please help 25 points!
Select the following statements that apply to velocity.

a. Velocity is a vector quantity.
b.Velocity is a scalar quantity.
c. Velocity is the same thing as speed.
d.Velocity is speed with net force.
e. Velocity is speed with direction.

Answer:Boiling

Explanation: If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. The most energetic particles at the surface escape from the surface of the liquid as a vapour as it gets warmer.

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

The answer will be low. An ammeter should have low resistance so it does not significantly affect the circuit's current flow while measuring it.

In a long answer, it is important to understand the concept of resistance in an ammeter. An ammeter is a device used to measure the electric current flowing through a circuit. However, the ammeter itself can affect the circuit by introducing its own resistance. This is known as the internal resistance of the ammeter.

When selecting an ammeter, it is important to choose one with a low internal resistance. This is because a high internal resistance will alter the current flowing through the circuit being measured. This alteration can result in inaccurate readings, which can cause problems in troubleshooting the circuit.


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Answer:

C

Explanation:

Prevents further damage to the network cable.

Answer:

Greta scored high in knowledge and vocabulary on the IQ test.

Explanation:

This statement highlights Greta's strengths in knowledge and vocabulary specifically, indicating that she performed well in these areas during the test. However, it does not provide information about her overall IQ score or her performance in other cognitive domains that may have been assessed in th

The equivalent capacitance of the circuit​ is Ceq = 1.2 uf

The ability of an element or circuits to receive and hold fuel inside the form of an electric charge is known as capacitance. Devices that retain energy comprise capacitors, which are available in a variety of sizes and forms.

let the capacitors are connected in series combination then-

the equivalent capacitance

1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 = Ceq^-1

Ceq^-1 = (1/3 + 1/6 + 1/4 + 1)/12

Ceq^-1 = 4+2+3+1/12

Ceq^-1 = 10/12

Ceq = 12/10

Ceq = 1.2 uf

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The nuisance doctrine is a legal principle that says someone who moves into a place knowing there is a nuisance there cannot later complain about the nuisance and demand compensation for it.

When a homeowner lives close to an airport, it is widely accepted that homeowner should have been aware of the potential noise and other disruptions connected with living close to an airport if the airport was already operational when the homeowner moved in. Such circumstances may make it more difficult for a homeowner to successfully file a claim for compensation based on noise pollution or other airport-related problems.

A stronger case might be made for compensation based on increased noise pollution and other negative effects caused by the airport if a homeowner moved into the neighbourhood before the airport was established and had no knowledge of or reasonable expectation of its construction. This is due to the fact that instead of "coming to the nuisance," they encountered a change in their surroundings after already settling down.

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Answer:

help please

A lamp is marked 1.8w in normal brightness it carries a

The statement "The lower-case letter m or c is used to designate the nature of the surface in the source region and hence the humidity characteristics of the air mass" is true beacause the letters 'm' and 'c' are used to denote the moisture content and temperature characteristics of air masses.

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Answer:

is a

Explanation:

A block of aluminum has a volume of 15.0 ml and a mass of 50.5 g. the density is: 3.36 g/ml

To solve this problem the density formula and the procedure that we have to use is:

d = m/v

Where:

Information about the problem:

Applying the density formula we get:

d = m/v

d = 50.5 g/15.0 ml

d= 3.36 g/ml

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

What is volume?

It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.

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Answer:

1) Used in optical instruments such as telescopes.

2) Used to form mirages

Explanation:

1) Perhaps the simplest example of this is the astronomical refractor telescope with a right-angle eyepiece holder. Astro scopes mostly point at things high in the sky, but it is inconvenient to place your eye low to look up through the scope, so the light path is bent 90 degrees just before the eyepiece. This can be done with a mirror, but using a simple 45 degree prism (internal angles 45, 45, and 90 degrees) will do the 90 degree bend more efficiently.

2) So when a light pass from cold air to hot air light tends to bend from its path which is known as refraction. As the light get refracted it reaches to a point where the light tends to form 90 degree angle.

Answer:

Explanation:

Gain  of kinetic energy + work done by friction = loss of potential energy

= 1 / 2 m ( 25² - 8² ) + work done by friction = m x 9.8 x ( 12 + 12 )

= .5 x 100 x ( 625 - 64 ) + work done by friction = 100 x 9.8 x 24

28050 + work done by friction = 23520

work done by friction = -4530 J

The volume occupied by the 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K is 12.6 L.

Mass of argon, m = 24.2 g

Pressure, P = 1.23 atm

Temperature, T = 318 K

We need to find the volume occupied by the argon gas.

The volume occupied by a gas can be calculated using the ideal gas law, PV = nRT,

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

We can rearrange this equation to solve for V:

V = nRT/P

We know the mass of argon, so we can calculate the number of moles using the molar mass of argon:

Ar molar mass = 39.948 g/moln = m/M = 24.2 g / 39.948 g/mol = 0.6069 mol

Now we can substitute the given values into the equation for V and solve for V:

V = (0.6069 mol)(0.08206 L atm/mol K)(318 K)/(1.23 atm) = 12.6 L

Therefore, the volume occupied by the 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K is 12.6 L.

The volume occupied by the 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K is 12.6 L.

We used the ideal gas law to calculate the volume of argon gas. We first calculated the number of moles of gas from the mass of argon, and then substituted the given values into the equation for V. The final answer is 12.6 L.

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Answer:

none

Explanation:

~both of them show to the nearest metre.

~millimeter has (mm) unit eg 0.7mm

0.76cm is the correct answer

bcoz after Mili metre there is centi metre so option c is correct

\(\frak{\huge{Mark \: me \: brainliest}}\)

The correct statement is: The girl is doing no work on the ball because the ball is not displaced.

The girl is not doing any work on the ball because the ball is not displaced. The ball does not move when the girl holds it in place. When a force is applied to an object, work is said to have been done. In order for work to be done, the object must move. The formula for work is:

Work = Force x Distance.

It implies that for work to be done, there must be a net displacement of an object in the direction of force applied.

The correct statement which describes whether a girl holding a ball in the same position is doing work on the ball is "The girl is doing no work on the ball because the ball is not displaced." The ball is at rest, so no displacement occurs. Therefore, the girl is not doing any work on the ball because work requires a net displacement of an object.

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Answer:

Explanation:

People should care about sexual harassment for many reasons. such as, sexual harassment is a very serious and touchy topic. Sexual harassment should not be tolerated and can ruin many peoples mental health.

A significant role is played by (b) Connecticut in the origination of the Chester White pig breed.

The breed was developed by Samuel Waring, a farmer from Chester, Connecticut, in the early 19th century. Waring selectively bred white pigs with excellent meat quality and maternal traits, resulting in the establishment of the Chester White breed.

The pigs were known for their large size, durability, and adaptability to various climates. Over time, the Chester White breed gained popularity across the United States, particularly in the Midwest and Northeast regions. While other states, such as Pennsylvania and New Jersey, also had involvement in pig breeding, Connecticut holds a prominent place in the breed's origin and development.

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In Activity 2-2, there will be a generated electric current in the coil due to the induced EMF when the coil is pulled away from the north pole of the magnet.

1. The magnetic field through the coil will change as the coil moves further away from the magnet's north pole. This change in magnetic field induces an electromotive force (EMF) in the coil according to Faraday's Law.

2. As the coil moves away from the north pole of the magnet, the direction of the induced EMF will be such that it opposes the change in a magnetic field. This is in accordance with Lenz's Law.

3. As a result, an electric current will be generated in the coil due to the induced EMF. The direction of the current will be determined by the right-hand rule, with the thumb pointing in the direction of the induced EMF and the fingers curling in the direction of the current.

4. The magnitude of the induced EMF and the resulting current will decrease as the coil moves further away from the magnet's north pole. This is because the rate of change in the magnetic field will decrease with distance.

In summary, when the coil is pulled away from the north pole of the magnet in Activity 2-2, an induced EMF and electric current will be generated in the coil. The magnitude of the induced EMF and current will decrease as the coil moves further away from the magnet's north pole.

Therefore, in Activity 2-2, there will be a generated electric current in the coil due to the induced EMF when the coil is pulled away from the north pole of the magnet.

Here is the complete question:

Activity 2-2: Coil Moving Near a Magnet

1. Mount the magnet close to the coil so the magnet can't move.

2. When the coil is connected to the meter in exactly the same way as in Activity 2-1 make observations to test Prediction 2-2. Start or end with one pole of the magnet near the center of the coil.

What do you predict in activity 2-2 when the coil is pulled away from the north pole of the magnet?

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The position of the mass as a function of time (in seconds) is given by the formula: y = -0.10 cos (9.96t) + 0.05m, where y is the position of the mass at a given time t in meters, and m is the initial displacement from equilibrium.

The reason that the coefficient of the cosine function is negative is because the mass is initially pulled down 5.0 cm before being released. This means that its initial position is below the equilibrium position, which is why the cosine function is used. If the mass had been pulled up and released, the sine function would have been used instead.

The coefficient of the cosine function is 9.96 because it is equal to the frequency of the motion, which is given by the formula: f = 1 / (2π) √(k/m), where f is the frequency of the motion in hertz, k is the spring constant in newtons per meter, and m is the mass in kilograms. Plugging in the given values, we get:

f = 1 / (2π) √(10 N/m / 5 kg)

= 1.58 Hz.

This is the frequency at which the mass oscillates up and down. The period of the motion is given by the formula: T = 1 / f = 0.63 s, which is the time it takes for the mass to complete one full cycle of motion (from its maximum displacement in one direction to its maximum displacement in the other direction and back again).

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Answer:

a. 5.23 m/s² b. 44.23 N

Explanation:

a. What is the centripetal acceleration of the  hammer?  

The centripetal acceleration a = rω² where r = radius of circle and ω = angular speed.

Now r = length of chain = 1.4 m and ω = 0.595 rev/s = 0.595 × 2π/s = 3.74 rad/s.

So a = rω²

= 1.4 m × (3.74 rad/s)²

= 5.23 m/s²

b. What is the tension in the chain?

The tension in the chain, T = ma where m = mass of hammer = 8.45 kg and a = centripetal acceleration of hammer = 5.23 m/s². This tension is the centripetal force on the hammer.

So, T = 8.45 kg × 5.23 m/s²

= 44.23 N

The maximum electromotive force induced in the coil by the generator is 56.45 V.

emf(max) = NAB/t

where;

Substitute the given parameter and solve for maximum electromotive force induced in the coil.

Area of the loop = 0.0462 m x 0.0462 m = 0.00213 m²

emf(max) = (353 x 0.00213 x 0.991) / (13.2 x 10⁻³)

emf(max) = 56.45 V

Thus, the maximum electromotive force induced in the coil by the generator is 56.45 V.

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Answer:

expands

Explanation:

Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      \(v_{oy}\) = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = \(v_{oy}\) - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

According to the available choices, the criterion that the sleep cycle alarm clock failed to meet is "It did not solve the problem." This is because the options were shown to you.

The goal of a sleep cycle alarm clock is to assist its users in waking up at the most restorative and energising point in their natural sleep cycle. This will allow for a more revitalised and productive start to the day.

On the other hand, if the sleep cycle alarm clock was unable to properly achieve this goal and did not provide a solution to the issue of waking up feeling refreshed, then it would not match the desired requirement.

The other possibilities that were brought up, such as cost-effectiveness, availability, and safety, are examples of other criteria that could have an effect on the overall evaluation of the sleep cycle alarm clock. Despite the fact that these factors are not directly connected to the particular issue that the alarm clock is designed to address, however, they are nevertheless relevant.

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The pressure of 65.0 m under water (which is equivalent to a hydrostatic pressure of 639.3 kPa) is equivalent to 7.274 atm.

We can use the following conversion factor to convert pressure from kilopascals (kPa) to atmospheres (atm):

1 atm = 101.325 kPa

To calculate the pressure in atmospheres, divide the pressure in kPa by 101.325:

7.27 atm (rounded to two decimal places) = 739 kPa / 101.325 kPa/atm

As a result, a pressure of 65.0 m under water corresponds to a pressure of 7.27 atmospheres (atm).

This suggests that the pressure at 65.0 m depth is 7.27 times higher than the air pressure at sea level.

Because of the weight of the water above it, the pressure produced by water increases with depth.

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The pressure 65.0 m under water is approximately 7.26 atm.

To convert the pressure from kilopascals (kPa) to atmospheres (atm), we need to use the conversion factor that relates the two units. The conversion factor is 1 atm = 101.325 kPa.

Given that the pressure is 739 kPa, we can convert it to atm by dividing it by the conversion factor:

739 kPa / 101.325 kPa/atm ≈ 7.26 atm

Therefore, the pressure of 65.0 m under water is approximately 7.26 atm. This means that the pressure exerted at a depth of 65.0 m under water is equivalent to 7.26 times the atmospheric pressure at sea level.

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Answer:

The tortoise won the race by approximately \(33\; {\rm s}\).

Explanation:

Note that speed in the question is measured in meters-per-second. Apply unit conversion and ensure that times in this question are also measured in seconds:

\(\begin{aligned} &1\; {\text{hour}} + 15\; {\text{minute}} \\ =\; & 1\; {\text{hour}} \times \frac{3600\; {\rm s}}{1\; {\text{hour}}} + 15\; {\text{minute}} \times \frac{60\; {\rm s}}{1\; \text{minute}} \\ =\; & 4500\; {\rm s}\end{aligned}\).

Time required for the tortoise to finish the race:

\(\begin{aligned} \text{time} &= \frac{\text{distance}}{\text{speed}} \\ &= \frac{1000\; {\rm m}}{0.20\; {\rm m\cdot s^{-1}}} \\ &= 5000\; {\rm s}\end{aligned}\).

The time required for the hare to finish the race includes:

\(\begin{aligned} \frac{800\; {\rm m}}{2.0\; {\rm m\cdot s^{-1}}} + 4500\; {\rm s} + \frac{200\; {\rm m}}{1.5\; {\rm m\cdot s^{-1}}} \approx 5033\; {\rm s} \end{aligned}\).

Therefore, the tortoise wins the race by approximately \(5033\; {\rm s} - 5000\; {\rm s} = 33\; {\rm s}\).

The distance the car will travel before it stops is 102.4 m.

The distance traveled by the car is calculated as follows;

s = ut + ¹/₂at²

where;

substitute the given parameter and solve for distance traveled by the car.

s = (32 x 6.4) + (0.5)(-5)(6.4²)

s = 102.4 m

Thus, the distance the car will travel before it stops is 102.4 m.

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The density of the of the olive oil, given that it has a mass of 690 grams and a volume of 750 cm³ is 0.92 g/cm³

We know that density is defined as mass per unit volume. It is expressed as:

Density = mass / volume

Thus, with the above formula, we can determine the density of the oliver oil as illustrated below:

Density = mass / volume

Density of olive oil = 690 / 750

Density of olive oil = 0.92 g/cm³

Therefore, we can conclude that the density of the olive oil is 0.92 g/cm³

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