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Energy is converted between different forms- watch the video below, then describe how energy is converted when you listen to music through headphones. Your answer should include four different energy forms​

Metal extraction is a reduction process because the extracted metal is in a bound state and has a positive valence. The addition of electrons converts cations into atoms or metals.

Metal extraction is always a reductive process. Metals have positive valences in the bound state, and cations are converted to atoms or metals by the addition of electrons. So by definition it is a reductive process.

Example - Mⁿ⁺ + ne⁻ → M

Mining is the process of extracting metal ores buried deep underground. Metal ores occur in varying amounts in the Earth's crust. By extracting metals from ores, minerals in the ground can be used. Ore is very different from the finished metal you see in buildings and bridges. Ore consists of the desired metallic compounds and impurities and a geological material called gangue. The recovery of metals and their separation takes place in several main steps.

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Boyle's and Avogadro's Laws all include Gases and the constant K which is therefore denoted as option I and II.

Boyle's law states that the pressure of an ideal gas increases as its container volume decreases and it was coined by a scientist known as Robert Boyle.

Avogadro's law on the other hand states that equal volumes of gases at constant pressure and temperature tend to occupy the same number of molecules and they both involve gases and have a constant which therefore makes it the correct choice.

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Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Thus option C is correct option.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

Giant planet atmospheres have layers of clouds and aerosols (tiny liquid droplets) made from different chemicals because different chemicals condense at different temperatures.

Therefore,  option C is correct option.

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Answer:

solar energy

Explanation:

The displacement of the balloon at an altitude where the atmospheric pressure is 10.82 inHg would be 9,603.7 L

The displacement of a balloon is determined by the volume of air that it displaces.

Apply Boyle's as follows;

V₁P₁ = V₂P₂

V₂ = (V₁P₁) / P₂

Where;

The final volume is calculated as follows;

V₂ = (3473 x 29.92) / (10.82)

V₂ = 9,603.7 L

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Answer:

39.37 inches.

Explanation:

100 divided by 2.54.

To solve this, we must be knowing each and every concept related to unit conversion and its calculations. Therefore, 39.3 inches are in 1 meter.

Many times in mathematics and science conventional measuring units must be converted into alternative measurement units. This is referred to as unit conversion. It is occasionally more important when resolving a situation. To finish the computations, mathematical conversions are employed.

Assume the length and breadth of a rectangle are given in centimeters and metre, respectively. The area in sq m may then be calculated by converting cm into metre units. As a result, the idea and technique of unit conversion must be understood.

Mathematically,

1 meter = 100 cm

1 inch = 2.54 cm

1 inch = 2.54/100m

1 inch =0.0254m

1 /0.0254 inch=1m

39.3inch=1m

Therefore, 39.3inches are in 1 meter.

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The energy of the photon of light can be obtained as 6.27 * 10^-20 J.

We know that a photon has to to do with a particular unit of light. We know that light can be said to be composed of very tiny corpuscles and these corpuscles of light is what we call the photon of the light.

We can be able to us the equation that is derived by Max Plank to be able to get the value of the energy of the photon of light. Now we know that a photon of light can have an energy that is able to be obtained by;

E = hf

h = Plank's constant

f = Frequency

Then;

E = 6.6 * 10^-34 Js * 9.5 * 10^13 Hz

= 6.27 * 10^-20 J

Thus as we can see from the parameters in the question, the energy of the photon is 6.27 * 10^-20 J.

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Answer:

Heat energy will flow from the plastic sphere to the water. This is because heat energy always flows from a warmer object to a cooler object.

Explanation:

In this case, the plastic sphere has a higher temperature of 85 °C, while the water has a lower temperature of 15 °C. Therefore, heat energy will naturally flow from the plastic sphere to the water until both objects reach thermal equilibrium, where they have the same temperature. As a result, the plastic sphere will cool down and the water will warm up until they reach the same temperature.

The enthalpy change for the reaction \(C2H4(g) + H2(g) → C2H6(g)\) is -137.15 kJ/mol.

Given:C2H4(g) + H2(g) → C2H6(g)The enthalpy of formation of C2H6(g) is -84.68 kJ mol-1The enthalpy of formation of C2H4(g) is 52.47 kJ mol-1The enthalpy of formation of H2(g) is 0 kJ mol-1Hence, using Hess's Law, the enthalpy change for the reaction \(C2H4(g) + H2(g) → C2H6(g)\) can be calculated by considering the formation of reactants and products from their respective elements. It can be given as:

\($$C_2H_4 + H_2 → C_2H_6$$$$\Delta H = H_f(C_2H_6) - [H_f(C_2H_4) + H_f(H_2)]$$$$\Delta H = -84.68 - [52.47 + 0]$$$$\Delta H = -84.68 - 52.47$$$$\Delta H = -137.15 kJ/mol$$.\)

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The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer: sorry I cant help you I need the same answer

Explanation:

Answer:

b

Explanation:

INFORMATION:

We know that:

- A certain polyatomic ion contains 49 protons and 50 electrons

And we must find its net charge

STEP BY STEP EXPLANATION:

Atoms have the same number of protons and electrons, hence atoms are neutral.

Proton is positively charged and electron is negatively charged.

Since one electron is extra in the polyatomic ion, the ion must have negative charge extra.

Therefore,

total net charge of the ion

= +49 -50

= -1

So, the correct option would be C)

ANSWER:

C) –1

Answer:

The chalcogens are the elements that belong to group 16 of the modern periodic table (or the oxygen family). Chalcogens consist of five elements – oxygen, sulfur, selenium, tellurium, and polonium.

The chalcogens (ore forming) are the chemical elements in group 16 of the periodic table. This group is also known as the oxygen family. Group 16 consists of the elements oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and the radioactive elements polonium (Po) and livermorium (Lv).Explanation:

Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

\(\text{Given that,}\\ \\\text{Volume,}~V= 57 mL = 0.057 L\\\\\text{Molar concentration,}~ S = 0.17 ~mol/L\\\\\text{Number of moles,} ~ n=?\\\\S = \dfrac{n}{V} \\\\\implies n = SV = 0.17\times 0.057 =0.00969 ~mol ~ HCl\)

The answer is 290.66 mL

Explanation:

The density of any substance including styrofoam is determined by two main factors: mass (atoms in the substance) and volume (space occupied). Moreover, the volume or mass of the substance can be calculated by using the density as these variables are related. Below I show the process:

density = mass / volume

mass = density x volume

volume = mass / density

volume = 21.80 g / 0.075 g/mL

volume = 290.66 mL

The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."

Here are possible words that can be made from this jumbled word:

Sky: Referring to the atmosphere above the Earth.

Zig: Describing a series of sharp turns or angles.

Text: Referring to written or printed words.

Six: The number following five and preceding seven.

It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.

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Answer:

The chemical formula of barium phosphate is Ba3(PO4)2.

Explanation:

brainlest ples :(

Answer:

These are the nonmetals.

Step 1

The reaction here is:

4 NaCl + CO2 => 2 Na2O+ CCl4 (Don't forget to balanced it)

-----------------

Step 2

Information provided:

The number of moles of carbon dioxide (CO2) = 0.89 moles

-----

Information needed:

The molar mass of Na2O = 62 g/mol approx.

-------------------

Step 3

By stoichiometry,

Procedure:

4 NaCl + CO2 => 2 Na2O+ CCl4

1 mole CO2 --------- 2 x 62 g Na2O

0.89 moles CO2 --------- X

X = (0.89 moles CO2 x 2 x 62 g Na2O)/1 mole CO2 = 110 g approx.

Answer: 110 g of Na2O produced.

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 4.67 × 6.02 × 10²³

We have the final answer as

Hope this helps you

The oxidation number of Ag in Ag2O is +1.

In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.

Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.

In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.

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Answer:

Nitrifying bacterium such as nitrosomonas or nitrobacter, whe applied to the soil, convert free ammonia or nitrogen to nitrates through oxidation. They are a group of aerobic bacteria playing an important role in the nitrogen cycle as producers of energy from inorganic source.

The schematic diagram attached summaries the action of such bacteria.

The correct option is B.

Air molecules speed up and collide with the tire walls more often.

When a cold tire is loaded to a certain pressure, the pressure rises as the tire heats up due to friction with the road. The increase in speed and frequency of the air molecules' collisions with the tire walls causes this to happen. The air inside the tire becomes warmer due to contact with the road. Charle's law states that a rise in heat causes an increase in pressure.

The air in your tires expands more in hot weather and contracts more in cold weather, depending on the temperature. The computer in your automobile, therefore, thinks that your tires are low on air when the temperature drops. The inflation pressure in tires normally declines by 1 to 2 psi for every 10 degrees as the temperature dips.

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