (5, -8) is -8, which lies on the x-axis. So, any point on the x-axis will have a y-coordinate of 0. Let's substitute the given values and solve for the x-coordinate.

d = √((x - 5)² + (0 - (-8))²)

Simplifying:

d = √((x - 5)² + 64)

Now, we want the distance d to be equal to 16 units. So, we set up the equation:

16 = √((x - 5)² + 64)

Squaring both sides of the equation to eliminate the square root:

16² = (x - 5)² + 64

256 = (x - 5)² + 64

Subtracting 64 from both sides:

192 = (x - 5)²

Taking the square root of both sides

√192 = x - 5

±√192 = x - 5

x = 5 ± √192

Therefore, the two points on the x-axis that are 16 units away from the point (5, -8) are:

Point 1: (5 + √192, 0)

Point 2: (5 - √192, 0)

In summary, the points on the x-axis that are 16 units away from the point (5, -8) are (5 + √192, 0) and (5 - √192, 0).

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Answer:b

Step-by-step explanation:

The terms in Pattern B are one third the corresponding terms in Pattern A.

Twenty standard cartons of octal boxes weigh a total of 1,100 pounds. The weight per carton is 55 pounds.

Given that twenty standard cartons of octal boxes weigh a total of 1,100 pounds. We need to find the weight per carton.

How to find the weight per carton? To find the weight per carton, we need to divide the total weight of twenty standard cartons of octal boxes by 20.Let's assume the weight of each carton be x.

Therefore, the equation can be formed asx * 20 = 1,100 Solving the above equation for x, x = 1,100/20 Therefore, the weight per carton is 55 pounds. So, twenty standard cartons of octal boxes weigh a total of 1,100 pounds.

The weight per carton is 55 pounds.

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Answer:

The volume will be 64 times larger.

Explanation:

When you multiply two single dimensions, such as length and width, the units will change from units to units squared (example: 2 ft * 2 ft = 4 ft^2). Similarly, When you multiply three single dimensions the units will change from units to units cubed (example: 2 ft * 2 ft * 2 ft = 8 ft^3). You can use the exponents as a trick to solve this type of question. For example, in this case, volume means that you are multiplying three single dimensions. Therefore, the end result will be units cubed. If each dimension is multiplied by four, you can cube the factor to find how many times larger the volume will be: 4^3 = 64.

TLDR: Since there are three dimensions, multiply 4 by itself three times to get the answer: 4 * 4 * 4 = 64.

In case I explained it badly, here is a more mathematical method to find the answer:

The formula for volume:

V = l * w * h

When you multiply each dimension by 4:

V = (4 * l) * (4 * w) * (4 * h)

Rearrange with the Commutative Property of Multiplication:

V = (4 * 4 * 4) * (l * w * h)

Simplify:

V = 64 * l * w * h

Therefore, the volume is 64 times greater.

The average speed throughout the given time was [1,2] = -2.00 cm/sii. -0.26 cm/siii for [1,1.1]. [1.1,1.01] = 0.17 cm/siv. [1.1,1.001] = 0.02 cm/s

The particle's displacement divided by the passage of time represents its average velocity at each time interval. The displacement of the particle for the above motion equation is given by s = 2 sint + 4 cost. By subtracting the displacement at the beginning and end of the period and dividing it by the change in time, we can determine the average velocity for each time period. As an illustration, the displacement for the time period [1,2] is 2 sin + 4 cos at the beginning of the period and 2 sin + 4 cos at the end of the period. These two figures differ by -4, and one second has passed between them.

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let's take a peek at the picture above, hmmm let's notice the vertex is at (-1 , 2), now let's get a point besides the vertex hmmm let's see it passes through (-2 , -1).

So we can reword that as what's the equation of a quadratic whose vertex is at (-1 , 2) and it passes through (-2 , -1)?

\(~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\)

\(\begin{cases} h=-1\\ k=2\\ \end{cases}\implies y=a(~~x-(-1)~~)^2 + 2\hspace{4em}\textit{we also know that} \begin{cases} x=-2\\ y=-1 \end{cases} \\\\\\ -1=a( ~~-2-(-1) ~~ )^2 + 2\implies -3=a(-2+1)^2\implies -3=a \\\\\\ ~\hfill~ {\Large \begin{array}{llll} y=-3(x+1)^2 + 2 \end{array}} ~\hfill~\)

Answer:

y = -3(x + 1)^2 + 2

Step-by-step explanation:

y = a(x - h)^2 + k is the vertex form of a quadratic, where

Finding (h, k):

We see from the graph that the vertex is a maximum and its coordinates are (-1, 2).  Thus h is -1 and k is 2.  Since h becomes negative, it will be 1 in the parentheses: (x - (-1) = (x + 1).

Finding a:

In order to find a, we will need to plug in a point on the parabola for (x, y) and (-1, 2) for h and k.  We see that (0, -1) lies on the parabola so we can use this point for (x, y).

-1 = a(0 - (-1))^2 + 2

-1 = a(0 + 1)^2 + 2

-3 = a(1)^2

-3 = a

Thus, a = -3.

Thus, the exact equation in vertex form of the parabola is:

y = -3(x + 1)^2 + 2

I attached a picture from Desmos Graphing Calculator that shows how the equation I provided works and contains the two points you marked on the parabola, including (-1, 2) aka the maximum, and (0, -1) aka the y-intercept.

Explanation:

A = set of odd numbers = {1,3,5}

B = set of factors of 12 = {1,2,3,4,6}

A U B = union of set A and set B

A U B = {1,3,5} union {1,2,3,4,6}

A U B = {1,3,5,       1,2,3,4,6}

A U B = {1,2,3,4,5,6}

The set union operation combines two sets into one bigger set. Duplicates are tossed out.

There are 6 elements in the set A U B = {1,2,3,4,5,6} out of 6 faces of the number cube.

Therefore, the probability event  A U B happens is 6/6 = 1 = 100%; i.e. it is guaranteed to happen. Each face of the number cube is either odd, a factor of 12, or both.

Side notes:

Answer:

just make a 120 angle and divide it by 2, 60.

The expression "D(50) - (D(15) ∪ D(20))" refers to the set difference between the set D(50) and the union of sets D(15) and D(20).

The set difference is the operation that gives you the elements that are in the first set (D(50)) but not in the second set (D(15) ∪ D(20)). Note that this prompt draws on Set Theory.

Set Theory is a branch of mathematics concerned with the study of sets, their properties, and their relationships.

In set theory, a set is a collection of distinct objects, and the set difference operation, represented by the minus sign (-), returns the elements that are in the first set but not in the second set.

The union of sets, represented by the symbol ∪, is the operation that gives you the set of all elements that are in at least one of the sets being considered.

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The quadrilateral which is a rectangle is a parallelogram for which a diagonal of the parallelogram creates two congruent triangles, indicating that the opposite sides of the quadrilateral, which are corresponding sides of the triangles are congruent.

A parallelogram is a quadrilateral that has two pairs of parallel opposite sides.

Elena can use the fact that all rectangles parallelograms to prove that a quadrilateral with 4 right angles must have congruent opposite sides as follows;

A quadrilateral with 4 right angles is a rectangle by definition of a rectangle.

A rectangle is a parallelogram, and the diagonal of the quadrilateral creates two congruent triangles, by Angle-Side-Angle, ASA congruency as follows;

The opposite sides of the quadrilateral are corresponding sides of the two congruent triangles and are therefore congruent by CPCTC.

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