Plants need sunlight, water, and minerals from the soil in order to grow and thrive. These factors
A.
are always abundant, allowing unlimited growth.
B.
limit the number of plant populations that can grow in an ecosystem.
C.
require human intervention to be replenished.
D.
prevent new plant populations from entering the ecosystem.

Answer:

P1V1=P2V2

Explanation:

because volume is inversely proportional to pressure provided that temperature remains constant

Time increases as the volume of hydrochloric acid remains the same. This is because the concentration of hydrochloric acid would remain constant, affecting the reaction rate. Option B

Based on factors that affect the rates of chemical reactions, the expected trend in the table can be analyzed.

In this experiment, calcium carbonate reacts with hydrochloric acid to produce carbon dioxide gas. The reaction rate is influenced by factors such as concentration, surface area, temperature, and presence of a catalyst. Let's examine the options provided:

A. Time increases as the volume of hydrochloric acid decreases:

This option suggests that as the volume of hydrochloric acid decreases, the time taken for carbon dioxide to form increases. However, in general, a decrease in the volume of hydrochloric acid would result in an increase in its concentration.

B. Time increases as the volume of hydrochloric acid remains the same:

If the volume of hydrochloric acid remains the same, it means the concentration of hydrochloric acid is constant. In this case, the reaction rate is not expected to change significantly, and the time taken for carbon dioxide to form should remain relatively constant. Therefore, this option is plausible.

C. Time decreases as the mass of calcium carbonate decreases:

If the mass of calcium carbonate decreases, the surface area of the reactant particles decreases. A smaller surface area would result in less contact between reactant particles, leading to a slower reaction rate. Thus, the time taken for carbon dioxide to form would be expected to increase, making this option unlikely.

D. Time decreases as the mass of calcium carbonate remains the same:

If the mass of calcium carbonate remains the same, the surface area of the reactant particles also remains the same. Therefore, the reaction rate should remain relatively constant, and the time taken for carbon dioxide to form would not show a significant change. Thus, this option is also plausible.

Option B is correct.

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Answer:

Energy cannot be destroyed or created.

C. i know this is right

Explanation:

Choosing a biome for a research project can provide a wealth of opportunities to better understand the natural world and contribute to important conservation and management efforts.

There are several convincing reasons for researchers to choose a particular biome for their project, some of which include:

Biodiversity: Biomes are characterized by their unique plant and animal species, which can provide a diverse range of research opportunities, including studying their adaptations, behaviors, and interactions.

Climate Change: Biomes are also influenced by climate change, making them an important area of research to better understand how these ecosystems are being affected by changes in temperature and precipitation patterns.

Human Impacts: Human activities, such as deforestation, agriculture, and urbanization, can have a significant impact on biomes. Studying these impacts can help researchers better understand how to mitigate and manage these effects.

Biogeochemical Cycles: Biomes are also important for studying biogeochemical cycles, such as the carbon and nitrogen cycles, which are essential for sustaining life on Earth.

Conservation: Finally, studying biomes can also contribute to conservation efforts, helping to preserve these unique ecosystems and the species that inhabit them.

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Explanation:

How many neutrons are there in the nucleus of arsenic?42 neutrons

The nucleus consists of 33 protons (red) and 42 neutrons (blue).

The volume of a 60% solution by mass that is prepared with 45 grams of a particular solute is 75 mL.

Firstly, to calculate the volume of the solution, we need to know the density of the solution. Since it is not mentioned in the question, we can assume it to be 1 g/ml.

Next, we can use the formula:

mass of solute = (mass of solution) x (percent by mass)

Here, the mass of solution is the mass of solute plus the mass of solvent.

Or, the mass of solute + the mass of solvent = the mass of solution

Therefore,

The mass of solvent = the mass of solution - the mass of solute

Substituting the values provided in the question, we get:

mass of solvent = (45) / (0.6) - 45 (since the solution is 60%)

mass of solvent = 75 - 45 = 30 g

Thus, mass of the solvent = 30g

Since volume = mass / density

The volume of the 60% solution = mass of solution / density

volume of solution = (45 + 30) / (1)

volume of solution = 75 mL

Thus, 75 mL of the 60% solution by mass is made with 45g of solute.

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The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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The number of mole of CaCO₃ in antacid tablet containing 0.512 g of CaCO₃ is 5.12×10⁻³ mole

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

From the question given above, the following data were obtained:

The number of mole in 0.512 g of CaCO₃ can be obtained as follow:

Mole = mass / molar mass

Mole of CaCO₃ = 0.512 / 100

Mole of CaCO₃ = 5.12×10⁻³ mole

Thus, 5.12×10⁻³ mole of CaCO₃ is present in the antacid tablet

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Dehydration of the process is linked to a decrease in entropy. correct option is (A).

Entropy is a measurement of a system's disorganization. It is an extended attribute of a thermodynamic system, which means that the amount of matter in the system affects its value. Entropy is frequently represented in equations by the letter S and is measured in joules per kelvin.

By combining several molecules into one, a dehydration reaction lowers the system's entropy. On the other hand, entropy is raised by catabolic, depolymerizing, and hydrolytic activities that break down molecules into smaller parts.

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The solubility of carbon dioxide in water at the given pressure would be 8.45 g CO2 in 100 mL of water.  

According to Henry's law:

C = kH x P

where:

To solve this problem, we need to use the Henry's law constant for carbon dioxide in water at 20 \(^oC\), which is 0.0349 mol/L/atm. Let's convert the given solubility from mass/volume units to molar concentration units as follows:

Now we can use Henry's law to calculate the solubility of carbon dioxide in water at 5.50 atm:

Concentration from mol/L to mass/volume units:

0.192 mol/L x 44.01 g/mol = 8.45 g CO2 / 100 mL

Therefore, the solubility of carbon dioxide in water at 5.50 atm pressure is approximately 8.45 g CO2 in 100 mL of water at 20 \(^oC\).

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The specific heat capacity of the alloy is 0.120 J/g°C.

What is Specific heat capacity?

Specific heat capacity, also known as specific heat, is the amount of heat required to raise the temperature of a unit mass (usually one gram) of a substance by one degree Celsius or Kelvin. Each substance has its own specific heat capacity, which depends on its chemical composition and physical state. The SI unit of specific heat is joules per gram per degree Celsius (J/g°C).

First, we need to calculate the heat absorbed by the water:

q_water = m_water * C_water * ∆T

where m_water is the mass of water, C_water is the specific heat capacity of water, and ∆T is the change in temperature of the water.

m_water = 50.0 g

C_water = 4.18 J/g°C

∆T = 31.10°C - 22.00°C = 9.10°C

q_water = (50.0 g) * (4.18 J/g°C) * (9.10°C) = 1911.5 J

Next, we need to calculate the heat released by the alloy:

q_alloy = - q_water

Since the calorimeter is insulated, the heat lost by the alloy is equal to the heat gained by the water.

q_alloy = m_alloy * C_alloy * ∆T

where m_alloy is the mass of the alloy, C_alloy is the specific heat capacity of the alloy, and ∆T is the change in temperature of the alloy.

m_alloy = 29.3 g

∆T = 31.10°C - 93.00°C = -61.90°C (note the negative sign)

q_alloy = (29.3 g) * C_alloy * (-61.90°C)

Finally, we can solve for the specific heat capacity of the alloy:

C_alloy = - q_water / (m_alloy * ∆T)

C_alloy = - (1911.5 J) / ((29.3 g) * (-61.90°C))

C_alloy = 0.120 J/g°C

Therefore, the specific heat capacity of the alloy is 0.120 J/g°C.

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Answer:

It is electrical → heat, sound, and motion

because a hair dryer makes heat to dry your hair and sound is the blowing and motion is how it goes

Explanation:

Answer:

A

Explanation:

electrical -- heat sound, and motion

Any time a liquid loses or receives energy, the temperature of the liquid changes.To calculate the amount pf energy change, the calorimeter monitors the weight of the fluid as well as the temperature change.

The 6000 series calorimeters' control systems serve as the foundation for the 6772 Calorimetric Thermometer, a high precision temperatures measuring device.It is a crucial component of both the 6755 Solution Calorimeter and the 6725 Semi-micro Calorimeter.

The calorimeter is a piece of equipment used in calorimetry, a procedure for calculating heat capacity and measuring the temperature of chemical processes or other physical changes.Among the most popular kinds are differential scanning operating, thermal micro cathode rays, titration calorimeters, and accelerated rate calorimeters.

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Once alcohol is in the bloodstream it will reach the brain in a few seconds to minutes, depending on various factors such as the amount and concentration of alcohol consumed, body weight, metabolism, and other individual factors.

Alcohol can swiftly cross the blood-brain barrier after it is ingested, having an impact on the brain and neurological system. Depending on the quantity and frequency of drinking, alcohol's effects on the brain can range from minor disturbances in judgment and coordination to more serious consequences including loss of consciousness and, in the worst circumstances, death.

Long-term changes in brain structure and function, such as cognitive impairment and a higher chance of developing specific neurological and mental illnesses, can also result from chronic alcohol consumption.

Once alcohol is in the bloodstream it will reach the brain in a few seconds to minutes, depending on various factors such as the amount and concentration of alcohol consumed, body weight, metabolism, and other individual factors.

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Masses of water and carbon dioxide be 54 g and  66 g respectively.

Mass is a measure of the amount of matter that an object contains

Here given data is 1.00 x10⁵ grams of oxygen and  1.00 x10⁵ grams of methane and the reaction is

CH₄ +2O₂ → CO₂ + 2H₂O

Then (12+4)= CH₄ , 2×(16×2)=2O₂  , 12+(16×2)=CO₂  , 2×(16+2)=2H₂O

CH₄ = 16 g, 2O₂ = 64 g, CO₂ = 44 g, 2H₂O = 36 g

Then, we have to find masses of water and carbon dioxide = ?

24g of CH₄=24/16×44 = 66 g of CO₂

16 g of CH₄ will produce 36 g of water

Then, 24 g of CH₄ = 24/16×36 = 54 g of water

Mass of water is  54 g and mass of carbon dioxide is 66 g

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Answer:

Where is the image ?

Explanation:

You have to post it so we can help you .

Answer:

where is the image?????

Answer:

Explanation:

The missing image can be seen below.

From the given information:

The elimination process follows E2 mechanism which is a 2nd order kinetics.

At E2 mechanism, the base attaches with the beta hydrogen while also removing the leaving group in the same process. In the given compound 2-chloro-2-methylpropane, chloride is the leaving group that results in the product; 2-methylprop-1-ene.

The mechanism is seen in the second image,

Answer:

cover the taste with sugar add two times the amount your supposed to put in

Explanation:

Explanation:

To answer this question, we need to observe the meniscus in the figure.

When observing the volume of a liquid in a beaker, graduated pipette or burette, read the point on the scale graduated that coincides with the underside of the surface liquid curve. This surface is called the meniscus. Always make sure the lower part of the meniscus is exactly matching the calibration mark.

In this case, meniscus is at 35.

Answer: 35.

Answer:

\(q_{rxn}\) = -13.3 KJ belongs to the bomb calorimeter

Explanation:

In this question, we are concerned with determining which of the two heats of reaction given, belongs to that in the bomb calorimeter

The kind of calorimetry used in a bomb calorimeter and a coffee-cup calorimeter is different.

In a bomb calorimeter, what we have is a constant volume calorimetry while in a coffee-cup calorimeter, what we have is a constant-pressure calorimetry.

For  constant volume calorimetry, the change in volume ΔV = 0 while for constant pressure calorimetry, the change in pressure ΔP = 0.

Mathematically, the relationship between the change in internal energy Δ\(E_{rxn}\) of the reaction, the work of the reaction \(w_{rxn}\) and the heat of the reaction \(q_{rxn}\) is given by;

Δ\(E_{rxn}\) =   \(w_{rxn}\) +   \(q_{rxn}\)

Kindly note that, in a bomb calorimeter, the work of the reaction \(w_{rxn}\) = 0

Thus, this means that for a bomb calorimeter,

Δ\(E_{rxn}\) =    \(q_{rxn}\)

This means that in the bomb calorimeter, the entire internal energy change is converted to heat of the reaction.

In the case of the coffee-cup calorimeter, the work of the reaction is non-zero and it is equal to the product of the pressure and the change in volume.

Thus, mathematically,

\(w_{rxn}\) = PΔV

Thus;

Δ\(E_{rxn}\) =   \(w_{rxn}\) +   \(q_{rxn}\) =  PΔV +   \(q_{rxn}\)

Since for a coffee cup calorimeter, the change in volume is positive(as given in the question), this means that;

ΔV > 0

and PΔV > 0

This automatically means that

Δ\(E_{rxn}\) >  \(q_{rxn}\)

Hence, in the coffee cup calorimeter, the entire change in internal energy is not converted to heat as part is used to do useful work.

Thus, this means that in the coffee cup calorimeter, the value of change in internal energy is greater than the value of heat.

This makes the magnitude  of heat in the bomb calorimeter   greater than that of the coffee cup calorimeter.

Since -13.3 KJ is the bigger magnitude of the two, then it belongs to the bomb calorimeter

Answer:

\(M=1.1M\)

Explanation:

Hello,

In this case, since we are mixing two NaOH solutions, the first step is to compute the total moles once the mixing is done, by using the volumes and concentrations of each solutions and subsequently adding them:

\(n_T=2.0L*0.60\frac{mol}{L}+495mL*\frac{1L}{1000mL}*3.0\frac{mol}{L}= 2.7molNaOH\)

Next, we compute the total volume by adding the volume of each solution:

\(V_T=2.0L+495mL*\frac{1L}{1000mL}= 2.495L\)

Finally, we compute the molarity of the resulting solution by the division between the total moles and the total volume:

\(M=\frac{2.7mol}{2.495L}\\ \\M=1.1M\)

Best regards.

Answer:

Reduction involves a half-reaction in which a chemical species decreases its oxidation number, usually by gaining electrons. The other half of the reaction involves oxidation, in which electrons are lost. Together, reduction and oxidation form redox reactions (reduction-oxidation = redox).

Explanation:

Hope this helps :)

The enthalpy change (ΔH) for the reaction CaC(s) + H2O(I) → Ca(OH)(ag) + CH4(g) is -3617.6 kJ.

To calculate ΔH for the reaction CaC(s) + H2O(l) → Ca(OH)2(ag) + CH4(g), we can use Hess's law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.

We can manipulate the given reactions to obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X (unknown value)

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's manipulate these equations to cancel out the common reactants and products and obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's sum up the equations to obtain the desired reaction:(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1271 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

By adding equations (ii), (iii), (iv), and (v), we can cancel out CaO(s), H2O(l), and O2(g):

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -1271 -653.1 -1300.0 -393.5

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -3617.6 kJ

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Answer: A. The farther a planet is from the Sun, the longer its orbital period is, and D. Planets with greater mass tend to have more moons.

Explanation: trust

The percent yield for the reaction of a sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate is 92.4%

Given the mass of carbon dioxide (\(CO2\)) = 0.49g

The mass of calcium carbonate (\(CaCO3\)) = 1.22g

The reaction is as follows:

\(CaCO3(s) -- > CaO(s)+CO2(s)\)

As we see 1 mole of CaCO3 is required to produce 1 mole of \(CO2\)

The molar mass of calcium carbonate, = 100.09 g/mol.

The molar mass of given carbon dioxide = 44g

mass of \(CaCO3\) used = number of moles x molar mass = 1 * 100 = 100g

Mass of \(CO2\) produced = 1 * 44 = 44g

Here for 100g of \(CaCO3\) 44g of \(CO2\) is produced.

Then for 1.22g of \(CaCO3\) = 44 * 1.22/100 = 0.53g of \(CO2\) is produced.

But the actual yield of carbon dioxide is 0.49 g

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

percent yield = 0.49/0.53 * 100 = 92.4%

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Answer:

the answer is B

hope this helped!

The internal energy of a human body is the net energy contained in the body due motion of its particle or molecules.

In a human body the internal energy is stored . It increases when the temperature of the body rises, or when the body observes some changes. Internal energy we can say that is the sum of kinetic and potential energy of all particles in the body.

Internal energy is a state function of a system and is an extensive quantity. Every substance possesses a fixed quantity of energy which depends upon  its chemical nature and also on its state of existence. Every substance have a definite value of Internal energy.

The change in the Internal energy of a reaction may be considered as the difference between the internal energies of the two states.

ΔU = \(E_{B}\) - \(E_{A}\)     where \(E_{B}\) and \(E_{A}\) are the initial energies of states A and B. Or we can also write the equation as:

ΔU = ΔE

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Answer:

0.550 M HCl

Explanation:

M1V1 = M2V2

M1 = 0.455 M NaOH

V1 = 14.50 mL NaOH

M2 = ?

V2 = 12.0 mL HCl

Solve for M2 --> M2 = M1V1/V2

M2 = (0.455 M)(14.50 mL) / (12.0 mL) = 0.550 M HCl

Answer:

The appropriate answer is "0.549 M".

Explanation:

The given values are:

N₁ = 14.50 mL

V₁ = 0.455 M

N₂ = 12 mL

Let

V₂ = C = ?

As we know,

⇒  \(N_1\times V_1=N_2\times V_2\)

On substituting the values, we get

⇒  \(14.50\times 0.455 = 12\times C\)

⇒            \(6.5975=12\times C\)

⇒                   \(C=\frac{6.5975}{12}\)

⇒                       \(=0.549 \ M\)

The pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C is 2.24 × 10⁰ atm.

The pressure of a substance can be calculated using the following formula;

PV = nRT

According to this question, the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C can be calculated as follows:

P × 2 = 0.1 × 0.0821 × 546

2P = 4.48266

P = 2.24 × 10⁰ atm

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