PLEASE ANSWER ASAP!
For her school Science ft Alyssa designs an experiment to learn more about
erosion. Her experimental set up is shown below
Using the illustration shown above, determine which of the following statements best
describes the independent variable itest variable). this experiment:



A The speed she pours the water, since it is the same for all trials.

B The amount of water she pours, because the amount she pours is the same.

C The height of the tray, because this is a change that may cause and effect on the experiment.


D The mass of sand that collects at the bottom of the tray, because this is what is being measured or observed.

Explanation:

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Among the given molecules, the polar molecule is XeF2. XeF2, or xenon difluoride, has a polar covalent bond and an asymmetrical molecular geometry, making it a polar molecule.

The polarity of a molecule is determined by the difference in electronegativity between its constituent atoms and the overall molecular geometry. In XeF2, xenon (Xe) has a lower electronegativity compared to fluorine (F). As a result, the fluorine atoms exert a greater pull on the shared electrons, creating a partial negative charge (δ-) on each fluorine atom and a partial positive charge (δ+) on the xenon atom.

Additionally, the molecular geometry of XeF2 is linear, with the two fluorine atoms on opposite sides of the central xenon atom. This arrangement leads to an asymmetrical distribution of charge within the molecule, resulting in a net dipole moment and overall polarity.

In contrast, CCl4 (carbon tetrachloride), XeF4 (xenon tetrafluoride), PBr5 (phosphorus pentabromide), and BrF5 (bromine pentafluoride) have symmetrical molecular geometries and/or symmetrical charge distributions, resulting in a net dipole moment of zero. These molecules are considered nonpolar.

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Answer:

The answer is 32. 29

Explanation:

Answer:

All are correct

Explanation:

This might be a little deceptive.  The question shows H, O and N which would designate ELEMENTS.

However, all of these can also be considered compounds and molecules as well.  BUT, they are H₂, O₂ and N₂ when they are molecules and compounds.

So it depends on the whether the question is being literal or not.

Answer:

P1V1/T1 = P2V2 / T2.

- combined gas

equation

(227×600) / 283. = (1780× P2 )/300

P2 = (300 ×227×600)/283 ×1780

P2 = 81.11

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The molecule with the highest effusion rate among the given choices (NO2, SO2, O2, and N2) would be N2 (nitrogen gas).

Explanation: Effusion rate refers to the rate at which a gas escapes or passes through a small opening or a porous barrier into an empty space or a region of lower pressure. It is a measure of how quickly gas molecules effuse, which is the process of gas particles moving from an area of higher concentration to an area of lower concentration through a small opening.

Effusion rate is influenced by several factors, including the size of the opening or barrier, the temperature of the gas, and the molar mass of the gas molecules. According to Graham's law of effusion, the effusion rate of a gas is inversely proportional to the square root of its molar mass. In other words, gases with lower molar masses effuse more rapidly than gases with higher molar masses at the same temperature.

The molecule with the highest effusion rate among the given choices (NO2, SO2, O2, and N2) would be N2 (nitrogen gas). Effusion rates are governed by Graham's Law, which states that lighter molecules effuse faster than heavier ones. Nitrogen gas has the lowest molar mass among the provided options, resulting in the highest effusion rate.

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Based on the principles of fluid mechanics and erosion, the water in the river flows faster on the outside of the bend and slower on the inside.

Meandering rivers are formed due to the lateral erosion of the riverbank, which creates a curvy path for the water to flow. This is caused by the differences in water velocity between the outside and inside bends of the river.

The above difference in velocity causes the water on the outside to exert more erosive force on the bank, leading to more erosion on the outside of the curve. The slower-moving water on the inside, by contrast, tends to deposit sediment, which can result in the formation of sandbars and other features.

Therefore, it is likely that there is more erosion on the outside of the curve in the riverbed as water flows through it.

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Answer:

2

Explanation:

Answer:

2

Explanation:

The following remains constant when water undergoes a phase change  is temperature.

The temperature remains constant during the phase change of any substances. the energy is used in the process of phase change to breaks the bonds ,since there is no increase in kinetic energy , so. there is rise in temperature. heat is used in latent heat conversion. Latent heat is the heat that absorbed or released during the phase change. temperature remains same until the phase change is completed. the phase happens with the change of heat.

Thus, The following remains constant when water undergoes a phase change is temperature.

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The electrical force between these two particles is approximately -2.3 N.

So,the correct answer is (B) -2.3 N

Coulomb’s law is given as:F=ke * q1 * q2 / d^2

Where,F = Force in Newton (N)q1 = Charge on particle 1 in Coulombs (C)q2 = Charge on particle 2 in Coulombs (C)k = Coulomb’s constant = 8.99 × 10^9 N m^2/C^2d = Distance between two particles in meters (m).

Given:e = 1.6 × 10^-19 Ck = 8.99 × 10^9 N m^2/C^2Distance between two particles, d = 10^-14 mAs given, both particles are negative charges; hence, the force between the two particles will be repulsive.

The formula to find the electric force between two negative charges is:F = -ke * q1 * q2 / d^2F = - (8.99 × 10^9 N m^2/C^2) * (1.6 × 10^-19 C) * (1.6 × 10^-19 C) / (10^-14 m)^2= - 2.304 × 10^-9 N= - 2.3 N (approximately).

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The substance in the diagram that would have a net movement out of the cell is Water.

The substance that will have to have a net movement out of the cell would need to first be in the cell. The only substances in the cell are water, starch, and glucose.

Water will be the most likely substance to have a net movement out of the cell thanks to the process of osmosis which allows water molecules to move from an area of high concentration to an area of low concentration across a semi - permeable membrane. This happens until the concentration gradient is the same across the semi - permeable membrane.

The water in the cell is 90 % which means it is 5 % more than the 85 % water in the beaker. Water would therefore move out of the cell in a net movement until the concentration is the same in the beaker and the cell.

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The antiseptic may affect the results of tests for bilirubin uric acid is Povidone-iodine.

Polyvinylpyrrolidone (povidone, PVP) and elemental iodine combine chemically to form the stable compound known as povidone-iodine. On a dry basis, it has a 9.0% to 12.0% available iodine content. H. A. Shelanski and M. V. Shelanski found this particular complex in 1955 at the Industrial Toxicology Laboratories in Philadelphia.

The compound was discovered to be less harmful to mice than tincture of iodine during in vitro tests to exhibit anti-bacterial efficacy. Clinical tests on humans revealed that the medication outperformed competing iodine formulations. Povidone-iodine was marketed right away and has since taken over as the most widely used iodine antiseptic.

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Povidone-iodine is an antiseptic that may affect the results of tests for bilirubin and uric acid. Povidone-iodine is a commonly used antiseptic that can be applied topically to the skin to reduce the risk of infection during medical procedures. However, it can also interfere with certain laboratory tests, including tests for bilirubin and uric acid.

Bilirubin is a yellow pigment that is produced when red blood cells break down, and it is excreted by the liver. Uric acid is a waste product that is produced when the body breaks down purines. Both bilirubin and uric acid can be measured through laboratory tests to help diagnose certain medical conditions.

However, povidone-iodine can interfere with these tests by reacting with the substances being tested, leading to inaccurate results. It is important for healthcare professionals to be aware of the potential for povidone-iodine to affect laboratory test results and take appropriate measures to minimize this risk, such as avoiding its use immediately prior to testing.

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Answer:

none of the above

Explanation:

those are all things that are in our solar syestem

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Answer:

5.42x10^24 atoms/1 x 1 mole/6.022x10^23

= 9.5 mol

Answer:

The magnesium atom is larger.

Explanation:

The magnesium atom is larger because it is on the left side of the Periodic Table (period 3 and group 2) where the atomic radius is larger.

Atomic radius is the distance from the center of the nucleus of an atom to the most external electron shell.

The greater the columbic attractions, the closer the protons in the nucleus are to the electrons in the outer layers, making the size of the atom smaller.

Explanation:

What would be the new volume if the pressure on 600 mL is increased from 90 kPa to 150 kPa? V = Pu V₂ = 360 mL ~ 400 mL 6.

The volume of 2.5 M solution of H₂SO₄ that is required to fully neutralize 30.0 ml of a 0.20 M naoh solution is equals to 2.4 ml.

In chemistry, neutralization is defined as a chemical reaction in which acid and a base react quantitatively with each other. We have two chemicals, H₂SO₄ acid and NaOH base. The balanced equation for the reaction is written as,

H₂SO₄+ 2NaOH → Na₂SO₄ + 2H₂O

So, in the reaction we can see that to neutralise 1 mole of NaOH, we need 0.5 moles of sulphuric acid. Now let us calculate volume of NaOH.

Molarity of NaOH solution = 0.20 M

Molarity of H₂SO₄ solution = 2.5 M

Volume of NaOH solution used to neutralize whole H₂SO₄ solution = 30.0 ml

Let the volume of H₂SO₄ solution be V ml.

Number of moles of NaOH solution

= Molarity× volume

=> Number of moles of NaOH solution

= 0.20 × 30

= 6 moles

Similarly, moles of H₂SO₄ solution = 2.5 × V

Because of neutralizing reaction, moles of NaOH solution = moles of H₂SO₄ solution

=> 2.5 × V = 6

=> V = 6/2.5 = 2.4 ml

Hence, required volume is 2.4 ml.

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It should still weigh 300g.

Explanation:

If I'm right, the Law of Conservation of Mass simply means the weight of whatever goes in will be the same when it comes out.

By using the acid – base extraction process, we can separate the given organic compounds.

A liquid-liquid extraction is a type of acid-base extraction. It usually includes differing amounts of solubility in water and an organic solvent. Any carbon-based liquid that does not dissolve well in water can be used as the organic solvent; prominent examples include ether, ethyl acetate, and dichloromethane.

Acid-base extraction is a method of purifying acids and bases from mixtures depending on their chemical characteristics by employing consecutive liquid-liquid extractions.

In this scenario, acid-base extraction is required since it is also employed to separate the two different weak acids or two weak bases with a considerable variation in their pKa (as observed in this case). In the case of acids, the considerably stronger acid with a low pKa value (here, pKa is 2) is neutralized to a salt by utilizing a weak base. Only the stronger acid is converted into a salt when the weak base reacts inefficiently with the weaker acid. The salt is then extracted into the aqueous phase while the other weakly acidic chemical stays dissolved in the organic solvent, which in this case is ether. We can now separate the aqueous and organic phases using a separatory funnel.

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There are 2 lone pairs

Given

a molecule of calcium sulfide

two valence electron of Calcium(Ca)

six valence electrons of Sulfur(S)

Required

number of lone pairs of electrons

Solution

Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound

Valence electrons are electrons used in a chemical bond

To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,

A lone pair electrons means refers to an unshared pair of electrons(not bonding to the other atoms)

Answer:

dissolving

Explanation:

The sugar can dissolve in water, the san then can be washed off and will remain

Answer:

a

Explanation:

because am pro

Gas molecules are characterized by their constant, random motion and large spacing, which allows them to move freely and independently without significant intermolecular forces. Their movement and speed are directly related to temperature, and their collisions are elastic in nature.

The movement and spacing of gas molecules can be characterized as follows:
1. Gas molecules are in constant, random motion, moving in straight lines until they collide with another molecule or the walls of their container.
2. The spacing between gas molecules is relatively large, with the distance between them being much greater than their individual sizes. This means that gas molecules are widely dispersed.
3. Due to their large spacing and constant motion, gas molecules exert negligible attractive or repulsive forces on each other, allowing them to move freely and independently.
4. Gas molecules' movement is directly related to their temperature. As the temperature increases, the kinetic energy of the gas molecules also increases, causing them to move faster.
5. When gas molecules collide with each other or the walls of their container, the collisions are considered elastic, meaning that no energy is lost during the collision.

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The mass of glucose metabolized is 428.4g

Glucose metabolism constitutes an important process where carbohydrates are split into simple sugars that further convert into glucose.

This flows via blood to the cells.

It involves several processes one among them is glycolysis.

Given data:

work performed can be found as:

W = mgh

Where,

Substituting the values in the equation

W = mgh

= 88.6 × 9.8 × 1950 = 1693146 J = 1693.146 kJ

The actual work done is four times original work. The actual work is

W = 4 × 1693.14 kJ

= 6772.56 kJ

The standard enthalpy of combustion of glucose is

-2840 kJ/mol

The number of moles of glucose required is :

No of moles of glucose required = 6772.56/-2840 = 2.38 mol

The molar mass of glucose is 180g/mol

The mass of glucose metabolized is= 2.38× 180= 428.4 g

Hence, the mass of glucose metabolized is 428.4g

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Answer:

3.55x10^24 atoms Ca

Explanation:

Use Avogadro's number: 6.022 x 10^23

5.90molsCa x (6.022x10^23/1mol) = 3.55x10^24