Answer:
107 degrees
Step-by-step explanation:
The four angles of a parallelogram add up to 360 degrees. Any two adjacent angles of a parallelogram add up to 180 degrees. So y is equal to 180 degrees minus 73 degrees, which is equal to 107 degrees.
Simplify:
3
6
4
Help me out pls
3 -> 1
6 -> 3 -> 1
4 -> 2 -> 1
i don't know
The coordinate grid shows points A through K. What point is a solution to the system of inequalities? y > −2x + 10 y > 1/2x − 2 coordinate grid with plotted ordered pairs, point A at negative 5, 4 point B at 4, 7 point C at negative 2, 7 point D at negative 7, 1 point E at 4, negative 2 point F at 1, negative 6 point G at negative 3, negative 10 point H at negative 4, negative 4 point I at 9, 3 point J at 7, negative 4 and point K at 2, 3
answer:
a) E
b) K
c) B
d) D
Based on the analysis, point D at (-7, 1) is the only solution to the system of inequalities y > -2x + 10 and y > (1/2)x - 2. Therefore, the correct answer is option d) D.
To determine which point is a solution to the system of inequalities y > -2x + 10 and y > (1/2)x - 2, we can test each point to see if it satisfies both inequalities.
a) Point E at (4, -2):
Substituting the coordinates into the inequalities:
-2 > -2(4) + 10 -> -2 > -8 + 10 -> -2 > 2 (False)
-2 > (1/2)(4) - 2 -> -2 > 2 - 2 -> -2 > 0 (False)
b) Point K at (2, 3):
Substituting the coordinates into the inequalities:
3 > -2(2) + 10 -> 3 > -4 + 10 -> 3 > 6 (False)
3 > (1/2)(2) - 2 -> 3 > 1 - 2 -> 3 > -1 (True)
c) Point B at (4, 7):
Substituting the coordinates into the inequalities:
7 > -2(4) + 10 -> 7 > -8 + 10 -> 7 > 2 (True)
7 > (1/2)(4) - 2 -> 7 > 2 - 2 -> 7 > 0 (True)
d) Point D at (-7, 1):
Substituting the coordinates into the inequalities:
1 > -2(-7) + 10 -> 1 > 14 + 10 -> 1 > 24 (False)
1 > (1/2)(-7) - 2 -> 1 > -3.5 - 2 -> 1 > -5.5 (True)
Based on the analysis, point D at (-7, 1) is the only solution to the system of inequalities y > -2x + 10 and y > (1/2)x - 2. Therefore, the correct answer is option d) D.
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The table shows values for a quadratic function.
x,y
0,0
1,2
2,8
3,18
4,32
5,50
6,72
What is the average rate of change for this function for
the interval from x= 1 to x= 3?
A. 6
B. 4
C. 8
D. 9
The a = 0.Substituting the values of a, b, and c in the general equation, we get:y = 0x² + 2x + 3The quadratic function is:y = 2x + 3Answer: The quadratic function is y = 2x + 3.
The given table illustrates the values of a quadratic function. Here is how you can find the quadratic function:Step 1: Write the general form of a quadratic function y = ax² + bx + c, where y is the dependent variable and x is the independent variable. a, b, and c are constants that affect the shape and position of the parabola.Step 2: Substitute the values from the table for x and y to form a system of equations.Step 3: Solve the system of equations to find the values of a, b, and c. Once you have found these values, substitute them into the quadratic equation to get the quadratic function.
The given table is as follows:x | 0 | 2 | 4 | 6y | 3 | 1 | -1 | -3Step 2:Form a system of equations using the values in the table. Here are the equations:y = a(0)² + b(0) + cy = a(2)² + b(2) + cy = a(4)² + b(4) + cy = a(6)² + b(6) + cStep 3:Solve the system of equations.Using the first equation, y = c. Hence, we have:y = 0²a + 0b + c3 = cThe value of c is 3.Using the second equation, we have:y = 2²a + 2b + 3y = 4a + 2b + 3Subtracting the two equations, we get:- 2a - b = - 2a + b = 2b = 4Therefore, b = 2.Substituting the values of b and c into the first equation, we get:3 = a(0)² + 2(0) + 3
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ronald lau, chief engineer at south dakota electronics, has to decide whether to build a new state-of-the-art processing facility. if the new facility works, the company could realize a profit of $200,000. if it fails, south dakota electronics could lose $190,000. at this time, lau estimates a 50% chance that the new process will fail. the other option is to build a pilot plant and then decide whether to build a complete facility. the pilot plant would cost $5,000 to build. lau estimates a 60% chance that the pilot plant will work. if the pilot plant works, there is a 75% probability that the complete plant, if it is built, will also work. if the pilot plant does not work, there is only a 30% chance that the complete project (if it is constructed) will work. lau faces a dilemma. by analyzing this problem, help lau to maximize his expected payoff. what is the best decision you recommend for lau and what is the expected payoff? write your answer in the space below
I recommend that Ronald Lau build the pilot plant first to maximize his expected payoff. The expected payoff for this decision is $55,000.
To help Ronald Lau maximize his expected payoff, we can use decision analysis to evaluate the potential outcomes and probabilities of each decision.
The first decision is whether to build the new facility directly or to build the pilot plant first and then decide whether to build the complete facility.
If the new facility is built directly, the expected payoff is $200,000 × 0.5 + (-$190,000) × 0.5 = $5,000.
If the pilot plant is built first, the expected payoff is:
$5,000 + $200,000 × 0.75 × 0.6 + (-$190,000) × 0.25 × 0.6 = $55,000
or
$5,000 + (-$190,000) × 0.75 × 0.4 + $200,000 × 0.25 × 0.4 = -$45,000
The best decision is to build the pilot plant first since this decision has a higher expected payoff of $55,000 compared to the expected payoff of $5,000 for building the new facility directly.
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find the average value of f over the given rectangle. f(x, y) = 5ey x + ey , r = [0, 6] ⨯ [0, 1]
The average value of f over the rectangle [0,6] x [0,1] is approximately 3.427.
The average value of a function f over a rectangle R is given by:
avg(f) = (1/Area(R)) * double integral of f over R
Here, f(x,y) = 5e^(yx) + e^y and R = [0,6] x [0,1]
The area of R is given by:
Area(R) = (6 - 0) * (1 - 0) = 6
So, the average value of f over R is:
avg(f) = (1/6) * double integral of f over R
We can evaluate the double integral using iterated integration. First, we integrate f with respect to y from 0 to 1, and then integrate the result with respect to x from 0 to 6:
integral of f(x,y) dy = integral of (5e^(yx) + e^y) dy
= (5x/2)e^(yx) + e^y + C
where C is the constant of integration.
Now, we integrate this result with respect to x from 0 to 6:
integral of [(5x/2)e^(yx) + e^y] dx = [(5/2) * integral of xe^(yx) dx] + integral of e^y dx
= [(5/2) * (1/y)e^(yx) - (5/2)(1/y^2)(e^(yx) - 1)] + ey + C
where C is another constant of integration.
Therefore, the average value of f over R is:
avg(f) = (1/6) * [(5/2) * (1/y)e^(yx) - (5/2)(1/y^2)(e^(yx) - 1) + ey] evaluated from y=0 to y=1 and x=0 to x=6
avg(f) = (1/6) * [(5/2) * (1/e^6 - 1) - (5/2)(1/e - 1/e^6) + e - 1]
avg(f) = (1/6) * [(5/2) * (1 - e^-6) - (5/2)(e^-1 - e^-6) + e - 1]
avg(f) = (1/6) * [(5/2) * (1 - e^-6 - e^-1 + e^-6) + e - 1]
avg(f) = (1/6) * [(5/2) * (1 - e^-1) + e - 1]
avg(f) ≈ 3.427
Therefore, the average value of f over the rectangle [0,6] x [0,1] is approximately 3.427.
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State the equation of the graphed function.
The equation of the graphed function is given as follows:
f(x) = x³ + 2x² - 5x - 6.
How to obtain the equation of the function?
The equation of the function is obtained considering the Factor Theorem, as a product of the linear factors of the function.
From the graph, the zeros of the function are:
x = -3.x = -1.x = 2.Hence the function is:
f(x) = a(x + 3)(x + 1)(x - 2).
In which a is the leading coefficient.
Expanding the product, we have that:
f(x) = a(x² + 4x + 3)(x - 2)
f(x) = a(x³ + 2x² - 5x - 6).
When x = 0, y = -6, hence the leading coefficient a is obtained as follows:
-6a = -6
a = 1.
Hence the function is:
f(x) = x³ + 2x² - 5x - 6.
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-34, -21, -8.5 Complete the recursively defined function to describe this sequence.
The recursive definition of the arithmetic sequence -34, -21, -8 is:
f(1) = -34.f(n + 1) = f(n) + 13.What is an arithmetic sequence?It is a sequence of values in which the difference between consecutive terms is constant and is called common difference d.
The nth term of an arithmetic sequence is given by the rule presented as follows:
\(a_n = a_1 + (n - 1)d\)
In which \(a_1\) is the first term of the sequence.
An arithmetic sequence can also be defined recursively, as follows:
\(f(1) = a_1\)f(n + 1) = f(n) + d.In this problem, the sequence is given as follows:
-34, -21, -8.
Hence the first term and the common ratio are given as follows:
First term: -34.Common ratio: 13, as each term is the previous term added to 13.Hence the recursive definition of the sequence is:
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In 1902, the yearly attendance at a major league baseball park was 3.4 × 105 people. One hundred years later, the yearly attendance was 1.7 × 106 fans. How many times greater was the attendance in 2002 than in 1902?
Answer:
5 times greater hope this helps
To make green paint, 3 parts yellow paint are mixed with 2 parts blue paint. Janis has 12 L of blue
paint. How much yellow paint does she need? Explain.
Answer:
jain has 3 blue paints the boys has 2 blue paints jain needs them
Guys I need your help
Using Venn diagram, It is found that value of x is equal to 15.
What is the unitary method?The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.
We have been given that 50 students study at least one of the subjects geography (G), mathematics (M) and history (H).
Also 18 study only mathematics. 19 study two or three of these subjects.
23 study geography.
G + M - (x + 7) = 23 + 18 -(x + 7) = 19
23 + 18 -(x + 7) = 19
41 - x - 7 = 19
x = 15
Therefore, the value of x is 5.
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Of men that attended a party,30 of them wore coats,20 wore ties and 10 wore hats. there were 4 men who wore coat and tie, or tie and hat or coat and hat. 14 men wore tie only with no coat and hat. find the number of men who wore coat,tie and hat . also find the number of men who wore hat only with no coat and tie
The number of men who wore coat, tie, and hat is 2.
The number of men who wore hat only with no coat and tie is 2 by the principle of inclusion-exclusion.
Let's break down the given information using a Venn diagram.
We are given:
- Men who wore coats (C): 30
- Men who wore ties (T): 20
- Men who wore hats (H): 10
- Men who wore coat and tie, or tie and hat, or coat and hat (C ∩ T ∩ H): 4
- Men who wore tie only (T - C - H): 14
Using the principle of inclusion-exclusion, we can calculate the number of men who wore coat, tie, and hat (C ∩ T ∩ H):
C ∩ T ∩ H = (C + T + H) - (C ∪ T ∪ H) + (C ∩ T ∩ H)
C ∩ T ∩ H = (30 + 20 + 10) - (4 + 14)
C ∩ T ∩ H = 60 - 18
C ∩ T ∩ H = 42
Therefore, the number of men who wore coat, tie, and hat is 42.
Now, let's calculate the number of men who wore hat only with no coat and tie (H - C - T):
H - C - T = (H + T) - (C ∪ T ∪ H) + (C ∩ T ∩ H)
H - C - T = (10 + 20) - (4 + 14)
H - C - T = 30 - 18
H - C - T = 12
Hence, the number of men who wore hat only with no coat and tie is 12.
According to the given information, there were 42 men who wore coat, tie, and hat, and there were 12 men who wore hat only with no coat and tie.
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A student said that 42% of 78 is 45. Is this answer reasonable? Explain.
whats the sample response for edg
Answer:
nope
Step-by-step explanation:
.42*78 is 32.76, not 45
Answer:
42% can round to 40%, and 78 can round to 80. 40% of 80 is 32, so 42% of 78 should be about 32. 45 is much greater than 32, so the answer is not reasonable.
Step-by-step explanation:
sample responce
In the state championship, the coach of the Terrific Tumblers gymnastics team chooses Nick to compete
in the vault. Nick performs his best vault and makes a few mistakes. The judges subtract 0.75 points
from Nick's highest possible score, and he ends up with a final score of 7.95 points.
Use an equation to find Nick's highest possible score.
points
the equation to find Nick's highest possible score is y = 7.95 + 0.75 x.
We are given that:
Nick competes in a vault.
Nick performs certain mistakes.
Let the number of mistakes performed by Nick be x.
Scores subtracted from the highest possible score for mistakes = 0.75
Total scores subtracted = 0.75 x
Final score = 7.95 points
So, the equation for his highest possible scores will be:
highest possible scores = 7.95 + 0.75 x
y = 7.95 + 0.75 x
Therefore, we get that, the equation to find Nick's highest possible score is y = 7.95 + 0.75 x.
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Each year the value of a car decreases by 12% of its value at the beginning of that year. The original value of the car is $20000. Calculate the value of the car at the end of 3 years
Answer:
The value of the car at the end of 3 years will be $13707.
Step-by-step explanation:
If the original value of the car is $20000, then after the first year, the value of the car will be $20000 - (12/100)*$20000 = $17600.
After the second year, the value of the car will be $17600 - (12/100)*$17600 = $15552.
After the third year, the value of the car will be $15552 - (12/100)*$15552 = $13707.
Therefore, the value of the car at the end of 3 years will be $13707.
The number of milligrams D (ht) of a certain drug that is in a patient's bloodstream h hours after the drug is injected is given by the following function.
D(h) = 25e -0. 4
When the number of milligrams reaches 6, the drug is to be injected again. How much time is needed between injections?
Round your answer to the nearest tenth, and do not round any intermediate computations.
The time is needed between injections is 3.6 hours, i.e., the drug is to be injected again when the number of milligrams reaches 6 mg.
We have the exponential function of number of milligrams D (ht) of a certain drug that is in a patient's bloodstream h hours after the drug is injected is
\(D(h)=25 {e}^{ - 0.4 h}\)
We have to solve for h (the numbers of hours) that would have passed when the D(h) (the amount of medication in the patient's bloodstream) equals 6 mg in order to know when the patient needs to be injected again.
\(6 = 25 {e}^{ - 0.4h} \)
\( \frac{6}{25} = \frac{25}{25} {e}^{ - 0.4h} \)
\(0.24= {e}^{ - 0.4h} \)
Taking logarithm both sides of above equation , we get,
\( \ln(0.24) = \ln( {e}^{ - 0.4h)} \)
Using the properties of natural logarithm,
\( \ln(0.24) = - 0.4h\)
\( - 1.427116356 = - 0.4h\)
\(h = \frac{1.42711635}{0.4} = 3.56779089\)
=> h = 3. 6
So, after 3.6 hours, the patient needs to be injected again.
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Suppose a and b vary inversely, and b = 8 when a = 6. Write a function that models the variation and find b when a = 30.
The function that models the inverse variation is:
b = k/a
Using the given values, we can find the value of k:
8 = k/6
k = 48
Substituting the value of a = 30 into the function, we can find the value of b:
b = 48/30 = 8/5 = 1.6
In an inverse variation, two variables are related in such a way that their product remains constant. Mathematically, it can be represented as a * b = k, where k is a constant. In this case, we are given that b = 8 when a = 6. Plugging these values into the equation, we get 6 * 8 = k, which gives us k = 48.
To find b when a = 30, we substitute the value of an into the equation. Thus, b = 48/30 = 8/5 = 1.6. Therefore, when a is 30, b is 1.6.
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what is 3/18 written in simplest form? and if you could please tell me how you figured that out, thank you
Answer: 1/6.
Step-by-step explanation:
3/18 is just 1/6 because you have to divide the numerator and denominator by 3.
what is the geometric mean of 27 and 8
Answer:
\( 6 \sqrt{6} \)
Step-by-step explanation:
\( \sqrt{27 \times 8} = \sqrt{216} = \sqrt{36 \times 6} = \sqrt{36} \sqrt{6} = 6 \sqrt{6} \)
Answer:
6√6
Step-by-step explanation:
The geometric mean of numbers 27 and 8 is calculated by
-multiplying the numbers, to find the area made by a rectangle that is 27 by 8 and then
-square root the result to shape the area into a square, and find the side of the square
Geometric Mean of 27 and 8 is √(27·8)
We can simplify the square-root by writing the prime factors of the numbers 27 = 3·3·3 and 8 = 2·2·2.
√(27·8) = √(3·3·3·2·2·2) = 3·2√(3·2) = 6√6
Geometric Mean of 27 and 8 is 6√6
what fractions could be used to represent the whole numbers on this number line? Explain your reasoning
Answer:
3/3, 6/3, 18/6, 32/8, 25/5
Step-by-step explanation:
You can do many different combinations but that is just one combination you can do that equals 1, 2, 3, 4, and 5.
Write the formulas that can represent follow:
1-First formula you have a set of providers and you want to select the best two of them to do your jobs.
2-Second formula write the probability that can happen if some of the providers will get down so then he can not do the job.
1-The formula will be;C(n, 2) = n! / 2!(n - 2)! = n(n - 1) / 2, where n >= 2.
2-The probability that can happen if some of the providers will get down so then he can not do the job; P(B|A) = P(A ∩ B) / P(A) = P(B) / P(A), where P(A) ≠ 0.
Explanation:
1. Formula to represent the selection of the best two providers out of a set of providers:
In this case, we can use the combination formula which is given by;
C(n, r) = n! / r!(n - r)!
Where n represents the total number of providers and r represents the number of providers to be selected.
Since we want to select the best two providers, we can plug in n = the total number of providers and r = 2 in the formula. Therefore, the formula becomes;
C(n, 2) = n! / 2!(n - 2)!
= n(n - 1) / 2, where n >= 2.
2. Formula to represent the probability of the provider not being able to do the job:
We can use conditional probability to represent the probability of a provider not being able to do the job given that some providers are down. The formula for conditional probability is given by;
P(A|B) = P(A ∩ B) / P(B)
where A and B are two events, P(A ∩ B) is the probability that both A and B occur and P(B) is the probability that event B occurs.
In this case, let's say that the probability of a provider being down is represented by event A, while the probability of the provider not being able to do the job is represented by event B. Then we can write;
P(B|A) = P(A ∩ B) / P(A)
where P(A ∩ B) is the probability that the provider is down and cannot do the job, and P(A) is the probability that the provider is down.
The probability of A ∩ B is usually given, so we only need to calculate P(A). Therefore, the formula becomes;
P(B|A) = P(A ∩ B) / P(A)
= P(B) / P(A), where P(A) ≠ 0.
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1. First formula to select best two providers:
\(C(n, r) = n! / (r! (n - r)!)\).
2. Second formula to write the probability of providers not being able to do the job:
\(P(x) = (n C x) * p^x * (1 - p)^(n-x)\)
Solution:
Formula to represent the probability and selection of providers are as follows:
1.
First formula to select best two providers:
If you have a set of providers and you want to select the best two of them to do your jobs, you can use the combination formula.
The formula to select n elements from a set of r elements is given by the formula:
\(C(n, r) = n! / (r! (n - r)!)\),
where n = total number of providers
r = number of providers you want to select.
In this case, you want to select the best two providers from a set of n providers. Therefore, the formula to select the best two providers is:
\(C(n, r) = n! / (r! (n - r)!)\)
2.
Second formula to write the probability of providers not being able to do the job:
If some of the providers will get down so then he can not do the job, the probability of this happening can be represented by the binomial probability formula.
The binomial probability formula is given by the formula:
\(P(x) = (n C x) * p^x * qx^(n-x)\)
where n = total number of providers,
x = number of providers who cannot do the job,
p = probability of a provider getting down,
q = probability of a provider not getting down.
In this case, if some of the providers will get down, the probability of a provider getting down is given. The probability of a provider not getting down is 1 minus the probability of a provider getting down.
Therefore, the formula to write the probability of some of the providers not being able to do the job is:
\(P(x) = (n C x) * p^x * (1 - p)^(n-x)\)
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1. Constrained optimization a. (5 points) Draw a budget constraint using the following information: P
x
=$2,P
y
= $4,I=$100. Label the X-intercept, Y-intercept, and the slope of the budget constraint. b. (5 points) Suppose the MRS=Y/(2X). Solve for the optimal bundle of X and Y. c. ( 3 points) Label the optional bundle "A" that you found in part b on the graph above and draw an indifference curve that shows the optimal bundle. d. (5 points) Now suppose that the income decreases to $80. Draw the new budget constraint on the graph above. What is the new optimal bundle (i.e., X
∗
= and Y
∗
= ) ? Label this point "B" and draw another indifference curve that corresponds to this optimal bundle. 2. Income pffects a. (5 points) Label the optimal bundle " A " on the graph above. Now, suppose that income decreases. Assuming that X is a normal good and Y is an inferior good, what happens to the optimal amount of X and Y after the change?
In this scenario, we have a budget constraint and an indifference curve representing preferences. By analyzing the given information, we can determine the optimal bundle of goods and how it changes with a decrease in income.
a. The budget constraint can be represented graphically. The X-intercept is found by setting Y = 0, giving us X = I/Px = 100/2 = 50. The Y-intercept is found by setting X = 0, giving us Y = I/Py = 100/4 = 25. The slope of the budget constraint is determined by the ratio of the prices, giving us -Px/Py = -2/4 = -1/2. Thus, the budget constraint line can be drawn connecting the X and Y intercepts with a slope of -1/2.
b. The optimal bundle of X and Y can be found by maximizing utility subject to the budget constraint. Given the marginal rate of substitution (MRS) of Y/(2X), we set the MRS equal to the slope of the budget constraint, -Px/Py = -1/2. Solving for X and Y, we can find the optimal bundle.
c. Labeling the optimal bundle found in part b as "A," we can draw an indifference curve passing through this point on the graph. The indifference curve represents the combinations of X and Y that provide the same level of utility.
d. If the income decreases to $80, the new budget constraint can be drawn with the same slope but a lower intercept. We can find the new optimal bundle, labeled "B," by maximizing utility subject to the new budget constraint. Similarly, we can draw another indifference curve passing through point B to represent the new optimal bundle.
If X is a normal good and Y is an inferior good, a decrease in income will generally lead to a decrease in the optimal amount of Y and an increase in the optimal amount of X. This is because as income decreases, the demand for inferior goods like Y tends to decrease, while the demand for normal goods like X remains relatively stable or may even increase. The specific changes in the optimal amounts of X and Y would depend on the specific preferences and income elasticity of the goods.
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if he rolls a non-4 on the first throw, the player is paid $5. the player is paid $10 if he rolls a 4 followed by a non-4; $20 if he rolls two 4s followed by a non-4; $30 if he rolls three 4s followed by a non-4; and $50 in all other cases. what is the expected amount paid to the player?
$7.50
The expected amount paid to the player is $7.50. This is calculated by taking the probability of each outcome multiplied by the amount paid for that outcome, and then summing them all together. The probabilities are as follows:
The expected amount paid is therefore: (0.75 x $5) + (0.0625 x $10) + (0.0039 x $20) + (0.0001 x $30) + (0.00001 x $50) = $7.50
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Use milligrams to prove that 1.989•10^27 kilograms are equal to 1.989•10 milligrams.
The weight of a substance can be measured using different units. These units include ounces, kilograms, grams, milligrams, e.t.c
It is proven mathematically that : \(1.989* 10^{27} kg = 1.989 * 10^{33} mg\)
The conversion rate from milligrams to kilograms is :
\(1 mg = 1 * 10^{-6} kg\)
To prove that \(1.989* 10^{27} kg = 1.989 * 10^{33} mg\), we make use of the conversion rate.\(1 mg = 1 * 10^{-6} kg\)
\(1.989 *10^{33} mg = ?\)
Cross Multiply
\((1.989 *10^{33} mg * 1 * 10^{-6} kg) / 1 mg\)
= \(1.989* 10^{27} kg\)
Therefore, we can boldly and mathematically say that :
\(1.989* 10^{27} kg = 1.989 * 10^{33} mg\)
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All of the following are rational numbers except____.
Answer:
3.14159
Explanation:
pi is irrational
Hope this helps!! <3
what is the answer 6u+2(u-8) - 4
Answer:
8u - 20
Step-by-step explanation:
The table shows the last holiday destination of 60 people.Holiday
destinations
Frequency | Angle in º
France
25
Spain
18
Greece
15
Other
2
Complete the table and draw a pie chart
to represent this information.
Note: Please draw your pie chart in a 'clockwise' direction from the line already drawn
and follow the order from the table (France, then Spain etc...).
The required answer are according to the following order,
a) France;
25/60 × 360/1 = 150°
b) Spain;
18/60 × 360/1 = 108°
c) Greece;
15/60 × 360/1 = 90°
d) Other;
2/60 × 360/1 = 12°
What do you mean by sum of angles?
We know that the sum of angles in a triangle is 360°. The question requires us to find the angle that corresponds to each of the given holiday destinations. We shall now proceed as follows:
The angle subtended is obtained from number of people that chose a particular location.
a) France;
25/60 × 360/1 = 150°
b) Spain;
18/60 × 360/1 = 108°
c) Greece;
15/60 × 360/1 = 90°
d) Other;
2/60 × 360/1 = 12°
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I’m having a hard time finding the answer, any help is appreciated (:
Answer:
True.
Step-by-step explanation:
It fails the vertical line test. The vertical line test checks to see if any inputs (x values) have more than one output. In this case, they do.
The amounts of nicotine in a certain brand of cigarette are normally distributed with a meank of 0.946 g and standard deviation of 0.289 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine In what range would you expect to find the middle 68% of amounts of nicotine in these cigarettes (assuming the mean has not changed)? Between and If you were to draw samples of size 41 from this population, in what range find the middle 68% of most average amounts of nicotine in' would you expect to the cigarettes in the sample? Between and Enter your answers rounded to 3 decimal places_
We would expect to find the middle 68% of the average amounts of nicotine in a sample of size 41 to be between approximately 0.901 g and 0.991 g by using properties of the normal distribution.
To find the range in which you would expect to find the middle 68% of amounts of nicotine in these cigarettes, we can use the properties of the normal distribution.
Given:
Mean (μ) = 0.946 g
Standard deviation (σ) = 0.289 g
For a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. Therefore, we can expect the middle 68% of amounts of nicotine to fall within the range:
μ ± σ
Substituting the given values:
0.946 ± 0.289
To calculate the range, we have:
Lower bound = 0.946 - 0.289 ≈ 0.657 g
Upper bound = 0.946 + 0.289 ≈ 1.235 g
Therefore, we can expect to find the middle 68% of amounts of nicotine in these cigarettes to be between approximately 0.657 g and 1.235 g.
Now, if we were to draw samples of size 41 from this population, the standard deviation of the sample mean (also known as the standard error) can be calculated as:
Standard error (SE) = σ / √n
where σ is the population standard deviation and n is the sample size.
Substituting the given values:
SE = 0.289 / √41 ≈ 0.045 g
To find the range in which we would expect to find the middle 68% of the sample means, we multiply the standard error by 1 to capture approximately 68% of the data, giving us:
Lower bound = μ - SE ≈ 0.946 - 0.045 ≈ 0.901 g
Upper bound = μ + SE ≈ 0.946 + 0.045 ≈ 0.991 g
Therefore, we would expect to find the middle 68% of the average amounts of nicotine in a sample of size 41 to be between approximately 0.901 g and 0.991 g.
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Solve
1. 3x(4-9)+7x-5=303
2. 5(2x+3)+12x=17
3. 7(4x-4)-20=38
1. 12x - 27x + 7x - 5 = 303
- 15x + 7x - 5 = 303
- 8x = 303 + 5
-8x = 308
x = - 38.5
2. 10x + 15 + 12x = 17
22x + 15 = 17
22x = 17 - 15
22x = 2
x = 0.0909090909
3.28x - 28 - 20 = 38
28x - 48 = 38
28x = 38 + 48
28x = 86
x = 3.07
find the radius of convergence, r, of the series. [infinity] xn 5 2n! n = 2
For an infinite power series, \(f(x)=∑_{n = 1}^{∞} \frac{n² x^{n}}{5^n n!} \\ \), the radius of convergence, r, of this series where limit is zero, is equals to the R = ∞.
An infinite power series, \(∑_{n=1 }^{∞} a_n(x−b)^n\\ \), the interval of convergence of this series is a set of numbers (b−R,b+R) for which the series converges. The value R is called the radius of convergence. The formula of radius of Convergence by ratio test is
\(\frac{1}{R} = \lim_{n→ \infty} |\frac{ a_{n + 1}}{a_n} | = l\\ \)
series converges if l < 1 series diverges if l > 1We have a infinite series defined as
\(f(x)=∑_{n = 1}^{∞} \frac{n² x^{n}}{5^n n!} \\ \)
here, \(a_n = \frac{n²}{5^n n!}\)
\(a_{n+1} = \frac{(n + 1)²}{5^{n +1} (n+1)!}\). Using the above formula, \(l = \lim_{n→ \infty} |\frac{\frac{(n + 1)²}{5^{n +1} (n+1)!}}{ \frac{n²}{5^n n!}} | \\ \)
\( = \lim_{n→ \infty} {\frac{(n + 1)²}{5^{n +1} (n+1)!}}×\frac{5^n n!} { {n}^{2}} \\ \)
\(= \lim_{n→ \infty} \frac{(n + 1)²}{5(n+1) n²} \\ \)
\(= \lim_{n→ \infty} \frac{(n + 1)}{5 n²}\\ \)
\(= \lim_{n→ \infty} \frac{(1 + \frac{1}{n})}{5 n} \\ \) = 0
Since, this limit is zero,i.e., l = 0 < 1. Thus, the ratio test is satisfied for all x and our series converges for all x. Hence , R= ∞ and the interval of convergence is (−∞,∞).
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