Answer:climate change I believe cause of global warming it’s melting all the permafr0st slowly and it will take time but it’s one day gonna be all gone
Explanation:
hope this helps have a nice day
the following are physiologic roles of copper except: connective tissue synthesis. maintenance of heart muscle. normal sexual development. functioning of the central nervous system.
The physiologic roles of copper include connective tissue synthesis, maintenance of heart muscle, normal sexual development, and functioning of the central nervous system. However, the statement in the question is incorrect as it states that copper does not have a role in connective tissue synthesis. In fact, copper is essential for the cross-linking of collagen fibers in connective tissue, which gives it strength and stability.
The following are physiologic roles of copper except: maintenance of heart muscle. Copper is essential for connective tissue synthesis, normal sexual development, and functioning of the central nervous system, but it is not directly responsible for maintaining heart muscle.
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the fundamental mechanism by which enzymes catalyze reactions is: a. they bind substrate just as a lock holds a key b. they utilize free energy from atp to convert substrate to product c. they stabilize the substrate of the reaction d. they stabilize the transition state of the reaction e. they stabilize the product of the reaction
A biological catalyst is an enzyme. Reactions' activation energies are reduced by catalysts. The rate of a reaction increases with decreasing activation energy. Enzymes accelerate processes by reducing activation energy.
The bonds holding together the atoms in molecules are ruptured, altered, and repaired during a chemical reaction, recombining the atoms to form new molecules. By lowering the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process. As a result, catalysts facilitate the formation of chemical bonds between atoms to create novel combinations and new compounds. Chemical reactions are accelerated and become more energy-efficient when catalysts are used. Additionally, catalysts possess a crucial quality known as selectivity that allows them to control an unwanted products.
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What bird species was most noticeably impacted by West Nile virus when the virus was first detected? Was this the only bird species affected by the virus?
Answer:
Mostly crows, robins, and jays were the first of a few bird species impacted by the West Nile Virus when it was detected.
No, there were over 300 species discovered to be affected by the virus, these were just the main ones to be impacted.
GIZMOs- Nitrogen Cycle- High School
Please help label them
Answer:
Explanation:
third tank is nitrie nitrieying
PLEASE HELP ASAPPPP
The question for this is: Four substances are involved in both photosynthesis and cellular respiration. They are sugars, water, oxygen, and carbon dioxide. Energy is also transformed from one type to another. Describe what happens to these four substances, light energy, and chemical energy during photosynthesis. Then write a simple equation for the substances and another for energy, using words and arrows to illustrate these changes.
My friends answer is:
Photosynthesis is the process by which plants use light energy to convert water and carbon dioxide into sugars and oxygen. During photosynthesis, light energy is absorbed by the plant and converted into chemical energy. The water and carbon dioxide are broken down into their component parts, and the oxygen is released into the atmosphere. The sugars are stored in the plant for later use. The equation for photosynthesis can be represented as light energy + water + carbon dioxide → sugars + oxygen. The equation for energy transformation can be represented as light energy → chemical energy.
D u m b it down to make it look like an 8th grader wrote it pls and thank u
Plants employ the process of photosynthesis to transform water and carbon dioxide into carbohydrates and oxygen.
Light energy is absorbed by the plant during photosynthesis and transformed into chemical energy. The oxygen is released into the environment, while the water and carbon dioxide are disintegrated into their component elements.
In the plant, the sugars are kept for future use. It is possible to write the photosynthesis equation as follows:
Light energy + water + carbon dioxide → sugars + oxygen.
Light energy → chemical energy can be used to describe the energy transformation equation.
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Which of the following phrases best describes the function of meiosis?
Group of answer choices
produces genetically unique diploid cells
produces genetically identical haploid cells
produces genetically unique haploid cells
produces genetically identical diploid cells
Answer: C.) Produces genetically unique haploid cells
Explanation: Meiosis will produce genetically unique cells because they are meant to pass onto offspring, and they are haploid because there are half the number of chromosomes in them. The organism will receive 2 sets, one from each parent, so that is why each parent who's cells undergo meiosis have to produce haploid cells.
40 yr old man, skin very sensitive to sunlight, formation of vesicles and blisters due to increase synthesis of compounds in skin subject to excitation of visible light. What biochem pathway defective ?
Therefore, this is a genetic condition that cannot be cured, and individuals who suffer from it must take appropriate precautions to protect themselves from sunlight to avoid complications.
The biochemical pathway that is likely defective in a 40-year-old man with skin that is sensitive to sunlight, the formation of vesicles and blisters due to an increase in the synthesis of compounds in skin subject to the excitation of visible light is the nucleotide excision repair (NER) pathway. It is important to note that it is a very intricate pathway.
The NER pathway's primary role is to identify and eliminate many types of DNA damage induced by a range of chemical and physical insults, including ultraviolet light (UV) from the sun. It is also capable of repairing specific types of DNA damage induced by a range of chemical and physical stimuli, such as cyclobutane pyrimidine dimers (CPDs), which are commonly caused by UV light.
This pathway's malfunction causes xeroderma pigmentosum (XP), which is a severe genetic disorder. XP is a rare, autosomal recessive disorder characterized by an extreme sensitivity to sunlight. The individual has a significantly increased risk of skin cancer because of a defect in DNA repair. There is no known cure for XP. Treatment involves preventing symptoms and skin damage.
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You are thinking about setting up a fish farm in your pond. You can rig it up to farm Tilapia or Pollock, but not both. You have the following information on the two possibilities:
Type of
Fish Farm Initial
Cost Annual
Cash Flow
Tilapia $1,000 $200
Pollock $1,800 $350
Each option will yield the annual cash flows for 10 years and then will be finished with no additional cost or revenue. If the required return is 8%, what is the PI of the incremental project that you would use to decide between these two types of fish farms?
a.) 0.6468
b.) 0.3420
c.) 0.2581
\(\huge\color{blue}\boxed{ANSWER:}\)
To calculate the Present Value (PV) of each project, we need to discount the annual cash flows at the required return rate of 8%. Then, we can calculate the Net Present Value (NPV) for each option:
For Tilapia:
\(PV = (200/1.08) + (200/1.08^2) + ... + (200/1.08^10) = 1473.40 \:
Initial \: Cost = 1000\)
NPV of Tilapia = PV - Initial Cost = 1473.40 - 1000 = 473.40
For Pollock:
\(PV = (350/1.08) + (350/1.08^2) + ... + (350/1.08^10) = 2581.61 \:
Initial \: Cost = 1800\)
NPV of Pollock = PV - Initial Cost = 2581.61 - 1800 = 781.61
To calculate the Profitability Index (PI), we divide the NPV of each project by the initial cost:
\(PI \: of \: Tilapia = NPV of \: Tilapia / Initial Cost = 473.40 / 1000 = 0.4734 \\
PI \: of \: Pollock = NPV of \: Pollock / Initial Cost = 781.61 / 1800 = 0.4342\)
Since we are interested in the increment (difference) between the two projects, we calculate:
\(Incremental \: PI = \: PI \: of \: Pollock - PI \: of \: Tilapia = 0.4342 - 0.4734 = - \: 0.0392\)
The Profitability Index of the incremental project is approximately -0.0392. None of the given choices match this value precisely, but the closest option is:
\(\large\color{green}\boxed{C. \: 0.2581}\)
When studying with a friend for a test, what key points about osmosis would you make sure you tell them? Check all that apply.
a. Osmosis refers to the movement of water along a concentration gradient
b. In osmosis, water moves to equalize solute concentrations on either side of the membrane
c. If osmosis occurs across a membrane, then diffusion is not occurring
d. The movement of water across a membrane can affect the turgor pressure of some cells
Osmosis is the process by which the movement of water occurs along the concentration gradient, hence options A, B, and D are correct.
What is osmosis?It is the process in which the movement of solvent occurs from a low concentration of solute to a high concentration of solute through a semipermeable membrane.
In osmosis, water moves to balance solute concentrations on either side of the membrane and it also affects the turgor pressure of some cells.
Therefore, water moves to balance solute concentrations, and the effect on the turgor pressure of some cells is observed during osmosis.
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goods and services that are nonexcludable and nonrivalrous and tend to be indivisible are ________. multiple choice private both public and private neither public nor private public
The goods and services that are nonexcludable and nonrivalrous and tend to be indivisible are public.
A public good is a commodity or service that is produced and provided without profit to all members of a community or society, either by the government or a private organization. The term "public" in this context refers to the population or society as a whole, rather than a particular group of people.
A non-excludable good is a good that may be used by anyone, regardless of whether or not they have paid for it. It is impossible to exclude anyone from using a non-excludable good. A non-rivalrous good is a good for which the use by one individual does not reduce the quantity or quality of the good available to others.
A good that is both non-rivalrous and non-excludable is a public good. Goods such as national defense, law enforcement, streetlights, and public parks are examples of public goods.
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6. Explain how the equations for photosynthesis and cellular respiration compare.
The products of one process are the reactants of the other. Notice that the equation for cellular respiration is the direct opposite of photosynthesis: Cellular Respiration: C6H12O6 + 6O2 → 6CO2 + 6H2O. Photosynthesis: 6CO2 + 6H2O → C6H12O6+ 6O.
HELP DUE IN 10 MINS!
All of the following are required for photosynthesis except:
a. Light
b. Chloroplasts
c. Oxygen
Answer:
chloroplast
Explanation:
light and oxygen are a crucial thing for plants
Answer:
c
Explanation:
:) have a nice day
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Geographic Isolation
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Question 1
Geographic isolation may result in
Responses
A extinctionextinction
B speciationspeciation
Question 2
Geographic isolation causes a reduction in ____________, eventually resulting in dissimilarities in a once-similar population of organisms.
Responses
A gene flowgene flow
B genetic mutationgenetic mutation
Question 3
Allopatric speciation is another name for
Responses
A speciation due to genetic mutationspeciation due to genetic mutation
B speciation by geographic isolation.
The answers to the questions are as follows:
Question 1:
Response: B speciation
Question 2:
Response: A gene flow
Question 3:
Response: B speciation by geographic isolation
Geographic isolation plays a significant role in shaping the evolution of species. Let's address each question individually:
Question 1:
Geographic isolation may result in:
Response: B speciation
Geographic isolation refers to the physical separation of populations of organisms due to geographical barriers such as mountains, rivers, or islands. When populations become isolated from each other, they experience different environmental conditions and selective pressures. Over time, these distinct environments can lead to genetic and phenotypic differences between the isolated populations. This divergence in characteristics can eventually result in the formation of new species, a process known as speciation. Therefore, option B, speciation, is the correct response.
Question 2:
Geographic isolation causes a reduction in ____, eventually resulting in dissimilarities in a once-similar population of organisms.
Response: A gene flow
Geographic isolation restricts or limits the movement of individuals between different populations. This restriction reduces the gene flow, which is the transfer of genetic material between populations. Gene flow is an important mechanism for maintaining genetic diversity and homogeneity within a population. When gene flow is reduced, isolated populations experience different genetic changes and accumulate genetic variations independently. Over time, these genetic differences can lead to dissimilarities in once-similar populations.
Question 3:
Allopatric speciation is another name for:
Response: B speciation by geographic isolation.
Allopatric speciation refers to the process of speciation that occurs when populations are geographically isolated from each other. The term "allopatric" means "different homeland." In this form of speciation, the physical separation of populations by a geographical barrier prevents gene flow between them. As a result, the isolated populations undergo independent evolutionary changes, leading to the formation of new species. Therefore, option B, speciation by geographic isolation, is the correct response.
In summary, geographic isolation can lead to speciation (Question 1), it reduces gene flow (Question 2), and the process of speciation by geographic isolation is known as allopatric speciation (Question 3).
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If it is true that when we look at objects nearly 11 billion light years away we are seeing them as they appeared 11 billion years ago, why are the galaxies that we see at great distances fully formed (mature) when the big bang model predicts they should be less organized at that early stage?
The galaxies appear to be matured when they should be less organized at that early stage because of the gravitational force by which they are joined.
What is the Big Bang Theory?The Big Bang Theory is the theory given about the formation of the universe. It says that the universe is founded by a small point that expands and created the universe, and it's still expanding.
The Big Bang Theory says that the universe should be less organized because it is randomly created, but the universe is growing and maturing more rapidly than it is thought about.
Thus, due to the gravitational attraction that binds the galaxies together, they appear mature while they should be less ordered at that early stage.
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the are repeating units within muscle fibers that act as the functional units of muscle contraction.
The fundamental contractile component of a myocyte is called a sarcomere (muscle fibre). The two primary protein filaments that make up a sarcomere—thin actin and thick myosin filaments—are the functional elements in charge of causing muscle contraction.
What is the name of the functional unit found within muscle cells?A sarcomere is the name for a skeletal muscle's functional unit. Myofibrils, which are comprised of actin and myosin filaments, make up the fibres of skeletal muscles. Sarcomeres, which are collections of these filaments, are formed.
The length of the myofibrils and subsequent myofibers can reach several centimetres. The muscle is made up of solitary multinucleated cells called muscle fibres. Sarcomeres, which are repeating units, make up myofibrils. Muscle contractions are mediated by these sarcomeres.
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What are similarities between all of the scientists mentioned in the reading?
Answer: made advancements in science, didn't try to fit what they discovered in with the church
Explanation:
(Its actually Physical Science)
To create a molecular model a student will use blue spheres to represent nitrogen (N) and white spheres to represent hydrogen (H). which option correctly describes a model of ammonia, NH3?
A. three blue spheres and three white spheres
B. one blue sphere and three white spheres
C. three blue spheres and one white sphere
D. one blue sphere and one white sphere
A molecular model is a three dimensional representation of a molecule that aids conceptualization of the actual nature of the molecule.
The correct answer is option B: one blue sphere and three white spheres
A molecular model helps us to see something close to what a molecule actually looks like in a three dimensional way.
The essence of molecular models is to aid conceptualization of details about arrangement of atoms in a molecule.
Since nitrogen is represented with blue balls and hydrogen is represented with white balls, it follows that a properly prepared model consists of one blue sphere and three white spheres.
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If many farmers begin to plant more genetically modified crops that have an increased tolerance to insects, what are some of the long term results?
The long term results of planting more genetically modified crops with an increased tolerance to insects are complex and multifaceted, and there are both potential benefits and potential risks that need to be considered.
One of the potential long term results of planting more genetically modified crops with an increased tolerance to insects is a decrease in the use of pesticides. This can have a positive effect on the environment, as there will be less chemical runoff into waterways and less potential for harm to non-target species.
However, there is also the potential for insects to develop resistance to the genetically modified crops, leading to a need for new methods of pest control.
Another potential long term result is an increase in crop yield, as the crops will be less likely to be damaged by insects. This can lead to a more stable food supply and potentially lower food prices.
However, there are also concerns about the potential impact of genetically modified crops on biodiversity and the potential for unintended consequences.
For example, there could be unintended effects on other species in the ecosystem or potential health risks for humans consuming the crops.
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PLS HELP A student has four snails, four sprigs of Elodea, eight test tubes of bromothymol blue, and two rooms (light and dark). The student wants to know what gases are produced by the snails and Elodea in light and dark conditions. Assuming the student only has time for one experiment, what setup will yield the most complete data? All test tubes contain bromothymol blue. Experiment 1: Light room with test tubes A to D. A contains 1 snail. B contains Elodea. C is empty. D contains 1 snail and Elodea. Dark room with test tubes E to H. E contains 1 snail. F contains Elodea. G is empty. H contains 1 snail and Elodea. Experiment 2: Light room with test tubes A to D. Each test tube contains 1 snail. Dark room with test tubes E to H. Each test tube contains Elodea. Experiment 3: Light room with test tubes A to D. Each test tube contains 1 snail and Elodea. Dark room with test tubes E to H. Each test tube is empty. Experiment 4: Light room with test tubes A to D. A contains 2 snails and Elodea. B contains 1 snail. C and D are empty. Dark room with test tubes E to H. E contains Elodea. F contains 1 snail and Elodea. G and H are empty. a. Experiment 1 b. Experiment 2 c. Experiment 3 d. Experiment 4
Answer:
Its A Experiment 1
Explanation:
You have conducted a simple population genetics analysis of two species. For both species you have measured genotype frequencies at a single locus for 50 individuals sampled from two locations. The data you obtained for each species is shown below.
Species A - observed genotype frequencies at two sampling locations and for both locations combined Genotype Frequencies Allele Frequencies HWE expected A/A A/a a/a Total # heterozygote frequency
individuals р q 2pq
Location 1 30 10 10 50 0.70 0.30 0.42 Location 2 5 10 35 50 0.20 0.80 0.32 Location 1 + 35 20 45 100
Location 2 Species B- observed genotype frequencies at two sampling locations and for both locations combined
Genotype Frequencies Allele Frequencies HWE expected A/A A/a a/a Total # heterozygote frequency
individuals р q 2pq
Location 1 20 10 20 50 0.50 0.50 0.50 Location 2 25 10 15 50 0.60 0.40 0.48 Location 1 + 45 20 35 100
Location 2 Hₛ = expected heterozygosity averaged across all locations
Hₜ = expected heterozygosity for the entire population ( i.e.location 1 + location 2 )
Fₛₜ + 1 - (Hₛ/Hₜ)
For both Species A and Species B, calculate the observed allele frequencies (p and q) and the expected heterozygote frequencies (2pq, assuming Hardy-Weinberg equilibrium) for Location 1 + 2.
using the information provided under the tables, calculate Fst for each species
what do these values for Fst tell you about geographic population subdivision in each species? Briefly explain your reasoning.
The Fst statistic reveals the degree of genetic variation between populations. If Fst is high, it indicates significant geographic population subdivision, while if it is low, it indicates little geographic population subdivision. As a result, Species A has significant population divergence in comparison to Species B.
Species A - observed genotype frequencies at two sampling locations and for both locations combined Genotype Frequencies
Allele Frequencies
HWE expected
A/AA/aa/a
Total#heterozygote frequency
individuals рq2pq
Location 130101050.70.30.42
Location 25 103550.20.80.32
Location 1 + 352045100
Location 2
The observed allele frequencies (p and q) and the expected heterozygote frequencies (2pq, assuming Hardy-Weinberg equilibrium) for Location 1 + 2:
Species A Observed allele frequencies: p=0.55 q=0.45
Expected heterozygote frequencies: 2pq = 2(0.55)(0.45)
= 0.495
Species B Observed allele frequencies: p=0.55 q=0.45
Expected heterozygote frequencies: 2pq = 2(0.55)(0.45)
= 0.495Fst
calculation: Fst is the proportion of genetic variation present among populations, and it is calculated by dividing the genetic variation between populations by the total genetic variation.
Fst = Fst = (Ht - Hs) / Ht
Species A: Fst = [0.495 − ((0.42 + 0.32) / 2)] / 0.495
Fst = 0.1767
Species B: Fst = [0.495 − ((0.50 + 0.48) / 2)] / 0.495
Fst = 0.0000
The Fst value is high in Species A and low in Species B. Species A shows a high Fst value (0.1767), which indicates a significant geographic population subdivision in this species. The low Fst value (0.0000) in Species B implies that there is little geographic population subdivision in this species.
The Fst statistic reveals the degree of genetic variation between populations. If Fst is high, it indicates significant geographic population subdivision, while if it is low, it indicates little geographic population subdivision. As a result, Species A has significant population divergence in comparison to Species B.
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In the cell cycle of typical cancer cells what have mutations done to the speed of the cell cycle?
Answer:
cells typically acquire more and more mutations, but cell division
Explanation:
The nature vs. nurture debate questions is...
Answer:
The nature versus nurture debate is one of the oldest issues in psychology. The debate centers on the relative contributions of genetic inheritance and environmental factors to human development.
Explanation:
Which of the following is NOT a classification of taxonomy?
Breed
Phylum
Class
Family
Answer:
Breed is the correct answer ( The last answer)
Explanation:
There are seven main taxonomic ranks: kingdom, phylum or division, class, order, family, genus, species.
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Many genes may interact to produce one trait:Epistasis
Epistasis is a kind of quality communication where the impact of one quality on a characteristic is subject to the presence of at least one modifier quality.
To put it another way, rather than one gene acting alone, the expression of a particular trait is affected by interactions between multiple genes.
Epistasis can take many different forms, including additive epistasis, dominant epistasis, and recessive epistasis, among others. The relationship between the involved genes' alleles determines the specific type of epistasis.
Epistasis is a mind-boggling peculiarity that can make it hard to foresee the declaration of specific qualities, as the communication between qualities can create surprising or non-natural results. In genetics and evolutionary biology, however, epistasis is important because it can help explain the diversity of traits observed in natural populations.
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i need help.
What happens during cytokinesis?
a. The cytoplasm becomes solid.
b. The cytoplasm changes color.
c. The cytoplasm falls apart.
d. The cytoplasm divides.
Answer:
d. The cytoplasm divides.
Explanation:
Last stage of the cell cycle
Explain what cell part muscle cells need more of than fat cells.
Answer:
Muscle cells require a significant amount of energy to function properly. Muscle cells have more mitochondria, which produce more ATP by utilizing power from the nutrition we consume. Fat cells, just from the other hand, use less energy to function.
The neurotransmitter acetylcholine (ACh) is most likely to be found:
The neurotransmitter acetylcholine (ACh) is most likely to be found at the neuromuscular junction in the skeletal muscle.
Acetylcholine (ACh) is a type of neurotransmitter. Acetylcholine is involved in the transmission of signals through the brain and nervous system, and it is the most abundant neurotransmitter in the body. A neurotransmitter is a chemical messenger that is produced in a nerve cell and transmitted to other cells, such as muscle cells, glands, or other nerves. Acetylcholine is produced in the presynaptic neuron and is released into the synaptic cleft to bind to receptors on the postsynaptic neuron.
Acetylcholine (ACh) is a neurotransmitter that is most commonly found at the neuromuscular junction in the skeletal muscle. It is involved in the transmission of signals through the brain and nervous system, and it is the most abundant neurotransmitter in the body. A neurotransmitter is a chemical messenger that is produced in a nerve cell and transmitted to other cells, such as muscle cells, glands, or other nerves.
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how do very tall plants (like trees) transport water and dissolved nutrients all the way to the leaves despite the high pressures needed to do this?
Very tall plants, such as trees, use a combination of passive and active transport mechanisms to transport water and dissolved nutrients from the roots to the leaves against gravity.
As per the question given,
The primary mechanism responsible for water transport is called transpiration, which is the process of water loss from leaves through small pores called stomata. Water molecules are cohesive and stick together through a property called "water tension" or "surface tension". When water evaporates from the leaves through transpiration, it creates a negative pressure or "suction force" that pulls water molecules up the plant's xylem, the specialized tissue responsible for water and nutrient transport. This negative pressure also helps to keep the plant's water column intact and prevents it from collapsing under the force of gravity.
However, the suction force generated by transpiration alone is not sufficient to transport water to the top of very tall plants like trees. Therefore, trees also use a pumping mechanism to move water against gravity. The active transport of ions (minerals and nutrients) in the plant's root cells creates a concentration gradient that drives water to flow into the roots through osmosis.
The water and dissolved nutrients then travel up the xylem in a process called "root pressure." The pressure generated by root pressure can help push water up the plant, particularly during periods of low transpiration rates or when water uptake is limited.
In summary, trees and other tall plants transport water and nutrients to the leaves through a combination of passive and active transport mechanisms that work together to overcome the high pressures required to move water and minerals up the plant. These mechanisms include transpiration, root pressure, and active ion transport, and they work together to ensure that water and nutrients are efficiently transported to all parts of the plant.
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Why is it important that the restriction enzymes used to make recombinant DNA generate sticky ends? See Section 20 Sticky ends of the recombinant DNA plasmid promote the replicator of the plasmid in bacterial cells. Sticky ends allow the recombinant DNA plasmid to enter the bacterial cell. Sticky ends allow the plasmid to re-anneal. The sticky ends on the plasmid and on the gene bind by complementary base pairing.
The statement that best answers the question is: Sticky ends on the plasmid and on the gene bind by complementary base pairing.
Recombinant DNA technology involves the manipulation and combination of DNA molecules from different sources to create new genetic material.
One of the crucial steps in this process is the use of restriction enzymes to cut DNA at specific recognition sites. These restriction enzymes produce DNA fragments with either blunt ends or sticky ends.
Sticky ends refer to the fragments of DNA that have single-stranded overhangs due to the staggered cleavage by restriction enzymes.
These single-stranded overhangs are complementary to each other and can base-pair with other DNA fragments with complementary sequences. The importance of sticky ends lies in their ability to facilitate the formation of recombinant DNA molecules.
When creating recombinant DNA, sticky ends on the plasmid and on the gene of interest can bind to each other through complementary base pairing.
This allows the gene of interest to be inserted into the plasmid, creating a recombinant plasmid. The sticky ends provide a temporary connection between the two DNA molecules, enabling DNA ligase to seal the strands together and form a stable recombinant DNA molecule.
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which of the following contributes to the fact that the small intestine cannot passively absorb bile salts? taurine and glycine have low pka values. bile salts are hydrophobic. pancreatic secretions increase intestinal ph.
The fact that bile salts are hydrophobic contributes to the fact that the small intestine cannot passively absorb them.
As amphipathic molecules with both hydrophilic and hydrophobic areas, bile salts have both. The hydrophilic part of the bile salts permits them to stay in solution in the aqueous environment of the digestive tract, whilst the hydrophobic region enables them to interact with and emulsify fats in the intestinal lumen.
Bile salts are hydrophobic, which makes it challenging for them to passively penetrate the hydrophilic epithelial cells lining the small intestine. Bile salts are combined with taurine or glycine to make them easier to absorb by lowering their hydrophobicity and raising their solubility in water.
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