please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

The probability that each box contains 2 tiles is 1/9.

To find the probability that each box contains 2 tiles when tiles numbered 1-6 are randomly placed into three different boxes, we use a counting approach.

Since there are 6 tiles, the total number of possible outcomes is 3⁶ = 729.

The number of ways to choose 2 tiles from 6 is denoted as C(6,2), which can be calculated as:

C(6,2) = 6! / (2! * (6-2)!) = 6! / (2! * 4!) = (6 * 5) / (2 * 1)

C(6,2) = 15

Similarly, the number of ways to choose 2 tiles from 4 is C(4,2), which can be calculated as:

C(4,2) = 4! / (2! * (4-2)!) = 4! / (2! * 2!) = (4 * 3) / (2 * 1) = 6

The number of favorable outcomes is C(6,2) * C(4,2) = 15 * 6

C(6,2) * C(4,2) = 90.

Probability = Number of favorable outcomes / Total number of possible outcomes

Probability = 90 / 729

Probability = 1/9

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Answer:

The correct option is (b) 0.333.

Step-by-step explanation:

The data provided is as follows:

                        Hepatitis C           No hepatitis C           Total

No Tattoos              5                             50                        55

 1 Tattoo                 10                           210                      220

> 1 Tattoo                15                           150                       165

   Total                   30                           410                       440

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

\(P(E)=\frac{n(E)}{N}\)

The condition probability of an event A provided that another event X has already occurred is:

\(P(A|X)=\frac{P(A\cap X)}{P(X)}\)

The number of people who has hepatitis C is:

n (Hepatitis C) = 30

The number of people who has hepatitis C and one tattoo is:

n (Hepatitis C and 1 Tattoo) = 10

Compute the probability that he or she has hepatitis C, given that he or she has one tattoo as follows:

\(P(\text{Hepatitis C} |\text{1 Tattoo})=\frac{n(\text{Hepatitis C and 1 Tattoo})}{n(\text{1 Tattoo})}\)

                                       \(=\frac{10}{30}\\\\=\frac{1}{3}\\\\=0.333\)

Thus, the correct option is (b).

The probability that he or she has hepatitis C, given that he or she has one tattoo will be 0.333. Then the correct option is B.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

The table is given below.

                       Hepatitis C           No hepatitis C           Total

No Tattoos              5                             50                        55

1 Tattoo                 10                           210                      220

> 1 Tattoo                15                           150                       165

  Total                   30                           410                       440

The number of people who has hepatitis C is 30. And the number of people who has hepatitis C and one tattoo is 10.

The probability that he or she has hepatitis C, given that he or she has one tattoo will be

P = 10/30

P = 1/3

P = 0.333

The probability that he or she has hepatitis C, given that he or she has one tattoo will be 0.333. Then the correct option is B.

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The difference quotient for the function is 8.

The function is given by:

f ( x ) = 8 x − 9, where h ≠ 0

To find f(a), substitute a for x in the function. So we have:

f ( a ) = 8 a − 9

To find f(a + h), substitute a + h for x in the function. So we have:

f ( a + h ) = 8 ( a + h ) − 9

The difference quotient can be found using the formula:

(f(a + h) - f(a))/h

Substituting the values found above, we have:

(8 ( a + h ) − 9 - (8 a − 9))/h

Expanding the brackets and simplifying, we have:

((8a + 8h) - 9 - 8a + 9)/h

= 8h/h

= 8

Therefore, the difference quotient for the function is 8.

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Answer:

The answer is b

Step-by-step explanation:

The distance traveled by the passenger train and the cattle train is equal to the total distance between them, which is 960 miles. Let x be the time (in hours) traveled by the passenger train and cattle train. Then, the equation that represents this situation is:

55x + 65x = 960

Simplifying the left-hand side of the equation, we get:

120x = 960

Dividing both sides by 120, we get:

x = 8

Therefore, the correct equation is:

B - 65x - 55x = 960

Answer:

0.865

Step-by-step explanation:

To solve for the probability we would be using the formula:

F(x) = 1 - e^−λx

Therefore, P(x > 2000) = F(x) = 1 - e^−λx

Mean = 1000 hours

λ = 1/mean = 1/1000 hours

x= 2000 hours

F(x) = 1 - e^−(1/1000)2000

F(x) = 1 - e^−2

= 0.8646647168

Therefore, the probability the the circuit will last at least 2000 hours = 0.865

Answer:

106142400

Step-by-step explanation:

2*5*5*6*8*9*13*14*15*18=1061424000

1061424000/10=106142400

Answer:  So the ratio is gonna be 5:3...

Step-by-step explanation:

Answer:

answer is in the picture.

Answer:

1/2

Step-by-step explanation:

The value of p-hat (the sample proportion) is 0.24, or 24% if total number of skittles in a sample is 300 out of which 72 skittles are purple.

The sample proportion, denoted by p-hat, is the proportion of purple skittles in the sample. We can calculate p-hat by dividing the number of purple skittles by the total number of skittles in the sample

p-hat = number of purple skittles / total number of skittles in sample

In this case, we have

Number of purple skittles = 72

Total number of skittles in sample = 300

Therefore,

p-hat = 72/300 = 0.24

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Answer:

10

Step-by-step explanation: 17+10=27, 17-10=7

Therefore, the linearization of f(x) = cos(x) at a = π/2 is L(x) = π/2 - x.

The linearization of a function f(x) at a point a is given by:

L(x) = f(a) + f'(a)(x - a)

where f'(a) denotes the derivative of f(x) evaluated at x = a.

In this case, we have:

f(x) = cos(x)

a = π/2

First, let's find f'(x):

f'(x) = -sin(x)

Then, we can evaluate f'(a):

f'(π/2) = -sin(π/2) = -1

Next, we can plug in the given values into the formula for linearization:

L(x) = f(a) + f'(a)(x - a)

L(x) = cos(π/2) + (-1)(x - π/2)

L(x) = 0 - x + π/2

L(x) = π/2 - x

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The critical points we obtain are (±√2, ±√2/2) and we need to check which of these are extrema by plugging them back into f(x, y) = x - y. We find that (±√2, ±√2/2) are saddle points, since f changes sign as we move in different directions.

In the first problem, we are asked to find the extrema of the function f(x-y-z) = x-y+z subject to the constraint x^2 + y^2 + z^2.
To find the extrema, we need to use the method of Lagrange multipliers. We introduce a new variable λ and set up the Lagrangian function L(x,y,z,λ) = f(x,y,z) + λ(g(x,y,z) - c), where g(x,y,z) is the constraint function (x^2 + y^2 + z^2) and c is a constant chosen so that g(x,y,z) - c = 0.
Then we find the partial derivatives of L with respect to x, y, z, and λ, and set them equal to zero to get a system of equations. Solving this system gives us the critical points, which we then plug back into f to determine whether they are maxima, minima, or saddle points.
In this case, we have:
L(x,y,z,λ) = x-y+z + λ(x^2 + y^2 + z^2 - c)
∂L/∂x = 1 + 2λx = 0
∂L/∂y = -1 + 2λy = 0
∂L/∂z = 1 + 2λz = 0
∂L/∂λ = x^2 + y^2 + z^2 - c = 0
Solving for x, y, z, and λ, we get:
x = -1/2λ
y = 1/2λ
z = -1/2λ
x^2 + y^2 + z^2 = c/λ
Substituting these back into f(x-y-z) = x-y+z, we get:
f(x,y,z) = x-y+z = (-1/2λ) - (1/2λ) - (1/2λ) = -3/2λ

To find the extrema, we need to check the sign of λ. If λ > 0, we have a minimum at (-1/2λ, 1/2λ, -1/2λ). If λ < 0, we have a maximum at the same point. If λ = 0, the Lagrangian does not give us any information, and we need to check the boundary of the constraint set.
The constraint x^2 + y^2 + z^2 = c is the equation of a sphere with radius √c centred at the origin. The function f(x-y-z) = x-y+z defines a plane that intersects the sphere in a circle. To find the extrema on this circle, we can use the method of Lagrange multipliers again, setting up the Lagrangian L(x,y,λ) = x-y+z + λ(x^2 + y^2 + z^2 - c) and following the same steps as before.
In the second problem, we are asked to find the extrema of the function f(x, y) = x - y subject to the constraint x^2 - y^2 = 2.  Again, we use the method of Lagrange multipliers, setting up the Lagrangian L(x,y,λ) = x - y + λ(x^2 - y^2 - 2) and solving the system of equations ∂L/∂x = ∂L/∂y = ∂L/∂λ = 0.

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To answer this question, re-arrange the terms to be on one side of the equation.

Thus, the value of x is 1.

Answer:

x=1

Step-by-step explanation:

Answer:

Undefined.

Step-by-step explanation:

Slope is the Rise/Run of a straight line.  Run is the change in the value of y for a change in x.  The graph shows all values are possible for y even when there is zero change in x.  All Values/0 = Undefined.

The explicit formula of the sequence is a(n) = 7 - 3n

From the question, we have the following parameters that can be used in our computation:

4, 1, −2, ....

In the above sequence, we can see that 3 is subtracted from the previous term to get the current term

This means that

first term, 4 = 8

common difference, d = -3

The nth term is then represented as

a(n) = a + (n - 1)d

Substitute the known values in the above equation, so, we have the following representation

a(n) = 4 + (n - 1) * -3

Evaluate

a(n) = 4 + 3 - 3n

So, we have

a(n) = 7 - 3n

Hence, the explicit is a(n) = 7 - 3n

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The production phase could have a larger contribution to acidification potential than the use and end-of-life phases for both conventional vehicles and EVs. The distance traveled in one year of normal commuting could be more suitable in this case.

A. The functional unit, which is defined as the quantified performance of a product system or service that will be used as a reference for conducting the life cycle assessment, is important for evaluating the impacts of products or systems on the environment.

The following are the different functional units that are acceptable or not acceptable to assess the environmental impacts of the product or system.

The first functional unit, one vehicle, is not appropriate as it doesn't represent the amount of driving a person could expect to do if they bought a new car and drove it until the end of its life.

The second functional unit, distance traveled in one full gas tank or battery charge, would not be appropriate for our purpose as it is not clear what type of vehicle it will be used for.

The third functional unit, one year of normal commuting, would not be appropriate as it does not consider all the environmental impacts over the lifetime of the vehicle.

The fourth functional unit, 1 kg of vehicle, would not be appropriate as it is too small of a functional unit to evaluate the environmental impacts of the vehicle.

B. If we also wanted to consider riding the public bus as a personal transportation option, 200,000 miles driven would not be an appropriate choice of functional unit. This is because buses are used for transportation purposes, and they will have different environmental impacts than cars.

Therefore, the distance traveled in one year of normal commuting could be more suitable in this case.

C. One other impact category we could consider is the acidification potential. The production phase could have a larger contribution to acidification potential than the use and end-of-life phases for both conventional vehicles and EVs.

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Answer:

x= -15

Step-by-step explanation:

................

To show that `(n + 3)7 ∈ Θ(n7)`, we need to prove that `(n + 3)7 = Θ(n7)`.This can be done by showing that `(n + 3)7 = O(n7)` and `(n + 3)7 = Ω(n7)` .Now, let's prove the two parts separately:

Proof for `(n + 3)7 = O(n7)`.

We want to prove that there exists a positive constant c and a non-negative constant k such that `(n + 3)7 ≤ cn7` for all `n ≥ k`.Using the Binomial theorem, we can expand `(n + 3)7` as:```
(n + 3)7
= n7 + 7n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6 + 37
≤ n7 + 21n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6 + n7
≤ 2n7 + 21n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6
≤ 2n7 + 84n6 + 441n5 + 2205n4 + 10395n3 + 45045n2 + 153609n + 729
```Thus, we can take `c = 153610` and `k = 1` to satisfy the definition of big-Oh notation. Hence, `(n + 3)7 = O(n7)`.Proof for `(n + 3)7 = Ω(n7)`We want to prove that there exists a positive constant c and a non-negative constant k such that `(n + 3)7 ≥ cn7` for all `n ≥ k`.Using the Binomial theorem, we can expand `(n + 3)7` as:```
(n + 3)7
= n7 + 7n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6 + 37
≥ n7
```Thus, we can take `c = 1` and `k = 1` to satisfy the definition of big-Omega notation. Hence, `(n + 3)7 = Ω(n7)`.

As we have proved that `(n + 3)7 = O(n7)` and `(n + 3)7 = Ω(n7)`, therefore `(n + 3)7 = Θ(n7)`.Thus, we have shown that `(n + 3)7 ∈ Θ(n7)`.From the proof, we can see that we used the Binomial theorem to expand `(n + 3)7` and used algebraic manipulation to bound it from above and below with suitable constants. This technique can be used to prove the time complexity of various algorithms, where we have to find the tightest possible upper and lower bounds on the number of operations performed by the algorithm.

Hence, we have shown that `(n + 3)7 ∈ Θ(n7)` for non-negative integer n.

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Answer:

Side length of each booth is 8.35 ft approximately.

Step-by-step explanation:

There are 11 companies set up equal sized square booths in a row along one wall of a convention center.

Now, refer the diagram to answer the problem.

It is given area is 1200.

So, length x width =1200

(11x+24)(x+2)=1200

Multiply using FOIL method.

\(11x^{2}\)+22x+24x+48=1200

\(11x^{2}\)+46x+48-1200=0

\(11x^{2}\)+46x-1152=0

Solve using quadratic formula

x=\(\frac{-46+/- \sqrt{46^{2}-4(11)(-1152 } }{2(11)}\)

x=\(\frac{-46+/-\sqrt{2116+50688} }{22}\)

x=\(\frac{-46+/-\sqrt{52804} }{22}\)

Simplify it

\(x=\frac{-49+/- 229.79}{22}\)

Simplify to get two values for x.

x=8.35; x=-12.67

Here negative does not work.

Side length of each booth is 8.35 ft.

The equation of a circle having endpoints of diameter as (4,9) and (4,-3) is (x - 4)² + (y - 3)² = 36.

The "center" of circle is called as midpoint of diameter.

The "x-coordinate" of "mid-point" is = (4+4)/2 = 4, and

The "y-coordinate" of "mid-point" is = (9+(-3))/2 = 3.

So, center of circle is (4,3),

The radius of circle is half the length of the diameter, which is distance between two endpoints of diameter. We find distance using distance formula:

⇒ distance = √((x₂ - x₁)² + (y₂ - y₁)²), where (x₁,y₁) and (x₂,y₂) are "end-points" of diameter.

⇒ distance = √((4 - 4)² + (9 - (-3))²)

⇒ √(144) = 12.

So, radius is 6.

The equation of circle with center (h,k) and radius "r" is : ⇒ (x - h)² + (y - k)² = r²,

Substituting the values

We get,

⇒ (x - 4)² + (y - 3)² = 6²,

⇒ (x - 4)² + (y - 3)² = 36,

Therefore, the equation of the circle is (x - 4)² + (y - 3)² = 36.

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Answer:

120

Step-by-step explanation:

Let's assume that "5 (!)" is 5! (5 factorial)

5*4*3*2*1 = 120

A multiplier of 1.2 means the value is multiplied or increased by a factor of 1.2.

A multiplier is a term used to represent a factor by which a value is multiplied or increased. It is a numeric value that indicates the extent of the increase or expansion of a given quantity. Multiplication by a multiplier results in scaling or changing the magnitude of the original value.

A multiplier of 1.2 indicates that a value will be increased by 20% or multiplied by a factor of 1.2. This means that when the multiplier is applied to the original value, the resulting value will be 1.2 times the original.

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Answer:

I think it's the first one but i'm not 100% sure

Step-by-step explanation:

a).  2^38 bytes of memory

b). 12 bits

c). The maximum number of entries in the single-level page table would be 2^38.

d). The size would be 2^38 * 4KB, which equals 2^20 pages.

e). The maximum number of entries it can have depends on the remaining bits of the logical address.

f). The amount of bits required to denote an index into the inner page table is obtained by subtracting the offset and outer page index bits from the logical address.

a. To address a physical memory size of 128GB (2^37 bytes), a 64-bit architecture would require 38 bits for the logical address, allowing access to a maximum of 2^38 bytes of memory.

b. Given that the page size is 4KB (2^12 bytes), 12 bits would be needed to specify the displacement into a page. This means that the lower 12 bits of the logical address would be used for page offset or displacement.

c. With a single-level page table, the maximum number of entries would be equal to the number of possible logical addresses. In this case, since the logical address requires 38 bits, the maximum number of entries in the single-level page table would be 2^38.

d. The size of the single-level page table is determined by the number of entries it contains. Since each entry maps to a page of size 4KB, the size of the single-level page table can be calculated by multiplying the number of entries by the size of each entry. In this case, the size would be 2^38 * 4KB, which equals 2^20 pages.

e. For a two-level page table, the size of the outer page table is determined by the number of entries it can contain. Since the outer page table uses 4KB pages, the maximum number of entries it can have depends on the remaining bits of the logical address. The number of bits used for the index into the outer page table is determined by subtracting the bits used for the inner page index and the offset from the total number of bits in the logical address.

f. The number of bits used to specify an index into the inner page table can be determined by subtracting the bits used for the offset and the bits used for the outer page index from the total number of bits in the logical address. The remaining bits are then used to specify the index into the inner page table.

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Answer:

$2.40 divided by 6 cans, is equal to $0.40 per can. so 40 cents or 0.40 Dollars

Step-by-step explanation:

This is a simple division word problem.  You have a 6 can pack of sodas for $2.40, divide 2.4 by 6 and you get 0.40.

Based on the explanation below, the conclusion that Elan is tired because Elan stayed up late is invalid.

In the question, it is stated that if Elan stays up late, he will be tired the next day.

However, staying up late is not the only thing that could make Elan get tired.

This implies that there are so many other things than can make Elan get tired such as working for long hours.

It is possible that Elan was tired because Elans worked long hours.

By implication, the conclusion is invalid.

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Power series solutions have a minimum radius of convergence of R of 10.0498 around the normal point x = 0 and 10 units around the normal point x=1.

A differential equation in mathematics is an equation that connects the derivatives of one or more unknown functions.

Applications often involve functions that reflect physical quantities, derivatives that depict the rates at which those values change, and a differential equation that establishes a connection between the three.

The given equation: \(\left(x^2-2 x+26\right) y^{\prime \prime}+x y^{\prime}-4 y=0\)

It is necessary to determine the power series solutions' minimal radius of convergence R around the typical points x = 0 and x = 1.

The separation between the ordinary point and the differential equation's singularity is now the minimal radius of convergence.

The polynomial's root, which is connected to the second derivative, is the singularity point.

The singularity points will be determined as follows:

\(\begin{aligned}& x^2-2 x+26=0 \\& x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\& x=\frac{2 \pm \sqrt{(-2)^2-4 \times 1 \times 26}}{2} \\& x=1 \pm \sqrt{-100} \\& x=1 \pm 10 i\end{aligned}\)

In this case, x1 = 1+10i and x2 = 1-10i are the singularity sites.

The ordinary points at this time are z1 = 0+01 and z2 = 1+0i.

One can compute the minimum radius of convergence using the formula:

\(\begin{aligned}& r_1=\left|z_1-x_1\right| \\& =|0+0 i-1-10 i| \\& =\sqrt{101} \\& =10.0498 \\& r_2=\left|z_2-x_1\right| \\& =\sqrt{100} \\& =10\end{aligned}\)

Therefore, power series solutions have a minimum radius of convergence of R of 10.0498 around the normal point x = 0 and 10 units around the normal point x = 1.

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Answer:

b ata.....

Step-by-step explanation:

no explanation

Answer:

radius=28cm/2

=14 cm

circumference of the wheel=2πr

=2×22/7×14

=88 cm

answer is option D