Please help! It’s asap :(

Answer:

C

Step-by-step explanation:

Uhm I tried my best im so sorry if it's wrong

it is B yep he was right have a nice day

La probabilidad de obtener en el dado blanco un número menor que tres y en el rojo un valor mayor a tres es:

p = 1/6.

Tiramos dos dados, uno blanco y uno rojo, y queremos obtener la probabilidad de obtener un número menor a 3 en el dado blanco y un numero mayor a 3 en el dado rojo.

Primero, el dado blanco tiene los posibles valores {1, 2, 3, 4, 5, 6}, los valores menores que 3 son {1, 2}

Entonces 2 de 6 resultados son menores que 3, es decir, la probabilidad es:

P = 2/6 = 1/3.

Para el dado rojo los posibles valores son los mismos, y los valores mayores que 3 son {4, 5, 6}, entonces 3 de 6 resultados son mayores que 3, es decir, la probabilidad es:

Q = 3/6 = 1/2.

La probabilidad conjunta es el producto de la dos probabilidades individuales:

p = P*Q = (1/3)*(1/2) = 1/6.

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4/5x = -1/4

x = -1/4 × 5/4

x = -5/16

x = -0.3125

_____

RainbowSalt2222 ☔

A new sample size of at least 537 fish to estimate the true mean length with a margin of error of 0.5 centimeters and 95% confidence.

To determine the size of a new sample so that the true mean length is estimated with a margin of error of 0.5 centimeters with 95% confidence, we need to find the standard error of the mean and use it in the formula for the margin of error.

The formula for the margin of error is: ME = z * (σ/√n)

where z is the z-score corresponding to the desired confidence level, σ is the standard deviation of the population, and n is the sample size.

We can estimate the standard deviation of the population using the sample variance, which is given as 34.9.

The standard deviation is the square root of the variance, so σ = √34.9

= 5.91.

To find the standard error of the mean, we divide the standard deviation by the square root of the sample size:

SEM = σ/√n

= 5.91/√n We want the margin of error to be 0.5 centimeters, so we can set up the equation:

0.5 = z * (5.91/√n)

To solve for n, we need to know the value of z for a 95% confidence level.

This corresponds to a z-score of 1.96. Substituting this into the equation gives: 0.5 = 1.96 * (5.91/√n)

Simplifying and solving for n gives: √n = 1.96 * (5.91/0.5) √n

n =(23.18)

n = 537

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Answer:adult=379, student=725

Step-by-step explanation:

Given

Total tickets sold for $2620

total  no of tickets 1104

The cost of an adult ticket is $5

The cost of a student ticket is $1

Suppose there are x adults and y students

So, we can write

\(\Rightarrow x+y=1104\quad \ldots(i)\\\Rightarrow 5x+y=2620\quad \ldots(ii)\)

Put the value of y from (i) into (ii)

\(\Rightarrow 5x+1104-x=2620\\\Rightarrow 4x=1516\\\Rightarrow x=379\)

Similarly, \(y=1104-379=725\)

Answer:

If the Garcia family has a monthly budget of $2000 and they spend a portion of that budget on groceries, we can use percentages to determine the amount spent on groceries.

In this case, we know that the family spends 20% of their monthly budget on groceries. To calculate this, we take 20% (or 0.2 as a decimal) of $2000, which gives us $400.

Therefore, the Garcia family spends $400 of their $2000 monthly budget on groceries. This leaves them with $1600 for their utility bills, such as electricity, gas, water, and other household expenses.

By using percentages to calculate their spending, the Garcia family can better track their expenses and make informed decisions about their budget. It is important to allocate funds appropriately to different expenses to ensure that all necessary expenses are covered while also allowing for some flexibility and savings.

The critical route contains four activities with standard deviations of 6, 4, 2, and 5 days. The critical path's standard deviation is 17 days.

It follows that the critical path's standard deviation is equal to the total of the standard deviations of the four activities that make up the critical path.

6 + 4 + 2 + 5

=17

indicating that the critical route deviates by 17 days from the mean days of critical path activities.

The term standard deviation refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed.

In contrast, a high or low standard deviation indicates that the data points are, respectively, above or below the mean.

A standard deviation that is close to zero implies that the data points are close to the mean.

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The volume of oil exiting the pipe is approximately 100 cu in/hr, 2,400 cu in/day, and 1.39 cu ft/day when converting cu in/day to cubic feet per day.



To calculate the volume of oil exiting the pipe every hour, you would need to know the flow rate of the oil in cubic inches per hour. Let's assume the flow rate is 100 cubic inches per hour.To find the volume of oil exiting the pipe every day, you would multiply the flow rate by the number of hours in a day. There are 24 hours in a day, so the volume of oil exiting the pipe every day would be 100 cubic inches per hour multiplied by 24 hours, which equals 2,400 cubic inches per day.

To convert the volume from cubic inches per day to cubic feet per day, you would need to divide the volume in cubic inches by the number of cubic inches in a cubic foot. There are 1,728 cubic inches in a cubic foot. So, dividing 2,400 cubic inches per day by 1,728 cubic inches per cubic foot, we get approximately 1.39 cubic feet per day.

Therefore, the volume of oil exiting the pipe is approximately 100 cubic inches per hour, 2,400 cubic inches per day, and 1.39 cubic feet per day.

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I know I'm not getting brainliest but i need points and I'm doing a challenge so

19251

Answer:

The system of equations 10d+25q=375 and q = 3d-2 can be used to find the numbers of dimes and quarters that Joann has.

Step-by-step explanation:

Given that:

Total value of dimes and quarters = $3.75 = 3.75*100 = 375 cents

One quarter = 25 cents

One dime = 10 cents

Let,

d be the number of dimes

q be the number of quarters

According to given statement,

10d+25q=375

q = 3d-2

Hence,

The system of equations 10d+25q=375 and q = 3d-2 can be used to find the numbers of dimes and quarters that Joann has.

Step-by-step explanation:

|14- c| = 15

=> 14 - c = 15 or 14 - c = -15

=> c = -1 or c = 29.

The proportion of the class with a midterm grade less than 75 is approximately 0.3085, or 30.85%. This means that 30.85% of the class is expected to have a midterm grade lower than 75.

We can use the cumulative distribution function (CDF) of the normal distribution to find the proportion of the class with a midterm grade less than 75.

The CDF of a normal distribution with mean μ and standard deviation σ evaluated at a point x is given by the formula:

CDF(x) = 0.5 * [1 + erf((x - μ) / (σ * √2))]

where erf is the error function.

For this problem, μ = 78 and σ = 6, and x = 75, so the CDF can be calculated as follows:

CDF(75) = 0.5 * [1 + erf((75 - 78) / (6 * √2))]

= 0.5 * [1 + erf(-0.3536)]

The value of erf(-0.3536) can be looked up in a table or calculated using a software package. The result is approximately -0.383.

CDF(75) = 0.5 * [1 + -0.383] = 0.5 * [0.617] = 0.3085

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The estimation of 0.000007328 is \(7\times10^{-6\).

Estimation is he ability to guess the amount of anything without actual measurement.

The number (n) is given as:

\(\text{n}=0.000007328\)

Multiply by 1

\(\text{n}=0.000007328\times1\)

The number is to be rounded to the nearest millionth.

So, we substitute \(\frac{1000000}{1000000}\) for 1

\(\text{n}=0.000007328\times1\)

\(\text{n}=0.000007328\times\dfrac{1000000}{1000000}\)

This becomes

\(\text{n}=7.328\times\dfrac{1}{1000000}\)

Express the fraction as a power of 10

\(\text{n}=7.328\times10^{-6\)

Approximate to a single digit

\(\rightarrow\bold{n=7\times10^{-6}}\)

Therefore, the estimation of 0.000007328 is \(7\times10^{-6}\).

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Pythagorean Theorm Unit? I got you!

It would be C, about 63.07

Now let's process the ASCII text file using the IMPORT and EXPORT procedures.

Must specify ASCII text file delimiter in DBMS options.

PROC IMPORT DATAFILE ="c:\sas\ego.csv" OUT=jeeshim.egov DBMS=CSV REPLACE;

GETNAMES=YES;

DATAROW = 2;

RUN

DATAFILE lets you import an external file.

Designates a SAS data file.

The DBMS specifies the type of external file. For example, "DBMS=DLM", "DBMS=CSV", and "DBMS=TAB".

REPLACE overwrites the existing file, if any.

GETNAMES reads the variable names from the first line of the data file.

The DATAROW option tells the row from which SAS reads the observations.

GETNAMES and DATAROW require a semicolon at the end.

This example exports the data set to an ASCII file by the specified range. DATA and OUTFILE respectively define the set of data to be output and the external file to which the data is output.

PROC export

DATA = jeeshim.egov

OUTFILE="c:\sas\ego.txt"

DBMS = DLM REPLACE;

RUN;

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The equation describes a line that contains the point (4, -3) is y = ( -1/25 )x - 71/25 .

Given :

The point (4, -3) and is perpendicular to the line represented by the equation y = 25x +3 .

Here slope m = 25

Perpendicular slope = -1 / m

= -1 / 25

The line equation is y = mx + c

Substitute m and ( 4 , -3 ) we get

-3 = -1/25 * 4 + c

-75 = -4 + 25c

-71 = 25c

c = -71/25

y = mx + c

y = ( -1/25 )x - 71/25

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Answer: 20

Step-by-step explanation:

Answer:

1 is the answer you needed

After the stock's value increases by 4.5% and then falls by the same percentage, the new value would be approximately $997.975.

Let's calculate the new value of the stock after the increase and decrease.

Starting with $1,000, a 4.5% increase in value would be calculated as (4.5/100) * 1000 = $45. This brings the value up to $1,045.

Next, a 4.5% decrease in value would be calculated as (4.5/100) * 1045 = $47.025. This amount is subtracted from the increased value of $1,045.

Subtracting $47.025 from $1,045 gives us $997.975, which is slightly less than $1,000.

Therefore, after the stock's value increases by 4.5% and then falls by the same percentage, the new value would be approximately $997.975. It's important to note that this calculation assumes a simple percentage increase and decrease without considering other factors that can affect stock market fluctuations.

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a)we have shown that if f(p1) = f(p2), then p1 = p2. Hence, the linear transformation f:P2 → R* is injective.

b) we need to find a polynomial p in P2 such that p(0.5) = y. Let p(x) = ax^2 + bx + c be such a polynomial. Then we have:

p(0.5) = a(0.5)^2 + b(0.5) + c = 0.25a + 0.5b + c

a) To determine if the linear transformation f:P2 → R* is injective, we need to check if different polynomials in P2 are mapped to different values in R*. In other words, we need to check if f(p1) = f(p2) implies p1 = p2 for any polynomials p1, p2 in P2.

Let p1(x) = a1x^2 + b1x + c1 and p2(x) = a2x^2 + b2x + c2 be two arbitrary polynomials in P2 such that f(p1) = f(p2). Then we have:

f(p1) = f(p2)

⟺ f(a1x^2 + b1x + c1) = f(a2x^2 + b2x + c2)

⟺ a1 + b1(0.5) - a1 = a2 + b2(0.5) - a2 (using the definition of f)

⟺ b1 = b2

Since f(p1) = f(p2), we also have:

a1 + b1(0.5) - a1 = a2 + b2(0.5) - a2

⟺ b1(0.5) = b2(0.5)

⟺ b1 = b2

Finally, we have:

a1 + b1(0.5) - a1 = a2 + b2(0.5) - a2

⟺ b1(0.5) = b2(0.5)

⟺ b1 = b2

Therefore, we have shown that if f(p1) = f(p2), then p1 = p2. Hence, the linear transformation f:P2 → R* is injective.

b) To determine if the linear transformation f:P2 → R* is surjective, we need to check if every element y in R* is the image of some polynomial in P2. In other words, we need to check if there exists a polynomial p in P2 such that f(p) = y for any y in R*.

Let y be an arbitrary element in R*. We want to find a polynomial p in P2 such that f(p) = y. Using the definition of f, we have:

f(ax^2 + bx + c) = a + b(0.5) - a = b(0.5)

Therefore, we need to find a polynomial p in P2 such that p(0.5) = y. Let p(x) = ax^2 + bx + c be such a polynomial. Then we have:

p(0.5) = a(0.5)^2 + b(0.5) + c = 0.25a + 0.5b + c

Hence, we need to solve the following system of equations for a, b, and c:

0.25a + 0.5b + c = y

Since this is a linear system of equations with three unknowns and one equation, there are infinitely many solutions (unless y is a special value that makes the system inconsistent). Therefore, we have shown that for any y in R*, there exists a polynomial p in P2 such that f(p) = y. Hence, the linear transformation f:P2 → R* is surjective.

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Answer:

Area of rectangle cage = 336 feet²

Step-by-step explanation:

Given:

Wire required for fencing = 100 feet

Width of rectangular cage = 8 feet

Find:

Area of rectangle cage

Computation:

Wire required for fencing = perimeter of cage

Perimeter of rectangular cage = 100 feet

2[l + b] = 100 feet

l + 8 = 50 feet

Length of rectangular cage = 42 feet

Area of rectangle cage = Length x Width

Area of rectangle cage = 42 x 8

Area of rectangle cage = 336 feet²

given:

To find 3/4 is a solution of the above given equation.

let us subsitute in value of x.

now,

we get the same answer for the equation.

Thus 3/4 is a solution of the given equaion.

Answer:

Step-by-step explanation:

First bag's unit price=$1.92 per kg  Second bag's unit price=$1.87 per kg

The second bag is the better deal

Step-by-step explanation:

Divide the price by the weight to get the unit price per kg

The lowest number is the better buy

Approximately 53.47% of prospective employees who test positive actually use illegal drugs.

we will use a tree diagram and the given information: 6% of prospective employees actually use illegal drugs, the false positive rate is 5%, and the false negative rate is 10%.
Step 1: Draw a tree diagram:
- First level: divide into two branches, one for "Uses Drugs (6%)" and one for "Does Not Use Drugs (94%)".
- Second level: under "Uses Drugs", divide into two branches, "Tests Positive (90%)" and "Tests Negative (10%)". Under "Does Not Use Drugs", also divide into two branches, "Tests Positive (5%)" and "Tests Negative (95%)".
Step 2: Calculate the probabilities:
- Probability of using drugs and testing positive: 0.06 * 0.9 = 0.054
- Probability of not using drugs and testing positive: 0.94 * 0.05 = 0.047
Step 3: Determine the percentage of prospective employees who test positive and actually use illegal drugs:
- Add the probabilities of testing positive (both using and not using drugs): 0.054 + 0.047 = 0.101
- Divide the probability of using drugs and testing positive by the total probability of testing positive: 0.054 / 0.101 ≈ 0.5347
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Answer:

-2(-6+3y-1) = -6y+14

Step-by-step explanation:

According to the California Cigarette & Tobacco Products Tax Law, the average pack of cigarettes purchase in California costs $8.40.

Option A.

The price of a cigarette in California has been on the rise for many years, owing to the state's aggressive anti-tobacco initiatives.

The state of California, like many other US states, has implemented measures aimed at discouraging smoking and the use of tobacco products, including the introduction of high taxes on cigarettes.

The tax imposed on tobacco products is intended to help cover the expenses of treating tobacco-related diseases, which cost the state millions of dollars every year.

The average cost of a pack of cigarettes in California has been steadily increasing over the years.

This can be attributed to a variety of factors, including higher tobacco taxes and anti-smoking legislation, as well as increased public awareness about the dangers of smoking and the impact it can have on one's health and wellbeing.

In conclusion, the average pack of cigarettes purchase in California is $8.40, as mandated by the state's Cigarette & Tobacco Products Tax Law.

This law, along with other anti-smoking initiatives, has been effective in reducing the prevalence of smoking and tobacco use in California over the years.

Option A.

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Jacob:

$32.90 ÷ 7 = $4.70 per shirt.

$4.70 per shirt.

Jacob paid $4.70 per shirt. (32.90 ÷ 7)

Kyle:

$60 ÷ 12 = $5 per shirt.

$5 per shirt

Kyle paid $5 per shirt (60 ÷ 12)

Kyle says that he paid less per shirt than Jacob. Is Kyle correct? Explain your answer.

Kyle is incorrect. $5 is more than $4.70.  

$5 - $4.70 =

0.30 cent difference.

The area of the trapezoid is 30x + 42. Option C

The formula for calculating the area of a trapezoid is expressed as;

A = 1/2h(b1+b2)

Such that the parameters are enumerated as;

Now, substitute the values, we get;

Area = 1/2 × 12(2x + 3 + 3x + 4)

collect the like terms, we have;

Area = 6(5x + 7)

Expand the bracket, we get;

Area = 30x + 42

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Answer:

b.

Step-by-step explanation:

(5x^5 + 4) - (2x^3+9)+(6x^5-x^3)

5x^5 + 4 - 2x^3 - 9 + 6x^5 - x^3

5x^5 + 6x^5 = 11x^5

-2x^3 - x^3 = -3x^3

+4 -9 = -5