(Please can you add the whole procedure, I do not understand this topic very well and I would like to learn and understand it completely. Thank you so much!)
A 20 MHz uniform plane wave travels in a lossless material with the following features:
\( \mu_{r}=3, \quad \epsilon_{r}=3 \)
Calculate:
a)The phase constant of the wave.
b) The wavelength.
c)The speed of propagation of the wave.
d) The intrinsic impedance of the medium.
e) The average power of the Poynting vector or Irradiance, if the amplitude of the electric field Emax = 100V/m
d) If the wave reaches an RF field detector with a square area of 1 cm x 1 cm, how much power in
Watts would be read on screen?

Answers

Answer 1

In a lossless material, a uniform plane wave with a frequency of 20 MHz propagates. The material has a relative permeability (μr) of 3 and a relative permittivity (εr) of 3. We need to calculate the phase constant of the wave, the permeability, the speed of propagation.

The intrinsic impedance of the medium, the average power of the Poynting vector or Irradiance, and the power reading on an RF field detector with a specific area.

To calculate the phase constant of the wave, we can use the formula β = ω√(με), where β is the phase constant, ω is the angular frequency (2πf), μ is the permeability of the medium, and ε is the permittivity of the medium.

The wavelength can be calculated using the formula λ = v/f, where λ is the wavelength, v is the speed of propagation, and f is the frequency.

The speed of propagation can be calculated using the formula v = c / √(μrεr), where c is the speed of light in vacuum.

The intrinsic impedance of the medium can be calculated using the formula Z = √(μ/ε), where Z is the intrinsic impedance, μ is the permeability of the medium, and ε is the permittivity of the medium.

The average power of the Poynting vector or Irradiance can be calculated using the formula Pavg = 0.5 * Z * |Emax|^2, where Pavg is the average power, Z is the intrinsic impedance, and |Emax| is the maximum amplitude of the electric field.

To calculate the power reading on an RF field detector, we can use the formula Power = Irradiance * Area, where Power is the power reading, Irradiance is the average power of the Poynting vector, and Area is the area of the detector.

By applying the appropriate formulas and calculations, the values for the phase constant, wavelength, speed of propagation, intrinsic impedance, average power, and power reading can be determined.

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Related Questions

I have this bigfoot worksheet for science. It says, "When designing an experiment, which two groups must be involved?" Can you help me?

Answers

Answer:

control group and experimental group

Which of the following is a measurement of acceleration?
O 33 km/h^2
O 20 m/s
O 300 m/s north
O 780 m/s^2 north

Answers

Answer:

D

Explanation:

i did that yesterday and your welcome homie b

tonya wants to estimate what proportion of her school’s seniors plan to attend the prom. she interviews an srs of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom.

Answers

According to the information provided, it should be highlighted that the 750 seniors in the school and made up population of interest, and interest parameter is percentage of seniors who intend to attend prom.

Additionally, a strictly random sample is required in order to create a confidence interval. Additionally, the sample size should be examined to see if it adequately represents the population.Using the z crucial of 1.645, a 90% confidence interval will be built. The sample fraction in this case will be:

= 36/50 = 0.72

Q = 1 - 0.72 = 0.28

n = 50

As a result, the confidence interval will be equal to 50 squared times the combination of 0.72 and 0.28. This amounts to 0.0635.

For a big sample randomly selected among 750 seniors, the interval here on context suggests that we are 90% certain that the fraction of those who desire to attend the prom falls within the interval.

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both MA and VR do not depend on fraction TRUE/FALSE​

Answers

False. Both Mechanical Advantage (MA) and Velocity Ratio (VR) can depend on fractions when considering certain aspects of simple machines.

MA and VR are important concepts in physics that describe the performance of simple machines, such as levers, pulleys, and inclined planes. Mechanical Advantage is defined as the ratio of output force to input force. In some cases, this ratio can be represented as a fraction. For example, when using a lever with unequal arms, the ratio of the lengths of the arms can be expressed as a fraction, which affects the mechanical advantage. Velocity Ratio is the ratio of the distance moved by the effort to the distance moved by the load. In simple machines like pulleys and gear systems, the ratio of the number of teeth or the diameters of the gears or pulleys can be represented as a fraction, which impacts the velocity ratio. In summary, both MA and VR can be influenced by fractions, depending on the specific simple machine and the parameters being considered.

The term "mechanical advantage" describes how much or to what extent a force is amplified or increased by utilising a tool or a machine. It is possible to compute mechanical advantage as follows:

Height of Incline (HI) / Incline Length (LI)

Let's say I built a hedge that slopes 10 metres from point x to point y, which is the back of a truck. It's 5 metres from point y to the ground.

Suppose LI = 10 m and HI = 5 m.

10/5 = 2 is the mechanical advantage granted.

The effort distance is another name for the incline angle. According to our calculations, I saved effort by forgoing horizontal movement compared to what it would have taken to lift that object off the ground.

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compared to ida, eros, and gaspra, what was odd about mathilde?
A. It was smaller in size
B. It had a different shape
C. It had a different composition
D. It had a different color

Answers

The odd feature about Mathilde is that it had a different shape. It has all the features like Ida, Eros, and Gaspra. Thus, option D is correct.

Mathilde is a type of metal body present in the asteroid belt having an irregular shape. It is different from other asteroids because of its highly elongated and heavily cratered structure in space. It is estimated that the diameter of the Mathilde is around 50 kilometers.

Mathilde does not have any defined shape and the color is also very distinct. Due to its high carbon nature, it looks like dark black color. This type of asteroid is more prone to collisions.

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How much will an object weigh on the moon if it weighs 60 lbs on the earth?

Answers

Answer:

10lbs on the moon

Explanation:

Your weight on the Moon would only be 33 pounds. Why is your weight on the It's because of the lower gravity on the Moon. Objects on the surface of the Moon experience only 16.5% of the gravity they would experience on Earth.29-Oct-2008

name an instrument that is used to produce high pitched notes

Answers

Answer:

The smaller instruments, the violin and viola, make higher-pitched sounds, while the larger cello and double bass produce low rich sounds

\(hey \: i \: am \: new \: here \: nice \: to \: meet \: you\)

Answer:

base ,violin,cello are some

A man attached a rope to a 30 kg box of books. He pulls with a force of 120 N at an angle of 60 with the horizontal. The kinetic friction is 33 N. Find the net force acting on the box.

Answers

Answer:

\(F_{net}=27N\)

Explanation:

The forces acting on the box are:

The x-component of the pulling force \(F_{x}\) and the friction force \(F_{fr}\). We assume positive in the direction of the pulling force in the x-component.  

\(F_{net}=F_{x}-F_{fr}\)

\(F_{net}=Fcos(60)-F_{fr}\)

\(F_{net}=120cos(60)-33\)

\(F_{net}=27N\)

I hope it helps you!

as a sample of matter is heated, it’s particles…

Answers

Answer:

spread and go up

Explanation:

like water when hot gas when cold ice when warm liquid

Suppose that the car encounters a wet section of the curved roadway so that this section of the curve has a

coefficient of friction less than us. The maximum safe speed to make this turn is V1. Mark the correct

relationship between Vo and Vi.

V1 < Vo

V1 = Vo

V1 > VO

Answers

V1 = Vo . This results in the conventional equation Vo = Vidt, where Vo is the integral output signal and Vi is indeed the signal input to the integrator.

What is the required coefficient of friction to keep the vehicle on the street?

Naturally, any coefficient with friction larger than 0.141—which is the minimum number for—will prevent the car from slipping.Keep in mind that the frictional force is orthogonal to the velocity.However, it is still moving in the direction needed to counteract the motion that'd happen in the absence of friction.

Can the friction coefficient go above 1?

Yes.Because the adhesion forces between molecules are stronger when the formular is substantially polished, frictional force increases.In this situation, the friction coefficient will be higher than one.

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what was one of the first observations that hinted at limitations in newton's theory of gravity?

Answers

One of the first observations that hinted at limitations in Newton's theory of gravity was the precession of the orbit of Mercury.

Despite Newton's theory accurately predicting the orbits of the other planets, the orbit of Mercury did not match its predicted path. In the late 1800s, astronomers noticed that Mercury's orbit was shifting slightly with each revolution, causing the point where it crossed the sun's equator to slowly rotate. This phenomenon, known as precession, could not be explained by Newton's theory alone. It wasn't until Einstein's theory of general relativity that the precession of Mercury's orbit could be accurately predicted. This observation led to the realization that Newton's theory of gravity had limitations and could not fully explain the behavior of objects in space.

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Before going in for an annual physical, a 70.0-{\rm kg} person whose body temperature is 37.0{\rm ^{\circ} C} consumes an entire 0.355-{\rm liter} can of a soft drink (which is mostly water) at12.0{\rm ^{\circ} C}.

A.)What will be the person's body temperature T_final after equilibrium is attained? Ignore any heating by theperson's metabolism. The specific heat capacity of a human body is3480 {\rm J/kg \cdot K} .

B.)Is the change in the person's body temperature great enoughto be measured by a medical thermometer? (A high-quality medicalthermometer can measure temperature changes as small as0.1{\rm ^{\circ}C} or less.) yes or no

Answers

Answer:

A) The person's body temperature T_final after equilibrium is attained = 36.85°C

B) The change in the person's temperature after equilibrium is attained = 0.15°C

A high-quality medical thermometer can measure temperature changes as small as 0.1°C, hence, YES, it would detect the minute drop by 0.15°C too.

Explanation:

If we assume that the soft drink has the same density as water (since it is stated in the question that it is mostly water).

Density of water = 1 g/mL = 1 kg/L

Ignoring any heating by the person's metabolism,

A) So, heat lost by the human body = heat gained by the soft drink as it attains thermal equilibrium with the human body

Let the final temperature of the human body + soft drink set up be T

Heat lost by the human body = mCΔT

m = mass of the human body = 70.0 kg

C = Specific heat capacity of the human body = 3480 J/kg.K

ΔT = Temperature change of the human body = 37 - (Final temperature) = 37 - T

Heat lost by the body = 70 × 3480 × (37 - T)

= (9,013,200 - 243,600T) J

Heat gained by soft drink = mCΔT

m = mass of the soft drink = density × volume = 1 × 0.355 = 0.355 kg

C = specific heat capacity of the soft drink = specific heat capacity of the soft drink = 4182 J/kg.K

ΔT = (final temperature) - 12 = (T - 12)

Heat gained by the soft drink = 0.355 × 4182 × (T - 12) = (1,484.61T - 17,815.32) J

heat lost by the human body = heat gained by the soft drink as it attains thermal equilibrium with the human body

(9,013,200 - 243,600T) = (1,484.61T - 17,815.32)

9,013,200 + 17,815.32 = 1,484.61T + 243,600T

9,031,015.32 = 245,084.61T

T = (9,031,015.32/245,084.61)

= 36.8485614825 = 36.85°C

B) The change in the person's temperature = 37 - 36.85 = 0.15°C

A high-quality medical thermometer can measure temperature changes as small as 0.1°C, hence it would detect the minute drop by 0.15°C too.

Hope this Helps!!!

The equilibrium temperature is required and to find whether the temperature change can be measured by a thermometer is required.

The temperature is 310 K.

Yes, the thermometer can measure the temperature difference.

\(m_1\) = Mass of person = 70 kg

\(c_1\) = Specific heat of person = 3480 J/kg K

T = Equilibrium temperature

\(T_1\) = Temperature of person = \(37\ ^{\circ}\text{C}+273.15 =310.15\ \text{K}\)

\(1\ \text{L}=1\ \text{kg}\) of water

\(m_2\) = Mass of water = \(0.355\ \text{kg}\)

\(c_2\) = Specific heat of soft drink mostly water = \(4186\ \text{J/kg K}\)

\(T_2\) = Temperature of soft drink = \(12\ ^{\circ}\text{C}=285.15\ \text{K}\)

The heat equation is

\(m_1c_1(T-T_1)=m_2c_2(T_2-T)\\\Rightarrow m_1c_1T-m_1c_1T_1=m_2c_2T_2-m_2c_2T\\\Rightarrow T=\dfrac{m_2c_2T_2+m_1c_1T_1}{m_1c_1+m_2c_2}\\\Rightarrow T=\dfrac{0.355\times 4186\times 285.15+70\times 3480\times 310.15}{70\times 3480+0.355\times 4186}\\\Rightarrow T=310\ \text{K}\)

The temperature difference is \(T_1-T=310.15-310=0.15\ \text{K}=0.15\ ^{\circ}\text{C}\)

Yes, the thermometer can measure the temperature difference.

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in the bohr model of the hydrogen atom, how does the energy difference between the n = 4 and n = 3 orbitals compare to the energy difference between the n = 3 and n = 2 orbitals?

Answers

In the Bohr model of the hydrogen atom, the energy difference between the n=4 and n=3 orbitals is less than the energy difference between the n=3 and n=2 orbitals. This is due to the fact that as the distance between the electron and the nucleus decreases, the energy of the electron increases, and vice versa.

The energy levels in the Bohr model are given by the equation E = (-13.6 eV/n^2), where n is the principal quantum number. Therefore, as the principal quantum number decreases, the energy levels get closer together, resulting in a greater energy difference between the n=3 and n=2 orbitals than between the n=4 and n=3 orbitals.

It is important to note that the Bohr model is a simplified representation of the hydrogen atom and does not accurately describe the behavior of multi-electron atoms. A more accurate description of the behavior of electrons in atoms is provided by the quantum mechanical model.

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At time t = 0, a static object at position x = 0 starts to move such that its position x(t) satisfies the equation
d^2x/dt^2 + dx/dt = te^-t
Using Laplace Transforms, determine the function x(t)

Answers

Based on the above illustration, the required function is `x(t) = t²e⁻ᵗ / 2`.

Given: The equation is, `d²x/dt² + dx/dt = te⁻ᵗ`.

Required:

Find `x(t)` using Laplace Transforms.

Let us apply the Laplace transform to both sides of the equation.

d²x/dt² → s² X(s) - s x(0) - x'(0)dx/dt → s X(s) - x(0)x(0) is 0 as the object starts from rest.

Putting the given value, `d²x/dt² + dx/dt = te⁻ᵗ` in the Laplace transform of the equation, we get (s² X(s) - s x(0) - x'(0)) + (s X(s) - x(0)) = 1 / (s + 1)²

On solving the above equation for `X(s)`, we get `X(s) = 1 / (s + 1)³`

On taking the inverse Laplace transform, we get, `x(t) = t²e⁻ᵗ / 2`

Hence, the required function is `x(t) = t²e⁻ᵗ / 2`.

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What is the mass of the block of iron that has a density of 7.87 g/cm3. Its volume measurements are 2 cm x 10 cm x 5 cm.

Answers

I believe that the mass is 787 but I’m not 100% certain.

2. A boulder is shoved by a bulldozer at 2.3m/s and falls from a
72m high cliff. How far from the base of the cliff will the
boulder land?

Answers

The boulder will land approximately 81.3 meters from the base of the cliff.

How far from the base of the cliff will the boulder land?The distance from the base of the cliff that the boulder will land can be calculated using the equation d=ut+1/2at^2, where d is the distance, u is the initial velocity, t is the time, and a is the acceleration due to gravity (9.8m/s^2).Using the given values, the equation becomes d=2.3t+1/2(9.8t^2). By solving for t, and inserting the value into the equation, the distance from the base of the cliff is calculated to be 577.4m.This type of calculation is called projectile motion. Projectile motion is the motion of an object traveling in a curved path, such as a ball or a boulder, due to the combined forces of gravity and inertia.In this particular example, the only force acting on the boulder is gravity, so it follows a parabolic path, reaching its highest point at the top of the cliff before falling back down to the base.The equation used to calculate the distance of the boulder is based on the principles of kinematics, which is the study of motion and the forces that cause it.

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The momentum of a 3000 kg truck is 6.36 x 104 kg·m/s. At what speed is the truck traveling? m/s


472

19,080

2.1

21.2

19.6

24.5

Answers

Answer:

21.2m/s

Explanation

Given data

P=6.36 x 10⁴kg·m/s.

M=3000kg

From the momentum expression

P=mv

v=p/m

Substitute

v=63600/3000

v=21.2m/s

Hence the Velocity is 21.2m/s

The speed of the truck is 21.2 m /s

Momentum is the product of the mass of the object and the velocity of the object. Therefore,

p = mv

where

m  = mass

v = velocity

m = 3000 kg

p = 6.36 x 104 kg·m/s.

lets find the velocity

6.36 x 10⁴  = 3000 × v

v = 6.36 x 10⁴ / 3000

v = 21.2 m / s

The speed of the truck is 21.2 m /s

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Question: Point B is 25 km due east of point A. Starting from point A, a camel walks 20 km in
a direction 15° south of east and then walks 8.0 km due north. What is the resultant angle?

Answers

Resultant angle; θ = 25.59°  

This question is dealing with bearings and distance.

We are told that from point A, the camel walks 20 km at 15° in the south of east direction.

Thus, d_s,e = 20 km

Resolving along the horizontal east direction gives; d_e = 20 cos 15

d_e = 19.32 km

Also, resolving along the vertical south direction gives; d_s = 20 sin 15

d_s = 5.18 km

Net vertical distance; d_vert = 8km - 5.18km = 2.72 km

Net horizontal distance; d_hor = 25km - 19.32 km = 5.68 km

Now, the resultant angle is given by;

tan θ = d_vert/d_hor

tan θ = 2.72/5.68

tan θ = 0.4789

θ = tan^(-1) 0.4789

θ = 25.59°

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Why did a coke ice cube melt faster than a normal ice cube?

Answers

Because of the carbonation
Carbonation is the answer

Why is 37 degrees the optimum temperature for e coli growth

Answers

E. coli has adapted to grow best at the optimum temperature range most conducive to its optimal enzymatic activity and metabolic processes, allowing for efficient and rapid growth in the human body.

37 degrees celsius is the most appropriate temperature for e. Coli boom due to the fact it's miles the temperature at which e. Coli can successfully carry out its metabolic tactics, which include protein synthesis, DNA replication, and mobile division.

E. Coli is a mesophilic bacterium, which means that it prospers at moderate temperatures commonly found inside the human frame (around 37°c). At decreased temperatures, inclusive of the ones located in refrigeration (4°c), e. Coli boom is slowed, and at better temperatures, such as those found in fever (above 40°c), e. Coli boom is inhibited or may even die.

The cause why e. Coli can develop and divide maximum efficiently at 37°c due to the specific enzymatic and metabolic pathways it possesses. Enzymes are organic catalysts that facilitate the chemical reactions important for existing processes. The enzymes in e. Coli functions optimally at this temperature variety, making an allowance for efficient nutrient uptake, electricity production, and cellular replication.

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#7. If no braking occurs, a total of how much power would be required to keep the railcar moving at 40m/s?

Answers

Once you have the resistive force value, you can simply multiply it by the velocity (40 m/s) to calculate the power required to maintain the railcar's constant speed without braking

To calculate the power required to maintain a railcar's constant speed of 40 m/s without braking, we need to consider the work done against the resistive forces acting on the railcar, such as air resistance and friction. Since power is the rate at which work is done, we can use the formula:

Power = Work / Time

The work done against the resistive forces can be represented as
Work = Force x Distance

To maintain a constant speed, the force applied to the railcar must equal the resistive force. Since we don't have specific values for the resistive force or distance, let's use a more general approach:

Power = Force x Distance / Time

Since distance/time is equal to speed (velocity), we can rewrite the formula as

Power = Force x Velocity

We already know the velocity (40 m/s), so we just need the resistive force value. Unfortunately, without more information about the railcar's size, shape, and other factors affecting resistance, we cannot determine the exact force. However, once you have the resistive force value, you can simply multiply it by the velocity (40 m/s) to calculate the power required to maintain the railcar's constant speed without braking.

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What is the wavelength in nanometers of light with a frequency of 7. 8 × 1015 hz?.

Answers

38 nm A waveform signal that is carried in space or down a wire has a wavelength,

What is wavelength?

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

The wavelength of the wave is the distance covered by it throughout a whole oscillation. A meter is the wavelength's SI unit (m).

*v=c/λ

v: 7.8 × 10^15 Hz c: 3.00*10^8 λ:?

7.8 × 10^15 Hz = 3.0010^8/λ

λ = 3.0010^8 m/s /7.8 × 10^15

λ = 3.8 10^-8

The calculated wavelength is in unit of meter. use the relationship between meter and nanometer to convert to the correct units.

3.8 10^-8 m (1nm/ 110^-9m )

= 38 nm

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The three laws dealing with the creation of various spectra are due to: A)Newton. B)Fraunhofer. C)Kirchhoff. D)Bohr. E)Einstein

Answers

The three laws dealing with the creation of various spectra are due to  (C) Kirchhoff.

The three laws dealing with the creation of various spectra are known as Kirchhoff's laws. They were formulated by German physicist Gustav Kirchhoff in the 19th century and describe the behavior of light when passing through or emitted by different materials.

Kirchhoff's laws are as follows:

1) Kirchhoff's First Law, also known as the law of thermal radiation, states that a hot, dense object (like a solid, liquid, or dense gas) emits a continuous spectrum of light. This law is associated with the work of many scientists, including Max Planck and Stefan-Boltzmann.

2) Kirchhoff's Second Law, also known as the law of emission, states that a hot, low-density gas produces an emission spectrum consisting of bright, discrete lines at specific wavelengths. This law is closely associated with the work of the German physicist Robert Bunsen and his collaborator Gustav Kirchhoff.

3) Kirchhoff's Third Law, also known as the law of absorption, states that a cool, low-density gas, when subjected to a continuous spectrum of light, absorbs specific wavelengths corresponding to its own emission spectrum. This law is essential in understanding how elements in stars and other celestial bodies can be identified based on their absorption lines in the spectrum.

While other scientists such as Newton, Fraunhofer, Bohr, and Einstein made significant contributions to the field of optics and spectroscopy, the laws specifically dealing with the creation of various spectra are attributed to Kirchhoff.

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describe photoelectric effect. group of answer choices photoelectric effect is the hypothesis that many metals emit electrons when light of high enough energy shines upon them. photoelectric effect is the observation that many metals emit electrons when light of high enough energy shines upon them. photoelectric effect is the observation that many metals absorb electrons when light of high enough energy shines upon them

Answers

The correct answer is: "Photoelectric effect is the observation that many metals emit electrons when light of high enough energy shines upon them."

The photoelectric effect is a phenomenon in which electrons are emitted from the surface of a material when it is exposed to light of a sufficiently high frequency or energy.

When light is incident on the surface of a metal, the photons of the light interact with the electrons in the metal. If the energy of the photons is greater than the work function of the metal

Which is the minimum amount of energy required to remove an electron from the metal, then electrons are emitted from the metal surface. These emitted electrons are called photoelectrons.

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The speed-time graph of a car is shown in the figure, which of the following statement is true: (figure shown in attachment)

• Car has an acceleration of 1.5 ms-2
• Car has constant speed of 7.5 ms-1
• Distance travelled by the car is 75 m
• Average speed of the car is 15 ms-1

The speed-time graph of a car is shown in the figure, which of the following statement is true: (figure

Answers

In the speed-time graph of a car in the figure, the correct statement is, the distance traveled by car is 75 m. Thus, option C is correct.

Speed is the distance traveled by an object per unit of time. In the graph, speed is taken in the Y axis, and time in the X axis. In the speed-time graph, the acceleration of an object and the distance traveled by an object can be determined. In the speed-time graph, the acceleration is obtained by taking the slope. From the figure, the speed of the car decreases, and it is called deceleration. If the car has a constant speed, the graph has a line parallel to the X-axis.

The distance traveled by car is obtained by determining the area of the figure.  The area of the figure is a triangle.

Distance = Area of the triangle = 1/2 (base×height)

                                                    = (15×10) /2

                                                    = 75m

The distance traveled by car is 75m. The ideal solution is C.

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How much power flows through a circuit with 5 amps and 120 volts?

Answers

600 watts may be your answer:)

Question 4: In a city the traffic lights on the main road are set up so that traffic lights are green for 55 seconds, red for 48 seconds, and amber for 17 seconds (the city is in California, so no one stops on amber).
(a) What is the chance that you will have to stop at a particular traffic light?
(b) Suppose that there are 10 traffic lights in the main street. What is the expected amount of time you are likely to be stopped at traffic lights if you drive all the way down the main street?

Answers

The probability of stopping at a traffic light is about 47.22%.

With 10 traffic lights, expect to be stopped for approximately 5 minutes and 45 seconds along the main street.

(a) To calculate the probability of stopping at a particular traffic light, we need to consider the cycle time of the traffic lights. The cycle time is the total time taken for one complete sequence of green, amber, and red signals. In this case, the cycle time is 55 + 17 + 48 = 120 seconds.

The probability of stopping at a particular traffic light can be calculated by dividing the red signal duration by the cycle time. Therefore, the probability is 48/120 = 0.4 or 40%.

However, in California, no one stops on amber, so we need to exclude the amber duration from the calculation. Therefore, the probability becomes 48/(55 + 48) ≈ 0.4722 or 47.22%.

(b) If there are 10 traffic lights on the main street, we can calculate the expected amount of time spent stopped at traffic lights by multiplying the probability of stopping at each traffic light by the average duration of being stopped.

The average duration of being stopped at a traffic light is the sum of the red signal duration and half of the amber signal duration. So, the average duration is (48 + 17/2) = 56.5 seconds. To find the expected amount of time stopped at traffic lights, we multiply the average duration by the number of traffic lights: 56.5 seconds * 10 = 565 seconds.

Therefore, if you drive all the way down the main street, the expected amount of time you are likely to be stopped at traffic lights is approximately 565 seconds, which is equivalent to 5 minutes and 45 seconds.

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7. What is the kinetic energy of a 3-kilogram ball that is rolling at 2 meters per second?

Answers

Answer:

6Newton meter is the answer.

Explanation:

Mass=m=3kg

Velocity=v=2m/s

Kinetic energy =K.E.=?

As we know that

K.E.=1/2mv^2

Putting the values

K.E.=1/2✖️3kg✖️(2m/s)^2

K.E.=1/2✖️3kg✖️4m^2/s^2

K.E=1/2✖️12Nm

K.E.=6Nm is your answer

Hope it will help you :)

The kinetic energy of a 3-kilogram ball that is rolling at 2 meters per second is E = 6 joules.

To find the Kinetic Energy, the given details are

Mass of the ball, m = 3 kg

Speed of the bag, v = 2 m/s

What is Kinetic Energy?An object with twice as much mass and the same speed will have twice as much kinetic energy, whereas an object with twice as much mass and the same speed will have four times as much kinetic energy.Kinetic energy is the kind of energy an object or particle has because it moves.When a net force is applied to an object, which is work that transfers energy, the object accelerates and gains kinetic energy.A moving object or particle's kinetic energy is a property that is affected by its mass as well as its motion.

The energy that is possessed due to the motion of an object is called the kinetic energy of the ball.

Its formula is given by :

E = 1/2 mv²

E = \(\frac{1}{2}\) (3)(2)²

E = 6 joules

So, the kinetic energy of the ball is 6 joules. Hence, this is the required solution.

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The general consensus is that our policymakers do not know what they are doing and are managing our economy ineffectively

Answers

Answer:

True.

This is because, from the information provided so far, it could be concluded that, the policy makers don't have any single idea of what they are doing regarding to the economy.

This could be seen in the series of poor performance of the economic indicators as shown which has lead to poor economic growth in our country.

Explanation:

A passenger aeroplane accelerates from rest along a runway. It accelerates at a uniform rate for 3.5s. At this point it reaches a speed of 84 m/s and then takes off. Calculate the acceleration of the aeroplane along the runway.

Answers

Please find attached photograph for your answer. Do comment whether it is useful or not. Mark as Brainliest if you like my answer.

A passenger aeroplane accelerates from rest along a runway. It accelerates at a uniform rate for 3.5s.
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