Ignacio plays a game where he draws one card from a well-shuffled standard deck of 52 cards 5. He wins the game if the card he draws is a Jack or a 4 Are the two events mutually exclusive? There is not enough information to determine if the two events are mutually exclusive. The two events are not mutually exclusive. The two events are mutually exclusive. What is the probability that ignacio wins the game? What is the probability that ignacio loses the game?
The probability that Ignacio wins the game is 8/52, which can be simplified to 2/13. The probability that Ignacio loses the game is 1 - 8/52 = 44/52, which can be simplified to 11/13.
The probability that Ignacio wins the game is the sum of the probabilities of drawing a Jack and drawing a 4, which is P(Jack) + P(4). The probability that Ignacio loses the game is the complement of winning, which is 1 - P(win).
To calculate the probability, we first need to determine the number of favorable outcomes and the total number of possible outcomes. There are 4 Jacks and 4 4s in a standard deck of 52 cards. Since the events of drawing a Jack and drawing a 4 are mutually exclusive (a card cannot be both a Jack and a 4), the probability of winning is P(Jack or 4) = P(Jack) + P(4) = 4/52 + 4/52 = 8/52.
Therefore, the probability that Ignacio wins the game is 8/52, which can be simplified to 2/13. The probability that Ignacio loses the game is 1 - 8/52 = 44/52, which can be simplified to 11/13.
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Trucks begin removing gravel from two different piles at the same time. Pile A holds 255 tons of gravel initially, and the gravel is removed at a rate of 20 tons per hour. Pile B holds 220 tons of gravel initially, and the gravel is removed at a rate of 15 tons per hour. After a certain number of hours, the amount of gravel remaining in Pile A equals the amount of gravel remaining in Pile B. At that time, how many tons of gravel will remain in each pile? 70 tons 105 tons 115 tons 140 tons
Answer: after 7 hours, there will be 115 tons of gravel remaining in both Pile A and Pile B.
Step-by-step explanation:
Let t be the number of hours since both trucks began removing gravel. The amount of gravel remaining in Pile A after t hours can be represented by the function:
A(t) = 255 - 20t
Similarly, the amount of gravel remaining in Pile B after t hours can be represented by the function:
B(t) = 220 - 15t
To find the time at which the amount of gravel remaining in both piles is equal, we can set the two functions equal to each other and solve for t:
255 - 20t = 220 - 15t
35 = 5t
t = 7
After 7 hours, the amount of gravel remaining in both piles will be equal. To find the amount of gravel remaining in each pile at that time, we can plug in t = 7 into the two functions:
A(7) = 255 - 20(7) = 115
B(7) = 220 - 15(7) = 115
Answer:
115 tons for both piles.
Step-by-step explanation:
Let's use "h" to represent the number of hours it takes for both piles to have the same amount of gravel remaining.
The amount of gravel remaining in Pile A after "h" hours can be represented as:
255 - 20h
Similarly, the amount of gravel remaining in Pile B after "h" hours can be represented as:
220 - 15h
We know that at this point, the amount of gravel remaining in Pile A will equal the amount of gravel remaining in Pile B, so we can set the two expressions equal to each other and solve for "h":
255 - 20h = 220 - 15h
35 = 5h
h = 7
After 7 hours, Pile A will have:
255 - 20(7) = 115 tons of gravel remaining
After 7 hours, Pile B will have:
220 - 15(7) = 115 tons of gravel remaining
Therefore, the answer is 115 tons for both piles.
Help me how do I do this (221x3 + 154x2 + 228x + 41) / (17x + 4)-4
The value of x from the equation (221x3 + 154x2 + 228x + 41) / (17x + 4)-4 is 992
How to find the value of x?In general, the algebraic expression should take one of the following forms: addition, subtraction, multiplication, or division. Bring the variable to the left side and all the remaining values to the right side to find the value of x. To find the answer, simplify the values. In algebra, the letter "x" is frequently used to represent an unknown value. It is referred to as a "variable" or "unknown" at times.
(221x3 + 154x2 + 228x + 41) / (17x + 4)-4
Multiplying 221*3 and 154*2 =663,308
( 663+308 + 228x + 41) / (17x + 4)-4
( 971+ 228x + 41) / (17x + 4)-4
=( 971+ 228x +41)
(17x + 4)
=1012+228x
(17x + 4)
-x=-992
x=992
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Complete the square
x^2 - 2x - 14 = 0
Normal faults assume a more shallow dip angle with depth; when the fault plane becomes nearly horizontal, these faults are termed ____________.
Normal faults assume a more shallow dip angle with depth; when the fault plane becomes nearly horizontal, these faults are termed as thrust fault.
Since,
A reverse fault in which the dip of the fault plane is so small as to be almost horizontal is called thrust fault. In thrust faults, the hanging wall moves almost horizonatlly over the footwall.
Hence,
Normal faults assume a more shallow dip angle with depth; when the fault plane becomes nearly horizontal, these faults are termed as thrust fault.
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I’ll give the Brainliest to who answers these questions with reasonable explanations.
1. A car stereo is on sale for $250 from its original $273 cost. What is the percent of the discount?
A. 84%
B. 92%
C. 9.2%
D. 8.4%
————————————————————————————————————————————————————————
2. The Universal Sports Company purchases weight racks directly from the manufacturer for $46 each. The weight racks are marked up 210% of the wholesale cost and sold. What is the amount of mark-up of each weight rack?
A. $1012
B. $966
C. $96.60
D. $142.60
————————————————————————————————————————————————————————
3. A television set that has an original price of $325.50 is on sale for 30% off. What is the selling price of the television?
A. $423.15
B. $97.65
C. $325.50
D. $227.85
————————————————————————————————————————————————————————
4. The Haas Door Co. produces truck dock door seals. Their 9' × 10' seal costs $280 to produce. The mark-up rate is 75% of the cost to produce. What is the retail price?
A. $280
B. $490
C. $770
D. $210
Thanks for the help!
Answer:
\(\mathrm{1.\:D.\:8.4\%}\\\mathrm{2.\:C.\: \$96.60}\\\mathrm{3.\:D.\: \$227.85}\\\mathrm{4.\:B.\:\$490}\)
Step-by-step explanation:
1. The car's initial price was $273. Since the sale price is $250, the car is on a \(273-250=\$23\) discount. The percent of discount is the discount price over the initial price:
\(\frac{23}{273}\approx \fbox{$8.4\%$}\).
2. Since the weight racks were initially priced $46, then marked up 210%, their mark-up is:
\(46\cdot2.1=\fbox{$\$96.60$}\)
*Worth noting that this is the mark-up (as the question is asking), not the total price after the mark-up.
3. The TV's initial price is $325.50. If it's on sale for 30%, it's final price will be \(100\%-30\%=70\%\) of the initial price:
\(\$325.50\cdot 0.7=\fbox{$\$227.85$}\)
4. The final retail price will be the initial price + the mark-up:
\(280+280(0.75)=\fbox{$\$490$}\).
Two cars are approaching an intersection on roads that are perpendicular to each other. car a is north of the intersection and traveling south at 60 mph. car b is east of the intersection and traveling west at 45 mph. how fast is the distance between the cars changing when car a is 14 miles from the intersection and car b is 48 miles from the intersection? (round your answer to two decimal places.)
mph?
The distance between the cars is changing at approximately 66.6 mph (rounded to one decimal place).
Using the given information, we can find the rate at which the distance between the two cars is changing.
Car A is moving south at 60 mph, and Car B is moving west at 45 mph. At the given moment, Car A is 14 miles from the intersection and Car B is 48 miles from the intersection.
We can use the Pythagorean theorem to find the distance between the cars: distance² = 14² + 48².
The distance is √(196 + 2304) = √2500 = 50 miles.
Now, we can differentiate the equation with respect to time: 2 * distance * d(distance)/dt = 2 * 14 * (-60) + 2 * 48 * (-45).
Divide both sides by 2 * 50 to find d(distance)/dt: d(distance)/dt = (14 * (-60) + 48 * (-45)) / 50 ≈ -66.6 mph.
The distance between the cars is changing at approximately 66.6 mph (rounded to one decimal place).
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The following TI-
84
Plus display presents some sample statistics.
1-Var-Stats
x
=67
Σ
x=2291
Σx2
=182,361
Sx=8
σx=8.024961059
↓n=29
Part: 0 /
In this case, the mean of the data set is 67, the sum of all the data values is 2291, the sum of all the squared data values is 182,361, the sample standard deviation is 8, the population standard deviation is 8.024961059, and the sample size is 29.
The TI-84 Plus display presents sample statistics for a set of data. The "x" symbol represents the mean, or average, of the data set. The "Σx" symbol represents the sum of all the data values, and the "Σx2" symbol represents the sum of all the squared data values.
These statistics can be used to analyze and interpret the data set. For example, the mean can be used to determine the central tendency of the data, and the standard deviation can be used to measure the spread of the data.
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In fluid mechanics, the steady two-dimensional flow of a fluid can be described in terms of a function y(x, y) called the stream function. Let u(x, y) and v(x, y) denote the velocity components of the fluid in each of the coordinate directions at the point (x, y). They are related to the stream function (x, y) by მს მს U = and V = ду Әх '
(a) For the stream function y(x, y) = ln √√(x − a)² + (y − b)², find the velocity components u(x, y) and v(x, y).
(b) Consider a fluid flow in a domain D (a subset of R2) which is described by a stream function (x, y). The first and second derivatives of are continuous at all points in D. Show that this flow satisfies the continuity equation ди Əv + = = 0. əx dy
(a) To find the velocity components u(x, y) and v(x, y) from the given stream function y(x, y) = ln √((x − a)² + (y − b)²), we can use the relationship:
u = ∂ψ/∂y and v = -∂ψ/∂x
where ψ is the stream function.
Taking the partial derivatives of the stream function with respect to y and x:
∂ψ/∂y = (∂/∂y)(ln √((x − a)² + (y − b)²))
= (∂/∂y)(1/2)ln((x − a)² + (y − b)²)
= (1/2)((∂/∂y)ln((x − a)² + (y − b)²))
= (1/2)(2(y − b))/(√((x − a)² + (y − b)²))
= (y − b)/(√((x − a)² + (y − b)²))
∂ψ/∂x = (∂/∂x)(ln √((x − a)² + (y − b)²))
= (∂/∂x)(1/2)ln((x − a)² + (y − b)²)
= (1/2)((∂/∂x)ln((x − a)² + (y − b)²))
= (1/2)(2(x − a))/(√((x − a)² + (y − b)²))
= (x − a)/(√((x − a)² + (y − b)²))
Therefore, the velocity components u(x, y) and v(x, y) are:
u(x, y) = (y − b)/(√((x − a)² + (y − b)²))
v(x, y) = -(x − a)/(√((x − a)² + (y − b)²))
(b) To show that the given flow satisfies the continuity equation ∂u/∂x + ∂v/∂y = 0, we need to calculate the partial derivatives and show that their sum is equal to zero.
∂u/∂x = ∂/∂x((y − b)/(√((x − a)² + (y − b)²)))
= (-(x − a))/((x − a)² + (y − b)²)
∂v/∂y = ∂/∂y(-(x − a)/(√((x − a)² + (y − b)²)))
= (-(y − b))/((x − a)² + (y − b)²)
Summing up the partial derivatives:
∂u/∂x + ∂v/∂y = (-(x − a))/((x − a)² + (y − b)²) + (-(y − b))/((x − a)² + (y − b)²)
= (-(x − a) − (y − b))/((x − a)² + (y − b)²)
= -((x − a) + (y − b))/((x − a)² + (y − b)²)
We observe that the numerator -(x − a) − (y − b) equals zero, so:
∂u/∂x + ∂v/∂y = -((x − a) + (y − b))/((x − a)² + (y − b)²) = 0
Therefore, the given flow satisfies the continuity equation ∂u/∂x + ∂v/∂y = 0.
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Which statement is true regarding the graphed functions?
I need help and can’t find the answers anywhere
Answer:
f(0)=g(0)
Step-by-step explanation:
The problem is asking for where the output (y value) of one function, f(x), matches the output of another function, g(x), otherwise called an intersection. You can see that the two lines intersect at 0 on the x axis in the graph, therefore f(0)=g(0) meaning the outputs of f(x) are the same as g(x) at x value 0.
HELPPPPPPPP PLEASE HELP ME EEEEEE
Answer: The correct answer is b
Step-by-step explanation:
25% off $30 is 22.50 and then when you add 7%ax it turns out to be 24.08
Tamika selects two different numbers at random from the set $\{8,9,10\}$ and adds them. Carlos takes two different numbers at random from the set $\{3,5,6\}$ and multiplies them. What is the probability that Tamika's result is greater than Carlos' result
The probability that Tamika's result is greater than Carlos' result is $\boxed{\frac{4}{9}}$.
To solve this problem, we can start by finding all the possible sums that Tamika can get by adding two different numbers from the set $\{8,9,10\}$:
- $8+9=17$
- $8+10=18$
- $9+10=19$
Similarly, we can find all the possible products that Carlos can get by multiplying two different numbers from the set $\{3,5,6\}$:
- $3\times5=15$
- $3\times6=18$
- $5\times6=30$
Now we need to compare each sum with each product to see which ones satisfy the condition that Tamika's result is greater than Carlos' result. We can organize this information in a table:
| Tamika's sum | Carlos' product | Tamika's sum > Carlos' product? |
| ------------ | -------------- | ----------------------------- |
| 17 | 15 | Yes |
| 17 | 18 | No |
| 17 | 30 | No |
| 18 | 15 | Yes |
| 18 | 18 | No |
| 18 | 30 | No |
| 19 | 15 | Yes |
| 19 | 18 | Yes |
| 19 | 30 | No |
Out of the 9 possible combinations, there are 4 that satisfy the condition, namely when Tamika gets a sum of 17, 18 (twice), or 19 and Carlos gets a product of 15 or 18. Therefore, the probability that Tamika's result is greater than Carlos' result is $\boxed{\frac{4}{9}}$.
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Can someone really help me :(
Area of triangle:
A= 1/2*b*h
= 1/2 *(29)* (19)
= 1/2 *(551)
= 275.5 in^2
Area of rectangle:
A= l * w
= (29) * (10)
= 290 in^2
Total Area:
275.5 + 290 = 565.5 in^2
Hope this helps! Have a great day :)
Answer:
565.5 in
Step-by-step explanation:
The area for a rectangle is A = lw
So A = (29)(10)
A = 290
The area for a triangle is A = 1/2bh
So A = 1/2(29)(19)
A = 1/2(551)
A = 275.5
You combine the two numbers to get a total area of 565.5 in
Please help!! I included a pic of the problem to make it easier.
Find the quotient (z/w)
z = 6(cos(pi/3) + isin(pi/3), w = 3(cos(pi/6) + isin(pi/6)
[A]2(cos(pi/6)+isin(pi/6)
[B]2(cos(pi/90)+isin(pi/90)
[C]18(cos(pi/2)+isin(pi/2)
[D] None of these
Answer: i think it is D
we have:
\(\frac{z}{w}= \frac{6(cos\frac{\pi }{3}+i.sin\frac{\pi }{3} ) }{3(cos\frac{\pi }{6}+i.sin\frac{\pi }{6}) }\\\\\\<=>\frac{z}{w}=\frac{2(\frac{1}{2}+i.\frac{\sqrt{3} }{2}) }{\frac{\sqrt{3} }{2}+i.\frac{1}{2} }\\\\<=>\frac{z}{w}= \frac{2+2\sqrt{3}.i }{\sqrt{3}+i }\)
Step-by-step explanation:
The area of a rectangle is 380 square units. Its length measures 20 units. Find the length of its diagonal. Round to the nearest tenth of a unit.
Answer:
27.6
Step-by-step explanation:
Please find the area...
The equation y=0.17x+4.39 can be used to predict the price of olive oil per quart, where x is the number of years since 2,014. According to the model, what will be the price of olive oil per quart in 2,035? Round answer to hundredths place. If the answer doesn't have a hundredths place then include a zero so that the answer does have an hundredths place. Do no state the units. Be sure to attach your work for credit
The price of olive oil per quart in 2035 will be $350.34
What is purchase price?This formula can be used to determine a product's overall cost. Cost Price + Margin = purchase price.
To predict the price of olive oil per quart in 2035, we need to plug in 2035 for x in the equation:
y = 0.17x + 4.39
y = 0.17(2035) + 4.39
y = 345.95 + 4.39
y = 350.34
So, according to the model, the price of olive oil per quart in 2035 will be $350.34 (rounded to the nearest hundredths place).
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The area of a square Park and a rectangular park is the same. The side length of the square Park is 60m and the length of the rectangular park is 90m. What is the breadth of the rectangular park?
The breadth of the rectangular park is 40 metres.
How to find the breadth of the rectangular park?The area of a square Park and a rectangular park is the same. The side length of the square Park is 60m and the length of the rectangular park is 90m.
Therefore,
area of the square park = l²
area of the square park = 60²
area of the square park = 3600 m²
Hence,
area of the rectangular park = lb
3600 = 90b
divide both sides by 90
b = 3600 / 90
b = 40
Therefore,
breadth of the rectangular park = 40 m
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what is 10639÷500 +22
The given expression is,
10639/500+22
According to
A sample of a radioactive isotope had an initial mass of 610 mg in the 1990 and decays exponentially over time. A measurement in the year 1992 found that the sample's mass had decayed to 340 mg. What would be the expected mass of the sample in the year 1997, to the nearest whole number?
we get that the equation that models the situation is:
\(m=610\cdot k^t^{}\)when t=2. We get that
\(340=610\cdot k^2\rightarrow k=\sqrt[]{\frac{340}{610}}\approx0.75\)so we get that after 7 years ( 1997 )
\(m=610\cdot(\sqrt[]{\frac{340}{610}})^7\approx79\)3,9, 13, 8, 10, 2
what’s the Median?
someone help?
The scale factor of two similar polygons is given. Find the ratio of their perimeters and the ratios of their areas.
1) 3:1
2) 7/4
The ratios of their perimeters and the ratios of their areas are 1) 3:1 and 9:1 and 2) 7:4 and 49:16.
Given the scale factor of two similar polygons, we need to find the ratio of their perimeters and the ratios of their areas,
To find the ratio of the perimeters of two similar polygons, we can simply write the scale factor as it is because the ratio of the perimeter is equal to the ration of the corresponding lengths.
1) So, perimeter = 3:1
The ratio of areas between two similar polygons is equal to the square of the scale factor.
Since the scale factor is 3:1, the ratio of their areas is:
(Ratio of areas) = (Scale factor)² = 9/1 = 9:1
Similarly,
2) Perimeter = 7:4
Area = 49/16
Hence the ratios of their perimeters and the ratios of their areas are 1) 3:1 and 9:1 and 2) 7:4 and 49:16.
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What is the measure of m∠6
Answer:
C. 118.2°
Step-by-step explanation:
180-61.8=118.2
In tryouts for the olympics, a speed skater had times of 44. 64, 43. 45, 42. 79, and 42. 28 seconds. Find the average time. (hint: add the numbers and divide by 4. ).
The average time of the Olympic speedskated is 43.29 units.
What do we mean by average?An average, which is frequently the sum of the numbers divided by the total number of the numbers in the group, is a single number that is selected to describe a group of numbers in simple English.
For example, the average of the numbers 2, 3, 4, 7, and 9 is 5.
The four sorts of averages that we recognize are mean, mode, median, and range.
Although the others are our most popular "measures of central tendency," range is actually a measure of spread or distribution.
So, the average time is calculated as follows:
We have: Time: 44.64,43.45,42.79 and 42.28
The formula for average mean: ∑ₓ/n
Where ∑ₓ is the sum of observations and n is the number of observations.
Now, calculate the average time:
Average = 44.64+43.45+42.79+42.28/4
Average = 173.16/4
Average = 43.29
Therefore, the average time of the Olympic speedskated is 43.29 units.
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what is 0.21212121... as a fraction???
Answer:
7/33
Step-by-step explanation:
x = 0.21212121.... 2 digits in the repeating sequence, x 100 both side
100 x = 21.21212121...
100x - x = 21.21212121... - 0.21212121.... = 21
99x = 21
x = 21/99 = 7/33
If this help, just add a happy face on comment, no star or brainliest please.
What is 25 time 39 divided by 2150?
Answer:
Approx 0.453488372
Step-by-step explanation:
You can get this with a calculator.
25 × 39 = 975
975÷2150≈ 0.453488372
I'm not sure if I'm supposed to round this or not, so I won't. If you need it rounded, comment, and I will!
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Quadrilateral ABCD is similar to quadrilateral A'B'C'D'. Select 2 equations that could be used to solve for missing lengths.
For Quadrilateral ABCD is similar to quadrilateral A'B'C'D' the missing lengths can be solved using option 1 and option 3.
What are transformations?A transformation is a method for changing the two-dimensional position of a polygon or other object on a plane or coordinate system. Two-dimensional figures can move across a plane or coordinate system via mathematical transformations.
The shape in two dimensions before any alteration is known as a preimage or inverse image. The transformed figure is depicted in the picture.
When two figures are similar then the ratio of their segments are equal.
This statement is correctly represented by:
A'B' / AB = A'D' / AD
and
AB / A'B' = AD / A'D'
Hence, for Quadrilateral ABCD is similar to quadrilateral A'B'C'D' the missing lengths can be solved using option 1 and option 3.
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What's the principal sum?
The principal sum refers to the amount payable in one sum in the case of accidental death and, in some cases, accidental dismemberment.
The amount paid in the case of accident or medical insurance in the event that the insured person dies, loses a limb, or loses sight is known to be as principal sum. It means that the principal sum amount is the maximum amount paid to the insured person for all injuries resulting from the accident.
Thus, the principal sum is the amount insured to be paid by the company to the beneficiary in the case of the insured individual's accidental death as well as in the loss of limb or sight.
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Can someone please help?
Answer:
b) X3=0+3-x
it should help you answer a
You buy a chocolate and a vanilla cupcake from a bakery. Each cupcake cost $3.50. What would be your total if you were charged 8% sales tax?
Answer:
43.75.Step-by-step explanation:
We know that:
We used $3.50 on both cupcakes.We are charged with a 8% sales tax.In this case:
We need to find out what 3.50 is 8% of what.Now, we can solve:
3.50 ÷ 0.08 (we do division for this)= 43.75The new cost is $43.75.