Pharmacodynamic tolerance involves changes in _____________ while metabolic tolerance involves changes in _____________. Group of answer choices A. enzymes / neurons B. neurons / enzymes C. brain / neuron D. neuron / brain

Answer:

I agree most with Natalie. Particles in a gas are very high energy/move around a lot, and well separated. Meanwhile, liquids particles don't move as much as the gas particles do,  but still have considerable movement and are closer together. Finally, solids are composed of particles that are tightly packed together and move the least out of the three states.

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Explanation:

male anther of a flower to the female stigma of a flower. This helps to bring about fertilization of the ovules in the flower by the male gametes from the pollen grains.

Insect pollinators include bees, (honey bees, solitary species, bumblebees); pollen wasps (Masarinae); ants; flies including bee flies, hoverflies and mosquitoes; lepidopterans, both butterflies and moths; and flower beetles. Vertebrates, mainly bats and birds, but also some non-bat mammals (monkeys, lemurs, possums, rodents) and some lizards pollinate certain plants. Among the pollinating birds are hummingbirds, honeyeaters and sunbirds with long beaks; they pollinate a number of deep-throated flowers. Humans may also carry out artificial pollination.

A pollinator is different from a pollenizer, a plant that is a source of pollen for the pollination process.

Answer:

Mitosis is the process in which the cell divides.

Explanation:

In telephase and cytokinesis the cell completes mitosis and becomes two genetically identical cells. The cytoplasm splits and two new nucleus reform.

Answer:

The coastline could recede, which means that the height of the coast wouldn't be the same as before

Explanation:

The cell is a living unit greater than the sum of its parts" emphasizes that a cell possesses emergent properties and functions that go beyond the individual components it comprises.

While a cell consists of various organelles with specific roles, its behavior and capabilities result from the interactions and integration of these components. Cells exhibit emergent properties such as growth, reproduction, response to stimuli, and specialized functions.

In multicellular organisms, cells collaborate to form tissues, organs, and organ systems, further showcasing emergent properties that cannot be attributed solely to individual cells.

Understanding the complexity and functionality of cells requires recognizing their integrated nature, where the whole cell entity transcends the mere sum of its constituent parts.

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Answer:

Taking in waste

Population dispersion is how individuals are spaced within a population. Option d is correct.

Population dispersion refers to the way individuals are arranged within a population. It can be clumped, random, or uniform. Clumped dispersion occurs when individuals cluster together, often due to the availability of resources or social behavior. Random dispersion occurs when individuals are spaced unpredictably, usually due to the absence of strong environmental factors or social behavior.

Uniform dispersion occurs when individuals are evenly spaced, typically due to competition for resources or territorial behavior. Studying population dispersion can provide insight into the distribution of resources, social behavior, and ecological interactions within a population. Option d is correct.

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Answer:

Overpopulation

Explanation:

Our earth has a carrying capacity which means the maximum amount of land and resources the environment can give to us without hurting itself. When we go over our carrying capacity we reach overpopulation which hurt our environment

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In the Meselson and Stahl experiment, heavy DNA was distinguished from normal DNA by centrifugation using a CsCl density gradient.

The Meselson and Stahl experiment involved labeling the heavy DNA with a heavy isotope of nitrogen, 15N, and the normal DNA with a lighter isotope, 14N. The DNA samples were then placed in a centrifuge tube with a CsCl solution, and subjected to centrifugation.

During centrifugation, the heavy DNA moved toward the bottom of the tube, while the normal DNA moved toward the top. This created a distinct band of heavy DNA at the bottom of the tube, and a distinct band of normal DNA at the top.

By comparing the positions of the two bands, the researchers were able to distinguish between the heavy and normal DNA and determine how DNA replication occurs in cells.

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Small body size and high surface-to-volume ratio are characteristics of phytoplankton. The benefits of these characteristics include buoyancy, simple waste ejection, and simple nutrition absorption. Option 3, 4, 5 are Correct.

High surface area to volume ratios in phytoplankton avoid sinking and improve the diffusion of both food in and waste out. Dinoflagellates and coccolithophores are more suited to areas with poor nutrition availability. Maintaining afloat.

Both phytoplankton and zooplankton species all have structural modifications that assist keep them floating in the water column. These adaptations, which increase the amount of their body surface area in contact with the water, include flat bodies, lateral spines, and long, thin appendages. For marine creatures, being tiny enhances the potential for wastes to spread out of the body. Option 3, 4, 5 are Correct.

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Correct Question:

Phytoplankton has a small body size and a large surface-to-volume ratio. what is/are the advantages of these features? choose all that apply.

1. allows for a more complex circulatory system

2. allows for a more complex respiratory system

3. ease of nutrient absorption

4. ease of waste expulsion

5. buoyancy.

Answer:

The relative rate of photosynthesis is greatest under high light intensity at 35°C. This can be seen from the graph, as the curve for high light intensity reaches its highest point at around 35°C. In contrast, the curve for low light intensity reaches its highest point at a lower temperature of around 25°C. Therefore, the correct answer is (D) high light intensity at 35°C.

Explanation:

Answer: Maximum photosynthesis occurs at 35 degrees Celsius in bright light. As the graph shows, the peak of the high-light intensity curve occurs around 35 degrees Celsius. In contrast, the peak of the low-light intensity curve occurs at a relatively mild 25 degrees Celsius. Therefore, (D) high light intensity at 35°C, is the correct answer.

Explanation:

Answer:

diffusion of oxygen and carbon dioxide

Answer:wbc or white blood cells

Explanation:

Answer: R = 2 ohm

Explanation: Based on the Ohm's law

                      U = R*I    --->   R = U / I

                                              R = 10 / 5

                                              R = 2 ohm

Answer:

Answer : The resistance of a circuit is 2 ohm.

Explanation:

Using Ohm's law :

Or,

where,

R = resistance of a circuit = ?

V = voltage of circuit = 10 volts = 10V

I = current flowing in a circuit = 5 A

Now put all the given values in the above formula, we get the resistance of circuit.

Therefore, the resistance of a circuit is 2 ohm.

Answer:

bad cholesterol

Explanation:

Your body needs healthy fats for energy and other functions. But too much saturated fat can cause cholesterol to build up in your arteries (blood vessels). Saturated fats raise your LDL (bad) cholesterol. High LDL cholesterol increases your risk for heart disease and stroke.

Answer:

The person's bad cholesterol would decrease.

Explanation:

edgy 2021

Answer:don’t put pesticides that will harm humans on your crops.

Explanation: many pesticides in today’s world will get people sick and cause disease.

Answer:

Global warming is a very popular place in the world and is a very popular city in the world with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you to find a home or home with a wide range of amenities and a great range of amenities to help you

Explanation:

Your home and home safely and to enjoy your warm weather with your lovely family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family for a very happy birthday celebrating your birthday with a wonderful birthday celebrating a birthday present for our wedding anniversary and anniversary celebrations and special wedding anniversary celebrations for our wedding day special wedding day celebrations and special wedding celebrations for our wedding anniversary celebrations in the evening with our lovely friends in a lovely hotel with a lovely view and a lovely relaxing holiday for a few days away from home for the night and the rest of the night and a lovely

Knowing the extensive and intensive properties of inputs used in production is useful because it helps in understanding the relationship between input quantities and output levels, allowing for better resource management and production planning.

Extensive properties of inputs refer to the quantities or amounts of resources used in production, such as the total amount of raw materials or labor hours. Intensive properties, on the other hand, measure the productivity or efficiency of inputs per unit of output, such as the amount of output produced per unit of input.

By knowing the extensive properties, such as the total quantities of inputs required, managers can estimate the overall resource requirements and allocate resources accordingly. This helps in optimizing resource utilization and reducing wastage.

Understanding the intensive properties provides insights into the productivity and efficiency of inputs. It allows managers to identify areas where improvements can be made to increase output levels without necessarily increasing the total amount of inputs. This knowledge is valuable for enhancing productivity, controlling costs, and improving overall production efficiency.

The complete question is

It is considered useful to know the extensive and intensive properties of the inputs used for the production of products. Why?

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that the condensation of chromatin into short threadlike structures that can be seen under a microscope occurs in the Prophase stage of mitosis. Furthermore, are the  would include more information about mitosis and how the Prophase stage leads to the separation

chromosomes during cell division. Lastly, an can be provided to further clarify the concept of chromatin condensation in the Prophase stage of mitosis. Mitosis is the process by which a single cell divides into two daughter cells. The mitotic cell cycle includes four distinct phases: Prophase, Metaphase, Anaphase, and Telophase. The Prophase stage is the first stage of mitosis, and it is during this phase that chromatin fibers in the nucleus condense into short threadlike structures called chromosomes.

Each chromosome contains two identical copies of DNA molecules that are held together at a region called the centromere. During Prophase, the nucleolus disappears, and the nuclear envelope breaks down, allowing the chromosomes to move freely in the cytoplasm. At the same time, spindle fibers form and attach to the chromosomes at the kinetochores, which are protein structures on the centromeres. The spindle fibers help to move the chromosomes towards the center of the cell during Metaphase, which is the next stage of mitosis.In summary, the condensation of chromatin fibers into short threadlike structures occurs during Prophase in the mitotic cell cycle.

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According to the given equation f(x) = 6(1-x) if we put the value of x = 8, we will get f(-8) is 54.

The given function f(x) = 6(1-x) is a linear function, where the slope is -6 and the y-intercept is 6. The negative slope indicates that the function is decreasing as x increases.

To find the value of f(-8), we substitute -8 for x in the equation.

f(-8) = 6(1-(-8))

Using the rule of double negatives, -(-8) becomes +8, which simplifies the expression to:

f(-8) = 6(1+8)

Evaluating the expression within the parentheses first, we get:

f(-8) = 6(9)

Finally, multiplying 6 and 9 together, we get:

f(-8) = 54

Therefore, the value of f(-8) is 54.

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Answer: Heat and pressure.

Explanation: Sedimentary rocks form from erosion of soil and weathering. Igneous rock is formed from the cooling of magma. Metamorphic rocks form from a ton of heat and pressure below the ground.

Metamorphic rocks are formed due to heat and pressure​, hence option D is correct.

Sedimentary rocks are created through weathering and soil erosion. Magma cools, which results in the formation of igneous rock. A tremendous amount of pressure and heat underground causes metamorphic rocks to develop.

In the world, there are three different types of rocks: igneous rocks, sedimentary rocks, and metamorphic rocks.

Volcanic magma seeped from the volcano to the earth's surface, where it cooled and hardened to produce igneous rocks.

Igneous rocks are the source of sedimentary rocks, which develop through time from the eroded remnants of igneous rocks.

Therefore, Igneous and sedimentary rocks undergo metamorphism as a result of heat and pressure over millions of years.

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Answer:

Photosynthesis converts carbon dioxide and water into oxygen and glucose. Glucose is used as food by the plant and oxygen is a by-product. Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.

Answer:

photosynthesis converts cabon dioxide and water into oxygen and glucose

while respiration converts glucose and oxygen into water and carbon dioxide

A homogeneous solution is one where the constituents or components are distributed evenly in the mixture. NH2CH3 and CH4 form a homogeneous solution.

1. NF3 and SO2: NF3 is a polar molecule whereas SO2 is a non-polar molecule. Thus, these two molecules will not form a homogeneous solution.

2. CBr4 and SF2: CBr4 is a non-polar molecule whereas SF2 is a polar molecule. Thus, these two molecules will not form a homogeneous solution

3. NH2CH3 and CH4: Both of these molecules are non-polar.Thus, they will form a homogeneous solution.

4. CO and C6H6: CO is a polar molecule whereas C6H6 is a non-polar molecule. Thus, these two molecules will not form a homogeneous solution.

Therefore, the pairs of NF3 and SO2 and CO and C6H6 will not form a homogeneous solution as these are a combination of a polar and a non-polar molecule.

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The chi-square statistic's "critical" value is 3.84. Basically, the null hypothesis if your calculated chi-square was higher than the critical threshold inside the table because it indicates that the data did not match.

The error margin within a collection of data is measured by statisticians using the critical value, which is defined as: Critical likelihood (p*) ≈ 1 - (Alpha / 2), wherein Alpha was equal to 1 - (minimum level of confidence / 100).

What is an illustration of good fit? Tests for the goodness of fit compare the actual data to the projected or expected data. The Kolmogorov-Smirnov, Shapiro-Wilk, and Chi-Square goodness-of-fit tests are a few examples. Usually, computer software is used to perform all three.

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The connective tissue layer that surrounds each muscle fiber and electrically isolates it is called the endomysium.

The endomysium is a delicate layer of connective tissue that surrounds individual muscle fibers or muscle cells. It consists of collagen and reticular fibers and separates each muscle fiber from its neighboring fibers, providing electrical insulation between them. This insulation prevents the electrical impulses generated within one muscle fiber from spreading to adjacent fibers.

In addition to its electrical isolation function, the endomysium also provides support, nutrients, and oxygen to the muscle fiber, and facilitates the exchange of waste products.

It is one of the layers of connective tissue, along with the perimysium and epimysium, that contribute to the overall structure and organization of skeletal muscle.

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Complete question:

You are tracking three loci in the fruit fly, loci A, B, and C, and want to know whether the loci are linked and if so what their physical distances are from one another as well as the physical order they are in. To find out this information you perform a three-point testcross with a fly that is heterozygous for all three alleles. The progeny of this cross are:

a/a B/b C/c    389

A/a b/b c/c     410

a/a b/b C/c       39

A/a B/b c/c       44

a/a b/b c/c        77

A/a B/b C/c      83

a/a B/b c/c          6

A/a b/b C/c         5

Total                 1053

(a) What is the recombination frequency between loci A and B?  

(b) What is the recombination frequency between loci B and C?  

(c) What is the recombination frequency between loci A and C?

(d) Are these loci linked?

(e) Demonstrate the physical arrangement of the genes on the chromosome, i.e. the order of the genes on a chromosome as well as their map distances.  

(f) Write out the genotypes of the parents for this cross, indicating which alleles are linked with one another for each parent?

Answer and Explanation:      

The Crossing-over frequency between two genes depends on the distance between them. A short distance between genes is a very little target for crossing-over to occur, which means that only a few of them will happen, compared with the number of events between genes that are more separated between each other.  Two genes that are very close will have a few recombination events and are strongly bounded.  While two separated genes will have more chances of recombination and are not bound.

To know if two genes are linked, we must observe the progeny distribution. In a tri-hybrid cross, If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1:1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the heterozygote parent.

In the present example, the phenotypic ratio shows different proportions than the expected ones if they were not linked.

We can recognize the parental gametes in the descendants because their phenotypes are the most frequent,

a/a B/b C/c    389

A/a b/b c/c     410  

while the double recombinants are the less frequent.

a/a B/b c/c          6

A/a b/b C/c         5        

And simple recombinant gametes produced by the cross, which frequencies are intermediate.  

a/a b/b C/c       39

A/a B/b c/c       44                  

a/a b/b c/c        77      

A/a B/b C/c      83      

Comparing the parental and the double recombinant we will realize that they only change in the position of the alleles C/c. This suggests that the position of the gene C is in the middle of the other two genes, A and B, because in a double recombinant only the central gene changes position in the chromatid.

A------C------B

Now we will call Region I to the area between A and C and Region II to the area between C and B.

Once established the order of the genes we can calculate distances between them, and we will do it from the central gene to the genes on each side. First We will calculate the recombination frequencies, and we will do it by region. We will call P1 to the recombination frequency between A and C genes, and P2 to the recombination frequency between C and B.

P1 = (R + DR) / N

P2 = (R + DR)/ N

Where: R is the number of recombinants in each region, DR is the number of double recombinants in each region, and N is the total number of individuals. To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.  

So:

Now, to calculate the recombination frequency between the two extreme genes, A and B, we can just perform addition or a sum:

P1 + P2= Pt

0.162 + 0.089 = Pt

0.251 = Pt  

The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU).  One centiMorgan (cM) equals one map unit (MU). The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

(a) What is the recombination frequency between loci A and B?    0.251

(b) What is the recombination frequency between loci B and C?   0.089  

(c) What is the recombination frequency between loci A and C?  0.162  

(d) Are these loci linked?  Yes. Their recombination frequency is inferior to 50% and the phenotypic rate is different from 1:1:1:1:1:1:1:1

(e) Demonstrate the physical arrangement of the genes on the chromosome, i.e. the order of the genes on a chromosome as well as their map distances.  

A-------------------C-----------------B

A--- 16.2 UM --C ---8.9 UM--B

A-------------25.1 UM--------------B

(f) Write out the genotypes of the parents for this cross, indicating which alleles are linked with one another for each parent?

a/a C/c B/b  x   A/a c/c b/b    

Answer:

Dense regular and dense irregular

Explanation:

Dense regular and dense irregular connective tissues.