Corresponding angles theorem states that parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.
To prove m∠ = m∠2.
Then,
m∠3 + m∠2 = 180m∠1 + m∠3 = 180m∠1 = m∠2How to prove corresponding angles?The corresponding angles theorem states that If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.
Corresponding angles are formed when a transversal passes through two lines.
As we know that line segment m is parallel to the line segment n.
m || n .
Hence,
m∠3 + m∠2 = 180 (same interior angles)
Same side interior angles are two angles that are on the same side of the transversal and on the interior of (between) the two lines.
Same side interior angles are supplementary.
m∠1 + m∠3 = 180(sum of angles on a straight line)
Angles on a straight line is supplementary.
So, by transitive property of equality, we get:
m∠ = m∠2
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Air is supplied to the activated sludge plant in Example 4 temperature of 25 oC. The oxygen transfer efficiency is 10%, Assum that the BOD5 is 67.5 percent of the ultimate BOD, calculate the volu of air supplied to the plant.
The volume of air supplied to the plant is 105.12 times the ultimate BOD.
Given the BOD5 as 67.5% of ultimate BOD and ultimate BOD as BODu.
So BOD5 = 0.675 BODu.
Here, it is assumed that the BOD of the waste is completely degraded.
Now, oxygen demand, L per day = [0.68 BODu (kg/day)] / [(kg/m3 ) (kg O2/kg BOD)]
= (0.68 BODu)/ 2
= 0.34 BODu.
The weight of air required for oxygen demand is given by:
Weight of air = L/day x 24 hr/day x 1.3 kg air/kg O2
= 0.34 BODu x 24 x 1.3
= 10.512 BODu.
Now, oxygen transfer efficiency is 10%.
Hence, the volume of air required is given by:
Air supply = Weight of air / Oxygen transfer efficiency
= 10.512 BODu/ 0.1
= 105.12 BODu.
Therefore, the volume of air supplied to the plant is 105.12 times the ultimate BOD.
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hey, please help. thank you
Answer:
SAS
Step-by-step explanation:
pretty sure since the angle z is connected to both right triangles the sides become congruent.
Find the most general real-valued solution to the linear system of differential equations x⃗ ′=[12−25]x⃗ .x→′=[1−225]x→.
The most general real-valued solution to the given linear system of differential equations is a combination of exponential terms involving eigenvalues and eigenvectors of the matrices A and B.
To find the most general real-valued solution to the linear system of differential equations:
x⃗ ′ = [12 − 25]x⃗
x→′ = [1 − 225]x→
Let's denote the matrix [12 − 25] as A and the matrix [1 − 225] as B. The system of differential equations can be written as:
x⃗ ′ = Ax⃗
x→′ = Bx→
To find the general solution, we need to solve the system of differential equations. Let's start with the first equation:
x⃗ ′ = Ax⃗
We can solve this equation by finding the eigenvalues and eigenvectors of matrix A. The eigenvalues, λ, are the solutions to the characteristic equation:
det(A - λI) = 0
where I is the identity matrix.
Solving this equation will give us the eigenvalues λ1 and λ2.
Once we have the eigenvalues, we can find the corresponding eigenvectors, v1 and v2.
The general solution for the first equation is then given by:
x⃗ = c1 * e^(λ1t) * v1 + c2 * e^(λ2t) * v2
where c1 and c2 are constants.
Now, let's move on to the second equation:
x→′ = Bx→
Similarly, we find the eigenvalues μ1 and μ2 of matrix B and the corresponding eigenvectors w1 and w2.
The general solution for the second equation is:
x→ = k1 * e^(μ1t) * w1 + k2 * e^(μ2t) * w2
where k1 and k2 are constants.
Combining the solutions for both equations, the most general real-valued solution to the given linear system of differential equations is:
x⃗ = c1 * e^(λ1t) * v1 + c2 * e^(λ2t) * v2
x→ = k1 * e^(μ1t) * w1 + k2 * e^(μ2t) * w2
where c1, c2, k1, and k2 are constants, and λ1, λ2, v1, v2, μ1, μ2, w1, and w2 are determined by the eigenvalue-eigenvector analysis of matrices A and B, respectively.
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Harry has a cube with a side length of 7 cm. What is the volume of Harry's cube?
Given,
Side = 7 cm
We know that,
Volume of a cube = side³
So, volume of Harry's cube
= (7 cm)³
= 343 cm³
Hi, here's a quick explanation;
if the given length is 7, and your object is a cube,
you'd cube 7,
which is = 7³
aka: 7 × 7 × 7
therefore,
the answer is 343.Hope this helps you out!! :D
In a math class with 25 students, a test was given the same day that an assignment was due. There were 15 students who passed the test and 20 students who completed the assignment. There were 13 students who passed the test and also completed the assignment. What is the probability that a student passed the test given that they did not complete the homework?
Answer:
40%
Step-by-step explanation:
20-15 = 5, 2 students passed and did the assignment, 0.4 = 40%
15. Find the value of x.
(68 - x)
3x
Answer:
17=x
Step-by-step explanation:
In this case, we need to use Vertical Angles Theorem to solve this problem. Basically, because of the position of the angles, they are congruent.
68-x = 3x
Add x to both sides
68=4x
Divide by 4
17=x
Hope this helps!
Answer:
The value of 'x' is: 17°
Step-by-step explanation:
From what is being shown, there are two angles that are given:
(68 - x)°
3x°
Since they are congruent angles, meaning they are equal to each other, they will be put into a(n) equation such like shown below:
(68 - x)° = 3x°
(Then remove the parenthesis)
68° - x° = 3x°
+ x°=+3x°
------------------
68° = 4x°
------------------
(Divide both sides by 4)
\(\frac{68}{4} = \frac{4x}{4}\)
------------------
17° = x
------------------
Your value of 'x' is 17.
1.Illustrate A U B and A N B using Venn diagrams given that
A= b,d,f,g,h
B=c,d,e,f,g
U=a,b,c,...,i
2.Using the same given sets in the previous problem illustrate B' and B given - A using venn Diagrams.
PLS I NEED HELPP
1. A∪B = {b, c, d, e, f, g}
A∩B = {d, f, g}
2. B' = { a, b, h , l)
How to determine the identitiesFrom the information given, we have that:
A= b, d , f, g,B= c ,d ,e , f, gU=a, b, c, d, e ,f ,g, h, iA∪B = {The sum of sets in A and B without repetition}
Then we have:
A∪B = {b, c, d, e, f, g}
A∩B = {Sets found in both A and B}
Then, we have:
A∩B = {d, f, g}
2. B' = { sets found in the universal set and not in B}
We have:
B' = { a, b, h , l)
Thus, we can see that union and intersection of sets give different subsets from the two original sets.
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half-life of Po-210 is 140 days. If the initial mass of the sample is 5
kg, how much will remain after 420 days.
Answer:
\(0.625kg\)
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass after 420 days
in order to solve so we can consider the half-life formula given by
\( \displaystyle f(t) = a {0.5}^{t/T} \)
where:
f(t) is the remaining quantity of a substance after time t has elapsed.a is the initial quantity of this substance.T is the half-lifesince it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
\(\displaystyle f(420)=5\cdot{0.5}^{420/140}\)
reduce fraction:
\(\displaystyle f(420)=5\cdot{0.5}^{3}\)
By using calculator we acquire:
\(\displaystyle f(420)=0.625\)
hence, the remaining sample after 420 days is 0.625 kg
Given: 51 = 650 W/m²; st = 275 W/m²; L1 = 94 W/m²; and L1 = 395 W/m2 Compute the albedo (a) and enter your answer in the text box. DO NOT INCLUDE UNITS, JUST THE NUMERICAL VALUE.
The albedo (a)in this case is approximately 0.4231.
How to calculate the albedo (a)To compute the albedo (a), we need to understand the terms given.
Albedo is the measure of reflectivity of a surface, expressed as the ratio of the reflected solar radiation (st) to the incoming solar radiation (51).
Here, 51 = 650 W/m² represents the total solar radiation, and st = 275 W/m² represents the reflected solar radiation.
Additionally, L1 = 94 W/m² and L1 = 395 W/m² seem to be irrelevant to the calculation of albedo, as they don't represent incoming or reflected solar radiation.
Therefore, we can disregard these terms for this calculation.
Now, we can calculate the albedo (a) using the formula:
a = (reflected solar radiation) / (incoming solar radiation) a = (st) / (51)
By substituting the given values:
a = (275 W/m²) / (650 W/m²) a ≈ 0.4231
Remember, albedo values range from 0 to 1, where 0 indicates no reflectivity and 1 indicates total reflectivity.
In this case, just provide the numerical value as the answer: 0.4231
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How do you solve this??
Answer:
\(a_n=-\frac{9}{4} +\frac{1}{4} *n; \ a_{45}=9.\)
Step-by-step explanation:
1. the difference between two sequent term is: 2- 7/4=7/4 - 3/2 = 3/2 - 5/4=... = 1/4.
2. using the value of the calculated difference it is possible to make up the formula of the given sequence ('n' - the number of term):
\(a_n=-\frac{9}{4}+\frac{1}{4} n.\)
3. for n=45:
\(a_{45}=-\frac{9}{4}+45*\frac{1}{4}=9.\)
Tom has 13 new magazines to read. Let M be the number of magazines he would have left to Read after reading R of them. Write an equation relating to M to R. Then graph your equation using the axis below
The equation that relates M to R is M = 13 - R
How to determine the equation that relates M to R?From the question, we have the following parameters:
Total number of new magazines = 13Number of magazines read = RNumber of magazines left = MThe total number of new magazines is the sum of the number of magazines read and the number of magazines left
This is represented as
Total number of new magazines = Number of magazines read + Number of magazines left
Substitute the known values in the above equation
13 = R +M
Make M the subject
M = 13 - R
Hence, the equation is M = 13 - R
See attachment for the graph
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A boutique sold $127.50 worth of purses. How many purses did they sell?
$7.50
Answer:
They sold 17 purses
Step-by-step explanation:
please reply within 10 minutes
Answer:
H
Step-by-step explanation:
For F - Median For Class 1 is 52.5 Median for Class 2 is 75 ( False )
For G - Range for class 2 is 75 Range for class 1 is 45.9 ( False )
For H - IQR for class 1 is 30.45 IQR for class 2 is 60 ( True )
For J - Minimum for Class 2 is 30 Minimum for Class 1 is 30 ( False )
Can someone help with this problem please.
A sheet of paper, 12 inches by 18 inches, is folded so that 2 opposite corners touch, as shown in the figures below. What is the area, in square inches, of the shaded triangle formed as the result of the overlap. (Please look at the picture!)
The area of the shaded triangle formed as the result of the overlap is = 62.35 inches ²
Calculation of the equilateral triangleAfter folding the rectangle with length of 12 inches and width of 18 inches, an equilateral triangle was formed.
An equilateral triangle is a type of triangle where by all the three sides are equal.
To determine the value of one of the sides, CB or CD is used because the folding didn't affect these sides.
Using the formula for the area of an equilateral triangle,
A = √¾ a²
a= 12 inches
A = √¾ ×12²
A = 62.35 inches ²
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Answer:
Its 78!!!!
Solution:
1/2(12 * 18 - 5 * 12) = 78
Question 1
03.04MC)
The sum of the consecutive numbers is 84 What is the largest of these number? A. 26
B. 27
C. 28
D. 29
plz help im giving 15 points!
Answer:
i dont know because u didnt give me how many numbers
Step-by-step explanation:
PLS HELP 50 POINTS!!!! NEED THIS IN 1 HOUR!!!
Which equation justifies why nine to the one third power equals the cube root of nine?
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
nine to the one third power all raised to the third power equals nine raised to the one third plus three power equals nine
nine to the one third power all raised to the third power equals nine raised to the one third minus three power equals nine
nine to the one third power all raised to the third power equals nine raised to the three minus one third power equals nine
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Step-by-step explanation:
we know that
The Power of a Power Property , states that :To find a power of a power, multiply the exponents
so
In this problem we have
Remember that
Raise to the third power
Applying the power of power property
therefore
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Answer:
You’re already a hero!
Helping others is the best! We’re sure you can give a great answer.
Step-by-step explanation:
Solve (2x + 5)² – 7 = 0 using extracting the square root.
Answer: x = \(\frac{ \sqrt{7}-5}{2}\)
x = \(\frac{ -\sqrt{7}-5}{2}\)
Step-by-step explanation:
\((2x + 5)^{2} - 7 = 0\)
Add 7 to both sides of the equation.
\((2x + 5)^{2} - 7 + 7= 0 + 7\)
Subtracting 7 from itself leaves 0.
\((2x + 5)x^{2} =7\)
Take the square root of both sides of the equation.
\(2x + 5 = \sqrt{7} \\2x + 5 = -\sqrt{7}\)
Subtract 5 from both sides of the equation.
\(2x + 5 - 5 = \sqrt{7} - 5 \\2x + 5 - 5 = - \sqrt{7} - 5\)
Subtracting 5 from itself leaves 0.
\(2x = \sqrt{7} - 5 \\2x = - \sqrt{7} - 5\)
Subtract 5 from \(\sqrt{7}\).
\(2x = \sqrt{7} - 5\)
Subtract 5 from \(-\sqrt{7}\).
\(2x = -\sqrt{7} - 5\)
Divide both sides by 2.
\(\frac{2x}{2} =\frac{ \sqrt{7}-5}{2} \\\frac{2x}{2} =\frac{- \sqrt{7}-5}{2}\)
Dividing by 2 undoes the multiplication by 2.
\(x=\frac{ \sqrt{7}-5}{2}\\x=\frac{ -\sqrt{7}-5}{2}\)
solve for X: -0.6x>3
Answer:
x < -5
Step-by-step explanation:
-0.6x > 3
=> Dividing 0.6 on both sides
=> -x > 3/0.6
=> -x > 5
=> x < -5 [When we multiply -1 on both sides the sign changes]
The solution to the inequality -0.6x > 3 is x < -5.
To solve for x in the inequality -0.6x > 3, we need to isolate x on one side of the inequality.
First, to divide both sides of the inequality by -0.6 to remove the coefficient in front of x.
Remember that when dividing or multiplying both sides of an inequality by a negative number, we need to reverse the inequality sign.
So, dividing both sides by -0.6 gives
x < 3 / -0.6
Simplifying the right side of the inequality, we have:
x < -5
Therefore, the solution to the inequality -0.6x > 3 is x < -5.
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Solve the following systems of equations. 2x + y = 3 and y= -5x + 5
y=-5x+5...(1)
2x+y=3...(2)
subt (1)into (2)
2x+(-5x+5)=3
2x-5x-5=3
2x-5x=3+5
-3x=8
divide by -3
x=-8/3
subt 2 into 1
y=-5(-8/3)+5
y=55/3
Solve for c round your answer to the nearest tenth
Answer:
C = 7.72 ~ 7.7
Step-by-step explanation:
So when you solve this equetion you must 1st find x then c
we can find x by using cos(60)
cos(60) = x/14
x = cos(60) × 14
x = 1/2 ×14
x = 7
so after we find x we are going to solve c by using cos (25)
cos (25) = X/C = 7/c
cos(25) × C = 7
C = 7/cos (25)
C = 7.72 ~ 7.7
so the solution is 7.7
suppose x and y are proportional. which of the following statements are true? select all that apply.
Suppose x and y are proportional. 3rd , 4th and 5th options are correct.
What is proportional in an equation?
The equation y = kx represents a proportionate relationship between two quantities y and x that have the same proportionality constant, k. A proportionate relationship exists if an equation in a different form can be rewritten as shown above.Given that x and y are proportional ,
then , x = my for some constant m
Δx = Δ (my) ⇒ m Δy
∴ 3rd option is correct .
x = my
y = 1/m x ⇒ kx
∴ 4th option is correct.
the points ( 0,0) satisfies x = my
the point ( 0, 0 ) is on the graph of y in terms of x .
∴ 5th option is correct .
y = kx
Δy = Δ ( kx) ⇒ k Δx
∴ 1st option is not true .
y = 2x also implies x and y are proportional .
∴ 2nd option is not true .
∵ 3rd , 4th and 5th options are correct.
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The complete question is -
Suppose x and y are proportional. Which of the following statements are true? Select all that apply. Ay = kx, where k is constant Oy=3 D Ax = mAy, where m is constant Oy kä, where k is constant The point(0, 0) is on the graph of y in terms of
Consider the logistic differential equation:
dy/dx = y/8(6 - y)
Let f(t) be the particular solution to the differential equationwith f(0) = 8
a. What is the limiting factor?
b. Use Euler's method, starting at t=0 with two steps of equalsize, to appropriate F(1).
c. What is the range of f for t > 0
The approximate value of f(1) using Euler's method with two steps of equal size is 6.636. The range of f for t > 0 is 0 < f(t) < 6.
a. The limiting factor in this logistic differential equation is the carrying capacity, which is 6 in this case. As y approaches 6, the growth rate of y slows down, until it eventually levels off at the carrying capacity.
b. To use Euler's method, we first need to calculate the slope of the solution at t=0. Using the given differential equation, we can find that the slope at t=0 is y(0)/8(6-y(0)) = 8/8(6-8) = -1/6.
Using Euler's method with two steps of equal size, we can approximate f(1) as follows:
f(0.5) = f(0) + (1/2)dy/dx|t=0
= 8 - (1/2)(1/6)*8
= 7.333...
f(1) = f(0.5) + (1/2)dy/dx|t=0.5
= 7.333... - (1/2)(7.333.../8)*(6-7.333...)
= 6.636...
Therefore, the approximate value of f(1) using Euler's method with two steps of equal size is 6.636.
c. The range of f for t > 0 is 0 < f(t) < 6, since the carrying capacity of the logistic equation is 6. As t approaches infinity, f(t) will approach 6, but never exceed it. Additionally, f(t) will never be negative, since it represents a population size. Therefore, the range of f for t > 0 is 0 < f(t) < 6.
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At the beginning of the week, a stock was $82.73 per share.
On Monday, the stock gained $0.19 per share.
-On Tuesday, it gained $0.07 per share.
-On Wednesday, the stock lost $0.13 per share.
-On Thursday, it lost $0.25 per share.
On Friday morning, what was the price of the stock per share?
Ejemplos prácticos de cuando usamos la fórmula general en nuestra vida cotidiana? Ayúdenme por favor
What is the area of major sector DFE?
Answer:
B. 171.74 cm²
Step-by-step explanation:
Area of a sector = \( \frac{\theta}{360} \times \pi r^2 \).
Where,
\( \theta = 260 \)
radius (r) = 8.7 cm
Plug in the values into the formula
Area of sector = \( \frac{260}{360} \times \pi 8.7^2 \)
Area of sector = \( \frac{260 \times \pi 75.69}{360} \)
Area of sector = 171.74 cm² (approximated)
Answer:
B. 171.69 cm²
Step-by-step explanation:
On average, Carmen can drive 28 miles on every gallon of gasoline. If she fils up her tank for $225 per gallon, how much
will it cost her to drive 336 mies?
Mhanifa please help i will mark brainliest
Answer:
NO is answer I believe if you rotate the figure such that the similar sides IJ and MN are on top.
Step-by-step explanation:
use the trapezoidal rule and simpson's rule to approximate the value of the definite integral for the given value of n. round your answer to four decimal places and compare the results with the exact value of the definite integral. 5 x x2 4 0 dx, n
Exact value of the definite integral is 320. Comparing the results: Exact value of the definite integral = 320, Trapezoidal Rule approximation (n = 4) = 340, Simpson's Rule approximation (n = 4) ≈ 246.6667.
What is trapezoid?
A trapezoid is a quadrilateral (a polygon with four sides) that has one pair of parallel sides. The parallel sides are called the bases of the trapezoid, while the non-parallel sides are called the legs.
To approximate the value of the definite integral ∫[0, 4] 5x * x^2 dx using the Trapezoidal Rule and Simpson's Rule, we need to specify the value of n, which represents the number of subintervals.
Let's calculate the approximations using n = 4 for both methods:
Trapezoidal Rule:
Using n = 4, we divide the interval [0, 4] into four subintervals of equal width: h = (4 - 0) / 4 = 1.
The approximated value using the Trapezoidal Rule is given by:
\(T_4 = (h/2) * [f(x_0) + 2f(x_1) + 2f(x_2) + 2f(x_3) + f(x_4)]\)
Plugging in the values:
\(T_4 = (1/2) * [f(0) + 2f(1) + 2f(2) + 2f(3) + f(4)]\\\\= (1/2) * [5(0)(0^2) + 2(5)(1)(1^2) + 2(5)(2)(2^2) + 2(5)(3)(3^2) + 5(4)(4^2)]\\\\= (1/2) * [0 + 10 + 80 + 270 + 320]\\\\= (1/2) * 680\\\\= 340\)
Simpson's Rule:
Using n = 4, we divide the interval [0, 4] into four subintervals of equal width: h = (4 - 0) / 4 = 1.
The approximated value using Simpson's Rule is given by:
\(S_4 = (h/3) * [f(x_0) + 4f(x_1) + 2f(x_2) + 4f(x_3) + f(x_4)]\)
Plugging in the values:
\(S_4 = (1/3) * [f(0) + 4f(1) + 2f(2) + 4f(3) + f(4)]\\\\= (1/3) * [5(0)(0^2) + 4(5)(1)(1^2) + 2(5)(2)(2^2) + 4(5)(3)(3^2) + 5(4)(4^2)]\\\\= (1/3) * [0 + 20 + 40 + 360 + 320]\\\\= (1/3) * 740\\\\= 246.6667\)
Exact value of the definite integral:
∫[0, 4] 5x * \(x^2\) dx = [(5/4) * \(x^4\)] evaluated from 0 to 4
\(= (5/4) * 4^4 - (5/4) * 0^4\\\\= (5/4) * 256 - (5/4) * 0\\\\= 320 - 0\\\\= 320\)
Comparing the results:
Exact value of the definite integral = 320
Trapezoidal Rule approximation (n = 4) = 340
Simpson's Rule approximation (n = 4) ≈ 246.6667
As we can see, the Trapezoidal Rule approximation is slightly greater than the exact value, while Simpson's Rule approximation is less than the exact value.
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Suan did 145 random math problem from each math book in her library. Each math book in the library ha an equal number of problem. I thi ample of the math problem in the library likely to be biaed?
Without additional information, it is not possible to say whether Suan's sample of 145 math problems is likely to be biased or not.
It is difficult to say whether this sample of math problems is likely to be biased without more information. A sample is considered biased if it is not representative of the larger population from which it was taken.
In this case, we do not know how many math books there are in the library or how many math problems each book contains. If there are only a few books in the library, then a sample of 145 problems is likely to be biased as it may not accurately reflect the range of difficulty levels in the library as a whole.
On the other hand, if there are many books in the library, a sample of 145 problems may be representative of the larger population and not biased.
Therefore, without additional information, it is not possible to say whether Suan's sample of 145 math problems is likely to be biased or not.
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--The given question is incomplete; the complete question is
"Suan did 145 random math problems from each math book in her library. Each math book in the library has an equal number of problems. Is this sample of the math problem in the library likely to be biased?"--
Can 2.5 cm 6.5 cm 6 cm be the sides of a right triangle?
2.5 cm, 6.5 cm, and 6 cm are the sides of a right triangle.
The sides of a triangle are 2.5 cm, 6.5 cm, and 6 cm in length.
The Pythagorean Theorem states that The sum of the squares representing the base and height equals the square of the hypotenuse.
\((Perpendicular)^{2}+(Base)^{2}=(Hypotenuse)^{2}\)
\((2.5)^{2}+(6)^{2}=(6.5)^{2}\)
6.25 + 36 = 42.25
42.25 = 42.25
The sides offered satisfy the specifications for a right triangle.
Given that it satisfies the Pythagorean theorem, a right triangle with sides of 2.5 cm, 6.5 cm, and 6 cm can be built.
Hence, 2.5 cm 6.5 cm 6 cm can be the sides of a right triangle.
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