Please help me and give an accurate answer

​

Answer:

The graph has 2 solutions

Step-by-step explanation:

they are -5 & 3

All the answers to the given questions are mentioned below -

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of a straight line can be also written as -

Ax + By + C = 0

By = - Ax - C

y = (- A/B)x - (C/A)

Given are six graphs as shown in the image.

The equation of graph [1] -

m = (- 2 - 4)/(2 - 0)

m = -6/2

m = -3

Equation : y = -3x + 4

The equation of graph [2] -

m = (0 + 1)/(2.5 - 0)

m = 1/2.5

m = 10/25

m = 2/5

Equation : y = 2x/5 - 1

The equation of graph [3] -

Equation : y = 4

The equation of graph [4] -

Equation : x = 2

[1] : 2x - y = - 7

y = 2x + 7

[2] : 5x + 3y = 12

3y = -5x + 12

y = -5x/2 + 4

[3] : x - y = 1

y = x - 1

[4] : x - 3y = - 15

3y = x + 15

y = x/3 + 5

[5] : 8x - 10y = 20

8x - 20 = 10y

y = 4x/5 - 2

[6] : 14x + 6y = 36

6y = -14x + 36

y = -7x/3 + 6

Therefore, all the answers to the given questions are mentioned above.

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[REFER TO IMAGE FOR QUESTION]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which

z is the zscore that has a pvalue of \(1 - \frac{\alpha}{2}\).

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

\(n = 1537, \pi = \frac{353}{1537} = 0.2297\)

95% confidence level

So \(\alpha = 0.05\), z is the value of Z that has a pvalue of \(1 - \frac{0.05}{2} = 0.975\), so \(Z = 1.96\).

The lower limit of this interval is:

\(\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087\)

The upper limit of this interval is:

\(\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507\)

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Answer:

I believe the answer is $3,020

The inverse of the conditional "If t<5, then t>6" is "If t≥5, then t≤6"  is not always true but true for some values of t.

An expression, rule, or law that defines a relationship between one variable and another variable.

Let's first consider the original statement: "If t<5, then t>6."

This statement is saying that if t is less than 5, then it must be greater than 6, which is impossible since no number can be less than 5 and greater than 6 at the same time.

So the original statement is always false, no matter what value of t we choose.

So, the inverse of "If t<5, then t>6" is "If t≥5, then t≤6".

This statement is saying that if t is greater than or equal to 5, then it must be less than or equal to 6.

This statement is true for any value of t that is greater than or equal to 5 and less than or equal to 6.

Hence, the inverse of the conditional "If t<5, then t>6" is "If t≥5, then t≤6"  is not always true but true for some values of t.

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Answer:

105 selection s

Step-by-step explanation:

Given:

The coach has to select 2 co-captains from the 15 girls out for soccer

n = 15

r = 2

The number of selections possible is;

N = nCr = n!/r!(n-r)!

Since no other is specified.

Substituting the values of n and r;

N = 15C2 = 15!/2!(15-2)!

N = (15×14)/2

N = 105

Therefore, she have 105 possible selections

Solution

We have the following expression

then the correct answer is:

B

Answer:

7529.536

Step-by-step explanation:

√384=19.6

19.6, is therefore the length of one side

Volume of cube is length³

19.6³=7529.536

Well it's just a try for me

The volume of the box when there is the cube shaped box wrapped and it should measured 384 square inches so it is 7529.536.

Since

A cube-shaped box can be wrapped completely in gift wrap that measures 384 square inches

So here the side should be like

\(= \sqrt{384}\)

= 19.6

Now the volume of the box should be

= \(19.6^3\)

= 7529.536

hence, The volume of the box should be considered as the 7529.536.

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Jacob's body metabolizes caffeine at a rate of 13.5% per hour.

a)Jacob's body will takes 4.77 ~5 hours to metabolize half of the 96 mg of caffeine.

b) If Jacob consumes an energy drink with 212 mg of caffeine in it, Jacob's body will take 4.77948 ~ 5 hours to metabolize half of the 212 mg of caffeine.

c) Jacob consumes a cup of coffee with c mg of caffeine in it. Jacob's body will take 4.77948~ 5 hours to metabolize half of the c mg of caffeine.

The volume will slowly decrease at regular intervals and at a regular rate. This growth reduction is calculated using the exponential decay formula. The general form is y = a(1- r)ᵗ

We have, decay rate r = 13.5 % = 0.135

Initial value , a = 96 mg

plugging the value in formula we get,

y = 96(1 - 0.135)ᵗ --(1)

Now, Half of 96 is 48

so, 48 = 96(0.865)ᵗ --(2)

dividing equation by 96 we get

=> 48/96 = (0.865)ᵗ

taking natrual logarithm both sides,

=> ln(1/2) = ln ((0.865))

=> ln(1/2) = t In (0.865)

=> t = ln(1/2)/In (0.865)

=> t = 4.77948

Since, decay rate is constant so, half never changes for any .

a) 4.779~5 hours, long will it take for Jacob's body to metabolize half of the 96 mg of caffeine.

b) Jacob's body to metabolize half of the 212 mg of caffeine is 4.779~ 5 hours.

c) for Jacob's body to metabolize half of the cmg of caffeine is 4.77948.. So, we have 4.77948 ~ 5 hours is decay constant rate.

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Solution

For this case we can calculate the following ratio:

Kimberly

Jody

therefore the best answer for this case is:

Jody

Each friend had originally 13 action figures before buying 11 more.

Given that there are 5 friends and each of them has x action figures in his or her collection. When they buy 11 more action figures, the total number of action figures they will have is 120.

a) We need to find an equation that models the problem. Let x be the original number of action figures that each friend had.

Therefore, the total number of action figures that each friend will have after purchasing 11 more is x + 11.

The total number of action figures will be 5(x + 11) = 5x + 55.

Now, according to the problem,5x + 55 = 120

This is our equation that models the problem.

b) We have to solve the equation 5x + 55 = 120 to find the original number of action figures, x, that each friend had before buying 11 more action figures.

5x + 55 = 120

5x = 120 - 55 (subtract 55 from both sides)

5x = 65x = 13

Therefore, each friend had originally 13 action figures before buying 11 more.

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Answer:

35.94 lb

Step-by-step explanation:

The net mass flow rate dm/dt = flow rate in - flow rate out

mass flow rate in = concentration in × volume flow rate in = 0.4 lb/gallon of salt × 5 gal/min = 2 lb/min

Let m(t) be the mass present at time, t.

So, the concentration at time, t = m(t)/volume of tank = m(t)/100

mass flow rate out = concentration out × volume flow rate out = m(t)/100 lb/gal× 5 gal/min = m(t)/20 lb/min

So, dm/dt = 2 lb/min - m(t)/20 lb/min

So, dm/dt = 2 - m(t)/20

dm/dt = [40 - m(t)]/20

separating the variables, we have

dm/[40 - m(t)] = dt/20

integrating, we have

∫dm/[40 - m(t)] = ∫dt/20

-1/-1 ×∫dm/[40 - m(t)] = ∫dt/20

1/-1 ×∫-dm/[40 - m(t)] = ∫dt/20

1/-1 ×㏑[40 - m(t)] = t/20 + C

-㏑[40 - m(t)] = t/20 + C

㏑[40 - m(t)] = -t/20 - C

taking exponents of both sides, we have

\(40 - m(t) = e^({\frac{-t}{20} - C}) \\40 - m(t) = e^{\frac{-t}{20}}e^{-C} \\40 - m(t) = Ae^{\frac{-t}{20}} (A = e^{-C})\\m(t) = 40 - Ae^{\frac{-t}{20}}\)

when t = 0 m(0) = 10 lb

So

\(m(t) = 40 - Ae^{\frac{-t}{20}}\\m(0) = 40 - Ae^{\frac{-0}{20}}\\10 = 40 - Ae^{0}\\10 = 40 - A\\A = 40 - 10 \\A = 30\)

So,

\(m(t) = 40 - 30e^{\frac{-t}{20}}\)

when t = 40 minutes, m(40) =

\(m(40) = 40 - 30e^{\frac{-40}{20}}\\m(40) = 40 - 30e^{-2}\\m(40) = 40 - 30 X 0.1353\\m(40) = 40 - 4.06\\m(40) = 35.94\)

So, at the end of 40 minutes, the amount of salt in the tank is 35.94 lb

Answer:

Step-by-step explanation:

208

Hey there! :)

Answer:

3/28.

Step-by-step explanation:

Divide fractions by multiplying by the divisor's reciprocal. Therefore:

2/7  ÷ 8/3 =

2/7 × 3/8 =

2 · 3 / 7 · 8=

6/ 56

Simplify:

6/56 = 3/28. This is your answer in simplest form.

The expression 2/7 divided by 8/3 is equal to 3/28.

We have,

To divide 2/7 by 8/3, multiply 2/7 by the reciprocal of 8/3:

= (2/7) ÷ (8/3)

= (2/7) * (3/8)

Now, simplify the multiplication:

(2/7) * (3/8)

= (2 * 3) / (7 * 8)

Multiplying the numerators (2 * 3) and denominators (7 * 8),

= 6 / 56

Divide by 2 on both the numerator and denominator.

= 2 x 3 / 2 x 28

= 3/28

Therefore,

The expression 2/7 divided by 8/3 is equal to 3/28.

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Answer:

consist of either a single capital letter or a capital letter and a small letter.

Step-by-step explanation:

A chemical reaction can be defined as a reaction in which two or more atoms of a chemical element react to form a chemical compound.

In Chemistry, a chemical element can be defined as any pure substance that is typically made up of only atoms and cannot be broken down into simpler substances through chemical processes. Thus, the atomic number (the number of protons in the nuclei of an atom) of a particular chemical element distinguishes from other chemical elements.

Generally, all chemical elements are denoted or represented by a symbol, which may either be single capital letter or a capital letter and a small letter.

This ultimately implies that, the symbols for elements with accepted names consist of either a single capital letter or a capital letter and a small letter. For example, the symbol for sodium is Na, copper is Cu, carbon is C, oxygen is O, iron is Fe, nitrogen is N, magnesium is Mg, potassium is K, argon is Ag, hydrogen is H, helium is He, phosphorus is P, etc.

Answer:

1 83/200

Step-by-step explanation:

You need to make the 2/3 a decimal which is 0.66 repeating. Then you do 5.66 divided by 4 which equals 1.415 then you need to simplify.

Hope this helps.

Answer:

The answer is The function h because the graphs of f and h are symmetrical about the line y = x.

Step-by-step explanation:

A function and its inverse function become symmetrical across the line y = x.  

Answer : 12z - 32

Explaination:

Uhhh yeah math?

Answer:

-4-3-2-1

Step-by-step explanation:

the answer is -4-3-2-1

Answer:

Area of the rectangles on either side of the wedge = 2×radius×height=2×18=36sqcm.

Step-by-step explanation:

Area of the sector (top and bottom) = 2×

360

45

​

×π×6

2

=9πsqcm

Curved area of the cylinder =  

8

2π×6×3

​

=

2

9

​

πsqcm.

Total area of each wedge =  

2

9

​

π+9π+36=36+

2

27

​

π=

2

9

​

(3π+8)sqcm

The graph of the given ordered pair is plotted and attached below.

Ordered pair:

Ordered pair refers the composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses.

Given,

Here we have the following ordered pair.

(0, 0) (10, 125) (20, 250) (30, 375) (40, 500)

Now, we have to plot the graph for this ordered pair.

In the given question, we have to perform the following steps.

After all these steps we get the graph like the following.

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The Profit of selling 850 gallons of gasoline is S/. 221.

The profit of selling 850 gallons of gasoline,  the difference between the selling price and the cost price per gallon, and then multiply that by the number of gallons sold.

Given:

Cost price per gallon = S/. 12.89

Selling price per gallon = S/. 13.15

Number of gallons sold = 850

Profit per gallon = Selling price per gallon - Cost price per gallon

Profit per gallon = S/. 13.15 - S/. 12.89

Profit per gallon = S/. 0.26

Total profit = Profit per gallon * Number of gallons sold

Total profit = S/. 0.26 * 850

Total profit = S/. 221

Therefore, the profit of selling 850 gallons of gasoline is S/. 221.

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They can buy 120 vans, 60 small trucks, and 80 large trucks.

The truck company plans to spend 10 million on 260 vehicles. Each commercial van cost 25,000 dollars. Each small truck 50,000 dollars and each large truck 50,000 dollars. They needed twice as many van as small truck

Therefore,

let

s = number of small truck

number of van = v

let

l = number of large truck

v + s + l = 260

25,000(v) + 50,000(s) + 50,000(l) = 10,000, 000

v + 2s + 2l = 400

Hence,

v = 2s

So,

2s + 2s + 2l = 400

4s + 2l = 400

2s + s + l = 260

3s + l = 260

2s + l = 200

s = 60

l = 200 - 2(60)

l = 200 - 120

l = 80

v = 2(600 = 120

Therefore, they can buy the following:

number of small truck = 60

number of van = 120

number of large truck = 80

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Answer:

its c

Step-by-step explanation:

The graph which best represents a function with a domain of all real numbers less than or equal to 6 is; Choice A as represented in the attached image.

According to the task content;

On this note, it follows that the graph which is characterized by the given domain is as attached.

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Yes, there is a difference in the shapes of the displacement-time graphs for uniform acceleration towards the positive direction, uniform acceleration towards the negative direction, uniform deceleration towards the positive direction, and uniform deceleration towards the negative direction.

Uniform acceleration towards the positive direction:

In this case, the object's velocity increases in the positive direction over time. The displacement-time graph will have a concave-upward shape, forming a curve that starts with a small slope and gradually becomes steeper as time progresses.

Uniform acceleration towards the negative direction:

Here, the object's velocity increases in the negative direction, meaning it accelerates in the opposite direction to its positive direction.

The displacement-time graph will have a concave-downward shape, forming a curve that starts with a steep slope and gradually becomes less steep as time progresses.

Uniform deceleration towards the positive direction:

In this scenario, the object's velocity decreases in the positive direction, but it still moves towards the positive direction.

The displacement-time graph will show a curve with a decreasing slope, forming a concave-downward shape, indicating that the object is slowing down.

Uniform deceleration towards the negative direction:

Here, the object's velocity decreases in the negative direction, opposing its initial direction.

The displacement-time graph will have a curve with a decreasing slope, forming a concave-upward shape, indicating that the object is slowing down but still moving in the negative direction.

In summary, the shapes of the displacement-time graphs differ based on the direction and type of acceleration (positive or negative) and whether the object is undergoing uniform acceleration or uniform deceleration. These differences can be observed through the concavity and slope of the graphs.

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