Pleas help need answer asap!!!

Answer:

1. 9.576

2. 17.442

3. 45.29

4. 79.294

5. 30.736

6. 30.8

7. 31.5

8. 25.85

9. 53.29

10. 49.184

11. 15.18

12. 15.573

13. 17.075

14. 74.06

15. 9.01

Step-by-step explanation:

Use a multiplication method to find the answers. I would put it up here but i dont know how.

The solution to the initial value problem can be written in the form:

y(x) = (1/K)∫|sin(5x)|⁵ (3x³ - csc(5x)) dx

where K is a constant determined by the initial condition.

To solve the initial value problem and find the solution y(x), we can use the method of integrating factors.

Given: dy/dx + 5cot(5x)y = 3x³ - csc(5x), y = 0

Step 1: Recognize the linear first-order differential equation form

The given equation is in the form dy/dx + P(x)y = Q(x), where P(x) = 5cot(5x) and Q(x) = 3x³ - csc(5x).

Step 2: Determine the integrating factor

To find the integrating factor, we multiply the entire equation by the integrating factor, which is the exponential of the integral of P(x):

Integrating factor (IF) = e^{(∫ P(x) dx)}

In this case, P(x) = 5cot(5x), so we have:

IF = e^{(∫ 5cot(5x) dx)}

Step 3: Evaluate the integral in the integrating factor

∫ 5cot(5x) dx = 5∫cot(5x) dx = 5ln|sin(5x)| + C

Therefore, the integrating factor becomes:

IF = \(e^{(5ln|sin(5x)| + C)}\)

= \(e^C * e^{(5ln|sin(5x)|)}\)

= K|sin(5x)|⁵

where K =\(e^C\) is a constant.

Step 4: Multiply the original equation by the integrating factor

Multiplying the original equation by the integrating factor (K|sin(5x)|⁵), we have:

K|sin(5x)|⁵(dy/dx) + 5K|sin(5x)|⁵cot(5x)y = K|sin(5x)|⁵(3x³ - csc(5x))

Step 5: Simplify and integrate both sides

Using the product rule, the left side simplifies to:

(d/dx)(K|sin(5x)|⁵y) = K|sin(5x)|⁵(3x³ - csc(5x))

Integrating both sides with respect to x, we get:

∫(d/dx)(K|sin(5x)|⁵y) dx = ∫K|sin(5x)|⁵(3x³ - csc(5x)) dx

Integrating the left side:

K|sin(5x)|⁵y = ∫K|sin(5x)|⁵(3x³ - csc(5x)) dx

y = (1/K)∫|sin(5x)|⁵(3x³ - csc(5x)) dx

Step 6: Evaluate the integral

Evaluating the integral on the right side is a challenging task as it involves the integration of absolute values. The result will involve piecewise functions depending on the range of x. It is not possible to provide a simple explicit formula for y(x) in this case.

Therefore, the solution to the initial value problem can be written in the form: y(x) = (1/K)∫|sin(5x)|⁵(3x³ - csc(5x)) dx

where K is a constant determined by the initial condition.

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Based on the advertisement seen by Dazuri, the cost of each soccer ball is $22.50

The advertisement says that the original cost of the ball is $30 but there is a 25% discount.

The price of each soccer ball is therefore reduced by the 25% discount on the ball.

The amount that each soccer ball costs is therefore:
= 30 - ( 30 x 25%)

= 30 - 7.5

= $22.50

Rest of the question is:
Soccer balls on sale at a 25% discount. Prices go back to $30 in a week. Don't miss out.

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Answer:

Big one! 6 43/72

Step-by-step explanation:

First, you need to get rid of the fractions. So, we move aside the two 3's and focus on the fractions.  This can be done with this formula:

((A × D) + (B × C)) / B × D

Plug the numbers in and you get:

((3 × 9) + (8 × 2)) / 8 × 9

(27 + 16) / 72

43/72

Then, we add the 3's together and you get:

6 43/72

Answer:

24 chairs  and 18 tables

Step-by-step explanation:

I split it up so 24 chairs and 12 tables plus 6 so 18 tables.

Answer:

y = 2x.

Step-by-step explanation:

The slope of the line = (y2-y1)(x2-x1)

= (8 - (-4)) / (4 - (-2))

= 12/6

= 2.

Now the y intercept is at (0, 0) so

the equation is y = 2x + 0

Answer:  y = 2x.

The Correct choices are :

Step-by-step explanation:

Find the distance between points D and E, E and F, and F and D. Then add the 3 distances.

In order to create a diagram that represents the quantities of each ingredient adde, could be:

CM = X X X

FB = X X

CS = x

Where CM is Cups of Milk, FB is Frozen Bananas and CS is Chocolate Syrup. There, x representent the ammount of each ingredient.

Now, we determine the proportions of the ingredients:

There are 3 cups of milk per two frozen bananas (3:2)

There are 2 frozen banas per tablespoon of chocolate syrup (2:1).

There are 3 cups of milk per tablespoon of chocolate syrup (3:1).

Now, in order to write 3 sentences that contain the ratio of the ingredients we could think of it as a recipe:

*"In order to get this smoothie we will need 3 cups of milk and a tablespoon of chocolate syrup."

*"We will also add 2 frozen bananas for each tablespoon of chocolate syrup."

*"Remember that that is the ammount of ingredients per serving, so if you want more servings you will also need another extra 3 cups of milk, 2 frozen bananas and 1 tablespoon of chocolate syrup for each extra serving."

Answer:

Rs. 28,571.4

Step-by-step explanation:

Let

Cost price = x

Profit = 5% of x

= 0.05x

Selling price = Rs.30, 000

Profit = Selling price - cost price

0.05x = 30,000 - x

Collect like terms

0.05x + x = 30,000

1.05x = 30,000

x = 30,000/1.05

x = Rs. 28,571.428571428

Approximately,

Cost price = x = Rs. 28,571.4

Answer:

The scale factor is 3

Step-by-step explanation:

Answer:56.66 mi/h

Step-by-step explanation:

210 + 130 / 3.5 + 2.5 = 340 / 6

Divide by 6 and you get 56.66

Rounding to the nearest tenth 56.7 mi/h

Answer:

Step-by-step explanation:

The Domain of the function f(x) = \(\frac{3}{4}\) | x | - 3 is set all real numbers.

The Range of the given function is [ - 3 , ∞ )

Answer: √90=3√5⋅2=3√10

Step-by-step explanation:

Answer:

10 1/2 sticks, or 11 sticks with half a stick left over.

Step-by-step explanation:

If every student (and there are 14 students) needs 3/4 stick of butter, the equation is 3/4 x 14 = 10 1/2

To find the area above the curve y = -e^x + e^(2x-3) and below the x-axis for x ≥ 0, we can use an integral. The area can be calculated by integrating the absolute value of the function from the point where it intersects the x-axis to infinity.

Let's denote the given function as f(x) = -e^x + e^(2x-3). We want to find the integral of |f(x)| with respect to x from the x-coordinate where f(x) intersects the x-axis to infinity.

First, we need to find the x-coordinate where f(x) intersects the x-axis. Setting f(x) = 0, we have:

-e^x + e^(2x-3) = 0

Simplifying the equation, we get:

e^x = e^(2x-3)

Taking the natural logarithm of both sides, we have:

x = 2x - 3

Solving for x, we find x = 3.

Now, the integral for the area can be written as:

A = ∫[3, ∞] |f(x)| dx

Substituting the expression for f(x), we have:

A = ∫[3, ∞] |-e^x + e^(2x-3)| dx

By evaluating this integral using appropriate techniques, such as integration by substitution or integration by parts, we can find the exact value of the area.

Please note that a graph of the function is necessary to visualize the region and determine the bounds of integration accurately.

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The solution for the equation ln 5 x=4 is 10.92.

ln 5 x=4

5 x = \(e^{4}\)

x = 10.92

A formula would be 3x - 5 = 16, for instance. When this equation is solved, we discover that the value of the variable x is 7.

The point-slope form, standard form, and slope-intercept form are the three main types of linear equations.

A formula that expresses the connection between two expressions on each side of a sign. Typically, it has a single variable and an equal sign.

Two expressions joined by the equals symbol ("=") form an equation. The "left hand side" and "right hand side" of the equation are the expressions on either side of the equals sign. The right side of an equation is frequently considered to be zero.

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Answer:

150

Step-by-step explanation:

Answer:

jhi

Step-by-step explanation:

Answer:

3f+7

Step-by-step explanation:

a. Null hypothesis: H₀: µ ≤ 74

b. A t-test is appropriate here because the population standard deviation is not known, and the sample size is less than 30.

c. The value of Test statistic is -6.325

d. At a 0.05 significance level, the critical value for a right-tailed test is  -1.664.

e. The test statistic (-4.38) is less than the critical value (1.645). Hence we can reject the null hypothesis.

a. Null hypothesis, H0: µ = 74, alternative hypothesis, H1: µ > 74  (there is no significant difference in the mean job satisfaction scores of employees after the telecommuting policy is adopted).

b. A t-test is appropriate here because the population standard deviation is not known, and the sample size is less than 30. This is a one-tailed test because the alternative hypothesis is directional (i.e., it states that the mean level of satisfaction will increase with telecommuting).

c. The test statistic is calculated using the formula: t = (X - µ) / (s / √n), where X is the sample mean, µ is the population mean, s is the sample standard deviation, and n is the sample size.  Substituting the values given in the question: t = (56 - 74) / (8 / √80) = -6.325

d. The critical value for a one-tailed t-test with 79 degrees of freedom at the 0.05 level of significance is -1.664. Since the calculated t-value of -6.325 is less than the critical value of -1.664, we reject the null hypothesis.

e. Based on the calculated t-value and critical value, we reject the null hypothesis that the mean level of satisfaction is the same before and after telecommuting and accept the alternative hypothesis that telecommuting increases the mean level of satisfaction among employees.

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To find the Maclaurin series of the function f(x) = (6x^2)e^(-7x), we can use the formula for the Maclaurin series of e^x and multiply it by 6x^2. The Maclaurin series of e^x is  e^x = ∑n=0[infinity] (1/n!) x^n

Multiplying by 6x^2, we getx

6x^2 e^x = ∑n=0[infinity] (6/n!) x^(n+2)

Now, we substitute x with -7x to get the Maclaurin series of f(xx

f(x) = (6x^2)e^(-7x) = 6x^2 e^x(-7x) = ∑n=0[infinity] (-42/n!) x^(n+2)

Therefore, the Maclaurin series of f(x) is

f(x) = ∑n=0[infinity] (-42/n!) x^(n+2)

To find the Maclaurin series of the function f(x) = (6x^2)e^(-7x), we can use the formula for the Maclaurin series of e^x and multiply it by 6x^2. The Maclaurin series of e^x is:

e^x = ∑n=0[infinity] (1/n!) x^n

Multiplying by 6x^2, we get:

6x^2 e^x = ∑n=0[infinity] (6/n!) x^(n+2)

Now, we substitute x with -7x to get the Maclaurin series of f(x):

f(x) = (6x^2)e^(-7x) = 6x^2 e^x(-7x) = ∑n=0[infinity] (-42/n!) x^(n+2)

Therefore, the Maclaurin series of f(x) is:

f(x) = ∑n=0[infinity] (-42/n!) x^(n+2)

To find the Maclaurin series of the function f(x) = (6x^2)e^(-7x), we can use the formula for the Maclaurin series of e^x and multiply it by 6x^2. The Maclaurin series of e^x is e^x = ∑n=0[infinity] (1/n!) x^n

Multiplying by 6x^2, we get

6x^2 e^x = ∑n=0[infinity] (6/n!) x^(n+2)

Now, we substitute x with -7x to get the Maclaurin series of f(x)x

f(x) = (6x^2)e^(-7x) = 6x^2 e^x(-7x) = ∑n=0[infinity] (-42/n!) x^(n+2)

Therefore, the Maclaurin series of f(x) is

f(x) = ∑n=0[infinity] (-42/n!) x^(n+2)

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Step-by-step explanation:

(cubic root (x²))⁶ = (x^2/3)⁶ = x^2×6/3 = x^12/3 = x⁴

Answer:

,

Step-b,y-step explanation:

Answer:

GF = GE so GE = 7x-3

Answer:

GE = 38

Step-by-step explanation:

6x + 2 = 7x - 3

6x + 5 = 7x

5 = x

Put the variable into the equation of GF, since GF and GE make a square therefore are equal.

7(5) - 3

GE = 38

Answer:

b = 60

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

b² + 63² = 87²

b² + 3969 = 7569 ( subtract 3969 from both sides )

b² = 3600 ( take the square root of both sides )

b = \(\sqrt{3600}\) = 60

Answer:

x=3

Step-by-step explanation:

isolate the variable by dividing each side by factors that dont contain the variable

Step-by-step explanation:

8x-4+2x+2=28

10x-2=28

10x=28+2

10x=30

x=3

6y = -24

y = -24/6

y = -4

I guess is the answer

Solution

For this case we can see that < XQL and < MQR are opposed by the vertex so then are equal

And if we set up equal the measures given we got:

-12x+133= 3x+79

Now we can solve for x. We can add 12x in both sides of the equation and we got:

133= 15x+79

Now we can subtract both sides of the equation 79 and we got:

54= 15x

And finally we got:

x= 54/15= 3.6º

Now we can find the angle < MQR replacing the value of x like this: