Plastic deformation is characterized by permanent _________, that is, the material (like a compressed snowball) doesn't return to its original shape.

Answer:

Explanation:

sorry i dont know

Option C - two hours. Type 1B buildings are fire-resistive and feature noncombustible materials in both structural and non-structural components.

These buildings' structural components, such as the structural frame supporting the roof, are designed to withstand high temperatures for an extended period and, as a result, have high fire-resistance ratings.What is the minimum fire-resistance rating for the structural frame supporting only the roof of a Type 1B building?The minimum fire-resistance rating for the structural frame supporting only the roof of a Type 1B building is two hours. This means that the structural frame supporting the roof of a Type 1B building must be capable of resisting high temperatures and flames for at least two hours before structural failure occurs.This standard is necessary to prevent the structural frame from collapsing and causing significant damage in the event of a fire. In high-rise buildings, it is critical to prevent structural failure to ensure that firefighters and other rescue personnel have adequate time to respond to the situation and evacuate occupants safely.Therefore, the answer is Option C - two hours.

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66.7 J of work is supplied by the refrigerator in order to remove 200J of heat from its interior. Which is having COP of 3

COP of refrigerator is defined as the ratio of heat removed from the substance (refrigerator) to Work input.

Full form of COP is Coefficient of Performance.

Formula of COP = Heat Removed(Q)/ Work input( W)

we have COP =3

Q= 200J substitute in formula

3=200/w ⇒ w=200/3 ⇒ 67J

Hence 66.7 J of work is supplied by the refrigerator in order to remove 200J of heat from its  interior. Which is having COP of 3

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Answer:

Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.

Explanation:

A value of R equal to 5000 Ω will result in a critically damped response.

The characteristic equation for a parallel RLC circuit is given by:

s^2 + (R/L)s + 1/(LC) = 0

where:

s = complex frequency

R = resistance (2000 Ω)

L = inductance (250 mH = 0.25 H)

C = capacitance (10 nF = 10 * 10^(-9) F)

Substituting the given values into the characteristic equation:

s^2 + (2000/0.25)s + 1/((0.25)(10*10^(-9))) = 0

s^2 + 8000s + 4 * 10^12 = 0

To determine whether the response will be over-, under-, or critically damped, we need to examine the discriminant of the characteristic equation. The discriminant is given by:

D = (b^2 - 4ac)

where:

a = 1

b = 8000

c = 4 * 10^12

Calculating the discriminant:

D = (8000^2 - 4(1)(4 * 10^12))

D = 64 * 10^6 - 16 * 10^12

D = -15.936 * 10^12

Since the discriminant is negative (D < 0), the response will be overdamped.

c) To find the value of R that yields a damped frequency of 12 krad/s, we can use the formula for the damped frequency:

ωd = sqrt((1/(LC)) - (R^2/(2L^2)))

Substituting the given values:

12 * 10^3 = sqrt((1/((0.25)(10 * 10^(-9)))) - (R^2/(2 * (0.25^2))))

Squaring both sides:

(12 * 10^3)^2 = (1/((0.25)(10 * 10^(-9)))) - (R^2/(2 * (0.25^2)))

144 * 10^6 = (1/(0.25 * 10^(-9))) - (R^2/(2 * 0.0625))

144 * 10^6 = 4 * 10^9 - (R^2/0.125)

Subtracting 4 * 10^9 from both sides:

140 * 10^6 = - (R^2/0.125)

Dividing both sides by -1:

-140 * 10^6 = R^2/0.125

R^2 = -(140 * 10^6)(0.125)

R^2 = -17.5 * 10^6

Taking the square root of both sides:

R = ±sqrt(-17.5 * 10^6)

Since the square root of a negative number is imaginary, there is no real value of R that yields a damped frequency of 12 krad/s.

Since there is no real value of R that satisfies the condition in (c), there are no roots of the characteristic equation to find.

To achieve a critically damped response, we need to set the discriminant equal to zero (D = 0) in the characteristic equation.

64 * 10^6 - 16 * 10^12 = 0

Dividing both sides by 16 * 10^12:

4 * 10^(-6) = 10^6 / R^2

R^2 = 10^6 / (4 * 10^(-6))

R^2 = 250 * 10^6

Taking the square root of both sides:

R = ±sqrt(250 * 10^6)

R = ±5000 Ω

Therefore, a value of R equal to 5000 Ω will result in a critically damped response.

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Answer & Explanation:

i) If a student foolishly decides to binge drink 21 beers on their 21st birthday, they would consume a total of 21 x 170 = <<21*170=3570>>3570 calories of digestible energy. Since one calorie is equivalent to raising the temperature of one gram of water by one degree Celsius, and one gallon of water is equivalent to 3,785 grams, the student would have consumed enough energy to raise the temperature of 3,785 grams x 3570 calories = 13,678,950 calories of water from 24 °C to 100 °C. This means that the student could have heated 13,678,950 / 100 = <<136789500/100=136789.5>>136789.5 grams of water from room temperature to boiling, which is equivalent to 136789.5 / 3,785 = <<136789.5/3785=36.19>>36.19 gallons of water.

ii) The energy equivalent of the beer consumed by the student is 3570 calories x 4.184 joules/calorie = 14,889.48 joules. Since one BTU is equivalent to 1,055 joules, this energy is equivalent to 14,889.48 joules / 1,055 joules/BTU = <<14889.48/1055=14.15>>14.15 BTU.

iii) If the student had purchased an equivalent amount of electrical energy from the utility company, they would have to pay 14.15 kW-hr x $0.10/kW-hr = $<<14.15*0.1=1.42>>1.42. This is cheaper than buying beer, as a can of beer typically costs more than $1.42.

Answer: Technician A is wrong , Technician B is correct.

Explanation:

The Air fuel ratio is used in the combustion process of engines whether internal or external, and defined as the mass  ratio of air to  fuel present in a combustion process.  When the ratio of the mass of air and fuel is right, combustion is said to be efficient and balanced and this is refereed to as stoichiometrc mixture which is a standard that all engines are required to target.

when the air fuel Ratios is  lower than the target stoichiometric, it is considered as a Rich mixture  while higher ratios  than stoichiometric are considered Lean mixtures. Lean mixtures are more efficient than rich mixtures although the main aim is to be at the stoichiometic mixture point.

Air fuel equivalence ratio, lambda and the amount of oxygen in an exhaust are two indicators for lean or rich mixtures in an air fuel ratio for combustion in engines

Now, Air–fuel equivalence ratio, λ (lambda), is defined as the  ratio of actual AFR to stoichiometry for a particular mixture,

when Lambda λ = 1.0 , the mixture is at stoichiometry,

when  λ < 1.0, the mixtrure is rich.

when  λ > 1.0, the mixture is  lean

 Therefore Technician A is wrong

Also The amount of oxygen present in the exhaust determines if the air-fuel mixture supplied to the combustion chambers is at the target or best ratio. Too much oxygen indicates that the mixture is lean and too little  indicates the mixture is rich. Therefore Technician B is right.

Answer:

Here are some characteristics that describe customers who are more likely to have low assets and medium-low debt:

* **Age:** Younger customers are more likely to have lower assets and debt than older customers. This is because they have had less time to accumulate assets and may be carrying more student loan debt.

* **Income:** Customers with lower incomes are more likely to have lower assets and debt than customers with higher incomes. This is because they have less money to save and invest, and may be spending more of their income on necessities.

* **Education:** Customers with less education are more likely to have lower assets and debt than customers with more education. This is because they may have lower-paying jobs and may be less likely to save and invest.

* **Marital status:** Single customers are more likely to have lower assets and debt than married customers. This is because they may have less income and may be spending more of their income on housing and other expenses.

* **Employment status:** Unemployed customers are more likely to have lower assets and debt than employed customers. This is because they may have less income and may be spending more of their income on necessities.

* **Credit score:** Customers with lower credit scores are more likely to have lower assets and debt than customers with higher credit scores. This is because they may have difficulty qualifying for loans and may be paying higher interest rates on debt.

It is important to note that these are just general trends, and there are always exceptions. There are many factors that can affect a customer's assets and debt, including their personal circumstances, financial decisions, and economic conditions.

Explanation:

Answer:

12 mins

Explanation:

The summation of the forces in vertical direction

= Fb - Fd - w = 0 ∴ Fd = Fb - w  ----- ( 1 )

Fb ( buoyant force ) = Pair * g * Vballoon ------- ( 2 )

Pair = air density , Vballoon = volume of balloon

Vballoon = \(\frac{\pi D^3}{6}\) ,  where D = 4  ∴  Vballoon = 33.51 ft^3

g = 32.2 ft/s^2

From property tables

Pair = 2.33 * 10^-3 slug/ft^3

μ ( dynamic viscosity ) = 3.8 * 10^-7 slug/ft.s

Insert values into equation 2

Fb = ( 2.33 * 10^-3 ) * ( 32.2 ) *( 33.51 )  = 2.514 Ib

∴ Fd = 2.514 - 2.5 = 0.014 Ib ( equation 1 )

Assuming that flow is Laminar  and  RE < 1

Re = (Pair * vd) / μair   -------- ( 3 )

where:  Pair = 2.33 * 10^-3 slug/ft^3 ,  vd = ( 987 * 4 ) ft^2/s ,   μair = 3.8 * 10^-7 slug/ft.s

Insert values into equation 3

Re = 2.4 * 10^7 (  this means that the assumption above is wrong )

Hence we will use drag force law

Assume Cd = 0.5

Express  Fd using the relation below

Fd = 1/2* Cd * Pair * AV^2

therefore V = 1.39 ft/s

Recalculate  Reynold's number using  v = 1.39 ft/s

Re = 34091

from the figure Cd ≈ 0.5 at Re = 34091  

Finally calculate the rise time ( time taken to reach an altitude of 1000 ft )

t = h/v

  = 1000 / 1.39 = 719 seconds ≈ 12 mins

Z≤ -4.852 ft, Maximum efficiency is η≅ 0.88 ≅ 88% is the maximum discharge possible

Solution

Given Data:-

D = 14.62in, N = 2134 rc/min, T=20°C. At T= 20°C ɣ=ρg= 62.35 lb/ft³, vapor pressure. Pv = 49.2 lb/ft².

The efficienies at each flow rate is computal by using formula

η = ρgθH / (550) (bhp)

→ As we can See the maximum efficiency point is at θ = 6ft³/s (close to 6ft³/s)

Maximum efficiency is η≅ 0.88 ≅ 88%

b) Given NPSHR = 16 ft,hg=22ft. Zactual. = 9ft  (below the sea surface)

To avoid cavitation NPSH < Pa - Pv/ρg - Z - hf

Z < Pa - Pv/ρg - hf

Z < 2116 - 49.2/62.35 - 16 - 22 [1 atm = 2116 lb/ft2]

Z≤ -4.852 ft

-> Keeping the pump 9 ft below the surface gives 4.148 ft of marign against cavitation.

Hence it is Sufficient to avoid cavitation.

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Answer:

yes

Explanation:

an idea could be a jack o lantern monster since it Halloween tomorrow  

Answer:

2.61 m separation

Explanation:

x = xo + vo t + 1/2 at^2      x o   and vo = 0   so this becomes

x  = 1/2 at^2

Find t    when   x = 3

3 = 1/2 (9.81)(t^2)

t = .782 sec

then the SECOND ball is at

x = 1/2 a t^2           but t is reduce by 1/2 second drop rate

x = 1/2 (9.81)(.782 - .5)^2 = .39  m

3 - .39  m = 2.61 m

a. The heat transfer to the working fluid passing through the steam generator = 3157.47 kj/kg

b. The thermal efficiency = 34.518%

c. The heat transfer from the working fluid passing through the condenser to the cooling water = 2067.58 kj/kg

The percentage of heat that is converted into usable work is expressed by thermal efficiency. The mathematical formula that can be used to determine the thermal efficiency is denoted by the symbol :

η = WQH

Where,

QH represents the total amount of heat energy absorbed from the hot source and

W represents the useful work.

Due to practical constraints, heat engines frequently run at an efficiency of 30% to 50%. According to the Second law of thermodynamics, it is impossible for heat engines to operate at 100% thermal efficiency (=1). This is not feasible because a heat engine will always produce some waste heat. The efficiency of a system can be increased in many different ways, even though a heat engine cannot operate at 100% efficiency.

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Demonstrating your ability to pay back borrowed money is one way to

develop a good credit history.

Paying bills on time and in full is another way to demonstrate that you can pay back money. Additionally, having a stable income, low debt-to-income ratio, and a low utilization of credit lines can all help demonstrate an ability to pay back borrowed money.

A good credit score is generally considered to be any score above 700. This score is typically determined by a credit reporting agency, such as Equifax, Experian, or TransUnion. Credit scores are calculated using a variety of factors, including the length and type of credit accounts, payment history, credit utilization, and more.

A score of 700 or higher is generally considered to be good because it indicates that a person is a relatively low risk for lenders and creditors. A good credit score can result in lower interest rates on loans and credit cards, as well as improved chances of approval for financing applications. Additionally, a good credit score may also be beneficial when applying for jobs, renting an apartment, or opening a new bank account.

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Explanation:

thermal expansion ∝L = (δL/δT)÷L ----(1)

δL = L∝L + δT ----(2)

we have δL = 12.5x10⁻⁶

length l = 200mm

δT = 115°c - 15°c = 100°c

putting these values into equation 1, we have

δL = 200*12.5X10⁻⁶x100

= 0.25 MM

L₂ = L + δ L

= 200 + 0.25

L₂ = 200.25mm

12.5X10⁻⁶ *115-15 * 20

= 0.025

20 +0.025

D₂ = 20.025

as this rod undergoes free expansion at 115°c, the stress on this rod would be = 0

One of the sources of failure common to both the Therac-25 and the Ariane 5 rocket was a software error.

In the case of the Therac-25, a race condition occurred due to a coding error that allowed multiple threads to access a shared variable simultaneously, causing a fatal radiation overdose in patients.  In the case of the Ariane 5 rocket, an overflow error occurred due to a data conversion error between the guidance system's 64-bit floating-point number and the onboard computer's 16-bit integer, causing the rocket to self-destruct shortly after launch.

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Answer:

Rear body panel. Rear bumper cover. Rear rails.

Explanation:

The body parts that serves as front end cross structures of vehicles are Rear body panel , front bumper and rear nails

Front end cross structures refers to several frontal parts or part that are located at the front of automobilles that define it's appearance and it's effective workability. The frontal parts are essential for the effective running of the vehicles and also define the vehicles appearance.

Therefore, The body parts that serves as front end cross structures of vehicles are Rear body panel , front bumper and rear nails.

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Ultrafine crystalline grains in the nanometer range that are separated by grain boundaries or interfaces define nanocrystalline materials.

A polycrystalline substance with a few nanometer-sized crystallites is referred to as a nanocrystalline (NC) substance. These materials bridge the gap between traditional coarse-grained materials and amorphous materials devoid of long-range organisation. Materials that contain clusters, crystallites, or molecules with diameters between 1 and 100 nm are said to be nanostructured materials.

The gecko's foot, iridescent butterfly wings, and hydrophobic leaves are just a few examples of nanostructures found in nature. Scientists and engineers are employing biomimicry to develop new goods with these nano-inspired qualities.

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In order to calculate the net torque for an object in static equilibrium, the pivot point must be a point about which the object can rotate.

The net torque for an object in static equilibrium can be calculated by considering the pivot point, which must be a point about which the object can rotate. When an object is in static equilibrium, it means that it is not rotating or accelerating.

To determine the net torque acting on the object, we need to consider the forces and their respective distances from the pivot point. Torque is the product of force and the perpendicular distance from the pivot point to the line of action of the force.

The pivot point, also known as the fulcrum, acts as the point of rotation for the object. It can be any point within or on the object, as long as it allows for rotation. However, for accurate calculations and to simplify the analysis, it is often convenient to choose a pivot point that aligns with the forces applied to the object.

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The Vogel theory is an important tool used in the field of production engineering, especially in petroleum and natural gas engineering.

This theory is named after Dr. Harold F. Vogel, who developed it in the 1950s to optimize the production of crude oil and natural gas from a reservoir. The Vogel theory is based on the concept of maximizing the net present value of the project by optimizing the production rate. It takes into account the production costs, the prices of crude oil and natural gas, and the decline in the production rate over time.

To apply the Vogel theory, one needs to estimate the production costs, the prices of crude oil and natural gas, and the decline in the production rate. The production costs include the costs of drilling, completing, and operating the wells, as well as the costs of transporting and processing the crude oil and natural gas. The optimal production rate is the production rate that maximizes the net present value of the project.

In conclusion, the Vogel theory is an important tool used in production engineering, especially in petroleum and natural gas engineering. This theory helps to optimize the production of crude oil and natural gas from a reservoir by finding the optimal production rate that maximizes the net present value of the project.

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Answer:

Sole Proprietorship, General Partnership , Limited Partnership, corporation

Explanation:

Business in something that an individual or a group of people do for a living and produce products and services that benefits the society and the people. There are several entities that can be common in business. Some common form of entities are :

Sole Proprietorship : One to one

-- here there is only one owner in the business and he maintains and manages the entire business functions under his control.

Limited Partnership : many to one

-- here two or more than two partners establish business and runs it but only one or more is liable to the amount of the investments.

General Partnership : many to many

-- It is a business partnership where all the partners shares the profits, the assets, legal liabilities and financial liabilities, etc.

Corporation : many to one

It is a business entity where a group of individual or a group of companies run a single business which is generally authorized by the state.

Some of the typical types of the entities that one may think to be common in term of the business entities are about the relationships that are held within many to many and one to many.

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Given Information:

Inlet velocity = Vin = 25 m/s

Exit velocity = Vout = 250 m/s

Exit Temperature = Tout = 300K

Exit Pressure = Pout = 100 kPa

Required Information:

Inlet Temperature of argon = ?

Inlet Temperature of helium = ?

Inlet Temperature of nitrogen = ?

Answer:

Inlet Temperature of argon = 360K

Inlet Temperature of helium = 306K

Inlet Temperature of nitrogen = 330K

Explanation:

Recall that the energy equation is given by

\($ C_p(T_{in} - T_{out}) = \frac{1}{2} \times (V_{out}^2 - V_{in}^2) $\)

Where Cp is the specific heat constant of the gas.

Re-arranging the equation for inlet temperature

\($ T_{in} = \frac{1}{2} \times \frac{(V_{out}^2 - V_{in}^2)}{C_p} + T_{out}$\)

For Argon Gas:

The specific heat constant of argon is given by (from ideal gas properties table)

\(C_p = 520 \:\: J/kg.K\)

So, the inlet temperature of argon is

\($ T_{in} = \frac{1}{2} \times \frac{(250^2 - 25^2)}{520} + 300$\)

\($ T_{in} = \frac{1}{2} \times 119 + 300$\)

\($ T_{in} = 360K $\)

For Helium Gas:

The specific heat constant of helium is given by (from ideal gas properties table)

\(C_p = 5193 \:\: J/kg.K\)

So, the inlet temperature of helium is

\($ T_{in} = \frac{1}{2} \times \frac{(250^2 - 25^2)}{5193} + 300$\)

\($ T_{in} = \frac{1}{2} \times 12 + 300$\)

\($ T_{in} = 306K $\)

For Nitrogen Gas:

The specific heat constant of nitrogen is given by (from ideal gas properties table)

\(C_p = 1039 \:\: J/kg.K\)

So, the inlet temperature of nitrogen is

\($ T_{in} = \frac{1}{2} \times \frac{(250^2 - 25^2)}{1039} + 300$\)

\($ T_{in} = \frac{1}{2} \times 60 + 300$\)

\($ T_{in} = 330K $\)

Note: Answers are rounded to the nearest whole numbers.

Answer:

science is hard but human cloning this is legendary but still its up to the government but me i would allow this because its something that science can upgrade to

Explanation:

Answer:

the % recovery of aluminum product is 80.5%

the % purity of the aluminum product is 54.7%

Explanation:

feed rate to separator = 2500 kg/hr

in one hour, there will be 2500 kg/hr x 1 hr = 2500 kg of material is fed into the  machine

of this 2500 kg, the feed is known to contain 174 kg of aluminium and 2326 kg of rejects.

After the separation, 256 kg  is collected in the product stream.

of this 256 kg, 140 kg is aluminium.

% recovery of aluminium will be = mass of aluminium in material collected in the product stream ÷ mass of aluminium contained in the feed material

% recovery of aluminium = 140kg/174kg x 100% = 80.5%

% purity of the aluminium product = mass of aluminium in final product ÷ total mass of product collected in product stream

% purity of the aluminium product = 140kg/256kg

x 100% = 54.7%

Answer:

\(D=4.02\)

Explanation:

From the question we are told that:

Part Dimension \(x=4.00in\)

Generally the equation for the corresponding dimension to which the mold cavity should be machined is mathematically given by

\(D=x-(xS)+(4S^2)\)

Where

S= Value for Skinage

From Table pf AB's

\(S=0.006\)

Therefore

\(D=4-(4*0.006)+(4(0.006)^2)\)

\(D=4.02\)

The genotyping lab's overall purpose is to ascertain the genetic composition of a person or group of individuals.

PCR (Polymerase Chain Reaction) is a technique used to amplify a specific section of DNA, which is then examined using gel electrophoresis to find any differences in the genetic sequence. This method enables researchers to detect and investigate genetic mutations, sequence variants, and gene expression patterns. The genotyping laboratory is a significant research tool in several domains, including medical genetics, forensic science, and evolutionary biology. The lab may also be used to diagnose diseases, create drugs, and provide tailored therapy.

Overall, the genotyping lab assists scientists in better understanding the genetic basis of many diseases, as well as in developing new treatments and cures.

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True. The top-down design process is indeed sometimes called stepwise refinement.

In this approach, the overall task or problem is broken down into a series of subtasks or smaller components. Each subtask is examined to determine if it can be further broken down into more detailed subtasks. This process continues until the subtasks are small enough to be written in code or implemented in a specific programming language. The stepwise refinement approach allows for a systematic and structured way of designing and implementing complex systems or programs.

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Answer:

It is used for solving optimization problems in which,given some functional,one seeks the function minimizing or minimizing it.

Explanation:

Please i need a Brainliest.