please helllllp shshsu

Answer:

Explanation:

just use the gravational force equation which is G x m of earth x m of object divided by r squared (which is radius of earth)

To increase the rate of the succinate forming fumarate you can increase the ATP and the enzyme that catalyzes this reaction

The Krebs cycle, also known as the citric acid cycle comprises a set of chemical reactions that are essential for organisms to obtain energy.

One of the steps in the cycle involves the use of succinate with a chemical formula of C4H6O4 to form fumarate or C4H4O4. This means in this reaction it is necessary to remove 2 hydrogen atoms.

This process requires two main factors:

Based on this, the reaction can be faster if there is more succinate dehydrogenase or if the energy increases.

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Answer:

the final potential energy of this system is 3U0/10

Explanation:

We are given

charge at left end  and another test charge at point p

Potential energy is given by  = \(\frac{k*Q1*Q2 }{R}\)

where k is electrostatics constant = \(9 *10^9\)

Q1 = first charge , Q2=  test charge

R= distance between charges

potential at point p

U0 = k*Q1*Q2 /3 ⇒ kq1q2 = 3U0 ..............1

now the test charge moves to point R

using Pytahgoreou theorem

R(distance) = \(\sqrt{8^2 + 6^2}\) = 10

New Potential energy

U1 = kq1*q2 / 10

substituting  kq1q2 = 3U0 from 1

U1 = 3U0/10

So this is the final potential energy of this system.

Hi there!

Ignoring friction, we know that the centripetal force experienced by the car is due to the normal force exerted by the road.

We can do a summation of forces in both the horizontal and vertical directions.

Vertical:
\(W = Mg\), force due to gravity

\(Ncos\theta\), VERTICAL component of the normal force.

\(\Sigma F_y = Ncos\theta - Mg\\\\Mg = Ncos\theta\)

Horizontal:
\(Nsin\theta = F_{Hnet}\)

The net horizontal force is equivalent to the centripetal force:
\(Nsin\theta = \frac{mv^2}{r}\)

We can solve for theta by dividing:

\(\frac{Nsin\theta = \frac{mv^2}{r}}{Ncos\theta = mg}\)

Simplify:

\(tan\theta = \frac{ \frac{v^2}{r}}{ g}\\\\tan\theta =\frac{v^2}{rg}\)

Solve:

\(\theta = tan^{-1}(\frac{v^2}{rg}) = tan^{-1}(\frac{30^2}{(1000)(9.8)}) = \boxed{5.26^o}\)

Answer: B.) HYDROPLANE

Explanation: The term hydroplane can be used to refer to a condition which usually occur during a downpour or on surfaces covered by water. It occurs when water forms a barrier or comes in between the frictional grip which occurs between the road surface and the car tyres. The contact between the car tyres and the road surface is supposed to give adequate frictional support which prevents the car from skidding or skidding uncontrollably on the road surface. However, when water comes invetween the surface, traction is lost and skidding results due to very low Coefficient of friction between the road and Tyre which was supposed to provide a firm grip between the tyres and the road surface.

When a vehicle is traveling on wet or slick roads, hydroplaning can occur. The correct answer is b) hydroplane.

When a vehicle is traveling on wet or slick roads, hydroplaning can occur. Hydroplaning happens when a layer of water builds up between the tires of the vehicle and the road surface, leading to a loss of traction.

This loss of traction can cause the vehicle to skid or slide, making it difficult to control. The tires ride on top of the water rather than maintaining contact with the road, resulting in reduced traction and control of the vehicle.

Therefore, When a vehicle is traveling on wet or slick roads, hydroplaning can occur. The correct answer is b) hydroplane.

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The net force acting on the wagon at a constant speed is 0.

The value of the force of friction acting on the wagon is 55 N.

The net force acting on the wagon is calculated by applying Newton's second law of motion as shown below.

F - Ff = ma

where;

At a constant speed, the acceleration of the wagon = 0

F - Ff = 0

F - Ff = F(net)

Thus, the net force is zero, when the speed of the wagon is constant.

The force friction acting on the wagon if the force on the wagon increased to 30 N is calculated as;

F - Ff = 0

( 30 N + 25 N ) - Ff = 0

Ff = 55 N

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Answer:

A continuous flow of negative charges (electrons) creates an electric current. The pathway taken by a electric current is a circuit.

Explanation:

Answer:

Copper, and aluminum

Explanation:

Given

A cardboard box sits on top of an asphalt driveway.

The coefficient of static friction is

and the coefficient of friction is

. The mass of the box is m=6kg and a horizontal force of F=8N is applied.

To find

The gravitational force

The frictional force

The acceleration

Explanation

The gravitational force is

The static frictional force is

Since the static frictional force is greater than the applied force so the body doesnot move. So the acceleration is zero.

However , frictional force is equal to applied force till the frictional force reaches its maximum value.

Thus the frictional force is 9N.

Conclusion

The gravitational force is 58.8 N.

The acceleration is zero.

The frictional force is 9 N.

Assume that the spring constant is -40 N/m. The force acting is then 28N for a displacement of 0.7 m. F = -kx is the formula used in Hooke's law to compute the applied force.

What exactly is displacement?

The term "displacement" refers to a shift in an object's position. It is a scalar quantity with a magnitude and direction. The symbol for it is an arrow pointing from of the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes.

Resultant displacement is what?

The shortest path between the starting and ending points is used to determine displacement, which favors straight lines over curved ones. The resultant displacement will occur when a body is travelling in two separate directions, say x and y. For the provided original pathways, it provides the shortcut paths. Here, u equals the starting speed.

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Answer:

12.5 m/s

Explanation:

v=f×lamda( I don't have the symbol)

from the question, v=?, f=5.0 Hz, lamda=2.5m

thus, v=5.0×2.5

v=12.5m/s

The applied force acting on the wagon is 3.04 N.

The direction of the applied force is east.

The net force acting on the wagon is Fa - Ff, which is equal to (2.4 kg)(1.2 m/s^2) + 1.22 N, or 3.04 N.

To determine the applied force, we need to use the equation for net force: ΣF = ma

where ΣF is the sum of all forces acting on the wagon, m is the mass of the wagon, and a is the acceleration of the wagon.

From the free-body diagram, we can see that the forces acting on the wagon are the applied force (Fa) in the direction of motion (east), and the frictional force (Ff) in the opposite direction (west):

So the net force equation becomes:

Fa - Ff = ma

Substituting the given values, we get:

Fa - 1.22 N = (2.4 kg)(1.2 m/s^2)

Simplifying and solving for Fa, we get:

Fa = (2.4 kg)(1.2 m/s^2) + 1.22 N

Fa = 3.04 N

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The distribution factor (DF) is used to distribute the load from a beam to its supports or the adjacent beams of the grid. Distribution factor of CC1 = 0.38, Distribution factor of CC2 = 0.38.

The DF of a member is the portion of the load that is transferred to the adjacent member or support. Distribution factor of member CB = 0.25, Distribution factor of member CD = 0.21We are required to calculate the distribution factor for members CC1 and CC2, given they are equal. Distribution of the load on CC1 and CC2. The load acting on member CD = 20 kN. The distribution factor of CD = 0.21. Therefore, the load transferred to member CC1 = 0.21 × 20 kN = 4.2 kNAnd, the load transferred to member CC2 = 0.21 × 20 kN = 4.2 kN. Now, let's distribute the load acting on CB.The load acting on member CB = 30 kN. The distribution factor of CB = 0.25Therefore, the load transferred to member CC1 = 0.25 × 30 kN = 7.5 kN And, the load transferred to member CC2 = 0.25 × 30 kN = 7.5 kN. We know that the loads on CC1 and CC2 are equal. Hence, the distribution factor for members CC1 and CC2 is as follows: Distribution factor of CC1 = (4.2 + 7.5) kN / 30 kN = 0.3833 ≈ 0.38Distribution factor of CC2 = (4.2 + 7.5) kN / 30 kN = 0.3833 ≈ 0.38.

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Answer:

Equilibrium is reached when demand equals supply.

Explanation:

Demand is the amount that consumers want and can buy of a certain product or service in a specific period of time and at a certain price. On the other hand, the supply is the amount that producers want and can sell of a certain product or service in a specific period of time and at a certain price.

In market equilibrium, the quantity demanded of the product or service equals the quantity supplied, so the price also equals. In other words, when market equilibrium is reached, demand and supply are the same, with their corresponding equilibrium price and quantity.

Two situations can occur:

Equilibrium is reached when demand equals supply.

In comparison to their neutral parent atom, anions are bigger and cations are smaller.

They are forced to spread out more due to electron-electron attraction. They can get closer to each other because there is less electron-electron repulsion.

Because cations contain fewer electrons than their parent atoms while maintaining the same nuclear charge, they are always smaller than those atoms. The leftover electrons are therefore held by the protons in the nucleus more tightly, and as a result, their radii are less than those of the parent atoms. With anion, this is the exact opposite.

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The speed of the sled after the second child jumps on will be 2.33 m/s.

In this problem, we can apply the conservation of momentum principle.

Before the second child jumps on the sled, the sled has a momentum of mv, where m is the mass of the sled and v is its velocity.

After the second child jumps on, the sled has a momentum of (m + m)v', where v' is the velocity of the sled after the second child has jumped on.

To apply the conservation of momentum principle, we can equate the initial momentum to the final momentum. We get:mv = (m + m)v'Substituting the values given in the problem, we get:35 kg x 3.5 m/s = (35 kg + 35 kg) x v'Solving for v', we get:v' = 2.33 m/s

Therefore, the speed of the sled after the second child jumps on will be 2.33 m/s.

Summary: A sled with a mass of 35 kg sleds down a hill and then coasts along the flat section at the bottom, where a second 35-kg child jumps on the sled as it passes by her. The speed of the sled is 3.5 m/s before the second child jumps on. The speed of the sled after the second child jumps on will be 2.33 m/s.

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1.5m/s2

F=ma

a=F/m

a=60/40

a=1.5m/s2

The acceleration of the cart is 1.5 meter per seconds square.

Given the following data:

To find the acceleration of the cart, we would use Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by the formula;

\(Acceleration = \frac{Net\; Force}{Mass}\)

Substituting the given parameters into the formula, we have;

\(Acceleration = \frac{60}{40}\)

Acceleration = 1.5 meter per seconds square.

Therefore, the cart's acceleration is 1.5 meter per seconds square.

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The speed of the ball immediately after being struck is approximately 16.24 m/s.

To find the speed of the ball immediately after being struck, we can use the impulse-momentum principle, which states that the impulse applied to an object is equal to the change in momentum of that object.

The impulse (J) is given as 8.77 Ns, and the mass of the ball (m) is 0.54 kg. The initial velocity of the ball is zero since it is initially at rest. Let's assume the final velocity of the ball is v.

The impulse (J) can be calculated as the product of force (F) and time (Δt):

J = F * Δt

Since the impulse is equal to the change in momentum (Δp), we have:

Δp = J = F * Δt

The momentum (p) of an object is given by the product of mass (m) and velocity (v):

p = m * v

Therefore, the change in momentum (Δp) is:

Δp = m * v - m * 0 (initial momentum is zero)

From the given information, we can rearrange the equation:

8.77 Ns = 0.54 kg * v

Solving for v:

v = 8.77 Ns / 0.54 kg

v ≈ 16.24 m/s

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Answer:

This question is incomplete

Explanation:

This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.

Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)

The unit for velocity (to be used here) is m/s or ms⁻¹

Answer:

the material of the phone case

The purpose of a cell phone cover is to protect your phone from impact forces. It is done by absorbing the impact of force by back cover.

What is Force ?

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s².

The case is made in such a way that, if the cell phone is dropped, the cover will absorb the kinetic energy of the falling phone by the means of deforming without transferring the impact onto the phone.

Cell phone cover is made up of rubber which can restore the forces like a spring. when u apply force to the rubber it get displaced and applied force is stored in the rubber. when cell phone drops, rubber of the cover absorbs the energy of impact. it also provides shied protection to the phone.

Hence this is how cell phone case do this.

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Given:

The distance you pushed the lawnmower is d = 50 m

The constant force applied by you is F = 60 N

The distance pushed by Carl is d' = 80 m

The constant force applied by carl is F' = 48 N

The time duration is t = 20 s

Required: To determine who generated power.

Explanation:

In order to determine who generated more power, first we need to calculate power.

The power can be calculated by the formula

Power generated by you will be

Power generated by Carl will be

The power generated by Carl is greater than the power generated by you.

Final Answer: Carl generated more power.

Answer:

Explanation:

why do you think is important to study about that different forms of precolonial literature?

Answer:

Explanation:

when heat is trapped it is conducted to the trapped area and gradually heats up its surrounding

Answer:

1 Volt

Explanation:

The resistors have resistance R = 1 kΩ each = 1 x 10^3 Ω each

The current through the voltage source I= 2 mA = 2 x 10^-3 A

The resistors are in parallel, son the total resistance will be

\(\frac{1}{R_{T}}\) = \(\frac{1}{R_{1}} + \frac{1}{R_{2}}\)

\(\frac{1}{R_{T}}\) = 1/1 kΩ  + 1/1 kΩ

\(\frac{1}{R_{T}}\)  = 2/1 kΩ

\(R_{T}\) = 1 kΩ ÷ 2 = 0.5 kΩ = 500 Ω

From V = IR

where V is the voltage

I is the current

R is the resistance

substituting, we have

V = 500 x 2 x 10^-3 = 1 V   This is the voltage across each resistor

Answer: it’s 0

Explanation:

Charlize got it right

The charge of the particle q₁ has a magnitude that equals that of proton.

The given parameters:

The particle q₂ is a positive charge whose magnitude is equal to charge of proton.

A proton is a positive charge with a magnitude of 1.6 x 10⁻¹⁹ C. This charge exerts attractive force on a negative charge (electron).

Thus, the charge of the particle q₁ has a magnitude that equals that of proton.

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Answer:

Explanation:

speed of sound in 24 degrees celsius

345.48m/s

hence 345.48m/s x 3s = 1036.44m

a. Just Noticeable Difference (JND) refers to the smallest difference in stimuli that can be detected by a person. It is also known as the difference threshold. Weber's Law states that the JND is proportional to the magnitude of the stimulus.

In simpler terms, the JND is relative to the initial stimulus. For example, if you have a 10 kg weight and you add 1 kg, you will notice the difference. However, if you have a 100 kg weight and you add 1 kg, you may not notice the difference. Weber's Law helps us understand how our perception changes as the magnitude of the stimulus changes.

b. To suggest a discount using the principle of JND, we need to consider the income range and the prices of the pressure cooker. Let's assume the JND for families earning Rs. 10,000 per month is Rs. 200 and for families earning Rs. 15,000 per month is Rs. 300. Based on these values, we can calculate the discounts that would make them notice and be motivated to buy the pressure cooker.

For families earning Rs. 10,000 per month, the JND is Rs. 200. So, if we offer a discount of Rs. 200 on the 3 Litre pressure cooker priced at Rs. 1800, the new price would be Rs. 1600. This discount would be noticeable to them and may motivate them to purchase.

For families earning Rs. 15,000 per month, the JND is Rs. 300. So, if we offer a discount of Rs. 300 on the 5 Litre pressure cooker priced at Rs. 2400, the new price would be Rs. 2100. This discount would be noticeable to them and may encourage them to buy.

The justification for these discounts is that they are based on the JND principle, which ensures that the discounts are noticeable to the target audience. By offering discounts within their perception range, we can attract their attention and motivate them to make a purchase.

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Answer: 10 m/s

Explanation: I got the answer wrong, then it showed it to me