Please help! Correct answer only please! I need to finish this assignment by today.

Out of the people who have already taken their seats at a seminar, 3 people have blond hair while 6 people do not. What is the experimental probability that the next person to take a seat will have blond hair?

Simplify your answer and write it as a fraction or whole number.

P(blond) =

Step-by-step explanation:

The answer has to be 4.

4×4=16

4+4+4×4=16

Answer:

12

Step-by-step explanation:

7x4=28

40-28=12

Answer:

Hey! Ok so the answers are A.50% B.100% C.80%

Step-by-step explanation:

Just predict the number to what they're next to.

Hoped this helped Im Eve btw. Hope you have a great day and consider marking this brainliest Thank you so much if you do! ✨

The error bounds for the linear and quadratic interpolating polynomials of f(x) = sin(x), f(x) = log10(3x - 1), f(x) = sqrt(x-1), and f(x) = -2 at x = 1.4 were found to be 0.01, 0.0012, 0.000925, and 0, respectively.

f(x) = sin(x)

Using X0 = 1, X1 = 1.25, and X2 = 1.6, the linear interpolation polynomial is

P1(x) = sin(1)(x-1.25)/(1-1.25) + sin(1.25)(x-1)/(1.25-1)

= -0.419 + 1.322x

The quadratic interpolation polynomial is

P2(x) = sin(1)(x-1.25)(x-1.6)/(1-1.25)(1-1.6) + sin(1.25)(x-1)(x-1.6)/(1.25-1)(1.25-1.6) + sin(1.6)(x-1)(x-1.25)/(1.6-1)(1.6-1.25)

= 0.2307x^2 - 0.6563x + 1.0307

we need to find an upper bound M on the second derivative of sin(x) on the interval [1,1.25]. Since |sin''(x)| <= 1 for all x, we can take M = 1.

Using Theorem 3.3 with n = 1, x = 1.4, x0 = 1, x1 = 1.25, and P(x) = P1(x), we get

|E(x)| <= M / (n+1)! |(x-x0)(x-x1)|

= 1 / 2 |0.15|

= 0.075

Therefore, the absolute error in approximating sin(1.4) using linear interpolation is bounded by 0.075.

we need to find an upper bound M on the third derivative of sin(x) on the interval [1,1.6]. Since |sin'''(x)| <= 1 for all x, we can take M = 1.

Using Theorem 3.3 with n = 2, x = 1.4, x0 = 1, x1 = 1.25, x2 = 1.6, and P(x) = P2(x), we get

|E(x)| <= M / (n+1)! |(x-x0)(x-x1)(x-x2)|

= 1 / 6 |0.15*0.4|

= 0.01

Therefore, the absolute error in approximating sin(1.4) using quadratic interpolation is bounded by 0.01.

For f(x) = log10(3x - 1), we have

f(1) = log10(2) ≈ 0.3010

f(1.25) = log10(2.75) ≈ 0.4393

f(1.6) = log10(3.8) ≈ 0.5798

Using Theorem 3.3, we can find the error bounds for the linear and quadratic interpolating polynomials as follows

For degree-1 polynomial

|f(1.4) - P1(1.4)| ≤ (1.4 - 1)(1.4 - 1.25)/2 * |f''(x)|, where x is some number between 1 and 1.25.

f''(x) = d²/dx²(log10(3x - 1)) = -9/[x ln(10)(3x - 1)²], which is negative for x in (1, 1.25). So, we can take x = 1 to obtain the maximum value of |f''(x)|.

Therefore,

|f(1.4) - P1(1.4)| ≤ (1.4 - 1)(1.4 - 1.25)/2 * |-9/[1 ln(10)(3 - 1)²]|

≈ 0.0150

For degree-2 polynomial

|f(1.4) - P2(1.4)| ≤ (1.4 - 1)(1.4 - 1.25)(1.4 - 1.6)/6 * |f'''(x)|, where x is some number between 1 and 1.6.

f'''(x) = d³/dx³(log10(3x - 1)) = 243/[x ln(10)(3x - 1)⁴], which is positive for x in (1, 1.6). So, we can take x = 1.6 to obtain the maximum value of |f'''(x)|.

Therefore,

|f(1.4) - P2(1.4)| ≤ (1.4 - 1)(1.4 - 1.25)(1.4 - 1.6)/6 * |243/[1.6 ln(10)(3*1.6 - 1)⁴]|

≈ 0.0012

Hence, the absolute error in the linear interpolation is bounded by 0.0150, and the absolute error in the quadratic interpolation is bounded by 0.0012.

For f(x) = -2

To find the error bound for both approximations, we can use Theorem 3.3 with n = 1 and x = 1.4. Since f(x) is a constant function, all of its derivatives are zero, so we can take M = 0.

Using Theorem 3.3 with n = 1, x = 1.4, x0 = 1, x1 = 1.25, and P(x) = P1(x), we get

|E(x)| <= M / (n+1)! |(x-x0)(x-x1)|

= 0

Therefore, the absolute error in approximating f(1.4) using the linear interpolation polynomial P1(x) is zero. Similarly, the absolute error in approximating f(1.4) using the quadratic interpolation polynomial P2(x) is also zero.

For the function f(x) = √(x-1), we have X0 = 1, X1 = 1.25, and X2 = 1.6.

Using Theorem 3.3, the error bound for the linear interpolation polynomial P1(x) is

|f(1.4) - P1(1.4)| <= (M2/2!) * |(1.4 - 1)(1.4 - 1.25)| = (0.03333/2) * 0.15 = 0.0025

where M2 is the maximum value of the second derivative of f(x) in the interval [1, 1.6], which is M2 = 1/(4*√(1.6-1)) = 0.03333.

Hence, the absolute error in the linear interpolation of f(x) at x=1.4 is at most 0.0025.

Using Theorem 3.3, the error bound for the quadratic interpolation polynomial P2(x) is:

|f(1.4) - P2(1.4)| <= (M3/3!) * |(1.4 - 1)(1.4 - 1.25)(1.4 - 1.6)| = (0.03704/6) * 0.15 * 0.2 = 0.000925

where M3 is the maximum value of the third derivative of f(x) in the interval [1, 1.6], which is M3 = 3/(8*√(1.6-1)^5) = 0.03704.

Hence, the absolute error in the quadratic interpolation of f(x) at x=1.4 is at most 0.000925.

To know more about error bound for the approximations:

https://brainly.com/question/15077400

#SPJ4

--The given question is incomplete, the complete question is given

"  Use Theorem 3.3 to find an error bound for the approximations in Exercise 2. Reference: Theorem 3.3 Theorem 3.3 Suppose X0,X1,..., X, are distinct numbers in the interval (a, b) and f € C++![a, b]. Then, for each x in [a,b], a number € (x) (generally unknown) between X0,X].....X., and hence in (a,b), exists with f(a+h)(EC) (x – xo)(x – X) --- (x – Xa), (3.3) f(x) = P(x) + x - (n + 1)! where P(x) is the interpolating polynomial given in Eq. (3.1). Reference: Exercise 2 For the given functions f (x), let Xo = 1, X1 = 1.25, and x2 = 1.6. Construct interpolation polynomials of degree at most one and at most two to approximate f(1.4), and find the absolute error.A f(x) = sin ax B. f(x) = log10 (3x - 1) D. f(x) = √X-1 C. f(x) = -2."--

2) 20 m³ is the answer

Answer:

x = -3

Step-by-step explanation:

this slope is a straight, vertical line passing through (-3, 5)

A highway superintendent states that four bridges into a city are used in the ratio 2:3:3:4 during the morning rush hour.

A highway study of an SRS of 6000 cars indicates that main answer in 40 words and explanation in 140 words.According to the question, there are four bridges into the city, and they are used in the ratio of 2:3:3:4.

That means that for every 2 cars coming from the first bridge, there are 3 cars coming from the second and the third bridges and 4 cars coming from the fourth bridge.According to the SRS of 6000 cars, the total number of cars from the first bridge is: 2/12 * 6000 = 1000

The total number of cars from the second bridge is: 3/12 * 6000 = 1500The total number of cars from the third bridge is: 3/12 * 6000 = 1500The total number of cars from the fourth bridge is: 4/12 * 6000 = 2000

Therefore, the number of cars coming from the first, second, third, and fourth bridges are 1000, 1500, 1500, and 2000, respectively, during the morning rush hour.

To know more about morning rush  click on below link:

https://brainly.com/question/28254231#

#SPJ11

Answer:120

Step-by-step explanation:

Answer:

The length of the other two equal sides is 11.75 yards.

Step-by-step explanation:

Let's call the length of the two equal sides of the rectangular enclosure "x". We know that the total amount of fencing used is 65 yards and that two sides already use 41.50 yards of fencing.

So, we can set up the equation:

2x + 41.50 = 65

To solve for x, we first need to isolate x on one side of the equation. We can start by subtracting 41.50 from both sides:

2x = 23.50

Then, we can divide both sides by 2 to solve for x:

x = 11.75

Therefore, the length of the other two equal sides is 11.75 yards.

The phenomena of hiding distribution characteristics in a system from applications and users is known as distribution transparency. Access transparency, location transparency are some examples.

Distributed databases have the attribute of distribution transparency, which keeps consumers from knowing the internal workings of the distribution.

Thus, access transparency, location transparency are some examples of the (distribution) transparency.

To know more about the transparency, here

https://brainly.com/question/14590546

#SPJ4

Step-by-step explanation:

42086

14

12

10+

4

2

422

+ 9

2 4 6

8 10 12 14 16 x

42595

Answer:

If you are a girl in this group, you are more likely to eat cereal for breakfast than not.

Step-by-step explanation:

On Edge

Answer:

Forma exacta:

x=50/11

Answer:

x = 4, y = 5.

Step-by-step explanation:

4x-2=3y-1

y+3=3x-4

Rearranging:

4x - 3y =  1       (A)

-3x + y = -7      (B)

Multiply  B by 3:

-9x + 3y = -21   (C)
Adding A and C:

-5x = -20

x = 4

Substitute for x in equation A:

4(4) - 3y = 1

3y = 15

y = 5.

The fourth term in the pattern is 23.

The given pattern starts with the number 16 and follows the rule of dividing the previous term by 2 and then adding 12. So, to find the fourth term of the pattern, we need to apply this rule to the third term.

The first term is 16. To find the second term, we divide 16 by 2 and then add 12. This gives us the value of 20. To find the third term, we divide 20 by 2 and then add 12, which gives us the value of 22.

Now, to find the fourth term, we will apply the same rule to the third term, which is 22. So, we divide 22 by 2 and then add 12. This gives us the value of 23.

Therefore, the fourth term in the pattern is 23. We can also verify this by applying the rule to the second term. We divide 20 by 2 and then add 12, which also gives us the value of 23.

In summary, the pattern starts with 16, and each subsequent term is obtained by dividing the previous term by 2 and adding 12. The fourth term in the pattern is 23.

Learn more about :

rule of dividing : brainly.com/question/18949981

#SPJ11

Answer:

54

Step-by-step explanation:

It is the answer to this question

Wait waaaait Hol' up.

Answer:

Its 18.

The true statement is: 15 ounces < 1 pounds.

Pounds is a unit of measurement used to quantify mass or weight. It is commonly abbreviated as "lb" or "lbs". The pound is the unit of mass or weight in the customary system of measurement used primarily in the United States and some other countries. One pound is equivalent to 0.453592 kilograms (kg) in the metric system.

To see why this is true, we need to know that there are 16 ounces in 1 pound. So, 15 ounces is less than 1 pound because:

15 ounces / 16 ounces per pound = 0.9375 pounds

0.9375 pounds < 1 pound

The other statements are false:

28 ounces > 2 pounds

28 ounces / 16 ounces per pound = 1.75 pounds

1.75 pounds is greater than 2 pounds, so this statement is false.

42 ounces > 3 pounds

42 ounces / 16 ounces per pound = 2.625 pounds

2.625 pounds is greater than 3 pounds, so this statement is false.

64 ounces < 4 pounds

64 ounces / 16 ounces per pound = 4 pounds

4 pounds is equal to 4 pounds, so this statement is also false.

To know more about pounds, visit:

https://brainly.com/question/29181271

#SPJ1

Answer:

13

Step-by-step explanation:

Find y-int of table m=11-2 = 9 2 = 9 (-5)+b. 10-(-5) 15. What is the value of x in the equation shown below? 2(x + 8) - 4x = 10x + 4 solve for X.

13 pages

The value of Z, calculated using the formula Z = (\(\bar X\) - \(\mu\)) / (\(\sigma\) / √n),is approximately 2.92 when rounded to two decimal places.

To determine the value of Z using the formula Z = \((\bar x - \mu)\) / (\(\sigma\)/ √n), we can substitute the given values into the equation:

\(\bar X\) = 40

μ = 38.6

σ = 4

n = 70

Now let's calculate the value of Z using these values:

Z = (40 - 38.6) / (4 / √70)

Z ≈ 0.672

To calculate it manually, follow these keystrokes:

Calculate the numerator: 40 - 38.6 = 1.4.

Calculate the denominator: 4 / √70 ≈ 0.4781.

Divide the numerator by the denominator: 1.4 / 0.4781 ≈ 2.9245.

Using a different set of keystrokes, you can calculate the same answer:

Calculate the numerator: 40 - 38.6 = 1.4.

Calculate the square root of 70: √70 ≈ 8.3666.

Divide the denominator: 4 / 8.3666 ≈ 0.4781.

Divide the numerator by the denominator: 1.4 / 0.4781 ≈ 2.9245.

Therefore, the value of Z is approximately 2.92 when rounded to two decimal places.

Learn more about decimal here:

https://brainly.com/question/30958821

#SPJ11

Approximately 16% of students scored 90 or better on the statistics class final exam.

1. Calculate the z-score for a score of 90 using the formula:

  z = (x - μ) / σ

  where x is the score, μ is the mean, and σ is the standard deviation.

  In this case, x = 90, μ = 80, and σ = 5.

  Therefore, z = (90 - 80) / 5 = 2.

2. Using the z-score table or a calculator, find the area under the standard normal distribution curve to the right of z = 2. The table provides the cumulative probabilities or percentages.

  From the z-score table, the area to the right of z = 2 is approximately 0.0228 or 2.28%.

3. Since we want to find the percentage of students who scored 90 or better, we need to consider the area to the left of z = 2. Subtracting the area to the right of z = 2 from 1, we get:

  1 - 0.0228 = 0.9772 or 97.72%.

4. Convert the decimal to a percentage:

  0.9772 * 100 ≈ 97.72%.

5. Finally, subtract this percentage from 100 to get the percentage of students who scored 90 or better:

  100 - 97.72 ≈ 2.28%.

Therefore, approximately 16% of students scored 90 or better on the statistics class final exam.

Learn more about z-score:

https://brainly.com/question/31871890

#SPJ11

(a) The solutions to the equation cos(θ) = -1/2, with 0° ≤ θ ≤ 360°, are θ = 120° and θ = 240°.

(b) The solutions to the equation tan(θ) = -1, with 0° ≤ θ ≤ 360°, is θ = 135°.

(c) The solutions to the equation √2sin(θ) + 1 = 0, with 0° ≤ θ ≤ 360°, is θ = 315°.

(a) To solve cos(θ) = -1/2, we can look for angles where the cosine function is equal to -1/2. These angles occur at 120° and 240° in the interval [0°, 360°].

(b) To solve tan(θ) = -1, we can look for angles where the tangent function is equal to -1. The angle 45° satisfies this condition, and since the tangent function has a period of 180°, we can add 180° to find another solution at 45° + 180° = 225°. Both angles lie in the interval [0°, 360°].

(c) To solve √2sin(θ) + 1 = 0, we can isolate the sine term. Subtracting 1 from both sides gives √2sin(θ) = -1. Dividing both sides by √2 gives sin(θ) = -1/√2. The angle that satisfies this condition is 315°, and it lies in the interval [0°, 360°].

To sketch a diagram for each part, you can plot the unit circle and mark the angles mentioned above. Label the corresponding trigonometric function values on the unit circle for clarity. This visual representation will provide a clearer understanding of the solutions within the given interval.

To learn more about cosine function: -brainly.com/question/3876065

#SPJ11

The units g/cm3 and kg/m3 are both used to express the density of a material, which is a measure of its mass per unit volume. Here's how you can convert g/cm3 to kg/m3: Multiply the density in g/cm3 by a conversion factor of 10^-3. Divide the result by a conversion factor of 100^3.

The conversion between g/cm3 and kg/m3 involves multiplying the density in g/cm3 by a conversion factor that takes into account the differences in units of mass (g vs. kg) and volume (cm3 vs. m3).

For example, let's consider the density of water, which is 1 g/cm3. To convert this density to kg/m3, we multiply by 10^-3 to get 0.001 kg/g. Then, we divide by 100^3 to get the final result: 1 g/cm3 * 10^-3 kg/g / 100^3 cm^3/m^3 = 0.001 kg/g * 1/10^9 cm^3/m^3 = 0.001/10^9 kg/m^3 = 1 kg/m^3.This is how you can convert g/cm3 to kg/m3.

For more such questions on Conversion of g/cm3 to kg/m3.

https://brainly.com/question/30086429#

#SPJ11

In multiple regression analysis, the correlation among the independent variables is termed multicollinearity

Multicollinearity in a multivariate regression model refers to the correlations between two or more independent variables. Multicollinearity can lead to skewed or false results when a researcher or analyst attempts to determine how effectively each independent variable can be used to predict or understand the dependent variable in a specific statistical model.

It is the term which is generally used to describe the situation in which two or more explanatory variables in a multiple regression model have strong linear correlations with one another but not with the dependent variable. Many times, the creation of new dependent variables that are reliant on other variables can also result in multicollinearity.

Read more about multicollinearity on:

https://brainly.com/question/17216244

#SPJ4

The length and width of the rectangle is 17 cm and 13 cm .

Let's assume the width of the rectangle to be x cm.

According to the question, the length of the rectangle is 4cm longer than its width.

Therefore, the length will be (x + 4) cm.

Now, Perimeter of the rectangle will be:

Perimeter = 2(length + width)

Substituting the values of length and width in the given formula, we get:

P = 2(x + 4 + x)

i.e., P = 2(2x + 4)

i.e., P = 4x + 8                                         ...(1)

According to the question, the perimeter of the rectangle is 60cm. Substituting this value in the equation (1), we get:

4x + 8 = 60

Now, subtracting 8 from both sides, we get:

i.e., 4x = 52

And, dividing both sides by 4, we get:

i.e., x = 13

Therefore, the width of the rectangle is 13 cm.

Now, substituting the value of width in the formula, we get:

L = x + 4

i.e., L = 13 + 4

i.e., L = 17

Therefore, the length of the rectangle is 17 cm.

Hence, the dimensions of the rectangle are 13 cm x 17 cm.

To learn more about the rectangle, click here,

https://brainly.com/question/29123947

https://brainly.com/question/28993977

The depth of the water in the cone-shaped tank is increasing at a rate of approximately 1.385 meters per second.

To determine the rate at which the depth of the water is changing, we can use related rates. Let's denote the depth of the water as h(t), where t represents time. We are given that dh/dt (the rate of change of h with respect to time) is 12 m/sec, and we want to find dh/dt when h = 18 meters.

To solve this problem, we can use the volume formula for a cone, which is V = (1/3)πr^2h, where r is the base radius and h is the depth of the water. We can differentiate this equation with respect to time t, keeping in mind that r is a constant (since the base radius does not change).

By differentiating the volume formula with respect to t, we get dV/dt = (1/3)πr^2(dh/dt). Now we can substitute the given values: dV/dt = 12 m/sec, r = 26 meters, and h = 18 meters.

Solving for dh/dt, we have (1/3)π(26^2) (dh/dt) = 12 m/sec. Rearranging this equation and solving for dh/dt, we find that dh/dt is approximately 1.385 meters per second. Therefore, the depth of the water in the tank is increasing at a rate of about 1.385 meters per second.

Learn more about volume of cone here: brainly.com/question/16419032

#SPJ11

Answer Expert Verified

4.4/5

97

Golda

Ace

2.9K answers

3.5M people helped

Solution :-

Following are the population of five major cities of India according to the Census of 2011.

1) Mumbai  

a) Indian System :

1,24,42,373 - One Crore Twenty Four Lakh Forty Two Thousand Three Hundred Seventy Three.

b) International system :

12,442,373 - Twelve Million Four Hundred Forty Two Thousand Three Hundred Seventy Three.

2) Delhi  

a) Indian System :  

1,10,34,555 - One Crore Ten Lakh Thirty Four Thousand Five Hundred Fifty Five.

b) International System :

11,034,555 - Eleven Million Thirty Four Thousand Five Hundred Fifty Five.

3) Bangalore  

a) Indian System :

84,43,675 - Eighty Four Lakh Forty Three Thousand Six Hundred Seventy Five.

b) International system :

8,443,675 - Eight Million Four Hundred Forty Three Thousand Six Hundred Seventy Five.

4) Hyderabad  

a) Indian System :

67,31,790 - Sixty Seven Lakh Thirty One Thousand Seven Hundred Ninety.

b) International System :

6,731,790 - Six Million Seven Hundred Thirty One Thousand Seven Hundred Ninety.

5) Ahmedabad  

a) Indian System :  

55,77,940 - Fifty Five Lakh Seventy Seven Thousand Nine Hundred Forty.

b) International System :

5,577,940 - Five Million Five Hundred Seventy Seven Thousand Nine Hundred Forty.

Answer:

Step-by-step explanation:

Comment me if you want to help me find my lost love

Answer:

\(\huge\colorbox{pink}{✏﹏ \: 3 cm\: }\)

Step-by-step explanation:

Diameter (d) = 6 cm

Radius (r) = ?

\(r = \frac{d}{2} \\ r = \frac{6}{2} \\ r = 3 \:cm\)

⋆┈┈｡ﾟ❃ུ۪❀ུ۪❁ུ۪❃ུ۪❀ུ۪ﾟ｡┈┈⋆

Answer:

The flow rate in mL/hr for infusing 2 liters of 5% dextrose over 16 hours is 125 mL/hr.

Step-by-step explanation:

We can use the following formula to calculate the flow rate:

Flow rate (mL/hr) = Volume to be infused (mL) / Time of infusion (hr)

First, we need to convert the total volume of 2 liters to mL:

2 liters = 2000 mL

Next, we can plug in the values:

Flow rate = 2000 mL / 16 hours

Flow rate = 125 mL/hr

Therefore, the flow rate in mL/hr for infusing 2 liters of 5% dextrose over 16 hours is 125 mL/hr.

50 miles because of the miles

Answer:

it has a gradient of 1 (or x)

Step-by-step explanation: