Place the events involved in generation of an action potential in the correct order of occurrence from left to right : Hyperpolarization K+ channels close; Na+ channels close K+ channels open; Threshold stimulus Na channels open; Na influx Depolarization; K+ efflux Repolarization

Given that four pairs of force and mass.

(1) Force, F1 = 12 N and mass, m1 = 1 kg

(2) Force, F2 = 60 N and mass, m2 = 2 kg

(3) Force, F3 = 1 N and mass, m3 = 0.2 kg

(4) Force, F4 = 5 N and mass, m4 = 0.35 kg

To find the least acceleration among these.

In order to find the least acceleration, we have to find the acceleration of each pair.

According to Newton's second law,

Here, a is acceleration, F is force and m is the mass.

For the first pair,

For the second pair,

For the third pair,

For the fourth pair,

On Comparing all the values of acceleration, the third pair (force=1 N and mass m=0.2 kg ) has the least acceleration of 5 m/s^2.

Answer:

Vf = 90km/h

      (90*1000)/3600 ==>

      (90*10)36

Vf = 25m/s

, Vi = 60km/h

         (60*1000)/3600

          16.666m/s =>16.7m/s

          , a = 4m/s^2

t = ?

Explanation:

Vf = Vi + at

25m/s = 16.7m/s +4m/s^2(t)

25m/s - 16.7m/s = 4m/s^2(t)

8.3m/s = 4m/s^2(t)

8.3m/s/4m/s^2 = t

2.075s = t => 2.1s

General Guidance

The answer provided below has been developed in a clear step by step manner.

Step: 1

3.

We know gravitational force between two objects is

thus if m2 increases then force of gravity between the objects also increses.

Explanation:

Where G is univarsal gravitational constant, m1&m2 are mass and r is distance between the mass.

Step: 2

1. We can only change thevalue of m1,m2 and r . In any simulation we cannot change the value of G because it is universal constant, and force will change according to the values of m1,m2&r.

Explanation:Please refer to solution in this step.

Answer:

If m2 increases then force of gravity between the objects also increses.

We can manipulate m1,m2&r.

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Answer:

96,000joules!!!

Explanation:

Hope this helps u

Answer:

A. 450 N

B. 3240 J

C. 0.77 KW

Explanation:

From the question given above, the following data were obtained:

Height of one step = 20 cm

Number of steps = 36

Mass of runner = 45 kg

Time taken = 4.2 s

Next, we shall convert 20 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m /100 cm

20 cm = 0.2 m

Next, we shall determine the total height. This can be obtained as follow:

Height of one step = 0.2 m

Number of steps = 36

Total height =?

Total height = 36 × 0.2

Total height = 7.2 m

A. Determination of the runner's weight.

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = m × g

W = 45 × 10

W = 450 N

B. Determination of the increase in the potential energy.

At the ground level, the potential energy (PE₁) is 0 J.

Next, we shall determine the potential energy at 7.2 m. This can be obtained as follow:

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Total height (h) = 7.2 m

Potential energy at height 7.2 m (PE₂) = ?

PE₂ = mgh

PE₂ = 45 × 10 × 7.2

PE₂ = 3240 J

Final, we shall determine the increase in potential energy. This can be obtained as follow:

Potential energy at ground (PE₁) = 0 J

Potential energy at height 7.2 m (PE₂) = 3240 J

Increase in potential energy =?

Increase in potential energy = PE₂ – PE₁

Increase in potential energy = 3240 – 0

Increase in potential energy = 3240 J

C. Determination of the power.

Energy (E) = 3240 J

Time (t) = 4.2 s

Power (P) =?

P = E/t

P = 3240 / 4.2

P = 771.43 W

Finally, we shall convert 771.43 W to kilowatt (KW). This can be obtained as follow:

1000 W = 1 KW

Therefore,

771.43 W = 771.43 W × 1 KW / 1000 W

771.43 W = 0.77 KW

Therefore, her power is 0.77 KW

Explanation:

pls write the full question

The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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The equation gives the capacitance of a parallel-plate capacitor:C = εA/d. Where C is the capacitance, ε is the permittivity of the dielectric material between the plates, A is the area of each plate, and d is the distance between the plates.

In this case, the area of each plate is 10 cm × 20 cm = 200 cm^2 = 0.02 m^2. The distance between the plates is 2.0 mm = 0.002 m. The permittivity of the dielectric material is ε = ε0εr, where ε0 is the vacuum permittivity (8.85 × 10^-12 F/m), and εr is the relative permittivity or dielectric constant (4.1).

So, substituting these values into the equation, we get:

C = εA/d

= (ε0εr)(0.02)/(0.002)

= (8.85 × 10^-12)(4.1)(0.02)/(0.002)

= 7.26 × 10^-11 F

= 72.6 pF

Therefore, the capacitance parallel-plate capacitor is 72.6 pF.

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The constant acceleration of the train is 50/9 m/s².

The two balls will collide at a height of approximately 10.204 meters above the ground.

Using the kinematic equations of motion, we have:

distance = initial velocity * time + 1/2 * acceleration * time^2

For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:

d1 = 0 + 1/2 * a * (300)^2

For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:

d2 = v * 300

For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:

d3 = v * 300 + 1/2 * (-a) * (300)^2

The total distance traveled is the sum of these three distances:

distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600

Since the total distance traveled is given as 10 km = 10000 m, we have:

v * 600 = 10000

Solving for v, we get:

v = 10000/600 = 50/3 m/s

Now we can use the second equation above to find a:

d2 = v * 300 = (50/3) * 300 = 5000 m

Therefore, the constant acceleration of the train is:

a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2

The constant acceleration of the train is 50/9 m/s^2.

Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.

Using the kinematic equation for free fall, we have:

h = 10 + 1/2 * g * t^2

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.

The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.

Using the kinematic equation for motion with constant acceleration, we have:

0 = 10 + (-g) * t

Solving for t, we get:

t = 10/g = 10/9.81 seconds

Substituting this value of t into the first equation, we get:

h = 10 + 1/2 * 9.81 * (10/9.81)^2

Simplifying, we get:

h = 10.204 m

The two balls will collide at a height of approximately 10.204 meters above the ground.

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Answer:

Gravitation Potential Energy and Elastic Potential Energy

Explanation:

PE=abbreviation for potential energy

PE is a mechanical energy like KE is. There are two types of PE in high school physics (do not talk about other PE's like chemical PE).

Elastic PE is like the stored energy for example in a pole vault competition, the Elastic PE is stored in the pole before the vaulter goes over the desired height. (Energy stored in ELASTIC object ONLY) (commonly on the 11th grade regents springs are used to represent elastic PE)

Gravitational PE can be calculated through the formula PE=mgh although some people substitute the PE with a U. (ENERGY STORED IN OBJECT'S HEIGHT)

Answer:

The answer is 2,475$+948= add you will get the answer rn

The weight we experience on a surface is the product of our mass and acceleration due to gravity on that surface. The mass of the astronaut in earth was 60 kg . Then his mass at moon will be 9.76 kg.

The gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts every objects into its center. That why we are all standing on the ground.

The weight we experience on earth is due to the gravity. That is the product of mass and acceleration due to gravity of a planet is the weight on the planet.

The weight of astronaut in earth = 60 kg

acceleration due to gravity on earth = 9.8 m/s²

mass = 60/9.8 m/s² = 6.19 kg

Acceleration due gravity on moon = 1.6 m/s²

then weight on moon = 1.6 m/s² ×6.19 kg = 9.7 kg.

Therefore, the weight of the astronaut in moon will be 9.7 kg.

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Answer:

86.7

Explanation:

sana makatulong yung answer ko

The velocity and acceleration of the marble will be greater when it travels 1.5 m compared to 0.5 m.

The velocity of an object is the rate of change of displacement with time.

The velocity of the marble after it has travelled the given distance is calculated as follows;

v² = u² + 2as

where;

Assuming the marble started from rest, without initial velocity, our final equation becomes.

v² = 0² + 2as

v² = 2as

v = √2as

From the final equation, the velocity of the marble increases with increase in the distance travelled by the marble.

Also, since acceleration is defined as the rate of change of velocity with time. As the velocity increases, the acceleration of the marble increases as well.

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Answer:

option 5

Explanation:

because all u do is have to add them up

Answer:

B and D

Explanation:

Answer:

It is B. inherits all the traits from its parent

And D. is identical to the parent's structure

Explanation:

Hope this helped have an amazing day!

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

c.electrical to mechanical

Explanation:

Answer: a

Explanation:

We need to convert 690 cu cm to liters

First we have the next equivalence

1 liter= 1000 cm^3

690 cm^3=0.69 liters

Answer:

C

Explanation:

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  \(F = 25 \ N\)

   The frequency is   \(f = 1 \ Hz\)

   The mass of the bridge per unit length is  \(\mu = 2000 \ kg /m\)

    The length of the central span is  \(d = 144 m\)

     The oscillation amplitude of the section  considered at the time considered is  \(A = 75 \ mm = 0.075 \ m\)

      The time taken for the undriven oscillation to decay to \(\frac{1}{e}\)  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            \(m = \mu * d\)

=>        \(m = 2000 * 144\)

=>        \(m = 288000 \ kg\)

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 \(A(t) = A_o e^{-\frac{bt}{2m} }\)

Here b is the damping constant and the \(A_o\) is the amplitude of the section when it was undriven

So from the question  

               \(\frac{A_o}{e} = A_o e^{-\frac{b6T}{2m} }\)

=>            \(\frac{1}{e} =e^{-\frac{b6T}{2m} }\)

=>          \(e^{-1} =e^{-\frac{b6T}{2m} }\)

=>           \(-\frac{3T b}{m} = -1\)

=>         \(b = \frac{m}{3T}\)

Generally the amplitude of the section considered is mathematically represented as

           \(A = \frac{n * F }{ b * 2 \pi }\)

=>       \(A = \frac{n * F }{ \frac{m}{3T} * 2 \pi }\)

=>       \(n = A * \frac{m}{3} * \frac{2\pi}{25}\)

=>       \(n = 0.075 * \frac{288000}{3} * \frac{2* 3.142 }{25}\)

=>       \(n = 1810 \ people\)

The acceleration of the wildebeest is increasing.

The vertical axis represents the velocity of the wildebeest.

The horizontal axis represents the time of motion of the wildebeest

The acceleration of an object is defined as the change in velocity per change in time of motion.

\(a = \frac{\Delta v }{\Delta t } = \frac{v_2 - v_1 }{t_2 - t_1}\)

where;

The acceleration of the wildebeest is calculated as;

\(a'= \frac{0- (-a) }{b - 0} \\\\a' = \frac{a}{b}\)

In the given chart, you will notice that the acceleration of the wildebeest at time (0) is negative a (-a).

At time (b), the acceleration becomes positive with a value of \(\frac{a}{b}\)

Thus, we can conclude that the acceleration of the wildebeest is increasing.

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Answer:

B. Northern Canada

Explanation:

A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)

I DID A Science PROJECT ON THIS >:)))

basically light travels into the eye to the retina located on the back of the eye. the retina is covered withe millions of light sensitive cells called Rods and cones. when these cells detect light they send signals to the brain that help detect color.

the color of an object is determined by the wavelengths of light that it reflects. it's determined by the arrangement of electrons in the atoms of that substance that will absorb and re-emit photons of particular energies according to quantum laws.

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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Answer:

Answer:

Short-term regulation of blood pressure is controlled by the autonomic nervous system (ANS). Changes in blood pressure are detected by baroreceptors. These are located in the arch of the aorta and the carotid sinus. Increased arterial pressure stretches the wall of the blood vessel, triggering the baroreceptors.

hope this helps and can i have brainliest please.

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Answer:

9.23m

Explanation:

Max height = u²sin²theta/2g

u is the speed = 34.7m/s

theta is the angle of elevation = 33°

g is the acceleration due to gravity = 9.8m/s²

Substitute into the formula

Max height = 24.7²sin²33/2(9.8)

Max height = 610.09sin²33/2(9.8)

Max height = 610.09(0.29663)/19.6

Max height = 180.97/19.6

Max Height = 9.23m

Hence the max height the football reaches during flight is 9.23m