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Answer:

b

Explanation:

Answer:

8cm

Explanation:

The general formula to find this is F/X where in this case the f is the total of the two forces (100+100) and x is the sum of the length ( 20+5) which together comes 200&25respectively then divide 200 with 25 which comes 8cm.

Answer: 1.15 s

Explanation:

Given

Height of rock h=6.5 m

The horizontal speed of tiger u=3.5 m/s

In the vertical direction, there is no initial speed

Using the equation of motion

\(\Rightarrow h=ut+\frac{1}{2}at^2\\\\\Rightarrow 6.5=0+\frac{1}{2}\times 9.8\times t^2\\\\\Rightarrow t=\sqrt{\dfrac{13}{9.8}}=1.15\ s\)

Time taken is 1.15 s

Answer:

Explanation:

Ginen:

g - free fall acceleration on Earth

M - mass of the Earth

g₁ = g - acceleration of free fall on the planet

M₁ = 2·M - Mass of the planet

______________

R₁  / R  - ?

\(g =\frac{G\cdot M}{R^2} \\\)

\(g_1 =\frac{G\cdot M_1}{R_1^2} \\\\\)

Equate:

\(\frac{G\cdot M}{R^2} = \frac{G\cdot M_1} {R_1^2}\\\\\frac{G\cdot M}{R^2} = \frac{G\cdot 2M} {R_1^2}\\\\\frac{1}{R^2} = \frac{2} {R_1^2}\\\\\\\)

\(R_1=\sqrt{2}\cdot R\\\\\frac{R_1}{R} = \sqrt{2} \\\)

The radius of the planet is √2 times greater than that of the Earth

Планета имеет массу в два раза больше Земли. Насколько больше должен быть радиус планеты для напряженности гравитационного поля, если поверхность планеты будет такой же, как на поверхности Земли?

The speed of a transverse wave on a string is 557 m/s, time required for a particle of the string to move is 33sec.

C=557m/s

wavelength=0.156m

A=2.69mm=3*10^-3

d=1.27km

frequency=C/wavelength=557/0.156

frequency=3571

total distance moved per sec =4A/T=4Af

                                                   =4*3*10^-3*3571=38

time required=1.27*10^3/38=33sec

Motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, secondary waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.

Longitudinal waves are mechanical waves that require a medium for propagation, transverse waves are non-mechanical waves that do not require a medium for propagation.

In a transverse wave, the particles are displaced perpendicular to the direction the wave travels.

Amplitude is  the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position.

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

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Answer:

The pressure on the floor is 12 Pascal(Pa).

Explanation:

Given,

Force (F) = 240N

Area (A) = 20 cm^2

Pressure (P) = ?

we know that,

P = F/A

= 240/ 20

= 12 Pa

Answer:

Work with the local civic groups to identify and eliminate eyesores, and beautify the local environment

Pick up a piece of litter every day

Keep a litter bag in your car or your recreational vehicle so you dispose of litter properly

Create a trash fishing contest in your waterway to increase awareness about illegal dumping and littering

Write a letter to the editor of your local newspaper asking others to respect public lands and keep them clean

Help your local schools conduct recycling drives and clean-up projects

Create a beautiful green space by planting trees and shrubs in an area in need of improvement.

Ask local businesses to adopt-a-spot and take care of it

Paint and fix up playground equipment

Organize a paint-out with family and friends and create a community paintbrush mural over a wall of illegal graffiti

Recycle your old tires

Report graffiti to your local authorities

Donate your old computer equipment or dispose of it properly

Conduct a recycling drive in your neighborhood or your business

Volunteer to help your employer conduct paper recycling drives at work

Donate gently used clothes to needy organizations and shelters and identify other items that you can reuse

Compost yard and food waste and seek advice if you don’t know how

Find out how pollution in storm drain runoff can impact our aquifers and ecosystems and be passionate about doing your part to reduce litter and solid waste

Ask your local government officials to establish regular community improvement activities and to support and promote volunteer efforts

Help your library establish an environmental corner that offers books and other educational materials about taking care of the Earth

Answer:

60 °C

Explanation:

From the question given above, the following data were obtained:

Mass of 1st sample (M₁) = 200 g

Temperature of 1st sample (T₁) = 80 °C

Mass of 2nd sample (M₂) = 100 g

Temperature of 2nd sample (T₂) = 20 °C

Equilibrium temperature (Tₑ) =?

NOTE: Since the sample are the same, the specific heat capacity is constant.

We can obtain the equilibrium temperature as follow:

Heat lost by 1st = heat gained by the 2nd

M₁C(T₁ – Tₑ) = M₂C(Tₑ – T₂)

Cancel out C

M₁(T₁ – Tₑ) = M₂(Tₑ – T₂)

200 (80 – Tₑ) = 100 (Tₑ – 20)

Clear bracket

16000 – 200Tₑ = 100Tₑ – 2000

Collect like terms

16000 + 2000 = 100Tₑ + 200Tₑ

18000 = 300Tₑ

Divide both side by 300

Tₑ = 18000 / 300

Tₑ = 60 °C

Therefore, the equilibrium temperature (i.e the final temperature) of the mixture is 60 °C.

The work done required to pump all of the water (a) over the side is 6.8094 × 10⁶ J and (b) out of an outlet 2 m over the side is 11.349 × 10⁶ J.

The total amount of work done required to pump all of the water in a circular swimming pool with a diameter of 14 m whose circular side is 3 m high, and the depth of the water is 1.5 m can be calculated as follows:

(a) Pump all of the water over the side:

We have been given that the circular swimming pool has a diameter of 14 m. The depth of the water is 1.5 m. So the radius of the pool can be calculated as:

r = d/2 = 14/2 = 7 m

The volume of the water that needs to be pumped out of the pool is given by the formula:

Volume of water = πr²h

Where h is the depth of the water.

V = πr²h= 22/7 × 7 × 7 × 1.5= 231 m³

The mass of water that needs to be pumped out of the pool can be calculated as follows:

Mass of water = Volume of water × Density of water = 231 × 1000= 231000g

The gravitational force on the water can be calculated as follows:

Gravitational force on water = Mass of water × Acceleration due to gravity = 231000 × 9.8= 2269800 N

Work done in pumping all the water over the side can be calculated as follows:

Work done = Gravitational force on water × Height from the surface to the top of the pool= 2269800 × 3= 6.8094 × 10⁶ J

(b) Pump all of the water out of an outlet 2 m over the side:

Work done in pumping all the water out of an outlet 2 m over the side can be calculated as follows:

Work done = Gravitational force on water × Height of outlet from the surface= 2269800 × 2= 4.5396 × 10⁶ J

Therefore, the total amount of work (in joules) required to pump all of the water over the side and pump all of the water out of an outlet 2 m over the side of the pool is 6.8094 × 10⁶ + 4.5396 × 10⁶ = 11.349 × 10⁶ J.

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To determine the width of the slit D, we can use the formula for the angular position of the mth minimum in a single-slit diffraction pattern:

θ = mλ / D

where θ is the angular position, λ is the wavelength, m is the order of the minimum, and D is the width of the slit.

Given that the distance on the screen between the m=4 minima and the central maximum is 2.9 cm, we can consider the angular position of the m=4 minimum. Since the distance is small compared to the distance from the slit to the screen (1.00 m), we can approximate the angular position as:

θ ≈ y / L

where y is the distance on the screen and L is the distance from the slit to the screen.

Using the approximation, we have:

θ = 2.9 cm / 100 cm = 0.029

Now we can rearrange the equation to solve for the width of the slit D:

D = mλ / θ

Plugging in the values:

D = (4 * 600 nm) / 0.029

D ≈ 82.8 µm

Therefore, the width of the slit is approximately 82.8 µm.

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Answer:

Mass and volume.

Explanation:

The equation for density is always mass divided by volume. To determine the density of a fluid, you would need to find its volume and its mass.

The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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Answer:

mnnnnnbmbmmmmnnmmmmmmnnnnnnmmm.mm nooooo

Explanation:

awer some folom myy thans for dog

The frequency range of electromagnetic waves of X-ray is 3 ×10¹⁶ Hz to  3 ×10¹⁹ Hz. The wavelength range of electromagnetic waves of X-ray is  0.01 nm t0 10 nm.

The electromagnetic spectrum of electromagnetic waves can be described as the range of frequencies of electromagnetic radiation and its wavelengths and photon energies. The electromagnetic spectrum have range from one Hertz to above 10²⁵ Hertz.

The wavelength of electromagnetic radiation lies in between 380 to 760 nm and is detected by the human eye and characterized as visible light.

Electromagnetic waves of each frequency band are known by different names; starting at the low frequency (long wavelength) end of the spectrum these are radio waves, microwaves, infrared (IR), visible light, UV, X-rays, and gamma rays at the high-frequency (short wavelength) end.

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Cecil can just barely clear a pet gate that is 0.81-m tall when she launches herself at a 45° angle from a distance of 1.5-m from the base of the gate. Her launch speed is 4.4 m/s. She was in the air for 0.193 s. She lands 0.556 m behind the gate.

To determine Cecil's launch speed, we can use the kinematic equations for projectile motion. Let's break down the problem into three parts:
(a) Launch speed:
Given that Cecil can barely clear the pet gate, we can assume that her vertical displacement (Δy) is equal to the height of the gate, which is 0.81 m. The launch angle (θ) is 45°. We can use the following equation to calculate her launch speed (v):
Δy = (\(v^2\) * sin²θ) / (2 * g)
Where g is the acceleration due to gravity, approximately \(9.8 m/s^2.\)
Plugging in the values:
0.81 m = (v^2 * sin² 45°)) / (2 * \(9.8 m/s^2.\))
Simplifying the equation, we get:
v^2 = (0.81 m * 2 * \(9.8 m/s^2.\)) / sin²(45°)
Taking the square root of both sides, we find:
v = sqrt((0.81 m * 2 * \(9.8 m/s^2.\)) / sin²(45°))
Calculating the value, we find:
v ≈ 4.4 m/s
Therefore, Cecil's launch speed is approximately 4.4 m/s.
(b) Time in the air:
To determine how long Cecil is in the air, we can use the vertical component of her motion. We can use the following equation:
Δy = v0y * t - (1/2) * g * t²
Where Δy is the vertical displacement, v0y is the initial vertical velocity (which can be found using the launch speed and launch angle), t is the time in the air, and g is the acceleration due to gravity.
Given that the initial vertical velocity (v0y) is equal to v * sinθ, we can rearrange the equation to solve for t:
0.81 m = (v * sinθ) * t - (1/2) * g * t²
Plugging in the values:
0.81 m = (4.4 m/s * sin(45°)) * t - (1/2) * \(9.8 m/s^2.\) * t²
Simplifying the equation, we get a quadratic equation:
(1/2) * \(9.8 m/s^2.\)* t² - (4.4 m/s * sin(45°)) * t + 0.81 m = 0
Solving this quadratic equation, we find two possible solutions for t:
t ≈ 0.193 s or t ≈ 0.046 s
Since Cecil cannot be in the air for a negative amount of time, the valid solution is:
t ≈ 0.193 s
Therefore, Cecil is in the air for approximately 0.193 seconds.
(c) Distance behind the gate:
To determine how far behind the gate Cecil lands, we can use the horizontal component of her motion. We can use the following equation:
Δx = v0x * t
Where Δx is the horizontal displacement, v0x is the initial horizontal velocity (which can be found using the launch speed and launch angle), and t is the time in the air.
Given that the initial horizontal velocity (v0x) is equal to v * cosθ, we can plug in the values to calculate Δx:
Δx = (4.4 m/s * cos(45°)) * 0.193 s
Simplifying the equation, we find:
Δx ≈ 0.556 m
Therefore, Cecil lands approximately 0.556 meters behind the gate.

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Answer:

Explanation:

Let the tension in horizontal rope be T₁ and in the other rope be T₂ which is making angle of 51.3⁰

The vertical component of tension T₂ will balance the weight .

= T₂ cos 51.3 = 2.9 x 9.8

T₂ = 2.9 x 9.8  / cos 51.3

= 28.42 / .625

= 45.47 N

The horizontal component of T₂ will balance T₁

T₂ sin 51.3 = T₁

45.47 sin 51.3 = T₁

T₁ = 35.48 N .

Answer:

C

Explanation:

Multiple choice

Rounding to two decimal places, the height of the cliff is approximately 88.2 meters.

To calculate the height of the cliff, we can use the equations of motion for free fall. When an object is dropped from rest, its motion can be described by the following equation:

\(h = (1/2) * g * t^2\)

where:

h = height (or distance) fallen,

g = acceleration due to gravity (approximately 9.8 m/s^2 on Earth),

t = time of fall.

Given that the stone falls for 4.2 seconds before hitting the ground, we can plug in these values into the equation to find the height of the cliff:

\(h = (1/2) * 9.8 * (4.2)^2\\h = (1/2) * 9.8 * 17.64\\h = 5 * 17.64\\ h \approx 88.2m\)

Rounding to two decimal places, the height of the cliff is approximately 88.2 meters.

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Complete question is:

A stone is dropped from the top of a cliff. It is seem to hit the ground below after 4.2sec. How high is the cliff ?

a. 88.2m

b. 860m

c. 160m

d. 180m

The eccentricity of Venus is = 0.0068. That is option C.

The orbital eccentricity is defined as the measurement that is used to show how an orbit deviates from the shape of a circle.

The Venus is one of the planets of the universe that is the second closest to the sun.

The Venus is one of the planets that has a small orbital eccentricity being 0.006772 which is approximately 0.0068. This means that it is closest to being circular in shape.

The planets with the largest orbital eccentricity is the planet Mercury with orbital eccentricity of 0.2056.

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When silver sulfide (Ag2S) reacts with hydrochloric acid (HCl), it forms silver chloride (AgCl) and hydrogen sulfide gas (H2S). To calculate the mass of silver chloride formed, we need to use the balanced chemical equation and the molar masses of the compounds involved.

The balanced chemical equation for the reaction is:
Ag2S + 2HCl → 2AgCl + H2S

From the equation, we can see that 1 mole of silver sulfide reacts to form 2 moles of silver chloride. To find the number of moles of silver chloride formed, we need to convert the mass of silver sulfide given (215 g) into moles.

First, find the molar mass of silver sulfide:
Ag2S = 2(107.87 g/mol) + 32.07 g/mol = 247.61 g/mol

Now, calculate the number of moles of silver sulfide:
Moles of Ag2S = Mass of Ag2S / Molar mass of Ag2S
Moles of Ag2S = 215 g / 247.61 g/mol ≈ 0.868 mol

Since 1 mole of silver sulfide forms 2 moles of silver chloride, the number of moles of silver chloride formed is double that of silver sulfide. Therefore, the moles of silver chloride formed is:
Moles of AgCl = 2 × Moles of Ag2S
Moles of AgCl = 2 × 0.868 mol = 1.736 mol

To calculate the mass of silver chloride formed, multiply the number of moles by its molar mass:
Mass of AgCl = Moles of AgCl × Molar mass of AgCl
Mass of AgCl = 1.736 mol × (107.87 g/mol) = 187.32 g

Therefore, the mass of silver chloride formed when 215 g of silver sulfide reacts with excess hydrochloric acid is approximately 187.32 grams.

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Answer:

Explanation:

Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:

\(v_{0y}=v_0sin\theta\) and filling in:

\(v_{0y}=23sin(25)\) which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:

\(v_{0y}=9.7m/s\)

a = -9.8 m/s/s

t = 2.8 seconds

Δx = ?? m

The one-dimensional motion equation that utilizes all of these variables is

Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:

Δx = \(9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2\) I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have

Δx = 27 + \(\frac{1}{2}(-9.8)(2.8)^2\) and then to the right of the + sign and to 2 significant digits we have

Δx = 27 - 38 so

Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.

Answer:

the average speed in annual work out is 46.5

Answer:

b

Explanation:

The overall net percentage of gain in the three stocks purchased each with $ 100 in which stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value is 8.3 %

Value of Stock a = 100 + 30%

Value of Stock a = $ 130

Value of stock b = 100 + 15%

Value of stock b = $ 115

Value of stock c = 100 - 20%

Value of stock c = $ 80

Net percentage gain = ( Net profit / Total investment - 1 ) * 100

Net profit = 130 + 115 + 80

Net profit = $ 325

Total investment = 100 + 100 + 100

Total investment = $ 300

Net percentage gain = ( 325 / 300 - 1 ) * 100

Net percentage gain = ( 0.083 ) * 100

Net percentage gain = 8.3 %

Therefore, the the overall net percentage of gain in the three stocks is 8.3 %

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The position when time, t =35s is  87.59 m.

The acceleration represented by the graph is 0.143 m/s².

a = Δv/Δt

where;

a = (6 - 5) / (7 - 0)

a = 0.143 m/s²

The position of the object is determined from the product of velocity and time of motion.

s = vt + ¹/₂at²

where;

s = 0 + ¹/₂(0.143)(35)²

s = 87.59 m

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The power consumption of the train's motor is 1,317,500 W.

Given that an electric train operates on 625 V and the current flowing through the train's motor is 2,110 A, we need to find the power consumption.

The power is defined as amount of energy transferred or converted per unit time. The electric power is given by the electric current times the voltage.

The formula to calculate power consumption is:

Power = Voltage x Current

In the given case, Voltage = 625V and Current = 2,110 A.

Substituting the given values in the formula, we get,

Power = 625 V x 2,110 A

Power = 1,317,500 W

Therefore, the power consumption of the electric train is 1,317,500 W.

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The density of the unknown sample is 0.67 g/ml.

To calculate the density, we use the formula:

Density = Mass / Volume

Mass = 38.00 g

Volume = 56.39 ml

Substituting the values into the formula:

Density = 38.00 g / 56.39 ml

Dividing the mass by the volume, we find:

Density = 0.674 g/ml

Rounding to two decimal places, the density of the unknown sample is 0.67 g/ml.

Density is a measure of how much mass is contained within a given volume. In this case, we are given the mass of the unknown sample as 38.00 g and its volume as 56.39 ml. To find the density, we divide the mass by the volume. By performing the calculation, we obtain a density of 0.674 g/ml.

When rounding the value to two decimal places, the density of the unknown sample is 0.67 g/ml. This means that for every milliliter of the sample, there is 0.67 grams of mass. Density is an important property in chemistry and materials science as it can help identify substances and determine their behavior in various applications.

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Answer:

Hecht.

Explanation:

it will avoid the sun rays from penetrating into the glass to make it hot,and even fall on the seat and burn

Explanation:

Because of the type of metal it was made with

Answer:

The car gets hot in the photograph because of greenhouse effect. Most noticeably the fact that the sunlight enters the car through the windows to heat up the inside surfaces, which then gets trapped inside the car, causing a buildup of temperature.

Sunscreen can help keep the car cool by reflecting the sunlight, which in turn reduces the amount of heat that enters the car. This also decreases the inside surfaces to the exposure of UV lights.