After evaluation of the given expression, the value obtained in mixed fraction form is equal to -4 3/10.
What is an expression?If a mathematical operation includes at least two words that are connected by an operator and either comprise numbers, variables, or both, it is referred to as an expression.
The operations with reflection coefficients include adding, subtracting, multiplying, and dividing. In order to include terms into an expression, a mathematical operation like reduction, addition, multiplication, or division is used.
As per the given expression in the question,
(-5 - (-4 1/2)) × 3 + (-2 4/5)
The expression in simplified form will be,
(-5 + 9/2) × 3 - 14/5
(-10 + 9) × 3 -14/5
-3/2 - 14/5
= (-15 - 28)/10
= -43/10
It can also be written in mixed fraction form,
= -4 3/10
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What is the price of a treasury strips with a face value of $100 that matures in 11 years and has a yield to maturity of 13. 5 percent?
The price of the Treasury STRIPS with a face value of $100, a maturity of 11 years, and a yield to maturity of 13.5 percent is approximately $34.14.
To calculate the price of a Treasury STRIPS (Separate Trading of Registered Interest and Principal Securities) with a face value of $100, a maturity of 11 years, and a yield to maturity of 13.5 percent, we can use the present value formula.
The present value of a bond or security can be calculated using the following formula:
PV = F / (1 + r)^n
Where:
PV = Present value or price of the security
F = Face value of the security
r = Yield to maturity as a decimal
n = Number of periods or years to maturity
Plugging in the given values, we have:
PV = $100 / (1 + 0.135)^11
Now, let's calculate the price:
PV = $100 / (1.135)^11
PV = $100 / 2.926426
Using a calculator or software, we can find that the value is approximately:
PV ≈ $34.14
Therefore, the price of the Treasury STRIPS with a face value of $100, a maturity of 11 years, and a yield to maturity of 13.5 percent is approximately $34.14.
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On April 11, 2012, two earthquakes were measured off the northwest coast of Sumatra. The first had a magnitude of
8.6. The second had a magnitude of 8.2. By what approximate factor was the intensity of the first earthquake greater
than the intensity of the second earthquake?
M-log
M = the magnitude of an earthquake
/= the intensity of an earthquake
lo=
= the smallest seismic activity that can be measured, which is 1
Answer:
Step-by-step explanation:
The relationship between magnitude (M) and intensity (I) of an earthquake is given by:
I ~ 10^(1.5M + 4.8)
We can use this relationship to compare the intensities of the two earthquakes:
I1/I2 = (10^(1.5M1 + 4.8))/(10^(1.5M2 + 4.8))
= 10^(1.5(M1 - M2))
Substituting the given magnitudes, we get:
I1/I2 = 10^(1.5(8.6 - 8.2))
= 10^(1.5(0.4))
≈ 2.24
Therefore, the intensity of the first earthquake was approximately 2.24 times greater than the intensity of the second earthquake.
pls will heart and give 5 stars if you answer within 2-3 min
Answer:
v=Bh
12*8= 96. <---B
2 <----h
v=192
Step-by-step explanation:
I hope that helps
Solve the following system of equations graphically. y=2x-3 x+y=3 What is the solution set?
A. [(2.1))
B. {(-2, -1)]
C. {(-1,-2)]
D. {(1,2)
8. A In rectangle ABCD, AC and BD are diagonals. If m/1 = 55, find ABD.
The value of m∠ABD is equals to 125 degrees.
What is a rectangle ?
Rectangle can be defined in which opposite sides are equal.
AC and BD are diagonals of the rectangle ABCD.
Angle ABD is adjacent to angle 1 and angle ABO, where O is the intersection of diagonals AC and BD.
We know that m∠1 = 55, and we can find m∠ABO using the fact that the diagonals of a rectangle bisect each other. Since angle AOB is opposite to side AB, which is congruent to side CD, we have:
m∠ABO = 180 - m∠AOB
= 180 - (180 - m∠1) / 2
= 180 - (180 - 55) / 2
= 62.5
Therefore, we can find m∠ABD by adding m∠ABO and m∠DBO, where DBO is congruent to ABO:
m∠ABD = m∠ABO + m∠DBO
= m∠ABO + m∠ABO
= 2m∠ABO
= 2(62.5)
= 125
Hence, The value of m∠ABD is 125 degrees.
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true or false
For all events E and F , Pr(E ∪ F ) = Pr(E) + Pr(F ).
The statement "Pr(E ∪ F) = Pr(E) + Pr(F)" is generally false. The probability of the union of two events, E and F, is not always equal to the sum of their individual probabilities. It holds true only if the events E and F are mutually exclusive.
The probability of the union of two events, E and F, denoted as Pr(E ∪ F), represents the probability that at least one of the events E or F occurs. When events E and F are mutually exclusive, it means that they cannot occur simultaneously. In this case, the probability of their union is equal to the sum of their individual probabilities: Pr(E ∪ F) = Pr(E) + Pr(F).
However, if events E and F are not mutually exclusive, meaning they can occur together, then the formula Pr(E ∪ F) = Pr(E) + Pr(F) does not hold. In such cases, the formula overcounts the probability by including the intersection of the events twice. To account for the overlapping portion, we need to subtract the probability of their intersection: Pr(E ∪ F) = Pr(E) + Pr(F) - Pr(E ∩ F).
In conclusion, the equation Pr(E ∪ F) = Pr(E) + Pr(F) holds true only if events E and F are mutually exclusive. Otherwise, the formula should include the probability of their intersection as well.
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Please help me!! (Look at the photo)
Answer:
310in
Step-by-step explanation:
7×10=70
70×2=140(there are two that are the same length)
5×10=50
50×2=100(there are two that are the same length)
5×7=35
35×2=70(there are two that are the same length)
70+100=170
170+140=310
please let me know if it's correct
if a is on the right of b on a numberline
If "a" is on the right of "b" on a number line, it means that "a" has a higher numerical value than "b".
If point "a" is on the right of point "b" on a number line, it means that "a" has a greater value than "b". This is because the number line is arranged from left to right, with the smallest values on the left and the largest values on the right. Therefore, if "a" is on the right of "b", it means that "a" has a higher numerical value than "b".
It's important to note that the distance between "a" and "b" on the number line is not necessarily significant. The only thing that matters is their relative positions on the line. This means that even if "a" and "b" are very close together on the number line, if "a" is to the right of "b", then "a" is still the larger number.
In conclusion, if "a" is on the right of "b" on a number line, it means that "a" has a higher numerical value than "b". This is because the number line is arranged from left to right with the smallest values on the left and the largest values on the right.
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In this exercise, you’ll create a form that accepts one or more
scores from the user. Each time a score is added, the score total,
score count, and average score are calculated and displayed.
I ne
In this exercise, you’ll create a form that accepts one or more scores from the user. Each time a score is added, the score total, score count, and average score are calculated and displayed.
In order to achieve this, you will need to utilize HTML and JavaScript. First, create an HTML form that contains a text input field for the user to input a score and a button to add the score to a list. Then, create a JavaScript function that is triggered when the button is clicked.
To update these values, you will need to loop through the array of scores and calculate the total and count, and then divide the total by the count to get the average.
Finally, the function should display the updated values to the user. You can use HTML elements such as `` or `
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Ria’s age is x years old.Jai’s age is x/2 + 5.If Jai is elder than Amit,which of these could be the possible relation between Amit’s and Ria’s age?
Answer:
Ria is older than Amit
Step-by-step explanation:
x is ria's age
x = 1/2 x + 5
(subtract 1/2 x from both sides)
1/2 x = 5
(divide by 1/2)
x = 10
Ria is 10
x/2 + 5 is Jay's age
10/2 + 5 = 10
Ria and Jay are the same age, so if Jay is older than Amit, Ria is as well.
sarah works part time in a shop
Maris purchased a building for £10 m on 1 January 2020 and rented it out to an unassociated company. At 31 December 2020 it is estimated that the building could be sold for £10.8 m, with selling costs of £200,000. If Maris uses the fair value model, which of these statements concerning the fair value exercise for the year ended 31 December 2020 is true?
a. Gain of £600,000 to Statement of Profit or loss
b. Gain of £600,000 to Revaluation surplus and OCl
c. Gain of £800,000 to Statement of Profit or loss
d. Gain of £800,000 to Revaluation surplus and OCl
The correct answer is: c. Gain of £800,000 to Statement of Profit or loss.
Since Maris uses the fair value model, the gain from the increase in the fair value of the building is recognized in the Statement of Profit or Loss. In this case, the building's fair value increased from £10 million to £10.8 million, resulting in a gain of £800,000. Therefore, the gain of £800,000 should be recognized in the Statement of Profit or Loss.According to the fair value model, any gain or loss resulting from the change in fair value of the asset should be recognized in the financial statements. In this case, the increase in the fair value of the building is considered a gain.
Since the gain of £800,000 (the difference between the fair value of £10.8 million and the original purchase price of £10 million) is a result of the change in the asset's fair value, it should be recognized in the Statement of Profit or Loss. This gain represents the increase in the value of the building during the year.
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Katelyn ate 1/3 of an apple pie, and Chad ate 3/8 of the same pie. What fraction of the pie was eaten?
Answer:
17/24 or 0.708333
Step-by-step explanation:
hope that helps :)
the graph of f (x) and g (z) are shown. The graph of g (x) is the reflection of the graph of f (x) across the x axis. If f (x)=3(1/2)^x what is the equation of g (x)?• g(x) = -3(1/2)^x -6• g(x) = -3(1/2)^x• g(x) = 3(2)^x• g(x) = -3(2)^x• g(x) = 3(1/2)^x. -6
To reflect a function over the x-axis, you have to change the sign of the function, you can express this as:
\(g(x)=-f(x)\)We know that the function f(x) has the following formula
\(f(x)=3(\frac{1}{2})^x\)Then, after the reflection over the x-axis, the function will have the following shape:
\(\begin{gathered} g(x)=-f(x) \\ g(x)=-3(\frac{1}{2})^x \end{gathered}\)The correct option is the second one g(x)=-3(1/2)^x
Sam's basketball game team won 70% of the 30 games they played. How many games did they win
Answer:21
Step-by-step explanation:
I need help solving these
1. 1. Vocabulary What does the exponent in the expression \(5^{6}\) tell you?
Answer: it means that \(5\) is multiplied by itself \(6\) times: \(5^{6} =5*5*5*5*5*5=15625\)
1. 2. \(4*4=4^{2}=16\)
The power is \(2\) or square, notice how the geometric model is made out of dots forming a flat square.
1. 3. \(2*2*2*2=2^{3} =8\)
The power is \(3\) or cube, notice how the geometric model is a cube.
1. 4. \(9*9=9^{2}=81\)
The power is \(2\) or square, notice how the geometric model is a flat square.
2. 5. \(7^{2} =49\)
2. 6. \((-2)^{4} = -2*-2*-2*-2=4*4=16\)
2. 7. \((-2)^{5} =16*-2=-32\)
2. 8. \(-(\frac{1}{2})^{4}=-(\frac{1^{4} }{2^{4}})=-(\frac{1}{16})=-\frac{1}{6}\)
3. 9. \(81=9^{x}, \frac{81}{9} = 9,9*9=9^{2}\)
3. 10. \(100000=10^{x} , \frac{100000}{10} =10000, \frac{10000}{10}=1000, \frac{1000}{10}=100, \frac{100}{10}=10,\)
\(10*10*10*10*10=10^{5}\)
3. 11. \(-64 = -4^{x}, \frac{-64}{-4}=16, \frac{16}{-4}=-4, -4*-4*-4=-4^{3}\)
3. 12. \(10 = 10^{x}, \frac{10}{10}=1, 10*1=10 =10^{1}\)
3. 13. \(81 =3^{x}, \frac{81}{3}= 27,\frac{27}{3}=9, \frac{9}{3}=3, 3*3*3*3=3^{4}\)
3. 14. \(36=-6^{x} , \frac{36}{-6}= -6, -6*-6=(-6)^{2}\)
4. 15. Technology First week => \(3\) hits, every week => the number of hits triples, means \(3^{3}\), 5th week => hits every week * 5 = \(3^{3}*5=27*5=135\) hits.
I apologize if there's any misspelling or wrong answer.
A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then they did in the 1990s. In 1990s, the average amount of time spent playing computer games was 10. 2 hours per week. Is the amount of time greater than that for this year? ten students were surveyed and asked how many hours they spent playing video games. The test statistics is equal to 0. 45. What is the p-value?.
From the hypothesis test, it is found that the p-value of the test is of 0.6634
At the null hypothesis, we test if the mean is still the same, that is, of 10.2 hours per week, thus:
H₀ : μ = 10.2
At the alternative hypothesis, we test if the mean has increased, that is, if it is greater than 10.2 hours per week, thus:
H₀ : μ > 10.2
Ten students were surveyed, so there are 9 degree of freedom. The test statistic is t = 0.45, and it is a one-tailed test, as we are testing if the mean is greater than a value.
Thus, using a t-distribution calculator, the p-value of the test is of 0.6634
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Complete the table:
a. 1
c. 2
b. -1
d. 0
Answer:
cos0 = 1
cos90 =0
so a for the first one and d for the other
Answer:
The answer is -1
Step-by-step explanation:
:)
The values of c for which y = C is a constant solution of y' = y2 + 5y - 6 are Select the correct answer. a. 2 and 3 b.-1 and 6 c. 1 and 6 d. 1 and -6 e.
The values of c for which y = C is a constant solution of y' = y² + 5y - 6 are 1 and -6.
Option d is the correct answer.
How to determine the constant solutionsTo find out the constant solutions of the equation (1), we need to first solve it. Let's solve equation (1) using separation of variables.
Separating variables in equation (1), we get:
dy / dx = y² + 5y - 6Now, multiplying both sides by dx, we get:
dy = (y² + 5y - 6) dxIntegrating both sides, we get:
∫ dy = ∫ (y² + 5y - 6) dxy = (y³ / 3) + (5y² / 2) - 6y + C1... (2)
where C1 is the constant of integration.
We can see that equation (2) is not in the form of y = f(x), which means we can't use it to find the values of c for which y = c is a constant solution of equation (1).
To convert equation (2) into the required form, we need to first simplify it.
Let's do that.Simplifying equation (2), we get:
y (y² + 5y - 12 / 3) + C1y (y² + 5y - 12) / 3 + C1
Now, for y = c to be a constant solution of equation (1), we have:
y (y² + 5y - 12) / 3 + C1 = c
Multiplying both sides by 3, we get:
y (y² + 5y - 12) + 3C1 = 3c
Rearranging, we get:y³ + 5y² - 12y - 3c + 3C1 = 0
Now, if y = c is a constant solution of equation (1), it means that equation (1) should be equal to 0.
So, we have:
y' = 0
On substituting y = c in equation (1), we get:(dy / dx) = c² + 5c - 6= 0
Solving the above equation, we get:
c = 1 and -6
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Please help if possible :)
9514 1404 393
Answer:
(a) no
(b) no
Step-by-step explanation:
The two questions are asking essentially the same thing. There is nothing that indicates DC ≅ DB or that AC ≅ AB. One (both) of these conditions is (are) required for ΔBAC to be isosceles, so that AD is both a perpendicular bisector of BC and a bisector of angle BAC.
There is not enough information to answer either question affirmatively.
1. What is the m2<5? Explain how you know. (2 points)
2.What is the measure of the sum of the angles in a triangle? (2 points)
3. L3 is in a triangle with L4 and L5. Write and solve an equation to find the m L3. (2 points)
4. What is the measure of a straight angle? (2 points)
5. L2 is in a straight line with L1 and L3. Write and solve an equation to find the m L2 (2 points)
an element in a ring is called an idempotent if . prove that the only idempotents in an integral domain are and . find a ring with a idempotent not equal to 0 or 1.
A ring with a idempotent not equal to 0 or 1 is 3 and 4.
Make (R,+) a domain that is integral.
As a commutative ring with two elements, R, ab = 0 when either an or b are equal to zero.
If a ∈ R is an idempotent element, then a ≠ 0,a ≠ 1 will result.
\(a^{2}\) = a
We can take multiple of 1 because the same number return if we multiply 1 to any number.
\(a^{2}\) = a·1
Subtract a·1 on both side, we get
\(a^{2}\) - a·1 = 0
Taking a common
a(a -1) = 0
(a -1) = 0 or a =0
R has no zero divisors.
So, a = 1 or a = 0
As a result, the only idempotent elements in the integral domain R are 0 and 1.
A ring that is not equal to 0 or 1 and is idempotent.
A ring with respect to addition and multiplication is the set R = 0 through 5.
Let 3 ∈ R,
\(3^{2}\) = 6+3 = 0+3 = 3
Let 4 ∈ R.
\(4^{2}\) = 16 = 12+4 = 2
Hence, 3 and 4 are idempotent elements other than 0 and 1
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The complete question is:
An element x in a ring is called an idempotent if \(x^2\) = x. Prove that the only idempotents in an integral domain are 0 and 1. Find a ring with an idempotent x not equal to 0 or 1.
Find the angle between the lines whose slopes are -1 & 0
The angle between the lines with slopes -1 and 0 is 45 degrees (or π/4 radians).
How to Find the Angle between two Lines with given Slopes?To find the angle between two lines given their slopes, we can use the formula:
θ = atan(|(m1 - m2) / (1 + m1 * m2)|)
where m1 and m2 are the slopes of the two lines.
In this case, we have two lines with slopes -1 and 0.
Let's calculate the angle:
θ = atan(|(-1 - 0) / (1 + (-1) * 0)|)
= atan(|-1 / 1|)
= atan(1)
The arctangent of 1 is 45 degrees (or π/4 radians).
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Brainliest to whoever gets it right: Apply the appropriate mathematical operation to solve this occupation related problem.
Labor rate: $8.75 per hour.
Hours worked: 16
Total price of services: $224
Overhead rate: %
Answer:
37.5%
Step-by-step explanation:
Labor rate = 8.75 dollars per hour.
Hours worked = 6
Direct cost of labor = 140 dollars
Total price of services = 224 dollars
Therefore, the overheads = 84 dollars which is
84 X 100 / 224 = 37.5%
Order -3, 5, -10, 16 from least to greatest. then order the same numbers from closest to zero to farthest from zero. next, describe how your lists are similar to each other. please answer the last part cause we are in need of help plllllllllllllllllleeeeeeeeeeeeeaaaaaaaaaaaaaaase.please thank you
The similarity lies in the fact that both lists contain the same set of numbers, but their order is determined by different criteria - one based on magnitude and the other based on distance from zero.
Let's order the numbers -3, 5, -10, and 16 as requested.
From least to greatest:
-10, -3, 5, 16
The ordered list from least to greatest is: -10, -3, 5, 16.
Now let's order the same numbers from closest to zero to farthest from zero:
-3, 5, -10, 16
The ordered list from closest to zero to farthest from zero is: -3, 5, -10, 16.
Regarding the similarity between the two lists, both lists contain the same set of numbers: -3, 5, -10, and 16. However, the ordering criteria are different in each case. In the first list, we order the numbers based on their magnitudes, whereas in the second list, we order them based on their distances from zero.
By comparing the two lists, we can observe that the ordering changes since the criteria differ. In the first list, the number -10 appears first because it has the smallest magnitude, while in the second list, -3 appears first because it is closest to zero.
Overall, the similarity lies in the fact that both lists contain the same set of numbers, but their order is determined by different criteria - one based on magnitude and the other based on distance from zero.
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The top view of Jake's circular pool is shown
below. If Jake has a circular pool cover that has
a diameter of 26 feet, find the area of the pool
cover.
Answer:
216.66
Step-by-step explanation:
If the diameter is 26 feet, then the area is half of 26, which is 13.
then you find the square root of the radius which is 169.
Then you multiply 169 by pi, which is described as 3.14.
And you get 216.66, so therefore, the answer is 216.66.
f(x) = x^2 - 4x + 4 in standard from.
Answer:
Step-by-step explanation:
ax + bx +c = 0
x^2 + (-4) x = 4
Please help the question is in the photo
Answer:
SSS or SAS
Step-by-step explanation:
The order of 105cm 1m 150mm from biggest to smallest
The order of the given numbers with different units of length from biggest to smallest is given by 105cm > 1m > 150mm.
Measurement with different units are,
105cm
1m
150mm
To arrange these measurements in order from biggest to smallest,
Convert all the measurements in the same units.
Convert all of them to meters,
1 meter = 100 centimeter
To convert centimeter to meter divide it by 100 we get,
105 cm
= 105 / 100 m
= 1.05 m
And 1 m = 1 m
1 meter = 100 centimeter
1 centimeter = 10millimeter
⇒ 1meter = 1000 millimeter
To convert millimeter to meter divide it by 1000 we get,
150 mm
= 150 / 1000 m
= 0.15 m
Now, arrange them in order from biggest to smallest we get,
1.05 m, 1 m, 0.15 m
1.05 m > 1 m > 0.15 m
⇒ 105cm > 1m > 150mm
Therefore, the order of the given numbers from biggest to smallest is equal to 105cm > 1m > 150mm.
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Let F(x) = integral from 0 to x sin(3t^2) dt. Find the MacLaurin polynomial of degree 7 for F(x)
Answer:
\(\displaystyle \int^x_0\sin(3t^2)\,dt\approx x^3-\frac{27}{42}x^7\)
Step-by-step explanation:
Recall the MacLaurin series for sin(x)
\(\displaystyle \sin(x)=x-\frac{x^3}{3!}+\frac{x^5}{5!}-...\)
Substitute 3t²
\(\displaystyle \displaystyle \sin(3t^2)=3t^2-\frac{(3t^2)^3}{3!}+\frac{(3t^2)^5}{5!}-...=3t^2-\frac{3^3t^6}{3!}+\frac{3^5t^{10}}{5!}-...\)
Use FTC Part 1 to find degree 7 for F(x)
\(\displaystyle \int^x_0\sin(3t^2)\,dt\approx\frac{3x^3}{3}-\frac{3^3x^7}{7\cdot3!}\\\\\int^x_0\sin(3t^2)\,dt\approx x^3-\frac{27}{42}x^7\)
Hopefully you remember to integrate each term and see how you get the solution!