Please Help!!! I WILL GIVE BRAINLIEST!!!! An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm. a.) Determine the horizontal distance traveled by the electron when it hits the plate. b.)Determine the velocity of the electron as it strikes the plate.

Answers

Answer 1

Answer:

a. 9.52 cm b. 4.34 × 10⁶ m/s

Explanation:

a. The horizontal distance traveled by the electron when it hits the plate.

The electric force F on the electron due to the electric field E of mass, m is

F = -eE = ma

a = -eE/m where a = acceleration of electron

The vertical distance moved by the electron is given by

Δy = ut +1/2at²

u = initial vertical velocity = 0. and take the top plate as y = 0 and bottom plate as y

So,

0 - y = 0 × t + 1/2at²

-y = 1/2at²

substituting a = -eE/m

-y = 1/2(-eE/m)t²

y = eEt²/2m

making t subject of the formula,

t = √(2ym/eE) where t is the time it takes to reach the bottom plate.

Since E = 4.0 × 10² N/C, y = distance between plates = 2.0 cm = 0.02 m, m = 9.109 × 10⁻³¹kg and e = 1.602 × 10⁻¹⁹ C

t = √[(2 × 0.02 m × 9.109 × 10⁻³¹kg)/(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C)]

t =  √[(0.36436 × 10⁻³¹kgm)/(6.408 × 10⁻¹⁷ N)]

t = √[(0.0569 × 10⁻¹⁴kgm/N)t

t = 0.238 × 10⁻⁷ s

t = 23.8 × 10⁻⁹ s

t = 23.8 ns

The horizontal distance moved when it hits the plates x = vt where v = initial horizontal velocity = 4.0 × 10⁶ m/s

x = 4.0 × 10⁶ m/s × 23.8 × 10⁻⁹ s

= 0.0952 m

= 9.52 cm

b. The velocity of the electron as it strikes the plate.

To find the velocity of the electron as it strikes the plates, we calculate its final vertical velocity V as it strikes the plate. This is gotten from

v' = u + at since u = 0,

v' = at

= -eEt/m

= -(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C × 0.238 × 10⁻⁷ s)/9.109 × 10⁻³¹kg

= -1.525 × 10⁻²⁴ Ns/9.109 × 10⁻³¹kg

= -0.167 × 10⁷ m/s

= -1.67 × 10⁶ m/s

So, the resultant velocity as it strikes the plate v = √(v'² + v²)

= √((-1.67 × 10⁶ m/s)² + (4 × 10⁶ m/s)²)

= √(2.7889  + 16) × 10⁶ m/s

= √18.7889 × 10⁶ m/s

= 4.335 × 10⁶ m/s

≅ 4.34 × 10⁶ m/s


Related Questions

a weightless spring scale is attached to two equal weights as shown below. the reading on the scale will be

Answers

When a weightless spring scale is attached to two equal weights, the reading on the scale will be zero. This is because the weights on both sides are balanced, resulting in no net force acting on the scale.



The reason for this is Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, when one weight exerts a downward force on the spring scale, the other weight exerts an upward force of the same magnitude on the scale.

These opposing forces cancel each other out, resulting in a net force of zero. As a result, the spring scale does not experience any deformation and the reading remains at zero.

It is important to note that this only applies when the two weights are equal. If the weights were different, there would be an imbalance in the forces, causing the spring scale to register a non-zero reading.

In summary, when a weightless spring scale is attached to two equal weights, the reading on the scale will be zero due to the balanced forces acting on it.

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suppose the distance from the lens system of the eye (cornea + lens) to the retina is 17 mm.

Answers

A) The power of the lens be when looking at distant objects is 58.823 D

B) The power of the lens be when looking at an object 20.0 cm from the eye is 63.823 D

According to the Dictionary of Ophthalmic Optics, the definition is stated thus: “The straight line measurement in millimeters (z axis) from the back or ocular surface vertex of a mounted spectacle lens to the apex of the cornea.” For a more practical definition, it is the straight line distance in millimeters from the back surface of any lens (mounted in spectacles or not) to the apex of the cornea.

(a) Power  1/p

      = 1/f

      = 1/ .017 m

      = 58.823 D

(b) 1/q + 1/p

    = (1/0.20 m) + (1/.017 m)

     = 63.823 D

The given question is incomplete, the complete question is

Suppose the distance from the lens system of the eye (cornea +lens) to the retina is 17 mm.

(a) What must the power of the lens be when looking at distant objects?

(b) What must the power of the lens be when looking at an object 20.0 cm from the eye?

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What would be the electron configuration for an aluminum ion?.

Answers

Answer:

[Ne] 3s² 3p¹

Explanation:

Answer: 1s2 2s2 2p6

Explanation:

The aluminum ground state would be 1s2 2s2 2p6 3s2 3p1.

However, the Aluminum Ion electron configuration would be 1s2 2s2 2p6 as it has LOST 3 electrons to have the noble gas configuration of Neon (Ne)

What are alkali earthmetals?

Answers

Answer:

The alkaline earth metals are the elements that correspond to group 2 of the modern periodic table. This group of elements includes beryllium, magnesium, calcium, strontium, barium, and radium. The elements of this group are quite similar in their physical and chemical properties.

Explanation:


DescriptionThe alkaline earth metals are six chemical elements in group 2 of the periodic table. They are beryllium, magnesium, calcium, strontium, barium, and radium. The elements have very similar properties: they are all shiny, silvery-white, somewhat reactive metals at standard temperature and pressure.

The atomic mass of sodium is 0.0230 kg/mole. How many moles are in 1.59 kg of sodium?

Answers

\(\\ \sf\longmapsto No\;of\:moles=\dfrac{Given\:mass}{Atomic\:mass}\)

\(\\ \sf\longmapsto No\:of\:moles=\dfrac{1.59}{0.0230}\)

\(\\ \sf\longmapsto No\:of\:moles=69.13moles\)

a lion is running at constant speed toward a gazelle that is standing still, as shown in the top figure above. after several seconds, the gazelle notices the lion and accelerates directly toward him, hoping to pass the lion and force him to reverse direction. as the gazelle accelerates toward and past the lion, the lion changes direction and accelerates in pursuit of the gazelle. the lion and the gazelle eventually each reach constant but different speeds. which of the following sets of graphs shows a reasonable representation of the velocities of the lion and the gazelle as functions of time?

Answers

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

It has SI units as m/s.The total amount of movement of an object per unit time is also called velocity. It depends on both the size and direction of the moving object.Velocity can also be called as speed when distance is taken into consideration instead of displacement.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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a lion is running at constant speed toward a gazelle that is standing still, as shown in the top figure

which is the hottest planet in our solar system​

Answers

Venus
Planetary surface temperatures tend to get colder the farther a planet is from the Sun. Venus is the exception, as its proximity to the Sun and dense atmosphere make it our solar system's hottest planet

Mass of the sun is 2x10³⁰ kg and that of the earth is 6/10²⁴ kg and the distance between them is 1.5 x 10¹¹m. What is the gravitational force produced between them? ​

Answers

Answer:

The gravitational force is 3.56 × 10^22 N

Explanation:

\({ \bf{force = \frac{GM_{s} m _{e}}{ {r}^{2} } }}\)

\({ \sf{force = \frac{6.67 \times {10}^{ - 11} \times (2 \times {10}^{30} ) \times (6\times {10}^{24}) }{(1.5 \times {10}^{11}) {}^{2} } }} \\ \\ { \sf{force = 3.56 \times {10}^{22} \: newtons}}\)

Why can u see the planets at night

Answers

Reflection off of the sun/moon.

Answer:

stupid question

Explanation:

10 N force is acting on the body of mass 5kg which is at rest. The velocity
gained by the body in 5 seconds is

Answers

Answer:

= 4m/s^2

Explanation:

Change in velocity is

20-0/5 = 4

what is the wavelength (in nm ) of the light used in this experiment? express your answer in nanometers.

Answers

To determine the wavelength of the light used in the experiment, we would need additional information or context about the experiment itself. information provided in the previous question about the current and charge of a lightning bolt does not directly give us the wavelength of the associated light

The given information about the current and charge of a lightning bolt does not provide any direct information about the wavelength of the associated light. To determine the wavelength of the light used in the experiment, we need additional information or assumptions about the nature of the experiment. The information provided in the previous question about the current and charge of a lightning bolt does not directly give us the wavelength of the associated light.

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A 40 W motor pulled a crate of bananas 5 meters horizontally in 120 seconds. How many Joules of work are done lifting the crate of bananas?

Answers

The total work done on the crate of bananas is 4800 J (the work done to move it horizontally).

What is work done?

Work done is defined as the product of displacement and force, w = FS.

Here,

There are two parts to the work done on the crate of bananas: the work done to move it horizontally and the work done to lift it vertically.

First, let's calculate the work done to move the crate horizontally. The formula for work is,

Work = Force x Distance x cos(Ф)

where theta is the angle between the force and the displacement. In this case, the force is the tension in the rope, and it is pulling horizontally. So, theta is 0 degrees, and cos(Ф) is 1.

The distance the crate is moved horizontally is 5 meters, and the force applied by the motor is,

Force = Power / Velocity = 40 W / (5 m / 120 s) = 960 N

So, the work done to move the crate horizontally is:

Work = 960 N x 5 m x cos(0) = 4800 J

The distance the crate is lifted vertically is not given in the problem, so we cannot calculate the work done to lift the crate without this information.

Therefore, the total work done on the crate of bananas is 4800 J (the work done to move it horizontally).

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Kevin bikes to the pizza place for lunch. He rides 1 km east, 3 km north, 4 km west, and finally 3 km south. What was his displacement?

Answers

Answer:

3km

Explanation:

To get the displacement, we will make use of the expression;

\(D = \sqrt{(\sum d_x)^2+(\sum d_y)^2}\)

Taking the sum of the distances along the x;

dx = 1km - 4km

dx = -3km

Taking the sum of the distances along the y axis

dy = 3km - 3km

dy = 0km

Substitute into the formula above;

\(R = \sqrt{(-3)^2+(0)^2}\\R = \sqrt{9} \\R = 3km\\\)

Hence his displacement is 3km

An isolated conducting rod of length 8.00 cm is oriented parallel to the x-axis. it moves in the y-direction at 3.90 m/s in the presence of a uniform magnetic field of magnitude 0.600 t that points in the -z-direction. find the magnitude of the motional emf in the rod.

Answers

The magnitude of the motional emf in the rod is 0.1872 when an isolated conducting rod of length 8.00 cm is oriented parallel to the x-axis. The speed of rod in y-direction is 3.90m/s.

Given an isolated conducting rod of length (l) = 8.00 cm = 8x10-2m

it moves in the y-direction at (v) = 3.90 m/s

uniform magnetic field of magnitude (B)= 0.600T

Let the magnitude of the motional emf in the rod be E

We know that E = BxlxV

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Hence the magnitude of the motional emf in the rod is 0.1872

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Two spaceships are heading toward each other at a mutal speed of 0.999c. both ships shine a laser beam at one another. how will each ship see the other light?

Answers

Both the ships will see the other ship with the same velocity i.e, 0.999c m/s.

To calculate the velocity of one ship as seen by the other ship, we need to use the velocity transformation formula derived from Lorentz transformation:

V = {v1 - v2/1-(v1)(v2)} x c

Here v1 and v2 are the velocities of the two ships

As the ships are heading towards each other v1 = -v2 = 0.999c

Putting this value in the above equation

V = 0.999c + 0.999c/1 - (0.999c)(0.999c) x c = 0.999c m/s

Hence, both the ships will see the other ship with the same velocity i.e, 0.999c m/s.

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momentum of photon calculatorphotons that have a wavelength of 0.00230 nm are compton scattered off stationary electrons at 30.0∘. what is the energy of the scattered photons?

Answers

The energy of the scattered photons is approximately 538.7 keV.

Momentum is a measure of an object's motion and is given by the product of its mass and velocity. However, photons, which are particles of light, have no mass but they still possess momentum due to their energy and wavelength.

The momentum of a photon is given by its energy divided by the speed of light. To calculate the energy of scattered photons, we can use the formula E = hf, where E is energy, h is Planck's constant and f is frequency.

However, since the problem gives us the wavelength of the photons, we can use the formula E = hc/λ, where c is the speed of light and λ is the wavelength.

Using this formula, we find that the energy of the scattered photons is approximately 538.7 keV.

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Why is the moon's shadow has a dark center surrounded by a region of increasing brightness?

Answers

Because the sun serves as an extended source, the moon's shadow has a dark center surrounded by a zone of rising brightness.

What do you know about the sun?

The star at the core of the solar system is the Sun. It is a nearly perfect ball of hot plasma that has been heated to incandescence by nuclear fusion processes in its center. The energy it radiates is primarily visible light, ultraviolet, and infrared radiation. It is the most crucial source of energy for life on Earth. The Sun has a radius that is around 109 times greater than that of the Earth, or 695,000 kilometers (432,000 miles). Its mass is approximately 330,000 times that of the Earth and makes up 99.86% of the solar system's total mass. The Sun's mass is made up of roughly 73% hydrogen and 24% helium, with much lesser amounts of heavier elements including oxygen, carbon, neon, and iron.

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the basic building block of all silicate minerals is the

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The basic building block of all silicate minerals is the silicon-oxygen tetrahedron.

The answer is: The silicon-oxygen tetrahedron is the basic building block of all silicate minerals.

Explanation: The basic building block of all silicate minerals is the silicon-oxygen tetrahedron. It consists of four oxygen atoms arranged around a silicon atom in a tetrahedral shape, which is a pyramid with a triangular base.

Each oxygen atom shares two electrons with the silicon atom, forming covalent bonds. The structure of the tetrahedron is so strong that it forms the backbone of all silicate minerals.

Silicate minerals are the most abundant minerals on Earth's crust. They are essential components of rocks and soils and play a vital role in the carbon cycle, the formation of mountains, and the formation of the Earth's crust.

Conclusion: Therefore, it can be concluded that the silicon-oxygen tetrahedron is the basic building block of all silicate minerals.

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Which scenario displays the corporate responsibility of a business toward a community?
A.
paying the correct amount of taxes on time
B.
contributing supplies to charities to help in disaster relief
C.
fair return of profits and arranging training programs
D.
serving customers to the best of their potential

Answers

Answer:

A.

Explanation:

Because you are working in the buisnes, you can make a good impression by paying the exact amount or more in taxes.

how the HSR works in China?

Answers

Answer:

High-speed rail in China is officially defined as "newly-built passenger-dedicated rail lines designed for electrical multiple unit (EMU) train sets traveling at not less than 250 km/h (155 mph) (including lines with reserved capacity for upgrade to the 250 km/h standard) on which initial service operate at not less ...

PLEASE HELP ASAP A ball is rolling on a flat, frictionless surface. What will happen to the ball if no unbalanced force acts on the ball?

A.
The ball will roll faster and faster.

B.
The ball will begin to roll in the opposite direction.

C.
The ball will begin to roll faster for a time and then begin to roll slower.

D.
The ball will continue to roll in the same direction and at the same speed.

Answers

the answer is A: the ball will roll faster and faster

Rolling friction causes a ball to roll more slowly when it rolls on a horizontal surface. Since static friction is to blame for the friction force, it produces no net work and has no effect on energy dissipation. Thus, option A is correct.

What happens to the ball if no unbalanced force on the ball?

On a frictionless horizontal surface, the ball could neither speed up no slow down because the horizontal surface was intermediate between downhill and uphill. Galileo concluded that in the absences of friction, a ball that once started rolling on a horizontal surface would roll forever.

Friction causes a ball rolling on a flat surface to slow down. The ball finally comes to a stop as a result of friction, which operates in opposition to the ball's motion. If not, it will continue to roll indefinitely.

Therefore, The friction force is brought on by static friction; it has no effect on releasing energy or producing net work.

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For the following two distributions of density of some material,

(i) rho = t −1/2 exp (− x2 /(4µt)) ,

(ii) rho = rho0 − 2x ,

1. Sketch rho as a function of x for a couple of different times.

2. Verify that rho satisfies the diffusion equation

∂rho/∂t = µ ∂2rho/∂x2 .

3. What is the flux of material, q, past any point x at any time t?

Answers

The density distributions (i) and (ii) can be sketched as functions of x for different times, providing insights into their behavior over time.

How can we demonstrate that the density distributions (i) and (ii) satisfy the diffusion equation?

The flux of material (q) past any point x at any time t can be determined by multiplying the density gradient (∂rho/∂x) with the diffusion coefficient µ. This represents the flow of material per unit area perpendicular to the x-axis, indicating the rate of material transport.

To sketch the density distributions (i) and (ii), we can plot the density values as a function of x for various time values. For distribution (i), the density decreases with increasing distance from the origin, forming a bell-shaped curve that decreases over time.

The rate of decrease depends on the diffusion coefficient µ. For distribution (ii), the density linearly decreases with increasing distance from the origin and remains constant over time. These sketches provide visual representations of how the density of the material changes spatially and temporally.

To verify that the density distributions satisfy the diffusion equation, we need to compare the equations with the given distribution forms.

By taking the partial derivative of density with respect to time (∂rho/∂t) and the second partial derivative of density with respect to x (∂²rho/∂x²), we can confirm whether they are proportional to each other with a factor of µ. If the resulting equations match, it indicates that the distributions satisfy the diffusion equation.

The flux of material (q) past any point x at any time t is determined by multiplying the density gradient (∂rho/∂x) with the diffusion coefficient µ. This represents the rate at which material is flowing through a specific point in the x-direction.

It provides information about the amount of material passing through a given area per unit time, highlighting the transport properties of the material.

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A rectangular block with dimensions 6.0 cm x 8.0 cm x 12.0 cm is made of aluminium of density 2700 kg m¹. Find the maximum pressure it can exert when placed on one of its faces on a horizontal surface.​

Answers

The maximum pressure the rectangular block can exert on a surface when placed on one of its faces on a horizontal surface is 317.71 Pa.

What is the maximum pressure of the block?

The maximum pressure the rectangular block can exert on a surface occurs when it is placed on one of its smallest faces.

To calculate the maximum pressure, we need to find the weight of the block, which is equal to its mass multiplied by the acceleration due to gravity. The mass of the block can be calculated as follows:

mass = density x volume

The volume of the block is:

volume = length x width x height

volume = 6.0 cm x 8.0 cm x 12.0 cm

volume = 576 cm³

Converting to meters:

volume = 0.006 m x 0.008 m x 0.12 m

volume = 5.76 x 10^-5 m³

Therefore, the mass of the block is:

mass = density x volume

mass = 2700 kg/m³ x 5.76 x 10^-5 m³

mass = 0.1555 kg

The weight of the block is:

weight = mass x acceleration due to gravity

weight = 0.1555 kg x 9.81 m/s²

weight = 1.526 N

When the block is placed on one of its smallest faces, the area of contact with the surface is:

area = length x width

area = 6.0 cm x 8.0 cm

area = 48 cm²

Converting to meters:

area = 0.06 m x 0.08 m

area = 0.0048 m²

Therefore, the maximum pressure the block can exert on the surface is:

pressure = weight / area

pressure = 1.526 N / 0.0048 m²

pressure = 317.71 Pa

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Get the equation for energy. Explain the physical meaning of
energy in cfd.

Answers

The equation for energy in the context of fluid dynamics, specifically in Computational Fluid Dynamics (CFD), is typically represented by the conservation of energy equation, also known as the energy equation or the first law of thermodynamics. The equation can be expressed as:

ρ * (du/dt + u * ∇u) = -∇p + ∇⋅(μ * (∇u + (∇u)^T)) + ρ * g + Q

where:

ρ is the density of the fluid

u is the velocity vector

t is time

∇u represents the gradient of velocity

p is the pressure

μ is the dynamic viscosity

g is the gravitational acceleration vector

Q represents any external heat source/sink

The physical meaning of energy in CFD is the total energy of the fluid system, which includes kinetic energy (associated with the motion of the fluid), potential energy (associated with the elevation of the fluid due to gravity), and internal energy (associated with the fluid's temperature and pressure). The energy equation describes how this total energy is conserved and transformed within the fluid system.

In CFD simulations, the energy equation plays a crucial role in modeling the energy transfer, heat transfer, and flow characteristics within the fluid. It helps in understanding how energy is distributed, dissipated, and exchanged within the fluid domain. By solving the energy equation numerically, CFD simulations can predict temperature profiles, flow patterns, heat transfer rates, and other important parameters that are essential for various engineering applications, such as designing efficient cooling systems, optimizing combustion processes, and analyzing thermal behavior in fluid flows.

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Convert this decimal into its fractional
form simplified completely.
0.350

Answers

Answer:

7/20

Explanation:

0.35 as a fraction =35/100

35/100 can b divided by 5 so =7/20

0.350 simplified as a fraction is 7/20

Answer:

7/20

Explanation:

(b) if one micrometeorite (a sphere with a diameter of 1.30 10-6 m) strikes each square meter of the moon each second, how many years would it take to cover the moon to a depth of 1.20 m? (hint: consider a box on the moon 1.00 m on a side and 1.20 m deep, and find how long it will take to fill the box.)

Answers

The time required to cover the Moon to a depth of 1.20 meters with micrometeorites.

To find out how long it would take to cover the Moon to a depth of 1.20 meters with micrometeorites, we can calculate the volume of the Moon and then divide it by the volume of one micrometeorite. Let's break down the calculation step by step:

Calculate the volume of the Moon:

The average radius of the Moon is approximately 1.737 ×10⁶ meters. Using the formula for the volume of a sphere, V = (4÷3)πr³, we can calculate the volume of the Moon.

\(V_{moon}\) = (4÷3)π(1.737 × 10⁶)³

Calculate the volume of one micrometeorite:

The diameter of the micrometeorite is given as 1.30 ×10⁽⁻⁶⁾ meters, which means the radius is half of that.

\(r_{meteorite}\) = (1.30 × 10⁽⁻⁶⁾)÷2

Using the formula for the volume of a sphere, V = (4÷3)πr₃, we can calculate the volume of one micrometeorite.

\(V_{meteorite}\) = (4÷3)π((1.30 × 10⁽⁻⁶⁾)÷2)³

Calculate the number of micrometeorites needed to fill the Moon:

To find the number of micrometeorites required to fill the Moon, we divide the volume of the Moon by the volume of one micrometeorite.

\(N_{meteorites}\) = \(V_{moon}\) ÷ \(V_{meteorite}\)

Calculate the time to fill the Moon:

Since one micrometeorite strikes each square meter of the Moon each second, we can equate the number of micrometeorites needed to fill the Moon to the number of seconds it would take.

Time = \(N_{meteorites}\) ÷ (1 m²/s)

Convert seconds to years:

Finally, we convert the time in seconds to years by dividing by the number of seconds in a year (assuming 365.25 days in a year and 24 hours in a day).

\(Time_{years}\) = Time ÷ (365.25 days/year × 24 hours/day × 3600 seconds/hour)

Performing these calculations will give us the time required to cover the Moon to a depth of 1.20 meters with micrometeorites.

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A person pushes on a box with a force of 500N. If the box does not move, what is the force of static friction on the box?
A. 100 N
B. 200 N
C. 500 N
D. Cannot be determined

Answers

Answer:

c

Explanation:

Please help!! :)

For this circuit, what will be the voltage drop across R1?

A. 21.3 V

B. 14.2 V

C. 45.0 V

D. 9.47 V

Please help!! :)For this circuit, what will be the voltage drop across R1? A. 21.3 VB. 14.2 VC. 45.0

Answers

Answer:

Option D. 9.47 V

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 Ω

Resistor 2 (R₂) = 30 Ω

Resistor 3 (R₃) = 45 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂ + R₃ (series connections)

R = 20 + 30 + 45

R = 95 Ω

Next, we shall determine the current in the circuit. This can be obtained as follow:

Voltage (V) = 45 V

Equivalent Resistance (R) = 95 Ω

Current (I) =?

V = IR

45 = I × 95

Divide both side by 95

I = 45 / 95

I = 0.4737 A

Finally, we shall determine, the voltage across R₁. This can be obtained as follow:

NOTE: Since the resistors are in series connection, the same current will pass through them.

Current (I) = 0.4737 A

Resistor 1 (R₁) = 20 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 0.4737 × 20

V₁ = 9.47 V

Therefore, the voltage across R₁ is 9.47 V.

Answer:

9.47

Explanation:

Just Took the Test

.- ¿Por qué se da ese incremento tan grande de energía de ionización requerida para retirar el segundo electrón de un átomo de sodio en contraste con el primer electrón?

Answers

Answer:

ver explicacion

Explanation:

El sodio tiene configuración electrónica 2,8,1.

Esto implica que el sodio tiene solo un electrón en su capa más externa. Como tal, cuando ese electrón se pierde, el siguiente electrón debería perderse de una capa interna llena.

Se requiere mucha más energía para perder un electrón de una capa interna llena de la que se requiere para perder un electrón de la capa más externa.

Por lo tanto, existe una brecha muy grande entre la primera y la segunda energía de ionización del sodio porque se requiere una cantidad de energía mucho mayor para eliminar un electrón de una capa interna que de una capa más externa.

. a free jet is a stream of fluid exhausted to the atmosphere (such as sketched below). the pressure of the fluid inside the free jet is usually assumed to be atmospheric pressure. however, if we do not neglect surface tension, the pressure in jet should be slightly higher than atmospheric pressure. thus, consider a free jet of water with velocity v

Answers

According to the question, the change in pressure for the jetstream is  14.54Pa.

What is pressure?

The force applied perpendicularly to an object's surface expressed as a symbol (p or P) is the force divided by the area of the object's surface. The pressure when compared to the surrounding air pressure is known as gauge pressure. Pressure is expressed using a number of different units. The SI unit of pressure, the pascal (Pa), for instance, is equal to one newton per square meter (N/m²). Some of these measurements are the result of dividing a unit of force by a unit of area.

Explanation:

Given;

jet's diameter,d = 10⁻²m

temperature, t = 20°C

Surface tension acts only on the lines AB and CD.

Consider the equilibrium of forces;

∑F = 0

P₁-P₀ = 2σ/d

here surface tension σ = 0.0727 N/m

P₁-P₀ = 2×0.0727/10⁻²

        = 14.54 Pascal

Hence, the change in pressure of the jetstream is 14.54 Pascal.

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