please help!!!! i don't know....​

Answer:

a=28 b=87

Step-by-step explanation:

a-10=18 a=10+18 a=28 b+16=103 b=103-16 b=87

We have that the GCF(16, 32) = 16, so we have that the sum is equal to

Answer:

-10

Step-by-step explanation:

1. First, let's simplify both sides of the equation.

2. To find the missing value to make the equation have infinitely many solutions, we need to make both sides of the equation equal.

3. Given that information, means that 4x - 10 has to equal 4x + (-10) because:

4. Now, with the information in #2, let's see if it's true:

Therefore, the missing number is -10.

Answer:

∠A = 120° (180°-60°)

∠W = 60° (b/c ∠W=∠X)

∠Y = 100° (b/c 180°-80°)

∠X = 60° (180°-120°)

∠Z = 120° (180-60°)

Step-by-step explanation:

im unsure about A and W

Answer:

Answer:

\(8\sqrt{5}+3\sqrt{30}\)

Step-by-step explanation:

\(\sqrt{5}(8+3\sqrt{6})\)

\((\sqrt{5})(8)+(\sqrt{5})(3\sqrt{6})\)

\(8\sqrt{5}+3\sqrt{30}\)

Answer:

∠B = 26.39° (nearest thousandth)

Step-by-step explanation:

Use trig ratio sin(B) = O/H

where O = opposite side to angle and H = hypotenuse:

⇒ sin(B) = O/H = 4/9

⇒ B = arcsin(4/9)

⇒ B = 26.387799..

⇒ B = 26.39° (nearest thousandth)

c ccccccccccccccccccccccccccccc

Answer: The answer is A

Step-by-step explanation: The vertical line test is a method that is used to determine whether a given relation is a function or not. The approach is rather simple. Draw a vertical line cutting through the graph of the relation, and then observe the points of intersection. So, Since the graph on the intersects the line once, it is a function.

Answer:

D

Step-by-step explanation:

D is the only one with 1.5 as a y-intercept.

~theLocoCoco

Answer:

Answer is D

Step-by-step explanation:

0x means that the x axis did move. the y intercept is 1.5. if no number appears infront of y or x just know that the 1 is always infront of y or x even if you don't see it.

The recursive rule for the number of acres at the beginning of the nth day in a forest fire that grows by 20% each day and is battled by firefighters who can put out 15 acres per day is given by: A(n) = 1.2 * A(n-1) - 15, where A(n) represents the number of acres at the beginning of the nth day. Using this rule, we can calculate that there are 89.6 acres burning at the beginning of the 8th day.

Explanation: To determine the recursive rule for the number of acres at the beginning of the nth day, we need to consider the given information. The forest fire initially covers 60 acres and grows by 20% each day. This means that the number of acres at the beginning of the next day (n+1) is 1.2 times the number of acres at the beginning of the current day (n). However, the firefighters are able to put out 15 acres of fire per day.

Therefore, to calculate A(n), we start with the initial number of acres, which is 60, and apply the recursive rule. A(n) = 1.2 * A(n-1) - 15. This formula takes into account the growth of the fire by 20% and the reduction of 15 acres due to the firefighters' efforts. By substituting the values, we can calculate the number of acres at the beginning of each day.

To find the number of acres burning at the 8th day, we substitute n = 8 into the recursive rule. A(8) = 1.2 * A(7) - 15. We need to determine A(7) first by substituting n = 7, and so on, until we reach the initial value A(1) = 60. Once we have calculated A(8), we can determine that there are 89.6 acres burning at the beginning of the 8th day

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The quotient of the polynomial 100x - 40 / 2- 5x is 4.

How do you find the quotient of a polynomial?

The quotient and remainder are then calculated as follows: Divide the dividend's first term by the divisor's highest term (meaning the one with the highest power of x, which in this case is x).

Given 100x - 40 / 2- 5x = 0

\(\Rightarrow \dfrac{100x - 400}{2 - 5x} = 0\)

factorize

\(\Rightarrow \dfrac{100(x - 4)}{2 - 5x} = 0\)

\(\Rightarrow 100(x - 4) = 0 \times 2 - 5x}\)

\(\Rightarrow 100x - 400 = 0\)

\(\Rightarrow 100x = 400\)

\(\Rightarrow x = \dfrac{400}{100}\)

⇒ x = 4

Thus, the quotient of the polynomial 100x - 40 / 2- 5x is 4.

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The probability of finding oil in Alaska is 0.45. The revised probabilities, obtained using Bayes' theorem, indicate that the most likely quality of oil to be found is medium-quality oil.

To calculate the probability of finding oil, we need to consider the probabilities of finding oil given different qualities. The probability of finding oil can be obtained by summing the individual probabilities of finding oil of high-quality, medium-quality, and no oil.

P(high-quality oil | soil) = P(soil | high-quality oil) * P(high-quality oil) / P(soil)

P(medium-quality oil | soil) = P(soil | medium-quality oil) * P(medium-quality oil) / P(soil)

P(no oil | soil) = P(soil | no oil) * P(no oil) / P(soil)

Given the preliminary geologic studies, P(soil | high-quality oil) = 0.25, P(soil | medium-quality oil) = 0.70, and P(soil | no oil) = 0.25. The probabilities of high-quality oil, medium-quality oil, and no oil are 0.55, 0.25, and 0.20, respectively.

Using Bayes' theorem, we can calculate the revised probabilities:

P(high-quality oil | soil) = (0.25 * 0.55) / (0.25 * 0.55 + 0.70 * 0.25 + 0.25 * 0.20)

P(medium-quality oil | soil) = (0.70 * 0.25) / (0.25 * 0.55 + 0.70 * 0.25 + 0.25 * 0.20)

P(no oil | soil) = (0.25 * 0.20) / (0.25 * 0.55 + 0.70 * 0.25 + 0.25 * 0.20)

After calculating these values, we find that the new probability of finding oil is 0.45. This means that there is a 45% chance of finding oil. According to the revised probabilities, the quality of oil that is most likely to be found is medium-quality oil.

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The length of the shorter leg is 16 units which was found using the given data.

A quadratic equation is a second-degree algebraic equation in x. In its usual form, the quadratic equation is ax² + bx + c = 0.

Given: The larger leg of a right triangle is twice more than three times the shorter leg, and the triangle's area is 400.

We know that,

Area of triangle = 1/2(larger leg)(shorter leg)

                  400=1/2(larger leg)(shorter leg)   Equation(1)

larger leg = 2 + 3(shorter leg)

We need to substitute this in Equation(1)

400 = 1/2[2+3(shorter leg)](shorter leg)

800 = 2(shorter leg) + 3(shorter leg)²

3(shorter leg)² + 2(shorter leg) - 800 = 0

Solving this quadratic equation,

we get, shorter leg = - 16 or +16

Thus, we found that the length of the shorter leg is 16 units as -16 cannot be the length because it is negative.

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The compound interval for the given interval is (-∞, ∞).

A compound inequality is a combination of two inequalities that are combined by either using "and" or "or". The process of solving each of the inequalities in the compound inequalities is as same as that of a normal inequality but just while combining the solutions of both inequalities depends upon whether they are clubbed by using "and" or "or".

The given intervals are (-∞, -2] or [-3, ∞).

Now, the compound interval is (-∞, ∞)

Thus, the interval notation is -∞<x<∞

Therefore, the compound interval for the given interval is (-∞, ∞).

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Answer: 24/5=4.8  36/8=4.5

Step-by-step explanation: First, let's start off by dividing 24 by 5. We can turn this into 24.0 divided by 5 to make it a bit simpler. We know that 240 by 5 = 48, then since there is a decimal 1 digit to the left in 24.0, we apply that decimal 1 digit to the left in 48, making it 4.8! Now let's do 36 by 8. We can do what we did for problem 1 and turn 36 into 36.0, 360 by 8 = 45 and applying the same logic we used before, 360 turns into 36.0, and 45 turns into 4.5! Therefore, Kalel is wrong, and the two equation is not equal.

P.S. Using long division, Kalel is technically kind of right, but there's still that unaccounted for '4' that we still need to divide.

The given limit can be expressed as the definite integral ∫[3π, 5π] cos(x) dx over the interval [3π, 5π].

To express the limit as a definite integral, we can rewrite the sum as a Riemann sum and take the limit as n approaches infinity.

The given sum can be written as:

lim(n → ∞) [Σ(i = 1 to n) cos(xi) Δxi],

where Δxi = (b - a) / n is the width of each subinterval, xi is a sample point in the i-th subinterval, and [a, b] is the interval [3π, 5π].

To express the limit as a definite integral, we can rewrite the sum using the definite integral notation:

lim(n → ∞) [Σ(i = 1 to n) cos(xi) Δxi] = ∫[3π, 5π] cos(x) dx,

where dx represents an infinitesimally small change in x. By taking the limit as n approaches infinity, the sum converges to the definite integral.

Therefore, the given limit can be expressed as the definite integral ∫[3π, 5π] cos(x) dx over the interval [3π, 5π].

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The probability of answering a question correctly is 0.7 + 0.3/N.

Given: N answer choices for each question; a student knows the answer to 70% of the questions; and the student guesses uniformly and at random for remaining 30% of the questions.

Let K be the event that the student knows the answer to a question and R be the event that the student answers the question correctly.

The probability of event K can be calculated as:

P(K) = 0.7The probability of event K' (not knowing the answer) can be calculated as:

P(K') = 0.3The probability of event R given K can be calculated as:

P(R|K) = 1The probability of event R given K' can be calculated as:P(R|K') = 1/N

Therefore, the probability of event R can be calculated using the law of total probability:

P(R) = P(K)P(R|K) + P(K')P(R|K')P(R)

= 0.7 × 1 + 0.3 × (1/N)P(R)

= 0.7 + 0.3/N

Therefore, the probability of answering a question correctly is 0.7 + 0.3/N.

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Answer:

x can be any number greater than 10, there are infinite solutions.

>, meaning x is greater than 10

The solution set to the inequality equation x > 10 has infinite number of solutions as x can have any value greater than 10

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

Given data ,

Let the inequality equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

x > 10   be equation (1)

So , the value of x is given by set P = { 11 , 12 , 13 , 14 ... }

Therefore , the value of x is any number greater than 10 and the inequality relation has infinite number of solutions

Hence , the inequality equation is x > 10

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Answer:

Step-by-step explanation:

\(we \ can \ show \\(a^{b})^{c}=a^{bc}\\,as,\\2^{-2}t^{6}\\a^{-b}=\frac{1}{a^{b}}\\2^{-2}t^{6}=\frac{1}{4}t^{6}\)

Answer:

See below.

Step-by-step explanation:

We are asked to simplify the given expression.

Let's begin by identifying an important rule. Because there's a negative exponent and a negative exponent outside of the parentheses, we multiply the exponents and the product will be a positive exponent.

We also need to remember that the exponent outside of the parentheses acts on everything inside the parentheses.

Evaluate:

\((2t^{-3} )^{-2} = 2^{-2} \times t^{6}.\)

Further Evaluate:

\(2^{-2} = \frac{1}{2^2} = \frac{1}{4}. \\t^{6} = t \times t \times t \times t \times t \times t.\)

Multiply:

\(t^{6} \times \frac{1}{4} = \frac{t^{6} }{4} \ or \ \frac{1}{4} (t^6) .\)

We can't simplify any further.

Therefore, our final answer is \(\frac{t^{6} }{4} \ or \ \frac{1}{4} (t^6).\)

Answer:mode

Step-by-step explanation:5+4+9+9+3+75+1=mode

a). We have proved all the given conditions.

b). It is true that condition 3 holds for all regular languages L1 and L2.

(a) Regular languages L1 and L2 can be suggested as follows:

Let \(L_1={0^{(n+1)} | n\geq 0}\)

and

\(L_2={1^{(n+1)} | n\geq 0}\)

We have to prove three conditions:1. L1 ⊈ L2:

The given languages L1 and L2 both are regular but L1 does not contain any string that starts with 1.

Therefore, L1 and L2 are distinct.2. L2  L1:

The given languages L1 and L2 both are regular but L2 does not contain any string that starts with 0.

Therefore, L2 and L1 are distinct.3. (L1 ∪ L2)* = L1* ∪ L2*:

For proving this condition, we need to prove two things:

First, we need to prove that (L1 ∪ L2)* ⊆ L1* ∪ L2*.

It is clear that every string in L1* or L2* belongs to (L1 ∪ L2)*.

Thus, we have L1* ⊆ (L1 ∪ L2)* and L2* ⊆ (L1 ∪ L2)*.

Therefore, L1* ∪ L2* ⊆ (L1 ∪ L2)*.

Second, we need to prove that L1* ∪ L2* ⊆ (L1 ∪ L2)*.

Every string that belongs to L1* or L2* also belongs to (L1 ∪ L2)*.

Thus, we have L1* ∪ L2* ⊆ (L1 ∪ L2)*.

Therefore, (L1 ∪ L2)* = L1* ∪ L2*.

Therefore, we have proved all the given conditions.

(b)It is true that condition 3 holds for all regular languages L1 and L2.

This can be proved by using the fact that the union of regular languages is also a regular language and the Kleene star of a regular language is also a regular language.

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Answer:

Below in bold.

Step-by-step explanation:

m < DAC  = 360 -15 - 155 - 166

                = 24⁰

The bearing of D from A

                = 180 + 15 + 24

                 =  219⁰

or S 39⁰ W.

Comparison or relational operations, such as <, >, =, allow for comparing numbers. They determine if a number is less than, greater than, equal to, or not equal to another number, enabling decision-making and comparisons within arithmetic and programming operations.

When comparing numbers, you can use various relational operators to determine the relationship between them. Here are the commonly used comparison operators:

Less than (<): This operator compares two numbers and returns true if the first number is smaller than the second number. For example, 5 < 10 is true.

Greater than (>): This operator compares two numbers and returns true if the first number is larger than the second number. For example, 10 > 5 is true.

Less than or equal to (<=): This operator compares two numbers and returns true if the first number is smaller than or equal to the second number. For example, 5 <= 5 is true.

Greater than or equal to (>=): This operator compares two numbers and returns true if the first number is larger than or equal to the second number. For example, 10 >= 10 is true.

Equal to (==): This operator compares two numbers and returns true if they are equal. For example, 5 == 5 is true.

Not equal to (!=): This operator compares two numbers and returns true if they are not equal. For example, 5 != 10 is true.

These comparison operators allow you to compare numbers and make decisions based on their relationships within arithmetic or programming operations.

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Answer:

5/7

Step-by-step explanation:

you divide by 2 or 3 or 4 or 5 ect

Step-by-step explanation:

find a common denomination

10÷2=5

14÷2=7

so, 10/14 = 5/7

                                             Incomplete question

Answer:

The difference in the amount of interest she would have to pay for the two loans is $1,400

Step-by-step explanation:

The amount of loan Holly is taking out, P = $10,000

The choices available for the loan are;

1) Loan duration, T₁ = 4-year

Interest rate, R₁ = 4%

2) Loan duration, T₂ = 6-year

Interest rate, R₂ = 5%

For the first choice, we have;

The simple interest, I, given by the formula;

\(I_1 = \dfrac{P \times R_1 \times T_1 }{100} = \dfrac{10,000 \times 4 \times 4 }{100} = \$ 1,600\)

For the second choice, we have;

The simple interest, I, given by the formula;

\(I_2 = \dfrac{P \times R_2 \times T_2 }{100} = \dfrac{10,000 \times 5 \times 6 }{100} = \$ 3,000\)

The difference, D, in the amount of interest she would have to pay for the two loans is therefore;

D = I₂ - I₁ = $3,000 - $1,600 = $1,400

The difference in the amount of interest she would have to pay for the two loans = D = $1,400.

Answer:

1400

Step-by-step explanation:

I got this question right...

Answer:The answer is ≥ greater than or equal to

can you mark me Brainliest please

Answer:

Yvette plotted (10, 2) because for 10 oranges you have 2 pineapples. Similarly, she would plot (20, 4) for the same reason.

Answer:

20,4

Step-by-step explanation:

edge

The profit margins (return on sales) for each division are approximately :Division A = 10.85%,Division B = 9.11% and The calculations for the year would be:Net Income = $85,428,Return on Assets = 18.9%.

To compute the profit margins (return on sales) for each division, we divide the profit by the sales and multiply by 100 to express the result as a percentage.

For Division A:

Profit Margin = (Profit / Sales) * 100

Profit Margin = ($230,000 / $2,120,000) * 100

Profit Margin ≈ 10.85%

For Division B:

Profit Margin = (Profit / Sales) * 100

Profit Margin = ($34,700 / $381,000) * 100

Profit Margin ≈ 9.11%

To calculate the net income and return on assets for Polly Esther Dress Shops Inc., we use the given information.

Net Income = Profit Margin * Sales

Net Income = 7% * $1,220,400

Net Income = $85,428

Return on Assets = Profit Margin * Asset Turnover

Return on Assets = 7% * 2.7

Return on Assets = 18.9%

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