PLEASE HELP DUE TODAY!!!

List the liquid mixtures from most sense to least dense using evidence and reasoning:

1) 1/2 cup of water
2) 1/2 cup of water + 2 tablespoons of salt
3) 1/2 cup of water + 2 tablespoons of sugar
4) 1/2 cup of water + 2 tablespoons of flour​

acid and base.

A base is a chemical that removes hydrogen ions from water by releasing hydroxide ions (OH-), whereas an acid produces hydrogen ions (H+) when it dissolves in water. Acids have a low pH, while bases have a high pH, and are sometimes viewed as the two extremes of a pH scale. An acid and a base can react to neutralise one another and produce water and salt when they are together. We refer to this as an acid-base reaction. The pH scale, which spans from 0 (extremely acidic) to 14 (very basic or alkaline), with 7 being neutral, measures the concentration of hydrogen ions in a solution.

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Answer:

Liquid

Explanation:

We have three states of matter. Solid, liquid and gaseous.





Answer:

94.15

Explanation:

The given mass of KOH is 0.591 g and it is dissolved in 7.50 L of water. The pH of a solution can be found by using the formula pH = 14 – pOH.

"What is the pOH of a solution prepared by dissolving 0.591 g of KOH(s) in 7.50 L of water?" is as follows:The pOH of the solution prepared by dissolving 0.591 g of KOH(s) in 7.50 L of water is 0.455.The balanced equation for the dissolution of KOH is:KOH(s) → K⁺(aq) + OH⁻(aq)The molar mass of KOH is 56.11 g/mol.

Number of moles of KOH = 0.591 g / 56.11 g/mol = 0.0105 molThe number of moles of OH⁻ ions present in solution is equal to the number of moles of KOH, which is 0.0105 mol.pOH = -log[OH⁻]= -log(0.0105) = 1.98pH = 14 – pOH = 14 - 1.98 = 12.02The pOH of the solution prepared by dissolving 0.591 g of KOH(s) in 7.50 L of water is 0.455.

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Given

P1 = 1 Atm ( at stp)

V1 = 3.00 L

V2 = 3.20 L

P2 = ?

We know that,

at constant temperature

P1V1 = P2V2

1 × 3 = 3.2 × P2

P2 = 3/3.2

P2 = 0.9375 Atm

pressure at 3.2 L is 0.9375 Atm.

Answer:

Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. ...

Physical state of the reactants and surface area. ...

Temperature. ...

Presence of a catalyst.

Answer:

It represents the noble gas that precedes the period before Potassium.

Explanation:

Period before potassium is 3, the noble gas in that period is Ar (Argon). So when condensing the electron configuration of Potassium, Argon can account for 18 electrons instead of writing out 18 electrons in full form from 1s2, 2s2 etc.

1.  The enthalpy change for the reaction 2SO₂(g) + O₂(g) → 2SO₃(g) the enthalpies of reaction are S(s) + O₂(g) → SO₂(g) ΔH= −297kJ and 2S(s) + 3O₂(g) → 2SO₃(g) ΔH = − 791 k J is -494 kJ..

2. The correct statement is the sign of heat (q) is positive when heat is absorbed by a system (Option A).

1. To calculate the enthalpy change for the reaction 2SO₂(g) + O₂(g) → 2SO₃(g), we need to use Hess's Law, which states that the enthalpy change for a reaction is equal to the sum of enthalpy changes for each step of the reaction.

First, we need to reverse the equation for the formation of SO₂:

SO₂(g) → S(s) + O₂(g)   ΔH = 297 kJ

This gives us:

S(s) + O₂(g) → SO₂(g)   ΔH = +297 kJ

Next, we need to multiply the equation for the formation of SO₃ by 2 and reverse it:

2SO₃(g) → 2S(s) + 3O₂(g)   ΔH = +791 kJ

2S(s) + 3O₂(g) → 2SO₃(g)   ΔH = -791 kJ

Now, we can add the two equations to get the overall equation:

2SO₂(g) + O₂(g) → 2SO₃(g)   ΔH = -494 kJ

Therefore, the enthalpy change for the reaction 2SO2(g) + O2(g) → 2SO3(g) is -494 kJ.

2) When heat is absorbed by a system, the system gains energy and the temperature of the system increases. This results in a positive value for q, representing the heat gained by the system. Conversely, when heat is released by a system, the system loses energy and the temperature of the system decreases. This results in a negative value for q, representing the heat lost by the system.

Thus, the correct answers are

1. -494 kJ

2. A

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The brightest star in our sky is Sirius. We can infer so because it has the smallest apparent magnitude (most negative).

The correct option is (a) Sirius's dog collar

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Answer:

Without the respiratory system your blood would be useless. The circulatory and respiratory systems work together to circulate blood and oxygen throughout the body

Explanation:

Answer:c

Explanation:

Answer:

15.1 mL of the HCl solution should be added

Explanation:

First off, let's use the definition of pH to find the desired number of H⁺ moles:

pH = -log[H⁺]

2.80 = -log[H⁺]

= [H⁺]

[H⁺] = 1.58 x 10⁻³ M

Then we use the definition of Molarity [C=n/V]:

[H⁺] = 1.58 x 10⁻³ M = molesH⁺ / 1.00 L

molesH⁺ =  1.58 x 10⁻³

So in the end there needs to be 1.58 x10⁻³ moles of H⁺ to achieve the desired pH.

Now let's calculate the added amounts of HCl and NaOH

mL HCl = 100 - 84 = 16 mL = 0.016 L

mL NaOH = 100 - 88 = 12 mL = 0.012 L

mol HCl = 0.016 L * 7.00x10⁻² M = 1.12x10⁻³ mol HCl = mol H⁺

mol HCl = 0.012 L * 5.00x10⁻² M = 6.0x10⁻⁴ mol NaOH = mol OH⁻

OH⁻ reacts with H⁺, producing water. So the moles of H⁺ remaining in the solution are:

1.12x10⁻³ - 6.0x10⁻⁴ = 5.2x10⁻⁴ mol H⁺

This means that the moles of H⁺ that we need to add are:

1.58x10⁻³ - 5.2x10⁻⁴ = 1.06x10⁻³ mol H⁺

Finally we calculate the required volume of HCl:

C = n/V

7.00 x10⁻² M = 1.06x10⁻³ mol H⁺ / V

V = 0.0151 L = 15.1 mL

Answer:

phosphorus which is in group 5A is most likely to form three covalent bonds

Answer:

What happens to acid when heated? When heated, the pure 100% acid loses sulfur trioxide gas, SO3, until a constant-boiling solution, or azeotrope, containing about 98.5% H2SO4 is formed at 337°C. Hot concentrated sulfuric acid reacts with most metals and with several nonmetals, e.g., sulfur and carbon.

Explanation:

Answer:

No, because every company is out to make profit. Making of profit is not going to be possible without marketing.

Radiation interacts with matter to produce :

Ionization

Excitation

Free radicals

Chemical bonds

Radiation interacts with matter to produce the following effects:

Ionization: Radiation can ionize atoms or molecules by removing or adding electrons, creating charged particles called ions.

Excitation: Radiation can excite atoms or molecules by elevating their energy levels without ionizing them.

Free radicals: Radiation can generate free radicals, which are highly reactive species with unpaired electrons.

Chemical bonds: Radiation can break chemical bonds in molecules, leading to the formation of new compounds or fragments.

Therefore, the correct answers are:

Ionization

Excitation

Free radicals

Chemical bonds

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Theoretical yield of copper is 7.22 g when 4.25g of iron in the chemical reaction.

2Fe(s) + 3Cu2(aq.) ---->  2Fe3(aq.)  + 3Cu (s)

Molar mass of Iron (Fe) is 56g/mole.

Molar mass of copper (cu) is 63.5g/mole.

2 mole ( 2 * 56g/mole) Iron produces = 3 mole ( 3 * 63.5g/mole ) copper

Theoretical yield is the maximum amount of product that could be formed from the given amounts of reactants. The actual yield is the amount of product that is actually formed when the reaction is carried out in the laboratory. The theoretical yield is the amount of product that would be formed from a reaction if it was 100% efficient.

There are 4. 25 g of Iron .so,

4.25 g Iron produces = (3 * 63.5g / 2 * 56 g ) * 4.25 g copper

                                     = 7.22 g copper

Theoretical yield of copper is 7.22g.

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The number of different uncharged (neutral) stable hydrogen atoms which one can build is two and the similarity is that they both have a single proton while the difference is that one has a neutron while the other has zero neutron.

This is referred to as the smallest particle of an element which can exist and has subatomic particles such as proton and neutron.

The different uncharged (neutral) stable hydrogen atoms which one can build include:

From this we can infer that they both have one proton and electron and one has no neutron while the other has just one.

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The molecular formula for the unknown compound is C₄H₈O₂. Therefore, option D is correct.

Molecular formulas supply the kind and number of atoms of each element present in a molecular compound.

In many cases, the molecular formula is the similar as the empirical formula. The molecular formula of methane is CH₄ and because it contains only one carbon atom, that is also its empirical formula.

Because when you balance the combustion equation as follows:

C₄H₈O₂ + 5O₂ ⇒ 4CO₂ + 4H₂O

This is now adapting the law of combustion that means both sides have 4 carbons,8 hydrogens and 12 oxygen.

Thus, option D is correct.

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To solve this problem, we need to use the equilibrium expression for the base dissociation reaction of pyridine:

C5H5N + H2O ↔ C5H5NH+ + OH-

where Kb is the base dissociation constant for pyridine, defined as:

Kb = [C5H5NH+][OH-]/[C5H5N]

We can use the Kb value to determine the concentration of hydroxide ions produced when pyridine dissolves in water. We can assume that the initial concentration of pyridine is equal to the final concentration of pyridine, since pyridine is a weak base and only partially dissociates in water.

We can also assume that the concentration of hydroxide ions produced is much smaller than the initial concentration of pyridine, so we can neglect its contribution to the total concentration of the solution.

First, we can calculate the concentration of hydroxide ions produced by pyridine:

Kb = [C5H5NH+][OH-]/[C5H5N]

1.7 x 10^-9 = [x][x]/[0.10-x]

where x is the concentration of hydroxide ions produced by pyridine.

Simplifying the expression, we get:

x^2 / (0.10 - x) = 1.7 x 10^-9

Since x is much smaller than 0.10, we can assume that (0.10 - x) is approximately equal to 0.10:

x^2 / 0.10 = 1.7 x 10^-9

Solving for x, we get:

x = sqrt(1.7 x 10^-9 x 0.10) = 1.2 x 10^-5 M

Therefore, the concentration of hydroxide

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Answer: 3127

Explanation:

Answer:

A

Explanation:

The letter A is the correct answer

Answer:

The most simple way to identify an ionic compound is to check if the chemical compound is made of just two elements where in one element can be a metal

Explanation:

:)

Explanation:

hope the picture above help u understand I did it in step so it would be easier to understand:)

Answer:

Add copper (II) oxide (insoluble base), a little at a time to the warm dilute sulfuric acid and stir until the copper (II) oxide is in excess (stops disappearing) Filter the mixture into an evaporating basin to remove the excess copper (II) oxide. Leave the filtrate in a warm place to dry and crystallize.

The three main steps involved in producing crystals of the salt copper sulfate is listed below.

Soluble salts can be made by reacting acids with soluble or insoluble reactants.

Titration method is used if the reactants are soluble

Insoluble salts are made by precipitation reactions.

For producing crystals of the salt Copper Sulfate from copper oxide following three steps needs to be done ,

1. Copper oxide is added continuously with a spatula to the Water Bath heated  Sulfuric Acid , until it gets in excess.

2. The mixture is filtered to remove extra Copper Oxide, and then pour the filtrate (Copper sulfate solution) into an evaporating basin , where it is heated to evaporate half of the water .

3. The solution is poured into a watch glass so that all the water evaporates.

Hence we are left with blue and regularly shaped Hydrated copper sulfate crystals .

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4974.9 kJ of energy are released during the interaction between 162.5 g of O2 and 216.7 g of NH3.

The given chemical equation shows the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). The enthalpy change (ΔH) for this reaction is -1225.6 kJ per mole of O2 consumed.

To determine the energy given off by the reaction between 162.5 g of O2 and 216.7 g of NH3, we need to first determine the limiting reactant. This is the reactant that is completely consumed in the reaction and limits the amount of product formed.

To find the limiting reactant, we need to calculate the number of moles of each reactant. The molar mass of O2 is 32.00 g/mol, so 162.5 g of O2 is equivalent to 5.078 moles of O2. The molar mass of NH3 is 17.03 g/mol, so 216.7 g of NH3 is equivalent to 12.71 moles of NH3.

The stoichiometric ratio of O2 to NH3 is 5:4, meaning that for every 5 moles of O2 consumed, 4 moles of NH3 are required. From the above calculations, we can see that there is excess NH3 in this reaction since only 4.063 moles of O2 are required to react with 3.250 moles of NH3.

Therefore, the amount of O2 that reacts is 4.063 moles, and the energy given off by the reaction is:

ΔH = (-1225.6 kJ/mol) x (4.063 mol) = -4974.9 kJ

Therefore, the reaction between 162.5 g of O2 and 216.7 g of NH3 gives off 4974.9 kJ of energy.

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The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in litres.
Therefore, the molarity of the H₂CO solution is 13.30 mol/L.

In this case, we have 5.50 L of a 13.3 M H₂CO solution. To find the molarity, we need to calculate the number of moles of H₂CO and divide it by the volume of the solution.

The formula weight of H₂CO is 30.03 g/mol. To convert from molarity to moles, we multiply the molarity by the volume in liters:

13.3 mol/L × 5.50 L = 73.15 mol

So we have 73.15 moles of H₂CO in 5.50 L of solution.

Finally, to find the molarity, we divide the number of moles by the volume of the solution:

73.15 mol ÷ 5.50 L = 13.30 mol/L

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The concentration of sodium is high outside the cell (extracellular fluid) and the concentration of potassium is high inside the cell (cytoplasm).

Potassium is important for keeping the body hydrated and with sodium support cellular function (sodium-potassium (Na⁺/K⁺) pump).

The sodium-potassium pump releases three Na+ ions, while in the same time two K+ ions exit the cell. For this process one molecule of ATP is consumed.

The sodium and potassium cations move against the concentration gradients.

The sodium-potassium pump keeps a higher concentration of sodium extracellularly and a higher level of potassium intracellularly.

It is very important for many physiological processes in organism.

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